Search Results

Search found 59194 results on 2368 pages for 'depth first search'.

Page 260/2368 | < Previous Page | 256 257 258 259 260 261 262 263 264 265 266 267  | Next Page >

  • DotNetNuke + XPath = Custom navigation menu DNNMenu HTML render

    - by Rui Santos
    I'm developing a skin for DotNetNuke 5 using the Component DNN Done Right menu by Mark Alan which uses XSL-T to convert the XML sitemap into an HTML navigation. The XML sitemap outputs the following structure: <Root > <root > <node id="40" text="Home" url="http://localhost/dnn/Home.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="0" > <node id="58" text="Child1" url="http://localhost/dnn/Home/Child1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="1" > <keywords >Child1</keywords> <description >Child1</description> <node id="59" text="Child1 SubItem1" url="http://localhost/dnn/Home/Child1/Child1SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child1 SubItem1</keywords> <description >Child1 SubItem1</description> </node> <node id="60" text="Child1 SubItem2" url="http://localhost/dnn/Home/Child1/Child1SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="0" only="0" depth="2" > <keywords >Child1 SubItem2</keywords> <description >Child1 SubItem2</description> </node> <node id="61" text="Child1 SubItem3" url="http://localhost/dnn/Home/Child1/Child1SubItem3.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child1 SubItem3</keywords> <description >Child1 SubItem3</description> </node> </node> <node id="65" text="Child2" url="http://localhost/dnn/Home/Child2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="1" > <keywords >Child2</keywords> <description >Child2</description> <node id="66" text="Child2 SubItem1" url="http://localhost/dnn/Home/Child2/Child2SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child2 SubItem1</keywords> <description >Child2 SubItem1</description> </node> <node id="67" text="Child2 SubItem2" url="http://localhost/dnn/Home/Child2/Child2SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child2 SubItem2</keywords> <description >Child2 SubItem2</description> </node> </node> </node> </root> </Root> My Goal is to render this XML block into this HTML Navigation structure only using UL's LI's, etc.. <ul id="topnav"> <li> <a href="#" class="home">Home</a> <!-- Parent Node - Depth0 --> <div class="sub"> <ul> <li><h2><a href="#">Child1</a></h2></li> <!-- Parent Node 1 - Depth1 --> <li><a href="#">Child1 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem2</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem3</a></li ><!-- ChildNode - Depth2 --> </ul> <ul> <li><h2><a href="#">Child2</a></h2></li> <!-- Parent Node 2 - Depth1 --> <li><a href="#">Child2 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child2 SubItem2</a></li> <!-- ChildNode - Depth2 --> </ul> </div> </li> </ul> Can anyone help with the XSL coding? I'm just starting now with XSL..

    Read the article

  • Does the 'dynamic' keyword and the DLR promote C# to a first class citizen as a dynamically typed la

    - by Quigrim
    I understand that the new ‘dynamic’ keyword in C# 4.0 facilitates interaction with dynamic .NET languages, and can help to cut code by using it instead of reflection. So usage is for very specific situations. However, what I would like to know is if it will give C# all the dynamic benefits that one would get in other dynamic languages such is the IronXXX languages? In other words, will it be possible to write a entire application in C# in a dynamic language style? And if it is possible, would it be recommended or not. And why, or why not respectively? Will I get all the benefits of a dynamic language without switching to another language?

    Read the article

  • Parsec Haskell Lists

    - by Martin
    I'm using Text.ParserCombinators.Parsec and Text.XHtml to parse an input and get a HTML output. If my input is: * First item, First level ** First item, Second level ** Second item, Second level * Second item, First level My output should be: <ul><li>First item, First level <ul><li>First item, Second level </li><li>Second item, Second level </li></ul></li><li>Second item, First level</li></ul> I wrote this, but obviously does not work recursively list= do{ s <- many1 item;return (olist << s) } item= do{ (count 1 (char '*')) ;s <- manyTill anyChar newline ;return ( li << s) } Any ideas? the recursion can be more than two levels Thanks!

    Read the article

  • CouchDB Map/Reduce raises execption in reduce function?

    - by fuzzy lollipop
    my view generates keys in this format ["job_id:1234567890", 1271430291000] where the first key element is a unique key and the second is a timestamp in milliseconds. I run my view with this elapsed_time?startkey=["123"]&endkey=["123",{}]&group=true&group_level=1 and here is my reduce function, the intention is to reduce the output to get the earliest and latest timestamps and return the difference between them and now function(keys,values,rereduce) { var now = new Date().valueOf(); var first = Number.MIN_VALUE; var last = Number.MAX_VALUE; if (rereduce) { first = Math.max(first,values[0].first); last = Math.min(last,values[0].last); } else { first = keys[0][0][1]; last = keys[keys.length-1][0][1]; } return {first:now - first, last:now - last}; } and when processing a query it constantly raises the following execption: function raised exception (new TypeError("keys has no properties", "", 1)) I am making sure not to reference keys inside my rereduce block. Why does this function constantly raise this exception?

    Read the article

  • Ruby: Is there a way to split a string only with the first x occurrencies?

    - by zxcvbnm
    For example, suppose I have this: 001, "john doe", "male", 37, "programmer", "likes dogs, women, and is lazy" The problem is that the line is only supposed to have 6 fields. But if I separate it with split I get more, due to the comma being used improperly to separate the fields. Right now I'm splitting everything, then when I get to the 5-th index onward I concatenate all the strings. But I was wondering if there was a split(",",6) or something along these lines.

    Read the article

  • What's your "best practice" for the first Java EE Spring project?

    - by cringe
    I'm currently trying to get into the Java EE development with the Spring framework. As I'm new to Spring, it is hard to imaging how a good running project should start off. Do you have any best practices, tipps or major DO NOTs for a starter? How did you start with Spring - big project or small tutorial-like applications? Which technology did you use right away: AOP, complex Hibernate...

    Read the article

  • How to select the first element of a set with JSTL?

    - by Sergio del Amo
    I managed to do it with the next code but there must be an easier way. <%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %> <%@ taglib prefix="fn" uri="http://java.sun.com/jsp/jstl/functions" %> <c:if test="${fn:length(attachments) > 0}"> <c:forEach var="attachment" items="${attachments}" varStatus="loopCount"> <c:if test="${loopCount.count eq 1}"> attachment.id </c:if> </c:forEach> </c:if>

    Read the article

  • How can I match at the beginning of any line, including the first, with a Perl regex?

    - by JoelFan
    According the the Perl documentation on regexes: By default, the "^" character is guaranteed to match only the beginning of the string ... Embedded newlines will not be matched by "^" ... You may, however, wish to treat a string as a multi-line buffer, such that the "^" will match after any newline within the string ... you can do this by using the /m modifier on the pattern match operator. The "after any newline" part means that it will only match at the beginning of the 2nd and subsequent lines. What if I want to match at the beginning of any line (1st, 2nd, etc.)? EDIT: OK, it seems that the file has BOM information (3 chars) at the beginning and that's what's messing me up. Any way to get ^ to match anyway? EDIT: So in the end it works (as long as there's no BOM), but now it seems that the Perl documentation is wrong, since it says "after any newline"

    Read the article

  • How do I ensure only the headers are shown for the first item in an ItemsControl in WPF?

    - by Dan Ryan
    I am using MVVM binding an ObservableCollection of children to an ItemsControl. The ItemsControl contains a UserControl used to style the UI for the children. <ItemsControl ItemsSource="{Binding Documents}"> <ItemsControl.ItemTemplate> <DataTemplate> <View:DocumentView Margin="0, 10, 0, 0" /> </DataTemplate> </ItemsControl.ItemTemplate> </ItemsControl> I want to show a header row for the contents of the ItemsControl but only want to show this once at the top (not for every child). How can I implement this behaviour in the DocumentView user control? Fyi I am using a Grid layout to style the child rows: <Grid> <Grid.ColumnDefinitions> <ColumnDefinition Width="34"/> <ColumnDefinition Width="100"/> <ColumnDefinition Width="*" /> <ColumnDefinition Width="60" /> </Grid.ColumnDefinitions> <Grid.RowDefinitions> <RowDefinition /> <RowDefinition /> </Grid.RowDefinitions> <TextBlock Grid.ColumnSpan="4" Grid.Row="0" Text="Should only show this at the top"></TextBlock> <Image Grid.Column="0" Grid.Row="1" Height="24" Width="24" Source="/Beazley.Documents.Presentation;component/Icons/error.png"></Image> <ComboBox Grid.Column="1" Grid.Row="1" Name="ContentTypes" ItemsSource="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type View:MainView}}, Path=DataContext.ContentTypes}" SelectedValue="{Binding ContentType}"/> <TextBox Grid.Column="2" Grid.Row="1" Text="{Binding Path=FileName}"/> <Button Grid.Column="3" Grid.Row="1" Command="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type View:MainView}}, Path=DataContext.RemoveFile}" CommandParameter="{Binding}">Remove</Button> </Grid>

    Read the article

  • JSON: How do I alert the name of the first node in level 1 in this code snippet?

    - by user143805
    var response = "{\"tree\":[{\"level1\":[{\"node\":{\"id\": 1,\"name\": \"paradox\",\"parent\": 0}}]},{\"level2\":[{\"node\":{\"id\": 2,\"name\": \"lucent\",\"parent\": 1}},{\"node\":{\"id\": 3,\"name\": \"reiso\",\"parent\": 1}}]},{\"level3\":[{\"node\":{\"id\": 4,\"name\": \"pessi\",\"parent\": 3}},{\"node\":{\"id\": 5,\"name\": \"misho\",\"parent\": 2}}]},{\"level4\":[{\"node\":{\"id\": 6,\"name\": \"hema\",\"parent\": 5}},{\"node\":{\"id\": 7,\"name\": \"iiyo\",\"parent\": 4}}]}]}"; var data = eval("(" + response + ")"); This is a dummy json response I am currently testing. Now how do I get the value of "name" in the 1st node of "level1" from the "tree"? Thanks

    Read the article

  • UITableViewIndex Grows to Incorrect Bounds Unexpectedly

    - by chadburggraf
    I have a standard UITableView + UISearchDisplayController + UITableViewIndex setup. Everything works like a champ. Except, under very specific conditions, the index grows too long to display on the screen. Specifically, after ending a search and re-displaying the unfiltered, indexed table, the index sometimes grows too long. More specifically, this doesn't happen if I search then cancel. It only happens if I search, then push a view controller from the search table, then pop that view controller back to the still-searching table, then cancel the search, then re-search and then cancel that final search. After the end of the final search the index is too long. In portrait, the table view is reporting a height of 416 and the index a height of 404 under normal conditions. If I log from searchDisplayControllerDidEndSearch when the index is sized incorrectly, it is reporting a height of 620. I've tried everything from setLayout on the table and the index to manually re-sizing the frame. Nothing works (the manual re-size causes the correct height to be logged, but it doesn't change the display on screen). I was about to try re-sizing after a delay in case the cancel animation was interfering, but then I realized what an absurd situation I'm in and thought seeking help might be wise...

    Read the article

  • whJavaScript: how to create a JS event that requires 2 seperate JS files to be loaded first while d

    - by Teddyk
    I want to perform asynchronous JavaScript downloads of two files that have dependencies attached to them. function addScript(url) { var script = document.createElement('script'); script.src = url; document.getElementsByTagName('head')[0].appendChild(script); } addScript('http://google.com/gmaps.js'); addScript('http://jquery.com/jquery.js'); function requiresJQuery() { ... } function requiresGmaps() { ... } function requiresBothJQueryGmaps() { ... } // do some work that has no dependencies on either JQuery or Google maps ... // now call a function that requires Gmaps to be loaded if (GmapsIsLoaded) { requiresGmaps(); } // then do something that requires both JQuery & Gmaps (or wait until they are loaded) if (JQueryAndGmapsIsLoaded) { requiresBothJQueryGmaps(); } Question: How can I create an event to indicate when: JQuery is loaded? Google Maps is loaded JQuery & Google Maps are both loaded?

    Read the article

  • .each or search function, how can I make use of those?

    - by Noor
    I have a ul list, with 10 items, and I have a label that displays the selected li text. When I click a button, I need to check the label, versus all the list items to find the matching one, when it finds that I need to assign the corresponding number. I.e. list: Messi Cristiano Zlatan hidden values of list items: www.messi.com www.cronaldo.com www.ibra.com label: Zlatan script (thought)procces: get label text, search list for matching string, get the value of that string. (and if someone could point me in a direction to learn these basic(?) stuff. tried to be as specific as possible, thanks guys! edit: really sorry for not being clear. the li's are all getting a class dynamically (.listitem). the links can be stored in an array or in a hidden field (or other ul thats hidden) it doesn't really matter where the links are.. $('.listitem').click(function() { $("#elname").text($(this).text()); $("#such").attr("href", $(this).attr('value')); }); I was trying that with the li's having values but I realized that li's can't have values.. thanks again!

    Read the article

  • How to redirect a URL with GET variables in routes.rb without Rails stripping out the variable first?

    - by Michael Hopkins
    I am building a website in Rails to replace an existing website. In routes.rb I am trying to redirect some of the old URLs to their new equivalents (some of the URL slugs are changing so a dynamic solution is not possible.) My routes.rb looks like this: match "/index.php?page=contact-us" => redirect("/contact-us") match "/index.php?page=about-us" => redirect("/about-us") match "/index.php?page=committees" => redirect("/teams") When I visit /index.php?page=contact-us I am not redirected to /contact-us. I have determined this is because Rails is removing the get variables and only trying to match /index.php. For example, If I pass /index.php?page=contact-us into the below routes I will be redirected to /foobar: match "/index.php?page=contact-us" => redirect("/contact-us") match "/index.php?page=about-us" => redirect("/about-us") match "/index.php?page=committees" => redirect("/teams") match "/index.php" => redirect("/foobar") How can I keep the GET variables in the string and redirect the old URLs the way I'd like? Does Rails have an intended mechanism for this?

    Read the article

  • Adding select menu default value via JS?

    - by purpler
    Hi, i'm developing a meta search engine website, Soogle and i've used JS to populate select menu.. Now, after the page is loaded none of engines is loaded by default, user needs to select it on his own or [TAB] to it.. Is there a possibility to preselect one value from the menu via JS after the page loads? This is the code: Javascript: // SEARCH FORM INIT function addOptions(){ var sel=document.searchForm.whichEngine;for(var i=0;i<arr.length;i++){ sel.options[i]=new Option(arr[i][0],i)}} function startSearch(){ searchString=document.searchForm.searchText.value;if(searchString!=""){ var searchEngine=document.searchForm.whichEngine.selectedIndex; var finalSearchString=arr[searchEngine][1]+searchString;location.href=finalSearchString}return false} function checkKey(e){ var character=(e.which)?e.which:event.keyCode;if(character=='13'){ return startSearch()}} // SEARCH ENGINES INIT var arr = new Array(); arr[arr.length] = new Array("Web", "http://www.google.com/search?q="); arr[arr.length] = new Array("Images", "http://images.google.com/images?q="); arr[arr.length] = new Array("Knoweledge","http://en.wikipedia.org/wiki/Special:Search?search="); arr[arr.length] = new Array("Videos","http://www.youtube.com/results?search_query="); arr[arr.length] = new Array("Movies", "http://www.imdb.com/find?q="); arr[arr.length] = new Array("Torrents", "http://thepiratebay.org/search/"); HTML: <body onload="addOptions();document.forms.searchForm.searchText.focus()"> <div id="wrapper"> <div id="logo"></div> <form name="searchForm" method="POST" action="javascript:void(0)"> <input name="searchText" type="text" onkeypress="checkKey(event);"/> <span id="color"></span> <select tabindex="1" name="whichEngine" selected="Web"></select> <br /> <input tabindex="2" type="button" onClick="return startSearch()" value="Search"/> </form> </div> </body>

    Read the article

  • which should be drawn first , class or sequence diagram?

    - by m0j1
    hi , I've had this discussion with my professor at college about UML diagrams . hi believes that sequence diagrams should be drawn before getting to class diagrams . but I think the opposite . I think after finishing the usecase diagram , the next diagram should be class diagram and after that we should get to sequence diagram . Rational rose requires us to use the classes in sequence diagram, which are already in class diagram . can anyone help me with this? thanks

    Read the article

  • Python opening a file and putting list of names on separate lines

    - by Jeremy Borton
    I am trying to write a python program using Python 3 I have to open a text file and read a list of names, print the list, sort the list in alphabetical order and then finally re-print the list. There's a little more to it than that BUT the problem I am having is that I'm supposed to print the list of names with each name on a separate line Instead of printing each name on a separate line, it prints the list all on one line. How can I fix this? def main(): #create control loop keep_going = 'y' #Open name file name_file = open('names.txt', 'r') names = name_file.readlines() name_file.close() #Open outfile outfile = open('sorted_names.txt', 'w') index = 0 while index < len(names): names[index] = names[index].rstrip('\n') index += 1 #sort names print('original order:', names) names.sort() print('sorted order:', names) #write names to outfile for item in names: outfile.write(item + '\n') #close outfile outfile.close() #search names while keep_going == 'y' or keep_going == 'Y': search = input('Enter a name to search: ') if search in names: print(search, 'was found in the list.') keep_going = input('Would you like to do another search Y for yes: ') else: print(search, 'was not found.') keep_going = input('Would you like to do another search Y for yes: ') main()

    Read the article

< Previous Page | 256 257 258 259 260 261 262 263 264 265 266 267  | Next Page >