Search Results

Search found 6743 results on 270 pages for 'regular joe'.

Page 29/270 | < Previous Page | 25 26 27 28 29 30 31 32 33 34 35 36  | Next Page >

  • Regular expression literal

    - by Marcus
    As I'm RegEx dyslexic.. what RegEx can you use to find each of the following strings - with the exception of "LoginException"? NullPointerException LoginException BooException Abc123Exception

    Read the article

  • Regular expression does not find the first occurance

    - by scharan
    I have the following input to a perl script and I wish to get the first occurrence of NAME="..." strings in each of the ... structures. The entire file is read into a single string and the reg exp acts on that input. However, the regex always returns the LAST occurrence of NAME="..." strings. Can anyone explain what is going on and how this can be fixed? Input file: ADSDF <TABLE> NAME="ORDERSAA" line1 line2 NAME="ORDERSA" line3 NAME="ORDERSAB" </TABLE> <TABLE> line1 line2 NAME="ORDERSB" line3 </TABLE> <TABLE> line1 line2 NAME="ORDERSC" line3 </TABLE> <TABLE> line1 line2 NAME="ORDERSD" line3 line3 line3 </TABLE> <TABLE> line1 line2 NAME="QUOTES2" line3 NAME="QUOTES3" NAME="QUOTES4" line3 NAME="QUOTES5" line3 </TABLE> <TABLE> line1 line2 NAME="QUOTES6" NAME="QUOTES7" NAME="QUOTES8" NAME="QUOTES9" line3 line3 </TABLE> <TABLE> NAME="MyName IsKhan" </TABLE> Perl Code starts here: use warnings; use strict; my $nameRegExp = '(<table>((NAME="(.+)")|(.*|\n))*</table>)'; sub extractNames($$){ my ($ifh, $ofh) = @_; my $fullFile; read ($ifh, $fullFile, 1024);#Hardcoded to read just 1024 bytes. while( $fullFile =~ m#$nameRegExp#gi){ print "found: ".$4."\n"; } } sub main(){ if( ($#ARGV + 1 )!= 1){ die("Usage: extractNames infile\n"); } my $infileName = $ARGV[0]; my $outfileName = $ARGV[1]; open my $inFile, "<$infileName" or die("Could not open log file $infileName"); my $outFile; #open my $outFile, ">$outfileName" or die("Could not open log file $outfileName"); extractNames( $inFile, $outFile ); close( $inFile ); #close( $outFile ); } #call main();

    Read the article

  • Using \b in C# regular expressions doesn't work?

    - by Nikhil
    I am wondering why the following regex does not match. string query = "\"1 2\" 3"; string pattern = string.Format(@"\b{0}\b", Regex.Escape("\"1 2\"")); string repl = Regex.Replace(query, pattern, "", RegexOptions.CultureInvariant); Note that if I remove the word boundary characters (\b) from pattern, it matches fine. Is there something about '\b' that might be tripping this up?

    Read the article

  • How to access a plugin model from a regular controller in PHP Cake 1.1

    - by Duncan
    Hopefully a simple question: I've a plugin which uses a set of tables (kb_items, kb_item_tags, etc). and I'd like to be able to access these models from another controller (say, my Pages controller), thus: class PagesController extends AppController{ function knowledgebase(){ $items = $this->KbItem->findAll(...); } } I am admittedly breaking the rules a little (by not placing this controller inside the knowledge base plugin), but this in this case its a custom page that doesn't need to be part of the knowledge base plugin code base. Please let me know if you need more details. Thanks in advance for any help!

    Read the article

  • Regular Expression: back references

    - by sixtyfootersdude
    sed 's/^\(\h*\)\(.*\)$/\1<!-- \2 -->/' web.xml I think that this should take this xml: <a> <d> bla </d> </a> And turn it into: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> --> But what is doing is this: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> -->

    Read the article

  • Pass a captured named regular expression to URL dictionary in generic view

    - by Trent Jurewicz
    I am working with a generic view in Django. I want to capture a named group parameter in the URL and pass the value to the URL pattern dictionary. For example, in the URLConf below, I want to capture the parent_slug value in the URL and pass it to the queryset dictionary value like so: urlpatterns = patterns('django.views.generic.list_detail', (r'^(?P<parent_slugs>[-\w])$', 'object_list', {'queryset':Promotion.objects.filter(category=parent_slug)}, 'promo_promotion_list'), ) Is this possible to do in one URLConf entry, or would it be wiser if I create a custom view to capture the value and pass the queryset directly to the generic view from my overridden view?

    Read the article

  • Issue with my regular expression?

    - by Rubans
    I'm trying to locate the number matches in a relative path for directory up references("..\"). So I have the following pattern : "(..\)" which works as expected for the path "....\a\b" where it will give me 2 successfull groups ("..\") but when I try the path "..\a\b" it will also return 2 when it should be 1. I tried this in a reg ex tool such Expresso and it seems to work as expected in there but not in in .net, any ideas?

    Read the article

  • Finding tags in query string with regular expression

    - by fatmatto
    Hi everybody! I have to set some routing rules in my php application, and they should be in the form /%var/something/else/%another_var In other words i beed a regex that returns me every URI piece marked by the % character, String marked by % represent var names so they can be almost every string. another example: from /%lang/module/controller/action/%var_1 i want the regex to extract lang and var_1 i tried something like /.*%(.*)[\/$]/ but it doesn't work.....

    Read the article

  • regular expression code

    - by Gaia Andreoletti
    Deal all, I need to find match between two tab delimited files files like this: File 1: ID1 1 65383896 65383896 G C PCNXL3 ID1 2 56788990 55678900 T A ACT1 ID1 1 56788990 55678900 T A PRO55 File 2 ID2 34 65383896 65383896 G C MET5 ID2 2 56788990 55678900 T A ACT1 ID2 2 56788990 55678900 T A HLA what I would like to do is to retrive the matching line between the two file. What I would like to match is everyting after the gene ID So far I have written this code but unfortunately perl keeps giving me the error: use of "Use of uninitialized value in pattern match (m//)" Could you please help me figure out where i am doing it wrong? Thank you in advance! use strict; open (INA, $ARGV[0]) || die "cannot to open gene file"; open (INB, $ARGV[1]) || die "cannot to open coding_annotated.var files"; my @sample1 = <INA>; my @sample2 = <INB>; foreach my $line (@sample1) { my @tab = split (/\t/, $line); my $chr = $tab[1]; my $start = $tab[2]; my $end = $tab[3]; my $ref = $tab[4]; my $alt = $tab[5]; my $name = $tab[6]; foreach my $item (@sample2){ my @fields = split (/\t/,$item); if ($fields[1]=~ m/$chr(.*)/ && $fields[2]=~ m/$start(.*)/ && $fields[4]=~ m/$ref(.*)/ && $fields[5]=~ m/$alt(.*)/&& $fields[6]=~ m/$name(.*)/){ print $line,"\n",$item; } } }

    Read the article

  • Extract a regular expression match in R version 2.10

    - by tovare
    Hi, I'm trying to extract a number from a string. And do something like this [0-9]+ on this string "aaaa12xxxx" and get "12". I thought it would be something like: > grep("[0-9]+","aaa12xxx", value=TRUE) [1] "aaa12xxx" And then I figured... > sub("[0-9]+", "\\1", "aaa12xxxx") [1] "aaa12xxx" But I got some form of response doing: > sub("[0-9]+", "ARGH!", "aaa12xxxx") [1] "aaaARGH!xxx" There's a small detail I'm missing Please advice :-) I'm using R version 2.10.1 (2009-12-14) Thanks ! Comments on the solution The best solution is to ignore the standard functions and install Hadley Wickham's stringr package to get something that actually makes sense. Kudos to Marek for figuring out how the standard library worked.

    Read the article

  • regular expression for emails NOT ending with replace script

    - by corroded
    I'm currently modifying my regex for this: http://stackoverflow.com/questions/2782031/extracting-email-addresses-in-an-html-block-in-ruby-rails basically, im making another obfuscator that uses ROT13 by parsing a block of text for all links that contain a mailto referrer(using hpricot). One use case this doesn't catch is that if the user just typed in an email address(without turning it into a link via tinymce) So here's the basic flow of my method: 1. parse a block of text for all tags with href="mailto:..." 2. replace each tag with a javascript function that changes this into ROT13 (using this script: http://unixmonkey.net/?p=20) 3. once all links are obfuscated, pass the resulting block of text into another function that parses for all emails(this one has an email regex that reverses the email address and then adds a span to that email - to reverse it back) step 3 is supposed to clean the block of text for remaining emails that AREN'T in a href tags(meaning it wasn't parsed by hpricot). Problem with this is that the emails that were converted to ROT13 are still found by my regex. What i want to catch are just emails that WEREN'T CONVERTED to ROT13. How do i do this? well all emails the WERE CONVERTED have a trailing "'.replace" in them. meaning, i need to get all emails WITHOUT that string. so far i have this regex: /\b([A-Z0-9._%+-]+@[A-Z0-9.-]+.[A-Z]{2,4}('.replace))\b/i but this gets all the emails with the trailing '.replace i want to get the opposite and I'm currently stumped with this. any help from regex gurus out there? MORE INFO: Here's the regex + the block of text im parsing: http://www.rubular.com/r/NqXIHrNqjI as you can see, the first two 'email addresses' are already obfuscated using ROT13. I need a regex that gets the emails [email protected] and [email protected]

    Read the article

  • Find last match with python regular expression

    - by SDD
    I wanto to match the last occurence of a simple pattern in a string, e.g. list = re.findall(r"\w+ AAAA \w+", "foo bar AAAA foo2 AAAA bar2) print "last match: ", list[len(list)-1] however, if the string is very long, a huge list of matches is generated. Is there a more direct way to match the second occurence of "AAAA" or should I use this workaround?

    Read the article

  • Flex 3 Regular Expression Problem

    - by Tommy
    I've written a url validator for a project I am working on. For my requirements it works great, except when the last part for the url goes longer than 22 characters it breaks. My expression: /((https?):\/\/)([^\s.]+.)+([^\s.]+)(:\d+\/\S+)/i It expects input that looks like "http(s)://hostname:port/location". When I give it the input: https://demo10:443/111112222233333444445 it works, but if I pass the input https://demo10:443/1111122222333334444455 it breaks. You can test it out easily at http://ryanswanson.com/regexp/#start. Oddly, I can't reproduce the problem with just the relevant (I would think) part /(:\d+\/\S+)/i. I can have as many characters after the required / and it works great. Any ideas or known bugs?

    Read the article

< Previous Page | 25 26 27 28 29 30 31 32 33 34 35 36  | Next Page >