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  • Sending login form to an open-mesh acess point for authentication with my own RADIUS server

    - by PachinSV
    I have my RADIUS server up and running and a custom external captive portal. But I'm not sure: what information should I send to the Open-Mesh AP with my login form (it is necessary to encrypt the password?, because if I don't use a secret word to encrypt in my network configuration the RADIUS server complaints about it and in the log shows me some strange characters in the password) I don't know what to do with the "challenge" and "md" parameters in my login splash page. Thank you very much for your help.

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  • Login keyring box frozen

    - by Maddie
    I'm new to ubuntu and I'm afraid I've done something really stupid. After booting, When prompted to enter a password to unlock my login keyring, I tried to enter in my password, but it won't let me. I can move my cursor but everything else is frozen. I tried to access the terminal by using Ctrl + Alt + F2, I entered my login and password from there and it worked, I just don't know what to do afterwards. Don't know what other information I can provide other than the fact that I am using Ubuntu 10.04

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  • What kind of sorting does the Windows 7 login screen use for usernames?

    - by Paul D. Waite
    I’ve set up ten Windows 7 user accounts, so that I can test different versions of Google Chrome*. I’ve named the accounts “Chrome 01”, “Chrome 02”, and so on. Ideally, I’d like the accounts sorted on the login screen by Chrome version, which is why I added the leading zero to the version number (assuming it was an alphabetic sort). However, when I created the “Chrome 10” account, it ended up sorted between “Chrome 01” and “Chrome 02”. What is going on? *(Chrome installs are user-account-specific)

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  • ubuntu login black screen

    - by newbeee
    I'm new in Ubuntu world I install it and I have gforce card after I install I use additional drivers and All i get is black screen what is with that people ??? they think I must know how to solve that ??? then i must spend day on Internet to see what is wrong and again it is os falt they didn't set on login to choose which graphic you want to use before you login screen default Intel or gforce power graphic .... wtf is with that people they dont use distro after they make it :(

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  • Thunderbird keeps asking me for the password every time I login

    - by mr_mohamed
    I haven't used thunderbird for a while but when i started to use it again I found out that i have to give the application driven password since i'm using gmail. So i types that application password which is automatically given by the google, but it asks for that every time i try to login. it's really frustrating, to obtain that password i have to go to goodle account settings everytime i login in thunderbird

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  • Require password to login to Nexus 7

    - by gnudoc
    The default behavior in the Nexus 7 Image is to log straight in to the default user's desktop, bypassing the lightdm greeter. This seems like an acceptable behavior for testing the core but it's clearly insecure. I've changed the default password and would like lightdm to actually require the password to be entered, rather than just having a button that says "login". I've turned automatic login on and off in System Settings ? User Accounts but this doesn't help. Any suggestions?

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  • Cannot pass the login screen after upgrade to 12.04 from 11.10

    - by joksan
    I just performed the upgrade from Ubuntu 11.10 to Ubuntu 12.04 LTS. The updater downloaded all packages but a few ones that the system said were already installed. When asked for it, I chose to install the new maintainer's version of grub. Now after that my system start up to the login page, some images won't load. Moreover, after I try to login, the graphical instance does not load, it just sits there showing the mouse pointer and nothing else.

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  • Can I disallow printing with parent controls on Snow Leopard?

    - by Quinn Taylor
    I have two children under 4 who are quite computer-savvy, and have their own account managed by parental controls to restrict what they can do an see. However, I haven't found a way to disallow them from printing, and I'm looking for a way do so. Their pictures of Sesame Street and Word World are cute and all, but I'd like to be in control of what (or even if) they print. (Our printer is connected wirelessly, not directly to the Mac.) I know I can add more time or authorize use of a given application by providing my password — can I do something similar for printing, such as approving or denying particular print jobs?

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  • NAS is intermittently inaccessible

    - by Natalie
    Model: QNAP TS-410 Turbo NAS Firmware version: 3.2.5 Build 0409T Issue: Each day, users connect to share folders on the NAS system and have read/write permissions for the share folders to which they need access. However, it often asks them for their log-in details and - when provided with right (or wrong) credentials for a user with read/write permissions - it denies them access. I've checked the logs and I keep seeing the following warnings: 2011-11-23 16:26:29 System 127.0.0.1 localhost Re-launch process [rpc.mountd]. 2011-11-23 16:26:16 System 127.0.0.1 localhost Re-launch process [proftpd]. 2011-11-23 16:25:30 System 127.0.0.1 localhost Re-launch process [rpc.mountd]. 2011-11-23 16:25:15 System 127.0.0.1 localhost Re-launch process [proftpd]. 2011-11-23 16:24:33 System 127.0.0.1 localhost Re-launch process [rpc.mountd]. 2011-11-23 16:24:21 System 127.0.0.1 localhost Re-launch process [proftpd]. 2011-11-23 16:23:37 System 127.0.0.1 localhost Re-launch process [rpc.mountd]. 2011-11-23 16:23:25 System 127.0.0.1 localhost Re-launch process [proftpd]. They seem to occur per minute but I am uncertain about whether or not they are relevant to this issue. The "Login failed" warning has also displayed in the system connection logs which tells me when and which user was unable to log in, as shown below: 2011-11-22 16:11:07 Administrator 192.168.0.xx computer-01 SAMBA --- Login Fail 2011-11-22 16:11:07 Administrator 192.168.0.xx computer-01 SAMBA --- Login Fail 2011-11-22 16:11:06 Administrator 192.168.0.xx computer-01 SAMBA --- Login Fail 2011-11-22 13:46:14 administrator 192.168.0.yy --- HTTP Administration Login Fail 2011-11-22 13:46:09 administrator 192.168.0.yy --- HTTP Administration Login Fail 2011-11-21 15:17:22 user 192.168.0.zz computer-02 SAMBA --- Login Fail 2011-11-21 15:17:18 user 192.168.0.zz computer-02 SAMBA --- Login Fail 2011-11-21 15:17:17 user 192.168.0.zz computer-02 SAMBA --- Login Fail I've researched this on Google and the QNAP forums and have not come up with a resolution as yet.

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  • Is it possible to write a class that interacts with controls on my WPF form?

    - by Adam S
    Hi all, I'm trying to write a class that I can use to interact with a group of similar controls in my wpf application. I have hit a few roadblocks and now I am wondering if this is a poor approach to begin with. I want to do this primarily to make my code more manageable - I have to interact with around 200 - 300 controls with my code, and it could get very tricky to have all my code in the main window class. Here's something I'd like to be able to do: class ProcControl { private CheckBox * [] Boxes = new CheckBox[10]; ProcControl() { //set boxes 0-9 to point to the actual checkboxes } //provides mass checking/unchecking functionality public void Refactor(CheckBox box) { //see what box it is int box_index = 0; while (Boxes[box_index] != box) { box_index++; } } } This doesn't work as it is right now. I have not figured out how to get my Boxes[] array to point to the actual checkboxes on my form, so I can't interact with them yet. Is it even possible to make an array that points to a bunch of controls so that I may process their properties in a nice manner? Why can't I access the controls at all from inside my class?

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  • WPF - Why doesn't Microsoft supply a decent set of most-used controls ?

    - by IUsedToBeAPygmy
    I've been playing with WPF for some months now, and I quite like it. But one of the things I don't get is why MS doesn't put a little more effort in helping developers by supplying basic controls, and I need to get this off my chest :) For example, I figure most applications somewhere will need to let you edit some properties - for configuration or whatever. What would be the most used types in a proprety-grid editor ? text numbers (byte, float/double, int, etc) colors ....etc. So why isn't there even something as simple as a control to edit numbers ? Like a generic NumericUpDown control that allows you to type in numbers (no text, no pasting invalid input) or spin them up/down according to some given rules (decimal, floating point, min/maxvalue) ? Why isn't there a generic colorpicker, so people get the same user-experience in every application ? Why isn't there a standard implementation of a SearchTextBox, a BreadCrumb-control, or all these other standard control types users have gotten accustomed to the last 10 years ? (..but at least they DID have the time to implement a generic splashscreen - because everyone knows that greatly increases user-productivity....) The well-known ideal is always to give people the same user-experience over different applications. So even if some of those controls would be easy to make - it would be preferred to have one version over different applications. I see people all over the internet trying to do the same stuff over and over again. Okay, so MS started a WPF Toolkit project on Codeplex that tries to implement some controls, but only did so half-heartedly and is completely dead by now (last update of the roadmap dates back to Mar 21 2009). The result of this is that a lot of people starting a WPF-project end up spending a lot of time on trying to figure out how to create some generic controls and get really frustrated. Wasn't the mantra "Developers, developers, developers!" ..? /Rant

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  • OSX Snow Leopard hangs after login

    - by sleepyjames
    After restoring from backup following filesystem corruption my user account hangs after login (After entering my password the login window disappears and all I get is the background and a mouse pointer, no spinning wheel of death etc ..) I can login as a different user and then logout and login as my main account (sometimes!) but this is not consistant. I can login with safemode ok and have tried deleting /System/Caches, ~/Library/Caches and removing all my ~/Library/Preferences which worked once but not again. Does anyone have an any idea which logs I can look in, if any, to see whats happening after login or any other tips? I'm using 10.6.2. Cheers.

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  • How to configure citrix presentation server 4.5 login config

    - by Cory
    Hello, I am a little confused as to something my Citrix Server has been doing. When I login to the web login, (username, password, domain); everything logs in ok and I see all the available application. The problem that I was trying to fix is that when I try to start an application, it asks me to login again to the server that is hosting the citrix server. So, is there anyway to have the initial login credentials pass-through to the server login or skip the server login completely? Side note - I do have pass-through authentication enabled on both my internal and external Citrix site. Thanks for the help! Cory

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  • Mac OS X Snow Leopard hangs after login

    - by sleepyjames
    After restoring from backup following filesystem corruption my user account hangs after login (After entering my password the login window disappears and all I get is the background and a mouse pointer, no spinning wheel of death etc ..) I can login as a different user and then logout and login as my main account (sometimes!) but this is not consistant. I can login with safemode ok and have tried deleting /System/Caches, ~/Library/Caches and removing all my ~/Library/Preferences which worked once but not again. Does anyone have an any idea which logs I can look in, if any, to see whats happening after login or any other tips? I'm using 10.6.2. Cheers.

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  • Why does this login fail for user 'Servername\Guest'?

    - by Metassebia
    I install SQL Server 2005 EXPRESS edition on one computer, Computer Name = 'MyServe' and Database name='MyDB',take it as database server. it is configured as both Database and Windows Authentication Mode. with username=sa and password=adminaa. I have application in C#.Net my connection string is ConnectionString = "Data Source=MyServe\SQLEXPRESS;Initial Catalog=MyDB;Integrated Security=True;User ID=sa;Password=adminaa"; when I run the application on the computer called MyServe, the database server, it works well, while when I install the application on different computer, when it tries to connect the database it gives an error called "login failed for user 'MyServe\Guest" what is wrong with configuration in the database server or other mistakes. please help me. thankyou in advance. Metasebia

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  • enabling a user (created with adduser command) for lightdm graphical login

    - by Basile Starynkevitch
    I just installed Ubuntu 12.04 AMD64 on a new (empty) hard disk (because the previous crashed) Since I am quite familiar with Debian, I created two accounts with the adduser command. Since I am also having an NFSv3 file system, I explictly gave user ids when creating them (for simplicity, I keep the same user id on the home server, running Debian; the user names contain digits; I'm not using LDAP), e.g. # grep bethy /etc/passwd bethy46:x:501:501:Bethy XXX,,,06123456:/home/bethy:/bin/bash # grep bethy /etc/group bethy64:x:501: # grep bethy /etc/shadow bethy46:$6$vQ-wmuchmorethings-2o/:15479:0:99999:7:: Of course /home/bethy exists The actual user name is slightly different, and I am not showing the real entries (for obvious privacy reasons) However, these users don't appear at graphical login prompt (lightdm). And they exist in the system, they have entries in /etc/passwd & /etc/shadow and I (partly) restored their /home I've got no specific user config under /etc/lightdm ; file /etc/lightdm/users.conf mentions # NOTE: If you have AccountsService installed on your system, then LightDM # will use this instead and these settings will be ignored but I have no idea of how to deal with AccountsService thru the command line As you probably guessed, I really dislike doing administrative tasks thru a graphical interface; I much prefer the command line What did I do wrong? How can a user entry not appear in lightdm graphical login? (I need to have my wife's user entry apparent for graphical login). I am not asking how to hide a user, but how to show it in lightdm graphical prompt work-around As I have been told in comments by Nirmik and by Enzotib, lightdm probably don't show any users of uid less than 1024. So I changed all the uid to be more than 8200 (including on the Debian NFS server) and this made all the users visible at the graphical prompt. It is a pain that such a threshold is not really documented.

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  • Login Fail - Google Music Manager

    - by TX-NY-CA
    This is on a Surface Pro. I have not installed a virtual machine. Here is Google's feedback on the error message I receive when attempting login: "Login failed. Could not identify your computer" error message If you're receiving a 'Login failed. Could not identify your computer.' error, we couldn’t identify your machine. Please note that at this time, virtual machines aren't supported by Google Play. If you're certain that you don't have a virtual machine, some users have reported that they were able to workaround the issue by disabling their network bridge." My ifconfig feedback, in case that's helpful: lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:80 errors:0 dropped:0 overruns:0 frame:0 TX packets:80 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:6640 (6.6 KB) TX bytes:6640 (6.6 KB) mlan0 Link encap:Ethernet HWaddr 60:45:bd:f9:04:c0 inet addr:10.129.116.166 Bcast:10.129.116.255 Mask:255.255.255.128 inet6 addr: fe80::6245:bdff:fef9:4c0/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:96714 errors:0 dropped:0 overruns:0 frame:0 TX packets:73079 errors:13 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:117500998 (117.5 MB) TX bytes:9008106 (9.0 MB)

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  • ubuntu box just redisplaying login screen after update

    - by David M. Karr
    My Ubuntu 12.04 box has been working fine. A recent update may have messed something up. I normally run remote windows on it, and I noticed that my windows were failing to start up. I then tried logging into it directly from the GUI console, and I'm seeing that after I press enter on the (valid) password, the page just redisplays. It's not a password error, as that would give me an inline error. I see some messages appear and disappear quickly between the login screen going away and then redisplaying, but they go away too quickly to read. I was able to run the non-gui login, and I did an update and upgrade, and then rebooted, but it's doing the same thing. I have a Samba connection from my Windows box, and that's still working. If it matters, here's my uname output (somewhat elided): Linux ... 3.2.0-26-generic #41-Ubuntu SMP Thu Jun 14 17:49:24 UTC 2012 x86_64 x86_64 x86_64 GNU/Linux What can I do to troubleshoot this? Note that when I select "Guest Session", it lets me log in and displays the window manager. This seems significant to me. Does this mean that something specific to my login is causing it to fail? Note: If it matters, here's the output from /var/log/dmesg. The line about gdm seems interesting: [ 9.815883] Bluetooth: RFCOMM TTY layer initialized [ 9.815887] Bluetooth: RFCOMM socket layer initialized [ 9.815888] Bluetooth: RFCOMM ver 1.11 [ 9.879088] [PCSPP,TRISTATE] [ 9.879092] parport0: irq 7 detected [ 9.883935] type=1400 audit(1341871177.871:10): apparmor="STATUS" operation="profile_load" name="/usr/lib/lightdm/lightdm/lightdm-guest-session-wrapper" pid=845 comm="apparmor_parser" [ 9.884365] type=1400 audit(1341871177.871:11): apparmor="STATUS" operation="profile_replace" name="/usr/sbin/ntpd" pid=851 comm="apparmor_parser" [ 9.950397] e1000e 0000:00:19.0: irq 42 for MSI/MSI-X [ 9.961160] init: gdm main process (907) killed by TERM signal [ 9.966358] lp0: using parport0 (polling).

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  • Can not login Dashboard / Unable to find the server at mykeystoneurl

    - by neo0
    I installed Dashboard following this guide: http://wiki.openstack.org/OpenStackDashboard Everything fine, but when I run the server, I can not login with the username and password in DATABASE config in local_settings.py. Here's my config: DATABASES = { 'default': { 'ENGINE': 'django.db.backends.mysql', 'NAME': 'dashboarddb', 'USER': 'nova', 'PASSWORD': 'nova', 'HOST': 'localhost', 'default-character-set': 'utf8' }, } When I run the Dashboard server and enter username + password. It returned this error on browser: Unable to find the server at mykeystoneurl (HTTP 400) And in the command line: DEBUG:openstack_dashboard.settings:Running in debug mode without debug_toolbar. DEBUG:openstack_dashboard.settings:Running in debug mode without debug_toolbar. Validating models... 0 errors found Django version 1.3.1, using settings 'openstack_dashboard.settings' Development server is running at http://0.0.0.0:8888/ Quit the server with CONTROL-C. Request returned failure status. Traceback (most recent call last): File "/home/us/horizon/.venv/src/python-keystoneclient/keystoneclient/client.py", line 121, in request body = json.loads(body) File "/usr/lib/python2.7/json/__init__.py", line 326, in loads return _default_decoder.decode(s) File "/usr/lib/python2.7/json/decoder.py", line 366, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) File "/usr/lib/python2.7/json/decoder.py", line 384, in raw_decode raise ValueError("No JSON object could be decoded") ValueError: No JSON object could be decoded [06/Mar/2012 15:20:03] "POST /auth/login/ HTTP/1.1" 200 3735 I also tried login as "admin" with password is "password" or "secrete" but I didn't work. What's wrong? Thank you!

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  • Advertising on personalized pages behind a login

    - by johneth
    I am currently building a web app which requires a user to log in. After they log in, they can see the content they've added to the web app, and things that the web app has done with the content they added. The URL structure won't differentiate different users (e.g. all user's 'homepage' would be example.com/home, not something like example.com/username/home). This is much the same way that Facebook works (all FB user's messages are at facebook.com/messages, for example). This presents a problem with advertising. I know that you can use AdSense behind a login, but as far as I'm aware, that's for things like forums, where everyone sees the same things (which wouldn't be the case in this site). I also know that I could put AdSense on the pages without allowing it to log in, which would produce inferior ads. I'm fairly certain it would be against the Terms of Service to give AdSense a login to a 'dummy' account with typical content, as it would not be seeing the same thing as every other user (which is impossible, as they all see different things). So, my question is: Is there an ad network, or other method, that can serve ads behind a login, maybe based on keywords rather than content?

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  • How to Retrieve Values of A Dynamically Created Control's Child Controls on PostBack?

    - by Jordan
    Given: I have a custom server control in the markup of an aspx page. This control creates child controls in its CreateChildControls() method (e.g. it retrieves content from a database and based on that content dynamically creates either a CheckBoxList or a RadioButtonList) Now I understand that I cannot access the dynamically created controls on postback unless I add them again on Page_Init or Page_PreInit (as per here). My question is, how do I add them again explicitly in Page_Init or Page_PreInit if they are just going to be added yet again when we get around to calling Render() on each of the custom server controls? I'm very certain this is not a unique problem, so there must be a best practice way of doing it...I just don't know what it is :/

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  • Is there any way to get all the controls on a container control?

    - by Mason Wheeler
    I've got a form with a bunch of controls on it, and I wanted to iterate through all the controls on a certain panel and enable/disable them. I tried this: var component: TComponent; begin for component in myPanel do (component as TControl).Enabled := Value; end; But that did nothing. Turns out all components are in the form's component collection, not their parent object's. So does anyone know if there's any way to get all the controls inside a control? (Besides an ugly workaround like this, which is what I ended up having to do): var component: TComponent; begin for component in myPanel do if (component is TControl) and (TControl(component).parent = myPanel) then TControl(component).Enabled := Value; end; Someone please tell me there's a better way...

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  • Server Controls in ASP.NET MVC without ViewState

    - by imran_ku07
      Introduction :           ASP.NET Web Forms provides a development environment just like GUI or windows application and try to hide statelessness nature of HTTP protocol. For accomplishing this target, Web Forms uses ViewState (a hidden field) to remove the gap between HTTP statelessness and GUI applications. But the problem with this technique is that ViewState size which grows quickly and also go back and forth with every request, as a result it will degrade application performance. In this article i will try to use existing ASP.NET server controls without ViewState.   Description :           When you add a server control which needs viewstate, in the presentation view in ASP.NET MVC application without a form tag, for example,            <asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>            It will shows the following exception,            Control 'TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server             When you place this textbox inside a form tag with runat=server, this will add the following ViewState even when you disable ViewState by using EnableViewState="false"            <input type="hidden" value="/wEPDwUJMjgzMDgzOTgzZGQ6u9CwikhHEW39ObrHyLTPFSboPA==" id="__VIEWSTATE" name="__VIEWSTATE"/>             The solution to this problem is to use the RenderControl method of server control which is simply renders HTML without any ViewState hidden field.         <% TextBox txt = new TextBox();          txt.Text = "abc";          StringBuilder sb = new StringBuilder();          System.IO.StringWriter textwriter = new System.IO.StringWriter(sb);          HtmlTextWriter htmlwriter = new HtmlTextWriter(textwriter);          txt.RenderControl(htmlwriter);  %>        <%= sb.ToString() %>             This will render <input type="text" > without any View State. This technique become very useful when you are using rich server controls like GridView. For example, let's say you have List of Recalls in Model.Recalls, then you will show your tabular data as,     <%  GridView gv = new GridView();          gv.AutoGenerateColumns = true;          gv.DataSource = Model.Recalls;          gv.DataBind();         StringBuilder sb = new StringBuilder();         System.IO.StringWriter textwriter = new System.IO.StringWriter(sb);         HtmlTextWriter htmlwriter = new HtmlTextWriter(textwriter);         gv.RenderControl(htmlwriter);%>            <%= sb.ToString() %>             This code might looks odd in your presentation view. A more better approach is to create a HTML Helper method which contains the above code. Summary :        In some cases you might needs to use existing ASP.NET Web Forms server controls but also dislikes ViewState. In this article i try to solve this gap by using the RenderControl method of Control class. Hopefully you enjoyed and become ready to create HTML helpers for many of the existing server controls.

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  • Creating a simple RSS reader using ListView,XMLDatasource,DataPager web server controls

    - by nikolaosk
    In my last ASP.Net seminar someone noticed that we did not talk at all about the XmlDataSource,ListView,DataPager web server controls. It is rather impossible to investigate/talk about all issues regarding ASP.Net in a seminar but I promised to write a blog post. I thought that I could combine all those three web server controls to create a RSS reader. 1) Launch Visual Studio 2008/2010. Express editions will work fine. 2) Create an empty asp.net web site. Choose an appropriate name. We will not write...(read more)

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