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  • Evaluate column value into rows

    - by Hugo Palma
    I have a column whose value is a json array. For example: [{"att1": "1", "att2": "2"}, {"att1": "3", "att2": "4"}, {"att1": "5", "att2": "6"}] What i would like is to provide a view where each element of the json array is transformed into a row and the attributes of each json object into columns. Keep in mind that the json array doesn't have a fixed size. Any ideas on how i can achieve this ?

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  • SQL Query to select upcoming events with a start and end date

    - by Chris T
    I need to display upcoming events from a database. The problem is when I use the query I'm currently using any events with a start day that has passed will show up lower on the list of upcoming events regardless of the fact that they are current My table (yaml): columns: title: type: string(255) notnull: true default: Untitled Event start_time: type: time end_time: type: time start_day: type: date notnull: true end_day: type: date description: type: string(500) default: This event has no description category_id: integer My query (doctrine): $results = Doctrine_Query::create() ->from("sfEventItem e, e.Category c") ->select("e.title, e.start_day, e.description, e.category_id, e.slug") ->addSelect("c.title, c.slug") ->orderBy("e.start_day, e.start_time, e.title") ->limit(5) ->execute(array(), Doctrine_Core::HYDRATE_ARRAY); Basically I'd like any events that is currently going on (so if today is in between start_day and end_day) to be at the top of the list. How would I go about doing this if it's even possible? Raw sql queries are good answers too because they're pretty easy to turn into DQL.

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  • Substitute Items on Internal Sales Orders

    - by ChristineS-Oracle
    Oracle Order Management now enables you to substitute items on internal sales order lines to manage item availability.  Oracle Order Management enables you to substitute items on internal sales order lines to manage item availability. Source organizations can decide to ship a substitute item in case the original item is not available to be shipped. The application supports manual (using Related Items window) and automatic (using ATP functionality) substitutions.To substitute an item on ISO, you must ensure that the value of the Item Substitution on Internal Order system parameter is set to a value other than None. In addition, you must ensure to define substitute item relationships and automatic item substitution setup in the system. The application provides the option to not send the notifications when any change happens on the ISO related to quantity, schedule arrival date, or item. You can control these notifications using the OM: Send Notifications of Internal Order Change profile option. For additional information refer to the Oracle Order Management Release Notes for Release 12.2.4 (Doc ID 1906521.1).

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  • October 2012 Security "Critical Patch Update" (CPU) information and downloads released

    - by user12244672
    The October 2012 security "Critical Patch Update" information and downloads are now available from My Oracle Support (MOS). See http://www.oracle.com/technetwork/topics/security/alerts-086861.html and in particular Document 1475188.1 on My Oracle Support (MOS), http://support.oracle.com, which includes security CVE mappings for Oracle Sun products. For Solaris 11, Doc 1475188.1 points to the relevant SRUs containing the fixes for each issue.  SRU12.4 was released on the CPU date and contains the current cumulative security fixes for the Solaris 11 OS. For Solaris 10, we take a copy of the Recommended Solaris OS patchset containing the relevant security fixes and rename it as the October CPU patchset on MOS.  See link provided from Doc 1475188.1 Doc 1475188.1 also contains references for Firmware, etc., and links to other useful security documentation, including information on Userland/FOSS vulnerabilities and fixes in https://blogs.oracle.com/sunsecurity/

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  • SQL Selecting from one table OR another then joining the two

    - by Cyprus106
    So this is interesting, and apparently beyond my SQL skillset. I need to select a particular record where an ID="0003" (or whatever) from either table1 or table2 if table1 doesn't have that record. Then I need to join table1 and table2 on a mutual field they both have (field name is Product_ID) I was playing with all sorts of variations of the following, (no, it doesn't work) but after 2 days of groping through the internet and a big SQL book I still can't figure anything out. SELECT ProductStock.Product_ID AS PSID, Products.ID AS PID, ProductStock.*, Products.* FROM ProductStock, Products LEFT JOIN (Products AS Pr) ON Pr.ID=ProductStock.Product_ID WHERE (ProductStock.ID="6003" OR Products.ID="6003")

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  • Query to find all bars that sell three different beers at the same price

    - by Eternal Learner
    Query to find "All bars that sell three different beers at the same price?" My Tables are Sells(bar,beer,price) - bar - foreign Key.. Bars(name,addr) - name primary key. I thought of something like this but that dosent seem to work ... Select A.bar As bar , B.bar as bar From Sells AS A, Sells AS B Where A.bar = B.bar and A.beer <> B.beer Group By(A.beer) Having Count(Distinct A.beer) >= 2 Is this the correct SQL query ?

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  • writting an sql query

    - by Praveen Prasad
    iam having 2 tables table Items Table (this table holds all items iam having) itemId --------- Item1 Item2 Item3 Item4 Item5 table 2 users_item relation UserId || ItemId 1 || Item1 1 || Item2 userId one has stored 2 items Item1,Item2. Now i want to write a query on table1 (Items table) so that it displays all items which user1 has NOT chosen.

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  • Transforming your Business with Oracle Consulting

    Stephan Scholl Senior Vice President, North America Consulting talks about the role that the 11,000+ professionals in Oracle Consulting play in helping customers transform their businesses and reap the benefits of the latest releases on their Oracle solutions.

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  • Need MYSQL query for finding lowest score per game player

    - by Chris Barnhill
    I have a game on Facebook called Rails Across Europe. I have a Best Scores page where I show the players with the best 20 scores, which in game terms refers to the lowest winning turn. The problem is that there are a small number of players who play frequently, and their scores dominate the page. I'd like to make the scores page open to more players. So I thought that I could display the single lowest winning turn for each player instead of displaying all of the lowest winning turns for all players. The problem is that the query for this eludes me. So I hope that one of you brilliant StackOverflow folks can help me with this. I have included the relevant MYSQL table schemas below. Here are the the table relationships: player_stats contains statistics for either a game in progress or a completed game. If a game is in progress, winning_turn is zero (which means that games with a winning_turn of zero should not be included in the query). player_stats has a game_player table id reference. game_player contains data describing games currently in progress. game_player has a player table id reference. player contains data describing a person who plays the game. Here's the query I'm currently using: 'SELECT p.fb_user_id, ps.winning_turn, gp.difficulty_level, c.name as city_name, g.name as goods_name, d.cost FROM game_player as gp, player as p, player_stats as ps, demand as d, city as c, goods as g WHERE p.status = "ACTIVE" AND gp.player_id = p.id AND ps.game_player_id = gp.id AND d.id = ps.highest_demand_id AND c.id = d.city_id AND g.id = d.goods_id AND ps.winning_turn > 0 ORDER BY ps.winning_turn ASC, d.cost DESC LIMIT '.$limit.';'; Here are the relevant table schemas: -- -- Table structure for table `player_stats` -- CREATE TABLE IF NOT EXISTS `player_stats` ( `id` int(11) NOT NULL auto_increment, `game_player_id` int(11) NOT NULL, `winning_turn` int(11) NOT NULL, `highest_demand_id` int(11) NOT NULL, PRIMARY KEY (`id`), KEY `game_player_id` (`game_player_id`,`highest_demand_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `game_player` -- CREATE TABLE IF NOT EXISTS `game_player` ( `id` int(10) unsigned NOT NULL auto_increment, `game_id` int(10) unsigned NOT NULL, `player_id` int(10) unsigned NOT NULL, `player_number` int(11) NOT NULL, `funds` int(10) unsigned NOT NULL, `turn` int(10) unsigned NOT NULL, `difficulty_level` enum('STANDARD','ADVANCED','MASTER','ULTIMATE') NOT NULL, `date_last_used` datetime NOT NULL, PRIMARY KEY (`id`), KEY `game_id` (`game_id`,`player_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `player` -- CREATE TABLE IF NOT EXISTS `player` ( `id` int(11) NOT NULL auto_increment, `fb_user_id` char(255) NOT NULL, `fb_proxied_email` text NOT NULL, `first_name` char(255) NOT NULL, `last_name` char(255) NOT NULL, `birthdate` date NOT NULL, `date_registered` datetime NOT NULL, `date_last_logged_in` datetime NOT NULL, `status` enum('ACTIVE','SUSPENDED','CLOSED') NOT NULL, PRIMARY KEY (`id`), KEY `fb_user_id` (`fb_user_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=1646 ;

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  • Get latest record from second table left joined to first table

    - by codef0rmer
    I have a candidate table say candidates having only id field and i left joined profiles table to it. Table profiles has 2 fields namely, candidate_id & name. e.g. Table candidates: id 1 2 and Table `profiles`: candidate_id name 1 Foobar 1 Foobar2 2 Foobar3 i want the latest name of a candidate in a single query which is given below: SELECT C.id, P.name FROM candidates C LEFT JOIN profiles P ON P.candidate_id = C.id GROUP BY C.id ORDER BY P.name; But this query returns: 1 Foobar 2 Foobar3 Instead of: 1 Foobar2 2 Foobar3

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  • MySQL Hibernate sort on 2 columns

    - by sammichy
    I have a table as follows Table item { ID - Primary Key content - String published_date - When the content was published create_date - When this database entry was created } Every hour (or specified time interval) I run a process to update this table with data from different sources (websites). I want to display the results according to the following rules. 1. The entries created each time the process runs should be grouped together. So the entries from the 2nd process run will always be after the entries from the first process run even if the published_date of an entry from the first run is after the published_date of an entry from the 2nd run. 2. Within the grouping by run, the entries by sorted by published_date 3. Another restriction is that I prefer that data from the same source not be grouped together. If I do the sort by create_date, published_date I will end up with data from source a, data from source b etc. I prefer that the data within each hour be mixed up for better presentation If I add a column to this table and store a counter which increments each time the process is run, it is possible to create a query to sort first by counter and then by published_dt. Is there a way to do it without adding a field? I'm using Hibernate over MySQL. e.g. Hour 1 (run 1) 4 rows collected from site a (rows 1-4) 3 rows collected from site b (rows 5-7) hour 2 (run 2) 2 row collected from site a (rows 8-9) 3 rows collected from site b (rows 10-12) ... After each run, new records are added to the database from each website. The create date is the time when the record was created in the database. The published date is part of the content and is read in from the external source. When the results are displayed I would like rows to be grouped together based on the hour they were published in. So rows 1-7 would be displayed before rows 8-12. Within each hourly grouping, I would like to sort the results by published date (timestamp). This is necessary so that the posts from all the sites collected in that hour are not grouped together but rather mixed in with each other.

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  • Oracle CRM On Demand Release 16

    Sandi Main Director, Oracle CRM On Demand Product Management provides an update on the features of this exciting new release. Learn how you can leverage Oracle CRM On Demand Release 16 to increase productivity and maximize your business needs.

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  • New Video: Oracle and Intel Collaboration

    - by Cinzia Mascanzoni
    We just published a webcast discussing the technical collaboration between Oracle and Intel. The panel highlights the recent collaborations on elastic computing, Oracle Database In-Memory, and the newly announced products Exadata Database Machine X4-8 and Sun Server X4-8. In addition, panelists reflect on the specific technical advances that have resulted from over twenty years of partnership.

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  • How to concatinate text on existing database entry?

    - by Starx
    I am a table, whose structure is somewhat like this id, name, link the link holds the name of the page like "link" = "index.php". Now I want to update this field and add "page=" in front of "index.php". Using this method I would like to update every entry in my table. My desired SQL syntax need to be something like this UPDATE mytable set link= 'page=' + <existing value of link> WHERE 1; I am using Where 1; to denote every other rows Anyone know what to accomplish this?

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  • Please verify the trigger created below for delete is correct or not?

    - by Parth
    Please verify the trigger created below for delete is correct or not? Its for the insertion of every field of deleted row in audit table.. Please reply whether this trigger will work for me? delimiter // CREATE TRIGGER audit_menu BEFORE DELETE ON menu FOR EACH ROW BEGIN INSERT INTO audit (menuid, field, oldvalue, changedone) VALUES (OLD.menuid, 'name', OLD.name, UNIX_TIMESTAMP() ), (OLD.menuid, 'age', OLD.age, UNIX_TIMESTAMP() ), (OLD.menuid, 'address', OLD.address, UNIX_TIMESTAMP() ), (OLD.menuid, 'sex', OLD.sex, UNIX_TIMESTAMP() ), (OLD.menuid, 'town', OLD.town, UNIX_TIMESTAMP() ) END;// delimiter ;

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  • one query instead of four - is it possible?

    - by Syom
    i must get data from four tables. i wrote the script with four queries, but i use it in ajax, and i wan't to do it by one query. here is queries... $query1 = "SELECT `id`,`name_ar` FROM `tour_type` ORDER BY `order`"; $query2 = "SELECT `id`,`name_ar` FROM `hotel_type` ORDER BY `order`"; $query3 = "SELECT `id`,`name_ar` FROM `food_type` ORDER BY `order`"; $query4 = "SELECT `id`,`name_ar` FROM `cities` WHERE `id_parrent` = '$id_parrent' ORDER BY `name_ar`"; is it possible to write in one query? thanks

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  • Complex data ordering...

    - by Povylas
    Hi, I have one tables ids in an array and they are ordered in the way I want and I have to select data from another table using those ids and in a order they are listen in the array. Pretty confusing but I was thinking of two solutions giving ORDER BY parameter the array but I do not know if that possible and another is to get all the necessary data and then turn it to array (mysql_fetch_assoc) then compare those two and somehow order the new array using the ids array. But I also do not know how to do this... Any ideas?

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  • Database Insider - October 2012 issue

    - by Javier Puerta
    The October issue of the Database Insider newsletter is now available. (Full newsletter here) NEWS   Newly Launched Oracle Exadata X3 Redefines Extreme Performance At Oracle OpenWorld 2012, Oracle announced the general availability of Oracle Exadata Database Machine X3, a complete package of servers, storage, networking, and software that is massively scalable, secure, and fully redundant—and ideally suited for the varied and unpredictable workloads of cloud computing. Read More WEBCASTS What Are Oracle Users Doing to Improve Availability and Disaster Recovery? The Independent Oracle Users Group (IOUG) surveyed more than 350 data managers and professionals regarding planned and unplanned downtime, database high availability, and disaster recovery solutions. Download the report and watch the Webcast today.

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