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  • How to pass array element one by one in text box in php

    - by trainee
    i am Reading the file contents and passed it in explod function("=",$string) ,it gives me two array parts[0].parts[1] seprated by = .parts[1] array displays all the values of the variable .now how can i use these values one by one to pass in the text box .The variable value comes in this way (value1 value2 value3 value4...) my code also throws the undefined offset :1 notice when i prints the parts[1]arrray

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  • php function to make slug (url string)

    - by andufo
    function gen_slug($str){ # special accents $a = array('À','Á','Â','Ã','Ä','Å','Æ','Ç','È','É','Ê','Ë','Ì','Í','Î','Ï','Ð','Ñ','Ò','Ó','Ô','Õ','Ö','Ø','Ù','Ú','Û','Ü','Ý','ß','à','á','â','ã','ä','å','æ','ç','è','é','ê','ë','ì','í','î','ï','ñ','ò','ó','ô','õ','ö','ø','ù','ú','û','ü','ý','ÿ','A','a','A','a','A','a','C','c','C','c','C','c','C','c','D','d','Ð','d','E','e','E','e','E','e','E','e','E','e','G','g','G','g','G','g','G','g','H','h','H','h','I','i','I','i','I','i','I','i','I','i','?','?','J','j','K','k','L','l','L','l','L','l','?','?','L','l','N','n','N','n','N','n','?','O','o','O','o','O','o','Œ','œ','R','r','R','r','R','r','S','s','S','s','S','s','Š','š','T','t','T','t','T','t','U','u','U','u','U','u','U','u','U','u','U','u','W','w','Y','y','Ÿ','Z','z','Z','z','Ž','ž','?','ƒ','O','o','U','u','A','a','I','i','O','o','U','u','U','u','U','u','U','u','U','u','?','?','?','?','?','?'); $b = array('A','A','A','A','A','A','AE','C','E','E','E','E','I','I','I','I','D','N','O','O','O','O','O','O','U','U','U','U','Y','s','a','a','a','a','a','a','ae','c','e','e','e','e','i','i','i','i','n','o','o','o','o','o','o','u','u','u','u','y','y','A','a','A','a','A','a','C','c','C','c','C','c','C','c','D','d','D','d','E','e','E','e','E','e','E','e','E','e','G','g','G','g','G','g','G','g','H','h','H','h','I','i','I','i','I','i','I','i','I','i','IJ','ij','J','j','K','k','L','l','L','l','L','l','L','l','l','l','N','n','N','n','N','n','n','O','o','O','o','O','o','OE','oe','R','r','R','r','R','r','S','s','S','s','S','s','S','s','T','t','T','t','T','t','U','u','U','u','U','u','U','u','U','u','U','u','W','w','Y','y','Y','Z','z','Z','z','Z','z','s','f','O','o','U','u','A','a','I','i','O','o','U','u','U','u','U','u','U','u','U','u','A','a','AE','ae','O','o'); return strtolower(preg_replace(array('/[^a-zA-Z0-9 -]/','/[ -]+/','/^-|-$/'),array('','-',''),str_replace($a,$b,$str))); } Works great, but i've found some cases in which it fails: echo gen_slug('andrés'); returns andras instead of andres why? any ideas on the preg_replace parameters?

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  • problem creating jpg thumb with php

    - by Ross
    Hi, I am having problems creating a thumbnail from an uploaded image, my problem is (i) the quality (ii) the crop http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/large.jpg http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/thumb.jpg If you look the quality is very poor and the crop is taken from the top and is not a resize of the original image although the dimesions mean it is in proportion. The original is 1600px wide by 1100px high. Any help would be appreciated. $thumb = $targetPath."Thumbs/".$fileName; $imgsize = getimagesize($targetFile); $image = imagecreatefromjpeg($targetFile); $width = 200; //New width of image $height = 138; //This maintains proportions $src_w = $imgsize[0]; $src_h = $imgsize[1]; $thumbWidth = 200; $thumbHeight = 138; // Intended dimension of thumb // Beyond this point is simply code. $sourceImage = imagecreatefromjpeg($targetFile); $sourceWidth = imagesx($sourceImage); $sourceHeight = imagesy($sourceImage); $targetImage = imagecreate($thumbWidth,$thumbHeight); imagecopyresized($targetImage,$sourceImage,0,0,0,0,$thumbWidth,$thumbWidth,imagesx($sourceImage),imagesy($sourceImage)); //imagejpeg($targetImage, "$thumbPath/$thumbName"); imagejpeg($targetImage, $thumb); chmod($thumb, 0755);

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  • count and fetch rows in php

    - by Mac Taylor
    hey guys i have a table in my mysql database named (names) now everyone can save their real names now i want to query this table and find out how many times these names used forexample the output should be : Jakob (20) Jenny (17) now this is my own code : list($usernames) =mysql_fetch_row(mysql_query('SELECT name FROM table_user GROUP BY name ORDER BY COUNT(name) DESC LIMIT 50 ')); list($c) =mysql_num_rows(mysql_query('SELECT COUNT(name) FROM table_user GROUP BY name ')); print $usernames.'('.$c.')' is this a correct approach ?!

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  • PHP, MySQL prepared statements - can you use results of execute more than once by calling data_seek(

    - by Carvell Fenton
    Hello, I have a case where I want to use the results of a prepared statement more than once in a nested loop. The outer loop processes the results of another query, and the inner loop is the results of the prepared statement query. So the code would be something like this (just "pseudoish" to demonstrate the concept): // not showing the outer query, it is just a basic SELECT, not prepared statement // we'll call it $outer_query $obj_array = array(); // going to save objects in this $ids = array(18,19,20); // just example id numbers $query = "SELECT field1, field2 FROM table1 WHERE id=?"; $stmt = $db->prepare($query); foreach ($ids as $id) { $stmt->bind_param("i", $id); $stmt->execute(); $stmt->bind_result($var1, $var2); $stmt->store_result(); // I think I need this for data_seek while ($q1 = $outer_query->fetch_object()) { while ($stmt->fetch()) { if ($q1->field1 == $var1) { // looking for a match $obj = new stdClass(); $obj->var1 = $var1; $obj->var2 = $var2; $obj_array[] = $obj; $stmt->data_seek(0); // reset for outer loop break; // found match, so leave inner } } } } The problem I seem to be experiencing is that the values are not getting bound in the variables as I would expect after the first time I use fetch in the inner loop. Specifically, in one example I ran with 3 ids for the foreach, the first id was processed correctly, the second was processed incorrectly (matches were not found in the inner loop even though they existed), and then the third was processed correctly. Is there something wrong with the prepared statment function calls in the sequence I am doing above, or is this an invalid way to use the results of the prepared statement? Thanks.

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  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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  • Errors checking and opening a URL using PHP

    - by Jean
    Hello Here is one script with out any errors $url="http://yahoo.com"; $file1 = fopen($url, "r"); $content = file_get_contents($url); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; And here is the same script using a look to check multiple urls and getting errors for ($j=1;$j<=$i;$j++) { if ($x[$j]!=''){ $t_u = "http:".$x[$j]; $file2 = fopen($t_u, "r"); $content2 = file_get_contents($t_u); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; } } The error is Warning: fopen() [function.fopen]: php_network_getaddresses: getaddrinfo failed: No such host is known. in g:/ What exactly is wrong here?

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  • (PHP) Converting an array of arrays from one format into another

    - by Richard Carter
    Hi, I currently have an array, created from a database, an example of which looks like the following: Array( [0] => Array ( objectid => 2, name => title, value => apple ), [1] => Array ( objectid => 2, name => colour, value => red ), [2] => Array ( objectid => 3, name => title, value => pear ), [3] => Array ( objectid => 3, name => colour, value => green ) ) What I would like to do is group all the items in the array by their objectid, and convert the 'name' values into keys and 'value' values into values of an associative array....like below: Array ( [0] => Array ( objectid => 2, title => apple, colour => red ), [1] => Array ( objectid => 3, title => pear, colour => green ) ) I've tried a few things but haven't really got anywhere.. Any ideas? Thanks in advance

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  • PHP mysql_fetch_array

    - by rag
    $n=mysql_num_rows($rs); $i=0; while($n>0) { while(($row=mysql_fetch_array($rs))&&$i<=5) { echo $row['room_name']; $i=$i+1; //echo $n."<br>"; } echo "<br>"; //echo "n1=".$n; $n=$n-5; // $i=0; } Output:101102103104105106 108109110 The row for roomname 107 is missing.... anybody please tell me what is the problem while reentering the loop again...

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  • PHP + MySQL - Match first letter of directory

    - by user1822825
    Let's say I have a class table. In the class table, there are many students with their pictures. In the first registration, I've registered the class and students with pictures. The pictures were put into a directory like classid_classname. Then, I change the class name. Now, I'm adding the student's picture. Now, the new picture can't be recognized because the class name has changed. The pic url will be set as classid_class(new)name. How can I match the first letter of the directory? This is my update code : $classID= $_POST["classID"]; $className= $_POST["className"]; $p1 = $_FILES['p1']['name']; $p2 = $_FILES['p2']['name']; $p3 = $_FILES['p3']['name']; $direct = $_POST["className"]; $direct = strtolower($direct); $direct = str_replace(' ', '_', $direct); $tfish = $classID."_".$direct; //the directory variable will have new name because it can't be fetched if the directory has been changed many times// $file = "slider_imagesClass/".$tfish."/"; $url = "/".$tfish."/"; How can I make the variable to match the first letter of the directory because the classID will not change? Thank you. Really appreciate your help :D

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  • Apply PHP regex replace on a multi-line repeated pattern

    - by Hussain
    Let's say I have this input: I can haz a listz0rs! # 42 # 126 I can haz another list plox? # Hello, world! # Welcome! I want to split it so that each set of hash-started lines becomes a list: I can haz a listz0rs! <ul> <li>42</li> <li>126</li> </ul> I can haz another list plox? <ul> <li>Hello, world!</li> <li>Welcome!</li> </ul> If I run the input against the regex "/(?:(?:(?<=^# )(.*)$)+)/m", I get the following result: Array ( [0] => Array ( [0] => 42 ) [1] => Array ( [0] => 126 ) [2] => Array ( [0] => Hello, world! ) [3] => Array ( [0] => Welcome! ) ) This is fine and dandy, but it doesn't distinguish between the two different lists. I need a way to either make the quantifier return a concatenated string of all the occurrences, or, ideally, an array of all the occurrences. Ideally, this should be my output: Array ( [0] => Array ( [0] => 42 [1] => 126 ) [1] => Array ( [0] => Hello, world! [1] => Welcome! ) ) Is there any way of achieving this, and if not, is there a close alternative? Thanks in advance!

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  • Math - Adding with PHP

    - by Wayne
    Basically I can't get it right. I need something like this: if($p == 1) { $start = 0; $limit = 16; } The numbers must add on depending on the value of the $p, e.g. if $p is 5 then the values of $start and $limit would be: if($p == 5) { $start = 64; $limit = 80; } The math is to add 16, depending on the value of $p. Thanks.

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  • PHP/MYSQL Trouble Selecting by Primary Key

    - by djs22
    Hi all, So I have a primary key column called key. I'm trying to select the row with key = 1 via this code: $query ="SELECT * FROM Bowlers WHERE key = '1'"; $result = mysql_query($query) or die(mysql_error()); For some reason, I'm getting this result: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key = '1'' at line 1 The mysql statement works for using other keys, ie WHERE name = 'djs22'. Any ideas?

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  • PHP does not store all variables in session

    - by Flurin Juvalta
    Dear all I'm assigning session variables by filling the $_SESSION - Array throughout my script. My problem is, that for some reason not all variables are available in the session. here is a shortened version of my code for explaining this issue: session_start(); print_r($_SESSION); $_SESSION['lang'] = 'de'; $_SESSION['location_id'] = 11; $_SESSION['region_id'] = 1; $_SESSION['userid'] = 'eccbc87e4b5ce2fe28308fd9f2a7baf3'; $_SESSION['hash'] = 'dce57f1e3bc6fba32afab93b0c38b662'; print_r($_SESSION); first call prints something like this: Array ( ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) the second call prints: Array ( [lang] => de [location_id] => 11 [region_id] => 1 ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) As you can see, the important login information is not stored in the session. Does anybody has an idea what could be wrong with my session? Thanks for your answers!

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  • Editing a remote file on-the-fly with PHP

    - by user275074
    Hi, I have a requirement to edit a remote text file on-the-fly, the content of which currently stands at ~1Mb. I have tried a couple of approaches and both seem to be clunky or hog memory which I can't rely on. Thinking out logically what I'm trying to achieve is: FTP to a remote server. Download a copy of the file for backup purposes and store it somewhere locally. Open the remote file and add the necessary lines required. Remove lines from the remote file as per an array of un-required data generated from the local server. Is this possible? I've managed to code steps 1 and 2 but I'm having difficult with 3 and 4. The way I'm doing it now is to use fgets and return the whole string. Really, I don't want to do this as it involves manipulating and re-generating the whole string (and it's large) and then re-inserting it in between two markers in the remote file. Is there no way of manipulating the lines of text in the file on-the-fly?

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  • Mysql results into array (PHP)

    - by cthulhu
    How can i convert mysql results (from mysql_fetch_array) into such a form? $some = array( "comments" => array( array( "text" => "hi", "id" => "1" ), array( "text" => "hi", "id" => "2" ), array( "text" => "hi", "id" => "3" ), array( "text" => "hi", "id" => "4" ) ) ); while the db looks like: comments id text 1 blabla bla 2 bla bla i've tried to fetch the values with foreach/while and insert it into two arrays but no success...

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  • Delete text in text box using PHP

    - by Idealflip
    Hello, is there a way to remove text from a text box using a submit button? I don't want to delete text from all boxes on the form. And I don't want to delete text 'onclick', for the element. I need the code to clear the text box, to initiate from within a block. Thanks for your help!

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  • PHP echo text if variable is blank

    - by user342391
    I am trying to echo €00.00 if my variable $amount equals zero I have done something wrong can you help?? Code while ($row9 = mysql_fetch_array($result9)) { $amount = $row9['amount']; } //$amount = $amount / 60; //$amount = round($amount, 2); if $amount == 0 echo "<b>Balance: &#8364;00.00</b>"; else echo "<b>Balance: $$amount</b>";

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  • PHP While Loops from Arrays

    - by Michael
    I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

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  • PHP Populating array with $variables

    - by Tom
    Hi, I'm trying to create a basic shopping cart, having an issue with the product page allowing users to add more items to their cart then are in stock (I have code in place to prevent this on the view cart page, just not the view product page) This is what I have so far; for ($i = 0; $i < $numItem; $i++) { extract($cartContent[$i]); $subTotal += $price * $cartQuantity; $cartLimiter[$itemNo => $cartQuantity]; Using an array so the position number becomes the item number and the cart quantity becomes the assigned value, however it doesn't seem to like it and throws out on the bottom line of code: Parse error: syntax error, unexpected T_DOUBLE_ARROW, expecting ']' Thanks

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  • <?php echo $questionTitle; ?> [closed]

    - by oil
    So this "question" makes no sense and will be closed. But are you willing to spend your hard-earned reputation to downvote it? Go on. A programmer should be able to make logical decisions, why will you downvote the question then instead of ignoring it?

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