Search Results

Search found 52100 results on 2084 pages for 'http sys'.

Page 312/2084 | < Previous Page | 308 309 310 311 312 313 314 315 316 317 318 319  | Next Page >

  • Why can't I put a jquery-ui progressbar inside a div with fixed position?

    - by Matthew
    I started the source from this progressbar example, and it works fine. My only change was to set the width of the progressbar to "20%". <!DOCTYPE html> <html> <head> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> <script> $(document).ready(function() { $("#progressbar").progressbar({ value: 37 }).css({ width : "20%"}); }); </script> </head> <body style="font-size:62.5%;"> <div id="progressbar"></div> </body> </html> I then put the progressbar inside another div, and used css to fix that div in the upper-right-hand corner. <!DOCTYPE html> <html> <head> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <style type="text/css"> #testContainer { position : fixed; top : 6; right : 6; } </style> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> <script> $(document).ready(function() { $("#progressbar").progressbar({ value: 37 }).css({ width : "20%"}); }); </script> </head> <body style="font-size:62.5%;"> <div id="testContainer"> <div id="progressbar"></div> </div> </body> </html> The progressbar becomes a slim vertical line on the left side of the screen. What am I doing wrong? I'm new to web development in general, and jquery in particular, so please forgive me if this is a stupid question.

    Read the article

  • Old query String hard coded 301 url redirection using htaccess

    - by Nilesh Toshniwal
    I have recently changed CMS of my website and now looking to redirect old urls like: oldpage.php?key=7cdb93c26 to some new urls but I want all of them in hard coded way and it should be a 301 redirect I tried the following rules but none of them work for me redirect 301 /oldpage.php?key=7cdb93c26 http://www.mynewsite.com/my-new-page.html redirect 301 "/oldpage.php?key=7cdb93c26" http://www.mynewsite.com/my-new-page.html RewriteRule ^oldpage.php?key=7cdb93c26$ http://www.mynewsite.com/my-new-page.html [L,R=301] RewriteRule ^oldpage.php?key=7cdb93c26$ /my-new-page.html [L,R=301]

    Read the article

  • emacs/Python: running python-shell in line buffered vs. block buffered mode

    - by Begbie00
    Hi all - In a related question and answer here, someone hypothesized that python-shell within emacs(23.2) was block-buffered instead of line-buffered. The recommended fix was to add sys.stdout.flush() to the spot in my script where I want stdio to flush its contents to the python-shell. Is there someway to trick python-shell (running in emacs 23.2 on Windows, not Linux) into either a) thinking it's attached to a TTY or b) using line-buffered instead of block-buffered mode? I don't see why I'd be able to do this in IDLE but not emacs. I'd rather customize emacs than add sys.stdout.flush() throughout my scripts. Call me lazy :-). Thanks, Mike

    Read the article

  • How to read remote video on Amazon S3 using ffmpeg

    - by virtualize
    I need to create poster frames from videos hosted on Amazon S3 via ffmpeg. So is there a way to use the remote video file directly in ffmpeg command line like this: ffmpeg -i "http://bucket.s3.amazonaws.com/video.mp4" -ss 00:00:10 -vframes 1 -f image2 "image%03d.jpg" ffmpeg just returns: http://bucket.s3.amazonaws.com/video.mp4: I/O error occurred Usually that means that input file is truncated and/or corrupted. I also tried forcing ffmpeg to use the videos mp4 container for reading: ffmpeg -f mp4 -i "http://bucket.s3.amazonaws.com/video.mp4" ... But no luck. Wget this video from S3 and processing it locally works fine of course, as well as reading the file remotely from other 'standard' http servers. So I know that ffmpeg supports remote file reading, but why not on S3?

    Read the article

  • javascript window.location gives me a wrong url path when checking firebug

    - by Elson Solano
    I have a sample url website: http://mysite.com/ var host = window.location.protocol+"://"+window.location.hostname; $.ajax({ type:"POST", data: params, url : host+'/forms/get_data.php', success:function(data){ ...othercodeblahblah } }); Why is it that when I try to check my firebug it makes the URL weird. This is the sample output of firebug: http://mysite.com/mysite.com/forms/get_data.php With this url it now gives me: "NetworkError: 404 Not Found - http://mysite.com/mysite.com/forms/get_data.php" Shouldn't it output like http://mysite.com/forms/get_data.php ? Why is it giving me a wrong url path? Your help would be greatly appreciated and rewarded! Thank!

    Read the article

  • How to catch non exist requested URL in Java servlet ?

    - by Frank
    My objects are stored online in two different places : <1 On my nmjava.com site, where I can put them in a directory called "Dir_My_App/Dir_ABC/" <2 On Google App Engine datastore When my Java app runs it checks both places for the objects, I designed the app so that it tries to get an object from a Url, it doesn't care whether it's an object in a directory or an object returned by a servlet. My_Object Get_Object(String Site_Url,String Object_Path) { ... get object by the name of Object_Path from the Site_Url ... } Now the request Url for my web site nmjava.com might look like this : http://nmjava.com/Dir_My_App/Dir_ABC/My_Obj_123 [ In a directory ] Or in the case of Google App Engine servlet : http://nm-java.appspot.com/Check_License/Dir_My_App/Dir_ABC/My_Obj_123 [ Non exist ] The "Object_Path" was generated by my app automatically. It can now get the object from my site by the above method like this : My_Object Get_Object("http://nmjava.com","/Dir_My_App/Dir_ABC/My_Obj_123"); In the Google App Engine, my servlet is running and ready to serve the object, if the request comes in correctly, but since I don't want to design my app to know whether the object is in one site's directory or in other site's datastore, I need to design the servlet to catch the non exist Url, such as the one above, and be able to make a call : My_Object Get_Object("http://nm-java.appspot.com/Check_License","/Dir_My_App/Dir_ABC/My_Obj_123"); So my question is : When a request comes into the servlet with a non exist Url, how should it catch it and analyze the url in order to respond properly, in my case it should know that : http://nm-java.appspot.com/Check_License/Dir_My_App/Dir_ABC/My_Obj_123 is asking for the object "My_Obj_123" [ ignore the dirs ] and return the object from the datastore. Now I'm getting this : Error: Not Found The requested URL /Check_License/Dir_My_App/Dir_ABC/My_Obj_123 was not found on this server. Where in my servlet and how do I detect the request for this non exist Url ?

    Read the article

  • What happens if a bean attempts to load the Spring application context in its constructor?

    - by Derek Mahar
    Given the following Spring application context and class A, what happens when you run class A? applicationContext.xml (in classpath): <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <bean name="a" class="A"/> </beans> A.java: class A { private ApplicationContext applicationContext = new ClassPathXmlApplicationContext("applicationContext.xml"); public static void main(String[] args) { A a = new A(); } }

    Read the article

  • Need to pass the registry path along with launch parameter ...

    - by velusbits
    I have a situation that demands, passing the registry path as a parameter for application launch, say I have IE as default launcher for http types HKEY_CLASSES_ROOT\http\shell\open\command\ Default = iexplore %1 Any shell launch of a URL would invoke iexplore <<"URL String". My requirement is additionally pass the registry path as parameter, so when a launch happens (note no change in the launch) iexplore <<"URL String" should translate into something like iexplore <<"URL String" "HKEY_CLASSES_ROOT\http\shell\open\command\" How should my registry key HKEY_CLASSES_ROOT\http\shell\open\command\ modified so as to get the extra registry path appended for all shell launches ? Any idea is appreciated, Thanks !

    Read the article

  • free RSS feed caching

    - by cherouvim
    Hello I've got an application which serves an rss feed of headlines and I need to provide this rss feed to other consumers. I don't want to provide the rss directly from my server though, due to limited server resources, so I need to proxy (cache) it through some service which will handle the load. Assuming the rss feed URL of my application is http://example.com/rss I initially provided my consumers with the url http://ajax.googleapis.com/ajax/services/feed/load?v=1.0&q=http%3A%2F%2Fexample.com%2Frss which solved my server load problem but introduced a liveness problem. The headlines are minutes to hours late from the actual feed (haven't exactly measured how much late). I've also tried distributing through feedburner so the url became something like http://feeds.feedburner.com/example123?format=xml but the liveness problem still exists. Is there a public and free solution for this problem? Anything below 5 minutes of liveness delay would be totally acceptable. thanks

    Read the article

  • ReportViewr: Hyperlink to a local file doesn't work

    - by kernelMode
    I need to add 2 type of links to existing report with c#. For exapmle: 1) http://www.google.co.il/ 2) file:///C:/index.html I added the links, but only the "http://" works. when I press the link of "file:///" nothing happens. I've uploaded the full project (very small though) which includes the problem: http://www.filefactory.com/file/452gsoyymalv/n/ObjectReports.zip btw, The "index.html" is a simple 'helloWorld' which loaded successfully when writing the path on the address bar in the browser. Do anyone know what additional settings should be set to make the link work? Thanks!!! KM *credit for the sample (without my case): http://www.c-sharpcorner.com/uploadfile/mahesh/reportviewerobject04172007111636am/reportviewerobject.aspx

    Read the article

  • FastCGI C++ program and missing SCRIPT_NAME

    - by Simone Margaritelli
    Hi guys, i'm studying the fastcgi developement kit because i'm writing a new scripting language and i'd like to write a fastcgi version of the interpreter to run scripts as webpages. I'm using this example from the sdk, located at /srv/http/bin/echocpp So, in my httpd.conf file, i have the following lines : FastCgiServer /srv/http/bin/echocpp -idle-timeout 120 -processes 4 ScriptAlias / /srv/http/bin/echocpp/ ... ... AddHandler fastcgi-script hy Where 'hy' is the extensions of my scripts. Then, when i try browse, for instance http://localhost/~evilsocket/prime.hy I see all the environment variables as expected from the echo-cpp.cpp programm, except for the SCRIPT_NAME that is empty. Is there something i'm missing out of this? How am i supposed to obtain the full path of the script to run it inside my fastcgi version of the interpreter? Thanks

    Read the article

  • PyQt signal between QObjects

    - by geho
    I'm trying to make a view and controller in PyQt where the view is emitting a custom signal when a button is clicked, and the controller has one of its methods connected to the emitted signal. It does not work, however. The respond method is not called when I click the button. Any idea what I did wrong ? import sys from PyQt4.QtCore import * from PyQt4.QtGui import QPushButton, QVBoxLayout, QDialog, QApplication class TestView(QDialog): def __init__(self, parent=None): super(TestView, self).__init__(parent) self.button = QPushButton('Click') layout = QVBoxLayout() layout.addWidget(self.button) self.setLayout(layout) self.connect(self.button, SIGNAL('clicked()'), self.buttonClicked) def buttonClicked(self): self.emit(SIGNAL('request')) class TestController(QObject): def __init__(self, view): self.view = view self.connect(self.view, SIGNAL('request'), self.respond) def respond(self): print 'respond' app = QApplication(sys.argv) dialog = TestView() controller = TestController(dialog) dialog.show() app.exec_()

    Read the article

  • Write XML File from a flex application back to a rails Server

    - by Markus
    Hi everybody, I have a XML-file, which I want to send to a rails server. To do so I use the following code: <mx:HTTPService id="dataService" result="resultHandler(event)" resultFormat="e4x"/> In a Function triggered by a save button, I do the following: var params:Object = {}; params["xml_file"] = xmlDoc; dataService.method = "POST"; dataService.url = "http://localhost:3000/containers"; dataService.send(params); Unfortunately there is always the Problem (see below) appearing. If I remove the params var, it runs a GET Request... [RPC Fault faultString="HTTP request error" faultCode="Server.Error.Request" faultDetail="Error: [IOErrorEvent type="ioError" bubbles=false cancelable=false eventPhase=2 text="Error #2032: Stream-Fehler. URL: http://localhost:3000/containers"]. URL: http://localhost:3000/containers"] what could be the problem? Thanks for any hints! Markus

    Read the article

  • Zend redirect problem

    - by John
    I'm trying to redirect to http://localhost/site/public/admin/login from http://localhost/site/public but for some reason, it keeps redirecting to http://localhost/admin/login The code I am using is: $this->_response->setRedirect('/admin/login')->sendResponse(); This is really frustrating me, and any help would be grealy appreciated

    Read the article

  • How can I fit an Image into another imageview

    - by user1597833
    I have an imageview with a default image already set from the xml, and I want to change it's image pragmatically so that the new image will scale to the previous image size, both of the images are rounded. I have tried setting the scaleType attribute to different values before setting the new image but it didn't work. This is the xml: <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" > <ImageView android:id="@+id/up_right_circle_firstiv" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_centerInParent="true" android:scaleType="fitXY" android:src="@drawable/circle_medium_up" /> This is the activity code: public class MainActivity extends Activity { ImageView middleCircle; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); middleCircle = (ImageView) findViewById(R.id.up_right_circle_firstiv); middleCircle.setImageResource(R.drawable.round_pic_one); } } Inside the activity. I have uploaded the screenshots: http://imgur.com/OM79T http://imgur.com/G7y3Q

    Read the article

  • What is your favourite programming-related lolcat picture?

    - by DR
    In the spirit of these questions... http://stackoverflow.com/questions/234075/what-is-your-best-programmer-joke http://stackoverflow.com/questions/354686/programming-related-songs http://stackoverflow.com/questions/517897/anyone-know-any-programming-related-poetry ... I wonder: What is your favourite programming-related lolcat picture? Please add one answer per picture.

    Read the article

  • Parse youtube links PHP

    - by Isis
    Hello 34|http://v19.lscache8.c.youtube.com/videoplayback?ip=0.0.0.0&sparams=id,expire,ip,ipbits,itag,algorithm,burst,factor,oc:U0dWRlZUVF9FSkNNNl9OTlhF&fexp=902210&algorithm=throttle-factor&itag=34&ipbits=0&burst=40&sver=3&expire=1271696400&key=yt1&signature=583C4A85FA65B6B9782B8B4B5E1F1C08D9EADCA3.5B28033470580BC52EB92A1CB71DBAFE0C4A2A8D&factor=1.25&id=cf3cec58d98073dc,5|http://v24.lscache4.c.youtube.com/videoplayback?ip=0.0.0.0&sparams=id,expire,ip,ipbits,itag,algorithm,burst,factor,oc:U0dWRlZUVF9FSkNNNl9OTlhF&fexp=902210&algorithm=throttle-factor&itag=5&ipbits=0&burst=40&sver=3&expire=1271696400&key=yt1&signature=7B74075BAA26B05A028B2219FD52D7A45197F555.A8878413DC7BB3FFAB0C9219CBD3FCDD7221B440&factor=1.25&id=cf3cec58d98073dc How to parse this text for: 34 http://... (before ,5|) 5 http://... to end Previously it was done so: if (preg_match_all('#|(.*?),#', $urlmap, $b)) { } Sorry for baaaaad english

    Read the article

  • Rewrite URL to index.php but avoid index.php in the URL

    - by Tom
    I'm trying to internally redirect all requests to index.php and externally redirect all requests that contain index.php using a .htaccess file. So URLs like http://host/test should be processed by index.php and URLs like http://host/index.php/test should be redirected to http://host/test and then processed by index.php (without redirecting the browser to index.php) I tried the following but always get a message "Too many redirects...": RewriteRule ^index\.php/?(.*)$ /$1 [R,L] RewriteRule .* index.php/$0 [L]

    Read the article

  • Jquery Resizable Image size issue

    - by alex
    Image size is not automatically detected when using jquery resizable. Both Firefox and IE displays the image much smaller, and chrome show nothing at all. I can't seem to find a direct answer to this issue. How can this be fixed. <link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.7/themes/base/jquery-ui.css" type="text/css" media="all"> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js" type="text/javascript"> </script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.7/jquery-ui.min.js" type="text/javascript"> </script> <img src="http://www.carsyouwilldrive.com/wp-content/uploads/2009/06/futurecar1.jpg"> <script type="text/javascript"> $("img").resizable(); </script>

    Read the article

  • 1 bug to kill... Letting PHP Generate The Canonical.

    - by Sam
    Hi folks, for building a clean canonical url, that always returns 1 base URL, im stuck in following case: <?php # every page $extensions = $_SERVER['REQUEST_URI']; # path like: /en/home.ast?ln=ja $qsIndex = strpos($extensions, '?'); # removes the ?ln=de part $pageclean = $qsIndex !== FALSE ? substr($extensions, 0, $qsIndex) : $extensions; $canonical = "http://website.com" . $pageclean; # basic canonical url ?> <html><head><link rel="canonical" href="<?=$canonical?>"></head> when URL : http://website.com/de/home.ext?ln=de canonical: http://website.com/de/home.ext BUT I want to remove the file extension aswell, whether its .php, .ext .inc or whatever two or three char extension .[xx] or .[xxx] so the base url becomes: http://website.com/en/home Aaah much nicer! but How do i achieve that in current code? Any hints are much appreciated +! (other advices for proper canonical usage in this multi-lingual environment are welcome as well)

    Read the article

  • php:unable to download youtube video using phptube class

    - by I Like PHP
    i m using phptube class for downloading you tube video. from this site In code i paste youtube url on a input box but there is errors below. Warning: file_get_contents(http://www.youtube.com/get_video?video_id=&t=) [function.file-get-contents]: failed to open stream: HTTP request failed! HTTP/1.0 404 Not Found and Warning: file_put_contents(./flvs/3Hx9VsqMUug.flv) [function.file-put-contents]: failed to open stream: No such file or directory in E:\xampp\htdocs\vdo\utube \functions.php on line 19 path:./flvs/3Hx9VsqMUug.flv please tell me where is problem???

    Read the article

  • Serialization of Entity Framework Models with .NET WCF Rest Service

    - by Chris Phillips
    I'm trying to put together a very simple REST-style interface for communicating with our partners. An example object in the API is a partner, which we'd like to have serialized like this: <partner> <id>ID</id> <name>NAME</name> </partner> This is fairly simply to achieve using the .NET 4.0 WCF REST template if we simply declare a partner class as: public class Partner { public int Id {get; set;} public string Name {get; set;} } But when I use the Entity Framework to define and store Partner objects, the resulting serialization looks something like this: <Partner p1:Id="NCNameString" p1:Ref="NCNameString" xmlns:p1="http://schemas.microsoft.com/2003/10/Serialization/" xmlns="http://schemas.datacontract.org/2004/07/TheTradeDesk.AdPlatform.Provisioning"> <EntityKey p1:Id="NCNameString" p1:Ref="NCNameString" xmlns="http://schemas.datacontract.org/2004/07/System.Data.Objects.DataClasses"> <EntityContainerName xmlns="http://schemas.datacontract.org/2004/07/System.Data">String content</EntityContainerName> <EntityKeyValues xmlns="http://schemas.datacontract.org/2004/07/System.Data"> ... This XML is obviously unacceptable for use as an external API. What are suggested mechanisms for using EF for the data store but maintaining a simple XML serialization interface?

    Read the article

  • Wpf application variable not changing

    - by Hasan Zubairi
    In my application I need some variables on almost all the pages so I declared them in Application.xaml like <sys:String x:key="First">First</sys:String> and on one page I change the value in code like Resources["First"] = "This is First"; on the second page when I call the variable like String f = (string)this.TryFindResource("First"); MessageBox.Show(f); the out put is "First" and not "This is First". I also tried like. Application.Current.Properties["First"]

    Read the article

  • xsl:for-each not supported in this context

    - by alexbf
    Hi! I have this XSLT document : <xsl:stylesheet version="1.0" xmlns:mstns="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/2001/XMLSchema" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/MyDocRootElement"> <xs:schema id="DataSet" targetNamespace="http://www.w3.org/2001/XMLSchema" attributeFormDefault="qualified" elementFormDefault="qualified" > <xs:element name="DataSet" msdata:IsDataSet="true"> <xs:complexType> <xs:choice maxOccurs="unbounded"> <xs:element name="Somename"> </xs:element> <xs:element name="OtherName"> </xs:element> <!-- FOR EACH NOT SUPPORTED? --> <xsl:for-each select="OtherElements/SubElement"> <xs:element name="OtherName"> </xs:element> </xsl:for-each> </xs:choice> </xs:complexType> </xs:element> </xs:schema> </xsl:template> </xsl:stylesheet> I have a validation error saying that the "for-each element is not supported in this context" I am guessing it has something to do with the xs namespace validation. Any ideas on how can I make this work? (Exclude validation?) Thanks Alex

    Read the article

< Previous Page | 308 309 310 311 312 313 314 315 316 317 318 319  | Next Page >