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• DVD ROM not working only in windows?

  - by Behrooz A

  I have an Asus N53SV laptop, My DVD rom doesn't read any type of DVD in windows , but I just installed windows 7 from a bootable DVD , I think this problem occurred after I tried to change my partitioning with paragon partition magic , I was trying to shrink , join and so , after that my windows showed an error that windows cannot find [weird address] on hard disk every time on starts. windows itself says the DVD drive works correctly and driver is working properly, but no DVD or CD can be read , note that the DVD I'm trying to read is the same DVD which I used to install windows some minutes ago. I don't know what's the problem

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• Global and local variables in my script

  - by Acorn

  I'm starting out learning javascript, and tried to write a little script that would make a grid of divs on a page. Here's the script: var tileWidth=50; var tileHeight=100; var leftPos=10; var topPos=10; var columns=10; var rows=10; var spacing=5; $('document').ready(function() { placeTiles(); }); function makeRow() { for (var i=0; i<columns; i++) { $('#canvas').append('<div class="tile" style="left:' + leftPos + 'px;top:' + topPos + 'px;"></div>'); var leftPos = leftPos + tileWidth + spacing; } } function placeTiles() { for (var i=0; i<rows; i++) { makeRow(); var topPos = topPos + tileHeight + spacing; } } At the moment, 100 <div>s get created, all with a top position of 10px and a left position of undefined (for the first <div> in the row) or NaN. What should I be doing differently? Why can't makerow() see my global leftPos variable (and all the other variables for that matter)? Thanks.

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• Question regarding ip checksum code

  - by looktt

  unsigned short /* this function generates header checksums */ csum (unsigned short *buf, int nwords) { unsigned long sum; for (sum = 0; nwords > 0; nwords--) // add words(16bits) together sum += *buf++; sum = (sum >> 16) + (sum & 0xffff); //add carry over sum += (sum >> 16); //what does this step do??? add possible left-over //byte? But isn't it already added in the loop (if //any)? return ((unsigned short) ~sum); } I assume nwords in the number of 16bits word, not 8bits byte (if there are odd byte, nword is rounded to next large), is it correct? The line sum = (sum 16) + (sum & 0xffff) is to add carry over to make 16bit complement sum += (sum 16); What's the purpose of this step? Add left-over byte? How? Thanks!

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• How to append \line into RTF using RichTextBox control

  - by Steve Sheldon

  When using the Microsoft RichTextBox control it is possible to add new lines like this... richtextbox.AppendText(System.Environment.NewLine); // appends \r\n However, if you now view the generated rtf the \r\n characters are converted to \par not \line How do I insert a \line control code into the generated RTF? What does't work: Token Replacement Hacks like inserting a token at the end of the string and then replacing it after the fact, so something like this: string text = "my text"; text = text.Replace("||" "|"); // replace any '|' chars with a double '||' so they aren't confused in the output. text = text.Replace("\r\n", "_|0|_"); // replace \r\n with a placeholder of |0| richtextbox.AppendText(text); string rtf = richtextbox.Rtf; rtf.Replace("_|0|_", "\\line"); // replace placeholder with \line rtf.Replace("||", "|"); // set back any || chars to | This almost worked, it breaks down if you have to support right to left text as the right to left control sequence always ends up in the middle of the placeholder. Sending Key Messages public void AppendNewLine() { Keys[] keys = new Keys[] {Keys.Shift, Keys.Return}; SendKeys(keys); } private void SendKeys(Keys[] keys) { foreach(Keys key in keys) { SendKeyDown(key); } } private void SendKeyDown(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYDOWN, (int)key, 0); } private void SendKeyUp(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYUP, (int)key, 0); } This also ends up being converted to a \par Is there a way to post a messaged directly to the msftedit control to insert a control character? I am totally stumped, any ideas guys? Thanks for your help!

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• CSS Float statement

  - by Jordan Pagaduan

  .float1 { float: left; width: 50%; height: 50%; } .float2 { float: right; width: 50%; height: 50%; } .float3 { float: left; width: 50%; height: 50%; } .float4 { float: right; width: 50%; height: 50%; } .clear { clear: both; } HTML: <div class="float1">Float 1</div> <div class="float2">Float 2</div> <div class="clear"></div> <div class="float3">Float 3</div> <div class="float4">Float 4</div> <div class="clear"></div> I want an output like this image: Please Correct my css code. Thank you.

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• how to speed up the code??

  - by kaushik

  i have very huge code about 600 lines plus. cant post the whole thing here. but a particular code snippet is taking so much time,leading to problems. here i post that part of code please tell me what to do speed up the processing.. please suggest the part which may be the reason and measure to improve them if this small part of code is understandable. using_data={} def join_cost(a , b): global using_data #print a #print b save_a=[] save_b=[] print 1 #for i in range(len(m)): #if str(m[i][0])==str(a): save_a=database_index[a] #for i in range(len(m)): # if str(m[i][0])==str(b): #print 'save_a',save_a #print 'save_b',save_b print 2 save_b=database_index[b] using_data[save_a[0]]=save_a s=str(save_a[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') print 3 for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) end_time=save_a[4] #print end_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(end_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 q=[] print 4 l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') q=k3.split(' ') #print q print 5 s=str(save_b[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) strt_time=save_b[3] #print strt_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(strt_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 w=[] l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') w=k3.split(' ') #print w cost=0 for i in range(12): #print q[i] #print w[i] h=float(q[i])-float(w[i]) cost=cost+math.pow(h,2) j_cost=math.sqrt(cost) #print cost return j_cost def target_cost(a , b): a=(b+1)*3 b=(a+1)*2 t_cost=(a+b)*5/2 return t_cost r1='shht:ra_77' r2='grx_18' g=[] nodes=[] nodes=nodes+[[r1]] for i in range(len(y_in_db_format)): g=y_in_db_format[i] #print g #print g[0] g.remove(str(g[0])) nodes=nodes+[g] nodes=nodes+[[r2]] print nodes print "lenght of nodes",len(nodes) lists=[] #lists=lists+[r1] for i in range(len(nodes)): for j in range(len(nodes[i])): lists=lists+[nodes[i][j]] #lists=lists+[r2] print lists distance={} for i in range(len(lists)): if i==0: distance[str(lists[i])]=0 else: distance[str(lists[i])]=long(123231223) #print distance group_dist=[] infinity=long(123232323) for i in range(len(nodes)): distances=[] for j in range(len(nodes[i])): #distances=[] if i==0: distances=distances+[[nodes[i][j], 0]] else: distances=distances+[[nodes[i][j],infinity]] group_dist=group_dist+[distances] #print distances print "group_distances",group_dist #print "check",group_dist[0][0][1] #costs={} #for i in range(len(lists)): #if i==0: # costs[str(lists[i])]=1 #else: # costs[str(lists[i])]=get_selfcost(lists[i]) path=[] for i in range(len(nodes)): mini=[] if i!=(len(nodes)-1): #temp=long(123234324) #Now calculate the cost between the current node and each of its neighbour for k in range(len(nodes[(i+1)])): for j in range(len(nodes[i])): current=nodes[i][j] #print "current_node",current j_distance=join_cost( current , nodes[i+1][k]) #t_distance=target_cost( current , nodes[i+1][k]) t_distance=34 #print distance #print "distance between current and neighbours",distance total_distance=(.5*(float(group_dist[i][j][1])+float(j_distance))+.5*(float(t_distance))) #print "total distance between the intial_nodes and current neighbour",total_distance if int(group_dist[i+1][k][1]) > int(total_distance): group_dist[i+1][k][1]=total_distance #print "updated distance",group_dist[i+1][k][1] a=current #print "the neighbour",nodes[i+1][k],"updated the value",a mini=mini+[[str(nodes[i+1][k]),a]] print mini

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• Div on top of Div using z-index.

  - by Iacks

  I have the following divs in my HTML: <div class="main"> <div class="bgimage"></div> <div class="content">Text</div> which is directly inside my body. With the following CSS: .content{filter:alpha(opacity=50);-moz-opacity: 0.5;opacity: 0.5;} .content{position:relative;z-index:1;border:#000 thin solid;width:960px;margin-left:auto;margin-right:auto;background-color:#000;} .bgimage{position:absolute;z-index:-1;width:1024px;height:768px;margin-left:auto;margin-right:auto;background-image:url(bg1.jpg);} Basically, I have a Div that with a display of a background image, and I will have another Div on top of this with transparency. This current code works, but my problem is when I am trying to take the content div down from the top. When I add margin-top:100px, for example, is also brings the image down. I thought it would not touch it if it is not on the same z-index? Why does adding a margin also force the bgimage div down? I have also tried making the div with class of content a position of absolute and a zindex, but then this won't centre. How should I solve this?

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• WPF Buttons Style

  - by Polaris

  I have WPF Form which has many buttons with the same code. Appearance of all buttons must be the same For example, code for one of these buttons <Button x:Name="btnAddRelative" Width="120" Click="btnAddRelative_Click" > <Button.Content> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" Add Relative" Height="20" VerticalAlignment="Center"/> </StackPanel> </Button.Content> </Button> How can I create one style and use it for all my buttons. All buttons has the same png image, only their text different. How can I do this. I tried to do this with Style object in Resource Section: <UserControl.Resources> <Style TargetType="Button" x:Key="AddStyle"> <Setter Property="Content"> <Setter.Value> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" " Height="20" VerticalAlignment="Center"/> </StackPanel> </Setter.Value> </Setter> </Style> </UserControl.Resources> But this code not work. Can any body know how can I do this?

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• ViewController has wrong orientation after Landscape-only has been popped

  - by noroom

  In a navigation-based app, LandscapeViewController only supports landscape mode (all others support both modes). I also have a "loading screen" that advises the user to rotate the phone before continuing. This way I can make sure that when my landscape view loads, that it's in landscape mode. The problem comes when i rotate the phone to portrait mode while still showing LandscapeVC. I press the Back nagivation button to navigate up one level (to a VC that supports both landscape and portrait modes), but the upper level shows in landscape mode even though the phone is in portrait mode. I guess this is because when I left this view I was in portrait mode, I then rotated the phone while in another view, so this view has not received the notification. If I then proceed to rotate the phone to the other landscape mode (say the LandscapeVC was loaded on its right side, so I'd rotate the upper VC from portrait to the left landscape mode), it will update. My question is: how can I notify this upper view that the phone was rotated, so when the user goes up after putting the phone in portrait mode, the upper view shows correctly?

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• iPhone TabbarController Switch Transition

  - by user269737

  I've implemented gestures (touchBegan-moved-ended) in order to allow for swiping through my tabs. It works. I'd like to add a slide-from-left and slide-from-right transition. It would be better if it could be part of the gesture if statement which tells me if the swipe is towards the right of left. Since I determine which tab is displayed from that, I could show that specific transition along with the new tab. So my question is this: what's the simplest way to simplement a slide transition at a specific instance. I don't want it to be for the whole tabbarcontrol since this is specifically for the swiping. Thanks for the help, much appreciated. For clarification purposes, this is snippet shows how I'm switching tabs: if(abs(diffx / diffy) > 2.5 && abs(diffx) > HORIZ_SWIPE_DRAG_MIN) { // It appears to be a swipe. if(isProcessingListMove) { // ignore move, we're currently processing the swipe return; } if (mystartTouchPosition.x < currentTouchPosition.x) { isProcessingListMove = YES; self.tabBarController.selectedViewController = [self.tabBarController.viewControllers objectAtIndex:0]; return; } else { isProcessingListMove = YES; self.tabBarController.selectedViewController = [self.tabBarController.viewControllers objectAtIndex:1 ]; return; }

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• IE not rendering div contents

  - by The.Anti.9

  I've written an app using HTML 5 and I wan't to show an error box instead of the page when someone visits from IE. When it detects navigator.appName as Microsoft Internet Explorer it hides everything and shows the error div that started out hidden. The div is as follows: <div id='ieerror' style='display:none;width:500px;height:500px;border:3px solid #ff0000;position:absolute;top:50%;left:50%;margin-top:-250px;margin-left:-250px;'> <center> <h1 style='font-size: 30px;'>Internet Explorer is not supported by Aud!</h1><br /><br /> <p>Internet Explorer does not support HTML 5 and therefore this application cannot run.<br /> Please upgrade your browser. We suggest <a href='http://www.google.com/chrome'>Google Chrome</a>!</p> </center> </div> The problem is that when I visit the page in IE, the div pops up with the border, but it has no contents. Nothing is inside of it. I went to view->source and looked at it, and the code is still there, but none of it is rendered. How do I fix this?

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• EC2 server in VPC stops responding after joining domain

  - by Geoff

  We have a EC2 Windows Server set up and running in our VPC, connected to our network via a Juniper 5GT. This is working well, with the tunnel up and stable. If I then join the server to our local domain, it appears to work - I can then log on using domain credentials, and use domain accounts when applying security to folders etc. After I log out, if I give it around an hour, the box becomes unresponsive. I can't ping it, although a tracert goes all the way barring the last hop - so the tunnel is ok. I can't RDP into it. If I reboot it, then it works for a while before doing the same thing. Un-joining it from the domain fixes the problem, and it stays up and stable. The event logs don't show anything obvious, at least to me. Any ideas?

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• gluLookAt vectors and FPS-style camera

  - by Kevin Pamplona

  I am attempting to implemented an FPS-style camera by updating three vectors: EYE, DIR, UP. These vectors are the same that are used by gluLookAt (since gluLookAt is specified by the position of the camera, the direction it is looking at, and an up vector). I have already implemented the left-right and up-down strafing movements, but I'm having a lot of trouble understanding the math behind making the camera look-around while remaining stationary. In this case, the EYE vector remains the same, while I must update DIR and UP. Below is the code I tried, but it doesn't seem to work properly. Any suggestions? Thanks. void Transform::left(float degrees, vec3& dir, vec3& up) { vec3 axis; axis = glm::normalize(up); mat3 R = rotate(-degrees, axis); dir = R*dir; dir = R*up; }; void Transform::up(float degrees, vec3& dir, vec3& up) { vec3 axis; axis=glm::normalize(glm::cross(dir,up)); mat3 R = rotate(-degrees, axis); dir = R*dir-; up = R*up; };

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• Django Template For Loop Removing <img> Self-Closing

  - by Zack

  Django's for loop seems to be removing all of my <img> tag's self-closing...ness (/>). In the Template, I have this code: {% for item in item_list %} <li> <a class="left" href="{{ item.url }}">{{ item.name }}</a> <a class="right" href="{{ item.url }}"> <img src="{{ item.icon.url }}" alt="{{ item.name }} Logo." /> </a> </li> {% endfor %} It outputs this: <li> <a class="left" href="/some-url/">This is an item</a> <a class="right" href="/some-url/"> <img src="/media/img/some-item.jpg" alt="This is an item Logo."> </a> </li> As you can see, the <img> tag is no longer closed, and thus the page doesn't validate. This isn't a huge issue since it'll still render properly in all browsers, but I'd like to know how to solve it. I've tried wrapping the whole for loop in {% autoescape off %}...{% endautoescape %} but that didn't change anything. All other self-closed <img> tags in the document outside the for loop still properly close.

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• Strange layout behaviour

  - by andrii

  I am a little bit confused. Here is an small web page. There are two main div-s: top and mainBlock. First contain image. The problem is that firebug shows that div#top's height is equal to 0 and because of that the next div mainBlock moves up. If I would delete this peace of code: div#logo{ float: left; } everything will start working fine and div#mainBlock will be below the div#top. Could you, please, explain me how it works and how to avoid this in proper way? Here is my code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <title>Paralab - Website &amp; interface design, web apps development, usability</title> <style text="text/css"> html, body{ } div#logo{ float: left; } #top{ width: 100%; } #mainBlock{ width:100%; } </style> </head> <body> <div id="top"> <div id="logo"> <img alt="logo" src="img/logo.png" /> </div> </div> <div id="mainBlock"> Contact Us </div> </body> </html>

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• Navigating through code with keyboard shortcuts

  - by MarceloRamires

  I'm starting to feel the need to run fastly through code with keyboard shortcuts, to arrive faster where I want to make any changes (avoiding use of mouse or long times holding [up], [left], [right] and [down]). I'm already using some: [home] - first position in current line [end] - last position in current line [ctrl] + [home] - first line of the entire code [ctrl] + [end] - last line of the entire code [pageup] - same vertical position, one screen above [pagedown] - same vertical position, one screen below [ctrl] + [pageup] - first line in current screen [ctrl] + [end] - last line in current screen [ctrl] + [left/right] - skipping word per word What have you got ? I use Visual Studio. (but I'm open to any answer, as I maybe can use others soon) obs: I've searched through stackoverflow and didn't find a nice question with this content, nor a list of keyboard code searching. If it's repeated, I'm sorry for not finding it, I'm here in my best intentions. This question is NOT about any shortcuts, and not only about visual studio, it's about running through code with shortcuts. Answers that suit the question so far: [Ctrl] + [-] - jumps to last cursor position [Ctrl] + [F3] - Jumps to next occurance of the word the curson is in [Shift] + [F3] - Same as the above, backwards. [F12] - Goes to definition of method/variable the cursor is in [Ctrl] + [ ] ] - Jumps to matching brace and select I'll ad more as there are answers.

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• Is there a sensible way of 'teaming' two ADSL connections?

  - by Tim Long

  I work in an office complex that has two seperate ADSL connections, which they use to provide two seperate networks (actually both the ADSL routers go into a Cisco managed switch with two VLANs, one for each ADSL connection). Circumstances have changed so that 95% of the users are all on one ADSL connection. It would be great if there were a way to join together both connections to emulate a single connection at double the speed, but the ISP doesn't support bonding. So, is there a sensible way to take two completely seperate ADSL lines and use them to provide a single internet gateway?

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• Presentation Issue in an Unordered List

  - by phreeskier

  I'm having an issue with correctly presenting items in an unordered list. The labels are floating left and the related spans that are long in length are wrapping and showing below the label. I need a solution that keeps the related spans in their respective columns. In other words, I don't want long spans to show under the labels. What property can I take advantage of so that I get the desired layout in all of the popular browsers, including IE6? Thanks in advance for the help. My code is as follows: <ul> <li> <label>Name</label> <span><%= Html.Encode(Model.Name) %></span> </li> <li> <label>Entity</label> <span><%= Html.Encode(Model.Entity) %></span> </li> <li> <label>Phone</label> <span><%= Html.Encode(Model.Phone) %></span> </li> </ul> My CSS styling is as follows: ul { display:block; list-style-type:none; margin:0; padding:0; } ul li label { float:left; width:100px; }

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• little java help....

  - by jona

  Hi I am doing some practice problems and trying to print a diagonal line like the example below. I have writen the program you see below and I honestly dont understand what I am doing wrong. I m a java beginner and I cant see how to find the error. Example ( If you only see a straight line of stars...then imagine it diagonally....from top left to bottom right) * * * * * code: class Diagonal{ public static void main(String args[]) { int row, col; for(row = 1; row < 6; row++) { for(col = 1; col <= row; col++) { if(col==row){ System.out.print("*"); } else{ System.out.print(""); } System.out.println(); } } } } I am trying to learn for loops because they really confuse me. Another practice is to print a similar diagonal line but this time from right to left. I cant do that without getting this right however :( I believe they will be pretty similar? Above my reasining is this: As long as the column # is the same as the row number the print the line or otherwise leave a blank....what's wrong with how i did it? THANK YOU!

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• How to insert and reterive key from registry editor

  - by deepa

  Hi.. I am new to cryptography.. i have to develop project based on cryptography..In part of my project I have to insert a key to the registry and afterwards i have to reterive the same key for decryption.. i done until getting the path of the registry .. Here i given my code.. import java.io.IOException; import java.io.InputStream; import java.io.StringWriter; public static final String readRegistry(String location, String key) { try { // Run reg query, then read output with StreamReader (internal class) Process process = Runtime.getRuntime().exec("reg query " + '"' + location + "\" /v " + key); StreamReader reader = new StreamReader(process.getInputStream()); reader.start(); process.waitFor(); reader.join(); String output = reader.getResult(); // Output has the following format: // \n<Version information>\n\n<key>\t<registry type>\t<value> if (!output.contains("\t")) { return null; } // Parse out the value String[] parsed = output.split("\t"); return parsed[parsed.length - 1]; } catch (Exception e) { return null; } } static class StreamReader extends Thread { private InputStream is; private StringWriter sw = new StringWriter(); ; public StreamReader(InputStream is) { this.is = is; } public void run() { try { int c; while ((c = is.read()) != -1) { System.out.println("Reading" + c); sw.write(c); } } catch (IOException e) { System.out.println("Exception in run() " + e); } } public String getResult() { System.out.println("Content " + sw.toString()); return sw.toString(); } } public static boolean addValue(String key, String valName, String val) { try { // Run reg query, then read output with StreamReader (internal class) Process process = Runtime.getRuntime().exec("reg add \"" + key + "\" /v \"" + valName + "\" /d \"\\\"" + val + "\\\"\" /f"); StreamReader reader = new StreamReader(process.getInputStream()); reader.start(); process.waitFor(); reader.join(); String output = reader.getResult(); System.out.println("Processing........ggggggggggggggggggggg." + output); // Output has the following format: // \n&lt;Version information&gt;\n\n&lt;key&gt;\t&lt;registry type&gt;\t&lt;value&gt; return output.contains("The operation completed successfully"); } catch (Exception e) { System.out.println("Exception in addValue() " + e); } return false; } public static void main(String[] args) { // Sample usage JAXRDeleteConcept hc = new JAXRDeleteConcept(); System.out.println("Before Insertion"); if (JAXRDeleteConcept.addValue("HKEY_CURRENT_USER\\Software\\Microsoft\\Windows\\CurrentVersion\\Explorer\\ComDlg32\\OpenSaveMRU", "REG_SZ", "Muthus")) { System.out.println("Inserted Successfully"); } String value = JAXRDeleteConcept.readRegistry("HKEY_CURRENT_USER\\Software\\Microsoft\\Windows\\CurrentVersion\\Explorer\\ComDlg32\\OpenSaveMRU" , "Project_Key"); System.out.println(value); } } But i dont know how to insert a key in a registry and read the particular key which i inserted..Please help me.. Thanks in advance..

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• Vertically align a heading and a paragraph in a div

  - by davey

  I'm trying to vertically align a h1 element and p in the middle of a div floated left but they end up next to each other vertically aligned. Im pretty sure it to do with the table-cell display but don't know how to vertically align without it. my code gives me: . . Heading Paragraph . . I want: . . Heading Paragraph . . heres my code: CSS: #HDRtext { float: left; width: 30%; height: 335px; padding: 0; display: table; color: white; } #HDRtext h1 { font-family: Georgia; font-size: 2em; display: table-cell; vertical-align: middle; } #HDRtext p { display: table-cell; vertical-align: middle; font-size:1em; font-family: Georgia; }

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• Got problem when uploading the html into the webview in iphone sdk.

  - by Monish Kumar

  Hi Guy's NSString* appendString=@""; appendString = [appendString stringByAppendingString:@"<body>"]; appendString =[appendString stringByAppendingString:@"<table background='footer.png' width='320' height='45' style='background-repeat:no-repeat'>"]; appendString =[appendString stringByAppendingString:@"<tr>"]; appendString =[appendString stringByAppendingString:@"<td align='left' width='57' height='31' style='padding: 6px 0 0 0' ><a href='/map/'><img src='details_Back.png'/></a></td>"]; appendString =[appendString stringByAppendingString:@"<td align='left' valign='middle' style='padding: 0 0 0 65px; font-family:Helvetica; font-size:21px ; font-weight:bold ; color:#FFF'>Details</td>"]; appendString =[appendString stringByAppendingString:@"</tr>"]; appendString =[appendString stringByAppendingString:@"</table>"]; appendString =[appendString stringByAppendingString:@"<br>"]; returnString = [returnString stringByReplacingOccurrencesOfString:@"<body>" withString:appendString]; printf("\n return string :%s",[returnString UTF8String]); [myWebView loadHTMLString:returnString baseURL:[NSURL URLWithString:@"http://abc.api.abcdefg.com/"]]; here in the above code the footer.png and details_back.png are the local images stored in my resource folder. Here the problem is I am gettin the background image from the server link I had passed to the webview as baseurl but the images footer.png and details_back.png which were stored in resource is not displayed. if I use the resource bundle as the baseurl then I am not displayed the background image from the server link. Can anyone please give me the suggestions to get rid of rid of this problem. thanks to all guy's, Monish.

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• Position absolute for rounded corners and problems in IE6

  - by danit

  Im using position absolute to give the top left corner of a DIV a rounded corner. HTML: <div id="MyDiv"> Some content <div class="topLeft">&nbsp</div> </div> CSS: #MyDiv { position: relative; padding: 12px; background: #fff url('graident.png') repeat-x top left; } .topLeft { position: absolute; top: 0; right: 0; width: 10px; height: 10px; background: transparent url('corner.png') no-repeat top right; } This works fine in all browsers expcept IE6. In IE6 the corner.png image seems to be about 1px out at the top corner, essentially not top: 0; and right: 0; but more like top: 1px; right: 1px; Can anyone explain why this might be happening only in IE6?

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• How do I share a home printer under Windows if the computer is part of a domain?

  - by Sorin Sbarnea

  I do have my work laptop at home and I want to share an USB printer in order to be able to print to it from my MacBook. Currently Windows 7 is refusing to share the printer because the computer is part of a domain and it tells me that I need to join a homegroup in order to be able to do that. Also it tells me that he cannot create this homegroup and this group has to be create by another Windows 7 computer from my network. As you can imagine I do have only one Windows computer on my home network. How can I solve this problem?

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• Rendering blocks side-by-side with FOP

  - by Rolf

  I need to generate a PDF from XML data using Apache FOP. The problem is that FOP doesn't support fo:float, and I really need to have items (boxes of rendered data) side-by-side in the PDF. More precisely, I need them in a 4x4 grid on each page, like so: In HTML, I would simply render these as left-floated divs with appropriate widths and heights. My data looks something like this: <item id="1"> <a>foo</a> <b>bar</b> <c>baz</c> </item> <item id="2">...</item> ... <item id="n">...</item> I considered using a two-column region-body, but then the order of items would be 1, 3, 2, 4 (reading from left to right) since they would be rendered tb-lr instead of lr-tb, and I need them to be in the correct order (id in above xml). I suppose I could try using a table, but I'm not quite sure how to group the items into table rows. So, some kind of workaround for the lack of fo:float would be greatly appreciated.

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