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  • MySQL : select/join on strings as fieldnames - is this possible?

    - by Dylan
    I can retrieve all column names from table 'categories' with : SELECT col.column_name FROM information_schema.columns AS col WHERE col.table_schema= database() and col.table_name = "categories" This produces a resultset like this : column_name ----------------- categoryID name description I can retrieve all values for a specific category with : SELECT * FROM categories AS c WHERE c.categoryID=12345 this results in a resultset like this: categoryID | name | description ------------------------------------------------ 12345 | test | this is a test Now I would like to get some kind of join of above selects to get a resultset that looks something like this : fieldname | value ---------------------------------------- categoryID | 12345 name | test description | this is a test Does anyone know if this is possible ? Can you do a join on strings that come from another select ?? The reason for this is that I'm writing a universal stored procedure that outputs all fields + their values from a table, without knowing what fields there are in the table. (The tablename is given in a parameter)

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  • There has to be an easier way.. pulling data from mysql

    - by Daniel Hunter
    I need to pull 3 values from a table and assign each one to a variable each value is based on to columns, a type and an id $ht_live_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='L'"); $ht_live_result = mysql_fetch_array($ht_live_query); $htCODE_Live = $ht_live_result['htcode']; You can see that I am assigning the desired value to the variable $htL $ht_General_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='G'"); $ht_General_result = mysql_fetch_array($ht_General_query); $htCODE_General = $ht_General_result['htcode']; $ht_Reward_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='R'"); $ht_Reward_result = mysql_fetch_array($ht_Reward_query); $htCODE_Reward = $ht_Reward_result ['htcode']; I know I am doing this the hard way but can not figure out how to do the foreach or while loop to attain the desired results.

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  • Having trouble comparing a range of dates entered in a form with records in a mySQL database

    - by Andrew Fox
    I have a table called schedule and a column called Date where the column type is date. In that column I have a range of dates, which is currently from 2012-11-01 to 2012-11-30. I have a small form where the user can enter a range of dates (input names from and to) and I want to be able to compare the range of dates with the dates currently in the database. This is what I have: //////////////////////////////////////////////////////// //////First set the date range that we want to use////// //////////////////////////////////////////////////////// if(isset($_POST['from']) && ($_POST['from'] != NULL)) { $startDate = $_POST['from']; } else { //Default date is Today $startDate = date("Y-m-d"); } if(isset($_POST['to']) && ($_POST['to'] != NULL)) { $endDate = $_POST['to']; } else { //Default day is one month from today $endDate = date("Y-m-d", strtotime("+1 month")); } ////////////////////////////////////////////////////////////////////////////////////// //////Next calculate the total amount of days selected above to use as a limiter////// ////////////////////////////////////////////////////////////////////////////////////// $dayStart = strtotime($startDate); $dayEnd = strtotime($endDate); $total_days = abs($dayEnd - $dayStart) / 86400 +1; echo "Start Date: " . $startDate . "<br>End Date: " . $endDate . "<br>"; echo "Day Start: " . $dayStart . "<br>Day End: " . $dayEnd . "<br>"; echo "Total Days: " . $total_days . "<br>"; //////////////////////////////////////////////////////////////////////////////////// //////Then we're going to see if the dates selected are in the schedule table////// //////////////////////////////////////////////////////////////////////////////////// //Select all of the dates currently in the schedule table between the range selected. $sql = ("SELECT Date FROM schedule WHERE Date BETWEEN '$startDate' AND '$endDate' LIMIT $total_days"); //Run a check on the query to make sure it worked. If it failed then print the error. if(!$result_date_query = $mysqli->query($sql)) { die('There was an error getting the dates from the schedule table [' . $mysqli->error . ']'); } //Set the dates to an array for future use. // $current_dates = $result_date_query->fetch_assoc(); //Loop through the results while a result is being returned. while($row = $result_date_query->fetch_assoc()) { echo "Row: " . $row['Date'] . "<br>"; echo "Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Set this loop to add 1 day to the Start Date until it reaches the End Date for($i = $dayStart; $i <= $dayEnd; $i = strtotime('+1 day', $i)) { $date = date('Y-m-d',$i); echo "Loop Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Run a check to see if any of the dates selected are in the schedule table. if($row['Date'] != $date) { echo "Current Date: " . $row['Date'] . "<br>"; echo "Date: " . $date . "<br>"; echo "It appears as though you've selected some dates that are not in the schedule database.<br>Please correct the issue and try again."; return; } } } //Free the result so something else can use it. $result_date_query->free(); As you can see I've added in some echo statements so I can see what is being produced. From what I can see it looks like my $row['Date'] is not incrementing and staying at the same date. I originally had it set to a variable (currently commented out) but I thought that could be causing problems. I have created the table with dates ranging from 2012-11-01 to 2012-11-15 for testing and entered all of this php code onto phpfiddle.org but I can't get the username provided to connect. Here is the link: PHP Fiddle I'll be reading through the documentation to try and figure out the user connection problem in the meantime, I would really appreciate any direction or advice you can give me.

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  • Compare two tables rows and remove if match

    - by Istvan
    Could anyone help me please in JQuery? I have two tables on my site leftTable and rightTable with same column names. The leftTable I fill up from a DB, but the rightTable it just contains some rows. What I would like to do is to not show (or remove) in the leftTable those rows which are exist in the rightTable! I Tryed this: $("#tableLeft tr").each(function () {if ($(this).find("td")[0].innerHTML == $("#tableRight tr").find("td")[0].innerHTML) {$(this).remove;}});

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  • Implementing Tagging System with PHP and mySQL. Caching help!!!

    - by Hamid Sarfraz
    With reference to this post: http://stackoverflow.com/questions/2122546/how-to-implement-tag-counting I have implemented the suggested 3 table tagging system completely. To count the number of Articles per tag, i am using another column named tagArticleCount in the tag definition table. (other columns are tagId, tagText, tagUrl, tagArticleCount). If i implement realtime editing of this table, so that whenever user adds another tag to article or deletes an existing tag, the tag_definition_table is updated to update the counter of the added/removed tag. This will cost an extra query each time any modification is made. (at the same time, related link entry for tag and article is deleted from tagLinkTable). An alternative to this is not allowing any real time editing to the counter, instead use CRONs to update counter of each tag after a specified time period. Here comes the problem that i want to discuss. This can be seen as caching the article count in database. Can you please help me find a way to present the articles in a list when a tag is explored and when the article counter for that tag is not up to date. For example: 1. Counter shows 50 articles, but there are infact 55 entries in the tag link table (that links tags and articles). 2. Counter shows 50 articles, but there are infact 45 extries in the tag link table. How to handle these 2 scenerios given in example. I am going to use APC to keep cache of these counters. Consider it too in your solution. Also discuss performance in the realtime / CRONNED counter updates.

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  • Moving from MySQL to MySQLi? I have the code here but I don't get it

    - by MuqMan
    I have posted the code there, please help me out as I am a newbie, I don't know much in terms of deprecation and stuff. <?php session_start(); include('settings.php'); $issub = $_POST['issub']; if($issub == "yes") { require('settings.php'); $dbcon = mysql_connect($dbhost, $dbuser, $dbpword); if(!dbcon) { die('Could not connect'.mysql_error()); } $selectdb = mysql_select_db($db, $dbcon); $formset = 'yes'; $val = 0; $user = trim($_POST['username'], ' '); $luser = mysql_real_escape_string($user); $password = $_POST['password']; $lpassword = mysql_real_escape_string($password); $selectdb; $userq = mysql_query("SELECT user FROM users WHERE user='".$luser."'"); $userresult = @mysql_result($userq, 0); //echo $userresult; if($userresult == $user) { $val = $val + 1; $usercorrect = 'yes'; } else { $usercorrect = 'no'; } $dbselect; $passwordq = mysql_query("SELECT password FROM users where user='".$luser."'"); $passresult = @mysql_result($passwordq, 0); if($passresult == sha1($password)) { $val = $val + 1; $passcorrect = 'yes'; } else { $passcorrect = 'no'; } if ($val == 2) { $_SESSION['loggedin'] = 'yes'; $_SESSION['uloggedin'] = $user; header('location: logged.php'); } }?> <?php ini_set('display_errors', 1); require('testinclude.php'); ?> <body> <div id="loginform"> <form action="/login.php" method="post" > <input type="hidden" name="issub" value="yes" /> <?php if($usercorrect == 'no') { echo '<span class="required"><i><small>The email address or password you entered is incorrect, please try again.</a></small></i></span>'; } ?> <br /> email: <?php if ($issub == 'yes') { if($user == null){ echo '<br /><span class="required"><i><small>Please enter your email address</a></small></i></span>'; } } ?> <br /><input type="text" name="username" id="usename" /> <br /> password: <br /><input type="password" name="password" id="password" /> <br /> <input type="submit" value="login" /> </form> <div> </body>

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  • What is some good software for designing MySQL databases?

    - by franzferdinand
    As above. Usually at work someone else does the database design, and when I do personal projects they're small enough to not really require more than five or six tables, but I'm about to start a personal project that I think will probably require around eleven or twelve tables and I'd like something to help me design it neatly and keep track of it.

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  • Best Practice for Exporting an App's Data to XML via PHP/MySQL?

    - by Alex Cook
    I have an a business app and I want to give my users the ability to export their data at anytime. I'm aware that I can write an XML file semi-manually by doing something like this: http://www.kirupa.com/web/mysql_xml_php.htm But, I thought I'd ask if this is the best practice? Or is there some framework I can use to do this more easily/quickly? Maybe there isn't - it won't be too hard to do it the above way. Also, less importantly - XML is the best format to export to, right? Thanks in advance.

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  • Drupal 6: using too many Views module causing site to go down cos of too many mysql connection.

    - by artmania
    Hi friends, I have HostGator Baby Shared Plan . I develop Drupal site on. everything was fine at the beginning, then by the time i go further with development, site started ti work really slow. now it is not working at all. giving my sql errors like TOO many connections, etc... I created so many blocks, pages with View. so it makes my site to so much depend on database. should not I do that? can it be the reason of my site's no working now. appreciate helps!!!!

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  • Does MySQL allow two primary keys on one table?

    - by Bharanikumar
    CREATE TABLE Orders -> ( -> ID SMALLINT UNSIGNED NOT NULL, -> ModelID SMALLINT UNSIGNED NOT NULL, -> Descrip VARCHAR(40), -> PRIMARY KEY (ID, ModelID) -> ); Basically, this appears to me to be creating two primary key on one table. Is that correct? I thought that we could create a number of unique keys in one table, but only one primary key. How is it that my system is allowing the creation of multiple primary keys? Please advise: what are the rules governing this?

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  • mysql database design: thread and reply of a reply?

    - by ajsie
    in my forum i have threads and replies. one thread has multiple replies. but then, a reply can be a reply of an reply (like google wave). because of that a reply has to have a column "reply_id" so it can point to the parent reply. but then, the "top-level" replies (the replies directly under the thread) will have no parent reply. so how can i fix this? how should the columns be in the reply table (and thread table). at the moment it looks like this: threads: id title body replies: id thread_id (all replies will belong to a thread) reply_id (here lies the problem. the top-level replies wont have a parent reply) body what could a smart design look like to enable reply a reply?

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  • Why does this sql statement keep saying it is a boolean and not a paramter? (php/Mysql)

    - by ggfan
    In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

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  • New to CakePHP -> How To Add Columns To a MySQL Table?

    - by walden
    I had a website made for me a long time ago, and the programmer did it in CakePHP. I'm now editing his scripts. I added a couple columns to a table, and found that doing saveField() on the new column does not do anything. How do I make CakePHP recognize the new columns? I'd appreciate your help. I'm not too familiar with CakePHP, so please go easy on me =)

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  • Mysql - Help me alter this query to apply AND logic instead of OR in searching?

    - by sandeepan-nath
    First execute these tables and data dumps :- CREATE TABLE IF NOT EXISTS `Tags` ( `id_tag` int(10) unsigned NOT NULL auto_increment, `tag` varchar(255) default NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=18 ; INSERT INTO `Tags` (`id_tag`, `tag`) VALUES (1, 'key1'), (2, 'key2'); CREATE TABLE IF NOT EXISTS `Tutors_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_tutor` int(10) default NULL, KEY `Tutors_Tag_Relations` (`id_tag`), KEY `id_tutor` (`id_tutor`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Tutors_Tag_Relations` (`id_tag`, `id_tutor`) VALUES (1, 1), (2, 1); The following query finds all the tutors from Tutors_Tag_Relations table which have reference to at least one of the terms "key1" or "key2". SELECT td . * FROM Tutors_Tag_Relations AS td INNER JOIN Tags AS t ON t.id_tag = td.id_tag WHERE t.tag LIKE "%key1%" OR t.tag LIKE "%key2%" Group by td.id_tutor LIMIT 10 Please help me modify this query so that it returns all the tutors from Tutors_Tag_Relations table which have reference to both the terms "key1" and "key2" (AND logic instead of OR logic). Please suggest an optimized query considering huge number of data records (the query should NOT individually fetch two sets of tutors matching each keyword and then find the intersection).

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  • Drawing up a session value within SQL query? PHP and MySQL

    - by Derek
    Hi, on one of my web pages I want my manager user to view all activities assigned to them (personally). In order to do this, I need something like this: $sql = "SELECT * FROM activities WHERE manager = $_SESSION['SESS_FULLNAME']"; Now obviously this syntax is all wrong, but because I am new to this stuff, is there a way I can call up the full name from the user's session within a query? This is so that when I call up the database values to be displayed within the web page, only the activities for the manager who is logged in is displayed. For example, the activities table has a manager column of a full name entry. Any help is much appreciated. Thanks.

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  • MySQL: selecting totals as three fields from same table as one query?

    - by coderama
    I have a table with various orders in it: ID | Date | etc... 1 | 2013-01-01 | etc 2 | 2013-02-01 | etc 3 | 2013-03-01 | etc 4 | 2013-04-01 | etc 5 | 2013-05-01 | etc 6 | 2013-06-01 | etc 7 | 2013-06-01 | etc 8 | 2013-03-01 | etc 9 | 2013-04-01 | etc 10 | 2013-05-01 | etc I want a query that ends wit the result: overallTotal | totalThisMonth | totalLastMonth 10 | 2 | 1 But I want to do this in one query! I am trying to find a way to use subqueries to do this. SO far I have: SELECT * from ( SELECT count(*) as overallTotal from ORDERS ) How can I combine this with other subqueries so I can get the totals in one query?

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  • Why is only 2 of my querys working? (PHP/Mysql)

    - by ggfan
    When I remove a posting, I want it to remove the posting itself, any comments related to it, and like/dislike of the comments, and favorites that people added. So there are 4 queries that do this, but somehow only 2 of the 4 are working. When I switch say query 2 for query 3, then query 2 works and query 3 doesn't... The table names are correct and it is getting the data via $_GET. // Grab the data from the GET $posting_id = $_GET['posting_id']; // Delete the posting from the database $query = "DELETE FROM posting WHERE posting_id=$posting_id LIMIT 1"; mysqli_query($dbc, $query) or die(mysql_error()); // Delete the comments $query2 = "DELETE FROM comments WHERE posting_id=$posting_id "; mysqli_query($dbc, $query2) or die(mysql_error()); // Delete the like/dislike $query3 = "DELETE FROM comment_likedislike WHERE posting_id=$posting_id "; mysqli_query($dbc, $query3) or die(mysql_error()); // Delete the favorites $query4 = "DELETE FROM favorite WHERE posting_id=$posting_id "; mysqli_query($dbc, $query4) or die(mysql_error());

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  • Mysql Query is not working in edited jTable code, why?

    - by Furkan Kadioglu
    I'm using this example: www.jtable.org I've downloaded the jTable PHP version. I then edited the script. The jTable simple version is working, but my edited version isn't. I can create a list, but I can't add a row; this code is causing problems. However, PHP doesn't display any error messages. else if($_GET["action"] == "create") { //Insert record into database $result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'"); //Get last inserted record (to return to jTable) $result = mysql_query("SELECT * FROM veriler WHERE id = LAST_INSERT_ID();"); $row = mysql_fetch_array($result); //Return result to jTable $jTableResult = array(); $jTableResult['Result'] = "OK"; $jTableResult['Record'] = $row; print json_encode($jTableResult); } What is the problem?

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