grep from a log file to get count
- by subodh1989
I have to get certain count from files. The grep statement i am using is like this :
counter_pstn=0
completed_count_pstn=0
rec=0
for rec in `(grep "merged" update_completed*.log | awk '{print $1}' | sed 's/ //g' | cut -d':' -f2)`
do
if [ $counter_pstn -eq 0 ]
then
completed_count_pstn=$rec
else
completed_count_pstn=$(($completed_count_pstn+$rec))
fi
counter_pstn=$(($counter_pstn+1))
done
echo "Completed Orders PSTN Primary " $completed_count_pstn
But the log file contains data in this format :
2500 rows merged.
2500 rows merged.
2500 rows merged.
2500 rows merged.2500 rows merged.
2500 rows merged.
2500 rows merged.
As a result , it is missing out the count of one merge(eg on line 4 of output).How do i modify the grep or use another function to get the count. NOTE that the 2500 number maybe for different logs. So we have to use "rows merged" pattern to get the count. i have tried -o ,-w grep options,but it is not working.
Expected output from above data:
17500
Actual output showing :
15000
