Search Results

Search found 18648 results on 746 pages for 'left join'.

Page 289/746 | < Previous Page | 285 286 287 288 289 290 291 292 293 294 295 296  | Next Page >

  • Vertically align a heading and a paragraph in a div

    - by davey
    I'm trying to vertically align a h1 element and p in the middle of a div floated left but they end up next to each other vertically aligned. Im pretty sure it to do with the table-cell display but don't know how to vertically align without it. my code gives me: . . Heading Paragraph . . I want: . . Heading Paragraph . . heres my code: CSS: #HDRtext { float: left; width: 30%; height: 335px; padding: 0; display: table; color: white; } #HDRtext h1 { font-family: Georgia; font-size: 2em; display: table-cell; vertical-align: middle; } #HDRtext p { display: table-cell; vertical-align: middle; font-size:1em; font-family: Georgia; }

    Read the article

  • CSS3 image rotation and reposition to fit in div

    - by blid
    I'll start with JS Fiddle: http://jsfiddle.net/zy2xy/4/ <div id="page" style="position: relative; background: #ccc; width: 500px; height: 600px;"> <div id="container" style="top: 50px; left: 100px; width: 200px; height: 200px; position: absolute; background: #fff;"> <img src="http://lorempixel.com/200/100/"> </div> </div>????????? I've got a whole page div #page, and inside that another div #container positioned absolute against #page. What I want to achieve, is to rotate image inside it 90deg, 180deg or 270deg but always move that image to top left corner of #container. I tried a little bit with transform-origin but I couldn't find any solution.

    Read the article

  • Why can't decimal numbers be represented exactly in binary?

    - by Barry Brown
    There have been several questions posted to SO about floating-point representation. For example, the decimal number 0.1 doesn't have an exact binary representation, so it's dangerous to use the == operator to compare it to another floating-point number. I understand the principles behind floating-point representation. What I don't understand is why, from a mathematical perspective, are the numbers to the right of the decimal point any more "special" that the ones to the left? For example, the number 61.0 has an exact binary representation because the integral portion of any number is always exact. But the number 6.10 is not exact. All I did was move the decimal one place and suddenly I've gone from Exactopia to Inexactville. Mathematically, there should be no intrinsic difference between the two numbers -- they're just numbers. By contrast, if I move the decimal one place in the other direction to produce the number 610, I'm still in Exactopia. I can keep going in that direction (6100, 610000000, 610000000000000) and they're still exact, exact, exact. But as soon as the decimal crosses some threshold, the numbers are no longer exact. What's going on? Edit: to clarify, I want to stay away from discussion about industry-standard representations, such as IEEE, and stick with what I believe is the mathematically "pure" way. In base 10, the positional values are: ... 1000 100 10 1 1/10 1/100 ... In binary, they would be: ... 8 4 2 1 1/2 1/4 1/8 ... There are also no arbitrary limits placed on these numbers. The positions increase indefinitely to the left and to the right.

    Read the article

  • Django Template For Loop Removing <img> Self-Closing

    - by Zack
    Django's for loop seems to be removing all of my <img> tag's self-closing...ness (/>). In the Template, I have this code: {% for item in item_list %} <li> <a class="left" href="{{ item.url }}">{{ item.name }}</a> <a class="right" href="{{ item.url }}"> <img src="{{ item.icon.url }}" alt="{{ item.name }} Logo." /> </a> </li> {% endfor %} It outputs this: <li> <a class="left" href="/some-url/">This is an item</a> <a class="right" href="/some-url/"> <img src="/media/img/some-item.jpg" alt="This is an item Logo."> </a> </li> As you can see, the <img> tag is no longer closed, and thus the page doesn't validate. This isn't a huge issue since it'll still render properly in all browsers, but I'd like to know how to solve it. I've tried wrapping the whole for loop in {% autoescape off %}...{% endautoescape %} but that didn't change anything. All other self-closed <img> tags in the document outside the for loop still properly close.

    Read the article

  • Pecking order of pigeons?

    - by sc_ray
    I was going though problems on graph theory posted by Prof. Ericksson from my alma-mater and came across this rather unique question about pigeons and their innate tendency to form pecking orders. The question goes as follows: Whenever groups of pigeons gather, they instinctively establish a pecking order. For any pair of pigeons, one pigeon always pecks the other, driving it away from food or potential mates. The same pair of pigeons always chooses the same pecking order, even after years of separation, no matter what other pigeons are around. Surprisingly, the overall pecking order can contain cycles—for example, pigeon A pecks pigeon B, which pecks pigeon C, which pecks pigeon A. Prove that any finite set of pigeons can be arranged in a row from left to right so that every pigeon pecks the pigeon immediately to its left. Since this is a question on Graph theory, the first things that crossed my mind that is this just asking for a topological sort of a graphs of relationships(relationships being the pecking order). What made this a little more complex was the fact that there can be cyclic relationships between the pigeons. If we have a cyclic dependency as follows: A-B-C-A where A pecks on B,B pecks on C and C goes back and pecks on A If we represent it in the way suggested by the problem, we have something as follows: C B A But the above given row ordering does not factor in the pecking order between C and A. I had another idea of solving it by mathematical induction where the base case is for two pigeons arranged according to their pecking order, assuming the pecking order arrangement is valid for n pigeons and then proving it to be true for n+1 pigeons. I am not sure if I am going down the wrong track here. Some insights into how I should be analyzing this problem will be helpful. Thanks

    Read the article

  • Paragraph with normal opacity within greyed-out div

    - by dmr
    I am greying out a web page when a user doesn't have permission to access it. In order to do that, I am placing a div with background-color white and a lowered opacity on top of the web page. I want to write some words in that div with the words having a normal opacity. As of now, the greyed out background is showing correctly. However, I can't seem to get the words to be a regular opacity. The derived styles on Firebug show the opacity on the words as normal, but it clearly isn't. What am I doing wrong? The HTML: <div class="noPermission"> <p>I'm sorry. You do not have permission to access this page.</p> </div> The CSS: div.noPermission { background-color: white; filter:alpha(opacity=50); /* IE */ opacity: 0.5; /* Safari, Opera */ -moz-opacity:0.50; /* FireFox */ z-index: 20; height: 100%; width: 100%; background-repeat:no-repeat; background-position:center; position:absolute; top: 0px; left: 0px; } div.noPermission p{ color: black; margin: 300px auto auto 50px; text-align: left; font-weight: bold; font-size: 18px; display: block; width: 250px; }

    Read the article

  • Position absolute for rounded corners and problems in IE6

    - by danit
    Im using position absolute to give the top left corner of a DIV a rounded corner. HTML: <div id="MyDiv"> Some content <div class="topLeft">&nbsp</div> </div> CSS: #MyDiv { position: relative; padding: 12px; background: #fff url('graident.png') repeat-x top left; } .topLeft { position: absolute; top: 0; right: 0; width: 10px; height: 10px; background: transparent url('corner.png') no-repeat top right; } This works fine in all browsers expcept IE6. In IE6 the corner.png image seems to be about 1px out at the top corner, essentially not top: 0; and right: 0; but more like top: 1px; right: 1px; Can anyone explain why this might be happening only in IE6?

    Read the article

  • Can I use the Airport Express as a an uplink between two networks?

    - by Ant Swift
    I have two separate networks using different IP ranges, 192.168.0.* for the wired only, isolated network and 192.160.1.* for the wireless only network which is connected to the internet. The wired network has a network printer setup and working and I want to be able to share it out to members of the wireless network (see diagram below). In short I need some kind of uplink between the two networks. Currently running a cable is out since there is no suitable route. I have a spare Airport Express and I am wondering if I could attach it to the wired network and have it join the wireless and act as the uplink between the two. Anyone know if the device is capable of this?

    Read the article

  • How do I share a home printer under Windows if the computer is part of a domain?

    - by Sorin Sbarnea
    I do have my work laptop at home and I want to share an USB printer in order to be able to print to it from my MacBook. Currently Windows 7 is refusing to share the printer because the computer is part of a domain and it tells me that I need to join a homegroup in order to be able to do that. Also it tells me that he cannot create this homegroup and this group has to be create by another Windows 7 computer from my network. As you can imagine I do have only one Windows computer on my home network. How can I solve this problem?

    Read the article

  • little java help....

    - by jona
    Hi I am doing some practice problems and trying to print a diagonal line like the example below. I have writen the program you see below and I honestly dont understand what I am doing wrong. I m a java beginner and I cant see how to find the error. Example ( If you only see a straight line of stars...then imagine it diagonally....from top left to bottom right) * * * * * code: class Diagonal{ public static void main(String args[]) { int row, col; for(row = 1; row < 6; row++) { for(col = 1; col <= row; col++) { if(col==row){ System.out.print("*"); } else{ System.out.print(""); } System.out.println(); } } } } I am trying to learn for loops because they really confuse me. Another practice is to print a similar diagonal line but this time from right to left. I cant do that without getting this right however :( I believe they will be pretty similar? Above my reasining is this: As long as the column # is the same as the row number the print the line or otherwise leave a blank....what's wrong with how i did it? THANK YOU!

    Read the article

  • Building a Server at Home

    - by madhairsilence
    Am left with a Spare PC . So , I thought of converting it to a Server kind of thing. I read about NAS Serer for simple file storage. But it is just a file server. I also play games like counter strike and other online games. So, I would like to use the same server for those purpose., so that a game server will running all the time so that me and my friends can join any time. Is running NAS server a best option or, is there any better arrangement possible so that my spare system can act better than a simple file server

    Read the article

  • osx 10.6 dhcp client-id option

    - by Clustermagnet
    Trying to join a osx machine on a dhcp network which forces certain client IDs. Even if I was to modify the client-id via the network properties, the DHCP server is not accepting this request, since Windows and Apple send this via different options You can set the ClassID in the Network Control Panel in the DHCP Client ID box. The trick lies in setting up your DHCP server to recognize it. Windows XP sends the DHCP class ID via DHCP option 77, and OS X sends it via option 61. You'll have to set your DHCP server to check for option 61, +with an offset of 1 and a length of 9+. That's the tricky bit. So, without modifying the DHCP server... (which does not belong to me), is there anything that can be done on OSX to modify the client-id option to be 77?

    Read the article

  • How to put JFrame into existing JPanel in Java Swing?

    - by suud
    I have an open-source java swing application like this: http://i47.tinypic.com/dff4f7.jpg You can see in the screenshot, there is a JPanel divided into two area, left and right area. The left area has many text links. When I click the SLA Criteria link, it will pop-up the SLA Criteria window. The pop-up window is JFrame object. Now, I'm trying to put the pop-up window into right area of the JPanel, so that means no pop-up window anymore, i.e. when I click the SLA Criteria link, its contents will be displayed at the right area of the JPanel. The existing content of the right area of JPanel will not be used anymore. The example illustration (note: it's made and edited using image editor, this is not the real screenshot of working application) is like this: http://i48.tinypic.com/5vrxaa.jpg So, I would like to know is there a way to put JFrame into JPanel? I'm thinking of using JInternalFrame, is it possible? Or is there another way? UPDATE: Source code: http://pastebin.com/tiqRbWP8 (VTreePanel.java, this is the JPanel) http://pastebin.com/330z3yuT (CPanel.java, this is the super class of VTreePanel) http://pastebin.com/MkNsbtjh (AWindow.java, this is the JFrame, pop-up window) http://pastebin.com/2rsppQeE (CFrame.java, this is the super class of AWindow)

    Read the article

  • Set 802.1Q tagged port on VLAN1 on Dell PowerConnect switch

    - by Javier
    I'm having big troubles when adding this Dell switch to my network. Here we use several VLANs to segment traffic. All switches (3com and DLink mostly) have configured the same VLANs, most ports are 'untagged' and belong to a single VLAN, except for the ports used to join together the switches (in a star topology), these ports belong to all VLANs and use 802.1Q tags. So far, it works really well. But on this new switch (a Dell PowerConnect 5448), the settings are very different (and confusing). I have configured the same VLANs, an the uplink ports are set in 'general' mode (supposed to be fully 802.1Q compliant), I can set the VLAN membership as 'T' on these ports for all VLANs except VLAN 1. It always stay as 'U' on VLAN 1. Any ideas?

    Read the article

  • Got problem when uploading the html into the webview in iphone sdk.

    - by Monish Kumar
    Hi Guy's NSString* appendString=@""; appendString = [appendString stringByAppendingString:@"<body>"]; appendString =[appendString stringByAppendingString:@"<table background='footer.png' width='320' height='45' style='background-repeat:no-repeat'>"]; appendString =[appendString stringByAppendingString:@"<tr>"]; appendString =[appendString stringByAppendingString:@"<td align='left' width='57' height='31' style='padding: 6px 0 0 0' ><a href='/map/'><img src='details_Back.png'/></a></td>"]; appendString =[appendString stringByAppendingString:@"<td align='left' valign='middle' style='padding: 0 0 0 65px; font-family:Helvetica; font-size:21px ; font-weight:bold ; color:#FFF'>Details</td>"]; appendString =[appendString stringByAppendingString:@"</tr>"]; appendString =[appendString stringByAppendingString:@"</table>"]; appendString =[appendString stringByAppendingString:@"<br>"]; returnString = [returnString stringByReplacingOccurrencesOfString:@"<body>" withString:appendString]; printf("\n return string :%s",[returnString UTF8String]); [myWebView loadHTMLString:returnString baseURL:[NSURL URLWithString:@"http://abc.api.abcdefg.com/"]]; here in the above code the footer.png and details_back.png are the local images stored in my resource folder. Here the problem is I am gettin the background image from the server link I had passed to the webview as baseurl but the images footer.png and details_back.png which were stored in resource is not displayed. if I use the resource bundle as the baseurl then I am not displayed the background image from the server link. Can anyone please give me the suggestions to get rid of rid of this problem. thanks to all guy's, Monish.

    Read the article

  • iTextSharp Overlay Image

    - by pennylane
    Hi guys I have an instance where I have a logo image as part of some artwork.. If a user uploads a new logo I have a form field which is larger than the default logo. I then use that form field to position the new image. The problem is I need to set the background colour of that form field to white so that it covers the old logo in the event that the new image is smaller than the old logo.. what I have done is: foreach (var imageField in imageReplacements) { fields.SetFieldProperty(imageField.Key, "bgcolor", iTextSharp.text.Color.WHITE, null); fields.RegenerateField(imageField.Key); PdfContentByte overContent = stamper.GetOverContent(imageField.Value.PageNumber); float[] logoArea = fields.GetFieldPositions(imageField.Key); if (logoArea != null) { iTextSharp.text.Rectangle logoRect = new iTextSharp.text.Rectangle(logoArea[1], logoArea[2], logoArea[3], logoArea[4]); var logo = iTextSharp.text.Image.GetInstance(imageField.Value.Location); if (logo.Width >= logoRect.Width || logo.Height >= logoRect.Height) { logo.ScaleToFit(logoRect.Width, logoRect.Height); } logo.Alignment = iTextSharp.text.Image.ALIGN_LEFT; logo.SetAbsolutePosition(logoRect.Left, logoArea[2] + (logoRect.Height - logo.ScaledHeight) / 2); // left: logoArea[3] - logo.ScaledWidth + (logoRect.Width - logo.ScaledWidth) / 2 overContent.AddImage(logo); } } The problem with this is that the background colour of the field is set to white and the image then doesn't appear.. i remove the SetFieldProperty and RegenerateField commands and the image replacement works fine.. is there a way to set a stacking order on layers?

    Read the article

  • Grid does not get auto size wpf

    - by Jasim Khan Afridi
    I have a Grid inside a grid. I want it to to avail maximum size irrespective of window size. Main_Grid should be max width Grid_tool_bar should be max width but infact it is not. I am unable to find the reason. Plz help me out. <Window x:Class="SocialNetworkingApp.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="MainWindow" Background="White" WindowStyle="None" HorizontalAlignment="Stretch" WindowState="Normal" AllowsTransparency="True" WindowStartupLocation="CenterScreen"> <Border Margin="0,0,0,0" BorderBrush="Black" BorderThickness="1,1,1,1" > <Grid x:Name="Main_Grid" Background="White" Width="Auto" Height="Auto" Margin="0,0,0,0" HorizontalAlignment="Left" VerticalAlignment="Top"> <Grid.RowDefinitions> <RowDefinition Height="30" /> <RowDefinition Height="25"/> <RowDefinition Height="50"/> <RowDefinition Height="Auto"/> <RowDefinition Height="20"/> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="1*"/> </Grid.ColumnDefinitions> <Grid Name="Title_Bar" Grid.Row="0" VerticalAlignment="Top" ShowGridLines="True" Grid.IsSharedSizeScope="True" MouseDown="Drag_Window" Background="#FF4FA2DA" HorizontalAlignment="Left" Width="766" Height="31"> <Grid.RowDefinitions> <RowDefinition Height="Auto" /> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="30"/> <ColumnDefinition Width="Auto"/> <ColumnDefinition Width="120" /> </Grid.ColumnDefinitions> </Grid> </Grid> </Border> </Window>

    Read the article

  • Is it possible to install and use a printer in Azure Worker Roles?

    - by lurkerbelow
    I'd like to know if it's possible to create and use a printer in Azure Worker Roles. I do know that I can install printers with basic batch commands. So I could define a batch script that would run as a startup task. something like: rundll32 printui.dll,PrintUIEntry /if /b "printer" /f %windir%\inf\ntprint.inf /r "file:" /m "printername") Question: Can I use a printer to print to file, maybe to local storage? I do need the function to print to file or atleast to have a printer installed, because I have to get the PCL output from different installed printers. Sadly I can not test it by myself. I do not have a CC to join the 90 days trial.

    Read the article

  • The XPath @root-node-position attribute info

    - by Igor Savinkin
    I couldn't find the @root-node-position XPath attribute info. Would you give me a link of where i can read about it? Is it XPath 2.0? The code (not mine) is ../preceding-sibling::div[1]/div[@root-node-position]/div applied to this HTML: <div class="left"> <div class='prod2'> <div class='name'>Dell Latitude D610-1.73 Laptop Wireless Computer </div>2 GHz Intel Pentium M, 1 GB DDR2 SDRAM, 40 GB </div> <div class='prod1'> <div class='name'>Samsung Chromebook (Wi-Fi, 11.6-Inch) </div>1.7 GHz, 2 GB DDR3 SDRAM, 16 GB </div> </div> <div class="right"> <div class='price2'>$239.95</div> <div class='price1 best'>$249.00</div> </div> Firstly i fetch a price text under class='right' with this query : //DIV[contains(@class,'best')] and then i apply the above mentioned XPath with @root-node-attribute under class='left' to retrieve the rest of the record info.

    Read the article

  • How to set up my network/bridging using Apple Airport equipment?

    - by John
    I'd like to set up my network like this, and I want to make sure it's possible using the hardware I have. I think it should be... I've got my cable modem in one room. I want to plug it into an Apple Airport Express and create my wireless my wireless network here. The airport express will do the NAT and DHCP. By my TV there are a few things to be networked (Xbox and Tivo). I have an airport extreme here. I'd like to have the airport extreme join the wireless network and share the connection to the ethernet ports. Can anyone provide some assistance on the best way to configure to do this? Thanks!

    Read the article

  • Java BoxLayout alignment issue

    - by ManInMoon
    Can anyone help me. Why is the Label "Current" NOT left aligned in Panel/Frame? public static void main(String[] args) { JFrame TFrame = new JFrame("Test DisplayLayout"); TFrame.setResizable(true); TFrame.setSize(new Dimension(900, 840)); TFrame.setLocationRelativeTo(null); TFrame.setTitle("DisplayLayout"); TFrame.setVisible(true); JPanel P = DisplayLayout2(); P.setVisible(true); P.setOpaque(true); P.setLayout(new BoxLayout(P, BoxLayout.Y_AXIS)); TFrame.add(P); TFrame.revalidate(); TFrame.repaint(); } public static JPanel DisplayLayout2() { JPanel Panel=new JPanel(); Panel.setVisible(true); Panel.setOpaque(true); Panel.setLayout(new BoxLayout(Panel, BoxLayout.Y_AXIS)); Panel.setAlignmentX(Component.LEFT_ALIGNMENT); JLabel lab = new JLabel("Current"); lab.setHorizontalAlignment(SwingConstants.LEFT); lab.setForeground(Color.WHITE); lab.setBackground(Color.PINK); lab.setOpaque(true); Panel.add(lab,Component.LEFT_ALIGNMENT); JPanel posPanel = new JPanel(); JScrollPane scrollPane = new JScrollPane(posPanel,JScrollPane.VERTICAL_SCROLLBAR_ALWAYS,JScrollPane.HORIZONTAL_SCROLLBAR_NEVER); scrollPane.setPreferredSize(new Dimension(290, 200)); scrollPane.setOpaque(true); posPanel.setBackground(Color.YELLOW); posPanel.setPreferredSize(new Dimension(290, 200)); posPanel.setLayout(new BoxLayout(posPanel, BoxLayout.Y_AXIS)); posPanel.setAlignmentX(Component.LEFT_ALIGNMENT); Panel.add(scrollPane); return Panel; }

    Read the article

  • Using Mergesort to calculate number of inversions in C++

    - by Brown
    void MergeSort(int A[], int n, int B[], int C[]) { if(n > 1) { Copy(A,0,floor(n/2),B,0,floor(n/2)); Copy(A,floor(n/2),n-1,C,0,floor(n/2)-1); MergeSort(B,floor(n/2),B,C); MergeSort(C,floor(n/2),B,C); Merge(A,B,0,floor(n/2),C,0,floor(n/2)-1); } }; void Copy(int A[], int startIndexA, int endIndexA, int B[], int startIndexB, int endIndexB) { while(startIndexA < endIndexA && startIndexB < endIndexB) { B[startIndexB]=A[startIndexA]; startIndexA++; startIndexB++; } }; void Merge(int A[], int B[],int leftp, int rightp, int C[], int leftq, int rightq) //Here each sub array (B and C) have both left and right indices variables (B is an array with p elements and C is an element with q elements) { int i=0; int j=0; int k=0; while(i < rightp && j < rightq) { if(B[i] <=C[j]) { A[k]=B[i]; i++; } else { A[k]=C[j]; j++; inversions+=(rightp-leftp); //when placing an element from the right array, the number of inversions is the number of elements still in the left sub array. } k++; } if(i=rightp) Copy(A,k,rightp+rightq,C,j,rightq); else Copy(A,k,rightp+rightq,B,i,rightp); } I am specifically confused on the effect of the second 'B' and 'C' arguments in the MergeSort calls. I need them in there so I have access to them for Copy and and Merge, but

    Read the article

  • XNA Vector2 Rotation Question

    - by Tom Allen
    I'm messing about with some stuff in XNA and am trying to move an object around asteroids-style in that you press left and right to rotate and up/down to go forwards and backwards in the direction you are pointing. I've got the rotation of the sprite done, but i can't get the object to move in the direction you've pointed it, it always moves up and down on the x = 0 axis. I'm guessing this is straight forward but I just can't figure it out. My "ship" class has the following properties which are note worthy here: Vector2 Position float Rotation The "ship" class has an update method is where the input is handled and so far I've got the following: public void Update(GameTime gameTime) { KeyboardState keyboard = Keyboard.GetState(); GamePadState gamePad = GamePad.GetState(PlayerIndex.One); float x = Position.X; float y = Position.Y; if (keyboard.IsKeyDown(Keys.Left)) Rotation -= 0.1f; if (keyboard.IsKeyDown(Keys.Right)) Rotation += 0.1f; if (keyboard.IsKeyDown(Keys.Up)) y -= ??; if (keyboard.IsKeyDown(Keys.Down)) y += ??; this.Position = new Vector2(x, y); } Any help would be most appreciated!

    Read the article

  • JQuery use variable by name of divID

    - by Russell Parrott
    Just a quick question, that I cannot fathom out, hope you guys and girls can help. I have a div (with ID) that when clicked opens a new div - great works well, what I really want is to "populate" the new div with predefined text based on the clicked div's ID. example: <div class="infobox" id="help_msg1">Click me</div> I may have say 3 (actually more but...) of these div's This opens: <div id="helpbox">text in here</div> In/on my .js page I have doc ready etc then: var help_msg1 ='text that is a help message'; var help_msg2 ='text that is another help message'; var help_msg3 ='text that is yet another help message'; Then $('.infobox').live('click',function() { $('#helpbox').remove(); $('label').css({'font-weight': '400'}); $(this).next('label').css({'font-weight': '900'}); var offset = $(this).next().next().offset(); var offsetby = $(this).next().next().width(); var leftitby = offset.left+offsetby+10; $('body').append('text in here'); $('#helpbox').css( { 'left': leftitby, 'top': offset.top } ); }); Note I remove each #helpbox before appending the new one and the .next().next() identifies the appropriate text input that lot all works. What I need is how do I put var help_msg1 into the append when id="help_msg1" is clicked or var help_msg2 when id="help_msg2" is clicked etc. I have tried

    Read the article

  • Titanium TableViewRow classname with custom rows

    - by pancake
    I would like to know in what way the 'className' property of a Ti.UI.TableViewRow helps when creating custom rows. For example, I populate a tableview with custom rows in the following way: function populateTableView(tableView, data) { var rows = []; var row; var title, image; var i; for (i = 0; i < data.length; i++) { title = Ti.UI.createLabel({ text : data[i].title, width : 100, height: 30, top: 5, left: 25 }); image = Ti.UI.createImage({ image : 'some_image.png', width: 30, height: 30, top: 5, left: 5 }); /* and, like, 5+ more views or whatever */ row = Ti.UI.createTableViewRow(); row.add(titleLabel); row.add(image); rows.push(row); } tableView.setData(rows); } Of course, this example of a "custom" row is easily created using the standard title and image properties of the TableViewRow, but that isn't the point. How is the allocation of new labels, image views and other child views of a table view prevented in favour of their reuse? I know in iOS this is achieved by using the method -[UITableView dequeueReusableCellWithIdentifier:] to fetch a row object from a 'reservoir' (so 'className' is 'identifier' here) that isn't currently being used for displaying data, but already has the needed child views laid out correctly in it, thus only requiring to update the data contained within (text, image data, etc). As this system is so unbelievably simple, I have a lot of trouble believing the method employed by the Titanium API does not support this. After reading through the API and searching the web, I do however suspect this is the case. The 'className' property is recommended as an easy way to make table views more efficient in Titanium, but its relation to custom table view rows is not explained in any way. If anyone could clarify this matter for me, I would be very grateful.

    Read the article

< Previous Page | 285 286 287 288 289 290 291 292 293 294 295 296  | Next Page >