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  • IPHONE: For UITableView -- changing to next view takes time, how to show UIActivityIndicatorView?

    - by westla7
    So, my UITableViewCell has UITableViewCellAccessoryDetailDisclosureButton, and when somebody clicks on it it make long time just to show next view screen... so I want to show some "rolling wait image" (UIActivityIndicatorView ?) say next to UITableViewCellAccessoryDetailDisclosureButton in this cell, but how do I do it right? How to use UITableViewCellAccessoryDetailDisclosureButton properly? Thank you.

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  • How can I send a json string to view as a json object?

    - by yapiskan
    I have a json string in an action of MVC controller. I want to send it to view as a JSON object. How can I solve this? public JsonResult Json() { ... some code here ... string jsonString = "{\"Success\":true, \"Msg\":null}"; return new JsonResult() { Data = jsonString, JsonRequestBehavior = JsonRequestBehavior.AllowGet }; }

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  • TabBar / "More View Controller" - Possible to have icons in colors other than black?

    - by Malakim
    Hi, Is it possible to have the icons in a TabBar and / or the "More navigation controller" be in colors other than grey and black? I tried changing the color of the icon I set for the view controller using UITabBarItem's - (id)initWithTitle:(NSString *)title image:(UIImage *)image tag:(NSInteger)tag method. My client thinks the interface is too dark and want's to brighten it up with some colorful icons... Thanks!

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  • How do I create a stored procedure that calls sp_refreshview for each view in the database?

    - by Allrameest
    Today I run this select 'exec sp_refreshview N''['+table_schema+'].['+table_name+']''' from information_schema.tables where table_type = 'view' This generates a lot of: exec sp_refreshview N'[SCHEMA].[TABLE]'. I then copy the result to the query editor window and run all those execs. How do I do this all at once? I would like to have a stored procedure called something like dev.RefreshAllViews which I can execute to do this...

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  • How do I make my custom Swing component visible?

    - by Alex
    I have no idea why it won't show. First I create an instance of the component and then add it to a certain element in a two-dimensional JPanel array. Then I loop through that array and add each JPanel to another JPanel container which is to hold all the JPanels. I then add that final container to my JFrame window and set visibility to true, it should be visible? public class View extends JFrame { Board gameBoard; JFrame gameWindow = new JFrame("Chess"); JPanel gamePanel = new JPanel(); JPanel[][] squarePanel = new JPanel[8][8]; JMenuBar gameMenu = new JMenuBar(); JButton restartGame = new JButton("Restart"); JButton pauseGame = new JButton("Pause"); JButton log = new JButton("Log"); View(Board board){ gameWindow.setDefaultCloseOperation(EXIT_ON_CLOSE); gameWindow.setSize(400, 420); gameWindow.getContentPane().add(gamePanel, BorderLayout.CENTER); gameWindow.getContentPane().add(gameMenu, BorderLayout.NORTH); gameMenu.add(restartGame); gameMenu.add(pauseGame); gameMenu.add(log); gameBoard = board; drawBoard(gameBoard); gameWindow.setResizable(false); gameWindow.setVisible(true); } public void drawBoard(Board board){ for(int row = 0; row < 8; row++){ for(int col = 0; col < 8; col++){ Box box = new Box(board.getSquare(col, row).getColour(), col, row); squarePanel[col][row] = new JPanel(); squarePanel[col][row].add(box); } } for(JPanel[] col : squarePanel){ for(JPanel square : col){ gamePanel.add(square); } } } } @SuppressWarnings("serial") class Box extends JComponent{ Color boxColour; int col, row; public Box(Color boxColour, int col, int row){ this.boxColour = boxColour; this.col = col; this.row = row; repaint(); } protected void paintComponent(Graphics drawBox){ drawBox.setColor(boxColour); drawBox.drawRect(50*col, 50*row, 50, 50); drawBox.fillRect(50*col, 50*row, 50, 50); } } A final question as well. Notice how each Box component has a position, what happens to the position when I add the component to a JPanel and add the JPanel to my JFrame? Does it still have the same position in relation to the other Box components?

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  • How do you programmatically set a Style on a View?

    - by Greg
    I would like to do something like this: <Button android:id="@+id/button" android:layout_width="wrap_content" android:layout_height="wrap_cotent" style="@style/SubmitButtonType" /> But in code The xml approach works fine provided that SubmitButtonType is defined. Now what I assume happens is that the appt parser runs through this xml, generates an AttributeSet. That AttributeSet when passed to context/theme#obtainStyledAttributes() will have the style ref mask anything that is not written inline in this tag. Great that's fine! Now how do we do this programmatically. Button, as well as other View types, has a constructor that has the form: <Widget>(Context context, AttributeSet set, int defStyle). So I thought this would work. Button button = new Button(context, null, R.style.SubmitButtonType); However, I am finding that defStyle is badly documented as it really should be written to be a resourceId to an attribute (from R.attrs) that will be passed to obtainStyledAttributes() as the attribute resource, and not the style resource. After looking at the code, all the view implementations seem to pass 0 as the styleRef. I don't see the harm in having it passed as both the attr and the style resource (more flexible and negligible overhead) However I might be approaching this all wrong. How do you do this in code then other than by setting each individual element of the style to the specific widget you want to style (only possible by looking a the code to see what param maps to which method or set of methods). The only way I have found to do this is: <declare-styleable> <attr name="totallyAdhoc_attribute_just_for_this_case" format="reference"> </declare-styleable> <style name="MyAlreadyExistantTheme" > ... ... <item name="totallyAdhoc_attribute_just_for_this_case">@style/SubmitButtonType</item> </style> And instead of passing R.style.SubmitButtonType as defStyle, I pass the new R.attr.totallyAdhoc_attribute_just_for_this_case. Button button = new Button(context, null, R.attr.totallyAdhoc_attribute_just_for_this_case); This works but sounds way too complicated.

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  • How to call a view on click of each UITableViewCell programatically?

    - by Cathy
    Hi, I have created a UITableViewcontroller and a UINavigationController in a TableController.m with UITableviewCell set to say @"CellOne" @"CellTwo". Now i also created two other files `ImageView1.m` ImageView2.m where if i click on CellOne i should be able to get the view placed on ImageView1.m, same applied to the ImageView2.m.How should i achieve this programatically without using nib file?

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  • How to refresh the properties view in Eclipse RCP?

    - by geejay
    I am using the properties view in RCP, i.e org.eclipse.ui.views.properties.PropertySheet. I want to be able to refresh the content of these properties programmatically. It seems RCP is geared towards the use case where this changes only when a selection changes. Is there any way I can fire a dummy event to get this to refresh (without having ugly UI artifacts such as visibly switching between parts) ?

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