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  • accessing list sent from server as JSON object

    - by tazim
    How to access a list sent in form of json object using django to the template received in ajax callback function . The code is as follows : views.py def showfiledata(request): with open("/home/tazim/webexample/test.txt") as f: list = f.readlines() f.closed return_dict = {'filedata':list} json = simplejson.dumps(return_dict) HttpResponse(json,mimetype="application/json") in template showfile.html: < html> < head> < script type="text/javascript" src="/jquerycall/">< /script> < script type="text/javascript"> $(document).ready(function() { $("button").click(function() { $.ajax({ type:"POST", url:"/showfiledata/", datatype:"json", success:function(data) { var s = data.filedata; $("#someid").html(s); } }); }); }); < /script> < /head> < body> < form method="post"> < button type="button">Click Me< /button> < div id="someid">< /div> < /form> < /body> < /html>

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  • Cloning input type file and set the value

    - by jribeiro
    I know that it isn't possible to set the value of an input type="file" for security reasons... My problem is: I needed to style an input type="file" so what I did was have a button and hide the file input. like: <a href="#" onclick="$('input[name=&quot;photo1&quot;]').click(); return false;" id="photo1-link"></a> <input type="file" name="photo1" class="fileInput jqtranformdone validate[required]" id="photo1" /> These works great in all browsers except IE which gives me an access denied error on submitting through ajax. I'm using the ajaxSubmit jquery plugin (malsup.com/jquery/form/) So after reading for a while I tried to do: var photo1Val = $('#photo1').val(); var clone1 = $('#photo1').clone().val(photo1Val); $('#photo1').remove(); clone1.appendTo('form'); console.log(photo1Val) //prints the right value C:/fakepath/blablabla.jpg $('form').ajaxSubmit(options); The problem is that after this the value of $('#photo1') is empty... Any ideas how to work around this? Thanks

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  • Uploading a file fails under WordPress

    - by Ash
    I'm using WordPress and I'm following W3's guide for uploading a file: HTML code: <html> <body> <form action="upload_file.php" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </body> </html> PHP code (upload_file.php): <?php if ($_FILES["file"]["error"] > 0) { echo "Error: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Stored in: " . $_FILES["file"]["tmp_name"]; } ?> The HTML code is pasted in a PHP page template and the PHP file under the WP installation directory under www. The problem is when I submit the file I get Error: 1. If I remark the "if" part of the PHP code and leave the "else" part I get: Upload: IMG_4258.JPG Type: Size: 0 Kb Stored in: So at least I know the PHP code is running. But what's causing it to fail? Is there a problem with the code or is WordPress meddling with the process?

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  • POST XML to server, receive PDF

    - by Shaggy Frog
    Similar to this question, we are developing a Web app where the client clicks a button to receive a PDF from the server. Right now we're using the .ajax() method with jQuery to POST the data the backend needs to generate the PDF (we're sending XML) when the button is pressed, and then the backend is generating the PDF entirely in-memory and sending it back as application/pdf in the HTTP response. One answer to that question requires the server-side save the PDF to disk so it can give back a URL for the client to GET. But I don't want the backend caching content at all. The other answer suggests the use of a jQuery plugin, but when you look at its code, it's actually generating a form element and then submitting the form. That method will not work for us since we are sending XML data in the body of the HTTP request. Is there a way to have the browser open up the PDF without caching the PDF server-side, and without requiring us to throw out our send-data-to-the-server-using-XML solution? (I'd like the browser to behave like it does when a form element is submitted -- a POST is made and then the browser looks at the Content-type header to determine what to do next, like load the PDF in the browser window, a la Safari)

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  • Load SQL query result data into cache in advance

    - by Marc
    I have the following situation: .net 3.5 WinForm client app accessing SQL Server 2008 Some queries returning relatively big amount of data are used quite often by a form Users are using local SQL Express and restarting their machines at least daily Other users are working remotely over slow network connections The problem is that after a restart, the first time users open this form the queries are extremely slow and take more or less 15s on a fast machine to execute. Afterwards the same queries take only 3s. Of course this comes from the fact that no data is cached and must be loaded from disk first. My question: Would it be possible to force the loading of the required data in advance into SQL Server cache? Note My first idea was to execute the queries in a background worker when the application starts, so that when the user starts the form the queries will already be cached and execute fast directly. I however don't want to load the result of the queries over to the client as some users are working remotely or have otherwise slow networks. So I thought just executing the queries from a stored procedure and putting the results into temporary tables so that nothing would be returned. Turned out that some of the result sets are using dynamic columns so I couldn't create the corresponding temp tables and thus this isn't a solution. Do you happen to have any other idea?

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  • Synchronizing DataGridView (DataTable) with the DB

    - by Ezekiel Rage
    Hi! I have the following situation: there is a table in the DB that is queried when the form loads and the retrieved data is filled into a DataGridView via the DataTable underneath. After the data is loaded the user is free to modify the data (add / delete rows, modify entries). The form has 2 buttons: Apply and Refresh. The first one sends the changes to the database, the second one re-reads the data from the DB and erases any changes that have been made by the user. My question is: is this the best way to keep a DataGridView synchronized with the DB (from a users point of view)? For now these are the downsides: the user must keep track of what he is doing and must press the button every while the modifications are lost if the form is closed / app crash / ... I tried sending the changes to the DB on CellEndEdit event but then the user also needs some Undo/Redo functionality and that is ... well ... a different story. So, any suggestions?

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  • JQuery Modal Boxes and Iframe

    - by Ólafur Waage
    I've been using Simple Modal and i feel it doesn't live up to what i need at the moment. Is there a Modal Box that supports loading external files and allows those external files to close the modal box and redirect the parent page to some url. An example of what i want to do. You have a list of users, you could click "Add user" and a Modal Box with the form pops up, you fill that in and submit it. That would close the box and reload the user list page so you would see the user in the list. Then you could click "Edit user" and a Modal Box with the user info filled in the form fields would pop up and you could edit, submit and it would close and refresh. I know this can be done if i have the user info form as a hidden div for each user but this will not scale well and it is a lot of overhead data. I found some code about this on Google Code but just can't get it to work (possibly different simple modal version I am willing to change to another modal box tool also. UPDATE: Do either Thickbox or Fancybox support being closed from a child IFrame element?

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  • Java object graph -> xml when direction of object association needs to be reversed.

    - by Sigmoidal
    An application I have been working on has objects with a relationship similar to below. In the real application both objects are JPA entities. class Underlying{} class Thing { private Underlying underlying; public Underlying getUnderlying() { return underlying; } public void setUnderlying(final Underlying underlying) { this.underlying = underlying; } } There is a requirement in the application to create xml of the form: <template> <underlying> <thing/> <thing/> <thing/> </underlying> </template> So we have a situation where the object graph expresses the relationship between Thing and Underlying in the opposite direction to how it's expressed in the xml. I expect to use JAXB to create the xml but ideally I don't want to have to create a new object hierarchy to reflect the associations in the xml. Is there any way to create xml of the form required from the entities in their current form (through the use of xml annotations or something)? I don't have any experience using JAXB but from the limited research I've done it doesn't seem like it's possible to reverse the direction of association in any straightforward way. Any help/advice would be greatly appreciated. One other option that has been suggested is to use XLST to transform the xml into the correct format. I have done no research on this topic as yet but I'll add to the question when I have some more info. Thanks, Matt.

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  • How to manually set an authenticated user in Spring Security / SpringMVC

    - by David Parks
    After a new user submits a 'New account' form, I want to manually log that user in so they don't have to login on the subsequent page. The normal form login page going through the spring security interceptor works just fine. In the new-account-form controller I am creating a UsernamePasswordAuthenticationToken and setting it in the SecurityContext manually: SecurityContextHolder.getContext().setAuthentication(authentication); On that same page I later check that the user is logged in with: SecurityContextHolder.getContext().getAuthentication().getAuthorities(); This returns the authorities I set earlier in the authentication. All is well. But when this same code is called on the very next page I load, the authentication token is just UserAnonymous. I'm not clear why it did not keep the authentication I set on the previous request. Any thoughts? Could it have to do with session ID's not being set up correctly? Is there something that is possibly overwriting my authentication somehow? Perhaps I just need another step to save the authentication? Or is there something I need to do to declare the authentication across the whole session rather than a single request somehow? Just looking for some thoughts that might help me see what's happening here.

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  • Visibility of reintroduced constructor

    - by avenmore
    I have reintroduced the form constructor in a base form, but if I override the original constructor in a descendant form, the reintroduced constructor is no longer visible. type TfrmA = class(TForm) private FWndParent: HWnd; public constructor Create(AOwner: TComponent; const AWndParent: Hwnd); reintroduce; overload; virtual; end; constructor TfrmA.Create(AOwner: TComponent; const AWndParent: Hwnd); begin FWndParent := AWndParent; inherited Create(AOwner); end; type TfrmB = class(TfrmA) private public end; type TfrmC = class(TfrmB) private public constructor Create(AOwner: TComponent); override; end; constructor TfrmC.Create(AOwner: TComponent); begin inherited Create(AOwner); end; When creating: frmA := TfrmA.Create(nil, 0); frmB := TfrmB.Create(nil, 0); frmC := TfrmC.Create(nil, 0); // Compiler error My work-around is to override the reintroduced constructor or to declare the original constructor overloaded, but I'd like to understand the reason for this behavior. type TfrmA = class(TForm) private FWndParent: HWnd; public constructor Create(AOwner: TComponent); overload; override; constructor Create(AOwner: TComponent; const AWndParent: Hwnd); reintroduce; overload; virtual; end; type TfrmC = class(TfrmB) private public constructor Create(AOwner: TComponent; const AWndParent: Hwnd); override; end;

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  • Help in J2ME for creating image and parse it

    - by HAMED
    Can anyone tell me how i can parse a png image into many png images in J2ME??? for examole:I just wnat to have a source image 150*150 pixel and parse it to 10 image with 15*15 pixel. I write an elemantary code that have exeption. This is my code: public class HelloMIDlet extends MIDlet implements CommandListener { private boolean midletPaused = false; private Command exitCommand; private Form form; private StringItem stringItem; Image im , im2; Form form1 = null; public HelloMIDlet() { try { // create source image im = Image.createImage("/image1.JPG"); int height = im.getHeight() ; int width = im.getWidth() ; int x = 0 ; int y = 0 ; while ( y < height ){ while ( x < width ){ // create 15*15 pixel of source image im2 = im.createImage(im, x, y, 15, 15, Sprite.TRANS_NONE) ; x += 15 ; } y += 15 ; x = 0 ; } } catch (IOException ex) { ex.printStackTrace(); } } please help me to make it right....It's emergency! Thanks a lot guys...

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  • JqueryUI dialog box causes button to lose styling

    - by superexsl
    Hey everyone, I'm using JQueryUI dialog boxes and, while it works, it seems to remove any CSS styling on the button that opens the dialog. I have to manually refresh the page to get the styling back. An example button which launches the dialog: (button_submit is my CSS theme and launc_popup is used to detect the button click in JQuery. <asp:Button ID="btnLaunch" CssClass="button_sub launch_popup" runat="server" Text="Dialog..." CausesValidation="false" OnClientClick="return false;" /> My jquery: $('.launch_popup').click(function() { $("#dialog-form").dialog("open"); }); My dialog-form: $("#dialog-form").dialog({ autoOpen: false, height: 300, width: 300, modal: true, buttons: { 'Close': function() { $(this).dialog('close'); } } }); This happens to all the buttons that open dialogs. Is there a way to 'restyle' the button without refreshing the page? (It's in an updatepanel if that makes a difference, although this bit's client-side so not sure if that should affect it). Thanks for any help

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  • Unable to send '+' through AJAX post?

    - by Harish Kurup
    I am using Ajax POST method to send data, but i am not able to send '+'(operator to the server i.e if i want to send 1+ or 20k+ it will only send 1 or 20k..just wipe out '+') HTML code goes here.. <form method='post' onsubmit='return false;' action='#'> <input type='input' name='salary' id='salary' /> <input type='submit' onclick='submitVal();' /> </form> and javascript code goes here, function submitVal() { var sal=document.getElementById("salary").value; alert(sal); var request=getHttpRequest(); request.open('post','updateSal.php',false); request.setRequestHeader("Content-Type","application/x-www-form-urlencoded"); request.send("sal="+sal); if(request.readyState == 4) { alert("update"); } } function getHttpRequest() { var request=false; if(window.XMLHttpRequest) { request=new XMLHttpRequest(); } else if(window.ActiveXObject) { try { request=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try { request=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e) { request=false; } } } return request; } in the function submitVal() it first alert's the salary value as it is(if 1+ then alerts 1+), but when it is posted it just post's value without '+' operator which is needed... is it any problem with query string, as the PHP backend code is working fine...

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  • RSpec: Can't convert Image to String when using Nested Resource.

    - by darrint
    I'm having trouble with and RSpec view test. I'm using nested resources and the model with a belongs_to association. Here's what I have so far: describe "/images/edit.html.erb" do include ImagesHelper before(:each) do @image_pool = stub_model(ImagePool, :new_record => false, :base_path => '/') assigns[:image] = @image = stub_model(Image, :new_record? => false, :source_name => "value for source_name", :image_pool => @image_pool) end it "renders the edit image form" do render response.should have_tag("form[action=#{image_path(@image)}][method=post]") do with_tag('input#image_source_name[name=?]', "image[source_name]") end end end The error I'm receiving: ActionView::TemplateError in '/images/edit.html.erb renders the edit image form' can't convert Image into String On line #3 of app/views/images/edit.html.erb 1: <h1>Editing image</h1> 2: 3: <% form_for(@image) do |f| %> 4: <%= f.error_messages %> 5: 6: <p> app/views/images/edit.html.erb:3 /opt/dtcm/railstest/lib/ruby/gems/1.9.1/gems/rspec-rails-1.3.2/lib/spec/rails/extensions/action_view/base.rb:27:in `render_with_mock_proxy' /opt/dtcm/railstest/lib/ruby/gems/1.9.1/gems/rspec-rails-1.3.2/lib/spec/rails/example/view_example_group.rb:170:in `render' Looking at the rails code where the exception occurs is not very revealing. Any ideas on how I can narrow down what is going on here? One thing I tried was calling form_for directly from the example and I got a different error griping about lack of 'polymorphic_path' defined on Spec::Rails::Example::ViewExampleGroup::Subclass_4:0xblah. Not sure if that actually means anything.

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  • MVC Html.ActionLink with post funtionality?

    - by Levitikon
    I'm checking to see if anyone has written an MVC extension for Html.ActionLink that you can pass in Post parameters like such: <% Html.ActionLink("Click me", "Index", "Home", new { MyRouteValue = "123" }, null, new { postParam1 = "a", postParam2 = "b" }); %> That would render the link like normal but having an onClick event that submits an also rendered form with an Action url for the Action, Controller, and Route Values with additional hidden inputs from the Post Parameters like such: <a href="#" onClick="$('#theform').submit(); return false;">Click me</a> <form id="theform" action="/Home/Index/123" method="post"> <input type="hidden" name="postParam1" value="a"> <input type="hidden" name="postParam2" value="b"> </form> I'm looking to redirect users to various pages with potentially a lot of data. Not only from page to page, but from email to page also. This would be highly reusable and I think would clean up a lot of code, and would save a bunch of time writing this if its already floating around out there. I hate recreating the wheel when I don't have to. Thanks!

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  • Skip HTML escape in custom label_tag helper in Rail 3

    - by tricote
    Hi, I have this nice class ErrorFormBuilder that allows me to add the error description near the corresponding field in the form view : class ErrorFormBuilder < ActionView::Helpers::FormBuilder #Adds error message directly inline to a form label #Accepts all the options normall passed to form.label as well as: # :hide_errors - true if you don't want errors displayed on this label # :additional_text - Will add additional text after the error message or after the label if no errors def label(method, text = nil, options = {}) #Check to see if text for this label has been supplied and humanize the field name if not. text = text || method.to_s.humanize #Get a reference to the model object object = @template.instance_variable_get("@#{@object_name}") #Make sure we have an object and we're not told to hide errors for this label unless object.nil? || options[:hide_errors] #Check if there are any errors for this field in the model errors = object.errors.on(method.to_sym) if errors #Generate the label using the text as well as the error message wrapped in a span with error class text += " <br/><span class=\"error\">#{errors.is_a?(Array) ? errors.first : errors}</span>" end end #Add any additional text that might be needed on the label text += " #{options[:additional_text]}" if options[:additional_text] #Finally hand off to super to deal with the display of the label super(method, text, options) end end But the HTML : text += " <br/><span class=\"error\">#{errors.is_a?(Array) ? errors.first : errors}</span>" is escaped by default in the view... I tried to add the {:escape = false} option : super(method, text, options.merge({:escape => false})) without success Is there any way to bypass this behavior ? Thanks

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  • Rails Model inheritance in forms

    - by Tiago
    I'm doing a reporting system for my app. I created a model ReportKind for example, but as I can report a lot of stuff, I wanted to make different groups of report kinds. Since they share a lot of behavior, I'm trying to use inheritance. So I have the main model: model ReportKind << ActiveRecord::Base end and created for example: model UserReportKind << ReportKind end In my table report_kinds I've the type column, and until here its all working. My problem is in the forms/controllers. When I do a ReportKind.new, my form is build with the '*report_kind*' prefix. If a get a UserReportKind, even through a ReportKind.find, the form will build the 'user_report_kind' prefix. This mess everything in the controllers, since sometimes I'll have params[:report_kind], sometimes params[:user_report_kind], and so on for every other inheritance I made. Is there anyway to force it to aways use the 'report_kind' prefix? Also I had to force the attribute 'type' in the controller, because it didn't get the value direct from the form, is there a pretty way to do this? Routing was another problem, since it was trying to build routes based in the inherited models names. I overcome that by adding the other models in routes pointing to the same controller.

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  • Compare values in serialized column in Doctrine with Query Builder

    - by ReynierPM
    I'm building a FormType for a Symfony2 project but I need some Query Builder on the field since I need to compare some values with the one stored on DB and show the results. This is what I have: .... ->add('servicio', 'entity', array( 'mapped' => false, 'class' => 'ComunBundle:TipoServicio', 'property' => 'nombre', 'required' => true, 'label' => false, 'expanded' => true, 'multiple' => true, 'query_builder' => function (EntityRepository $er) { return $er->createQueryBuilder('ts') ->where('ts.tipo_usuario = (:tipo)') ->setParameter('tipo', 1); } )) .... But tipo_usuario at DB table is stored as serialized text for example: record1: value1 | a:1:{i:0;s:1:"1";} record2: value2 | a:4:{i:0;s:1:"1";i:1;s:1:"2";i:2;s:1:"3";i:3;s:1:"4";} I'll have two different forms (I don't know how to pass the Request to a form) in the first one I'll only show the first record and for the second one the first and second record for example: First form will show: checkbox: value1 Second form will show: checkbox: value1 checkbox: value2 I achieve this? Any help?

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  • iTextSharp Overlay Image

    - by pennylane
    Hi guys I have an instance where I have a logo image as part of some artwork.. If a user uploads a new logo I have a form field which is larger than the default logo. I then use that form field to position the new image. The problem is I need to set the background colour of that form field to white so that it covers the old logo in the event that the new image is smaller than the old logo.. what I have done is: foreach (var imageField in imageReplacements) { fields.SetFieldProperty(imageField.Key, "bgcolor", iTextSharp.text.Color.WHITE, null); fields.RegenerateField(imageField.Key); PdfContentByte overContent = stamper.GetOverContent(imageField.Value.PageNumber); float[] logoArea = fields.GetFieldPositions(imageField.Key); if (logoArea != null) { iTextSharp.text.Rectangle logoRect = new iTextSharp.text.Rectangle(logoArea[1], logoArea[2], logoArea[3], logoArea[4]); var logo = iTextSharp.text.Image.GetInstance(imageField.Value.Location); if (logo.Width >= logoRect.Width || logo.Height >= logoRect.Height) { logo.ScaleToFit(logoRect.Width, logoRect.Height); } logo.Alignment = iTextSharp.text.Image.ALIGN_LEFT; logo.SetAbsolutePosition(logoRect.Left, logoArea[2] + (logoRect.Height - logo.ScaledHeight) / 2); // left: logoArea[3] - logo.ScaledWidth + (logoRect.Width - logo.ScaledWidth) / 2 overContent.AddImage(logo); } } The problem with this is that the background colour of the field is set to white and the image then doesn't appear.. i remove the SetFieldProperty and RegenerateField commands and the image replacement works fine.. is there a way to set a stacking order on layers?

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  • How do I create an "iframe popup" when I hover over an <a> tag?

    - by Angela
    Here is the scenario: a User will see a list of company names, each wrapped in an tag. He is able to see dynamic information and as he hover over each name and then make a request. So Given a list of companies, each wrapped in an tag. When the cursor hovers over an tag Then a "pop-up" appears that contains an -based, dynamic content. Given the pop-up When the User clicks on the "submit" button in the pop-up Then the form (based on the framework" is submitted and ajax displays "request succesful" So, because I am using a php-framework, I'd like to use iframe to contain the form. Some challenges: When the cursor is no longer hovering over the tag, the hover disappears. How do I keep it operating? How do I make it appear in an so I can have full form-submission and POST-ing dynamic values through the URL? How do the "popup" disappear when the cursor is no longer on either the -tag or the pop-up itself? Can I do it without loading a bunch of 's onto the page, because the list of companies could be long.

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  • Using C# to HttpPost data to a web page

    - by druffmuff
    I want to log in into a website using C# code. Here's the html code of the example form: <form action="http://www.site.com/login.php" method="post" name="login" id="login"> <table border="0" cellpadding="2" cellspacing="0"> <tbody> <tr><td><b>User:</b></td><td colspan=\"2\"><b>Password:</b></td></tr> <tr> <td><input class="inputbg" name="user" type="text"></td> <td><input class="inputbg" name="password" type="password"></td> <td><input type="submit" name="user_control" value="Submit" class="buttonbg"></td> </tr> </tbody></table> </form> This is what I have tried so far with unsuccessful results: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.site.com/login.php"); request.Method = "POST"; using (StreamWriter writer = new StreamWriter(request.GetRequestStream(), Encoding.ASCII)) { writer.Write("user=user&password=pass&user_control=Eingabe"); } HttpWebResponse response = (HttpWebResponse)request.GetResponse(); using (StreamReader reader = new StreamReader(response.GetResponseStream())) { stream = new StreamWriter("login.html"); stream.Write(reader.ReadToEnd()); stream.Close(); } Any Ideas, why this is failing?

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  • JSP Upload File Java.lang.NullPointer

    - by newbie123
    I want to develope upload and download file from server. Upload.html <form action="/UploadFile/UploadFile" method="POST" enctype="multipart/form-data">Select a file: <input type="submit" name="button" /> <input type="file" name="first"></form> UploadFile.servlet protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String temp = request.getParameter("first"); System.out.println(temp); File origFile = new File(temp); FileOutputStream out = new FileOutputStream(request.getContextPath() + "pdtImages/" + "FirstFile"); InputStream ins = new FileInputStream(origFile); try { System.out.println(request.getContextPath()); byte[] buf = new byte[1024]; int len; while ((len = ins.read(buf)) > 0) { out.write(buf, 0, len); } out.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } When I submitted the file I got null pointer error message. I not very familiar with jsp can anybody help me? I want to store the file to the server directory.

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • how to submit a from with validation in PHP?

    - by jitendra
    I want to submit this form through PHP. with validation for required field and validation for phone number and email field also <form action="" method="" id="get-protected"> <div class="row requiredRow"> <label for="txt_FirstName"> First Name</label> <input id="txt_FirstName" type="text" class="required" title="First Name. This is a required field" /> </div> <div class="row"> <label for="txt_LastName"> Last Name</label> <input id="txt_LastName" type="text" title="First Name. This is a required field" /> </div> <div class="row"> <label for="txt_Phone"> Phone</label> <input id="txt_Phone" type="text" title="First Name. This is a required field" /> </div> <div class="row requiredRow"> <label for="txt_Email"> Email</label> <input id="txt_Email" type="text" class="required" title="Email. This is a required field" /> </div> <div class="row"> <input type="submit" value="" class="button" /> </div> </form>

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