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  • I have a problem with mysql and php

    - by neo skosana
    Hi I have a problem, this is my code: $db = new mysqli("localhost", "root", "", "blah"); $result1 = $db-query("select * from c_register where email = '$eml' and password = '$pass'"); if($result1-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'client'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result2 = $db-query("select * from b_register where email = '$eml' and password = '$pass'"); if($result2-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'business'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result3 = $db-query("select * from g_register where email = '$eml' and password = '$pass'"); if($result3-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'employee'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result4 = $db-query("select * from k_register where email = '$eml' and password = '$pass'"); if($result4-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'super'; promptUser("You have successfully logged in!!!","index.php"); } else { promptUser("Username/Password do not match. Please try again!!!",""); } Funny enough this code works, but I no that I went about it the wrong way. I am new with php and mysql, so please help. I also tried e.gresult4->free(); for all the variable that save the data, and I got this error: Fatal error: Call to a member function free() on a non-object in...

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  • iPhone - Problem with in-app purchases

    - by Satyam svv
    I've created iPhone app with in-app purchase. Now, I'm in testing phase. I created provisioning profile com.satyam.testapp In iTunes connected I created the application and uploaded the images, screen shots, desscription etc. I also created two id's for in-app purchase. One is com.satyam.testapp.book1 and the other one is com.satyam.testapp.book5 I created test account also for verifying my in-app purchases. Using com.stayam.testapp i created developer test profile and using the same in my developed application. I logged out the itunes app store account in my iphone. Now i started running my application on my iphone. Its saying that no items are there to purchase. But its not even asking me for credentials where i've to enter test account username and password..... how to debug it? Here's my delegate: - (void)productsRequest:(SKProductsRequest *)request didReceiveResponse:(SKProductsResponse *)response { NSArray *myProduct = [[NSArray alloc] initWithArray:response.products]; for(int i=0;i<[myProduct count];i++) { SKProduct *product = [myProduct objectAtIndex:i]; NSLog(@"Name: %@ - Price: %f",[product localizedTitle],[[product price] doubleValue]); NSLog(@"Product identifier: %@", [product productIdentifier]); } for(NSString *invalidProduct in response.invalidProductIdentifiers) NSLog(@"Problem in iTunes connect configuration for product: %@", invalidProduct); [request autorelease]; [myProduct release]; }

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  • Problem convert column values from VARCHAR(n) to DECIMAL

    - by Kevin Babcock
    I have a SQL Server 2000 database with a column of type VARCHAR(255). All the data is either NULL, or numeric data with up to two points of precision (e.g. '11.85'). I tried to run the following T-SQL query but received the error 'Error converting data type varchar to numeric' SELECT CAST([MyColumn] AS DECIMAL) FROM [MyTable]; I tried a more specific cast, which also failed. SELECT CAST([MyColumn] AS DECIMAL(6,2)) FROM [MyTable]; I also tried the following to see if any data is non-numeric, and the only values returned were NULL. SELECT ISNUMERIC([MyColumn]), [MyColumn] FROM [MyTable] WHERE ISNUMERIC([MyColumn]) = 0; I tried to convert to other data types, such as FLOAT and MONEY, but only MONEY was successful. So I tried the following: SELECT CAST(CAST([MyColumn] AS MONEY) AS DECIMAL) FROM [MyTable]; ...which worked just fine. Any ideas why the original query failed? Will there be a problem if I first convert to MONEY and then to DECIMAL? Thanks!

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  • Object Oriented Programming Problem

    - by Danny Love
    I'm designing a little CMS using PHP whilst putting OOP into practice. I've hit a problem though. I have a page class, whos constructor accepts a UID and a slug. This is then used to set the properties (unless the page don't exist in which case it would fail). Anyway, I wanted to implement a function to create a page, and I thought ... what's the best way to do this without overloading the constructor. What would the correct way, or more conventional method, of doing this be? My code is below: <?php class Page { private $dbc; private $title; private $description; private $image; private $tags; private $owner; private $timestamp; private $views; public function __construct($uid, $slug) { } public function getTitle() { return $this->title; } public function getDescription() { if($this->description != NULL) { return $this->description; } else { return false; } } public function getImage() { if($this->image != NULL) { return $this->image; } else { return false; } } public function getTags() { if($this->tags != NULL) { return $this->tags; } else { return false; } } public function getOwner() { return $this->owner; } public function getTimestamp() { return $this->timestamp; } public function getViews() { return $this->views; } public function createPage() { // Stuck? } }

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  • db4o problem with graph of objects

    - by Staszek28
    I am a new to db4o. I have a big problem with persistance of a graph of objects. I am trying to migrate from old persistance component to new, using db4o. Before I peristed all objects its graph looked like below (Take a look at Zrodlo.Metadane.abstrakt string field with focused value) [its view from eclipse debuger] with a code: ObjectContainer db=Db4o.openFile(DB_FILE); try { db.store(encja); db.commit(); } finally{ db.close(); } After that, I tried to read it with a code: ObjectContainer db=Db4o.openFile((DB_FILE)); try{ Query q = db.query(); q.constrain(EncjaDanych.class); ObjectSet<Object> objectSet = q.execute(); logger.debug("objectSet.size" + objectSet.size()); EncjaDanych encja = (EncjaDanych) objectSet.get(0); logger.debug("ENCJA" + encja.toString()); return encja; }finally{ db.close(); } and I got it (picture below) - string field "abstrakt" is null now !!! I take a look at it using ObjectManager (picture below) and abstrakt field has not-null value there!!! The same value, that on the 1st picture. Please help me :) It is my second day with db4o. Thanks in advance! I am attaching some code with structure of persisted class: public class EncjaDanych{ Map mapaIdRepo = new HashMap(); public Map mapaNazwaRepo = new HashMap(); }

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  • CanCan polymorphic resource access problem

    - by Call 'naive' True
    Hi everybody, i don't quite understand how to restrict access to links in this particular case with CanCan. I always get "Edit" link displayed. So i believe the problem is in my incorrect definition of cancan methods(load_ and authorize_). I have CommentsController like that: class CommentsController < ApplicationController before_filter :authenticate_user! load_resource :instance_name => :commentable authorize_resource :article def index @commentable = find_commentable #loading our generic object end ...... private def find_commentable params.each { |name, value| if name =~ /(.+)_id$/ return $1.classify.constantize.includes(:comments => :karma).find(value) end } end end and i have in comments/index.html.erb following code that render file from other controller: <%= render :file => "#{get_commentable_partial_name(@commentable)}/show.html.erb", :collection => @commentable %> you can think about "#{get_commentable_partial_name(@commentable)}" like just "articles" in this case. Content of "articles/show.html.erb": <% if can? :update, @commentable %> <%= link_to 'Edit', edit_article_path(@commentable) %> | <% end %> my ability.rb: class Ability include CanCan::Ability def initialize(user) user ||= User.new # guest user if user.role? :admin can :manage, :all elsif user.role? :author can :read, [Article, Comment, Profile] can :update, Article, :user_id => user.id end end end relations with models is: class Comment < ActiveRecord::Base belongs_to :commentable, :polymorphic => true, :dependent => :destroy ... end class Article < ActiveRecord::Base has_many :comments, :as => :commentable, :dependent => :destroy ... end i have tried debug this issue like that user = User.first article = Article.first ability = Ability.new(user) ability.can?(:update, article) and i always get "= true" in ability check Note: user.role == author and article.user_id != user.id if you need more information please write thank's for your time && sorry for my english

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  • Problem with .release behavior in file_operations

    - by Yannick
    Hello, I'm dealing with a problem in a kernel module that get data from userspace using a /proc entry. I set open/write/release entries for my own defined /proc entry, and manage well to use it to get data from userspace. I handle errors in open/write functions well, and they are visible to user as open/fopen or write/fwrite/fprintf errors. But some of the errors can only be checked at close (because it's the time all the data is available). In these cases I return something different than 0, which I supposed to be in some way the value 'close' or 'fclose' will return to user. But whatever the value I return my close behave like if all is fine. To be sure I replaced all the release() code by a simple 'return(-1);' and wrote a program that open/write/close the /proc entry, and prints the close return value (and the errno). It always return '0' whatever the value I give. Behavior is the same with 'fclose', or by using shell mechanism (echo "..." /proc/my/entry). Any clue about this strange behavior that is not the one claimed in many tutorials I found? BTW I'm using RHEL5 kernel (2.6.18, redhat modified), on a 64bit system. Thanks. Regards, Yannick

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  • Problem with poor font rendering with CSS3 transitions, jQuery, & Google Fonts

    - by Justin
    In Firefox, there is no problem. Here's an image: http://cl.ly/3R0L1q3P1r11040e3T1i In Safari, the text is rendering poorly: http://cl.ly/0a1101341r2E1D2d1W46 In IE7 & IE8, it's much worse, but I don't have a picture. Sorry :( I'm using Isotope jQuery plugin, and the CSS3 transitions seem to cause the poor font-rendering. I'm also using Google Font API. Here's what the CSS transitions for Isotope are written as: /**** Isotope CSS3 transitions ****/ .isotope, .isotope .isotope-item { -webkit-transition-duration: 0.8s; -moz-transition-duration: 0.8s; transition-duration: 0.8s; } .isotope { -webkit-transition-property: height, width; -moz-transition-property: height, width; transition-property: height, width; } .isotope .isotope-item { -webkit-transition-property: -webkit-transform, opacity; -moz-transition-property: -moz-transform, opacity; transition-property: transform, opacity; } I appreciate any help with this. Looks great in Firefox! Thanks!

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  • Problem using the prependTo() in jQuery

    - by raulriera
    Hi all, I am having a problem trying to use the prependTo() function in jQuery... for some reason I can't get this to work $(" <div id="note178" class="note"> <div class="delete"><a href="/chart-notes/delete/178" onclick="$.ajax({ dataType: 'script', url: '/chart-notes/delete/178'}); return false;"><img src='/images/icons/delete.png'></a></div> <div class="timestamp">1 minute ago </div> <div class="content">ñasdas dasdasdasd conclusión</div> </div> ").prependTo(".notes").fadeIn("slow"); Although when doing it like this, it works fine $.ajax({ url:'/chart-notes/show/<cfoutput>#chartnote.id#</cfoutput>', success: function(data) { $(data).prependTo(".notes").fadeIn("slow"); // Scroll to the top of the annotations $('html, body').animate({scrollTop: $(".notes").offset().top}, 1000); // Clear the form $('#chartnote-notes').val(""); } }); The "data" response from that success function is the same <div id="note178" class="note"> <div class="delete"><a href="/chart-notes/delete/178" onclick="$.ajax({ dataType: 'script', url: '/chart-notes/delete/178'}); return false;"><img src='/images/icons/delete.png'></a></div> <div class="timestamp">1 minute ago </div> <div class="content">ñasdas dasdasdasd conclusión</div> </div> As before

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  • first data global gateway API - invalid XML problem

    - by B.Georg
    Hello, i am implementing the First Data Global Gateway API into a Java E-Commerce Web application. The problem that i have is that I get an error message SGS-020003: Invalid XML returned from the staging.linkpt.net server. By switching the optional entities off, I managed to locate the problematic entity. It is the Shipping entity. I have the following data inside it: <shipping> <zip>10105</zip> <phone>123456789</phone> <email>[email protected]</email> <name>DJBla</name> <state>NY</state> <address1>some city</address1> <address2>suite 6</address2> <city>New York</city> <country>US</country> </shipping> According to the First Data Global Gateway User Manual Version 1.1 everything is correct with my XML. Would anyone have an idea where the error could be? Kind Regards, B.Georg

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  • Uva's 3n+1 problem

    - by dmindreader
    I'm solving Uva's 3n+1 problem and I don't get why the judge is rejecting my answer. The time limit hasn't been exceeded and the all test cases I've tried have run correctly so far. import java.io.*; public class NewClass{ /** * @param args the command line arguments */ public static void main(String[] args) throws IOException { int maxCounter= 0; int input; int lowerBound; int upperBound; int counter; int numberOfCycles; int maxCycles= 0; int lowerInt; BufferedReader consoleInput = new BufferedReader(new InputStreamReader(System.in)); String line = consoleInput.readLine(); String [] splitted = line.split(" "); lowerBound = Integer.parseInt(splitted[0]); upperBound = Integer.parseInt(splitted[1]); int [] recentlyused = new int[1000001]; if (lowerBound > upperBound ) { int h = upperBound; upperBound = lowerBound; lowerBound = h; } lowerInt = lowerBound; while (lowerBound <= upperBound) { counter = lowerBound; numberOfCycles = 0; if (recentlyused[counter] == 0) { while ( counter != 1 ) { if (recentlyused[counter] != 0) { numberOfCycles = recentlyused[counter] + numberOfCycles; counter = 1; } else { if (counter % 2 == 0) { counter = counter /2; } else { counter = 3*counter + 1; } numberOfCycles++; } } } else { numberOfCycles = recentlyused[counter] + numberOfCycles; counter = 1; } recentlyused[lowerBound] = numberOfCycles; if (numberOfCycles > maxCycles) { maxCycles = numberOfCycles; } lowerBound++; } System.out.println(lowerInt +" "+ upperBound+ " "+ (maxCycles+1)); } }

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  • Project euler problem 3 in haskell

    - by shk
    I'm new in Haskell and try to solve 3 problem from http://projecteuler.net/. The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143 ? My solution: import Data.List getD :: Int -> Int getD x = -- find deviders let deriveList = filter (\y -> (x `mod` y) == 0) [1 .. x] filteredList = filter isSimpleNumber deriveList in maximum filteredList -- Check is nmber simple isSimpleNumber :: Int -> Bool isSimpleNumber x = let deriveList = map (\y -> (x `mod` y)) [1 .. x] filterLength = length ( filter (\z -> z == 0) deriveList) in case filterLength of 2 -> True _ -> False I try to run for example: getD 13195 > 29 But when i try: getD 600851475143 I get error Exception: Prelude.maximum: empty list Why? Thank you @Barry Brown, I think i must use: getD :: Integer -> Integer But i get error: Couldn't match expected type `Int' with actual type `Integer' Expected type: [Int] Actual type: [Integer] In the second argument of `filter', namely `deriveList' In the expression: filter isSimpleNumber deriveList Thank you.

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  • Problem with sprintf function, last parameters are wrong when written

    - by Apoc
    So I use sprintf sprintf(buffer,"%f|%f|%f|%f|%f|%f|%d|%f|%d", x, y, z, u, v, w, nID,dDistance, nConfig) But when I print the buffer I get the 2 last parameters wrong, they are lets suppose to be 35.0000 and 0 and in the string they are 0.00000 and 10332430 and my buffer is long enough and all the other parameters are good in the string Any idea? Is there a length limit to sprintf or something^ I checked the types of all the numbers and they are right, but what seems to be the problem is the dDistance. When I remove it from the sprint, the nConfig gets the right value in the string, but when I remove nConfig, dDistance still doesn't get the right value. I checked and dDistance is a double. Any idea? Since people don't seem to believe me I did this : char test[255]={0}; int test1 = 2; double test2=35.00; int test3 = 0; sprintf(test,"%d|%f|%d",test1,test2,test3); and I get this in my string: 2|0.000000|1078034432

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  • Copy recordset data into multiple sheets to avoid problem of maximum rows limit in Excel VBA

    - by Sam
    I am developing reporting application in Excel/vba 2003. VBA code sends search query to database and gets the data through recordset. It will then be copied to one of excel sheet. The rertrieved data looks like as shown below. ProductID--|---DateProcessed--|----State----- 1................|.. 1/1/2010..............|.....Picked Up 1................|.. 1/1/2010..............|.....Forward To Approver 1................|.. 1/2/2010..............|.....Approver Picked Up 1................|.. 1/3/2010..............|.....Approval Completed 2................|.. 1/1/2010..............|.....Picked Up 3................|.. 1/2/2010..............|.....Picked Up 3................|.. 1/2/2010..............|.....Forward To Approver The problem is data retrieved from search query is so huge that it goes above the excel row limit (65536 rows in excel 2003). So I want to split this data into two excel sheets. While spliting the data I want to ensure that the data for same product shoud remain in one sheet. For example, if the last record in the above result set is 65537th record then I also want to move all records for product 3 into new sheet. So sheet1 will contain records for product id 1 and 2 with total records = 65534. Sheet 2 will cotain records for product id 3 - with total records = 2. How can I acheive this in vba? If it is not possible, is there any alternative solution ? Thanks in Advance !

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  • Decimal problem in Java

    - by Jerome
    I am experimenting with writing a java class for financial engineering (hobby of mine). The algorithm that I desire to implement is: 100 / 0.05 = 2000 Instead I get: 100 / 0.05 = 2000.9999999999998 I understand the problem to be one with converting from binary numbers to decimals (float -- int). I have looked at the BigDecimal class on the web but have not quite found what I am looking for. Attached is the program and a class that I wrote: // DCF class public class DCF { double rate; double principle; int period; public DCF(double $rate, double $principle, int $period) { rate = $rate; principle = $principle; period = $period; } // returns the console value public double consol() { return principle/rate; } // to string Method public String toString() { return "(" + rate + "," + principle + "," + period + ")"; } } Now the actual program: // consol program public class DCFmain { public static void main(String[] args) { // create new DCF DCF abacus = new DCF(0.05, 100.05, 5); System.out.println(abacus); System.out.println("Console value= " + abacus.consol() ); } } Output: (0.05,100.05,5) Console value= 2000.9999999999998 Thanks!

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  • Server Push CGI Perl Problem writing the JPEG image

    - by Jujjuru
    I am a beginner in Perl CGI etc. I was experimenting with server-push concept with a piece of perl code. It is supposed to send a jpeg image to the client every 3 seconds. Unfortunately nothing seems to work. Can somebody help identify the problem? Here is the code.... use strict; # turn off io buffering $|=1; print "Content-type: multipart/x-mixed-replace;"; print "boundary=magicalboundarystring\n\n"; print "--magicalboundarystring\n"; #list the jpg images my(@file_list) = glob "*.jpg"; my($file) = ""; foreach $file(@file_list ) { open FILE,">", $file or die "Cannot open file $file: $!"; print "Content-type: image/jpeg\n\n"; while ( <FILE> ) { print "$_"; } close FILE; print "\n--magicalboundarystring\n"; sleep 3; next; } EDIT: added turn off i/o buffering, added "use strict" and "@file_list", "$file" are made local

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  • problem with drag and drop for the winform using c#

    - by karthik
    I dont have the title bar in my winform, so i need to code drag and drop for the entire form. I am using the below code to do it, which works fine. I have two panels in my form, PanelA and PanelB. During the startup i show PanelA where the drag and drop works perfectly. Later when the user clicks the button in PannelA, i need to make PanelA visible false and show the PanelB My drag and drop is not working when the PanelB is loaded in form. Whats the problem here ? private void SerialPortScanner_MouseUp(object sender, MouseEventArgs e) { this.drag = false; } private void SerialPortScanner_MouseDown(object sender, MouseEventArgs e) { this.drag = true; this.start_point = new Point(e.X, e.Y); } private void SerialPortScanner_MouseMove(object sender, MouseEventArgs e) { if (this.drag) { Point p1 = new Point(e.X, e.Y); Point p2 = this.PointToScreen(p1); Point p3 = new Point(p2.X - this.start_point.X, p2.Y - this.start_point.Y); this.Location = p3; } }

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  • sqlite3 DELETE problem "Library Routine Called Out Of Sequence"

    - by Michael Bordelon
    Here is my second stupid Noob problem. I am trying to do a simple Delete and I keep blowing up on the prepare step. I already have other Deletes, Inserts, Updates and Selects working. I am sure it is something simple. I appreciate your help. + (void)flushTodaysWorkouts { sqlite3_stmt *statement = nil; //open the database if (sqlite3_open([[BIUtility getDBPath] UTF8String], &database) != SQLITE_OK) { sqlite3_close(database); NSAssert(0, @"Failed to opendatabase"); } NSArray *woList = [self todaysScheduledWorkouts]; for (Workout *wo in woList) { NSInteger woID = wo.woInstanceID; if(statement == nil) { const char *sql = "DELETE FROM IWORKOUT WHERE WOINSTANCEID = ?"; if(sqlite3_prepare_v2(database, sql, -1, &statement, NULL) != SQLITE_OK) NSAssert1(0, @"Error while creating delete statement. '%s'", sqlite3_errmsg(database)); } //When binding parameters, index starts from 1 and not zero. sqlite3_bind_int(statement, 1, woID); if (SQLITE_DONE != sqlite3_step(statement)) NSAssert1(0, @"Error while deleting. '%s'", sqlite3_errmsg(database)); sqlite3_finalize(statement); } if(database) sqlite3_close(database); }

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  • UserControl/TreeView Problem....Not getting result during runtime..

    - by Samiul
    Hi all, My problem is, I'm using a TreeView in a UserControl. While debugging, I can see the results are adding in the TreeView but it's not happening when I'm using that UserControl onto my MainForm. The UserControl containing the TreeView remains blank during runtime of the main application. I've also referenced the UserControl project with my Main project. Here I'm giving my code for helping me out. Thanks in advance. Code: In the UserControl class: public override void Refresh() { PopulateTreeView(); } private void PopulateTreeView() { TreeNodeCollection treeNodeCollection; treeNodeCollection = CreateParentNode("My Information"); CreateChildNode(treeNodeCollection, "Name"); CreateChildNode(treeNodeCollection, "Address"); this.Update(); myTreeView.ExpandAll(); } private TreeNodeCollection CreateParentNode(string parentNode) { TreeNode treeNode = new TreeNode(parentNode); myTreeView.Nodes.Add(treeNode); return treeNode.Nodes; } private void CreateChildNode(TreeNodeCollection nodeCollection, string itemName) { TreeNode treeNode = new TreeNode(itemName); nodeCollection.Add(treeNode); } In my MainForm: private void button1_Click(object sender, EventArgs e) { UserControl userControl = new UserControl(); userControl.Refresh(); }

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  • Apache redirection problem!!!!

    - by vikas
    Hi guys, I am setting up a pre-built website built in php. The site was actually hosted on the linux server. Now I am trying to set it up on a Window machine with WAMP server. In this website almost every page request passes through a particular file called redirect(which is basically a php file without extension). Now the problem is that when I inspected the configuration(httpd.conf, apache.conf,.htaccess, vhost.conf etc) of the apache server on the linux machine, I nowhere found the redirect rules for doing so. Neither mod_rewrite nor mod_alias rules for this redirection were found there. But is still redirects the request properly. I also noticed that Zend Framework library is there in the exact same directory where the redirect file is. This library is included in the include_path in php.ini. However, the web site is still not developed using Zend MVC and I have seen NO proof of ZEND being used there. So I am really confused how this redirection is working there? I am unable to set up this on window machine without rewrite rules of mod_rewrite or mod_alias. Do you guys know any alternative of both the said modules for redirection? I know the site is really weird, but i have to set it up. :) Thanks in advance for your help.

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  • regexp in java problem

    - by Staszek28
    Hello! I found some problem while testing my NLP system. I have a java regex "(.\.\s)*Dendryt.*" and for string "v Table of Contents List of Tables . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . " it just dont stop computing. Its clear that this regex complexity is very high, I will try to refactor it. Have you some suggestions for me for a future regex development ??? Thanks.

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  • Authentication Problem in Silverlight - Cannot connect to SQL Server

    - by Johann
    Hi All, At the moment, when I try to register a user using the default Business Template in Silverlight, I am getting an error. Basically I am following a tutorial found on Channel 9 on how to build a business app with Silverlight. "An error has occurred while establishing a connection to the server. (provider: Named Pipes Provider, error: 40 – Could not open a connection to SQL Server) (Microsoft SQL Server, Error: 5) An error has occurred while establishing a connection to the server. When connecting to SQL Server 2005, this failure may be caused by the fact that under the default settings SQL Server does not allow remote connections. (provider: Named Pipes Provider, error: 40 – Could not open a connection to SQL Server) (Microsoft SQL Server, Error: 1326)". I found a blog where it identifies the problem, and followed every step, however I am still getting the same problems. Here is my connection string:- <add name="SIEventManagerEntities" connectionString="metadata=res://*/EventManagerDBModel.csdl|res://*/EventManagerDBModel.ssdl|res://*/EventManagerDBModel.msl;provider=System.Data.SqlClient;provider connection string=&quot;Data Source=MONFU-PC;Initial Catalog=SIEventManager;Integrated Security=SSPI;MultipleActiveResultSets=True&quot;" providerName="System.Data.EntityClient" /> Any help would really be very much appreciated! Thanks

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  • Problem in getting response from server in jquery

    - by Alvin
    Hello, I'm using $.ajax(options) method to pass the request to server based on username and password, but whenever I try to print the response by XMLHttpRequest object when response gets successful, I'm getting an empty value. $(document).ready(function(){ $("#form").submit(function(){ $.ajax({url:"Chat.jsp",type:"POST",data:$("#form").serialize(),success:function(request) { alert(request.responseText); //This is displaying nothing },error:function(){document.write("YOU can't");}}); }); }); This is what I'm doing in my servlets code after executing query: try { String user = request.getParameter("j_username"); String password = request.getParameter("j_password"); if(user != null && password != null) { String query = "Select * from users where user_name="+"\'"+user+"\'"+"&& user_pass="+"\""+password+"\""; DBCheck db= new DBCheck(); boolean b = db.doExecuteQuery(con.createStatement(),query); response.setHeader("Cache-Control", "no-cache"); if(b) { response.getWriter().println("Username already exits"); } else { response.getWriter().println("Username doesn't exit"); } } } catch(SQLException ex) { ex.printStackTrace(); } } May I know the problem, and how can I fix it?

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  • Problem with 2 levels of inheritance in hibernate mapping

    - by Seth
    Here's my class structure: class A class B extends A class C extends A class D extends C class E extends C And here are my mappings (class bodies omitted for brevity): Class A: @Entity @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @MappedSuperclass @DiscriminatorColumn( name="className", discriminatorType=DiscriminatorType.STRING ) @ForceDiscriminator public abstract class A Class B: @Entity @DiscriminatorValue("B") public class B extends A Class C: @Entity @DiscriminatorValue("C") @MappedSuperclass @DiscriminatorColumn( name="cType", discriminatorType=DiscriminatorType.STRING ) @ForceDiscriminator public abstract class C extends A Class D: @Entity @DiscriminatorValue("D") public class D extends C Class E: @Entity @DiscriminatorValue("E") public class E extends C I've got a class F that contains a set of A: @Entity public class F { ... @OneToMany(fetch=FetchType.LAZY, cascade=CascadeType.ALL) @JoinTable( name="F_A", joinColumns = @JoinColumn(name="A_ID"), inverseJoinColumns = @JoinColumn(name="F_ID") ) private Set<A> aSet = new HashSet<A>(); ... The problem is that whenever I add a new E instance to aSet and then call session.saveOrUpdate(fInstance), hibernate saves with "A" as the discrimiator string. When I try to access the aSet in the F instance, I get the following exception (full stacktrace ommitted for brevity): org.hibernate.InstantiationException: Cannot instantiate abstract class or interface: path.to.class.A Am I mapping the classes incorrectly? How am I supposed to map multiple levels of inheritance? Thanks for the help!

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  • Problem with SQL Server "EXECUTE AS"

    - by Vilx-
    I've got the following setup: There is a SQL Server DB with several tables that have triggers set on them (that collect history data). These triggers are CLR stored procedures with EXECUTE AS 'HistoryUser'. The HistoryUser user is a simple user in the database without a login. It has enough permissions to read from all tables and write to the history table. When I backup the DB and then restore it to another machine (Virtual Machine in this case, but it does not matter), the triggers don't work anymore. In fact, no impersonation for the user works anymore. Even a simple statement such as this exec ('select 3') as user='HistoryUser' produces an error: Cannot execute as the database principal because the principal "HistoryUser" does not exist, this type of principal cannot be impersonated, or you do not have permission. I read in MSDN that this can occur if the DB owner is a domain user, but it isn't. And even if I change it to anything else (their recommended solution) this problem remains. If I create another user without login, I can use it for impersonation just fine. That is, this works just fine: create user TestUser without login go exec ('select 3') as user='TestUser' I do not want to recreate all those triggers, so is there any way how I can make the existing HistoryUser work? Bump: Sorry, but this is kinda urgent...

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