C: Proper syntax for allocating memory using pointers to pointers.
- by ~kero-05h
This is my first time posting here, hopefully I will not make a fool of myself.
I am trying to use a function to allocate memory to a pointer, copy text to the buffer, and then change a character. I keep getting a segfault and have tried looking up the answer, my syntax is probably wrong, I could use some enlightenment.
/* My objective is to pass a buffer to my Copy function, allocate room, and copy text to it. Then I want to modify the text and print it.*/
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int Copy(char **Buffer, char *Text);
int main()
{
char *Text = malloc(sizeof(char) * 100);
char *Buffer;
strncpy(Text, "1234567890\n", 100);
Copy(&Buffer, Text);
}
int Copy(char **Buffer, char *Text)
{
int count;
count = strlen(Text)+1;
*Buffer = malloc(sizeof(char) * count);
strncpy(*Buffer, Text, 5);
*Buffer[2] = 'A'; /* This results in a segfault. "*Buffer[1] = 'A';" results in no differece in the output. */
printf("%s\n", *Buffer);
}
