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  • regular expression for letters, numbers and - _ .

    - by Jorre
    I'm having trouble checking in PHP if a value is is any of the following combinations letters (upper or lowercase) numbers (0-9) underscore (_) dash (-) point (.) no spaces! or other characters a few examples: OK: "screen123.css" OK: "screen-new-file.css" OK: "screen_new.js" NOT OK: "screen new file.css" I guess I need a regex for this, since I need to throw an error when a give string has other characters in it than the ones mentioned above.

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  • How to implement a timer for regular events?

    - by Torben Jonas
    I would like to implement some timers into my application. My goal is to provide an easy way to execute some function every x seconds/minutes so I thought about implementing a 1 sec, 5 sec and 15 seconds timer. The first thing i would like to update every 1 second is the built in clock (don't know if there is any other solution in c#, used this method in c++) Another use would be e.g. a sync function etc. which shall be executed every xx seconds. My question is if there are any useful tutorials on this topic? It is the first time that I would like to implement such an timer system into one of my applications and I do not know if there are any things I have to keep in mind. Thank you in advance for any answer :)

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  • Using regular expression to trim html

    - by Tim
    Been trying to solve this for a while now. I need a regex to strip the newlines, tabs and spaces between the html tags demonstrated in the example below: Source: <html> <head> <title> Some title </title> </head> </html> Wanted result: <html><head><title>Some title</title></head></html> The trimming of the whitespaces before the "Some title" is optional. I'd be grateful for any help

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  • List files with two dots in their names using java regular expressions

    - by Nivas
    I was trying to match files in a directory that had two dots in their name, something like theme.default.properties I thought the pattern .\\..\\.. should be the required pattern [. matches any character and \. matches a dot] but it matches both oneTwo.txt and theme.default.properties I tried the following: [resources/themes has two files oneTwo.txt and theme.default.properties] 1. public static void loadThemes() { File themeDirectory = new File("resources/themes"); if(themeDirectory.exists()) { File[] themeFiles = themeDirectory.listFiles(); for(File themeFile : themeFiles) { if(themeFile.getName().matches(".\\..\\..")); { System.out.println(themeFile.getName()); } } } } This prints nothing and the following File[] themeFiles = themeDirectory.listFiles(new FilenameFilter() { public boolean accept(File dir, String name) { return name.matches(".\\..\\.."); } }); for (File file : themeFiles) { System.out.println(file.getName()); } prints both oneTwo.txt theme.default.properties I am unable to find why these two give different results and which pattern I should be using to match two dots... Can someone help?

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  • Scala: Matching optional Regular Expression groups

    - by Brian Heylin
    I'm trying to match on an option group in Scala 2.8 (beta 1) with the following code: import scala.xml._ val StatementPattern = """([\w\.]+)\s*:\s*([+-])?(\d+)""".r def buildProperty(input: String): Node = input match { case StatementPattern(name, value) => <propertyWithoutSign /> case StatementPattern(name, sign, value) => <propertyWithSign /> } val withSign = "property.name: +10" val withoutSign = "property.name: 10" buildProperty(withSign) // <propertyWithSign></propertyWithSign> buildProperty(withoutSign) // <propertyWithSign></propertyWithSign> But this is not working. What is the correct way to match optional regex groups?

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  • Regular expression to Match addresses

    - by Burfi
    I have below set of strings to be searched : 1Dept Neurosci, The Univ. of New Mexico, ALBUQUERQUE, NM; 2Mol. and Human Genet., Baylor Col. of Med., Houston,, TX; 3Psychiatry, Univ. of Texas Southwestern Med. Ctr., Dallas, TX; 4Clin. Genet., Erasmus Univ. Med. Ctr., Rotterdam, Netherlands; 5Human Genet., Emory Univ., Atlanta, GA Above is a set of addresses , which starts with a digit (used to link it to the person).Need to search all the address as : 1Dept Neurosci, The Univ. of New Mexico, ALBUQUERQUE, NM 2Mol. and Human Genet., Baylor Col. of Med., Houston,, TX 3Psychiatry, Univ. of Texas Southwestern Med. Ctr., Dallas, TX 4Clin. Genet., ErasmusUniv. Med. Ctr., Rotterdam, Netherlands 5Human Genet., Emory Univ.Atlanta, GA I have written the below Regex : \d\w+,* It only matches a digit followed by a word . How can I modify it .Please suggest is there any better way.

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  • How to process this string via regular expression

    - by iiduce
    my string style like this: expression1/field1+expression2*expression3+expression4/field2*expression5*expression6/field3 a real style mybe like this: computer/(100)+web*mail+explorer/(200)*bbs*solution/(300) "+" and "*" represent operator "computer","web"...represent expression (100),(200) represent field num . field num may not exist. I want process the string to this: /(100)+web*+explorer/(200)bbs/(300) rules like this: if expression length is more than 3 and its field is not (200), then add brackets to it.

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  • regular expression and escaping

    - by pstanton
    Sorry if this has been asked, my search brought up many off topic posts. I'm trying to convert wildcards from a user defined search string (wildcard is "*") to postgresql like wildcard "%". I'd like to handle escaping so that "%" => "\%" and "\*" => "*" I know i could replace \* with something else prior to replacing * and then swap it back, but i'd prefer not to and instead only convert * using a pattern that selects it when not proceeded by \. String convertWildcard(String like) { like = like.replaceAll("%", "\\%"); like = like.replaceAll("\\*", "%"); return like; } Assert.assertEquals("%", convertWildcard("*")); Assert.assertEquals("\%", convertWildcard("%")); Assert.assertEquals("*", convertWildcard("\*")); // FAIL Assert.assertEquals("a%b", convertWildcard("a*b")); Assert.assertEquals("a\%b", convertWildcard("a%b")); Assert.assertEquals("a*b", convertWildcard("a\*b")); // FAIL ideas welcome.

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  • Regular expressions in c++ STL

    - by Radek Šimko
    Is there any native library in STL which is tested and works without any extra compiler options? I tried to use <regex>, but the compiler outputs this: In file included from /usr/include/c++/4.3/regex:40, from main.cpp:5: /usr/include/c++/4.3/c++0x_warning.h:36:2: error: #error This file requires compiler and library support for the upcoming ISO C++ standard, C++0x. This support is currently experimental, and must be enabled with the -std=c++0x or -std=gnu++0x compiler options.

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  • Problem with regular expression for some special parttern.

    - by SpawnCxy
    Hi all, I got a problem when I tried to find some characters with following code: preg_match_all('/[\w\uFF10-\uFF19\uFF21-\uFF3A\uFF41-\uFF5A]/',$str,$match); //line 5 print_r($match); And I got error as below: Warning: preg_match_all() [function.preg-match-all]: Compilation failed: PCRE does not support \L, \l, \N, \U, or \u at offset 4 in E:\mycake\app\webroot\re.php on line 5 I'm not so familiar with reg expression and have no idea about this error.How can I fix this?Thanks.

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  • string substitution regular expression not working in tcl

    - by Puneet Mittal
    i am trying to replace all the special characters including white space, hyphen, etc, to underscore, from a string variable in tcl. I wrote the code below but it doesn't seem to be working. set varname $origVar puts "Variable Name :>> $varname" if {$varname != ""} { regsub -all {[\s-\]\[$^?+*()|\\%&#]} $varname "_" $newVar } puts "New Variable :>> $newVar" one issue is that, instead of replacing the string in $varname, it is replacing the data inside $origVar. No idea why, and also i read the example code (for proper syntax) in my tcl book and according to that it should be something like this regsub -all {[\s-][$^?+*()|\\%&#]} $varname "_" newVar so i used the same syntax but it didn't work and gave the same result as modifying the $origVar instead of required $varname value.

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  • Regular expression and newline

    - by Ockonal
    Hello guys, I have such text: <[email protected]> If you do so, please include this problem report. <[email protected]> You can delete your own text from the attached returned message. The mail system <[email protected]>: connect to *.net[82.*.86.*]: Connection timed out I have to parse email from it. Could you help me with this job? upd There could be another email addresses in <%here%. There should be connection between 'The mail system' text. I need in email which goes after that text.

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  • [Python] OR in regular expression?

    - by www.yegorov-p.ru
    Hello. I have text file with several thousands lines. I want to parse this file into database and decided to write a regexp. Here's part of file: blablabla checked=12 unchecked=1 blablabla unchecked=13 blablabla checked=14 As a result, I would like to get something like (12,1) (0,13) (14,0) Is it possible?

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  • perl regular expressions substitution/replacement using variables with special characters

    - by user961627
    Okay I've checked previous similar questions and I've been juggling with different variations of quotemeta but something's still not right. I have a line with a word ID and two words - the first is the wrong word, the second is right. And I'm using a regex to replace the wrong word with the right one. $line = "ANN20021015_0104_XML_16_21 A$xAS A$xASA"; @splits = split("\t",$line); $wrong_word = quotemeta $splits[1]; $right_word = quotemeta $splits[2]; print $right_word."\n"; print $wrong_word."\n"; $line =~ s/$wrong_word\t/$right_word\t/g; print $line; What's wrong with what I'm doing? Edit The problem is that I'm unable to retain the complete words - they get chopped off at the special characters. This code works perfectly fine for words without special characters. The output I need for the above example is: ANN20021015_0104_XML_16_21 A$xASA A$xASA But what I get is ANN20021015_0104_XML_16_21 A A Because of the $ character.

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  • Using regular expressions

    - by Tom
    What is wrong with this regexp? I need it to make $name to be letter-number only. Now it doens't seem to work at all. if (!preg_match("/^[A-Za-z0-9]$/",$name)) { $e[]="name must contain only letters or numbers"; }

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  • Regular Expression to Match YouTube Watch URL

    - by dododedodonl
    Hi, I've got this regex (I'm not good at it) /http://www.youtube.com/watch?v=[a-zA-Z0-9_]/i it has to match any youtube watch url (because youtube always redirects to that domain)... It should match http://www.youtube.com/watch?v=iMXCqgWjpL8 but it doesn't. Can someone help me? Regard, dodo

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  • Regular Expression Sanitize (PHP)

    - by atif089
    Hello, I would like to sanitize a string in to a URL so this is what I basically need. Everything must be removed except alphanumeric characters and spaces and dashed. Spaces should be converter into dashes. Eg. This, is the URL! must return this-is-the-url Thanks

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  • Regular Expression .net flavor

    - by user1440109
    Dont ask how this works but currently it does ("^\|(.?)\|*$")....kinda. This removes all extra pipes...part one....I have searched all over no anwser yet. I am using VB2011 beta...asp web form......vb coding though! I want to capture special character pipe (|) which is used to seperate words...i.e. car|truck|van|cycle problem is users lead with, trail with, use multiple, and use spaces before and after...i.e. |||car||truck | van || cycle. another example: george bush|micheal jordon|bill gates|steve jobs <-- this would be correct but when I do remove space it takes correct space out. so I want to get rid of whitespace leading, trailing, any space before | and space after | and only allow one pipe (|)....in between alphanumeric of course.

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  • Regular Expression Help

    - by WizardsSleeve
    Hi There, Does anyone have a regurlar expression available which only accepts dates in the format dd/mm/yy but also has strict checking to make sure that the date is valid, including leap year support? I am coding in vb.net and am struggling to work this one out. Many Thanks

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  • Regular Expressions - Match all alphanumeric characters except individual numbers

    - by imaginonic
    I would like to create a RegEx to match only english alphanumeric characters but ignore (or discard) isolated numbers in Ruby (and if possible in JS too). Examples: 1) I would like the following to be matched: 4chan 9gag test91323432 asf5asdfaf35edfdfad afafaffe But not: 92342424 343424 34432 and so on.. The above is exactly what I would want. 2) However, I would be really thankful if someone could also include French letters like: é ë ê (These are just few examples of many) 1) is my priority, it's totally okay if 2) is impossible or difficult to implement. Sorry, my regex skills aren't that great (hence this question!) Thank you.

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