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  • go programming POST FormValue can't be printed

    - by poor_programmer
    Before I being a bit of background, I am very new to go programming language. I am running go on Win 7, latest go package installer for windows. I'm not good at coding but I do like some challenge of learning a new language. I wanted to start learn Erlang but found go very interesting based on the GO I/O videos in youtube. I'm having problem with capturing POST form values in GO. I spend three hours yesterday to get go to print a POST form value in the browser and failed miserably. I don't know what I'm doing wrong, can anyone point me to the right direction? I can easily do this in another language like C#, PHP, VB, ASP, Rails etc. I have search the entire interweb and haven't found a working sample. Below is my sample code. Here is Index.html page {{ define "title" }}Homepage{{ end }} {{ define "content" }} <h1>My Homepage</h1> <p>Hello, and welcome to my homepage!</p> <form method="POST" action="/"> <p> Enter your name : <input type="text" name="username"> </P> <p> <button>Go</button> </form> <br /><br /> {{ end }} Here is the base page <!DOCTYPE html> <html lang="en"> <head> <title>{{ template "title" . }}</title> </head> <body> <section id="contents"> {{ template "content" . }} </section> <footer id="footer"> My homepage 2012 copy </footer> </body> </html> now some go code package main import ( "fmt" "http" "strings" "html/template" ) var index = template.Must(template.ParseFiles( "templates/_base.html", "templates/index.html", )) func GeneralHandler(w http.ResponseWriter, r *http.Request) { index.Execute(w, nil) if r.Method == "POST" { a := r.FormValue("username") fmt.Fprintf(w, "hi %s!",a); //<-- this variable does not rendered in the browser!!! } } func helloHandler(w http.ResponseWriter, r *http.Request) { remPartOfURL := r.URL.Path[len("/hello/"):] fmt.Fprintf(w, "Hello %s!", remPartOfURL) } func main() { http.HandleFunc("/", GeneralHandler) http.HandleFunc("/hello/", helloHandler) http.ListenAndServe("localhost:81", nil) } Thanks! PS: Very tedious to add four space before every line of code in stackoverflow especially when you are copy pasting. Didn't find it very user friendly or is there an easier way?

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  • Getting ORACLE programming object definitions

    - by Yaakov Davis
    Let's say I have an ORACLE schema with contains a package. That package defines types, functions, procedures, etc: CREATE PACKAGE... DECLARE FUNCTION ... PROCEDURE ... END; Is there a query I can execute to get the definitions of those individual objects, without the wrapping package?

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  • how to use session in iphone programming?

    - by jaydp
    Hi Friends, I made an iphone story book application. Suppose any user read story book and at half of the story book he/she close the apps. when he/she want to read again this application at a time ask for continue or start again. This is possible by using session but i don't know how to use session in iphone sdk. So, please help me about this problem. Thanks!

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  • HTML tags in ojective c programming

    - by user1661826
    Is there any function in Objective-C to print a list of elements as unordered HTML elements. For ex - [@"a--b-c---d" htmlList: @"--"] returns @ "ab-c-d" the "--" is the delimiter to seperate the string of elements. I have used NSSArray to store the input string and function componentsSeperatedByString:@"--" to get the elements. How do I go ahead in adding the HTML tags li and /li between elements and ul and /ul at the end of the entire list? Please help, Im a beginner in objective -C

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  • Socket Programming : Inputstream Stuck in loop - read() always return 0

    - by Atom Skaa ska Hic
    Server side code public static boolean sendFile() { int start = Integer.parseInt(startAndEnd[0]) - 1; int end = Integer.parseInt(startAndEnd[1]) - 1; int size = (end - start) + 1; try { bos = new BufferedOutputStream(initSocket.getOutputStream()); bos.write(byteArr,start,size); bos.flush(); bos.close(); initSocket.close(); System.out.println("Send file to : " + initSocket); } catch (IOException e) { System.out.println(e.getLocalizedMessage()); disconnected(); return false; } return true; } Client Side public boolean receiveFile() { int current = 0; try { int bytesRead = bis.read(byteArr,0,byteArr.length); System.out.println("Receive file from : " + client); current = bytesRead; do { bytesRead = bis.read(byteArr, current, (byteArr.length-current)); if(bytesRead >= 0) current += bytesRead; } while(bytesRead != -1); bis.close(); bos.write(byteArr, 0 , current); bos.flush(); bos.close(); } catch (IOException e) { System.out.println(e.getLocalizedMessage()); disconnected(); return false; } return true; } Client side is multithreading,server side not use multithreading. I just paste some code that made problem if you want see all code please tell me. After I debug the code, I found that if I set max thread to any and then the first thread always stuck in this loop. That bis.read(....) always return 0. Although, server had close stream and it not get out of the loop. I don't know why ... But another threads are work correctly. do { bytesRead = bis.read(byteArr, current, (byteArr.length-current)); if(bytesRead >= 0) current += bytesRead; } while(bytesRead != -1);

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  • ASP.Net MVC - Models and User Controls

    - by cdotlister
    Hi guys, I have a View with a Master Page. The user control makes use of a Model: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BudgieMoneySite.Models.SiteUserLoginModel>" %> This user control is shown on all screens (Part of the Master Page). If the user is logged in, it shows a certain text, and if the user isn't logged in, it offers a login box. That is working OK. Now, I am adding my first functional screen. So I created a new view... and, well, i generated the basic view code for me when I selected the controller method, and said 'Create View'. My Controller has this code: public ActionResult Transactions() { List<AccountTransactionDetails> trans = GetTransactions(); return View(trans); } private List<AccountTransactionDetails> GetTransactions() { List<AccountTransactionDto> trans = Services.TransactionServices.GetTransactions(); List<AccountTransactionDetails> reply = new List<AccountTransactionDetails>(); foreach(var t in trans) { AccountTransactionDetails a = new AccountTransactionDetails(); foreach (var line in a.Transactions) { AccountTransactionLine l = new AccountTransactionLine(); l.Amount = line.Amount; l.SubCategory = line.SubCategory; l.SubCategoryId = line.SubCategoryId; a.Transactions.Add(l); } reply.Add(a); } return reply; } So, my view was generated with this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Collections.Generic.List<BudgieMoneySite.Models.AccountTransactionDetails>>" %> Found <%=Model.Count() % Transactions. All I want to show for now is the number of records I will be displaying. When I run it, I get an error: "The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BudgieMoneySite.Models.AccountTransactionDetails]', but this dictionary requires a model item of type 'BudgieMoneySite.Models.SiteUserLoginModel'." It looks like the user control is being rendered first, and as the Model from the controller is my List<, it's breaking! What am I doing wrong?

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  • programming in lua, objects

    - by anon
    Sample code: function Account:new (o) o = o or {} -- create object if user does not provide one setmetatable(o, self) self.__index = self return o end taken from: http://www.lua.org/pil/16.1.html What is the purpose of the: self.__index = self line? And why is it executed every time an object is created?

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  • telephone application programming on Linux

    - by Daniel Stevens
    I'm a Linux user looking to write a program which will pick up the phone, dial a number, play a recording and record what the person on the other end of the line says and save it to an audio file. I will want to use the modem that came with my computer if possible. What should I use to write this program?

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  • Programming Java professionally

    - by user299925
    Just seeking some advice. By profession I am primarily a front-end programmer working with ajax technologies (currently I use php as my backend language of choice). As of lately I've been looking at Java as a very good OOP language to learn and just wanted to know if you guys have any advice as to what's the best way to learn the language and achieve proficency that may some day lead to mastery.

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  • Qt Programming:Installer not able to create shortcut in start menu in Windows 7

    - by nav
    Hello all, I am creating an installer to deploy some application .and I am getting following problems All applications shortcut get created in start menu under a common name like: *Start MENU-CMKIT-gcompris -open office -Scratch* A pop up should be launched at the end of installation,which has buttons for each application and it will start respective application when user clicks on button.Its not launching now. Its very critical for me,please help me.I am also ready to pay for this but give me solution for these. please mail me on

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  • where is HOME and END key for MacBook Pro?

    - by George2
    Hello everyone, I am using a MacBook Pro running Mac OS X 10.5. I am new to this development environment, and previously worked on Windows. I am wondering what is the HOME key (goes to the begin position of a line in text file) and END key (goes to the end position of a line in text file) on the Mac? My MacBook Pro seems to not have these two keys on the keyboard. thanks in advance, George

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  • insserv: Script <SCRIPT_NAME> is broken: missing end of LSB comment.

    - by udo
    I am getting this error when running: insserv -r udo-startup.sh insserv: Script udo-startup.sh is broken: missing end of LSB comment. insserv: exiting now! The content of udo-startup.sh is this: #!/bin/bash ### BEGIN INIT INFO # Provides: udo-startup.sh # Required-Start: $local_fs $remote_fs $network $syslog # Required-Stop: $local_fs $remote_fs $network $syslog # Default-Start: 2 3 4 5 # Default-Stop: 0 1 6 # Short-Description: - # Description: - ### END INIT INF ID=$(xinput list | grep -i touchpad | sed '/TouchPad/s/^.*id=\([0-9]*\).*$/\1/') xinput set-prop $ID "Device Enabled" 0 exit 0

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  • Why am I getting a warning that windows is logging on with a temporary profile to run a task scheduler task?

    - by Dan C
    I am having a strange problem with the Windows Server 2008 Task Scheduler. I have to run a small command-line application every few minutes. This application just executes a quick web service call on the localhost and adds an entry to a log file; so it should not need anything special in terms of permissions. First, I created a new user account "my_scheduler" just for the task. This account is a member of the Users group (not sure what other settings I should turn on/off) and set it's password to not expire. I then create a task to run the application every few minutes. I set it to "Run whether user is logged on or not" and turned on "Do not store password. The task will only have access to local resources" (I did this since it's not hitting anything on the network. I did not turn on "Run with highest privileges" since it does not seem to need them. I set the schedule to "After triggered, repeat every 30 minutes for a duration of 1 day" and "Allow task to be run on demand" (no other settings enabled). However, I notice that in the Event Log, I see a bunch of these warnings whenever the task is run: "Windows cannot find the local profile and is logging you on with a temporary profile. Changes you make to this profile will be lost when you log off." Even though I get the warning, the task is executing (I see the log entries appearing). Another (possibly related) issue is that I also see that it's starting multiple copies of the task (within a few seconds of each other) even though it should only start one. This is also a big problem. Any idea how I can fix this? Thanks in advance, Dan

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  • Key-Based SSH Permission denied (publickey) Ubuntu 12-04

    - by user125176
    I have configured sshd to accept key-based ssh logins with LogLevel on DEBUG, and uploaded my public key to ~/.ssh.authorized_keys, where permissions are set as: 700 ~/.ssh 600 ~/.ssh/authorized_keys From root, I can su - USERNAME. From the client I get Permission denied (publicly). From the server Here's how it is telling me that it "Could not open authorized keys '/home/USERNAME/.ssh/authorized_keys': Permission denied". Client protocol version 2.0; client software version OpenSSH_5.2 match: OpenSSH_5.2 pat OpenSSH* Enabling compatibility mode for protocol 2.0 Local version string SSH-2.0-OpenSSH_5.9p1 Debian-5ubuntu1 permanently_set_uid: 105/65534 [preauth] list_hostkey_types: ssh-rsa,ssh-dss,ecdsa-sha2-nistp256 [preauth] SSH2_MSG_KEXINIT sent [preauth] SSH2_MSG_KEXINIT received [preauth] kex: client->server aes128-ctr hmac-md5 none [preauth] kex: server->client aes128-ctr hmac-md5 none [preauth] SSH2_MSG_KEX_DH_GEX_REQUEST received [preauth] SSH2_MSG_KEX_DH_GEX_GROUP sent [preauth] expecting SSH2_MSG_KEX_DH_GEX_INIT [preauth] SSH2_MSG_KEX_DH_GEX_REPLY sent [preauth] SSH2_MSG_NEWKEYS sent [preauth] expecting SSH2_MSG_NEWKEYS [preauth] SSH2_MSG_NEWKEYS received [preauth] KEX done [preauth] userauth-request for user USERNAME service ssh-connection method none [preauth] attempt 0 failures 0 [preauth] PAM: initializing for "USERNAME" PAM: setting PAM_RHOST to "USERHOSTNAME" PAM: setting PAM_TTY to "ssh" userauth_send_banner: sent [preauth] userauth-request for user USERNAME service ssh-connection method publickey [preauth] attempt 1 failures 0 [preauth] test whether pkalg/pkblob are acceptable [preauth] Checking blacklist file /usr/share/ssh/blacklist.RSA-4096 Checking blacklist file /etc/ssh/blacklist.RSA-4096 temporarily_use_uid: 1001/1002 (e=0/0) trying public key file /home/USERNAME/.ssh/authorized_keys Could not open authorized keys '/home/USERNAME/.ssh/authorized_keys': Permission denied restore_uid: 0/0 temporarily_use_uid: 1001/1002 (e=0/0) trying public key file /home/USERNAME/.ssh/authorized_keys2 Could not open authorized keys '/home/USERNAME/.ssh/authorized_keys2': Permission denied restore_uid: 0/0 Failed publickey for USERNAME from IPADDRESS port 57523 ssh2 Connection closed by IPADDRESS [preauth] do_cleanup [preauth] monitor_read_log: child log fd closed do_cleanup PAM: cleanup

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  • What is the advantage of not running as root? [closed]

    - by Shmuel Brill
    Possible Duplicate: What's wrong with always being root? All modern brands of Linux highly discourage (or disable) one from running as root instead of a normal user. I do not understand why. As a "normal" user, one could Download a rouge program from the internet. Run it (After all, one isn't root, what can it do). It installs itself in .bashrc or .xinitrc It writes a rouge "sudo" and "su" and adds . to the path Not noticing that . is in path, one runs sudo. The rouge program now has root password and can do anything it wants in the system. Even if 3-6 doesn't happen, the program could still Be part of a botnet. Read all files in the home directory and send them back (mine for SS#, Credit Card numbers, bank account numbers, etc). Send spam. Run a backdoor server to allow an attacker a chance to connect to the machine to determine vulnerabilities. It seems that the whole "permissions" thing (root/non-root) is just to prevent amateur crackers from getting into the system, so the question is: Is there a point in avoiding running as root, and is there a way to protect oneself if one wants to run unsafe code?

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  • Is it ever good to share a userid?

    - by Ladlestein
    On Un*x, Is it ever a good idea to have one userid that many different people log into when they do stuff? Often I'm installing software or something on a Linux or BSD system. I've developed software for 24 years now, so I know how to make the machine do what I want, but I've never had responsibility for maintaining a multi-user installation where anyone really cared about security. So my opinions feel untested. Now I'm at a company where there's a server that many people log into with a single userid and do stuff. I'm installing some software on it. It's not really a public-facing server, and is only accessible via VPN, but it's used by many people nonetheless, to run tests on custom software, things like that. It's a staging server. I'm thinking that at the very least, using a single user obscures an audit trail, and that's bad. And it's just inelegant, because people don't have their own spaces on the server. But then again, with more userids, maybe there's a greater chance that one can be compromised, allowing attackers to gain access. ?

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  • REMOTE_USER not getting set?

    - by landed
    I am trying to setup LDAP Authentication in Joomla using a plugin called JMapMyLDAP (in fact 4 plugins each doing a different job). I need to pull a part of a string out of the server variable REMOTE_USER and this should be visible (we see here http://timplummer.com.au/4-how-to-integrate-joomla-3-with-active-directory-using-ldap.html) in phpinfo(); The issue is that REMOTE_USER is not set or at least not appearing. A few things to note (if you don't mind) here- conceptually I am not really understanding authentication as a whole subject it appears to be vast despite my years working in websites. Yes I used asp and built php pages to check a user is who they say they are with a token(/session?) that was given to just them and then they are identified when a stateless request is made to the server. Thats my level of understanding. This sounds different to the basic authentication in apache where a password sits in a file and a username and the user needs to login to a basic form to get access to the folder/docs this is via an .htaccess file. Ok so with the LDAP to work I need to get REMOTE_USER this sounds very reasonable as how else do we know is making the request. Thank you.

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  • Question about using ServiceModelEx's "WCFLogbook" from "Programming WCF Services" book

    - by Bill
    I am attempting to compile/run a sample WCF application from Juval Lowy's website (author of Programming WCF Services & founder of IDesign). Of course the example application utilizes Juval's ServiceModelEx library and logs faults/errors to a "WCFLogbook" database. Unfortunately, when the sample app faults, I get the following new error: "Cannot open database "WCFLogbook" requested by the login. The login failed. Login failed for user 'Bill-PC\Bill'." I suspect the error occurs as a result of not finding the "WCFLogbook" database, which I believe still needs to be created. Included in the library source directory, there are two files -WCFLogbookDataSet.xsd and WCFLogbook.sql; which neither seem to be referenced anywhere within the library code. This leads me to beleive that the sql and xsd files are there to be used to create the database somehow in SQL. Could someone please advise me if I am going in the correct direction here and if whether these files can be used to create the database (and if so, how)?

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  • Linq-to-Sql IIS7 Login failed for user ‘DOMAIN\MACHINENAME$’

    - by cfdev9
    I am encountering unexpected behaviour using Linq-to-sql DataContext. When I run my application locally it works as expected however after deploying to a test server which runs IIS7, I get an error Login failed for user ‘DOMAIN\MACHINENAME$’ when attempting to open objects from the DataContext. This code explains the error, which breaks on the very last line with the error "System.Data.SqlClient.SqlException: Login failed for user". var connStr ="Data Source=server;Initial Catalog=Test;User Id=testuser;Password=password"; //Test 1 var conn1 = new System.Data.SqlClient.SqlConnection(connStr); var cmdString = "SELECT COUNT(*) FROM Table1"; var cmd = new System.Data.SqlClient.SqlCommand(cmdString, conn1); conn1.Open(); var count1 = cmd.ExecuteScalar(); conn1.Close(); //Test 2 var conn2 = new System.Data.SqlClient.SqlConnection(connStr); var context = new TestDataContext(conn2); var count2 = context.Table1s.Count(); The connection string is not even using integrated security, so why is Linq-to-sql trying to connect as a specific user? If I change the server name in the connection string I get a different error so its using atleast part of the connection string, but apparently ignoring the UserId and Password. Very confused.

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  • Setting the Classpath and Accessing code from book: Programming Clojure

    - by user130153
    (I posted this same question on the Clojure list but haven't got an answer yet. Is anyone here ready to help?) I am going through Programming Clojure and I recently downloaded the code from the books official website. For other utils I can do, for example, (require 'clojure.contrib.str-utils) and it works. But how do I load code from the book? (require 'examples.introduction) throws the following exception: java.io.FileNotFoundException: Could not locate examples/ introduction__init.class or examples/introduction.clj on classpath: (NO_SOURCE_FILE:0) [Thrown class clojure.lang.Compiler$CompilerException] Here is the full backtrace: Backtrace: 0: clojure.lang.Compiler.eval(Compiler.java:4543) 1: clojure.core$eval__3990.invoke(core.clj:1728) 2: swank.commands.basic$eval_region__686.invoke(basic.clj:36) 3: swank.commands.basic$listener_eval__695.invoke(basic.clj:50) 4: clojure.lang.Var.invoke(Var.java:346) 5: user$eval__1200.invoke(NO_SOURCE_FILE) 6: clojure.lang.Compiler.eval(Compiler.java:4532) 7: clojure.core$eval__3990.invoke(core.clj:1728) 8: swank.core$eval_in_emacs_package__307.invoke(core.clj:55) 9: swank.core$eval_for_emacs__384.invoke(core.clj:123) 10: clojure.lang.Var.invoke(Var.java:354) 11: clojure.lang.AFn.applyToHelper(AFn.java:179) 12: clojure.lang.Var.applyTo(Var.java:463) 13: clojure.core$apply__3243.doInvoke(core.clj:390) 14: clojure.lang.RestFn.invoke(RestFn.java:428) 15: swank.core$eval_from_control__310.invoke(core.clj:62) 16: swank.core$eval_loop__313.invoke(core.clj:67) 17: swank.core$spawn_repl_thread__445$fn__476$fn__478.invoke(core.clj: 173) 18: clojure.lang.AFn.applyToHelper(AFn.java:171) 19: clojure.lang.AFn.applyTo(AFn.java:164) 20: clojure.core$apply__3243.doInvoke(core.clj:390) 21: clojure.lang.RestFn.invoke(RestFn.java:428) 22: swank.core$spawn_repl_thread__445$fn__476.doInvoke(core.clj:170) 23: clojure.lang.RestFn.invoke(RestFn.java:402) 24: clojure.lang.AFn.run(AFn.java:37) 25: java.lang.Thread.run(Unknown Source) I am trying both Clojure Box and Enclojure in NetBeans on Windows XP. Is it a classpath issue? Where should I place the folder that contains code from the book? Please help me out with my variable enviroment settings as well.

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  • Question on Scala Closure (From "Programming in Scala")

    - by Ekkmanz
    I don't understand why authors said that Code Listing 9.1 from "Programming in Scala" use closure. In chapter 9, they show how to refactor code into more less duplicated form, from this original code: object FileMatcher { private def filesHere = (new java.io.File(".")).listFiles def filesEnding(query: String) = for (file <- filesHere; if file.getName.endsWith(query)) yield file def filesContaining(query: String) = for (file <- filesHere; if file.getName.contains(query)) yield file def filesRegex(query: String) = for (file <- filesHere; if file.getName.matches(query)) yield file } To the second version: object FileMatcher { private def filesHere = (new java.io.File(".")).listFiles def filesMatching(query: String, matcher: (String, String) => Boolean) = { for (file <- filesHere; if matcher(file.getName, query)) yield file } def filesEnding(query: String) = filesMatching(query, _.endsWith(_)) def filesContaining(query: String) = filesMatching(query, _.contains(_)) def filesRegex(query: String) = filesMatching(query, _.matches(_)) } Which they said that there is no use of closure here. Now I understand until this point. However they introduced the use of closure to refactor even some more, shown in Listing 9.1: object FileMatcher { private def filesHere = (new java.io.File(".")).listFiles private def filesMatching(matcher: String => Boolean) = for (file <- filesHere; if matcher(file.getName)) yield file def filesEnding(query: String) = filesMatching(_.endsWith(query)) def filesContaining(query: String) = filesMatching(_.contains(query)) def filesRegex(query: String) = filesMatching(_.matches(query)) } Now they said that query is a free variable but I don't really understand why they said so? Since ""query"" seems to be passed from top method down to string matching function explicitly.

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  • How to Send user to two different web pages when login

    - by Pradeep
    protected static Boolean Authentication(string username, string password) { string sqlstring; sqlstring = "Select Username, Password, UserType from Userprofile WHERE Username='" + username + "' and Password ='" + password + "'"; // create a connection with sqldatabase System.Data.SqlClient.SqlConnection con = new System.Data.SqlClient.SqlConnection( "Data Source=PRADEEP-LAPTOP\\SQLEXPRESS;Initial Catalog=BookStore;Integrated Security=True"); // create a sql command which will user connection string and your select statement string System.Data.SqlClient.SqlCommand comm = new System.Data.SqlClient.SqlCommand(sqlstring, con); // create a sqldatabase reader which will execute the above command to get the values from sqldatabase System.Data.SqlClient.SqlDataReader reader; // open a connection with sqldatabase con.Open(); // execute sql command and store a return values in reade reader = comm.ExecuteReader(); // check if reader hase any value then return true otherwise return false if (reader.Read()) return true; else return false; } Boolean blnresult; blnresult = Authentication(Login2.UserName, Login2.Password); if (blnresult == true) { Session["User_ID"] = getIDFromName(Login2.UserName); Session["Check"] = true; Session["Username"] = Login2.UserName; Response.Redirect("Index.aspx"); } so a user like Staff or even Administrators loging to same Index.aspx. i want to change it to different web pages. how to change sites for each user types. i have seperate user types. and i have taken UserType in the Authentication function.

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  • Non-deprecated code for detecting whether a SharePoint User has a specific Permission Level

    - by ccomet
    In our application, we have some forms which need to show some data specifically if the current user has a specific permission level. These users belong to an SPGroup which includes users who should not see this data, so in this particular case I cannot filter based off of group membership. My current solution has been to use web.CurrentUser.Roles and use a simple check on whether it contains a permission level of the correct name. Roles is of the deprecated SPRole class, so I am bombarded with warning messages despite the fact it technically works. It suggests that I use SPRoleAssignment or SPRoleDefinition (the recommendation seems arbitrary since some lines recommend one while others recommend the other even though it is being used for the same thing). However, I cannot seem to find any method to directly retrieve an SPRoleAssignment or SPRoleDefinition object from an SPUser or SPPrincipal object, nor can I retrieve either object corresponding specifically to the current user of the SPWeb object. How can I update these methods to use non-deprecated code? I've found other cases of determining user permissions, but I haven't found one that will work from a starting point of the current web or the current user. It's not urgent, but it certainly is helpful to avoid having to sift through all of those warnings just to reach the more important warnings.

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  • Relative path from an ASP.NET user control NavigateUrl

    - by Daniel Ballinger
    I have a user control that contains a GridView. The GridView has both a HyperLinkField column and a template column that contains a HyperLink control. The ASP.NET project is structured as follows, with the Default.aspx page in each case using the user control. Application Root Controls UserControl with GridView SystemAdminFolder Default.aspx Edit.aspx OrganisationAdminFolder Default.aspx Edit.aspx StandardUserFolder Default.aspx Edit.aspx Note: The folders are being used to ensure the user has the correct role. I need to be able to set the DataNavigateUrlFormatString for the HyperLinkField and the NavigateUrl for the HyperLink to resolve to the Edit.aspx page in the corresponding folder. If I set the navigate URL to "Edit.aspx" the URL in the browser appears as 'http://Application Root/Controls/Edit.aspx' regardless of the originating directory. I can't use the Web application root operator (~/) as the path needs to be relative to the current page, not the application root. How can I use the same user control in multiple folders and resolve the URL to another page in the same folder? Note: The question is strongly based off a similar question by azhar2000s on the asp.net forums that matches my problem.

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