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  • PHP SDK Requires two logins...doesn't recognize first

    - by Jay Konieczny
    I am using the following code to authenticate whether users are logged in or not. While users can log in, they have to click the login button twice. Additionally, sometimes even after they click the log-in button twice, my "user info" part of the page (earlier in the page than the content) shows them as logged out while the actual page shows them as logged in. Here is the code. Could someone suggest a better way of handling log-ins? function isLoggedIn($facebook) { if (isset($facebook) and $facebook->getUser() != 0) { // UserID exists, but user may still not be logged in. Let's check: try { $facebook->api('/me', 'GET'); // If this succeeds, then they are logged in. return true; } catch(FacebookApiException $e) { // Some kind of error, so not logged in. if(session_id() === '') session_destroy(); return false; } } else { if(session_id() === '') session_destroy(); return false; } } Thanks!

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  • [PHP] Local/Dev/Live deployment - best workflow

    - by Adam Kiss
    Hello, situation We our little company with 3 people, each has a localhost webserver and most projects (previous and current) are on one PC network shared disk. We have virtual server, where some of our clients' sites and our site. Our standard workflow is: Coder PC ? Programmer localhost ? dev domain (client.company.com) ? live version (client.com) It often happens, that there are two or three guys working on same projects at the same time - one is on dev version, two are on localhost. When finished, we try to synchronize the files on dev version and ideally not to mess up any files, which *knock knock * doesn't happen often. And then one of us deploys dev version on live webserver. question we are looking for a way to simplify this workflow while updating websites - ideally some sort of diff uploader or VCS probably (Git/SVN/VCS/...), but we are not completely sure where to begin or what way would be ideal, therefore I ask you, fellow stackoverflowers for your experience with website / application deployment and recommended workflow. We probably will also need to use Mac in process, so if it won't be a problem, that would be even better. Thank you

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  • PHP File Upload + jQuery

    - by st4ck0v3rfl0w
    Hello Everyone, So I have my upload script working just fine, but now it's a matter of making it look the way I want for my layout. <input type="file" name="userfile" id="userfile"/> This obviously shows a textbox with a Choose File button. What I really need is my own custom button (which will ultimately be an image) that upon successful file select (not upload quite yet) triggers a jQuery event to show a div. I do NOT want the filename textbox to show. Basic steps outlined below. User clicks on image button to upload their file User selects file jQuery shows a div with more fields User clicks submit and file is uploaded

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  • Leading zeroes in php

    - by sanders
    Hello, I would like to present a list from 0 to 59 of with the numbers 0 to 9 have a leading zero. This is my code but it doesn't work so far. Any idea's? for($i=0; $i<60; $i++){ if($i< 10){ sprintf("%0d",$i); } array_push($this->minutes,$i); }

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  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    I having been looking around for an answer to this and have not found an answer anywhere, I am hoping someone has done this before! I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="primary[1][text]" /> <input type="file" name="primary[1][file]" /> <input type="text" class="a" name="secondary[1][text][]" /> <input type="file" name="secondary[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="primary[2][text]" /> <input type="file" name="primary[2][file]" /> <input type="text" class="a" name="secondary[2][text][]" /> <input type="file" name="secondary[2][file][]" /> To complicate matters, the "secondary" form fields can also be duplicated (thus the [] at the end of the secondary name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $f_num) { echo $f['file']['name']; } but I get an "Undefined index: file... " error.

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  • PHP Session Array Value keeps showing as "Array"

    - by Nerathas
    Hello, When sending data from a form to a second page, the value of the session is always with the name "Array" insteed of the expected number. The data should get displayed in a table, but insteed of example 1, 2, 3 , 4 i get : Array, Array, Array. (A 2-Dimensional Table is used) Is the following code below a proper way to "call" upon the stored values on the 2nd page from the array ? $test1 = $_SESSION["table"][0]; $test2 = $_SESSION["table"][1]; $test3 = $_SESSION["table"][2]; $test4 = $_SESSION["table"][3]; $test5 = $_SESSION["table"][4]; What exactly is this, and how can i fix this? Is it some sort of override that needs to happen? Best Regards.

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  • PHP - BUG with filter_var and FILTER_VALIDATE_FLOAT

    - by Samuele
    I think there is a bug in this filter_var or maybe I'm doing something wrong: Try this: $options = array( 'options' => array( 'default' => 3, 'min_range' => 1000.0, 'max_range' => 5000.6, ) ); $VariableValue2 = 5698; $VariableValue4 = 5698.2; $chicco3 = filter_var($VariableValue2, FILTER_VALIDATE_INT, $options); $chicco4 = filter_var($VariableValue4, FILTER_VALIDATE_FLOAT, $options); It suppose to don't validate it... Infact the value: 5698 is greater than 5000.6!!!! But with FILTER_VALIDATE_INT it work FINE!! It return 3 that is the default value in case it don't validate it... PERFECT... Instead, with FILTER_VALIDATE_FLOAT it validate it... It return 5698.2!!! I'm doing something wrong??? Thank you to everybody... Samuele

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  • php $_SESSION[document_root] too far down the tree

    - by Idealflip
    Hi, I have multiple sub-domains within the document_root. And multiple folders/classes within those sub-domain folders. I need something that will help me with my include_once paths, but $_SESSION[DOCUMENT_ROOT] goes too far down. And if I were to use this, and transfer the website folder later, all my include_once paths will/might break. Hope my question is clear... Any recommendations?

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  • PHP : If...Else...Query

    - by Rachel
    I am executing this statement under while (($data=fgetcsv($this->fin,5000,";"))!==FALSE) Now what I want in else loop is to throw exception only for data value which did not satisfy the if condition. Right now am displaying the complete row as I am not sure how to throw exception only for data which does not satisfy the value. Code if ((strtotime($data[11]) &&strtotime($data[12])&&strtotime($data[16]))!==FALSE && ctype_digit($data[0]) && ctype_alnum($data[1]) && ctype_digit($data[2]) && ctype_alnum($data[3]) && ctype_alnum($data[4]) && ctype_alnum($data[5]) && ctype_alnum($data[6]) && ctype_alnum($data[7]) && ctype_alnum($data[8]) && $this->_is_valid($data[9]) && ctype_digit($data[10]) && ctype_digit($data[13]) && $this->_is_valid($data[14])) { //Some Logic } else { throw new Exception ("Data {$data[0], $data[1], $data[2], $data[3], $data[4], $data[5], $data[6], $data[7], $data[8], $data[9], $data[10], $data[11], $data[12], $data[13], $data[14], $data[16]} is not in valid format"); } Guidance would be highly appreciated as to how can I throw exception only for data which did not satisfy the if value.

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  • Simple PHP query question: LIKE

    - by pg
    When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    Example form here: http://jsfiddle.net/superuntitled/uaTtx/1/ I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="question[1][text]" /> <input type="file" name="question[1][file]" /> <input type="text" class="a" name="answer[1][text][]" /> <input type="file" name="answer[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="question[2][text]" /> <input type="file" name="question[2][file]" /> <input type="text" class="a" name="answer[2][text][]" /> <input type="file" name="answer[2][file][]" /> To complicate matters, the "answer" form fields can also be duplicated (thus the [] at the end of the 'answer' name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $p_num) { echo $p_num['file']['name']; foreach ($_FILES['answer'] as $a_num) { echo $a_num['file']['name']; } } but I get an "Undefined index: file... " error. How can I parse out the posted values.

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  • What are the PHP "encryption" functions?

    - by Rob
    Looking for built in encryption functions, not to hide the string from the clever programmer, but instead just to obfuscate it a bit. Looking for functions such as str_rot13 and base64_encode, but I can't seem to locate any. Surely there are more?

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  • PHP foreach help

    - by sea_1987
    Hello I have an array that looks like this, Array ( [cfi_title] => Mr [cfi_firstname] => Firstname [cfi_surname] => Lastname [cfi_email] => [email protected] [cfi_subscribe_promotional] => [cfi_tnc] => [friendsName] => Array ( [0] => Firstname 1 [1] => Firstname 2 [2] => Firstname 3 ) [friendsEmail] => Array ( [0] => [email protected] [1] => [email protected] [2] => [email protected] ) [submit_form] => Submit ) My dilema is I need to save the values from the friendsName and friendsEmail arrays into a database, I know I can loop through them but how can I send the matching data, for example I need to save [friendsName][0] and friendsEmail][0] on the same row of database? I know I need to use a foreach but I just cannot figure out the logic.

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  • php - How do I get rid of this strange "empty delimiter" message

    - by Steven
    I have some code that uses the stristr function to extract data I need. It works, in that it gives me the results I'm looking for. BUT (you knew there was a but), it gives me this error message for every iteration of the loop: Warning: stristr() [function.stristr]: Empty delimiter in ... line 55 Like I said, the code works apart from this error. Can anyone suggest how i could amend this code to get rid of the message? Thanks in advance $data = stristr("$text", "$key"); $result = string_limit_words($data,2); print "$result<BR>";

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  • Php random row help...

    - by Skillman
    I've created some code that will return a random row, (well, all the rows in a random order) But i'm assuming its VERY uneffiecent and is gonna be a problem in a big database... Anyone know of a better way? Here is my current code: $count3 = 1; $count4 = 1; //Civilian stuff... $query = ("SELECT * FROM `*Table Name*` ORDER BY `Id` ASC"); $result = mysql_query($query); while($row = mysql_fetch_array($result)) { $count = $count + 1; $civilianid = $row['Id']; $arrayofids[$count] = $civilianid; //echo $arrayofids[$count]; } while($alldone != true) { $randomnum = (rand()%$count) + 1; //echo $randomnum . "<br>"; //echo $arrayofids[$randomnum] . "<br>"; $currentuserid = $arrayofids[$randomnum]; $count3 += 1; while($count4 < $count3) { $count4 += 1; $currentarrayid = $listdone[$count4]; //echo "<b>" . $currentarrayid . ":" . $currentuserid . "</b> "; if ($currentarrayid == $currentuserid){ $found = true; //echo " '" .$found. "' "; } } if ($found == true) { //Reset array/variables... $count4 = 1; $found = false; } else { $listdone[$count3] = $currentuserid; //echo "<u>" . $count3 .";". $listdone[$count3] . "</u> "; $query = ("SELECT * FROM `*Tablesname*` WHERE Id = '$currentuserid'"); $result = mysql_query($query); $row = mysql_fetch_array($result); $username = $row['Username']; echo $username . "<br>"; $count4 = 1; $amountdone += 1; if ($amountdone == $count) { //$count $alldone = true; } } } Basically it will loop until its gets an id (randomly) that hasnt been chosen yet. -So the last username could take hours :P Is this 'bad' code? :P :(

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  • REST Authentication in PHP (CodeIgniter)

    - by zidane
    I writing REST API form my web application. Application is written using CodeIgniter framework. Application itself is working fine, but I'm stuck on making REST Authentication. I think that basic Http Authentication will be good enough for some time. Public API is not yet planned. Is there any code example how to achieve REST Authentication so after user is authenticated he can freely call all protected methods.

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  • Php, in_array with no exactly match

    - by John Smith
    I want to do the following: $a = array(); $a[] = array(1,2); $a[] = array(2,5); $a[] = array(3,4); var_dump (in_array(array(2,5), $a)); this returns OK, as it expected, but if the source array is not fully matched: $a = array(); $a[] = array(1,2, 'f' => array()); $a[] = array(2,5, 'f' => array()); $a[] = array(3,4, 'f' => array()); var_dump (in_array(array(2,5), $a)); it returns false. Is there a way to do it with the built-in way, or I have to code it?

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  • Create a PHP cache system in MySQL database?

    - by Zach Smith
    I'm creating a web service that often scrapes data from remote web pages. After scraping this data, I have a simple multidimensional array of information to use. The scraping process is fairly taxing on my server, and the page load takes a while. I was considering adding a simple cache system using a MySQL database, where I create one row per remote web page with a the array of information pulled from it stored as a JSON encoded string. Is this a good enough system? Or would something like a text file per web page be a better idea?

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  • PNG composition using GD and PHP

    - by Dominic
    I am trying to take a rectangular png and add depth using GD by duplicating the background and moving it down 1 pixel and right 1 pixel. I am trying to preserve a transparent background as well. I am having a bunch of trouble with preserving the transparency. Any help would be greatly appreciated. Thanks! $obj = imagecreatefrompng('rectangle.png'); $depth = 5; $obj_width = imagesx($obj); $obj_height = imagesy($obj); imagesavealpha($obj, true); for($i=1;$i<=$depth;$i++){ $layer = imagecreatefrompng('rectangle.png'); imagealphablending( $layer, false ); imagesavealpha($layer, true); $new_obj = imagecreatetruecolor($obj_width+$i,$obj_height+$i); $new_obj_width = imagesx($new_obj); $new_obj_height = imagesy($new_obj); imagealphablending( $new_obj, false ); imagesavealpha($new_obj, true); $trans_color = imagecolorallocatealpha($new_obj, 0, 0, 0, 127); imagefill($new_obj, 0, 0, $trans_color); imagecopyresampled($new_obj, $layer, $i, $i, 0, 0, $obj_width, $obj_height, $obj_width, $obj_height); //imagesavealpha($new_obj, true); //imagesavealpha($obj, true); } header ("Content-type: image/png"); imagepng($new_obj); imagedestroy($new_obj);

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  • php / phpDoc - @return instance of $this class ?

    - by searbe
    How do I mark a method as "returns an instance of the current class" in my phpDoc? In the following example my IDE (Netbeans) will see that setSomething always returns a foo object. But that's not true if I extent the object - it'll return $this, which in the second example is a bar object not a foo object. class foo { protected $_value = null; /** * Set something * * @param string $value the value * @return foo */ public function setSomething($value) { $this->_value = $value; return $this; } } $foo = new foo(); $out = $foo->setSomething(); So fine - setSomething returns a foo - but in the following example, it returns a bar..: class bar extends foo { public function someOtherMethod(){} } $bar = new bar(); $out = $bar->setSomething(); $out->someOtherMethod(); // <-- Here, Netbeans will think $out // is a foo, so doesn't see this other // method in $out's code-completion ... it'd be great to solve this as for me, code completion is a massive speed-boost. Anyone got a clever trick, or even better, a proper way to document this with phpDoc?

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  • PHP IF statement not taking variable into account!

    - by Jess
    I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

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  • PHP syntax question: global $argv, $argc;

    - by Andrew
    So I have a PHPUnit test, and found this code within a function. global $argv, $argc; echo $argc; print_r($argv); I understand what these variables represent (arguments passed from the command line), but I've never seen this syntax before:global $argv, $argc; What specifically is going on here?

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