Search Results

Search found 31707 results on 1269 pages for 'php jedi'.

Page 292/1269 | < Previous Page | 288 289 290 291 292 293 294 295 296 297 298 299  | Next Page >

  • PHP, MySQL prepared statements - can you use results of execute more than once by calling data_seek(

    - by Carvell Fenton
    Hello, I have a case where I want to use the results of a prepared statement more than once in a nested loop. The outer loop processes the results of another query, and the inner loop is the results of the prepared statement query. So the code would be something like this (just "pseudoish" to demonstrate the concept): // not showing the outer query, it is just a basic SELECT, not prepared statement // we'll call it $outer_query $obj_array = array(); // going to save objects in this $ids = array(18,19,20); // just example id numbers $query = "SELECT field1, field2 FROM table1 WHERE id=?"; $stmt = $db->prepare($query); foreach ($ids as $id) { $stmt->bind_param("i", $id); $stmt->execute(); $stmt->bind_result($var1, $var2); $stmt->store_result(); // I think I need this for data_seek while ($q1 = $outer_query->fetch_object()) { while ($stmt->fetch()) { if ($q1->field1 == $var1) { // looking for a match $obj = new stdClass(); $obj->var1 = $var1; $obj->var2 = $var2; $obj_array[] = $obj; $stmt->data_seek(0); // reset for outer loop break; // found match, so leave inner } } } } The problem I seem to be experiencing is that the values are not getting bound in the variables as I would expect after the first time I use fetch in the inner loop. Specifically, in one example I ran with 3 ids for the foreach, the first id was processed correctly, the second was processed incorrectly (matches were not found in the inner loop even though they existed), and then the third was processed correctly. Is there something wrong with the prepared statment function calls in the sequence I am doing above, or is this an invalid way to use the results of the prepared statement? Thanks.

    Read the article

  • Math - Adding with PHP

    - by Wayne
    Basically I can't get it right. I need something like this: if($p == 1) { $start = 0; $limit = 16; } The numbers must add on depending on the value of the $p, e.g. if $p is 5 then the values of $start and $limit would be: if($p == 5) { $start = 64; $limit = 80; } The math is to add 16, depending on the value of $p. Thanks.

    Read the article

  • How to code a 'Next in Results' within search results in PHP

    - by thebluefox
    Right, bit of a head scratcher, although I've got a feeling there's an obvious answer and I'm just not seeing the wood for the trees. Baiscally, using Solr as a search engine for my site, bringing back 15 results per page. When you click on a result, you get a detail page, that has a "Next in Results" link on it, which obviously forwards you on to the next result. Whats the best way of doing this? I've come up with a few solutions but they're either too inpractical or just don't work. I could store all the ids in a session array, then grab the one after the current one and put that in the link. But with possibly hundreds/thousands of results, the memory that array would need, and the performance hit of dealing with it isn't practical. I could take the same approach and put it into the db, but I'll still have to deal with a potentially huge array when I grab them out of the db. Or; I could do the search again, only returning the id's, and grab the one after the one we're currently looking at. I think this could be the best option? Although it does seem kind of messy, namely because of when I have to select the id thats on a different 'page' (ie the 16th, 31st etc result). Unless I pass through where it was in the results, and select from there, but that still doesn't seem like the right way to do it. I'm really sorry if this is just complete nonsense, any help is massively appreciated as always, Cheers guys!

    Read the article

  • Mysql results into array (PHP)

    - by cthulhu
    How can i convert mysql results (from mysql_fetch_array) into such a form? $some = array( "comments" => array( array( "text" => "hi", "id" => "1" ), array( "text" => "hi", "id" => "2" ), array( "text" => "hi", "id" => "3" ), array( "text" => "hi", "id" => "4" ) ) ); while the db looks like: comments id text 1 blabla bla 2 bla bla i've tried to fetch the values with foreach/while and insert it into two arrays but no success...

    Read the article

  • (PHP) Converting an array of arrays from one format into another

    - by Richard Carter
    Hi, I currently have an array, created from a database, an example of which looks like the following: Array( [0] => Array ( objectid => 2, name => title, value => apple ), [1] => Array ( objectid => 2, name => colour, value => red ), [2] => Array ( objectid => 3, name => title, value => pear ), [3] => Array ( objectid => 3, name => colour, value => green ) ) What I would like to do is group all the items in the array by their objectid, and convert the 'name' values into keys and 'value' values into values of an associative array....like below: Array ( [0] => Array ( objectid => 2, title => apple, colour => red ), [1] => Array ( objectid => 3, title => pear, colour => green ) ) I've tried a few things but haven't really got anywhere.. Any ideas? Thanks in advance

    Read the article

  • PHP/MYSQL Trouble Selecting by Primary Key

    - by djs22
    Hi all, So I have a primary key column called key. I'm trying to select the row with key = 1 via this code: $query ="SELECT * FROM Bowlers WHERE key = '1'"; $result = mysql_query($query) or die(mysql_error()); For some reason, I'm getting this result: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key = '1'' at line 1 The mysql statement works for using other keys, ie WHERE name = 'djs22'. Any ideas?

    Read the article

  • php curl login not work

    - by Massimo Zampieri
    Hi i have a problem with the curl. I watched an old post Remote Login not Working With Curl, but it not work. I followed baba's advice but the code enter in the if statement. Sorry for my bad english. Can anyone help me? This is the code: $url="http://hipfile.com/"; $urllog="http://hipfile.com/login.html"; $postdata = "login=bnnoor&password=########&op=login"; $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_REFERER, $urllog); curl_setopt ($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt ($ch, CURLOPT_POST, 1); $result = curl_exec ($ch); if (!$result) { $http_code = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); // make sure we closeany current curl sessions die($http_code.' Unable to connect to server. Please come back later.'); } echo $result; curl_close($ch);

    Read the article

  • PHP Populating array with $variables

    - by Tom
    Hi, I'm trying to create a basic shopping cart, having an issue with the product page allowing users to add more items to their cart then are in stock (I have code in place to prevent this on the view cart page, just not the view product page) This is what I have so far; for ($i = 0; $i < $numItem; $i++) { extract($cartContent[$i]); $subTotal += $price * $cartQuantity; $cartLimiter[$itemNo => $cartQuantity]; Using an array so the position number becomes the item number and the cart quantity becomes the assigned value, however it doesn't seem to like it and throws out on the bottom line of code: Parse error: syntax error, unexpected T_DOUBLE_ARROW, expecting ']' Thanks

    Read the article

  • [PHP] Weird problem with dynamic method invocation

    - by Rolf
    Hi everyone, this time, I'm facing a really weird problem. I've the following code: $xml = simplexml_load_file($this->interception_file); foreach($xml->children() as $class) { $path = str_replace('__CLASS_DIR__',CLASS_DIR,$class['path']); if(!is_file($path)) { throw new Exception('Bad configuration: file '.$path.' not found'); } $className = pathinfo($path,PATHINFO_FILENAME); foreach($class as $method) { $method_name = $method['name']; $obj = new $className(); var_dump(in_array($method_name,get_class_methods($className)));exit; echo $obj->$method_name();### not a method ??? } } As you can see, I get the class name and method name from an XML file. I can create an instance of the class without any problem. The var_dump at the end returns true, that means $method_name (which has 2 optional parameters) is a method of $className. BUT, and I am pretty sure the syntax is correct, when I try: $obj-$method_name() I get: Fatal error: Method name must be a string If you have any ideas, pleaaaaase tell me :) Thanks in advance, Rolf

    Read the article

  • INSERT INTO error MYSQL/PHP

    - by bat
    I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (total, addy, cc) VALUES ('798' , '123 sadf' , '12124123')' at line 1 $total = addslashes(($_SESSION['total'])); $addy = addslashes(($_POST['addy'])); $cc = addslashes(($_POST['cc'])); echo "$total"; echo "$addy"; echo "$cc"; mysql_query("INSERT INTO order (total, addy, cc) VALUES ('$total' , '$addy' , '$cc')") or die(mysql_error()); help plz =]

    Read the article

  • PHP While Loops from Arrays

    - by Michael
    I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

    Read the article

  • Modify a php limit text function adding some kind of offset to it

    - by webmasters
    Maybe you guys can help: I have a variable called $bio with bio data. $bio = "Hello, I am John, I'm 25, I like fast cars and boats. I work as a blogger and I'm way cooler then the author of the question"; I search the $bio using a set of functions to search for a certain word, lets say "author" which adds a span class around that word, and I get: $bio = "Hello, I am John, I'm 25, I like fast cars and boats. I work as a blogger and I'm way cooler then the <span class=\"highlight\">author</span> of the question"; I use a function to limit the text to 85 chars: $bio = limit_text($bio,85); The problem is when there are more then 80 chars before the word "author" in $bio. When the limit_text() is applied, I won't see the highlighted word author. What I need is for the limit_text() function to work as normal, adding all the words that contain the span class highlight at the end. Something like this: *"This is the limited text to 85 chars, but there are no words with the span class highlight so I am putting to be continued ... **author**, **author2** (and all the other words that have a span class highlight around them separate by comma "* Hope you understood what I mean, if not, please comment and I'll try to explain better. Here is my limit_text() function: function limit_text($text, $length){ // Limit Text if(strlen($text) > $length) { $stringCut = substr($text, 0, $length); $text = substr($stringCut, 0, strrpos($stringCut, ' ')); } return $text; } UPDATE: $xturnons = str_replace(",", ", ", $xturnons); $xbio = str_replace(",", ", ", $xbio); $xbio = customHighlights($xbio,$toHighlight); $xturnons = customHighlights($xturnons,$toHighlight); $xbio = limit_text($xbio,85); $xturnons = limit_text($xturnons,85); The customHighlights function which adds the span class highlighted: function addRegEx($word){ // Highlight Words return "/" . $word . '[^ ,\,,.,?,\.]*/i'; } function highlight($word){ return "<span class='highlighted'>".$word[0]."</span>"; } function customHighlights($searchString,$toHighlight){ $searchFor = array_map('addRegEx',$toHighlight); $result = preg_replace_callback($searchFor,'highlight',$searchString); return $result; }

    Read the article

  • Create Chart using PHP-MySQL

    - by Ajith
    I have a mysql table - request_events with three fields; request_eventsid,datetime,type.this table will track all the activities of my website day wise and also type wise.thus,type may be 1 or 2.I need to display an open-chart for understanding the progress.So I need to retrieve the ratio of type2/type1 as input day wise.How can I get all these input for last 30 days from this table.Please give me some idea....It already kill my week end.Please help me

    Read the article

  • PHP does not store all variables in session

    - by Flurin Juvalta
    Dear all I'm assigning session variables by filling the $_SESSION - Array throughout my script. My problem is, that for some reason not all variables are available in the session. here is a shortened version of my code for explaining this issue: session_start(); print_r($_SESSION); $_SESSION['lang'] = 'de'; $_SESSION['location_id'] = 11; $_SESSION['region_id'] = 1; $_SESSION['userid'] = 'eccbc87e4b5ce2fe28308fd9f2a7baf3'; $_SESSION['hash'] = 'dce57f1e3bc6fba32afab93b0c38b662'; print_r($_SESSION); first call prints something like this: Array ( ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) the second call prints: Array ( [lang] => de [location_id] => 11 [region_id] => 1 ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) As you can see, the important login information is not stored in the session. Does anybody has an idea what could be wrong with my session? Thanks for your answers!

    Read the article

  • Disable popup message in php

    - by chupinette
    When i upload a excel file, i have used COM() to open and automate converting it to xml. It works fine, But when i run it, it always shows the message from Microsoft Excel: A file named ''' already exists in this location. Do you want to replace it? I can choose between Yes No and Cancel. normally i would choose Yes. But i dont want users to click on Yes each time. Can i disable this? Please inform me if any relevant codes need to be posted. Thanks

    Read the article

  • Searching with MATCH(), AGAINST() and AS score with mysqli and php

    - by Drew
    Below is the code I am using to search my table. I have made the relevant columns FULLTEXT in the table. This doesn't return me anything. Can someone tell me what it is that i'm doing wrong? Thanks in advance. $sql = 'SELECT id,uname,class,school, MATCH(uname, class, school) AGAINST(?) AS score FROM images WHERE MATCH(uname, class, school) AGAINST(? IN BOOLEAN MODE) ORDER BY score DES'; $stmt = $db_connection->prepare($sql); $stmt->bind_param('ss',$keyword,$keyword); $stmt->execute(); $stmt->store_result(); $stmt->bind_result($id,$uname,$class,$school); $xml = "<data>".PHP_EOL; while($stmt->fetch()){ $xml .= " <person>".PHP_EOL; $xml .= " <id>$id</id>".PHP_EOL; $xml .= " <name>$uname</name>".PHP_EOL; $xml .= " <class>$class</class>".PHP_EOL; $xml .= " <school>$school</school>".PHP_EOL; $xml .= " </person>".PHP_EOL; } $xml .= "</data>"; echo $xml; Below is an image of the indexes of the table:

    Read the article

  • PHP MySQLi and MySQLi_STMT: Which insert_id to use?

    - by Carvell Fenton
    Hello all, Both the MySQLi and MySQLi_STMT classes have an $insert_id property. If I am connected to my database using a MySQLi object (say $db), and then I perform an INSERT with a MySQLi_STMT object (say $stmt), to get the id of the last INSERT, should I use: $last_id = $db->insert_id; or $last_id = $stmt->insert_id; Or would they be the same, in which case it doesn't matter? I thought this might be a quick answer for someone, and save me the time of writing the test code to check it. Thanks in advance as always.

    Read the article

  • PHP echo text if variable is blank

    - by user342391
    I am trying to echo €00.00 if my variable $amount equals zero I have done something wrong can you help?? Code while ($row9 = mysql_fetch_array($result9)) { $amount = $row9['amount']; } //$amount = $amount / 60; //$amount = round($amount, 2); if $amount == 0 echo "<b>Balance: &#8364;00.00</b>"; else echo "<b>Balance: $$amount</b>";

    Read the article

  • need to query MongoDB using php

    - by Mario Villarroel
    I need to query mongodb with something like this: ("something" < X OR "something" = "nll") AND ("someother"X OR "someother"= "nll") AND z=$z AND s=1 I've tried a few things, but can't get it to work, this is what I've tried: find( array( '$or'=array(array("something"=array("$le",$X)),array("something"="nll")), '$or'=array(array("someother"=array("$ge",$X)),array("someother"="nll")) )) But that's getting me the OR overwritten, so I'm lost on that... After diggin a bit more, I assembled this code that seems to be what I need, but doesn't work either: find( array('$and'=array( array( '$or' = array( array("something"=array('$gte'=$X)),array("something"="nll"))), array('$or' = array( array("someother"=array('$lte'=$X)),array("someother"="nll")))),"Z"=$z, "s"="1"); But this doesn't work as it returns zero results and I know for sure that there are more than 2 items that match on the db. (100% certain)

    Read the article

  • <?php echo $questionTitle; ?> [closed]

    - by oil
    So this "question" makes no sense and will be closed. But are you willing to spend your hard-earned reputation to downvote it? Go on. A programmer should be able to make logical decisions, why will you downvote the question then instead of ignoring it?

    Read the article

< Previous Page | 288 289 290 291 292 293 294 295 296 297 298 299  | Next Page >