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  • from loop to Nested loops ?

    - by WM
    I have this program that returns a factorial of N. For example, when entering 4,,, it will give 1! , 2! , 3! How could I convert this to use nested loops? public class OneForLoop { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Enter a number : "); int N = input.nextInt(); int factorial = 1; for(int i = 1; i < N; i++) { factorial *= i; System.out.println(i + "! = " + factorial); } } }

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  • Python instances and attributes: is this a bug or i got it totally wrong?

    - by Mirko Rossini
    Suppose you have something like this: class intlist: def __init__(self,l = []): self.l = l def add(self,a): self.l.append(a) def appender(a): obj = intlist() obj.add(a) print obj.l if __name__ == "__main__": for i in range(5): appender(i) A function creates an instance of intlist and calls on this fresh instance the method append on the instance attribute l. How comes the output of this code is: [0] [0, 1] [0, 1, 2] [0, 1, 2, 3] [0, 1, 2, 3, 4] ? If i switch obj = intlist() with obj = intlist(l=[]) I get the desired output [0] [1] [2] [3] [4] Why this happens? Thanks

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  • How can I do printing in Java with layouts instead of low level coordinates?

    - by Jonas
    I need to to some printing from my Java Swing application. I have tried to use Java Tutorials, but everything is very low level, and time-consuming. I have to specify the coordinates for every line that I want to print. It it also very lowlevel to use text, because I have to use FontMetrics and calculate what space all text fills up. Is there any easier way to to printing in Java? I would like to design the documents with something like layout managers instead. Any good library or API?

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  • Weird exception with delayed_job

    - by Tam
    Trying to queue a job with delayed_job as follows: Delayed::Job.enqueue(BackgroundProcess.new(current_user, object)) current_user and object are not nil when I print them out. The weird thing is that sometimes refreshing the page or running the command again works! Here is the exception trace: Delayed::Backend::ActiveRecord::Job Columns (44.8ms) SHOW FIELDS FROM `delayed_jobs` TypeError (wrong argument type nil (expected Data)): /Users/.rvm/rubies/ruby-1.9.1-p378/lib/ruby/1.9.1/yaml.rb:391:in `emit' /Users/.rvm/rubies/ruby-1.9.1-p378/lib/ruby/1.9.1/yaml.rb:391:in `quick_emit' /Users/.rvm/rubies/ruby-1.9.1-p378/lib/ruby/1.9.1/yaml/rubytypes.rb:86:in `to_yaml' vendor/plugins/delayed_job/lib/delayed/backend/base.rb:65:in `payload_object=' activerecord (2.3.9) lib/active_record/base.rb:2918:in `block in assign_attributes' activerecord (2.3.9) lib/active_record/base.rb:2914:in `each' activerecord (2.3.9) lib/active_record/base.rb:2914:in `assign_attributes' activerecord (2.3.9) lib/active_record/base.rb:2787:in `attributes=' activerecord (2.3.9) lib/active_record/base.rb:2477:in `initialize' activerecord (2.3.9) lib/active_record/base.rb:725:in `new' activerecord (2.3.9) lib/active_record/base.rb:725:in `create' vendor/plugins/delayed_job/lib/delayed/backend/base.rb:21:in `enqueue'

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  • Add the "selected" attribute to a drop down option with jQuery

    - by gaoshan88
    How do I add the attribute "selected" to a drop down menu option based on that option matching some variable? Here is how the dropdown is populated... loginOptions = ["First", "Second", "Third]; var Login = $( '#Login' ); for ( var i = 0; i < loginOptions.length; i++ ) { Login.append('<option value="'+ loginOptions[i] +'">'+ loginOptions[i] +'</option>'); } I want to mark one option as "selected" based on whether or not its value matches another variable. so if loginOption[i] is equal to var existingLoginValue then set that option to 'selected' Something that would do if(loginOptions[i] === existingLoginValue){ print 'selected'; }; Thanks!

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  • Can't get Facebook's user photos with php

    - by Liso22
    I'm trying to get the user photos, but I cannot get the user's photos data. I'm trying this: $photos = $facebook->api('https://graph.facebook.com/'.$profileFID.'/photos?access_token='.$access_token); print_r($photos); I'm sure the URL is correct since pasting it in the browser shows the photos array. However when I try to print the array to check if I got it I get only this: ( [id] => https://graph.facebook.com/1409006586/photos ) How can I get the full array with the user photos?

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  • LuaInterface: add a table to the script scope

    - by user93422
    Question: how can I insert a table from C# into 'LuaInterface' script scope using a C# object (preferably anonymous type)? /// I want to do this, but it does not work /// (complains that 'test' is userdata and not table /// when I pass it to pairs() in the script) //lua["test"] = new { A = 1, B = 2 }; /// another option /// but building this string is a PITA (actual string is nested and long). lua.DoString("test = { A = 1, B = 2 }"); // So I have to do this lua.NewTable("test"); ((LuaTable) lua["test"])["A"] = 1; ((LuaTable) lua["test"])["B"] = 2; lua.DoString("for k,v in pairs(test) do print(k..': '..v) end");

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  • Referenced vector does not pass through functions

    - by kylepayne
    The referenced vector to functions does not hold the information in memory. Do I have to use pointers? Thanks. #include <iostream> #include <cstdlib> #include <vector> #include <string> using namespace std; void menu(); void addvector(vector<string>& vec); void subvector(vector<string>& vec); void vectorsize(const vector<string>& vec); void printvec(const vector<string>& vec); void printvec_bw(const vector<string>& vec); int main() { vector<string> svector; menu(); return 0; } //functions definitions void menu() { vector<string> svector; int choice = 0; cout << "Thanks for using this program! \n" << "Enter 1 to add a string to the vector \n" << "Enter 2 to remove the last string from the vector \n" << "Enter 3 to print the vector size \n" << "Enter 4 to print the contents of the vector \n" << "Enter 5 ----------------------------------- backwards \n" << "Enter 6 to end the program \n"; cin >> choice; switch(choice) { case 1: addvector(svector); menu(); break; case 2: subvector(svector); menu(); break; case 3: vectorsize(svector); menu(); break; case 4: printvec(svector); menu(); break; case 5: printvec_bw(svector); menu(); break; case 6: exit(1); default: cout << "not a valid choice \n"; // menu is structured so that all other functions are called from it. } } void addvector(vector<string>& vec) { //string line; //int i = 0; //cin.ignore(1, '\n'); //cout << "Enter the string please \n"; //getline(cin, line); vec.push_back("the police man's beard is half-constructed"); } void subvector(vector<string>& vec) { vec.pop_back(); return; } void vectorsize(const vector<string>& vec) { if (vec.empty()) { cout << "vector is empty"; } else { cout << vec.size() << endl; } return; } void printvec(const vector<string>& vec) { for(int i = 0; i < vec.size(); i++) { cout << vec[i] << endl; } return; } void printvec_bw(const vector<string>& vec) { for(int i = vec.size(); i > 0; i--) { cout << vec[i] << endl; } return; }

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  • How to split up a long list using \n

    - by pypy
    Here is a long string that I convert to a list so I can manipulate it, and then join it back together. I am having some trouble being able to have an iterator go through the list and when the iterator reach, let us say every 5th object, it should insert a '\n' right there. Here is an example: string = "Hello my name is Josh I like pizza and python I need this string to be really really long" string = string.split() # do the magic here string = ' '.join(string) print(string) Output: Hello my name is Josh I like pizza and python I need this string to be really really long Any idea how i can achieve this? I tried using: for words in string: if words % 5 == 0: string.append('\n') but it doesn't work. What am I missing?

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  • stuck in while loop python

    - by user1717330
    I am creating a chat server in python and got quite far as a noob in the language. I am having 1 problem at the moment which I want to solve before I go further, but I cannot seem to find how to get the problem solved. It is about a while loop that continues.. in the below code is where it goes wrong while 1: try: data = self.channel.recv ( 1024 ) print "Message from client: ", data if "exit" in data: self.channel.send("You have closed youre connection.\n") break except KeyboardInterrupt: break except: raise When this piece of code get executed, on my client I need to enter "exit" to quit the connection. This works as a charm, but when I use CTRL+C to exit the connection, my server prints "Message from client: " a couple of thousand times. where am I going wrong?

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  • Python implementation of avro slow?

    - by lazy1
    I'm reading some data from avro file using the avro library. It takes about a minute to load 33K objects from the file. This seem very slow to me, specially with the Java version reading the same file in about 1sec. Here is the code, am I doing something wrong? import avro.datafile import avro.io from time import time def load(filename): fo = open(filename, "rb") reader = avro.datafile.DataFileReader(fo, avro.io.DatumReader()) for i, record in enumerate(reader): pass return i + 1 def main(argv=None): import sys from argparse import ArgumentParser argv = argv or sys.argv parser = ArgumentParser(description="Read avro file") start = time() num_records = load("events.avro") end = time() print("{0} records in {1} seconds".format(num_records, end - start)) if __name__ == "__main__": main()

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  • Question about pipe in Perl

    - by Uri
    The following code is working sort of fine: open( PIPE, '-|', 'ant' ); for( <PIPE> ) { print; } However, it doesn't do what I want. Since the Ant build can take 5 minutes, I would like to see the output line by line. Instead, I'm getting the entire input at the end of the process. Looking at it with the Perl debugger, Perl waits at the 'for' statement, until Ant terminates. Why is that?

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  • Semicolon in object variable name

    - by milkfilk
    There's a common LDAP attribute called userCertificate;binary. It actually has a semi-colon in the attribute name. In ruby, I turn an LDAP entry into a OpenStruct object called 'struct'. struct.class = OpenStruct But of course ruby thinks it's an end-of-line character. ? struct.userCertificate;binary NameError: undefined local variable or method `binary' for main:Object from (irb):52 from :0 IRB knows that the local variable is there, because it gives me struct.userCertificate;binary from the tab auto-completion. I can also see the class variable when calling struct.methods on it. struct.methods = ... "send", "methods", "userCertificate;binary=", "hash", ... It's definitely there, I can see the contents if I print the whole variable to_s(). But how can I access the local variable when it has a semicolon in it? I have workarounds for this but I thought it was an interesting problem to post.

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  • How do I reference members of a single object passed to the View?

    - by Juxtaposed
    I'm new to MVC2 in ASP.NET/C#, so please forgive me if I misunderstand something. I have code similar to this in my Controller: var singleInstance = new Person("John"); ViewData["myInstance"] = singleInstance; return View(); So in my view, Index.aspx, I want to be able to reference members in that object. For example, Person has a member called Name, which is set in the constructor. In the view I want to get Person.Name from what is stored in the ViewData object. Ex.: <%= ViewData["myInstance"].name %> That doesn't work. The only real workaround I've found is to do something like this: <% var thePerson = ViewData["myInstance"]; print (or whatever the method is) thePerson.Name; %> Any help would be much appreciated... This was so much easier in PHP/Zend Framework... sigh

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  • Ajax / GroovyGrails Post data coming over with unexpected leading character. Who is encoding/decod

    - by ?????
    I'm having an encoding issue, and I'm not sure where to look for the problem. I have this Ajax.Request function (prototype library) sending data to a Groovy/Grails encoder var myAjax = new Ajax.Request(url, {method:'post', encoding:'UTF-8', contentType:'application/x-www-form-urlencoded', parameters:{'content':new_content}, onSuccess:success, onFailure:failure}); The data is coming in with an unexpected %A0 at the beginning: I have this simple controller that just echos the content back: def titlechange = { def content = URLDecoder.decode(params['content']) printf("Content: %s; DecodedContent = %s\n", params['content'], content) response.characterEncoding='UTF-8' render content } the debug print statement shows: Content: %A0Hello%2C%20world%21; DecodedContent = †Hello, world! Where is that %A0 coming from? My grails configuration has this: // The default codec used to encode data with ${} grails.views.default.codec="none" // none, html, base64 grails.views.gsp.encoding="UTF-8" grails.converters.encoding="UTF-8 Is the issue on the grails side or on the JavaScript side?

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  • I Made Simple Generator,, Is there any faster way ??

    - by Rami Jarrar
    Hi, i do like this: import time f = open('wl4.txt', 'w') hh = 0 ###################################### for n in range(1,5): for l in range(33,127): if n==1: b = chr(l) + '\n' f.write(b) hh += 1 elif n==2: for s0 in range(33, 127): b = chr(l) + chr(s0) + '\n' f.write(b) hh += 1 elif n==3: for s0 in range(33, 127): for s1 in range(33, 127): b = chr(l) + chr(s0) + chr(s1) + '\n' f.write(b) hh += 1 elif n==4: for s0 in range(33, 127): for s1 in range(33, 127): for s2 in range(33,127): b = chr(l) + chr(s0) + chr(s1) + chr(s2) + '\n' f.write(b) hh += 1 ###################################### print "We Made %d Words." %(hh) ###################################### f.close() So, is there any faster method to make it faster,,

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  • Cast Object to JTable?

    - by Chris
    I am trying to implement a ListSelectionListener for some of my JTables. Simply (at the moment) the ListSelectionListener is supposed to simply return the text of the cell that was selected. My program design has several JTables and I would like to have one ListSelectionListener work for them all. In the valueChanged event of the ListSelectionListener I thought it was possible to do something like: private class SelectionHandler implements ListSelectionListener { public void valueChanged(ListSelectionEvent e) { JTable table = (JTable)e.getSource(); String data = (String) table.getValueAt(table.getSelectedRow(), 0); // Print data } } But when I do this I a ClassCastException error. Is there a way to do something like this? One solution I thought of was to compare the source of the event (e.getSource()) to all my JTables to see if they were equivalent (big if block) and then just calling .getValueAt inside that block but that would making the code in the future difficult if tables were to be added or removed.

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  • Passing value from :locals to link_remote_to

    - by Teef L
    In my edit.haml file, I have =render :partial => 'old_question_tags', :locals => {:current_question => @question.id}. I'd like to pass the value in :current_question to a link_to_remote call in _old_question_tags.haml: #{link_to_remote image_tag('red-x.png', {:alt => "Remove #{t.name} tag"}), :url => {:action => 'remove_old_tag_from_question', :tag_remove => t.id, :current_question => current_question}} But I get this error on the link_to_remote line: ActionView::TemplateError (undefined local variable or method `current_question' for #<ActionView::Base:0xdb2fec8>) In _old_question_tags.haml, if I just print current_question (using =current_question), it prints the number without any problems. How do I properly pass that value to the partial so that I can pass it to the link_to_remote call?

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  • get entire line with java.util.scanner.hasNext(regex)

    - by Hussain
    I'm doing something in Java that requires input to be matched against the pattern ^[1-5]$. I should have a while loop looping through each line of input, checking it against the pattern, and outputting an error message if it does not. Sudo code: while (regex_match(/^[^1-5]$/,inputLine)) { print ("Please enter a number between 1 and 5! "); getNextInputLine(); } I can use java.util.Scanner.hasMatch("^[^1-5]$"), but that will only match a single token, not the entire line. Any idea on how to make hasMatch match against the entire line? (Setting the delimiter to "\n" or "\0" doesn't work.)

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  • How refresh a DrawingArea in PyGTK ?

    - by Lialon
    I have an interface created with Glade. It contains a DrawingArea and buttons. I tried to create a Thread to refresh every X time my Canva. After a few seconds, I get error messages like: "X Window Server 0.0", "Fatal Error IO 11" Here is my code : import pygtk pygtk.require("2.0") import gtk import Canvas import threading as T import time import Map gtk.gdk.threads_init() class Interface(object): class ThreadCanvas(T.Thread): """Thread to display the map""" def __init__(self, interface): T.Thread.__init__(self) self.interface = interface self.started = True self.start() def run(self): while self.started: time.sleep(2) self.interface.on_canvas_expose_event() def stop(self): self.started = False def __init__(self): self.interface = gtk.Builder() self.interface.add_from_file("interface.glade") #Map self.map = Map.Map(2,2) #Canva self.canvas = Canvas.MyCanvas(self.interface.get_object("canvas"),self.game) self.interface.connect_signals(self) #Thread Canvas self.render = self.ThreadCanvas(self) def on_btnChange_clicked(self, widget): #Change map self.map.change() def on_interface_destroy(self, widget): self.render.stop() self.render.join() self.render._Thread__stop() gtk.main_quit() def on_canvas_expose_event(self): st = time.time() self.canvas.update(self.map) et = time.time() print "Canvas refresh in : %f times" %(et-st) def main(self): gtk.main() How can i fix these errors ?

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  • European signs in img src problem

    - by Rakoon
    Hey. I recently encountered a strange problem on my website. Images with æ ø and å in them (Western European signs) Won't display. The character encoding on all sites is "Iso-8859-1" I can print æ ø and å on the page without problems. If I right click the "broken image" and choose properties, it displays the filename with the european signs. (/admin/content/galleri/å.jpg) the code for img looks like this <img name='bilde' src='content/{$_SESSION["linkname"]}/{$row["img"]}' class='topmargin_ss leftmargin_ms rightmargin_s' width='80' height='80'> (Wasn't allowed to post images so the code is without starting and ending brackets) Made 4 files: z.jpg æ.jpg ø.jpg å.jpg Only z.jpg shows up, they are the exact same jpg. The images are uploaded using php code, which works, uploads to the right directory and has no problem with the european signs. Does anybody know what could be causing this?

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  • Problem with SQLite executemany

    - by Strider1066
    I can't find my error in the following code. When it is run a type error is given for line: cur.executemany(sql % itr.next()) = 'function takes exactly 2 arguments (1 given), import sqlite3 con = sqlite3.connect('test.sqlite') cur = con.cursor() cur.execute("create table IF NOT EXISTS fred (dat)") def newSave(className, fields, objData): sets = [] itr = iter(objData) if len(fields) == 1: sets.append( ':' + fields[0]) else: for name in fields: sets.append( ':' + name) if len(sets)== 1: colNames = sets[0] else: colNames = ', '.join(sets) sql = " '''insert into %s (%s) values(%%s)'''," % (className, colNames) print itr.next() cur.executemany(sql % itr.next()) con.commit() if __name__=='__main__': newSave('fred', ['dat'], [{'dat':1}, {'dat':2}, { 'dat':3}, {'dat':4}]) I would appreciate your thoughts.

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  • How can I recursively read out directories in Perl?

    - by Przemek
    Hi, I want to read out a directory recursively to print the data-structure in an HTML-Page with Template::Toolkit. But I'm hanging in how to save the Paths and Files in a form that can be read our easy. My idea started like this sub list_dirs{ my ($rootPath) = @_; my (@paths); $rootPath .= '/' if($rootPath !~ /\/$/); for my $eachFile (glob($path.'*')) { if(-d $eachFile) { push (@paths, $eachFile); $paths[$i] = &list_dirs($eachFile); } else { push (@files, $eachFile); } } return @paths; } How could I solve this problem?

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  • Unix - "xargs" - output "in the middle" (not at the end!)

    - by Petike
    Hello, example use of "xargs" application in Unix can be something like this: ls | xargs echo which is the same as (let's say I have "someFile" and "someDir/" in the working dir): echo someFile someDir so "xargs" take its "input" and place it "at the end" of the next command (here at the end of echo). But sometimes I want xargs to place its input somewhere "in the middle" of next command. For example: find . -type f -name "*.cpp" -print | xargs g++ -o outputFile so if I had in the current directory files "a.cpp" "b.cpp" "c.cpp" the output would be the same as with the command: g++ -o outputFile a.cpp b.cpp c.cpp but I want to have something like this: g++ a.cpp b.cpp c.cpp -o outputFile Is there a way to do it? P.S.: I need it in some cases, because e.g.: i586-mingw32msvc-g++ -o outputFile `pkg-config --cflags --libs gtkmm-2.4` a.cpp b.cpp c.cpp doesn't work but this one works fine: i586-mingw32msvc-g++ a.cpp b.cpp c.cpp -o outputFile `pkg-config --cflags --libs gtkmm-2.4` Thanks. Petike

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  • What is an efficient way to erase substrings?

    - by Legend
    I have a long string and a set of <end-index, string> list like the following: long_sentence = "This is a long long long long sentence" indices = [[6, "is"], [8, "is a"], [18, "long"], [23, "long"]] An element 6, "is" indicates that 6 is the end index of the word "is" in the string. I want to get the following string in the end: >> print long_sentence This .... long ......... long sentence" I tried an approach like this: temp = long_sentence for i in indices: temp = temp[:int(i[0]) - len(i[1])] + '.'*(len(i[1])+1) + temp[i[0]+1:] While this seems to be working, it is taking exceptionally long time (more than 6 hours on 5000 strings inside a 300 MB file). Is there a way to speed this up?

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