Search Results

Search found 16795 results on 672 pages for 'button remapping'.

Page 310/672 | < Previous Page | 306 307 308 309 310 311 312 313 314 315 316 317  | Next Page >

  • Prevent empty form input array from being posted?

    - by user355295
    Sorry if this has been answered somewhere; I'm not quite sure how to phrase the problem to even look for help. Anyway, I have a form with three text input boxes, where the user will input three song titles. I have simple PHP set up to treat those input boxes as an array (because I may want, say, 100 song titles in the future) and write the song titles to another document. <form method="post"> <input type="text" name="songs[]" value="" /> <input type="text" name="songs[]" value="" /> <input type="text" name="songs[]" value="" /> <button type="submit" name="submit" value="submit">Submit</button> </form> <?php if (isset($_POST['submit'])) { $open = fopen("test.html", "w"); if(empty($_POST['songs'])) { } else { $songs = $_POST['songs']; foreach($songs as $song) { fwrite($open, $song."<br />"); }; }; }; ?> This correctly writes the song titles to an external file. However, even when the input boxes are empty, the external file will still be written to (just with the <br />'s). I'd assumed that the if statement would ensure nothing would happen if the boxes were blank, but that's obviously not the case. I guess the array's not really empty like I thought it was, but I'm not really sure what implications that comes with. Any idea what I'm doing wrong? (And again, I am clueless when it comes to PHP, so forgive me if this has been answered a million times before, if I described it horribly, etc.)

    Read the article

  • Creating dynamic icons based on data entered into database from django forms

    - by John Hoke
    So I'm using Django to create a projects page with multiple forms for each project. Let's call them form 1, 2, 3, and 4. Once you create a project you can fill out any of these forms. I want to create "buttons" or links for each one of the forms that would show up on the main page. Now this is the part I need help with: Step 1. I want it so that if you click on a button for a form (say form 1) and none exists for that project yet a pop up would come up saying "This form does not exist yet, are you sure you want to create one?". And if you'd answer yes you would be directed to the form page. Step 2. But if that form does exist, I don't want any pop up to open and I want the link to take the user directly to that page. Step 3. My next problem is this. These forms are in order, so if you didn't create form 1 but created form 2, I don't want to give the user access to form 1. So in this scenario, if you click on form 1 I want a pop up to open and say "This form can no longer be created", and the link wouldn't function anymore. Basically the button will have 3 function. First it should look at the database and if data for that specific form exists it should do "Step 2", if data for that form and the proceeding forms don't exist it should do "Step 1", and if data for that form doesn't exist but data for proceeding form's does exist is should do "Step 3". Is this possible? Please help as I need to find a solution to this soon. Any help would be highly appreciated. Thank you

    Read the article

  • New to J2EE; architecture suggestions for a service/daemon?

    - by Kate
    I am brand new to the J2EE world. As an exercise to try and familiarize myself with J2EE, I'm trying to create a tiered web-app, but I'm getting a little stuck on what the best way is to spin up a service in the background that does work. Paramters of the service: It must open and hold a socket connection and receive information from the connected server. There is a 1-to-1 correlation between a user and a new socket connection. So the idea is the user presses a button on the web-page, and somewhere on the server a socket connection is opened. For the remainder of the users session (or until the user presses some sort of disconnect button) the socket remains open and pushes received information to some sort of centralized store that servlets can query and return to the user via AJAX. Is there a J2EE type way to handle this situation? Naturally what I would think to do is to just write a Java application that listens on a port that the servlets can connect to and spawns new threads that open these sockets, but that seems very ad-hoc to me. (PS: I am also new to Stack Overflow, so forgive me if it takes me some time to figure the site out!)

    Read the article

  • Form wont stay on top. How do I keep my excel form from hiding behind other windows after I browse

    - by ScottK
    I have a vb.net program that opens up an excel workbook and runs a macro ("Report") in that workbook when a button is clicked. //Workbook with macro and form xlWorkbook = xlApp.Workbooks.Open("W:Data\Excel Program.xls") //Macro: xlApp.Run("Report") //Macro opens form from workbook. I browse for my two .csv files //and then click a button to run code that creates my reports. //form closes, show the excel report after its created xlApp.Visible = True After I browse my first file and select it so that its location is displayed in my text box, the excel form then hides behind any open windows. I want this form to stay on top. It is after this code executes that the form will hide behind all other open windows: Private Sub btnBrowseFile1_Click() Dim fileName1 As String fileName1 = Application.GetOpenFilename("CSV file (*.csv), *.csv") If fileName1 <> "False" Then Me.txtFileName1.text = fileName1 End If End Sub EDIT: I still have no luck with this problem. When the excel macro is opened from a vb program I have this hiding issue...but only after browsing for a file. Why does the focus leave the form and go to Windows after browsing a file? Any one have any suggestions?

    Read the article

  • Can I get away with this or is it just too crude and unpractical ?

    - by The_AlienCoder
    I spent the whole of last night searching for a free AspNet web chat control that I could simply drag into my website. Well the search was in vain as I could not find a control that matched my needs i.e List of users, 1 to 1 chat, Ability to kick out users.. In the end I decided to create my own control from scractch. Although it works well on my machine Im concerned that It maybe a little crude and unpractical on a shared hosting enviroment. Basically this is what I did : Created an sql database that stores the chat messages. Wrote the stored procedures and and included a statement that clears old messages Then the 'crude' part : Dragged an update panel and timer control on my page Dragged a Repeater databound to the chat messages table inside the update panel Dragged another update panel and inside it put a textbox and a button Configured the timer control to tick every 5 seconds. ..and then I made it all work like this In the timer tick event I 'refreshed' the messages display by invoking Databind() on my repeater i.e protected void Timer1_Tick(object sender, EventArgs e) { MyRepeater.DataBind(); } Then in my send button click event protected void btnSend_Click(object sender, EventArgs e) { MyDataLayer.InsertMessage(Message, Sender, CurrTime); } Well It works well on my machine and Ive got the other functionalities(users list, kick out user..) to work by simply creating more tables. But like I said it seems a little crude to me. so I need a proffesional opinion. Should I run with this or try another Approach ?

    Read the article

  • Stopping a SoundPlayer loop at the local level

    - by EvanRyan
    I'm working on setting up an alarm that pops up as a dialog with multiple sound file options the user can choose from. The problem I'm having is creating a sound player at the local level that I can close with a button. The problem I'm having is that the sound keeps looping when I close the form because the SoundPlayer doesn't exist within the button click event. here's what I have: void callsound() { if (SoundToggle == 0) // if sound enabled { if ((SoundFile == 0) && (File.Exists(@"attention.wav"))) { System.Media.SoundPlayer alarm = new System.Media.SoundPlayer(@"attention.wav"); alarm.PlayLooping(); } if ((SoundFile == 1) && (File.Exists(@"aahh.wav"))) { System.Media.SoundPlayer alarm = new System.Media.SoundPlayer(@"aahh.wav"); alarm.PlayLooping(); } } private void button1_Click(object sender, EventArgs e) { //alarm.Stop(); Only works if SoundPlayer declared at class level this.Close(); } Is there a way I can do what I want to do by declaring the SoundPlayer instances where I am? Or is there a way to declare it at the class level, and still be able to change the sound file based on user settings?

    Read the article

  • Cannot press QPushButton in a simple program

    - by shadyabhi
    Basically, I want a simple pushButton with a colorful text which when pressed exits the application. Why cant I press PushButton in this simple program. I am using QT 4.6 on Arch x86_64. #include <QtGui/QApplication> #include <QLabel> #include <QPushButton> #include<QtGui> int main(int argc, char *argv[]) { QApplication a(argc, argv); QMainWindow *Main=new QMainWindow; QPushButton *button = new QPushButton(Main); QLabel *label = new QLabel(Main); label->setText("<h2><i>Hello</i> ""<font color=red>Qt!</font></h2>"); label->setVisible(true); QObject::connect(button, SIGNAL(clicked()),label, SLOT(clear())); label->setAlignment(Qt::AlignCenter|Qt::AlignVCenter); label->setWindowTitle("HelloWorld Test Program"); Main->show(); return a.exec(); }

    Read the article

  • how to add jquery live to lightbox v2?

    - by Mahmoud
    Hey all I am trying to create a page that well display a gallery image, when the user clicks on any images it inlarges using lightbox v2 now after that i adding on each image a button that well submit to jcart script which well add to cart, but when the user click on the button it refreshes. so i wanted to use jquery live to submit to jcart without closing the lightbox v2 but i still dont know how to do? code used inside lightbox title is <form class="jcart" method="post" action="" name = "add" > <input type="hidden" name="id" value="".$row['pro_num']."" /> <input type="hidden" name="name" value="".$row['pro_name']."" /> <input type="hidden" name="price" value="".$row['pro_price']."" /> <input type="hidden"name="qty" size = "1" value="1" /> <br /> <input type="image" value="Submit" name="addto" src = "images/add.png" /> </form>

    Read the article

  • View Controller Question

    - by user341444
    First off I'm new at programming. I'm creating an app with one navigation bar controller. The app is pretty basic except for a quiz section that is comprised of 12 xibs. As the users takes the quiz a new xib is pushed onto the stack. I want to create a button that takes the user back to the home screen if they do not want to complete the quiz. The back button takes them to the previous xib which could be 11 deep. Is it possible to dismiss the modal views and reload the rootView controller? Here's the code from my delegate @synthesize window; @synthesize navigationController; (void)applicationDidFinishLaunching:(UIApplication *)application { // Override point for customization after application launch [window addSubview:[navigationController view]]; [window makeKeyAndVisible]; } (void)dealloc { [window release]; [navigationController release]; [super dealloc]; } This is how I'm pushing new xibs onto the stack (IBAction) showTesting: (id)sender { Testing *varTesting = [[[Testing alloc] initWithNibName:@"Testing" bundle:nil] autorelease]; [[self navigationController] pushViewController:varTesting animated: YES]; } Any help would be greatly appreciated. Thanks

    Read the article

  • How do I add events to nested server controls? (ASP.Net)

    - by bert
    I am building a custom master page type control i.e. sort of like a datagrid but should be easier to add custom functionality into it. It's going great but part of the desired functionality is to have a paging control that switches on and off and part of that control would be a textbox that displays the current page number and on TextChanged redirects to the new page of the dataset. The problem I'm having is that technically the textbox which has its event fired is embedded in a control that is embedded in the control you actually put on the page sort of like Page  | Display Control  | Paging Control  | Textbox Buried all the way down there the event is not firing. Worse the postback javascript isn't even being written onto the page (Nothing on the page posts back so far this is the only bit that really needs to). I've been trawling around Google for quite a while now and picked up that I need to implement INamingContainer (done) and I need to add the control into the page's control tree (is Pre_Init too late for that? When's a good time to Add the Control to the page?) then the event should fire, apparently. But I've been unable to find an example of best practice on this there are quite a few near misses where people are having button angst but this isn't a button. So can anyone point me in the direction of getting a control embedded in a control embedded in a control added to a page to behave properly?

    Read the article

  • Keeping the number of objects and event-listeners on stage as low as possible

    - by DevEight
    Hello. I am creating a site with lots of big scrollable text-boxes in it. Each text-box object contained some text, and two buttons to scroll up/down with. The scroll buttons each had an event listener so the text moved when you clicked them. These text-boxes were stacked on-top of each other with all except one having an alpha of 0. If I wanted to change which text-box is active I move it to the front and call a small TweenLite animation. To the left (outside of the text-box objects) I have an object similar to a menu. It also has about 12 or so event-listeners (one for every button). This turns out cause A LOT of lag an it's very troublesome for my laptop to run it. What I need help with doing is to reduce the number of event-listeners on the stage and also the amount of text-boxes. What I was thinking was to add the text-boxes using AS so I only have 1 on the stage at a time but I couldn't figure out how to do it. I also thought it might be better to just use 1 big event-listeners and from mouseX and mouseY decide which button the user is trying to push. Are there any better alternatives to this? And if so, please elaborate on how to do it.

    Read the article

  • Visual Basic: Newbie questions.

    - by Omega
    Hello there. I am starting to learn visual basic. So far, it is quite simple and easy to use. I am liking it! Anyway, I want to make applications a little bit more complex. So far I have done very silly things. I would appreciate if you could help me with these: How do I open a new window (form)? Maybe I click a button on my main form and another form pops up. How do I "deactivate" the main form while the new form is running? (if I try to click the main form, an error sound plays) So my second form has a text field and a "OK" button. If I click it, the second form closes activating the main form again. I want to "pass" the text in the text field from the second form to the first one. How do I do that? Thank you, I am enjoying this new programming environment (didn't use Visual Studio much before)

    Read the article

  • PHP SDK Requires two logins...doesn't recognize first

    - by Jay Konieczny
    I am using the following code to authenticate whether users are logged in or not. While users can log in, they have to click the login button twice. Additionally, sometimes even after they click the log-in button twice, my "user info" part of the page (earlier in the page than the content) shows them as logged out while the actual page shows them as logged in. Here is the code. Could someone suggest a better way of handling log-ins? function isLoggedIn($facebook) { if (isset($facebook) and $facebook->getUser() != 0) { // UserID exists, but user may still not be logged in. Let's check: try { $facebook->api('/me', 'GET'); // If this succeeds, then they are logged in. return true; } catch(FacebookApiException $e) { // Some kind of error, so not logged in. if(session_id() === '') session_destroy(); return false; } } else { if(session_id() === '') session_destroy(); return false; } } Thanks!

    Read the article

  • Printing a JFrame and its components

    - by Alex Terreaux
    I have been working in a big program and one of its functionalities should be to print the contents of the main window. I checked the API and found this example: http://docs.oracle.com/javase/tutorial/2d/printing/gui.html it was very helpful, I tried to use that code in my program by placing this inside the actionperformed method of my print button: PrinterJob job = PrinterJob.getPrinterJob(); job.setPrintable(this); boolean ok = job.printDialog(); if (ok) { try { job.print(); } catch (PrinterException ex) { /* The job did not successfully complete */ } } If I click the print button, I get a printer dialog and when I tell it to print, it just prints a blank document. I know the above code is not all I need, as I've seen in the API's examples there is a print() method, but apparently they never call it, so it is pretty confusing. I've tried calling and using it many times, but with no success. Also, I think that when I finally get it to print, my window will need to be printed in the landscape orientation, it even may need some scaling. Any ideas on how to do that? I would like any useful help to help me implement this code successfully. I know I should be able to do it by myself just by checking the documentation (I've tried for almost 2 days now) but I can't get it to work. I've learned all the programming I know through the internet. Any help will be greatly appreciated.

    Read the article

  • Jquery form Ajax Submit

    - by user1766080
    I want to submit a form using ajax in the background. I tried: <div class="form-horizontal" id="form"> <label for="name" class="control-label">Username</label> <div class="controls"> <span id="name_input"><input type="text" name="name" id="medium" class='input-medium input-square'></span> <span class="help-inline" id = "ajax_load"></span> </div> <div class="form-actions"> <button class="btn btn-red5" onclick="resolve()">Login</button> <input type="reset" class='btn btn-danger' value="Reset"> </div> </div> And the Javascript: <script type="text/javascript"> var resolve = function () { jAlert('test', 'test'); $('#ajax_load').html('<a href="#" class="btn btn-mini btn-square tip" title="Reloading"><img src="templates/img/ajax-loader.gif" alt=""></a>'); $.ajax( { url : 'plugin.php?plugin=test', type : 'post', data: $("#form").serialize(), success : function( resp ) { if(resp.ajax_success == false) { } else { jAlert('test', 'test'); } } }); }; </script> I get an alert, but there is no form submit. I checked that with Live http headers. Why does it not submit the form?

    Read the article

  • Display a jQuery Dialog/Popup, then set a hidden field using the result of the dialog

    - by Dan Harris
    The Problem I have a page with a form on. It has a hidden field called: generic_portrait I want the user to click a link "select portrait" This will open a Dialog/Popup using jQuery, based on a dropdown completed earlier in the form. If the value of the dropdown called "gender" is "male" then show male options, if "gender" is set to "female" show female options. Each portrait has a radio button, each with a name assigned "male1", "male2" etc Depending on the radio button selected in the popup, I want the hidden field to be set to match this. The Questions What is the best way to show a dialog/popup using jQuery, different depending on a dropdown box on the page. Use Javascript to see what is selected, then show a corresponding Div? I can do the check to see what the dropdown is set to using jQuery, but how can I then shown a specific popup based on that? Once i've popped it up, how do I take the value assigned to the selected radio box, and set the hidden field called "generic_portrait" to this value. Why i'm asking Normally I would figure this out myself, as i'm sure it's not that difficult, but I don't use Javascript and/or PHP very often, and this is due for a client urgently. So I would really, really appreciate some help on this one. Thanks for all replies in advance.

    Read the article

  • On load rather than on click

    - by connor
    I have the following code: jQuery(function ($) { var OSX = { container: null, init: function () { $("input.apply, a.apply").click(function (e) { e.preventDefault(); $("#osx-modal-content").modal({ overlayId: 'osx-overlay', containerId: 'osx-container', closeHTML: null, minHeight: 80, opacity: 65, position: ['0',], overlayClose: true, onOpen: OSX.open, onClose: OSX.close }); }); }, open: function (d) { var self = this; self.container = d.container[0]; d.overlay.fadeIn('fast', function () { $("#osx-modal-content", self.container).show(); var title = $("#osx-modal-title", self.container); title.show(); d.container.slideDown('fast', function () { setTimeout(function () { var h = $("#osx-modal-data", self.container).height() + title.height() + 20; // padding d.container.animate( {height: h}, 200, function () { $("div.close", self.container).show(); $("#osx-modal-data", self.container).show(); } ); }, 300); }); }) }, close: function (d) { var self = this; // this = SimpleModal object d.container.animate( {top:"-" + (d.container.height() + 20)}, 500, function () { self.close(); // or $.modal.close(); } ); } }; OSX.init(); }); To load this script, a button with the class "apply" has to be clicked... Does anyone know a way of loading this script "onload" without a button being clicked? I have tried a lot of things, but I am a newbie when it comes to Javascript. Thanks!

    Read the article

  • WPF A good way to make a view/edit control?

    - by Jefim
    Hi, this is just a question to discuss - what is the best way to make a view/edit control in WPF? E.g. we have an entity object Person, that has some props (name, surname, address, phone etc.). One presentation of the control would be a read-only view. And the other would have the edit view for this same person. Example: <UserControl x:Name="MyPersonEditor"> <Grid> <Grid x:Name="ViewGrid" Visibility="Visible"> <TextBlock Text="Name:"/> <TextBlock Text="{Binding Person.Name}"/> <Button Content="Edit" Click="ButtonEditStart_Click"/> </Grid> <Grid x:Name="EditGrid" Visibility="Collapsed"> <TextBlock Text="Name:"/> <TextBox Text="{Binding Person.Name}"/> <Button Content="Save" Click="ButtonEditEnd_Click"/> </Grid> </Grid> </UserControl> I hope that the idea is clear. The two options I see right now two grids with visibility switching and a TabControl without its header panel This is just a discussion question - not much trouble with it, yet I am just wondering if there are any other possibilities and elegant solutions to this.

    Read the article

  • "Add another item" form functionality

    - by GSTAR
    I have a form that lets a user enter their career history - it's a very simple form with only 3 fields - type (dropdown), details (textfield) and year (dropdown). Basically I want to include some dynamic functionality whereby the user can enter multiple items on the same page and then submit them all in one go. I had a search on Google and found some examples but they were all based on tables - my markup is based on DIV tags: <div class="form-fields"> <div class="row"> <label for="type">Type</label> <select id="type" name="type"> <option value="Work">Work</option> </select> </div> <div class="row"> <label for="details">Details</label> <input id="details" type="text" name="details" /> </div> <div class="row"> <label for="year">Year</label> <select id="year" name="year"> <option value="2010">2010</option> </select> </div> </div> So basically the 3 DIV tags with class "row" need to be duplicated, or to simplify things - the div "form-fields" could just be duplicated. I am also aware that the input names would have to converted to array format. Additionally each item will require a "remove" button. There will be a main submit button at the bottom which submits all the data. Anyone got an elegant solution for this?

    Read the article

  • How can I make a new CTP (CakePHP) file in NetBeans?

    - by John Isaacks
    I have found a lot of info about adding CTP file support for NetBeans, but this is usually talking about code highlighting and treating a ctp file like a php file. This can be done at: Tools - Options - Miscellaneous - Files I have done this. However, when I try to create a NEW ctp file. I do not have the option. I tried going to Tools -> Templates to add a ctp template. There is no "new" button just an "add" button that looks for a file. I created a file on my desktop called cake_template.ctp on my desktop. I added it to the PHP templates in the template manager. I called the template "PHP Cake Template". Still when I go to create a new file, the option is not there. I restarted NetBeans, still the same. I just want to create a new .ctp file, it shouldn't be this difficult. Does anyone know how? I am using version 6.9.1

    Read the article

  • jQuery : how to apply effect on a child element

    - by Tristan
    Hello, instead of re-writting the same function, i want to optimise my code : <div class="header"> <h3>How to use the widget</h3> <span id="idwidget" ></span> </div> <div class="content" id="widget"> the JS : <script type="text/javascript"> $(document).ready(function() { var showText="Show"; var hideText="Hide"; $("#idwidget").before("<a href='#' class='button' id='toggle_link'>"+showText+"</a>"); $('#widget').hide(); $('a#toggle_link').click(function() { if ($('a#toggle_link').text()==showText) { $('a#toggle_link').text(hideText); } else { $('a#toggle_link').text(showText); } $('#widget').toggle('slow'); return false; }); }); This is working just with the div which is called widget and the button called idwidget. But on this page i have also : <div class="header"> <h3>How to eat APPLES</h3> <span id="IDsomethingelse" ></span> </div> <div class="content" id="somethingelse"> And i want it to be compatible with the code. I heard about children attribute, do you have an idea how to do that please ? Thank you

    Read the article

  • Is there a way to rotate an html table?

    - by Josh
    Is there a way to rotate an html table? So, say I had a table like this: <table id="table-1" cellspacing="0" cellpadding="2"> <tr><td>1</td></tr> <tr><td>2</td></tr> <tr><td>3</td></tr> <tr><td>4</td></tr> <tr><td>5</td></tr> <tr><td>6</td></tr> </table> and wanted to some sort of button that had javascript behind it that could rotate the table any which direction. For example, clicking the right button, results in: <table id="table-1" cellspacing="0" cellpadding="2"> <tr><td>6</td><td>5</td><td>4</td><td>3</td><td>2</td><td>1</td></tr> </table> I have a drag and drop plugin that uses a table, and I am trying to do a piece that allows for a user to add to a queue (that results in the table), and then they can also rotate it around as well. Thanks.

    Read the article

  • How do I display core data on second view controller?

    - by jon
    I am working on my first core data iPhone application. I am using a navigation controller, and the root view controller displays 4 rows. Clicking the first row takes me to a second table view controller. However, when I click the back button, repeat the row tap, click the back button again, and tap the row a third time, I get an error. I have been researching this for a week with no success. I can reproduce the error easily: Create a new Navigation-based Application, use Core Data for storage, call it MyTest which creates MyTestAppDelegate and RootViewController. Add new UIViewController subclass, with UITableViewController and xib, call it ListViewController. Copy code from RootViewController.h and .m to ListViewController.h and .m., changing the file names appropriately. To simplify the code, I removed the trailing “_” from all variables. In RootViewController, I added #import ListViewController.h, set up an array to display 4 rows and navigate to ListViewController when clicking the first row. In ListViewController.m, I added #import MyTestAppDelegate.h” and the following code: - (void)viewDidLoad { [super viewDidLoad]; if (managedObjectContext == nil) { managedObjectContext = [(MyTestAppDelegate *)[[UIApplication sharedApplication] delegate] managedObjectContext]; } .. } The sequence that causes the error is tap row, return, tap row, return, tap row - error. managedObjectContext is synthesized for the third time. I appreciate your patience and your help, as this makes no sense to me. ADDENDUM: I may have a partial solution. http://www.iphonedevsdk.com/forum/iphone-sdk-development/41688-accessing-app-delegates-managed-object-context.html If I do not release the managedObjectContext in the .m file, the error goes away. Is that ok or will that cause me issues? - (void)dealloc { [fetchedResultsController release]; // [managedObjectContext release]; [super dealloc]; } ADDENDUM 2: See solution below. Sorry for the formatting issues - this was my first post.

    Read the article

  • retrieving and restoring textview information from sharedpreferences

    - by user1742524
    I have an activity that allows user to enter notes and store them in dynamically created textviews. However, when the use leaves the activity and returns, all the created textviews disappear. How can i store store or retrieve all of these created textviews, whenever i return to the activity? Also, i think that my sharedpreferences will be overwriting each time a new textview is added. Any suggestions? public class DocNoteActivity extends Activity { private LinearLayout nLayout; private EditText etDocNote; private Button btnAdd1; public static final String PREFS_NAME = "MyPrefsFile"; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.adddocnote); etDocNote = (EditText) findViewById(R.id.editDocNote); btnAdd1 = (Button) findViewById(R.id.btnAdd1); nLayout = (LinearLayout) findViewById(R.id.linearLayout); TextView tvNote = new TextView(this); tvNote.setText(""); btnAdd1.setOnClickListener(onClick()); } private OnClickListener onClick() { // TODO Auto-generated method stub return new OnClickListener(){ public void onClick(View v) { // TODO Auto-generated method stub String newDocNote = etDocNote.getText().toString(); nLayout.addView(createNewTextView(newDocNote)); getSharedPreferences("myprefs", 0).edit().putString("etDocNote", newDocNote).commit(); } }; } private TextView createNewTextView(String newText) { // TODO Auto-generated method stub LayoutParams lparams = new LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT); TextView tvNote = new TextView(this); tvNote.setLayoutParams(lparams); tvNote.setText(newText); return tvNote; } }

    Read the article

  • Unable to `submit()` an html form after intercepting the submit with javascript.

    - by Ross Rogers
    I'm trying to intercept the submission of a form in order to change the value of my keywords label. I have the following code: <HTML> <FORM name="searchForm" method="get" action="tmp.html" > <input type="label" name="keywords" /> <input type="button" name="submit" value="submit" onclick="formIntercept();"/> </FORM> <SCRIPT language="JavaScript"> document.searchForm.keywords.focus(); function formIntercept( ) { var f = document.forms['searchForm']; f.keywords.value = 'boo'; f.submit(); }; </SCRIPT> </HTML> When I run this in chrome and click the submit button the keywords label changes to boo, but the javascript console says: Uncaught TypeError: Property 'submit' of object <#an HtmlFormElement> is not a function. How can I submit the form with the manipulated keywords?

    Read the article

< Previous Page | 306 307 308 309 310 311 312 313 314 315 316 317  | Next Page >