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  • Crashing app when i want to go rootview from other view controller

    - by Priyanka
    Hello All, I want to go Root view Controller from another view controller but i got the terminating error. following is the error message in console, Terminating app due to uncaught exception 'NSRangeException', reason: '* -[NSCFArray removeObjectsInRange:]: index (4) beyond bounds (1)' This is my code for that NSArray *arr=self.navigationController.viewControllers; //ListOfInjuriesViewController *list=[[ListOfInjuriesViewController alloc]init]; [self.navigationController popToViewController:[arr objectAtIndex:2] animated:YES]; So any one can give me the suggestion on it so can remove the crash

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  • Help with ejb 3, weblogic and spring.

    - by berserkpi
    So,hi there. I've created a simple EJB3 test project, the code is simple: @Stateless @Remote( { ISumaSimple.class }) public class SumaSimpleBean implements ISumaSimple { /** * Default constructor. */ public SumaSimpleBean() { // TODO Auto-generated constructor stub } @Override public int sumar(int a, int b) { // TODO Auto-generated method stub return a + b; } } public interface ISumaSimple { public int sumar(int a, int b); } Ok, my client is a stand alone spring aplication which configuration is: <bean id="sumaSimpleServicio" class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiEnvironment"> <props> <prop key="java.naming.factory.initial"> org.apache.openejb.client.RemoteInitialContextFactory </prop> <prop key="java.naming.provider.url"> ejbd://localhost:4201 </prop> </props> </property> <property name="jndiName" value="SumaSimpleBeanRemote" /> </bean> <bean id="clienteService" class="qtx.cliente.simple.ClienteService"> <property name="sumaSimpleServicio" ref="sumaSimpleServicio"></property> </bean> All worked smoothly, but then I tried deploying using weblogic 10.3, I just changed these values: weblogic.jndi.WLInitialContextFactory t3://localhost:7010 In weblogic jndi tree my ejb is under: SimpleEJB3SimpleEJB_jarSumaSimple3_ISumaSimple Of course I added wlclient.jar to my spring client classpath. I think I am missing something in weblogic case, but dunno. My spring client is throwing this exception: Caused by: org.springframework.beans.TypeMismatchException: Failed to convert property value of type [qtx.ejb.simple._SumaSimple3_gwze0z_ISumaSimpleIntf_Stub] to required type [qtx.servicio.simple.ISumaSimple] for property 'sumaSimpleServicio'; nested exception is java.lang.IllegalArgumentException: Cannot convert value of type [qtx.ejb.simple._SumaSimple3_gwze0z_ISumaSimpleIntf_Stub] to required type [qtx.servicio.simple.ISumaSimple] for property 'sumaSimpleServicio': no matching editors or conversion strategy found at org.springframework.beans.BeanWrapperImpl.convertForProperty(BeanWrapperImpl.java:391) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.convertForProperty(AbstractAutowireCapableBeanFactory.java:1288) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyPropertyValues(AbstractAutowireCapableBeanFactory.java:1249) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1010) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:472) ... 14 more Caused by: java.lang.IllegalArgumentException: Cannot convert value of type [qtx.ejb.simple._SumaSimple3_gwze0z_ISumaSimpleIntf_Stub] to required type [qtx.servicio.simple.ISumaSimple] for property 'sumaSimpleServicio': no matching editors or conversion strategy found at org.springframework.beans.TypeConverterDelegate.convertIfNecessary(TypeConverterDelegate.java:219) at org.springframework.beans.TypeConverterDelegate.convertIfNecessary(TypeConverterDelegate.java:138) at org.springframework.beans.BeanWrapperImpl.convertForProperty(BeanWrapperImpl.java:386) ... 18 more Any help would be appreciated.

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  • Add a datatable to a data set

    - by Jibu P C_Adoor
    Hii... I have a data table 'dt1' that is belongs to 'ds1'. I have created another instance of dataset 'ds2' and try to add the datatable 'dt1' to 'ds2'. Now i got one exception 'DataTable already belongs to another data set'. Is there any reliable way to add the dt1 to ds2?

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  • how to return 2 values from a java function?

    - by javaLearner.java
    Here is my code: // Function code public static int something(){ int number1 = 1; int number2 = 2; return number1, number2; } // Main class code public static void main(String[] args) { something(); System.out.println(number1 + number2); } Error: Exception in thread "main" java.lang.RuntimeException: Uncompilable source code - missing return statement at assignment.Main.something(Main.java:86) at assignment.Main.main(Main.java:53) Java Result: 1

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  • Jaxb to generate the XML directly to the OutputStream

    - by sonu
    Hi, I have a 500Mb csv file. I need to convert it into XML file. I am using the Jaxb to created the xml file. It is working fine for small amout of data. but for large amout of data like 300 mb it is throwing out of memory exception. Can anyone tell me that How can I create each element and write it into a file without creating the whole tree using the jaxb?" Thanks Sonu

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  • OutOfMemoryError loading Bitmap via DefaultHttpClient

    - by Goddchen
    i have a simple problem: Although i'm using sampleSize properly, my code doesn't even reach the BitmapFactorycode, since DefaultHttpClient is already throwing the exception. Here is my code: DefaultHttpClient client = new DefaultHttpClient(); HttpGet request = new HttpGet(mSongInfo.imageLarge); HttpResponse response = client.execute(request); int sampleSize = 1; while (response.getEntity().getContentLength() / sampleSize / sampleSize > 100 * 1024) { sampleSize *= 2; } BitmapFactory.Options options = new BitmapFactory.Options(); options.inSampleSize = sampleSize; final Bitmap bitmap = BitmapFactory.decodeStream(response .getEntity().getContent(), null, options); And here is the exception: 0 java.lang.OutOfMemoryError: (Heap Size=11463KB, Allocated=7623KB, Bitmap Size=9382KB) 1 at org.apache.http.util.ByteArrayBuffer.<init>(ByteArrayBuffer.java:53) 2 at org.apache.http.impl.io.AbstractSessionInputBuffer.init(AbstractSessionInputBuffer.java:82) 3 at org.apache.http.impl.io.SocketInputBuffer.<init>(SocketInputBuffer.java:98) 4 at org.apache.http.impl.SocketHttpClientConnection.createSessionInputBuffer(SocketHttpClientConnection.java:83) 5 at org.apache.http.impl.conn.DefaultClientConnection.createSessionInputBuffer(DefaultClientConnection.java:170) 6 at org.apache.http.impl.SocketHttpClientConnection.bind(SocketHttpClientConnection.java:106) 7 at org.apache.http.impl.conn.DefaultClientConnection.openCompleted(DefaultClientConnection.java:129) 8 at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:173) 9 at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164) 10 at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119) 11 at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:359) 12 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555) 13 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487) 14 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465) 15 at de.goddchen.android.easysongfinder.fragments.SongFragment$1.run(SongFragment.java:79) 16 at java.lang.Thread.run(Thread.java:1027) As you can see, the code doesn't even reach the part where i check the size (Content-Length) of the image and calculate a proper sample size. I wasn't aware that simply calling DefaultHttpClient.execute(...) will already load the complete content into the memory. Am i doing something wrong? What is the right way to first retrieve the content length and then start reading the content from an InputStream? EDIT To avoid common answers that show how to load images from a URL: i already know how to do that, i have also posted the code above, so why do you keep referencing tutorials on that? I explicitly was very clear about the problem: Why is HttpClient.execute(...)already fetching the whole content and storing it in memory instead of providing a proper ÌnputStreamto me? Please don't post any beginner tutorials on how to load aBitmap`from a URL...

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  • C# - Converting a float to an int... and changing the int depending on the remainder

    - by Django Reinhardt
    Hi, this is probably the really newbie question (well, I'm pretty sure it is), but I have a float that's being returned and I need a quick and efficient way of turning it into an int. Pretty simple, but I have an exception. If the remainder of the float is anything other than .0 then I want to increment the int. Some quick examples: Float = 98.0, Int = 98 Float = 98.1, Int = 99 Float = 6.6, Int = 7 etc. Thanks for any help!

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  • How can I pipe input to a Java app with Perl?

    - by user319479
    I need to write a Perl script that pipes input into a Java program. This is related to this, but that didn't help me. My issue is that the Java app doesn't get the print statements until I close the handle. What I found online was that $| needs to be set to something greater than 0, in which case newline characters will flush the buffer. This still doesn't work. This is the script: #! /usr/bin/perl -w use strict; use File::Basename; $|=1; open(TP, "| java -jar test.jar") or die "fail"; sleep(2); print TP "this is test 1\n"; print TP "this is test 2\n"; print "tests printed, waiting 5s\n"; sleep(5); print "wait over. closing handle...\n"; close TP; print "closed.\n"; print "sleeping for 5s...\n"; sleep(5); print "script finished!\n"; exit And here is a sample Java app: import java.util.Scanner; public class test{ public static void main( String[] args ){ Scanner sc = new Scanner( System.in ); int crashcount = 0; while( true ){ try{ String input = sc.nextLine(); System.out.println( ":: INPUT: " + input ); if( "bananas".equals(input) ){ break; } } catch( Exception e ){ System.out.println( ":: EXCEPTION: " + e.toString() ); crashcount++; if( crashcount == 5 ){ System.out.println( ":: Looks like stdin is broke" ); break; } } } System.out.println( ":: IT'S OVER!" ); return; } } The Java app should respond to receiving the test prints immediately, but it doesn't until the close statement in the Perl script. What am I doing wrong? Note: the fix can only be in the Perl script. The Java app can't be changed. Also, File::Basename is there because I'm using it in the real script.

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  • database transaction rollback processing in PHP

    - by user198729
    try { $con->beginTransaction(); $this->doSave($con); $con->commit(); } catch (Exception $e) { $con->rollBack(); throw $e; } The code above is quite standard an approach to deal with transactions, but my question is:what if $con->rollBack() also fails? It may cause db lock,right?If so,what's the perfect way to go?

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  • Check for active connection in NHibernate

    - by Dofs
    I have a system with a few different databases, and I would like to check if a certain database is down, and if so display a message to the user. Is it possible in NHibernate to check if there is an active connection to the database, without having to request data and then catch the exception?

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  • How to write a Python 2.6+ script that does gracefully fail with older pyhton?

    - by Sorin Sbarnea
    I'm using the new print from Python 3.x and I observed that the following code does not compile due to the end=' '. from __future__ import print_function import sys if sys.hexversion < 0x02060000: raise Exception("py too old") ... print("x",end=" ") # fails to compile with py24 How can I continue using the new syntax but make the script fails nicely? Is it mandatory to call another script and use only safe syntax in this one?

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  • Writing String into a File

    - by Halo
    I'm implementing a WebScript using Alfresco's JavaScript. l'm trying to insert string to a file, but I can't do it. When I write another file's content like: file.properties.content.write(content); It works, and the file's contents are copied into my file. But I can't insert string directly, like: file.properties.content.write("Stuff like that"); it gives an exception. How can I write string into this file?

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  • How do I diagnose a failure in the Membership service on an ASP.NET remote site?

    - by ProfK
    Yesterday I added a custom MembershipProvider to an ASP.NET web application, but when I deployed the application to its remote host server, it failed. I know I had the login info correct, and I also know that for nearly any exception in the login process, the Login control displays the standard error message, "Your login failed", so I assume something is wrong in the code/config. What can I do to diagnose what is wrong on the server?

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  • What is wrong with this C++ Code ?

    - by mr.bio
    Hi .. i am a beginner and i have a problem : this code doesnt compile : main.cpp: #include <stdlib.h> #include "readdir.h" #include "mysql.h" #include "readimage.h" int main(int argc, char** argv) { if (argc>1){ readdir(argv[1]); // test(); return (EXIT_SUCCESS); } std::cout << "Bitte Pfad angeben !" << std::endl ; return (EXIT_FAILURE); } readimage.cpp #include <Magick++.h> #include <iostream> #include <vector> using namespace Magick; using namespace std; void readImage(std::vector<string> &filenames) { for (unsigned int i = 0; i < filenames.size(); ++i) { try { Image img("binary/" + filenames.at(i)); for (unsigned int y = 1; y < img.rows(); y++) { for (unsigned int x = 1; x < img.columns(); x++) { ColorRGB rgb(img.pixelColor(x, y)); // cout << "x: " << x << " y: " << y << " : " << rgb.red() << endl; } } cout << "done " << i << endl; } catch (Magick::Exception & error) { cerr << "Caught Magick++ exception: " << error.what() << endl; } } } readimage.h #ifndef _READIMAGE_H #define _READIMAGE_H #include <Magick++.h> #include <iostream> #include <vector> #include <string> using namespace Magick; using namespace std; void readImage(vector<string> &filenames) #endif /* _READIMAGE_H */ If want to compile it with this code : g++ main.cpp Magick++-config --cflags --cppflags --ldflags --libs readimage.cpp i get this error message : main.cpp:5: error: expected initializer before ‘int’ i have no clue , why ? :( Can somebody help me ? :)

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  • Asp.Net - When does it restart the application

    - by Seattle Leonard
    I know that whenever you add/remove/modify any file in the "App_Code", "App_GlobalResources", and "bin" directories that ASP.NET will recompile and essentially restart the application. My question is : "What happens to any threads currently executing durring the change?" Do they finish? Is a Thread.Abort Exception thrown? What happens if the application itself makes a change in any of those directories?

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  • problem with QMainWindow setCentralWidget and stackedWidget

    - by user63898
    Hello i have gui the i created in the designer , simple one . QMainWIndow that contains stackedWidget , the application starts with stackedWidget index 0 that contains qwebkit widget and after some user flow ,it changes to stackedWidget index 1 that contains QTree widget , to center the first widget i use in the QMainWindow constractor this line of code this-setCentralWidget(ui.webView); but when the application switching to index number 1 im getting exception that is coming from the switching command . why ?

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  • C# ApplicationContext usage

    - by rd42
    Apologies if my terminology is off, I'm new to C#. I'm trying to use an ApplicationContext file to store mysql conn values, like dbname, username, password. The class with mysql conn string is "using" the namespace for the ApplicationContext, but when I print out the connection string, the values are making it. A friend said, "I'm not initializing it" but couldn't stay to expand on what "it" was. and the "Console.WriteLine("1");" in ApplicationContext.cs never shows up. Do I need to create an ApplicationContext object and the call Initialize() on that object? Thanks for any help. ApplicationContext.cs: namespace NewApplication.Context { class ApplicationContext { public static string serverName; public static string username; public static string password; public static void Initialize() { //need to read through config here try { Console.WriteLine("1"); XmlDocument xDoc = new XmlDocument(); xDoc.Load(".\\Settings.xml"); XmlNodeList serverNodeList = xDoc.GetElementsByTagName("DatabaseServer"); XmlNodeList usernameNodeList = xDoc.GetElementsByTagName("UserName"); XmlNodeList passwordNodeList = xDoc.GetElementsByTagName("Password"); } catch (Exception ex) { // MessageBox.Show(ex.ToString()); //TODO: Future write to log file username = "user"; password = "password"; serverName = "localhost"; } } } } MySQLManager.cs: note: dbname is the same as the username as you'll see in the code, I copied this from a friend who does that. using System; using System.Collections.Generic; using System.Linq; using System.Text; using MySql.Data; using MySql.Data.MySqlClient; using NewApplication.Context; namespace NewApplication.DAO { class MySQLManager { private static MySqlConnection conn; public static MySqlConnection getConnection() { if (conn == null || conn.State == System.Data.ConnectionState.Closed) { string connStr = "server=" + ApplicationContext.serverName + ";user=" + ApplicationContext.username + ";database=" + ApplicationContext.username + ";port=3306;password=" + ApplicationContext.password + ";"; conn = new MySqlConnection(connStr); try { Console.WriteLine("Connecting to MySQL... "); Console.WriteLine("Connection string: " + connStr + "\n"); conn.Open(); // Perform databse operations // conn.Close(); } catch (Exception ex) { Console.WriteLine(ex.ToString()); } } return conn; } } } and, thanks for still reading, this is the code that uses the two previous files: class LogDAO { MySqlConnection conn; public LogDAO() { conn = MySQLManager.getConnection(); } Thank you, rd42

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