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  • error: expected `;' before '{' token - What is the cause?

    - by melee
    Here is my implementation file: using namespace std; #include <iostream> #include <iomanip> #include <string> #include <stack> //line 5 #include "proj05.canvas.h" //----------------Constructor----------------// Canvas::Canvas() //line 10 { Title = ""; Nrow = 0; Ncol = 0; image[][100]; // line 15 position.r = 0; position.c = 0; } //-------------------Paint------------------// line 20 void Canvas::Paint(int R, int C, char Color) { cout << "Paint to be implemented" << endl; } The errors I'm getting are these: proj05.canvas.cpp: In function 'std::istream& operator>>(std::istream&, Canvas&)': proj05.canvas.cpp:11: error: expected `;' before '{' token proj05.canvas.cpp:22: error: a function-definition is not allowed here before '{' token proj05.canvas.cpp:24: error: expected `}' at end of input proj05.canvas.cpp:24: error: expected `}' at end of input These seem like simple syntax errors, but I am not sure what's wrong. Could someone decode these for me? I'd really appreciate it, thanks for your time! EDIT Here is the definition of Canvas in my .h file: #ifndef CANVAS_H #define CANVAS_H #include <iostream> #include <iomanip> #include <string> #include <stack> class Canvas { public: Canvas(); void Paint(int R, int C, char Color); const int Nrow; const int Ncol; string Title; int image[][100]; stack<int> path; struct PixelCoordinates { unsigned int r; unsigned int c; } position; }; #endif

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  • PHP: Fastest way possible to read contents of a file.

    - by SoLoGHoST
    Ok, I'm looking for the fastest possible way to read all of the contents of a file via php with a filepath on the server, also these files can be huge. So it's very important that it does a READ ONLY to it as fast as possible. Is reading it line by line faster than reading the entire contents? Though, I remember reading up on this some, that reading the entire contents can produce errors for huge files. Is this true?

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  • python tracing a segmentation fault

    - by pygabriel
    Hi, I'm developing C extensions from python ad I obtain some segfaults (inevitable during the development...). I'm searching a way to display at which line of code the segfault happens (an idea is like tracing every single line of code), how I can do that?

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  • ASP.Net MVC - Models and User Controls

    - by cdotlister
    Hi guys, I have a View with a Master Page. The user control makes use of a Model: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BudgieMoneySite.Models.SiteUserLoginModel>" %> This user control is shown on all screens (Part of the Master Page). If the user is logged in, it shows a certain text, and if the user isn't logged in, it offers a login box. That is working OK. Now, I am adding my first functional screen. So I created a new view... and, well, i generated the basic view code for me when I selected the controller method, and said 'Create View'. My Controller has this code: public ActionResult Transactions() { List<AccountTransactionDetails> trans = GetTransactions(); return View(trans); } private List<AccountTransactionDetails> GetTransactions() { List<AccountTransactionDto> trans = Services.TransactionServices.GetTransactions(); List<AccountTransactionDetails> reply = new List<AccountTransactionDetails>(); foreach(var t in trans) { AccountTransactionDetails a = new AccountTransactionDetails(); foreach (var line in a.Transactions) { AccountTransactionLine l = new AccountTransactionLine(); l.Amount = line.Amount; l.SubCategory = line.SubCategory; l.SubCategoryId = line.SubCategoryId; a.Transactions.Add(l); } reply.Add(a); } return reply; } So, my view was generated with this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Collections.Generic.List<BudgieMoneySite.Models.AccountTransactionDetails>>" %> Found <%=Model.Count() % Transactions. All I want to show for now is the number of records I will be displaying. When I run it, I get an error: "The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BudgieMoneySite.Models.AccountTransactionDetails]', but this dictionary requires a model item of type 'BudgieMoneySite.Models.SiteUserLoginModel'." It looks like the user control is being rendered first, and as the Model from the controller is my List<, it's breaking! What am I doing wrong?

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  • Is there any C/C++ editor in Linux that shows errors while typing

    - by MetallicPriest
    The Visual C++ editor has a great feature which is that it underlines errors with a red line while typing the code. So for example, if you are using a variable that is not declared, it will underline it with a red curly line. In this way, the programmer can resolve a lot of errors while typing and doesn't have to wait for compiling for noticing them. Now my question is, is there any editor for Linux that has this great feature?

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  • Problem with Free SMTP Server in php code

    - by Nuha
    I wrote php code for use to contact us form but I can not find free SMTP server to use it. I Try to use SMTP Server For Gmail but I found this error. Warning: mail() [function.mail]: "sendmail_from" not set in php.ini or custom "From:" header missing in C:\www\htdocs\contactUs.php on line 25" line 25 is : mail ($to,$subject,$body,$headers); statement that indicate using Gmail SMTP Server is : ini_set("SMTP","smtp.gmail.com"); SO,can U help me ?:(

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  • javascript error: variable is not defined

    - by Hristo
    to is not defined [Break on this error] setTimeout('updateChat(from, to)', 1); I'm getting this error... I'm using Firebug to test and this comes up in the Console. The error corresponds to line 71 of chat.js and the whole function that wraps this line is: function updateChat(from, to) { $.ajax({ type: "POST", url: "process.php", data: { 'function': 'getFromDB', 'from': from, 'to': to }, dataType: "json", cache: false, success: function(data) { if (data.text != null) { for (var i = 0; i < data.text.length; i++) { $('#chat-box').append($("<p>"+ data.text[i] +"</p>")); } document.getElementById('chat-box').scrollTop = document.getElementById('chat-box').scrollHeight; } instanse = false; state = data.state; setTimeout('updateChat(from, to)', 1); // gives error }, }); } This links to process.php with function call getFromDB and the code for that is: case ('getFromDB'): // get the sender and receiver user IDs from their user names $from = mysql_real_escape_string($_POST['from']); $query = "SELECT `user_id` FROM `Users` WHERE `user_name` = '$from' LIMIT 1"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_assoc($result); $fromID = $row['user_id']; $to = mysql_real_escape_string($_POST['to']); $query = "SELECT `user_id` FROM `Users` WHERE `user_name` = '$to' LIMIT 1"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_assoc($result); $toID = $row['user_id']; $query = "SELECT * FROM `Messages` WHERE `from_id` = '$fromID' AND `to_id` = '$toID' LIMIT 1"; $result = mysql_query($query); while($row = mysql_fetch_assoc($result)) { $text[] = $line = $row['message']; $log['text'] = $text; } break; So I'm confused with the line that is giving the error. setTimeout('updateChat(from,to)',1); aren't the parameters to updateChat the same parameters that came into the function? Or are they being pulled in from somewhere else and I have to define to and from else where? Any ideas how to fix this error? Thanks, Hristo

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  • Detect main class

    - by Daniel
    Hoe can I detect the main class of my application? The one, which is either given on the command line or loaded from the jar given at the command line? If this is not possible, why not?

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  • Cocoa - Change text of label

    - by Nick
    I've got a cocoa application that reads in a text file. I'd like to display that text in a multi-line label, but I for the life of me can't figure it out. I opened up my .nib file and poped a multi-line label down but after that I'm stuck. I don't have any experience working with XCode or Cocoa, mostly Eclipse, Visual Studio, and pretty much every other IDE except XCode which seems very foreign.

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  • What's the "Find Result" Control Visual Studio Integrated?

    - by Nano HE
    Hi, I am developing a simple Windows Application in C# and Visual Studio 2005. I need a search result control - just like visual studio integrated by itself. After I double click each line to trigger the individual event. I tried multi-line textBox Control, but whole the box can only support one click event. thank you.

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  • add_without_safety create new DB entry in controller

    - by Karl Entwistle
    Im trying to get a controller to create a new account with the user id filled in, this doesn't work in my controller or in the console, why? Any suggestions on how to implement this would be much appreciated. class PaymentNotification < ActiveRecord::Base after_create :add_account_to_market private def add_account_to_market if status == "Completed" line = LineItem.find(:first, :conditions => { :cart_id => cart.id }) line.quantity.times do Account.new(:user_id => cart.user_id) end end end end

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  • Update Params in Python During Infinite Loop

    - by python Dude
    Hello, I was hoping to get some help on a question. I have an infinite loop that I need run and I need to update a set of variables (x in this case) at random times from the command-line. Is there any way to do this? For example: x = 0 while True: x = x + 1 if x < 30: do something and I need to update x's value from the command-line periodically

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  • Alligning a multiline li in an ul

    - by user146780
    I have two li (points) on this page http://animactions.ca/Animactions/le_developpement_des_equipes_de_travail.php that take up two lines. I'm not sure how to properly align them so that they line up with the first line. I'm referring to this point: Renforcir la cohésion et l’esprit d’équipe pour un travail proactif et durable qui génère des rendements supérieurs. Thanks

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  • Getting source code information from groovy stack trace

    - by dotsid
    When exception generated I want to show some additional information (source code) for particular exception. But grails have very hairy exceptions (it's all about groovy dynamic nature). It's my problem where to get and how to display source code. All I need is file/line information. So... Is there any possibility to get file and line where exception were generated in grails/groovy?

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  • How to create "floating TextViews" in Android?

    - by Sotapanna
    Hi stackies, I'm programmatically putting various TextViews into a LinearLayout with a horizontal orientation. After 2h of research I couldn't find out how to tell Android not to squeeze all the TextViews in one line but instead to "float" non-fitting TextViews into the next line. I know there isn't something like actual "lines" in a LinearLayout, but how can I tell the TextViews to actually behave like floating DIVs from the HTML world? Thanks alot! Be well S.

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  • reading input file from server and displaying output on client side

    - by tazim
    Hi, I have to read a file from server side . Obtained its contents stored it in a list and sent it to template Now, My question is how to access this list so as to display the contents of files line by line . I am using ajax and jquery to obtain the data on client side def showfiledata(request): f = open("/home/tazim/webexample/test.txt") list = f.readlines() return_dict = {'list':list} json = simplejson.dumps(list) return HttpResponse(json,mimetype="application/json")

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  • XCode C++ source code print issue on Mac

    - by George2
    Hello everyone, I am using MacBook Pro Mac OS 10.5 with related version of XCode. I am new to this development environment. I am developing C++ console/terminal applications (File-New project, then from the list on the left "Command line utility", and on the right "C++ tool".). For C++ source code file, I want to print source file content with line number. Any ideas how to do this? thanks in advance, George

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  • VBA: Validate List settings

    - by stanigator
    Sub Macro1() ' ' Macro1 Macro ' ' Worksheets("Drop-down").Select For i = 1 To 10 ActiveSheet.Cells(i, 2).Select With Selection.Validation .Delete ' Error in this line .Add Type:=xlValidateList, AlertStyle:=xlValidAlertStop, Operator:= _ xlBetween, Formula1:=Range(Worksheets("Misc").Cells(2, i), Worksheets("Misc").Cells(2, i).End) .IgnoreBlank = True .InCellDropdown = True .InputTitle = "" .ErrorTitle = "" .InputMessage = "" .ErrorMessage = "" .ShowInput = True .ShowError = True End With Next i End Sub I'm getting an error in the line below the comment, yet I don't know how to fix it. It would be great to hear some suggestions. Thanks in advance!

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  • Displaying individual elements of an object in an Arraylist through a for loop?

    - by user1180888
    I'm trying to Display individual elements of an Object I have created. It is a simple Java program that allows users to add and keep track of Player Details. I'm just stumped when it comes to displaying the details after they have been added already. here is what my code looks like I can create the object and input it into the arraylist no problem using the case 2, but when I try to print it out I want to do something like System.out.println("Player Name" + myPlayersArrayList.PlayerName + "Player Position" + myPlayerArrayList.PlayerPosition + "Player Age" + "Player Age"); I know that is not correct, but I dont really know what to do, if anyone can be of any help it would be greatly appreciated. Thanks System.out.println("Welcome to the Football Player database"); System.out.print(System.getProperty("line.separator")); UserInput myFirstUserInput = new UserInput(); int selection; ArrayList<Player> myPlayersArrayList = new ArrayList<Player>(); while (true) { System.out.println("1. View The Players"); System.out.println("2. Add A Player"); System.out.println("3. Edit A Player"); System.out.println("4. Delete A Player"); System.out.println("5. Exit ") ; System.out.print(System.getProperty("line.separator")); selection = myFirstUserInput.getInt("Please select an option"); System.out.print(System.getProperty("line.separator")); switch(selection){ case 1: if (myPlayersArrayList.isEmpty()) { System.out.println("No Players Have Been Entered Yet"); System.out.print(System.getProperty("line.separator")); break;} else {for(int i = 0; i < myPlayersArrayList.size(); i++){ System.out.println(myPlayersArrayList); } break; case 2: { String playerName,playerPos; int playerAge; playerName = (myFirstUserInput.getString("Enter Player name")); playerPos = (myFirstUserInput.getString("Enter Player Position")); playerAge = (myFirstUserInput.getInt("Enter Player Age")); myPlayersArrayList.add(new Player(playerName, playerPos, playerAge)); ; break; }

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