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  • SQL for total count and count within that where condition is true

    - by twmulloy
    Hello, I have a single user table and I'm trying to come up with a query that returns the total count of all users grouped by date along with the total count of users grouped by date who are of a specific client. Here is what I have thus far, where there's the total count of users grouped by date, but can't seem to figure out how to get the count of those users where user.client_id = x SELECT user.created, COUNT(user.id) AS overall_count FROM user GROUP BY DATE(user.created) trying for a row result like this: [created] => 2010-05-15 19:59:30 [overall_count] => 10 [client_count] => (some fraction of overall count, the number of users where user.client_id = x grouped by date)

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  • inserting array into database table in single query

    - by Praveen Prasad
    iam having an array of items like [item1,itmem2,item3]; i have to insert these items at a particular userId: final results look like this UserId ItemId 2 || item1 2 || item2 2 || item3 currently iam looping through the array in php code and inserting each item one by one eg foreach($items as $item) { insert into items (UserId,ItemId) value (2,$item); } is it possible i can insert all entries in single query.

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  • Parsing CSV File to MySQL DB in PHP

    - by Austin
    I have a some 350-lined CSV File with all sorts of vendors that fall into Clothes, Tools, Entertainment, etc.. categories. Using the following code I have been able to print out my CSV File. <?php $fp = fopen('promo_catalog_expanded.csv', 'r'); echo '<tr><td>'; echo implode('</td><td>', fgetcsv($fp, 4096, ',')); echo '</td></tr>'; while(!feof($fp)) { list($cat, $var, $name, $var2, $web, $var3, $phone,$var4, $kw,$var5, $desc) = fgetcsv($fp, 4096); echo '<tr><td>'; echo $cat. '</td><td>' . $name . '</td><td><a href="http://www.' . $web .'" target="_blank">' .$web.'</a></td><td>'.$phone.'</td><td>'.$kw.'</td><td>'.$desc.'</td>' ; echo '</td></tr>'; } fclose($file_handle); show_source(__FILE__); ?> First thing you will probably notice is the extraneous vars within the list(). this is because of how the excel spreadsheet/csv file: Category,,Company Name,,Website,,Phone,,Keywords,,Description ,,,,,,,,,, Clothes,,4imprint,,4imprint.com,,877-466-7746,,"polos, jackets, coats, workwear, sweatshirts, hoodies, long sleeve, pullovers, t-shirts, tees, tshirts,",,An embroidery and apparel company based in Wisconsin. ,,Apollo Embroidery,,apolloemb.com,,1-800-982-2146,,"hats, caps, headwear, bags, totes, backpacks, blankets, embroidery",,An embroidery sales company based in California. One thing to note is that the last line starts with two commas as it is also listed within "Clothes" category. My concern is that I am going about the CSV output wrong. Should I be using a foreach loop instead of this list way? Should I first get rid of any unnecessary blank columns? Please advise any flaws you may find, improvements I can use so I can be ready to import this data to a MySQL DB.

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  • Perl like regular expression in Oracle DB

    - by user13136722
    There's regular expression support in Oracle DB Using Regular Expressions in Database Applications Oracle SQL PERL-Influenced Extensions to POSIX Standard But '\b' is not supported which I believe is quite wideliy used in perl and/or other tools perlre - perldoc.perl.org \b Match a word boundary So, I experimented with '\W' which is non-"word" character When combined with beginning-of-line and end-of-line like below, I think it works exactly the same as '\b' SELECT * FROM TAB1 WHERE regexp_like(TEXTCOL1, '(^|\W)a_word($|\W)', 'i')

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  • Optimising (My)SQL Query

    - by Simon
    I usually use ORM instead of SQL and I am slightly out of touch on the different JOINs... SELECT `order_invoice`.*, `client`.*, `order_product`.*, SUM(product.cost) as net FROM `order_invoice` LEFT JOIN `client` ON order_invoice.client_id = client.client_id LEFT JOIN `order_product` ON order_invoice.invoice_id = order_product.invoice_id LEFT JOIN `product` ON order_product.product_id = product.product_id WHERE (order_invoice.date_created >= '2009-01-01') AND (order_invoice.date_created <= '2009-02-01') GROUP BY `order_invoice`.`invoice_id` The tables/ columns are logically names... it's an shop type application... the query works... it's just very very slow... I use the Zend Framework and would usually use Zend_Db_Table_Row::find(Parent|Dependent)Row(set)('TableClass') but I have to make lots of joins and I thought it'll improve performance by doing it all in one query instead of hundreds... Can I improve the above query by using more appropriate JOINs or a different implementation? Many thanks.

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  • Java: Making concurrent MySQL queries from multiple clients synchronised

    - by Misha Gale
    I work at a gaming cybercafe, and we've got a system here (smartlaunch) which keeps track of game licenses. I've written a program which interfaces with this system (actually, with it's backend MySQL database). The program is meant to be run on a client PC and (1) query the database to select an unused license from the pool available, then (2) mark this license as in use by the client PC. The problem is, I've got a concurrency bug. The program is meant to be launched simultaneously on multiple machines, and when this happens, some machines often try and acquire the same license. I think that this is because steps (1) and (2) are not synchronised, i.e. one program determines that license #5 is available and selects it, but before it can mark #5 as in use another copy of the program on another PC tries to grab that same license. I've tried to solve this problem by using transactions and table locking, but it doesn't seem to make any difference - Am I doing this right? Here follows the code in question: public LicenseKey Acquire() throws SmartLaunchException, SQLException { Connection conn = SmartLaunchDB.getConnection(); int PCID = SmartLaunchDB.getCurrentPCID(); conn.createStatement().execute("LOCK TABLE `licensekeys` WRITE"); String sql = "SELECT * FROM `licensekeys` WHERE `InUseByPC` = 0 AND LicenseSetupID = ? ORDER BY `ID` DESC LIMIT 1"; PreparedStatement statement = conn.prepareStatement(sql); statement.setInt(1, this.id); ResultSet results = statement.executeQuery(); if (results.next()) { int licenseID = results.getInt("ID"); sql = "UPDATE `licensekeys` SET `InUseByPC` = ? WHERE `ID` = ?"; statement = conn.prepareStatement(sql); statement.setInt(1, PCID); statement.setInt(2, licenseID); statement.executeUpdate(); statement.close(); conn.commit(); conn.createStatement().execute("UNLOCK TABLES"); return new LicenseKey(results.getInt("ID"), this, results.getString("LicenseKey"), results.getInt("LicenseKeyType")); } else { throw new SmartLaunchException("All licenses of type " + this.name + "are in use"); } }

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  • Help with SQL query (Calculate a ratio between two entitiess)

    - by Mestika
    Hi, I’m going to calculate a ratio between two entities but are having some trouble with the query. The principal is the same to, say a forum, where you say: A user gets points for every new thread. Then, calculate the ratio of points for the number of threads. Example: User A has 300 points. User A has started 6 thread. The point ratio is: 50:6 My schemas look as following: student(studentid, name, class, major) course(courseid, coursename, department) courseoffering(courseid, semester, year, instructor) faculty(name, office, salary) gradereport(studentid, courseid, semester, year, grade) The relations is a following: Faculity(name) = courseoffering(instructor) Student(studentid) = gradereport (studentid) Courseoffering(courseid) = course(courseid) Gradereport(courseid) = courseoffering(courseid) I have this query to select the faculty names there is teaching one or more students: SELECT COUNT(faculty.name) FROM faculty, courseoffering, gradereport, student WHERE faculty.name = courseoffering.instructor AND courseoffering.courseid = gradereport.courseid AND gradereport.studentid = student.studentid My problem is to find the ratio between the faculty members salary in regarding to the number of students they are teaching. Say, a teacher get 10.000 in salary and teaches 5 students, then his ratio should be 1:5. I hope that someone has an answer to my problem and understand what I'm having trouble with. Thanks Mestika

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  • Customers Go On Record About Oracle ERP and HCM Cloud Services

    - by Kathryn Perry
    Listen to these Oracle customers from Red Robin, Herbalife, LendingClub, and Cricket.talk about how they're using Oracle ERP and HCM Cloud Services. Collectively they're driving cost savings, managing global, fast paced growth, automating processes, implementing quickly in the cloud, and much more. Here's the video link: http://www.youtube.com/user/FusionAppsAtOracle

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  • how to tackle a custom forms database

    - by Neil Hickman
    I'm currently researching a project for the place that I work in. We are trying to create a system that will allow forms to be set up dynamically from a database. My question is what database structure would best suit something like this? I currently have a structure of: forms_form forms_formfields forms_formdata I don't think this is the most appropriate layout for this. Basically to make is make sense I need to be able to make a form within the database that can have infinite fields all customized and have the data when submitted stored in the database.

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  • It's Alive!

    - by Oracle OpenWorld Blog Team
    See what leading-edge, provocative, and fascinating new content will be featured at Oracle OpenWorld in 2012. by Karen Shamban It’s what you’ve been waiting for. The Oracle OpenWorld Content Catalog—the central repository for information on sessions, demos, labs, user groups, exhibitors, and more—is live. Right now. In the Content Catalog you can search on tracks, session types, session categories, keywords, and tags. Or, you can search for your favorite speakers to see what they’re presenting this year. And, directly from the catalog, you can share sessions you’re interested in with friends and colleagues through a broad array of social media channels. Start checking out Oracle OpenWorld content now to plan your week at the conference. Then you’ll be ready to sign up for all of your sessions in mid-July when the scheduling tool goes live. Thinking of cross-registering for JavaOne? The JavaOne Content Catalog is also live at this very minute so you can see what great content is on offer there.

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  • READ_ME_FIRST: What Do I Do All of Those SPARC Threads?

    - by user12608550
    New Oracle Technical White Paper: READ_ME_FIRST: What Do I Do All of Those SPARC Threads? Executive Overview With an amazing 1,536 threads in an Oracle M5-32 system, the number of threads in a single system has never been so high. This offers a tremendous processing capacity, but one may wonder how to make optimal use of all these resources. In this technical white paper, we explain how the heavily threaded Oracle T5 and M5 servers can be deployed to efficiently consolidate and manage workloads using virtualization through Oracle Solaris Zones, Oracle VM Server for SPARC, and Oracle Enterprise Manager Ops Center, as well as how to improve the performance of a single application through multi-threading. READ_ME_FIRST: What Do I Do All of Those SPARC Threads?

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  • How can get unique values from data table using dql?

    - by piemesons
    I am having a table in which there is a column in which various values are stored.i want to retrieve unique values from that table using dql. Doctrine_Query::create() ->select('rec.school') ->from('Records rec') ->where("rec.city='$city' ") ->execute(); Now i want only unique values. Can anybody tell me how to do that... Edit Table Structure: CREATE TABLE IF NOT EXISTS `records` ( `id` int(11) NOT NULL AUTO_INCREMENT, `state` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL, `city` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL, `school` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=16334 ; This is the Query I am using: Doctrine_Query::create() ->select('DISTINCT rec.city') ->from('Records rec') ->where("rec.state = '$state'") // ->getSql(); ->execute(); Generting Sql for this gives me: SELECT DISTINCT r.id AS r__id, r.city AS r__city FROM records r WHERE r.state = 'AR' Now check the sql generated:::: DISTINCT is on 'id' column where as i want Distinct on city column. Anybody know how to fix this. EDIT2 Id is unique cause its an auto incremental value.Ya i have some real duplicates in city column like: Delhi and Delhi. Right.. Now when i am trying to fetch data from it, I am getting Delhi two times. How can i make query like this: select DISTINCT rec.city where state="xyz"; Cause this will give me the proper output. EDIT3: Anybody who can tell me how to figure out this query..???

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  • How do I re-create a MySQL InnoDB table from an .ibd file?

    - by knorv
    Assume that the following MySQL files have been restored from a backup tape: tablename.frm tablename.ibd Furthermore, assume that the MySQL installation was running with innodb_file_per_table and that the database was cleanly shutdown with mysqladmin shutdown. Given a fresh install of the same MySQL version that the restored MySQL files were taken from, how do I import the data from tablename.ibd/tablename.frm into this new install?

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  • What's New in the latest release of Oracle User Productivity Kit 11.0

    Enterprises are always looking to reduce overall project timelines, optimize business processes, and increase acceptance of their enterprise applications to ensure maximum ROI. The latest release of Oracle User Productivity Kit helps customers streamline the workflow process for the creation of content and offers conceptual-based assessment options to increase user adoption. Discover what is great and innovative about the latest release of Oracle UPK and UPK Professional. Learn about the integration of the UPK Developer and the Knowledge Center, which provides developers with a centralized, web-based platform for content deployment, tracking, and reporting.

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  • ASP.Net / MySQL : Translating content into several languages

    - by philwilks
    I have an ASP.Net website which uses a MySQL database for the back end. The website is an English e-commerce system, and we are looking at the possibility of translating it into about five other languages (French, Spanish etc). We will be getting human translators to perform the translation - we've looked at automated services but these aren't good enough. The static text on the site (e.g. headings, buttons etc) can easily be served up in multiple languages via .Net's built in localization features (resx files etc). The thing that I'm not so sure about it how best to store and retrieve the multi-language content in the database. For example, there is a products table that includes these fields... productId (int) categoryId (int) title (varchar) summary (varchar) description (text) features (text) The title, summary, description and features text would need to be available in all the different languages. Here are the two options that I've come up with... Create additional field for each language For example we could have titleEn, titleFr, titleEs etc for all the languages, and repeat this for all text columns. We would then adapt our code to use the appropriate field depending on the language selected. This feels a bit hacky, and also would lead to some very large tables. Also, if we wanted to add additional languages in the future it would be time consuming to add even more columns. Use a lookup table We could create a new table with the following format... textId | languageId | content ------------------------------- 10 | EN | Car 10 | FR | Voiture 10 | ES | Coche 11 | EN | Bike 11 | FR | Vélo We'd then adapt our products table to reference the appropriate textId for the title, summary, description and features instead of having the text stored in the product table. This seems much more elegant, but I can't think of a simple way of getting this data out of the database and onto the page without using complex SQL statements. Of course adding new languages in the future would be very simple compared to the previous option. I'd be very grateful for any suggestions about the best way to achieve this! Is there any "best practice" guidance out there? Has anyone done this before?

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  • Oracle Virtual Compute Appliance (OVCA) Launch Channel Update Webcast - May 28

    - by Giuseppe Facchetti
    Join us for an Oracle Virtual Compute Appliance (OVCA) launch update for the channel.This training webcast is a follow up to the OVCA launch on April 16. We will provide a brief product overview of OVCA followed by some great OPN program content, resell criteria, OPN Incentive Program and Demo Equipment Program details. There will be two sessions to accommodate each region. Additionally, don't miss the latest Oracle Virtual Compute Appliance article packed with great information!

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  • Need help with a SELECT statement

    - by Travis
    I express the relationship between records and searchtags that can be attached to records like so: TABLE RECORDS id name TABLE SEARCHTAGS id recordid name I want to be able to SELECT records based on the searchtags that they have. For example, I want to be able to SELECT all records that have searchtags: (1 OR 2 OR 5) AND (6 OR 7) AND (10) Using the above data structure, I am uncertain how to structure the SQL to accomplish this. Any suggestions? Thanks!

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  • $query returns results but not the ones i want: $query looks good to me :S

    - by Toni Michel Caubet
    I'll start again, Lets say My data is: Table element (id,name,....) 1, name element 1, .... 2, name element 2, .... 3, name element 3, .... Table tags (id,name,id_element, ....) 1, happy , 1 2, result, 1 3, very , 1 4, element, 2 5, another, 3 6, element, 1 7, happy, 2 So if search is 'very, happy,element,result': Results i would like 1) element with id = 2 because it has all tags 2) element with id = 1 because it has the tag 'element' and the tag 'happy' (only 2 less taggs) 3) .... (only 3 less taggs) So if search is 'happy,element': Results i would like 1) element with id = 1 because it has all tags (and no more) 2) element with id = 2 because it has the tag 'element' and the tag 'happy' (and two more tags) 3) .... and 3 more tags This is an echo to my query: (it doesn't fit al requirements i wrote, but its first test to find with matched tags) SELECT element.id as id_deseada,tagg.* FROM element,tagg WHERE tagg.id_element = element.id AND tagg.nombre IN ('happy','tagg','result') GROUP BY tagg.id_element ORDER BY element.votos This returns 10 duplicated elements... :S and doen't even have all taggs (and on database there are taggs with 'happy' results) if it helps, thats how i get the elements of a tag (by name and with only one tagg) $query = "SELECT element.id FROM element,tagg WHERE tagg.nombre = '$nombre_tagg' AND tagg.id_element = element.id AND lan = '$lan' GROUP BY tagg.id_element"; I hope it's a bit easier to understand now, excuse my english.. :) Thanks a lot for you possible aportation!

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  • How can i rewrite this query for faster execution

    - by sam
    SELECT s1.ID FROM binventory_ostemp s1 JOIN ( SELECT Cust_FkId, ProcessID, MAX(Service_Duration) AS duration FROM binventory_ostemp WHERE ProcessID='4d2d6068678bc' AND Overall_Rank IN ( SELECT MIN(Overall_Rank) FROM binventory_ostemp WHERE ProcessID='4d2d6068678bc' GROUP BY Cust_FkId ) GROUP BY Cust_FkId ) AS s2 ON s1.Cust_FkId = s2.Cust_FkId AND s1.ProcessID=s2.ProcessID AND s1.Service_Duration=s2.duration AND s1.ProcessID='4d2d6068678bc' GROUP BY s1.Cust_FkId It just goes away if there are more than 10K rows in that table. What it does is find rows for each customer who has min. of overall rank and in those max. of service duration for a given processid Table Data ID Cust_FkId Overall_Rank Service_Duration ProcessID 1 23 2 30 4d2d6068678bc 2 23 1 45 4d2d6068678bc 3 23 1 60 4d2d6068678bc 4 56 3 90 4d2d6068678bc 5 56 2 50 4d2d6068678bc 6 56 2 85 4d2d6068678bc

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  • How to create wordpress-like option table and get values for each row?

    - by Nacho
    Hi guys. I'm looking to create an options table in my db that makes every record a system option, so I can work with a little number of fields. My db has the following structure: 3 columns named id, name, and value The following data is inserted as an example: +--+-----------+--------------------------+ |id|name |value | +--+-----------+--------------------------+ | 1|uri |www.example.com | | 2|sitename |Working it out | | 3|base_folder|/folder1/folder2/ | | 4|slogan |Just a slogan for the site| +--+-----------+--------------------------+ That way I can include a large number of customizable system options very easily. The problem is that I don't know how to retrieve them. How do I get the value of uri and store it as a var? And better yet, how do I get, for exmaple, values of id 1 and 4 only without making a query each time? (I assume multiple queries are useless and a pretty ugly method.) I know the question is pretty basic but I'm lost here. I'd really appreciate your answer!

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  • Table alias -- Unkown column in field list

    - by Jason
    Hi all, I have a sql query which is executing a LEFT JOIN on 2 tables in which some of the columns are ambiguous. I can prefix the joined tables but when I try to prefix one of the columns from the table in the FROM clause, it tells me Unknown column. I even tried giving that table an alias like so ...From points AS p and using "p" to prefix the tables but that didn't work either. Can someone tell me what I'm doing wrong. Here is my query: SELECT point_title, point_url, address, city, state, zip_code, phone, `points`.`lat`, `points`.`longi`, featured, kmlno, image_url, category.title, category_id, point_id, lat, longi, reviews.star_points, reviews.review_id, count(reviews.point_id) as totals FROM (SELECT *, ( 3959 * acos( cos( radians('37.7717185') ) * cos( radians( lat ) ) * cos( radians( longi ) - radians('-122.4438929') ) + sin( radians('37.7717185') ) * sin( radians( lat ) ) ) ) AS distance FROM points HAVING distance < '25') as distResults LEFT JOIN category USING ( category_id ) LEFT JOIN reviews USING ( point_id ) WHERE (point_title LIKE '%Playgrounds%' OR category.title LIKE '%Playgrounds%') GROUP BY point_id ORDER BY totals DESC, distance LIMIT 0 , 10

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