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  • Class Assignment Operators

    - by Maxpm
    I made the following operator overloading test: #include <iostream> #include <string> using namespace std; class TestClass { string ClassName; public: TestClass(string Name) { ClassName = Name; cout << ClassName << " constructed." << endl; } ~TestClass() { cout << ClassName << " destructed." << endl; } void operator=(TestClass Other) { cout << ClassName << " in operator=" << endl; cout << "The address of the other class is " << &Other << "." << endl; } }; int main() { TestClass FirstInstance("FirstInstance"); TestClass SecondInstance("SecondInstance"); FirstInstance = SecondInstance; SecondInstance = FirstInstance; return 0; } The assignment operator behaves as-expected, outputting the address of the other class. Now, how would I actually assign something from the other class? For example, something like this: void operator=(TestClass Other) { ClassName = Other.ClassName; }

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  • Type casting Collections using Conversion Operators

    - by Vyas Bharghava
    The below code gives me User-defined conversion must convert to or from enclosing type, while snippet #2 doesn't... It seems that a user-defined conversion routine must convert to or from the class that contains the routine. What are my alternatives? Explicit operator as extension method? Anything else? public static explicit operator ObservableCollection<ViewModel>(ObservableCollection<Model> modelCollection) { var viewModelCollection = new ObservableCollection<ViewModel>(); foreach (var model in modelCollection) { viewModelCollection.Add(new ViewModel() { Model = model }); } return viewModelCollection; } Snippet #2 public static explicit operator ViewModel(Model model) { return new ViewModel() {Model = model}; } Thanks in advance!

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  • Shift Operators in C++

    - by Codeguru
    If the value after the shift operator is greater than the number of bits in the left-hand operand, the result is undefined. If the left-hand operand is unsigned, the right shift is a logical shift so the upper bits will be filled with zeros. If the left-hand operand is signed, the right shift may or may not be a logical shift (that is, the behavior is undefined). Can somebody explain me what the above lines mean??

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  • 'Object variable or With block variable not set' error when setting a range in VBA

    - by David Gard
    I have a function that creates a Pivot Table, but I am getting an error when I try to set a range that will be merged and have a title added to it. In the below code, pivot_title_range is a 'String' variable, and is optional when calling the funtion. title_range is a 'Range' variable. Both lines that set the range (whether or not the users declares pivot_title_range) cause the same error. If pivot_title_range = "" Then title_range = ActiveSheet.Range("B3:E4") Else title_range = ActiveSheet.Range(pivot_title_range) End If Here is the error that I am getting - Run-time error '91': Object variable or With block variable not set If required, here is a Pastebin of the full function - http://pastebin.com/L711jayc. The offending code starts on line 160. Is anybody able to tell me what I am doing wrong? Thanks.

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  • Am I immoral for using a variable name that differs from its type only by case?

    - by Jason Baker
    For instance, take this piece of code: var person = new Person(); or for you Pythonistas: person = Person() I'm told constantly how bad this is, but have yet to see an example of the immorality of these two lines of code. To me, person is a Person and trying to give it another name is a waste of time. I suppose in the days before syntax highlighting, this would have been a big deal. But these days, it's pretty easy to tell a type name apart from a variable name. Heck, it's even easy to see the difference here on SO. Or is there something I'm missing? If so, it would be helpful if you could provide an example of code that causes problems.

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  • What does "===" mean?

    - by Stefan Konno
    I recently studied some code that I'm supposed to use for different reasons, it's unrelevant. The thing I've noticed is someone using the operator "===" which I can't make sense out of. I've tried it with a function and it corresponds in crazy ways. The language is PHP by the way. Does anyone know what the definition of this operator is, I can't even find it in the declaration of php operators.

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  • Conversion constructor vs. conversion operator: precedence

    - by GRB
    Reading some questions here on SO about conversion operators and constructors got me thinking about the interaction between them, namely when there is an 'ambiguous' call. Consider the following code: class A; class B { public: B(){} B(const A&) //conversion constructor { cout << "called B's conversion constructor" << endl; } }; class A { public: operator B() //conversion operator { cout << "called A's conversion operator" << endl; return B(); } }; int main() { B b = A(); //what should be called here? apparently, A::operator B() return 0; } The above code displays "called A's conversion operator", meaning that the conversion operator is called as opposed to the constructor. If you remove/comment out the operator B() code from A, the compiler will happily switch over to using the constructor instead (with no other changes to the code). My questions are: Since the compiler doesn't consider B b = A(); to be an ambiguous call, there must be some type of precedence at work here. Where exactly is this precedence established? (a reference/quote from the C++ standard would be appreciated) From an object-oriented philosophical standpoint, is this the way the code should behave? Who knows more about how an A object should become a B object, A or B? According to C++, the answer is A -- is there anything in object-oriented practice that suggests this should be the case? To me personally, it would make sense either way, so I'm interested to know how the choice was made. Thanks in advance

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  • Safest way to change variable names in a project

    - by kamziro
    So I've been working on a relatively large project by myself, and I've come to realise that some of the variable names earlier on were.. less than ideal. But how does one change variable names in a project easily? Is there such a tool that can go through a project directory, parse all the files, and then replace the variable names to the desired one? It has to be smart enough to understand the language I imagine. I was thinking of using regexp (sed/awk on linux?) tools to just replace the variable name, but there were many times where my particular variable is also included as a part of strings. There's also the issue about changing stuff on a c++ namespace, because there is actually two classes in my project that share the same name, but are in different namespaces. I remember visual stuio being able to do this, but what's the safest and most elegant way to do this on linux?

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  • Javascript redeclared global variable overrides old value

    - by Yousuf Haider
    I ran into an interesting issue the other day and was wondering if someone could shed light on why this is happening. Here is what I am doing (for the purposes of this example I have dumbed down the example somewhat): I am creating a globally scoped variable using the square bracket notation and assigning it a value. Later I declare a var with the same name as the one I just created above. Note I am not assigning a value. Since this is a redeclaration of the same variable the old value should not be overriden as described here: http://www.w3schools.com/js/js_variables.asp //create global variable with square bracket notation window['y'] = 'old'; //redeclaration of the same variable var y; if (!y) y = 'new'; alert(y); //shows New instead of Old The problem is that the old value actually does get overriden and in the above eg. the alert shows 'new' instead of 'old'. Why ? I guess another way to state my question is how is the above code different in terms of semantics from the code below: //create global variable var y = 'old'; //redeclaration of the same variable var y; if (!y) y = 'new'; alert(y); //shows Old

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  • Uiimport does not save variable to base workspace

    - by Tim
    I tried using uiimport to load a file to the base workspace.....It worked first time....but after trying again after a while...I wasnt seeing the variable in the base work space. I used the default variable name which is given by 'uiimport". This was the command I used: uiimport(filename) And two variables where created by default..."data" and "textdata"(which is the header)....but now when i run it is no longer saved in the base workspace I do not want to assign a variable to the uiimport like so... K = uiimport(filename) assignin(base,'green',K) I do not want to do that because My dataset has a text header and the data itself, and doing this would assign both "textdata" and "data" to "green" variable How would I be able to get the dimensions of ONLY the "data" in green and how would I pass only "data"(which is in the green variable in the workspace.."rmbr"...the green variable holds both "data" and "textdata") to another function. I was able to do all this when the uiimport automatically saved the variables in the base workspace....but somehow now it doesn't. I would appreciate any help or tips on this matter

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  • variable in variable in batch and delayed expansion

    - by rezna
    Hi, I'm trying to use variable in variable in conjunction with delayed expansion but still no luck. SETLOCAL EnableDelayedExpansion SET ERROR_COMMAND=exit /B ^!ERRORLEVEL^! This is my last try. I want to setup an ERROR_COMMAND to be called when one of the steps in batch file crashes. The command is supposed to be: IF ERRORLEVEL 1 !ERROR_COMMAND! or IF ERRORLEVEL 1 %ERROR_COMMAND% The thing is, I'm not able to find out, how to SET properly the ERROR_COMMAND variable, so that ERRORLEVEL is not evaluated at the time of assignment, but at the time of evaluating the variable Of course I can copy&paste the code all over the batch file, but using the variable just seems a bit prettier... Anyone? Thanks, Milan

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  • How to get the original variable name of variable passed to a function

    - by Acorn
    Is it possible to get the original variable name of a variable passed to a function? E.g. foobar = "foo" def func(var): print var.origname So that: func(foobar) Returns: >>foobar EDIT: All I was trying to do was make a function like: def log(soup): f = open(varname+'.html', 'w') print >>f, soup.prettify() f.close() .. and have the function generate the filename from the name of the variable passed to it. I suppose if it's not possible I'll just have to pass the variable and the variable's name as a string each time.

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  • Using xsl:variable in a xsl:foreach select statment

    - by Nefariousity
    I'm trying to iterate through an xml document using xsl:foreach but I need the select=" " to be dynamic so I'm using a variable as the source. Here's what I've tried: ... <xsl:template name="SetDataPath"> <xsl:param name="Type" /> <xsl:variable name="Path_1">/Rating/Path1/*</xsl:variable> <xsl:variable name="Path_2">/Rating/Path2/*</xsl:variable> <xsl:if test="$Type='1'"> <xsl:value-of select="$Path_1"/> </xsl:if> <xsl:if test="$Type='2'"> <xsl:value-of select="$Path_2"/> </xsl:if> <xsl:template> ... <!-- Set Data Path according to Type --> <xsl:variable name="DataPath"> <xsl:call-template name="SetDataPath"> <xsl:with-param name="Type" select="/Rating/Type" /> </xsl:call-template> </xsl:variable> ... <xsl:for-each select="$DataPath"> ... The foreach threw an error stating: "XslTransformException - To use a result tree fragment in a path expression, first convert it to a node-set using the msxsl:node-set() function." When I use the msxsl:node-set() function though, my results are blank. I'm aware that I'm setting $DataPath to a string, but shouldn't the node-set() function be creating a node set from it? Am I missing something? When I don't use a variable: <xsl:for-each select="/Rating/Path1/*"> I get the proper results. Here's the XML data file I'm using: <Rating> <Type>1</Type> <Path1> <sarah> <dob>1-3-86</dob> <user>Sarah</user> </sarah> <joe> <dob>11-12-85</dob> <user>Joe</user> </joe> </Path1> <Path2> <jeff> <dob>11-3-84</dob> <user>Jeff</user> </jeff> <shawn> <dob>3-5-81</dob> <user>Shawn</user> </shawn> </Path2> </Rating> My question is simple, how do you run a foreach on 2 different paths?

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  • The EXCEPT and INTERSECT Operators in SQL Server

    The UNION, EXCEPT and INTERSECT operators of SQL enable you to combine more than one SELECT statement to form a single result set. Rob Sheldon explains all, with plenty of examples. Join SQL Backup’s 35,000+ customers to compress and strengthen your backups "SQL Backup will be a REAL boost to any DBA lucky enough to use it." Jonathan Allen. Download a free trial now.

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  • Bringing Alerts and Operators together with Notifications

    - by fatherjack
    I have covered SQL Server Alerts (Alerts are good, arent they?) on this blog before and I more recently did a post regarding Notifications (Are your Jobs talking to you) and how they should be configured. Now we need to check that these things are linked up so that when an Alert condition is met that you get the appropriate Notifications sent to Operators. Straight into the code we need and then a review of what it does ... DECLARE @ChosenOperator SYSNAME DECLARE @FailSafeOp TABLE ...(read more)

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