Search Results

Search found 1081 results on 44 pages for 'combinations'.

Page 3/44 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Prevent Virtualbox intercepting certain key combinations?

    - by Blazemore
    Is it possible to prevent my Windows 7 guest OS intercepting Ctrl+Up/Down, and allow my Ubuntu how to intercept them instead? I have a dual-monitor setup with two vertical virtual desktops on Ubuntu. I have a Windows 7 fullscreen guest on one monitor, set to always display on the current workspace. This means I have effectively two vertical workspaces on one monitor, and just Windows 7 on the other. The problem occurs with Windows 7 is focussed and I hit Ctrl+Up/Down to switch workspaces. I have to click out of the VM first, which breaks my workflow. Can this be fixed?

    Read the article

  • Objective-C vs JavaScript loop performance

    - by micadelli
    I have a PhoneGap mobile application that I need to generate an array of match combinations. In JavaScript side, the code hanged pretty soon when the array of which the combinations are generated from got a bit bigger. So, I thought I'll make a plugin to generate the combinations, passing the array of javascript objects to native side and loop it there. To my surprise the following codes executes in 150 ms (JavaScript) whereas in native side (Objective-C) it takes ~1000 ms. Does anyone know any tips for speeding up those executing times? When players exceeds 10, i.e. the length of the array of teams equals 252 it really gets slow. Those execution times mentioned above are for 10 players / 252 teams. Here's the JavaScript code: for (i = 0; i < GAME.teams.length; i += 1) { for (j = i + 1; j < GAME.teams.length; j += 1) { t1 = GAME.teams[i]; t2 = GAME.teams[j]; if ((t1.mask & t2.mask) === 0) { GAME.matches.push({ Team1: t1, Team2: t2 }); } } } ... and here's the native code: NSArray *teams = [[NSArray alloc] initWithArray: [options objectForKey:@"teams"]]; NSMutableArray *t = [[NSMutableArray alloc] init]; int mask_t1; int mask_t2; for (NSInteger i = 0; i < [teams count]; i++) { for (NSInteger j = i + 1; j < [teams count]; j++) { mask_t1 = [[[teams objectAtIndex:i] objectForKey:@"mask"] intValue]; mask_t2 = [[[teams objectAtIndex:j] objectForKey:@"mask"] intValue]; if ((mask_t1 & mask_t2) == 0) { [t insertObject:[teams objectAtIndex:i] atIndex:0]; [t insertObject:[teams objectAtIndex:j] atIndex:1]; /* NSArray *newCombination = [[NSArray alloc] initWithObjects: [teams objectAtIndex:i], [teams objectAtIndex:j], nil]; */ [combinations addObject:t]; } } } ... the array in question (GAME.teams) looks like this: { count = 2; full = 1; list = ( { index = 0; mask = 1; name = A; score = 0; }, { index = 1; mask = 2; name = B; score = 0; } ); mask = 3; name = A; }, { count = 2; full = 1; list = ( { index = 0; mask = 1; name = A; score = 0; }, { index = 2; mask = 4; name = C; score = 0; } ); mask = 5; name = A; },

    Read the article

  • create program in c for permutation combination and showing frequency

    - by Vishal Oswal
    I have 2 strings where I have saved fixed 20 characters and these are “A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T” and same 20 char in string 2. so I will get 400 combinations of 2 character sets like AA,AB,AC,AD,AE,AF,……………AT BA,BB,BC,BD,BE,BF,…………..BT CA,CB,CC,CD,CE,CF……………CT This way we will get 400 combinations (Which program I have created successfully) but then user will put the value till 31 characters witch will be treated as 3rd string for E.g. “ABCDDAAAB” now I have to check the frequency of user input in the sequence of 12,23,34,45,56,67,78,89 (2 CHAR SET) means AB,BC,CD,DD,DA,AA,AA,AB and need to show the frequency of user input OUTPUT: AB=2 BC=1 CD=1 DD=1 DA=1 AA=2 please its urgent

    Read the article

  • PHP 2D Array output all combinations

    - by stukerr
    Hi there, I've had this problem bending my mind for a while now (head cold doesn't help either!), basically I have a PHP array which looks like this example: $array[0][0] = 'apples'; $array[0][1] = 'pears'; $array[0][2] = 'oranges'; $array[1][0] = 'steve'; $array[1][1] = 'bob'; And I would like to be able to produce from this a table with every possible combination of these, but without repeating any combinations (regardless of their position), so for example this would output Array 0 Array 1 apples steve apples bob pears steve pears bob But I would like for this to be able to work with as many different arrays as possible. Many thanks!

    Read the article

  • Creating combinations that have no more one intersecting element

    - by khuss
    I am looking to create a special type of combination in which no two sets have more than one intersecting element. Let me explain with an example: Let us say we have 9 letter set that contains A, B, C, D, E, F, G, H, and I If you create the standard non-repeating combinations of three letters you will have 9C3 sets. These will contain sets like ABC, ABD, BCD, etc. I am looking to create sets that have at the most only 1 common letter. So in this example, we will get following sets: ABC, ADG, AEI, AFH, BEH, BFG, BDI, CFI, CDH, CEG, DEF, and GHI - note that if you take any two sets there are no more than 1 repeating letter. What would be a good way to generate such sets? It should be scalable solution so that I can do it for a set of 1000 letters, with sub set size of 4. Any help is highly appreciated. Thanks

    Read the article

  • All possible combinations for two column data

    - by Alec Dobbie
    I have a two column view Product Id Tag ---------------------- 1 Leather 1 Watch 2 Red 2 Necklace 2 Pearl I'm trying to get all possible combinations of tags for a product as such: 1 Leather 1 Leather,Watch 2 Pearl 2 Pearl,Necklace 2 Pearl Necklace,Red 2 Necklace 2 Necklace, Red 2 Red I've found and stolen some SQL that give me the complete list for all but not the small versions, its below. Any ideas, it's started to make my head hurt. A virtual pint for the best answer. SELECT ProductId, (SELECT CAST(Tag + ', ' AS VARCHAR(MAX)) FROM ProductByTagView WHERE Product.ProductId = ProductByTagView.ProductId order by tag FOR XML PATH ('')) AS Tags FROM Product

    Read the article

  • how many color combinations in a 24 bit image

    - by numerical25
    I am reading a book and I am not sure if its a mistake or I am misunderstanding the quote. It reads... Nowadays every PC you can buy has hardware that can render images with at least 16.7 million individual colors. Rather than have an array with thousands of color entries, the images instead contain explicit color values for each pixel. A 24-bit display, of course, uses 24 bits, or 3 bytes per pixel, for color information. This gives 1 byte, or 256 distinct values each, for red, green, and blue. This is generally called true color, because 256^3 (16.7 million) He says 1 byte is equal to 256 distinct values. 1 byte = 8 bits. 8^2 bits = 64 combinations of colors right ?? It's not adding up right to me. I know it might be something simple to understand, but I don't understand.

    Read the article

  • How to check and match the possible combinations of arraylist elements

    - by Jessy
    String [] A = {"High","Medium","Low"}; String [] B = {"High","Medium","Low"}; String [] C = {"High","Medium","Low"}; String [] D = {"High","Medium","Low"}; String [] E = {"High","Medium","Low"}; String [] F = {"High","Medium","Low"}; JComboBox Ai = new JComboBox(A); JComboBox Bi = new JComboBox(B); JComboBox Ci = new JComboBox(C); JComboBox Di = new JComboBox(C); JComboBox Ei = new JComboBox(E); JComboBox Fi = new JComboBox(F); .... //add the user choice in arrayList ArrayList<String> a = new ArrayList<String>(); a.add((String) Ai.getSelectedItem()); a.add((String) Bi.getSelectedItem()); a.add((String) Ci.getSelectedItem()); a.add((String) Di.getSelectedItem()); a.add((String) Ei.getSelectedItem()); a.add((String) Fi.getSelectedItem()); Scenario: On each comboBox, user need to choose one, which mean there are 6 choices at the end. There are 6*5*4*3*2*1 = 720 possible combinations of choices made by the user. What is the best way to check and match the user choice without writing the 720 else if ? e.g. if(Ai=="High" && Bi=="High" && Ci=="Low" && Di=="High" && Ei=="Low" && Fi=="Medium") { System.out.println("Good Choice"); } Thank you.

    Read the article

  • C# algorithm for figuring out different possible combinations...

    - by ttomsen
    I have 10 boxes, each box can hold one item from a group/type of items, each 'group' type only fits in one of the 10 box types. The pool can have n number of items. The groups have completely distinct items. Each item has a price, i want an algorithm that will generate all the different possibilities, so i can figure out different price points. so a smaller picture of the problem BOX A - can have item 1,2,3,4 in it BOX B - can have item 6,7,8,9,10,11,12 BOX C - can have item 13,15,16,20,21 The items are stored in a db, they have a column which denotes which box they can go in. All box types are stored in an array, and I can put the items in a generic list. Anyone see a straightforward way to do this. I have tried doing 10 nested foreach's to see if i could find a simpler way. The nested loops will take MANY hours to run. the nested for each's basically pull all combinations, then calculate a rank for each combination, and store the top 10 ranked combination of items for output

    Read the article

  • Counting combinations in c or in python

    - by Dennis
    Hello I looked a bit on this topic here but I found nothing that could help me. I need a program in Python or in C that will give me all possible combinations of a and b that will meet the requirement n=2*a+b, for n from 0 to 10. a, b and n are integers. For example if n=0 both a and b must be 0. For n=1 a must be zero and b must be 1, for n=2 a can be 1 and b=0, or a=0 and b=2, etc. I'm not that good with programming. I made this: #include <stdio.h> int main(void){ int a,b,n; for(n = 0; n <= 10; n++){ for(a = 0; a <= 10; a++){ for(b = 0; b <= 10; b++) if(n == 2*a + b) printf("(%d, %d), ", (a,b)); } printf("\n"); } } But it keeps getting strange results like this: (0, -1079628000), (1, -1079628000), (2, -1079628000), (0, -1079628000), (3, -1079628000), (1, -1079628000), (4, -1079628000), (2, -1079628000), (0, -1079628000), (5, -1079628000), (3, -1079628000), (1, -1079628000), (6, -1079628000), (4, -1079628000), (2, -1079628000), (0, -1079628000), (7, -1079628000), (5, -1079628000), (3, -1079628000), (1, -1079628000), (8, -1079628000), (6, -1079628000), (4, -1079628000), (2, -1079628000), (0, -1079628000), (9, -1079628000), (7, -1079628000), (5, -1079628000), (3, -1079628000), (1, -1079628000), (10, -1079628000), (8, -1079628000), (6, -1079628000), (4, -1079628000), (2, -1079628000), (0, -1079628000), ideone Any idea what is wrong? Also if I could do this for Python it would be even cooler. :D

    Read the article

  • Find valid assignments of integers in arrays (permutations with given order)

    - by evident
    Hi everybody! I am having a general problem finding a good algorithm for generating each possible assignment for some integers in different arrays. Lets say I have n arrays and m numbers (I can have more arrays than numbers, more numbers than arrays or as much arrays as numbers). As an example I have the numbers 1,2,3 and three arrays: { }, { }, { } Now I would like to find each of these solutions: {1,2,3}, { }, { } { }, {1,2,3}, { } { }, { }, {1,2,3} {1,2}, {3}, { } {1,2}, { }, {3} { }, {1,2}, {3} {1}, {2,3}, { } {1}, { }, {2,3} { }, {1}, {2,3} {1}, {2}, {3} So basically I would like to find each possible combination to assign the numbers to the different arrays with keeping the order. So as in the example the 1 always needs to come before the others and so on... I want to write an algorithm in C++/Qt to find all these valid combinations. Does anybody have an approach for me on how to handle this problem? How would I generate these permutations?

    Read the article

  • Is there an expand.grid like function in R, returning permutations ?

    - by Brani
    To become more specific, here is an example: > expand.grid(5, 5, c(1:4,6),c(1:4,6)) Var1 Var2 Var3 Var4 1 5 5 1 1 2 5 5 2 1 3 5 5 3 1 4 5 5 4 1 5 5 5 6 1 6 5 5 1 2 7 5 5 2 2 8 5 5 3 2 9 5 5 4 2 10 5 5 6 2 11 5 5 1 3 12 5 5 2 3 13 5 5 3 3 14 5 5 4 3 15 5 5 6 3 16 5 5 1 4 17 5 5 2 4 18 5 5 3 4 19 5 5 4 4 20 5 5 6 4 21 5 5 1 6 22 5 5 2 6 23 5 5 3 6 24 5 5 4 6 25 5 5 6 6 This data frame was created from all combinations of the supplied vectors. I would like to create a similar data frame from all permutations of the supplied vectors. Notice that each row must contain exactly 2 fives, yet not necessarily as the fist two elements. Thank you.

    Read the article

  • a non recursive approach to the problem of generating combinations at fault

    - by mark
    Hi, I wanted a non recursive approach to the problem of generating combination of certain set of characters or numbers. So, given a subset k of numbers n, generate all the possible combination n!/k!(n-k)! The recursive method would give a combination, given the previous one combination. A non recursive method would generate a combination of a given value of loop index i. I approached the problem with this code: Tested with n = 4 and k = 3, and it works, but if I change k to a number 3 it does not work. Is it due to the fact that (n-k)! in case of n = 4 and k = 3 is 1. and if k 3 it will be more than 1? Thanks. int facto(int x); int len,fact,rem=0,pos=0; int str[7]; int avail[7]; str[0] = 1; str[1] = 2; str[2] = 3; str[3] = 4; str[4] = 5; str[5] = 6; str[6] = 7; int tot=facto(n) / facto(n-k) / facto(k); for (int i=0;i<tot;i++) { avail[0]=1; avail[1]=2; avail[2]=3; avail[3]=4; avail[4]=5; avail[5]=6; avail[6]=7; rem = facto(i+1)-1; cout<<rem+1<<". "; for(int j=len;j>0;j--) { int div = facto(j); pos = rem / div; rem = rem % div; cout<<avail[pos]<<" "; avail[pos]=avail[j]; } cout<<endl; } int facto(int x) { int fact=1; while(x0) fact*=x--; return fact; }

    Read the article

  • Silverlight handling multiple key press combinations.

    - by SilverDark
    I have a Silverlight application in which I catch certain key presses such as TAB or CTRL to perform some action. However, I want to be able to handle multiple keys pressed at the same time such as CTRL + R or something like that. Is there any way to do that in Silverlight, and if so, how? Thank you in advance.

    Read the article

  • Generating all unique combinations for "drive ya nuts" puzzle

    - by Yuval A
    A while back I wrote a simple python program to brute-force the single solution for the drive ya nuts puzzle. The puzzle consists of 7 hexagons with the numbers 1-6 on them, and all pieces must be aligned so that each number is adjacent to the same number on the next piece. The puzzle has ~1.4G non-unique possibilities: you have 7! options to sort the pieces by order (for example, center=0, top=1, continuing in clockwise order...). After you sorted the pieces, you can rotate each piece in 6 ways (each piece is a hexagon), so you get 6**7 possible rotations for a given permutation of the 7 pieces. Totalling: 7!*(6**7)=~1.4G possibilities. The following python code generates these possible solutions: def rotations(p): for i in range(len(p)): yield p[i:] + p[:i] def permutations(l): if len(l)<=1: yield l else: for perm in permutations(l[1:]): for i in range(len(perm)+1): yield perm[:i] + l[0:1] + perm[i:] def constructs(l): for p in permutations(l): for c in product(*(rotations(x) for x in p)): yield c However, note that the puzzle has only ~0.2G unique possible solutions, as you must divide the total number of possibilities by 6 since each possible solution is equivalent to 5 other solutions (simply rotate the entire puzzle by 1/6 a turn). Is there a better way to generate only the unique possibilities for this puzzle?

    Read the article

  • Multi-base conversion - using all combinations for URL shortener

    - by Guffa
    I am making an URL shortener, and I am struggling with the optimal way of encoding a number (id) into a character string. I am using the characters 0-9,A-Z,a-z so it will basically be a base-62 encoding. That is pretty basic, but it doesn't make use of all possible codes. The codes that it would produce would be: 0, 1, ... y, z, 10, 11, ... zy, zz, 100, 101, ... Notice that the codes 00 to 0z is not used, the same for 000 to 0zz, and so on. I would like to use all the codes, like this: 0, 1, ... y, z, 00, 01, ... zy, zz, 000, 001, ... It would be some combination of base-62 and base-63, with different bases depending on the position... Using base-62 is easy, for example: create procedure tiny_GetCode @UrlId int as set nocount on declare @Code varchar(10) set @Code = '' while (@UrlId > 0 or len(@Code) = 0) begin set @Code = substring('0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz', @UrlId % 62 + 1, 1) + @Code set @UrlId = @UrlId / 62 end select @Code But I haven't yet managed to make a multi-base conversion out of it, to make use of all the codes.

    Read the article

  • Generating All Permutations of Character Combinations when # of arrays and length of each array are

    - by Jay
    Hi everyone, I'm not sure how to ask my question in a succinct way, so I'll start with examples and expand from there. I am working with VBA, but I think this problem is non language specific and would only require a bright mind that can provide a pseudo code framework. Thanks in advance for the help! Example: I have 3 Character Arrays Like So: Arr_1 = [X,Y,Z] Arr_2 = [A,B] Arr_3 = [1,2,3,4] I would like to generate ALL possible permutations of the character arrays like so: XA1 XA2 XA3 XA4 XB1 XB2 XB3 XB4 YA1 YA2 . . . ZB3 ZB4 This can be easily solved using 3 while loops or for loops. My question is how do I solve for this if the # of arrays is unknown and the length of each array is unknown? So as an example with 4 character arrays: Arr_1 = [X,Y,Z] Arr_2 = [A,B] Arr_3 = [1,2,3,4] Arr_4 = [a,b] I would need to generate: XA1a XA1b XA2a XA2b XA3a XA3b XA4a XA4b . . . ZB4a ZB4b So the Generalized Example would be: Arr_1 = [...] Arr_2 = [...] Arr_3 = [...] . . . Arr_x = [...] Is there a way to structure a function that will generate an unknown number of loops and loop through the length of each array to generate the permutations? Or maybe there's a better way to think about the problem? Thanks Everyone!

    Read the article

  • Multilingual best practices on SQL Server, EF and MVC combinations

    - by dengereli
    ASP.NET MVC, resource management is look like enough for application multlingual multiculture support. But I am wondering practices about data. User stories; User set culture as en-US and see all product items in English. User set culture as fr-FR and see all product items in French. User set culture as ru-RU and see all product items in Russian. User doesn't have right change culture settings and application never reach multilingual resources, it will use default language and culture.

    Read the article

  • Looking for combinations of server and embedded database engines

    - by codeelegance
    I'm redesigning an application that will be run as both a single user and multiuser application. It is a .NET 2.0 application. I'm looking for server and embedded databases that work well together. I want to deploy the embedded database in the single user setup and of course, the server in the multiuser setup. Past releases have been based on MSDE but in the past year we've been having a lot of install issues: new installs hanging and leaving the system in an unknown state, upgrades disconnecting the database, etc. I migrated the application to SQL Server 2005 and the install is more reliable (as long as a user doesn't try to install over a broken MSDE installation). Since next year's release will be a complete redesign I figured now's the best time to address the database issue as well. The database has been abstracted from the rest of the application so I just need to choose which database(s) to use and write an implementation for each one. So far I've considered: SQL Server/ SQL Server Compact Edition Firebird (same DB engine is available in two different server modes and an embedded dll) Each has its own merits but I'm also interested in any other suggestions. This is a fairly simple program and its data requirements are simple as well. I don't expect it to strain whatever database I eventually choose. So easy configuration and deployment hold more weight than performance.

    Read the article

  • Key combinations for a Hot key

    - by HanuAthena
    We are developing a hot key for one of our application. A key combination that is easy to remember easy to press (especially for people with small fingers) certainly not ctrl-alt-del ;) Which key combination do you suggest for a hot-key?

    Read the article

  • string combinations

    - by vbNewbie
    I would like to generate a combination of words. For example if I had the following list: {cat, dog, horse, ape, hen, mouse} then the result would be n(n-1)/2 cat dog horse ape hen mouse (cat dog) (dog horse) (horse ape) (ape hen) (hen mouse) (cat dog horse) (dog horse ape) (horse ape hen) etc Hope this makes sense...everything I found involves permutations The list I have would be a 500 long

    Read the article

  • linear combinations in python/numpy

    - by nmaxwell
    greetings, I'm not sure if this is a dumb question or not. Lets say I have 3 numpy arrays, A1,A2,A3, and 3 floats, c1,c2,c3 and I'd like to evaluate B = A1*c1+ A2*c2+ A3*c3 will numpy compute this as for example, E1 = A1*c1 E2 = A2*c2 E3 = A3*c3 D1 = E1+E2 B = D1+E3 or is it more clever than that? In c++ I had a neat way to abstract this kind of operation. I defined series of general 'LC' template functions, LC for linear combination like: template<class T,class D> void LC( T & R, T & L0,D C0, T & L1,D C1, T & L2,D C2) { R = L0*C0 +L1*C1 +L2*C2; } and then specialized this for various types, so for instance, for an array the code looked like for (int i=0; i<L0.length; i++) R.array[i] = L0.array[i]*C0 + L1.array[i]*C1 + L2.array[i]*C2; thus avoiding having to create new intermediate arrays. This may look messy but it worked really well. I could do something similar in python, but I'm not sure if its nescesary. Thanks in advance for any insight. -nick

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >