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  • How to build unlimited level of menu through PHP and mysql

    - by Starx
    Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu now there is not problem while creating submenu inside another submenu now this is way I fetch the submenu for the top menu <ul class="topmenu"> <? $list = $obj -> childmenu($parentid); //this list contains the array of submenu under $parendid foreach($list as $menu) { extract($menu); echo '<li><a href="#">'.$name.'</a></li>'; } ?> </ul> What I want to do is. I want to check if a new menu has other child menu and I want to keep on checking until it searches every child menu that is available and I want to display its child menu inside its particular list item like this Home ........

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  • php, sql selection

    - by cosy
    I have a stupid question, I have this table : id_product name value 1 price 10-20 1 type computer 2 price 20-30 3 price 100-200 and I want to select from this table GROUP BY id_product and ORDER BY value WHERE name='price' how can i do this? Thanks a lot

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  • How to use default arguments in php

    - by liysd
    I want to define a function doSomething(arg1, arg2) with default values to arg1=val and arg2=val When I write function doSomething($arg1="value1", $arg2="value2"){ // do something } Is it possible now to call doSomething with default arg1 and arg2="new_value2"

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  • rename folder into sub-folder with PHP

    - by Workoholic
    Hi. I'm trying to move a folder by renaming it. Both the test1 and test2 folders already exist. rename( "test1", "test2/xxx1/xxx2" ); The error I get is: rename(...): No such file or directory I assume this is because the directory "xxx1" does not exist. How can I move the test1 directory anyway?

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  • sorting a list of objects by value php

    - by Mike
    I have a list of objects: class Beer { var $name; var $id; var $style; var $brewery; var $rate; function getName() { return $this->name; } function getID() { return $this->id; } function getStyle() { return $this->style; } function getBrewery() { return $this->brewery; } function getRate() { return $this->rate; } } After doing some research online on how to accomplish this, this is my code: usort($localBeersList, "cmp"); function cmp($a, $b) { if ($a->getRate() == $b->getRate()) { return 0; } return ($a->getRate() < $b->getRate()) ? -1 : 1; } If I try and output my list after this I do not get anything.

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  • PHP/WordPress Session CountDown

    - by Cameron
    I have the following code to show how long a user has left before their session will expire, I am using WordPress. How can I do this? Thanks <script> var obj_Span; var n_Seconds = 0; var n_Minutes = 0; var n_Hours = 0; function F_ConvertNumberToString ( n_Num ) { var str_Num = String(n_Num); if ( str_Num.length < 2 ) str_Num = "0" + str_Num; return str_Num; } function F_CountDown () { if ( n_Hours == 0 && n_Minutes == 0 && n_Seconds == 0 ) { obj_Span.innerHTML = "(Sorry, your session has expired.)"; } else { if ( n_Seconds >= 0 ) n_Seconds --; if ( n_Seconds < 0 ) { n_Minutes --; n_Seconds = 59; } if ( n_Minutes >= 0 ) { window.setTimeout ( "F_CountDown()", 1000 ); } if ( n_Minutes < 0 ) { n_Hours --; n_Minutes = 59; window.setTimeout ( "F_CountDown()", 1000 ); } F_UpdateDisplay (); } } function F_UpdateDisplay ( ) { if ( document.getElementById ) { if (n_Hours > 0 ) obj_Span.innerHTML = "(Remaining " + F_ConvertNumberToString(n_Hours) + ":" + F_ConvertNumberToString(n_Minutes) + ":" + F_ConvertNumberToString(n_Seconds) + ")"; else obj_Span.innerHTML = "(Remaining " + F_ConvertNumberToString(n_Minutes) + ":" + F_ConvertNumberToString(n_Seconds) + ")"; } } function F_StartCountDown ( n_Session ) { obj_Span = document.getElementById ( "CountDown" ); n_Minutes = n_Session; n_Hours = Math.floor(n_Minutes/60); n_Minutes = n_Minutes - (60*n_Hours); F_CountDown (); } </script> <script> F_StartCountDown ( " code here... " ); </script> <span id="CountDown"></span>

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  • change last key name from array in php

    - by robertdd
    i want to be able to change the last key from array i try with this function i made: function getlastimage($newkey){ $arr = $_SESSION['files']; $oldkey = array_pop(array_keys($arr)); $arr[$newkey] = $arr[$oldkey]; unset($arr[$oldkey]); $results = end($arr); //echo json_encode($results); print_r($arr); } if i call the function getlastimage('newkey') it change the key!but after if i print the $_SESSION the key is not changed? why this?

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  • PHP MySQLi and MySQLi_STMT: Which insert_id to use?

    - by Carvell Fenton
    Hello all, Both the MySQLi and MySQLi_STMT classes have an $insert_id property. If I am connected to my database using a MySQLi object (say $db), and then I perform an INSERT with a MySQLi_STMT object (say $stmt), to get the id of the last INSERT, should I use: $last_id = $db->insert_id; or $last_id = $stmt->insert_id; Or would they be the same, in which case it doesn't matter? I thought this might be a quick answer for someone, and save me the time of writing the test code to check it. Thanks in advance as always.

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  • Exploding a String In PHP

    - by streetparade
    How do i explode this string '||25||34||73||94||116||128' i need to have a array like this array ( 0 => '25', 1 => '34', 2 => '73', 3 => '94', 4 => '116', 5 => '128' ) explode("||", $array); didnt work for me i get this array array ( 0 => '', 1 => '25', 2 => '34', 3 => '73', 4 => '94', 5 => '116', 6 => '128', )

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  • PHP search multidimensional array for value, then place that element at start of array

    - by BobFlemming
    I need to search this array: cars - [0] -make : Ford -model: Escort -year: 1991 [1] -make: Honda -model: Civic -year: 1996 [2] -make: Vauxhall -model: Astra -year: 1972 And if (for example) the model is "Civic" , place that 'car' at position 0. So the end array would be like: cars - [0] -make: Honda -model: Civic -year: 1996 [1] -make : Ford -model: Escort -year: 1991 [2] -make: Vauxhall -model: Astra -year: 1972 I've tried some usort variations: function typeSort($a, $b) { if ($a['model'] == 'Civic' ) { return 0; } return ($a['model'] < $b['model']) ? -1 : 1; } but this is just returning 1

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  • php Form to Email sanitizing

    - by Jacob
    Hi, im using the following to send a contact us type form, iv looked into security and only found that you need to protect the From: bit of the mail function, as ive hardcoded this does that mean the script is spamproof / un-hijackable $tenantname = $_POST['tenan']; $tenancyaddress = $_POST['tenancy']; $alternativename = $_POST['alternativ //and a few more //then striptags on each variable $to = "[email protected]"; $subject = "hardcoded subject here"; $message = "$tenantname etc rest of posted data"; $from = "[email protected]"; $headers = "From: $from"; mail($to,$subject,$message,$headers);

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  • Parallel CURL function Help .. php

    - by Webby
    Hello.. Firstly let me explain the code below is just a tiny snippet of the code I'm using on the working site. Basically I'm hoping someone can help me rewrite just the function below to enable parallel CURL calls... that way it will fit nicely into the existing code without me having to rewrite the whole from the ground up like some of the samples I've been finding today any ideas? function get_data($url) { $ch = curl_init(); $timeout = 5; curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,5); $data = curl_exec($ch); curl_close($ch); return $data; } p.s. $url goes through a huge bunch of urls in a loop already so I'd hole to keep that intact.. Help always appreciated and rewarded

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  • php paging and the use of limit clause

    - by Average Joe
    Imagine you got a 1m record table and you want to limit the search results down to say 10,000 and not more than that. So what do I use for that? Well, the answer is use the limit clause. example select recid from mytable order by recid asc limit 10000 This is going to give me the last 10,000 records entered into this table. So far no paging. But the limit phrase is already in use. That brings to question to the next level. What if I want to page thru this record particular record set 100 recs at a time? Since the limit phrase is already part of the original query, how do I use it again, this time to take care of the paging? If the org. query did not have a limit clause to begin with, I'd adjust it as limit 0,100 and then adjusting it as 100,100 and then 200,100 and so on while the paging takes it course. But at this time, I cannot. You almost think you'd want to use two limit phrases one after the other - which is not not gonna work. limit 10000 limit 0,1000 for sure it would error out. So what's the solution in this particular case?

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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  • PHP problem with die()

    - by ThinkingInBits
    So, I have this code: } else { $photograph_moderation = new PhotographModeration($this->photograph_id); $photograph_moderation->purgePhotograph(); //eventually take to an error page die('image is not big enough to upload'); } the purgePhotograph() function gets called properly when this condition is met, but the script never appears to die. Is there a reason why die wouldn't get called here? purgePhotograph() has no script killing commands either.

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  • PHP DOMElement, replacing text of a node

    - by waitinforatrain
    I have a HTML node like so: <b>Bold text</b> A variable $el contains a DOMElement reference to the text of that HTML node ("Bold text"), got from the XPath expression //b/text() I want to change the element to <b><span>Bold Text</span></b> So I tried: $span = $doc->createElement('span', "Bold Text"); $el->parentNode->replaceChild($span,, $el) which fails because parentNode is null. So, as a test, I tried: $el-insertBefore($span, $el); which throws no errors but produces no change in the output. Any thoughts?

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  • Adding rows to an array in PHP

    - by ChuckO
    I have loaded an associative array of records from a MySQL database table. The array consists of 1 to 7 rows representing one week of entries, which might not have been entered for each day. How can I insert blank rows into the array for the missing days so that I can easily display the data in a table? I don't need to update the database with the blanks.

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  • Organize array in PHP from mysql

    - by Matthew Carter
    Hi i have a social networking website. what i want it to do is pull out my friends status updates. basically what it does is i have a mysql query that pulls out all of my friends and in that while loop there is another mysql query that pulls out the status's from my friends. i want it to be in order of date but since its one while loop in another what it does is pull out all status's from friend 1 then 2 then 3 and not in order by date. i even tried ORDER BY DATE but that just ordered it by date within the friend.. my thought is that i could putt it all in an array and friends is one thing and the values is the stats. then just sort by values would this work and how could i do it. THANKS SO MUCH

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  • How to display MySQL Select statement results in PHP

    - by Vafello
    I have the following code and it should return just one value (id) from mysql table. The following code doesnt work. How can I output it without creating arrays and all this stuff, just a simple output of one value. $query = "SELECT id FROM users_entity WHERE username = 'Admin' "; $result = map_query($query); echo $result;

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  • PHP - Get dates of next 5 weekdays?

    - by Dan
    I'm trying to create an array of the next 5 working week days (Monday - Friday, excluding today). I know the working week varies around the world but this is not important for what I am trying to do. So, for example, if today is a Wednesday, I want the dates for Thursday and Friday of the current week and Monday, Tuesday and Wednesday of the following week. I thought this would work: $dates = array(); for ($i = 1; $ < 6; $i ++) { $dates[] = date('Y-m-d', strtotime('+ '.$i.' weekday')); } But for today, it is giving me: Monday 1st Tuesday 2nd Wednesday 3rd Thursday 4th Sunday 7th! Any advice appreciated. Thanks

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