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  • apache sendmail: trying to change user "from" address from apache to domain account

    - by Wes
    I apologize if I am asking a question already answered, but my problem isn't really that I haven't found an answer. I have, in fact, found a half-dozen different "solutions" to my problem, tried them all, in various combinations, and have been consistently unsuccessful. The goal All I want to do is change the envelope "from" address for all email sent from [email protected] to [email protected], always. What I've already done I am running Apache, PHP, and sendmail on CentOS 5.5, [email protected]. We have an SMTP server at 192.168.0.4. The domain's email accounts are all at @domain.org. I have successfully set up "smart host" using this line in the sendmail.mc file: define(`SMART_HOST', `192.168.0.4')dnl Then I set up masquerading, and was hopeful this would solve it. I have this in the .mc file: FEATURE(`masquerade_entire_domain')dnl FEATURE(`masquerade_envelope')dnl FEATURE(`allmasquerade')dnl MASQUERADE_AS(`domain.org')dnl MASQUERADE_DOMAIN(`domain.org.')dnl MASQUERADE_DOMAIN(`localhost.localdomain.')dnl This rewrites "to" addresses, but not "from" addresses. Testing from the command line: sendmail -v [email protected] Always is shown from the local user (in this case root, or my local user account). I had read that "sendmail" command sometimes bypasses masquerading. Nevertheless, using the "mail" command has the same result. After that, I have explored several "solutions", including: mailertable virtusertable FEATURE(`accept_unresolvable_domains')dnl LOCAL_DOMAIN(`localhost.localdomain')dnl FEATURE(`genericstable')dnl /etc/mail/access file /etc/mail/local-host-names file /etc/mail/trusted-users file All to no affect. The last thing I've tried So, I decided to go in a different direction, and try to set the envelope "from" address via PHP, using either the configuration in /etc/php.ini, or adding the -f parameter to the mail() function or to sendmail command. If I run this command: sendmail -v -f [email protected] [email protected] I get this error in /var/log/maillog: Mar 30 08:56:16 localhost sendmail[24022]: p2UCuE8w024022: [email protected], size=5, class=0, nrcpts=1, msgid=<[email protected]>, relay=user@localhost Mar 30 08:56:19 localhost sendmail[24022]: p2UCuE8w024022: [email protected], [email protected] (500/502), delay=00:00:05, xdelay=00:00:03, mailer=relay, pri=30005, relay=[192.168.0.4] [192.168.0.4], dsn=5.1.1, stat=User unknown Mar 30 08:56:19 localhost sendmail[24022]: p2UCuE8w024022: p2UCuE8x024022: DSN: User unknown Mar 30 08:56:23 localhost sendmail[24022]: p2UCuE8x024022: [email protected], delay=00:00:04, xdelay=00:00:04, mailer=relay, pri=31029, relay=[192.168.0.4] [192.168.0.4], dsn=2.0.0, stat=Sent (Ok: queued as B5E2E40E0A2) Which is basically a "User unknown" 550 error. Help Please help. What do I need to change? Should I just start over in the sendmail.mc file? It has a ton of config options stuffed in it, over days of trying things. Why is changing the envelope "from" address via the command line generating a "User unknown" error?

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  • trouble shooting ntfs-loop-xen combination in wubi based grub of Ubuntu

    - by Registered User
    Here is a situation I installed Ubuntu on a laptop using Wubi in Windows 7 drive.*The laptop is not mine.*I have installed and things worked by now perfectly without any problem.We are trying to set up a Xen (virtualization)environment in this laptop. After setting up every thing cleanly.When I needed to boot with following grub entries menuentry "Xen Linux 2.6.32.27" { insmod ntfs set root='(hd0,2)' loopback loop0 /ubuntu/disks/root.disk set root=(loop0) multiboot /boot/xen.gz module /boot/vmlinuz-2.6.32.27 dummy=dummy root=/dev/sda2 loop=/ubuntu/disks/root.disk ro console=tty0 module /boot/initrd.img-2.6.32.27 } I got error file not found error unknown command 'multiboot' error unknown command 'module' error unknown command 'module' Now to dig this issue further I reboot the machine and go to grub command prompt and manually pass on each of the above parameters which you see in the grub entry when I reached grub> insmod multiboot then I got following message on screen error:file not found. It looks like this wubi+ grub setup has just enough modules to use loopback file on ntfs, but the ACTUAL /boot directory is on the loopback NOT ntfs (hd0,2). Therefore any attempt to read any files from (hd0,2) simply wont work, cause there's no file there.I need to use insmod multiboot and command multiboot and module which are available in grub on a normal install without Wubi.But since the laptop is not mine so I am not allowed to partition it and have to make it work in this situation only. While a normal Kernel is still booting? How can I get module multiboot in this Wubi based install.

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  • Windows: redirect stdout and stderror to nothing

    - by Ramblingwood
    I have a command I am running produces a ton of output, I want to silence the output without writing to a file. I have used the following to send all output to a file, but again I don't want any file output: command > out.txt 2>&1 I have used command > /bin/null on my CentOS box before, but I can't find a similar thing for windows.

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  • The great Vanishing Act of INetMgr.exe on my Windows 7 x64 system

    - by marc_s
    I'm facing an odd issue with the IIS Manager on Windows 7 (x64). At home, I have Win7 Professional, and when I check my IIS manager icon in the start menu, I see it links to %windir%\system32\inetsrv\InetMgr.exe When I launch this from the command line, it works like a charm. At work, however, I have Windows 7 Enterprise (x64), and when I check my link in the start menu, the entry is exactly the same. If I click on it - it works like a charm. Now if I'd like to launch it from the command line (cmd.exe or TakeCommand), however - the file just isn't there - a DIR %windir%\system32\inetsrv\*.exe shows a number of files, including a "inetmgr6.exe" - but no "inetmgr.exe" - and of course, I can't launch it either :-( Strangely enough, when I look at the directory %windir%\system32\INetSrv in Windows Explorer or Windows Powershell, I SEE the INetMgr.exe file and I can launch it - no problem. What the **** is going on here? How can I find the INetMgr.exe from my classic command line and launch it from there?? UPDATE: ok, some updates. On my work laptop, the INetMgr.exe file appears to really be located in a directory called c:\windows\syswow64\inetsrv (I'm recalling from memory, so don't quote me on the directory name - something like that). I can see this if I search for it in e.g. Powershell or Windows 7 Explorer. However, from a "classic" command line like cmd.exe, it appears to be in c:\windows\system32\inetsrv ..... hmmm.... trouble is - even though I now know where the file really is, I cannot access that directory from my classic command line - not even if I'm running cmd.exe as admin with elevated privileges....... so I know where the file is, but that still doesn't solve my problem :-(

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  • Correct MySQL username/password, but getting Access Denied error when run from script

    - by Nick
    I'm currently trying to run the following command from within a shell script. /usr/bin/mysql -u username -ppassword -h localhost database It works perfectly fine when executed manually, and not from within a script. When I try to execute a script that contains that command, I get the following error: ERROR 1045 (28000) at line 3: Access denied for user 'username'@'localhost' (using password: YES) I literally copied and pasted the working command into the script. Why the error? As a sidenote: the ultimate intent is to run the script with cron. EDIT: Here is a stripped down version of my script that I'm trying to run. You can ignore most of it up until the point where it connects to MySQL around line 19. #!/bin/sh #Run download script to download product data cd /home/dir/Scripts/Linux /bin/sh script1.sh #Run import script to import product data to MySQL cd /home/dir/Mysql /bin/sh script2.sh #Download inventory stats spreadsheet and rename it cd /home/dir /usr/bin/wget http://www.url.com/file1.txt mv file1.txt sheet1.csv #Remove existing export spreadsheet rm /tmp/sheet2.csv #Run MySQL queries in "here document" format /usr/bin/mysql -u username -ppassword -h localhost database << EOF --Drop old inventory stats table truncate table table_name1; --Load new inventory stats into table Load data local infile '/home/dir/sheet1.csv' into table table_name1 fields terminated by ',' optionally enclosed by '"' lines terminated by '\r\n'; --MySQL queries to combine product data and inventory stats here --Export combined data in spreadsheet format group by p.value into outfile '/tmp/sheet2.csv' fields terminated by ',' optionally enclosed by '"' lines terminated by '\r\n'; EOF EDIT 2: After some more testing, the issue is with the << EOF that is at the end of the command. This is there for the "here document". When removed, the command works fine. The problem is that I need << EOF there so that the MySQL queries will run.

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  • Can't update scala on Gentoo

    - by xhochy
    As I wanted to test Scala 2.9.2 on my gentoo system I tried updated the package but ended up with this error. I can't figure out where the problem may be: Calculating dependencies ...... done! >>> Verifying ebuild manifests >>> Jobs: 0 of 1 complete, 1 running Load avg: 0.23, 0.16, 0.20 >>> Emerging (1 of 1) dev-lang/scala-2.9.2 >>> Jobs: 0 of 1 complete, 1 running Load avg: 0.23, 0.16, 0.20 >>> Failed to emerge dev-lang/scala-2.9.2, Log file: >>> Jobs: 0 of 1 complete, 1 running Load avg: 0.23, 0.16, 0.20 >>> '/var/tmp/portage/dev-lang/scala-2.9.2/temp/build.log' >>> Jobs: 0 of 1 complete, 1 running Load avg: 0.23, 0.16, 0.20 >>> Jobs: 0 of 1 complete, 1 running, 1 failed Load avg: 0.23, 0.16, 0.20 >>> Jobs: 0 of 1 complete, 1 failed Load avg: 0.23, 0.16, 0.20 * Package: dev-lang/scala-2.9.2 * Repository: gentoo * Maintainer: [email protected] * USE: amd64 elibc_glibc kernel_linux multilib userland_GNU * FEATURES: sandbox [01m[31;06m!!! ERROR: Couldn't find suitable VM. Possible invalid dependency string. Due to jdk-with-com-sun requiring a target of 1.7 but the virtual machines constrained by virtual/jdk-1.6 and/or this package requiring virtual(s) jdk-with-com-sun[0m * Unable to determine VM for building from dependencies: NV_DEPEND: virtual/jdk:1.6 java-virtuals/jdk-with-com-sun !binary? ( dev-java/ant-contrib:0 ) app-arch/xz-utils >=dev-java/java-config-2.1.9-r1 source? ( app-arch/zip ) >=dev-java/ant-core-1.7.0 dev-java/ant-nodeps >=dev-java/javatoolkit-0.3.0-r2 >=dev-lang/python-2.4 * ERROR: dev-lang/scala-2.9.2 failed (setup phase): * Failed to determine VM for building. * * Call stack: * ebuild.sh, line 93: Called pkg_setup * scala-2.9.2.ebuild, line 43: Called java-pkg-2_pkg_setup * java-pkg-2.eclass, line 53: Called java-pkg_init * java-utils-2.eclass, line 2187: Called java-pkg_switch-vm * java-utils-2.eclass, line 2674: Called die * The specific snippet of code: * die "Failed to determine VM for building." * * If you need support, post the output of `emerge --info '=dev-lang/scala-2.9.2'`, * the complete build log and the output of `emerge -pqv '=dev-lang/scala-2.9.2'`. !!! When you file a bug report, please include the following information: GENTOO_VM= CLASSPATH="" JAVA_HOME="" JAVACFLAGS="" COMPILER="" and of course, the output of emerge --info * The complete build log is located at '/var/tmp/portage/dev-lang/scala-2.9.2/temp/build.log'. * The ebuild environment file is located at '/var/tmp/portage/dev-lang/scala-2.9.2/temp/die.env'. * Working directory: '/var/tmp/portage/dev-lang/scala-2.9.2' * S: '/var/tmp/portage/dev-lang/scala-2.9.2/work/scala-2.9.2-sources' * Messages for package dev-lang/scala-2.9.2: * Unable to determine VM for building from dependencies: * ERROR: dev-lang/scala-2.9.2 failed (setup phase): * Failed to determine VM for building. * * Call stack: * ebuild.sh, line 93: Called pkg_setup * scala-2.9.2.ebuild, line 43: Called java-pkg-2_pkg_setup * java-pkg-2.eclass, line 53: Called java-pkg_init * java-utils-2.eclass, line 2187: Called java-pkg_switch-vm * java-utils-2.eclass, line 2674: Called die * The specific snippet of code: * die "Failed to determine VM for building." * * If you need support, post the output of `emerge --info '=dev-lang/scala-2.9.2'`, * the complete build log and the output of `emerge -pqv '=dev-lang/scala-2.9.2'`. * The complete build log is located at '/var/tmp/portage/dev-lang/scala-2.9.2/temp/build.log'. * The ebuild environment file is located at '/var/tmp/portage/dev-lang/scala-2.9.2/temp/die.env'. * Working directory: '/var/tmp/portage/dev-lang/scala-2.9.2' * S: '/var/tmp/portage/dev-lang/scala-2.9.2/work/scala-2.9.2-sources' The following eix output may help: % eix java-virtuals/jdk-with-com-sun [I] java-virtuals/jdk-with-com-sun Available versions: 20111111 {{ELIBC="FreeBSD"}} Installed versions: 20111111(16:08:51 18/04/12)(ELIBC="-FreeBSD") Homepage: http://www.gentoo.org Description: Virtual ebuilds that require internal com.sun classes from a JDK Both virtual jdks 1.6 and 1.7 are installed: % eix virtual/jdk [I] virtual/jdk Available versions: (1.4) ~1.4.2-r1[1] (1.5) 1.5.0 ~1.5.0-r3[1] (1.6) 1.6.0 1.6.0-r1 (1.7) (~)1.7.0 Installed versions: 1.6.0-r1(1.6)(23:22:48 10/11/12) 1.7.0(1.7)(23:21:09 10/11/12) Description: Virtual for JDK [1] "java-overlay" /var/lib/layman/java-overlay

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  • Can not login Dashboard / Unable to find the server at mykeystoneurl

    - by neo0
    I installed Dashboard following this guide: http://wiki.openstack.org/OpenStackDashboard Everything fine, but when I run the server, I can not login with the username and password in DATABASE config in local_settings.py. Here's my config: DATABASES = { 'default': { 'ENGINE': 'django.db.backends.mysql', 'NAME': 'dashboarddb', 'USER': 'nova', 'PASSWORD': 'nova', 'HOST': 'localhost', 'default-character-set': 'utf8' }, } When I run the Dashboard server and enter username + password. It returned this error on browser: Unable to find the server at mykeystoneurl (HTTP 400) And in the command line: DEBUG:openstack_dashboard.settings:Running in debug mode without debug_toolbar. DEBUG:openstack_dashboard.settings:Running in debug mode without debug_toolbar. Validating models... 0 errors found Django version 1.3.1, using settings 'openstack_dashboard.settings' Development server is running at http://0.0.0.0:8888/ Quit the server with CONTROL-C. Request returned failure status. Traceback (most recent call last): File "/home/us/horizon/.venv/src/python-keystoneclient/keystoneclient/client.py", line 121, in request body = json.loads(body) File "/usr/lib/python2.7/json/__init__.py", line 326, in loads return _default_decoder.decode(s) File "/usr/lib/python2.7/json/decoder.py", line 366, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) File "/usr/lib/python2.7/json/decoder.py", line 384, in raw_decode raise ValueError("No JSON object could be decoded") ValueError: No JSON object could be decoded [06/Mar/2012 15:20:03] "POST /auth/login/ HTTP/1.1" 200 3735 I also tried login as "admin" with password is "password" or "secrete" but I didn't work. What's wrong? Thank you!

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  • Oracle Linux Tips and Tricks: Using SSH

    - by Robert Chase
    Out of all of the utilities available to systems administrators ssh is probably the most useful of them all. Not only does it allow you to log into systems securely, but it can also be used to copy files, tunnel IP traffic and run remote commands on distant servers. It’s truly the Swiss army knife of systems administration. Secure Shell, also known as ssh, was developed in 1995 by Tau Ylonen after the University of Technology in Finland suffered a password sniffing attack. Back then it was common to use tools like rcp, rsh, ftp and telnet to connect to systems and move files across the network. The main problem with these tools is they provide no security and transmitted data in plain text including sensitive login credentials. SSH provides this security by encrypting all traffic transmitted over the wire to protect from password sniffing attacks. One of the more common use cases involving SSH is found when using scp. Secure Copy (scp) transmits data between hosts using SSH and allows you to easily copy all types of files. The syntax for the scp command is: scp /pathlocal/filenamelocal remoteuser@remotehost:/pathremote/filenameremote In the following simple example, I move a file named myfile from the system test1 to the system test2. I am prompted to provide valid user credentials for the remote host before the transfer will proceed.  If I were only using ftp, this information would be unencrypted as it went across the wire.  However, because scp uses SSH, my user credentials and the file and its contents are confidential and remain secure throughout the transfer.  [user1@test1 ~]# scp /home/user1/myfile user1@test2:/home/user1user1@test2's password: myfile                                    100%    0     0.0KB/s   00:00 You can also use ssh to send network traffic and utilize the encryption built into ssh to protect traffic over the wire. This is known as an ssh tunnel. In order to utilize this feature, the server that you intend to connect to (the remote system) must have TCP forwarding enabled within the sshd configuraton. To enable TCP forwarding on the remote system, make sure AllowTCPForwarding is set to yes and enabled in the /etc/ssh/sshd_conf file: AllowTcpForwarding yes Once you have this configured, you can connect to the server and setup a local port which you can direct traffic to that will go over the secure tunnel. The following command will setup a tunnel on port 8989 on your local system. You can then redirect a web browser to use this local port, allowing the traffic to go through the encrypted tunnel to the remote system. It is important to select a local port that is not being used by a service and is not restricted by firewall rules.  In the following example the -D specifies a local dynamic application level port forwarding and the -N specifies not to execute a remote command.   ssh –D 8989 [email protected] -N You can also forward specific ports on both the local and remote host. The following example will setup a port forward on port 8080 and forward it to port 80 on the remote machine. ssh -L 8080:farwebserver.com:80 [email protected] You can even run remote commands via ssh which is quite useful for scripting or remote system administration tasks. The following example shows how to  log in remotely and execute the command ls –la in the home directory of the machine. Because ssh encrypts the traffic, the login credentials and output of the command are completely protected while they travel over the wire. [rchase@test1 ~]$ ssh rchase@test2 'ls -la'rchase@test2's password: total 24drwx------  2 rchase rchase 4096 Sep  6 15:17 .drwxr-xr-x. 3 root   root   4096 Sep  6 15:16 ..-rw-------  1 rchase rchase   12 Sep  6 15:17 .bash_history-rw-r--r--  1 rchase rchase   18 Dec 20  2012 .bash_logout-rw-r--r--  1 rchase rchase  176 Dec 20  2012 .bash_profile-rw-r--r--  1 rchase rchase  124 Dec 20  2012 .bashrc You can execute any command contained in the quotations marks as long as you have permission with the user account that you are using to log in. This can be very powerful and useful for collecting information for reports, remote controlling systems and performing systems administration tasks using shell scripts. To make your shell scripts even more useful and to automate logins you can use ssh keys for running commands remotely and securely without the need to enter a password. You can accomplish this with key based authentication. The first step in setting up key based authentication is to generate a public key for the system that you wish to log in from. In the following example you are generating a ssh key on a test system. In case you are wondering, this key was generated on a test VM that was destroyed after this article. [rchase@test1 .ssh]$ ssh-keygen -t rsaGenerating public/private rsa key pair.Enter file in which to save the key (/home/rchase/.ssh/id_rsa): Enter passphrase (empty for no passphrase): Enter same passphrase again: Your identification has been saved in /home/rchase/.ssh/id_rsa.Your public key has been saved in /home/rchase/.ssh/id_rsa.pub.The key fingerprint is:7a:8e:86:ef:59:70:ef:43:b7:ee:33:03:6e:6f:69:e8 rchase@test1The key's randomart image is:+--[ RSA 2048]----+|                 ||  . .            ||   o .           ||    . o o        ||   o o oS+       ||  +   o.= =      ||   o ..o.+ =     ||    . .+. =      ||     ...Eo       |+-----------------+ Now that you have the key generated on the local system you should to copy it to the target server into a temporary location. The user’s home directory is fine for this. [rchase@test1 .ssh]$ scp id_rsa.pub rchase@test2:/home/rchaserchase@test2's password: id_rsa.pub                  Now that the file has been copied to the server, you need to append it to the authorized_keys file. This should be appended to the end of the file in the event that there are other authorized keys on the system. [rchase@test2 ~]$ cat id_rsa.pub >> .ssh/authorized_keys Once the process is complete you are ready to login. Since you are using key based authentication you are not prompted for a password when logging into the system.   [rchase@test1 ~]$ ssh test2Last login: Fri Sep  6 17:42:02 2013 from test1 This makes it much easier to run remote commands. Here’s an example of the remote command from earlier. With no password it’s almost as if the command ran locally. [rchase@test1 ~]$ ssh test2 'ls -la'total 32drwx------  3 rchase rchase 4096 Sep  6 17:40 .drwxr-xr-x. 3 root   root   4096 Sep  6 15:16 ..-rw-------  1 rchase rchase   12 Sep  6 15:17 .bash_history-rw-r--r--  1 rchase rchase   18 Dec 20  2012 .bash_logout-rw-r--r--  1 rchase rchase  176 Dec 20  2012 .bash_profile-rw-r--r--  1 rchase rchase  124 Dec 20  2012 .bashrc As a security consideration it's important to note the permissions of .ssh and the authorized_keys file.  .ssh should be 700 and authorized_keys should be set to 600.  This prevents unauthorized access to ssh keys from other users on the system.   An even easier way to move keys back and forth is to use ssh-copy-id. Instead of copying the file and appending it manually to the authorized_keys file, ssh-copy-id does both steps at once for you.  Here’s an example of moving the same key using ssh-copy-id.The –i in the example is so that we can specify the path to the id file, which in this case is /home/rchase/.ssh/id_rsa.pub [rchase@test1]$ ssh-copy-id -i /home/rchase/.ssh/id_rsa.pub rchase@test2 One of the last tips that I will cover is the ssh config file. By using the ssh config file you can setup host aliases to make logins to hosts with odd ports or long hostnames much easier and simpler to remember. Here’s an example entry in our .ssh/config file. Host dev1 Hostname somereallylonghostname.somereallylongdomain.com Port 28372 User somereallylongusername12345678 Let’s compare the login process between the two. Which would you want to type and remember? ssh somereallylongusername12345678@ somereallylonghostname.somereallylongdomain.com –p 28372 ssh dev1 I hope you find these tips useful.  There are a number of tools used by system administrators to streamline processes and simplify workflows and whether you are new to Linux or a longtime user, I'm sure you will agree that SSH offers useful features that can be used every day.  Send me your comments and let us know the ways you  use SSH with Linux.  If you have other tools you would like to see covered in a similar post, send in your suggestions.

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  • Why does Alacarte give me this error when I try to add items to the menu?

    - by RichardoC
    When I try to add anything to the menu in 12.04 I get this error. $ alacarte Traceback (most recent call last): File "/usr/share/alacarte/Alacarte/MainWindow.py", line 317, in on_new_item_button_clicked process = subprocess.Popen(['gnome-desktop-item-edit', file_path], env=os.environ) File "/usr/lib/python2.7/subprocess.py", line 679, in __init__ errread, errwrite) File "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child raise child_exception OSError: [Errno 2] No such file or directory Thank you, R.C.

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  • Determine if the "yes" is necessary when doing an SCP

    - by glowcoder
    I'm writing a Groovy script to do an SCP. Note that I haven't ran it yet, because the rest of it isn't finished. Now, if you're doing an scp for the first time, have to authenticate the fingerprint. Future times, you don't. My current solution is, because I get 3 tries for the password, and I really only need 1 (it's not like the script will mistype the password... if it's wrong, it's wrong!) is to pipe in "yes" as the first password attempt. This way, it will accept the fingerprint if necessary, and use the correct password as the first attempt. If it didn't need it, it puts yes as the first attempt and the correct as the second. However, I feel this is not a very robust solution, and I know if I were a customer I would not like seeing "incorrect password" in my output. Especially if it fails for another reason, it would be an incredibly annoying misnomer. What follows is the appropriate section of the script in question. I am open to any tactics that involve using scp (or accomplishing the file transfer) in a different way. I just want to get the job done. I'm even open to shell scripting, although I'm not the best at it. def command = [] command.add('scp') command.add(srcusername + '@' + srcrepo + ':' + srcpath) command.add(tarusername + '@' + tarrepo + ':' + tarpath) def process = command.execute() process.consumeOutput(out) process << "yes" << LS << tarpassword << LS process << "yes" << LS << srcpassword << LS process.waitfor() Thanks so much, glowcoder

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  • Is the carriage-return char considered obsolete

    - by Evan Plaice
    I wrote an open source library that parses structured data but intentionally left out carriage-return detection because I don't see the point. It adds additional complexity and overhead for little/no benefit. To my surprise, a user submitted a bug where the parser wasn't working and I discovered the cause of the issue was that the data used CR line endings as opposed to LF or CRLF. Hasn't OSX been using LF style line-endings since switching over to a unix-based platform? I know there are applications like Notepad++ where line endings can be changed to use CR explicitly but I don't see why anybody would want to. Is it safe to exclude support for the statistically insignificant percentage of users who decide (for whatever reason) to the old Mac OS style line-endings?

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  • .desktop shortcuts aren't working for java applications in LXDE

    - by chaz
    I just installed minecraft on my LXDE desktop/Lubuntu machine and I'm trying to create a .desktop file on the desktop that executes java -jar ~/minecraftlauncher.jar. The command works in bash scripts and the terminal but refuses to work when I click on my .DESKTOP shortcut which is suppose to execute the same command. I've experimented with other jars and they can't seem to start too. Here is my xsession log: ** (pcmanfm:1572): DEBUG: launch command: <java -jar ~/Downloads/minecraft_server.jar> ** (pcmanfm:1572): DEBUG: sn_id = pcmanfm-1572-administrator-Dimension-3000-java-14_TIME14031891 Unable to access jarfile ~/Downloads/minecraft_server.jar ** (pcmanfm:1572): DEBUG: launch command: <java -jar ~/minecraftlauncher.jar> ** (pcmanfm:1572): DEBUG: sn_id = pcmanfm-1572-administrator-Dimension-3000-java-15_TIME14070158 Unable to access jarfile ~/minecraftlauncher.jar UPDATE: Whoops, it seems to work when I give an absolute path. I guess the home path is something else. UPDATE: I guess X doesn't resolve the home specifier. I ran a .desktop file that executed a script that outputs the current directory, and it seems to be correct.

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  • Where does the information shown by OS X Terminal 'Display all commands' feature come from?

    - by Sergio Acosta
    I just learned that if you hit and hold ESC while on the Mac Terminal, a prompt appears after a few seconds offering to show every command available on your system, including aliases, built-ins, and executables on your PATH. Soruce: http://www.mactricksandtips.com/2008/05/list-all-possible-terminal-commands.html However, the output is show through a more filter, and I cannot grep it or pipe it to another command. Does anyone know how this magic output is generated? Is it just generated on the fly by Terminal? Is there a bash command that can be called explicitly on the command line and get the same result? It is mostly curiosity, but I would love to be able to get the results as text I can post-process and not just browse on screen.

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  • Break free of a fullscreen app on MacOS X

    - by Petruza
    How do you break free of a fullscreen app on MacOS X? There are some, mostly games, that when they become unresponsive won't allow you to switch to another app with Command-Tab, and I know no other way to close that app or get away from it. Command-W or Command-Q won't work either. Is there a shortcut to launch Activity Monitor, or Terminal, to kill the application?

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  • Library order is important

    - by Darryl Gove
    I've written quite extensively about link ordering issues, but I've not discussed the interaction between archive libraries and shared libraries. So let's take a simple program that calls a maths library function: #include <math.h int main() { for (int i=0; i<10000000; i++) { sin(i); } } We compile and run it to get the following performance: bash-3.2$ cc -g -O fp.c -lm bash-3.2$ timex ./a.out real 6.06 user 6.04 sys 0.01 Now most people will have heard of the optimised maths library which is added by the flag -xlibmopt. This contains optimised versions of key mathematical functions, in this instance, using the library doubles performance: bash-3.2$ cc -g -O -xlibmopt fp.c -lm bash-3.2$ timex ./a.out real 2.70 user 2.69 sys 0.00 The optimised maths library is provided as an archive library (libmopt.a), and the driver adds it to the link line just before the maths library - this causes the linker to pick the definitions provided by the static library in preference to those provided by libm. We can see the processing by asking the compiler to print out the link line: bash-3.2$ cc -### -g -O -xlibmopt fp.c -lm /usr/ccs/bin/ld ... fp.o -lmopt -lm -o a.out... The flag to the linker is -lmopt, and this is placed before the -lm flag. So what happens when the -lm flag is in the wrong place on the command line: bash-3.2$ cc -g -O -xlibmopt -lm fp.c bash-3.2$ timex ./a.out real 6.02 user 6.01 sys 0.01 If the -lm flag is before the source file (or object file for that matter), we get the slower performance from the system maths library. Why's that? If we look at the link line we can see the following ordering: /usr/ccs/bin/ld ... -lmopt -lm fp.o -o a.out So the optimised maths library is still placed before the system maths library, but the object file is placed afterwards. This would be ok if the optimised maths library were a shared library, but it is not - instead it's an archive library, and archive library processing is different - as described in the linker and library guide: "The link-editor searches an archive only to resolve undefined or tentative external references that have previously been encountered." An archive library can only be used resolve symbols that are outstanding at that point in the link processing. When fp.o is placed before the libmopt.a archive library, then the linker has an unresolved symbol defined in fp.o, and it will search the archive library to resolve that symbol. If the archive library is placed before fp.o then there are no unresolved symbols at that point, and so the linker doesn't need to use the archive library. This is why libmopt needs to be placed after the object files on the link line. On the other hand if the linker has observed any shared libraries, then at any point these are checked for any unresolved symbols. The consequence of this is that once the linker "sees" libm it will resolve any symbols it can to that library, and it will not check the archive library to resolve them. This is why libmopt needs to be placed before libm on the link line. This leads to the following order for placing files on the link line: Object files Archive libraries Shared libraries If you use this order, then things will consistently get resolved to the archive libraries rather than to the shared libaries.

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  • How do I find out which process is eating up my bandwidth?

    - by Bruce Connor
    I think I'm being the victim of a bug here. Sometimes while I'm working (I still don't know why), my network traffic goes up to 200 KB/s and stays that way, even tough I'm not doing anything internet-related. This sometimes happens to me with the CPU usage. When it does, I just run a top command to find out which process is responsible and then kill it. Problem is: I have no way of knowing which process is responsible for my high network usage. Both the resource monitor and the top command only tell me my total network usage, neither of them tells me process specific network info. Is there another command I can use to find out which process is getting out of hand? I've already tried killing all the obvious ones (firefox, update-manager, pidgin, etc) with no luck. So far, restarting the machine is the only way I found of getting rid of the issue. EDIT: (just to be clear) I've found questions here about monitoring total bandwidth usage, but, as I mentioned, that's not what I need. UPDATE: The command iftop gives results that disagree entirely with the information reported by System Monitor. While the latter claims there's high network traffic, the former claims there's barely 1 KB/s. Thanks

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  • Any good reason open files in text mode?

    - by Tinctorius
    (Almost-)POSIX-compliant operating systems and Windows are known to distinguish between 'binary mode' and 'text mode' file I/O. While the former mode doesn't transform any data between the actual file or stream and the application, the latter 'translates' the contents to some standard format in a platform-specific manner: line endings are transparently translated to '\n' in C, and some platforms (CP/M, DOS and Windows) cut off a file when a byte with value 0x1A is found. These transformations seem a little useless to me. People share files between computers with different operating systems. Text mode would cause some data to be handled differently across some platforms, so when this matters, one would probably use binary mode instead. As an example: while Windows uses the sequence CR LF to end a line in text mode, UNIX text mode will not treat CR as part of the line ending sequence. Applications would have to filter that noise themselves. Older Mac versions only use CR in text mode as line endings, so neither UNIX nor Windows would understand its files. If this matters, a portable application would probably implement the parsing by itself instead of using text mode. Implementing newline interpretation in the parser might also remove some overhead of using text mode, as buffers would need to be rewritten (and possibly resized) before returning to the application, while this may be less efficient than when it would happen in the application instead. So, my question is: is there any good reason to still rely on the host OS to translate line endings and file truncation?

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  • How to configure sudoers to always keep LD_LIBRARY_PATH envrionment variable?

    - by Yanick Girouard
    No matter what I try, it seems that the LD_LIBRARY_PATH environment variable is not kept after I run a command with sudo. The only way I managed to have it stick, is to prefix my sudo command with LD_LIBRARY_PATH=/the/path whenever I call it from the command-line, but I would like to not have to do this every time. It seems the env_keep option ignores this variable, and so does the exempt_group option. My %group currently has ALL=(ALL) NOPASSWD:ALL as its access in sudoers. I would like this specific environment variable to be kept for any command I run. How can I do this? My server is running Red Hat Enterprise Linux 5.7.

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  • I am getting an error while writing my first app as shown in developer get-started tutorial

    - by TrickyJ
    I am trying to learn to develop apps in ubuntu and currently i am going through this tutorial. As shown in the video I am writing the below given codes: self.refreshbutton = self.builder.get_object("refreshbutton") def on_refreshbutton_clicked(self, widget): print "Refresh" As soon as I try to run my application it is giving me an error : I type this command to run my application : quickly run (trickybrowser:4418): Gtk-WARNING **: Theme parsing error: gtk-widgets.css:1971:11: Not using units is deprecated. Assuming 'px'. (trickybrowser:4418): Gtk-WARNING **: Failed to parse /usr/share/themes/mac-os-lion-theme-v2/gtk-3.0/settings.ini: Key file contains line '/* ' which is not a key-value pair, group, or comment Traceback (most recent call last): File "bin/trickybrowser", line 32, in <module> import trickybrowser File "/home/tricky/trickybrowser/trickybrowser/__init__.py", line 14, in <module> from trickybrowser import TrickybrowserWindow File "/home/tricky/trickybrowser/trickybrowser/TrickybrowserWindow.py", line 32 print "Refresh" ^ IndentationError: expected an indented block

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  • Can't get into the admin console after migrating to new server

    - by Emerson
    I migrated my WordPress blog to a new server, and everything seemed to be working fine until it started giving me the error when entering the admin area: Fatal error: Allowed memory size of 33554432 bytes exhausted (tried to allocate 4864 bytes) in /home/neworder/public_html/blog/wp-admin/includes/plugin.php on line 729 The line 729 has: $protected = array( '_wp_attached_file', '_wp_attachment_metadata', '_wp_old_slug', '_wp_page_template' ); I had installed the maintenance-mode, and I have suspicions that this is what broke the forum. If I remove the plugin it then gives another error: Fatal error: Allowed memory size of 33554432 bytes exhausted (tried to allocate 19456 bytes) in /home/neworder/public_html/blog/wp-admin/includes/post.php on line 1158 And that line has: $content .= '<p class="hide-if-no-js">' . esc_html__( 'Remove featured image' ) . '</p>'; } I tried to restore the blog file-system from the old server and also to restore the database from the old server (2x), but still it gives me the same error. The blog itself seems to be working fine: http://blog.antinovaordemmundial.com/

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  • "unresolvable problem" error when upgrading from 12.04 to 14.04

    - by flyingfisch
    So I have solved this issue, but now I have another problem: An unresolvable problem occurred while calculating the upgrade. This can be caused by: * Upgrading to a pre-release version of Ubuntu * Running the current pre-release version of Ubuntu * Unofficial software packages not provided by Ubuntu If none of this applies, then please report this bug using the command 'ubuntu-bug ubuntu-release-upgrader-core' in a terminal. I am not upgrading to a pre-release version of Ubuntu and I am not running a pre-release either. I have unchecked all my 3rd-party packages using Ubuntu Software Manager, EditSoftware Sources... What else might be wrong? UPDATE After doing sudo update-manager -d and sudo apt-get update;sudo apt-get dist-upgrade as per JimB's post, and then running sudo do-release-upgrade, here what I get: Err http://extras.ubuntu.com trusty/main Translation-en Err http://extras.ubuntu.com trusty/main Translation-en_US Err http://extras.ubuntu.com trusty/main Translation-en Ign http://extras.ubuntu.com trusty/main Translation-en_US Ign http://extras.ubuntu.com trusty/main Translation-en Fetched 0 B in 0s (0 B/s) Checking package manager Reading package lists... Done Building dependency tree Reading state information... Done Building data structures... Done Calculating the changes Calculating the changes Could not calculate the upgrade An unresolvable problem occurred while calculating the upgrade. This can be caused by: * Upgrading to a pre-release version of Ubuntu * Running the current pre-release version of Ubuntu * Unofficial software packages not provided by Ubuntu If none of this applies, then please report this bug using the command 'ubuntu-bug ubuntu-release-upgrader-core' in a terminal. Restoring original system state Aborting Reading package lists... Done Building dependency tree Reading state information... Done Building data structures... Done === Command detached from window (Mon Aug 18 23:53:10 2014) === === Command terminated with exit status 1 (Mon Aug 18 23:53:10 2014) ===

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  • Linux how to force quit the process by root

    - by Mirage
    I have run the command to backup 7 accounts and then i want to quit that command while its running. How can i quit from command line I want that it should quit backing up all accounts not just current account and then i have to press again untill all accounts open

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  • How to install Tor (Web Browser) in Ubuntu 12.10?

    - by Zignd
    I would like to install the Tor, but I'm having some problems. I know that someone will say "This question is a exactly duplication of How to install tor?", but it's not, because the another question can not be applied to Ubuntu 12.10 as the deb command is not available anymore. I did a research and even at the Tor's Official Website the available resource can not be applied to Ubuntu 12.10. I tried to use the deb command (as the above question says: deb http://deb.torproject.org/torproject.org <DISTRIBUTION> main) and the Terminal says deb: command not found and when I try to install it says E: Unable to locate package deb. I've also tried to use the ppa: ubun-tor, but it's not compatible with Quantal Quetzal, because it's too old. I've also tried to use sudo apt-get install tor, but browser icon don't shows up after installation and if you try to use the command tor in the Terminal I get the following error message: Nov 26 10:59:25.731 [notice] Tor v0.2.3.22-rc (git-4a0c70a817797420) running on Linux. Nov 26 10:59:25.731 [notice] Tor can't help you if you use it wrong! Learn how to be safe at https://www.torproject.org/download/download#warning Nov 26 10:59:25.731 [notice] Read configuration file "/etc/tor/torrc". Nov 26 10:59:25.737 [notice] Initialized libevent version 2.0.19-stable using method epoll (with changelist). Good. Nov 26 10:59:25.737 [notice] Opening Socks listener on 127.0.0.1:9050 Nov 26 10:59:25.737 [warn] Could not bind to 127.0.0.1:9050: Address already in use. Is Tor already running? Nov 26 10:59:25.737 [warn] Failed to parse/validate config: Failed to bind one of the listener ports. Nov 26 10:59:25.737 [err] Reading config failed--see warnings above. Thanks in advance.

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  • OpenGL ES 1 Pixel Error?

    - by Beginner001
    I am developing a game on android using OpenGL ES 1.0 for Android OS. It is a 2d game using a simple Orthographic projection and textures for the sprites. One of these textures has a small line (it looks like 1 pixel) all the way across the top that has the same colors as the bottom 1-pixel line of the texture. It is almost as if the bottom line of the image raster was copied and pasted as the top line as well. Is anyone familiar with this type of error? What could the problem be?

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