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  • Unresponsive form instance when instantiating form gets minimized

    - by sjlewis
    There's form A is the main form that gets hidden and is accessible via NotifyIcon's context menu. Form A instantiates form B via NotifyIcon's context menu also. Form B reacts to mouse events, etc. No problem there. Form B instantiates form C. Form C reacts to mouse events, etc. No problem here as well, but when form B gets minimized, form C no longer reacts to mouse events (eg. can no longer move, button clicks do not respond). Any idea why form C behaves like this in relation to form B getting minimized. I also tried to instantiate form C through form A (eg. form B calling a method in form A to instantiate form C) but the same thing happens. Is there any way to make form C respond even w/ form B (initiator) minimized?

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  • Does form with enctype="multipart/form-data" cause problems accessing a hidden field

    - by Ankur
    I have created a hidden form element <form name="UploadImage" enctype="multipart/form-data" method="post" action="UploadImage"> <label> </label> <input name="imgUploadObjId" id="imgUploadObjId" value="52" type="hidden"> //rest of the form here </form> And I am trying to get the value with this line in a servlet (as I have done before): int objId = Integer.parseInt(request.getParameter("imgUploadObjId")); But I get this (line 33 is the line above): java.lang.NumberFormatException: null java.lang.Integer.parseInt(Unknown Source) java.lang.Integer.parseInt(Unknown Source) web.objects.UploadImage.doPost(UploadImage.java:33) javax.servlet.http.HttpServlet.service(HttpServlet.java:637) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) Is there something different about a form with enctype="multipart/form-data"? Or can you see some other error.

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  • Spring Form: Submitting extra parameter on submit buttons

    - by theringostarrs
    Hi, I am working on a form with a bunch of selection criteria that will generate a report when the form is submitted. I also have a number of different reports that can be generated form this same criteria, and want the type of report to be selectable by using a tab system where each tab clicked on submits the form and generates the correct report. I was to do this by passing an extra parameter into the form to switch onto the right form type I am new to Spring, and from the guidance of an elder was told to use an input button for each tab with the following approximate syntax: <input type="submit" name="${form.selectionValues.tabSelection}" value="1" /> tabSelection form property of the SelectionValues object is not being set. I wasn't surprised ;) DIdn't think this would work. So I am wondering how can I can submit a post back from a button in Spring containing the form values plus an extra tabSelection parameter and value? How should I mark up this mechanism? Will I have to do anything to the form controller to register this extra parameter? The original markup I was using to build this page, was using HTML anchor tags instead of buttons for the tab links, which would be much better for the CSS, is there any way to trigger a full form submit using an anchor href? I know this will be a GET request instead of a POST, and not associated with the form.. so I dont expect this to work.. just trying to think of solutions! I would prefer to use the priginal markup, as the styles are there. Any help would be appreciated

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  • How to create the automatic mass form submitter (javascript-ajax script) to be used on the 3rd part

    - by Daniel
    I need a script that can handle the following tasks. Take user data from my database and fill in and submit / post data to forms located on third part websites.: So I want to know if is it hard to create or do somebody knows if does exists some script for mass form submissions in PHP -Javascript-Ajax ? I run Dancers & Hostess & Model jobs website, I would like to find some script which allows the girls automaticly submit to hundreds websites forms (other 3rd part model agencies) with their similar model application form info on my website previously specified, 1).Firstly the girls will fill out my agency portfolio very detailed form , like this i will get all the model personal info from them , 2) Secondly i would like to allow for example models to submit to 100 and more other model agencies forms (I will find those websites before, and I will get their field names = values and thanks to some script would like to connect them with every girl data already created in my website to submit . I would like to implement it to my wordpress website where the girls has their portfolios instead of my pages . I would like to offer this service especially to models , it should work like some directory submitters , The script knows names - values and fill it out itself, but I want it online - browser side, where the girls should only fill out captcha if there is and click the button "submit".After succesful submit it should offer other form to submit. I would be very happy if you know the answer or if you can redirect me to some article

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  • Stop a custom submit button from firing the form validation on a CCK form

    - by kidrobot
    I've added a submit button inside a fieldgroup on a CCK form using hook_form_alter as follows: function mymodule_form_alter(&$form, $form_state, $form_id) { if ($form_id == 'object_node_form') { $form['group_wikipedia']['search'] = array( '#type' => 'submit', '#value' => t('Search Wikipedia'), '#name' => 'searchwiki', '#submit' => array('mymodule_searchwiki_submit'), ); } } When I press the button, the validation handlers for the full form eg. checks for required fields, run as though I have pressed the 'Submit' button at the end of the form. I thought that changing the #name property from 'op' to 'searchwiki' would prevent this kind of mix-up, but not so. Does anyone know a workaround for this?

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  • ajax->form submit onchage event on selectTag keeping submit button on form without click

    - by prashant
    Hi, I am using cakephp 1.1. for my project.I used ajax-form for form creation.In one form, form submitted using onchange event of selectTag taking submit button and giving submit.click for that button.But it peroperly not redirect to view file gives error "cake/libs/model/datasources/dbo_source.php" and submit that form,but I am not getting to which view it is submitting(submittied form to itself).

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  • Jquery validations on form with no fields

    - by jcovert
    I have a table (in a form) populated with radio buttons (with a button for each value in a collection). If the collection is empty, nothing shows up in the table (which is fine). (I'm using Struts2) My trouble comes when validating that the user has selected one of these radio buttons when the submit button is clicked. I'm using JQUERY validations, and it works quite well UNLESS there are no radio buttons to select (collection is empty). $('#startProcessForm').validate({ rules: { selectedProcess: { required: true } }, messages: { selectedProcess: "Please select a process to start." } }); If the list IS empty, then there are no fields (radio button or otherwise) named "selectedProcess". So my question is this: How can I make "selectedProcess" exist AND fail the 'required:true' validation if there's nothing in the collection? I was thinking I could create an empty tag of the same name (selectedProcess) if the collection is empty? Here's what I'd guess would work but doesn't seem to: <s:if test="processes != null && !processes.isEmpty()"> <s:iterator value="processes" status="processesStatus"> <tr> <td><s:radio name="selectedProcess" list="{name}"></s:radio></td> </tr> </s:iterator> </s:if> <s:else> <tr> <td><a name="selectedProcess"></a></td> </tr> </s:else> Thanks!

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  • Passing variables to a Custom Zend Form Element

    - by user322003
    Hi, I'm trying to create a custom form element which extends Zend_Form_Element_Text with a validator (so I don't have to keep setting up the validator when I use certain elements). Anyway, I'm having trouble passing $maxChars variable to it when I instantiate it in my Main form. I've provided my shortened code below This is my custom element below class My_Form_Custom_Element extends Zend_Form_Element_Text { public $maxChars public function init() { $this->addValidator('StringLength', true, array(0, $this->maxChars)) } public function setProperties($maxChars) { $this->maxChars= $maxChars; } } This is where I instantiate my custom form element. class My_Form_Abc extends Zend_Form { public function __construct($options = null) { parent::__construct($options); $this->setName('abc'); $customElement = new My_Form_Custom_Element('myCustomElement'); $customElement->setProperties(100); //**<----This is where i set the $maxChars** $submit = new Zend_Form_Element_Submit('submit'); $submit -> setAttrib('id', 'submitbutton'); $this->addElements(array($customElement ,$submit)); } } When I try to pass '100' using $customElement-setProperties(100) in my Form, it doesnt get passed properly to my StringLength validator. I assume it's because the validator is getting called in Init? How can I fix this?

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  • Automating Form Login

    - by Greg_Gutkin
    Introduction A common task in configuring a web application for proxying in Pagelet Producer is setting up form autologin. PP provides a wizard-like tool for detecting the login form fields, but this is usually only the first step in configuring this feature. If the generated configuration doesn't seem to work, some additional manual modifications will be needed to complete the setup. This article will try to guide you through this process while steering you away from common pitfalls. For the purposes of this article, let's assume the following characteristics about your environment: Web Application Base URL: http://host/app (configured as Resource Source URL in PP) Pagelet Producer Base URL: http://pp/pagelets Form Field Auto-Detection Form Autologin is configured in the PP Admin UI under resource_name/Autologin/Form Login. First, you'll enter the URL to the login form under "Login Form Identification". This will enable the admin wizard to connect to and display the login page. Caution: RedirectsMake sure the entered URL matches what you see in the browser's address bar, when the application login page is displayed. For example, even though you may be able to reach the login page by simply typing http://host/app, the URL you end up on may change to http://host/app/login via browser redirect(s).The second URL is the one you will want to use. Caution: External Login ServersThe login page may actually come from a different server than the application you are trying to proxy. For example, you may notice that the login page URL changes to http://hostB/appB. This is common when external SSO products are involved. There are two ways of dealing with this situation. One is to configure Pagelet Producer to participate in SSO. This approach is out of scope of this article and is discussed in a separate whitepaper (TODO add link). The second approach is to use the autologin feature to provide stored credentials to the SSO login form. Since the login form URL is not an extension of the application base URL (PP resource URL), you will need to add a new PP resource for the SSO server and configure the login form on that resource instead of the original application resource. One side benefit of this additional resource is that it can reused for other applications relying on the same SSO server for login. After entering the login page URL (make sure dropdown says "URL"), click "Automatically Detect Form Fields". This will bring up the web app's login page in a new browser window. Fill it out and submit it as you would normally. If everything goes right, Pagelet Producer will intercept the submitted values and fill out all the needed configuration data in the Admin UI. If the login form window doesn't close or configuration data doesn't get filled in, you may have not entered the login page URL correctly. Review the two cautionary notes above and make any necessary changes. If the form fields got filled automatically, it's time to save the configuration and test it out. If you can access a protected area of the backend application via a proxied PP URL without filling out its login form, then you are pretty much done with login form configuration. The only other step you will need to complete before declaring this aspect of configuration production ready is configuring form field source. You may skip to that section below. Manual Login Form Identification Let's take a closer look at Login Form Identification. This determines how Pagelet Producer recognizes login forms as such. URL The most efficient way of detecting login forms is by looking at the page URL. This method can only be used under the following conditions: Login page URL must be different from the post login application URLs. Login page URL must stay constant regardless of the path it takes to reach the page. For example, reaching the login page by going to the application base URL or to a specific protected URL must result in a redirect to the same login page URL (query string excluded). If only the query string parameters change, just leave out the query string from the configured login page URL. If either of these conditions is not fullfilled, you must switch to the RegEx approach below. RegEx If the login page URL is not uniform enough across all scenarios or is indistinguishable from other page locations, PP can be configured to recognize it by looking at the page markup itself. This is accomplished by changing the dropdown to "RegEx". If regular expressions scare you, take comfort from the fact that in most cases you won't need to enter any special regex characters. Let's look at an example: Say you have a login form that looks like <form id='loginForm' action='login?from=pageA' > <input id='user'> <input id='pass'> </form> Since this form has an id attribute, you can be reasonably sure that this login form can be uniquely identified across the web application by this snippet: "id='loginForm'". (Unless, of course your backend web application contains login forms to other apps). Since no wildcards are needed to find this snippet, you can just enter it as is into the RegEx field - no special regular expression characters needed! If the web developer who created the form wasn't kind enough to provide a unique id, you will need to look for other snippets of the page to uniquely identify it. It could be the action URL, an input field id, or some other markup fragment. You should abstain from using UI text as an identifier it may change in translated versions of the page and prevent the login page logic from working for international users. You may need to turn to regular expression wildcard syntax if no simple matches work. For more information on regular expression, refer to the Resources section. Form Submit Location Now we'll look at the form submit location. If the captured URL contains query string parameters that will likely change from one form submission to the next, you will need to change its type to RegEx. This type will tell Pagelet Producer to parse the login page for the action URL and submit to the value found. The regular expression needs to point at the actual action URL with its first grouping expression. Taking the example form definition above, the form submit location regex would be: action='(.*?)' The parentheses are used to identify the actual action URL, while the rest of the expression provides the context for finding it. Expression .*? is a so-called reluctant wildcard that matches any character excluding the single quote that follows. See Resources section below for further information on regular expressions. Manual Form Field Detection If the Admin UI form field detection wizard fails to populate login form configuration page, you will have to enter the fields by hand. Use a built-in browser developer tool or addon (e.g. Firebug) to inspect the form element and its children input elements. For each input element (including hidden elements), create an entry under Form Fields. Change its Source according to the next section. Form Field Source Change the source of any of the fields not exposed to the users of the login form (i.e. hidden fields) to "Generated". This means Pagelet Producer will just use the values returned by the web app rather than supplying values it stored. For fields that contain sensitive data or vary from user to user (e.g. username & password), change the source to User (Credential) Vault. Logging Support To help you troubleshoot you autologin configuration, PP provides some useful logging support. To turn on detailed logging for the autologin feature, navigate to Settings in Admin UI. Under Logging, change the log level for AutoLogin to Finest. Known Limitations Autologin feature may not work as expected if login form fields (not just the values, but the DOM elements themselves) are generated dynamically by client side JavaScript. Resources RegEx RegEx Reference from Java RegEx Test Tool

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  • C# resize all elements in form when resizing form

    - by vale4674
    NOTE: I can't put more than one hyperlink so i deleted letter "h" on begining of every link I have this image as the background of the form: ttp://img811.imageshack.us/img811/3347/31886905.jpg So my form looks like this: ttp://img823.imageshack.us/i/cisto.jpg/ When i resize it it looks like this: ttp://img820.imageshack.us/i/cistoumanjeno.jpg/ Now what I need to do is to put listeners on every rextangle like on the picture: ttp://img810.imageshack.us/img810/238/18887457.jpg I made transparent panels and put them on form to match the rectangles on the image (on image, panels are green so you can see where they are): ttp://img809.imageshack.us/i/paneli.jpg/ but when I resize the form it turns like this: ttp://img810.imageshack.us/i/paneliumanjeno.jpg/ anchor and dock properties don't work because they rely on parent container and here rectangles are on background image. QUESTION: I would like to do something like "relative-resize and position". Is that posible? So when I resize form, all the panels fits the rectangles on image.

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  • Javascript onunload form submit isn't submitting data

    - by Kevin
    I currently have form that checks if a user has unsubmitted changes when they leave the page with a function called through the onunload event. Here's the function: function saveOnExit() { var answer = confirm("You are about to leave the page. All unsaved work will be lost. Would you like to save now?"); if (answer) { document.main_form.submit(); } } And here's the form: <body onunload="saveOnExit()"> <form name="main_form" id="main_form" method="post" action="submit.php" onsubmit="saveScroll()"> <textarea name="comments"></textarea> <input type="submit" name="submit2" value="Submit!"/> </form> I'm not sure what I'm doing wrong here. The data gets submitted and saved in my database if I just press the submit button for the form. However, trying to submit the form through the onunload event doesn't result in anything being stored, from what I can tell. I've tried adding onclick alerts to the submitt button and onsubmit alerts to the form elements and I can verify that the submit button is being triggered and that the form does get submitted. However, nothing gets passed stored in the database. Any ideas as to what I'm doing wrong? Thanks.

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  • Saving a modified InfoPath form to its form library

    - by Nathan Lykken
    Within our corporate SharePoint 2007 site, there is a particular form library that contains 10 separate files. 9 of these are either Excel, Word, or PowerPoint files and one of these is an InfoPath 2007 form that serves as a report. After noticing an error within this InfoPath form, I saved this InfoPath form to my local directory and then, within the design mode of InfoPath, I modified this InfoPath form. What is the proper way to save this modified InfoPath form to its form library? Everything that I have tried results in nobody except myself having access to this modified InfoPath form. I can open this InfoPath form without error but when my coworkers try to open this InfoPath form on their machines, they receive this error: “The form cannot be opened because it requires the domain permission level and it currently has restricted permission. To fix this problem, open the form from the location it was published to."

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  • Table Decorators on Zend Framework Form

    - by ulduz114
    hello i created a form that it decorates as table form its my code for decorates $this->setElementDecorators(array( 'ViewHelper', 'Errors' array(array('data'=>'HtmlTag'), array('tag'=>'td','class'=>'element')), array('Label',array('tag'=>'td')), array(array('row'=>'HtmlTag'),array('tag'=>'tr')), )); $this->setDecorators(array( 'FormElements', array('HtmlTag',array('tag'=>'table')), 'Form' )); it works correctly, now i wana errors message decorates too what do i change my code?

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  • Access VBA sub with form as parameter doesn't alter the form

    - by Ski
    I have a Microsoft Access 2003 file with various tables of data. Each table also has a duplicate of it, with the name '[original table name]_working'. Depending on the user's choices in the switchboard, the form the user choose to view must switch its recordsource table to the working table. I refactored the relevant code to do such a thing into the following function today: Public Sub SetFormToWorking(ByRef frm As Form) With frm .RecordSource = rst![Argument] & "_working" .Requery Dim itm As Variant For Each itm In .Controls If TypeOf itm Is subForm Then With Item Dim childFields As Variant, masterFields As Variant childFields = .LinkChildFields masterFields = .LinkMasterFields .Form.RecordSource = .Form.RecordSource & "_working" .LinkChildFields = childFields .LinkMasterFields = masterFields .Form.Requery End With End If Next End With End Sub The lines of code that call the function look like this: SetFormToWorking Forms(rst![Argument]) and SetFormToWorking Forms(cmbTblList) For some reason, the above function doesn't change the recordsource for the form. I added the 'ByRef' keyword to the parameter just to be certain that it was passing by reference, but no dice. Hopefully someone here can tell me what I've done wrong?

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  • how to check if the enddate is after the startdate in a zend form

    - by murze
    I have a zend form with a start- and an endate. $form = new Zend_Form(); $form->setName($this->formName) ->setMethod('post'); $feStartdate = new Zend_Form_Element_Text('startdate'); $feEnddate = new Zend_Form_Element_Text('enddate'); $form->addElement($feStartDate) ->addElement($feEndDate) ->addElement('submit', 'submit', array('label' => 'Save')); I assume I must write a custom validator for to check this. How would this custom validator look like and how can I call it? I assume something like $feEnddate->addValidator('dateComesAfter', $feStartDate)

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  • Disable escape in Zend Form Element Submit

    - by Joaquín L. Robles
    I can't disable escaping in a Zend_Form_Element_Submit, so when the label has special characters it won't display it's value.. This is my actual Zend Form piece of code: $this->submit = new Zend_Form_Element_Submit('submit'); $this->submit->setLabel('Iniciar Sesión'); $this->submit->setIgnore(true); $this->addElement($this->submit); I've tried $this->submit->getDecorator('Label')->setOption('escape', false); but I obtain an "non-object" error (maybe submit isn't using the "Label" Decorator).. I've also tried as suggested $this->submit->setAttrib('escape', false); but no text will be shown either.. Any idea? Thanks

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  • Zend_Form : Adding fields in sub-forms on user's click

    - by anu iyer
    I'm having a zend form - comprised of a number of zend - sub forms, where the user is creating a new question (its a content management system). In one of the subforms, the user can click on a button to add more textfields, like this: [----------] [----------] [click to add more] which should give [----------] [----------] [----------] [click to add more] I'm trying to set a flag in the sub form in question - or set a count on how many times the button has been clicked, to add that many total fields to the subform - but its simply not working. I tried using a static count variable - but the value doesnt get incremented at all. Any thoughts on how to do this in a Zend-subform within a zend form? I'll definitely update if I hit a solution. Thanks!

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  • Form Validation Options

    The steps involved in transmitting form data from the client to the Web server User loads web form. User enters data in to web form fields User clicks submit On submit page validates fields using JavaScript. If validation errors are found then the validation script stops the browser from canceling posting the data to the web server and displays error messages as needed. If the form passes the data validation process then the browser will URL encode the values of every field and post it to the server.  The server reads the posted data from the query string and then again validates the data just to ensure data consistency and to prevent any non-validated data because JavaScript was turned off on the clients browser from being inserted in to a database or passed on to other process. If the data passes the second validation check then the server side code will continue with the requested processes. In my opinion, it is mandatory to validate data using client side and server side validation as a fail over process. The client side validation allows users to correct any error before they are sent to the web server for processing, and this allows for an immediate response back to the user regarding data that is not correct or in the proper format that is desired. In addition, this prevents unnecessary interaction between the user and the web server and will free up the server over time compared to doing only server side validation. Server validation is the last line of defense when it comes to validation because you can check to ensure the user’s data is correct before it is used in a business process or stored to a database. Honestly, I cannot foresee a scenario where I would only want to use one form of validation over another especially with the current cost of creating and maintaining data. In my opinion, the redundant validation is well worth the overhead.

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  • Auto submit form on clicking specific dropdown - jquery

    - by blasteralfred
    Hi, I have a form like below <form name="testform" id="testform" action="test.php" method="get"> <input name="field1" id="field1" type="text" value=""> <input name="field2" id="field2" type="text" value=""> <select name="dropdown" id="dropdown"> <option value="option1" selected="selected">option1</option> <option value="option2">option2</option> <option value="option3">option3</option> </select> <input type="submit" name="Submit" value="Submit" id="Submit"> </form> I want to submit the form automatically when someone click (or select) an option from the dropdown. How can I make this possible using jquery or something else or simple js. Thanks in advance... :) blasteralfred

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  • JSF submit dataTable and openpopup window after? is this possible?

    - by raimun
    Is it possible to just submit a dataTable instead of the entire form and then open a popupwindow after the submit? My dataTable has textboxes in it and the popup window is actually dependent on the data/values found in these textboxes. Since the user can change the values of the textboxes, I am required to get the latest values from the dataTables before the popup is opened. the popup is opened through a button found in each row of the datatable. i am using JSF2. thanks.

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  • Bypass django form validation on new form instance

    - by Thomas Schultz
    Hello! I have a situation where we are trying to autofill some form data on the second page of a signup and I was wondering if there's a way to bypass the entire form validation when we pass in only a couple of fields? so we have something like form = NewForm(request.POST) Where request.POST only contains some of the fields in NewForm(). So the page loads and there is feedback about how some fields are not filled in yet. This all happens from the GET request of the second page. Is there a way to do something like... form = NewForm(request.POST, validate=False)

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  • Display small form while main form is "locked"

    - by daemonsvk
    Hi there, i'm thinking about writing a WPF program that would require login and password at the app startup. I thought about small form with two textboxes as a login form. User will have to fill in his details and then the main form of the application will be unlocked. How will you solve this? Thanks for your answers, daemonsvk

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  • Creating form object for variable kind of form.

    - by Bunny Rabbit
    i want to create a form for users to submit questions in django ..so far the models i have created are class Question(models.Model): statement=models.CharField(max_length=100) class Choice(models.Model): statement=models.CharField(max_length=100) value=models.IntegerField() question=models.ForeignKey(Question) Now i want to write a Form class for creating a above form but the problem is the number of choices are variable,a user can decide how many choices a question must have .How do i do that in django?

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  • Handling form from different view and passing form validation through session in django

    - by Mo J. Mughrabi
    I have a requirement here to build a comment-like app in my django project, the app has a view to receive a submitted form process it and return the errors to where ever it came from. I finally managed to get it to work, but I have doubt for the way am using it might be wrong since am passing the entire validated form in the session. below is the code comment/templatetags/comment.py @register.inclusion_tag('comment/form.html', takes_context=True) def comment_form(context, model, object_id, next): """ comment_form() is responsible for rendering the comment form """ # clear sessions from variable incase it was found content_type = ContentType.objects.get_for_model(model) try: request = context['request'] if request.session.get('comment_form', False): form = CommentForm(request.session['comment_form']) form.fields['content_type'].initial = 15 form.fields['object_id'].initial = 2 form.fields['next'].initial = next else: form = CommentForm(initial={ 'content_type' : content_type.id, 'object_id' : object_id, 'next' : next }) except Exception as e: logging.error(str(e)) form = None return { 'form' : form } comment/view.py def save_comment(request): """ save_comment: """ if request.method == 'POST': # clear sessions from variable incase it was found if request.session.get('comment_form', False): del request.session['comment_form'] form = CommentForm(request.POST) if form.is_valid(): obj = form.save(commit=False) if request.user.is_authenticated(): obj.created_by = request.user obj.save() messages.info(request, _('Your comment has been posted.')) return redirect(form.data.get('next')) else: request.session['comment_form'] = request.POST return redirect(form.data.get('next')) else: raise Http404 the usage is by loading the template tag and firing {% comment_form article article.id article.get_absolute_url %} my doubt is if am doing the correct approach or not by passing the validated form to the session. Would that be a problem? security risk? performance issues? Please advise Update In response to Pol question. The reason why I went with this approach is because comment form is handled in a separate app. In my scenario, I render objects such as article and all I do is invoke the templatetag to render the form. What would be an alternative approach for my case? You also shared with me the django comment app, which am aware of but the client am working with requires a lot of complex work to be done in the comment app thats why am working on a new one.

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