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  • Mysql limit function doesn't seem to work for me...

    - by chandru_cp
    Here is my query, select t1.dSyllabus_id,t1.dBatch,t1.dFilePathName, t2.dDegreeName,t3.dDepartmentAbbr from tbl_syllabus as t1 join tbl_degree_master as t2, tbl_department_master as t3 where t2.dDegree_id=t1.dDegree_id and t3.dDepartment_id=t1.dDepartment_id and t1.dCollege_id='1' and t1.dIsDelete='0' and i get applying limit , select t1.dSyllabus_id,t1.dBatch,t1.dFilePathName, t2.dDegreeName,t3.dDepartmentAbbr from tbl_syllabus as t1 join tbl_degree_master as t2, tbl_department_master as t3 where t2.dDegree_id=t1.dDegree_id and t3.dDepartment_id=t1.dDepartment_id and t1.dCollege_id='1' and t1.dIsDelete='0' limit 0,5 i get , I dont get the first five records why?

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  • Failed to obtain JDBC Driver for MySQL under Tomcat environment

    - by Michael Mao
    Hi all: I've been trying to obtain the Driver class for JDBC connection to MySQL. The workstation is running on Linux, Fedora 10. I have manually set up the classpath variable for Java by CLI like this: bash-3.2$ echo $CLASSPATH /home/cmao/public_html/jsp/mysql-connector-java-5.1.12-bin.jar This shows that I've added the lastest mysql connection jar archive to my CLASSPATH variable. I've created a test JSP page which can be found here And source code for this page is: <%@page language="java"%> <%@page import="java.sql.*"%> <%@page import="java.util.*"%> <html> <head> <title>UTS JDBC MySQL connection test page</title> </head> <body> <% Connection con = null; out.print("Java version is : " + System.getProperty("java.version") + "<br />"); out.print("Tomcat version is : " + application.getServerInfo() + "<br />"); out.print("Servlet version is: " + application.getMajorVersion() + "<br />"); out.print("JSP version is : " + JspFactory.getDefaultFactory().getEngineInfo().getSpecificationVersion() +"<br />"); //out.print("Java classpath is : " + System.getProperty("java.class.path")+ "<br />"); //out.print("JSP classpath is : " + appliaction.getAttribute("org.apache.catalina.jsp_classpath") + "<br />"); //out.print("Tomcat classpath is : " + System.getProperty("org.apache.tomcat.common.classpath") + "<br />"); try { Class c = Class.forName("com.mysql.jdbc.Driver"); } catch(Exception e) { out.println("Error! Failed to obtain JDBC driver for MySQL... Missing class \"com.mysql.jdbc.Driver\"<br />"); } %> </body> </html> None of those commented out line would work, various Jsper Expetions would be thrown. You can check those Error pages from the following links: classpath Error page catalina Error page tomcat Error page It seems, from my limited knowledge of JSP and Servlet, the Tomcat environment "ignores" my Java CLASSPATH? In which case I cannot configure the MySQL JDBC package to let my Servlets(a JSP is but a Servlet anyway) work. I am not sure how to fix this issue. would it be better if I use an IDE like Eclipse or NetBeans and create a real Java "web app" so that everything can be "self-configured" by the usage of a web.config XML configuration file? So that I can certainly bypass this Tomcat environment restriction? Many thanks for the suggestions in advance.

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  • MySQL, SQL Select Statement, Where with OR... What's wrong with this?

    - by nobosh
    I'm looking for help with my query below. which is never returning anything for veggie... Is the way I have my WHERE statement written valid? SELECT * FROM newsfeed INNER JOIN newsfeedaction ON newsfeed.newsfeedactionid = newsfeedaction.newsFeedActionID INNER JOIN person ON newsfeed.personID = person.personID LEFT OUTER JOIN food ON newsfeed.foodID = food.foodID LEFT OUTER JOIN veggie ON newsfeed.veggieID = veggie.veggieID WHERE ( newsfeed.veggieID IS NOT NULL AND veggie.deleted = 'N' ) OR ( newsfeed.foodID IS NOT NULL AND food.deleted = 'N')

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  • mysql fetch result parent id and category id by single query?

    - by Karthik
    I have the table and values like this, CREATE TABLE `category` ( `id` INT( 4 ) NOT NULL AUTO_INCREMENT PRIMARY KEY , `category` VARCHAR( 50 ) NOT NULL , `parent` INT( 4 ) NOT NULL ) INSERT INTO `category` VALUES (1, 'MCA', 9); INSERT INTO `category` VALUES (2, 'M Tech', 9); INSERT INTO `category` VALUES (3, 'B Tech', 9); INSERT INTO `category` VALUES (4, 'BioTech', 9); INSERT INTO `category` VALUES (5, 'InfoTech', 9); INSERT INTO `category` VALUES (6, 'Chemical', 10); INSERT INTO `category` VALUES (7, 'Indus', 10); INSERT INTO `category` VALUES (8, 'Physics', 10); INSERT INTO `category` VALUES (9, 'Information Science', 0); INSERT INTO `category` VALUES (10, 'Others Science', 0); I need a single query for getting the values in terms of category and subcategory. 3rd values zero as category and others are subcategory.

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  • How to order the images in a mysql database?

    - by user305270
    Hy! Here is my problem: i have a profile and this profile has for example 100 images. When someone visit this profile the first image will be the first result of my query that sorts by updated_at. But if the user would want to put the image with the (id = 8) to be the first, then (id = 22) then (id = 88) and so on? I need to put another field or is really necessary a new table to make a custom sort on images? and maybe someone explain this to me how to do? thanks, i appreciate your help ;)

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  • How do I bring forward the SELECTED option in PHP from MySQL?

    - by Derek
    Hi all, In my update form, I want the fields to recall the values that are already stored. This is very simple in a text field, but for my drop down () I'm having trouble with PHP reading the already stored name of user. Here is my query and code: $sql = "SELECT users.user_id, users.name FROM users"; $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); $row = mysql_fetch_array($result);?> <label>Designated Person:</label> <select name="name" id="name"> <option value="<?php echo $row['user_id']?>" SELECTED><?php echo $row['name']?> - Current</option> <?php while($row = mysql_fetch_array($result)) { ?> <option value="<?php echo $row['user_id']; if (isset($_POST['user_id']));?>"><?php echo $row['fullname']?></option> <?php } ?> The result of this displays all of the users (as required) and lets me select a user then perform the change successfully...however the 'SELECTED' is always the first one in my database and never the user that was selected when my activity was added :( !!!

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  • What's a reasonable number of rows and tables to be able to join in MySQL?

    - by Philip Brocoum
    I have one table that maps locations to postal codes. For example, New York State has about 2000 postal codes. I have another table that maps mail to the postal codes it was sent to, but this table has about 5 million rows. I want to find all the mail that was sent to New York State, which seems simple enough, but the query is unbelievably slow. I haven't been able to even wait long enough for it to finish. Is the problem that there are 5 million rows? I can't help but think that 5 million shouldn't be such a large number for a computer these days... Oh, and everything is indexed. Is SQL just not designed to handle such large joins?

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  • PDOStatement::bindParam() not setting AI value from MySQL insert?

    - by Alan
    I have a simple insert statement using PDO php class. $statement = $db->prepare('INSERT INTO demographics (id,location_id,male,ethnicity_id,birthyear) VALUES (:id,:location_id,:male,:ethnicity_id,:birthyear)'); $statement->bindParam(':id',$demo->id,PDO::PARAM_INT,4); $statement->bindParam(':location_id', $demo->locationid,PDO::PARAM_INT); $statement->bindParam(':male',$demo->male,PDO::PARAM_BOOL); $statement->bindParam(':ethnicity_id',$demo->ethnicityid,PDO::PARAM_INT); $statement->bindParam(':birthyear',$demo->birthyear,PDO::PARAM_INT); $statement->execute(); print_r($demo); Even though the statement executes correctly (row is correctly written), $demo-id is null. Any thoughts?

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  • MySQL calling in Username to show instead of ID!

    - by Jess
    I have a users table, books table and authors table. An author can have many books, while a user can also have many books. (This is how my DB is currently setup). As I'm pretty new to So far my setup is like bookview.php?book_id=23 from accessing authors page, then seeing all books for the author. The single book's details are all displayed on this new page...I can get the output to display the user ID associated with the book, but not the user name, and this also applies for the author's name, I can the author ID to display, but not the name, so somewhere in the query below I am not calling in the correct values: SELECT users.user_id, authors.author_id, books.book_id, books.bookname, books.bookprice, books.bookplot FROM books INNER JOIN authors on books.book_id = authors.book_id INNER JOIN users ON books.book_id = users.user_id WHERE books.book_id=" . $book_id; Could someone help me correct this so I can display the author name and user name both associated with the book! Thanks for the help :)

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  • How to Display result of subquery rows as one column in MySQL?

    - by SIA
    Hi I have three tables Category, Movies and RelCatMov Category-table categoryid, categoryName 1 thriller 2 supsense 3 romantic 4 action 5 sci-fi Movies-table movieid, movieName 1 Avataar 2 Titanic 3 NinjaAssassin RelCatMov-table categoryid, MovieID 1 1 2 2 3 2 4 2 5 2 Now i Want to display a the record as MovieName Categories Titanic Suspense,Romantic,Sci-fi,action How to do this. I am writing a query select MovieName,(select categoryname from category b,relcatmov c where b.categoryid=c.categoryid and c.movieid=a.movieid) as categories from movies a; Error: Subquery returns more than one row!!! How to display the result of rows in one column? Please help!!!

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  • Specifying column names from a list in the data.frame command.

    - by MW Frost
    I have a list called cols with column names in it: cols <- c('Column1','Column2','Column3') I'd like to reproduce this command, but with a call to the list: data.frame(Column1=rnorm(10)) Here's what happens when I try it: > data.frame(cols[1]=rnorm(10)) Error: unexpected '=' in "data.frame(I(cols[1])=" The same thing happens if I wrap cols[1] in I() or eval(). How can I feed that item from the vector into the data.frame() command?

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  • Mysql - Operand should contain 1 column(s) : What's wrong with the query...?

    - by SpikETidE
    Hi everybody.... I am trying to query a database to find the following If a customer searches for a hotel in a city between dates A and B, find and return the hotels in which rooms are free between the two dates. There will be more than one room in each room type(i.e. 5 Rooms in type A, 10 rooms in Type B etc) and we have to query the db to find only those hotels in which there is atleast one room free in atleast one type. This is my table structure.... **Structure for table 'reservations'** reservation_id hotel_id room_id customer_id payment_id no_of_rooms check_in_date check_out_date reservation_date **Structure for table 'hotels'** hotel_id hotel_name hotel_description hotel_address hotel_location hotel_country hotel_city hotel_type hotel_stars hotel_image hotel_deleted **Structure for table 'rooms'** room_id hotel_id room_name max_persons total_rooms room_price room_image agent_commision room_facilities service_tax vat city_tax room_description room_deleted And this is my query $city_search = '15'; $check_in_date = '29-03-2010'; $check_out_date = '31-03-2010'; $dateFormat_check_in = "DATE_FORMAT('$reservations.check_in_date','%d-%m-%Y')"; $dateFormat_check_out = "DATE_FORMAT('$reservations.check_out_date','%d-%m-%Y')"; $dateCheck = "$dateFormat_check_in >= '$check_in_date' AND $dateFormat_check_out <= '$check_out_date'"; $query = "SELECT $rooms.room_id, $rooms.room_name, $rooms.max_persons, $rooms.room_price, $hotels.hotel_id, $hotels.hotel_name, $hotels.hotel_stars, $hotels.hotel_type FROM $hotels,$rooms,$reservations WHERE $hotels.hotel_city = '$city_search' AND $hotels.hotel_id = $rooms.hotel_id AND $hotels.hotel_deleted = '0' AND $rooms.room_deleted = '0' AND $rooms.total_rooms - (SELECT SUM($reservations.no_of_rooms) as tot, $rooms.room_id as id FROM $reservations,$rooms WHERE $dateCheck GROUP BY $reservations.room_id) > '0'"; The number of rooms already reserved in each room type in each hotel will be stored in the reservations table... The query returns the error : Operand should contain 1 column(s) I tried running the sub-query alone but i don't get any result... And i have lost quite some amount of hair trying to de-bug this query from yesterday... What's wrong with this...? Or is there a better way to do what i mentioned above...? Thanks for your time...

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  • When does a MySQL Query actually execute in PHP?

    - by MJB
    This sounds like a really simple question, but I am new to PHP. If I have a statement like this: $r =& $db->query("insert into table (col1, col2) values (10, 20)"); Do I have to still execute it, or does it get executed when I reference it? I have another case where I have a select query, which seems logically to run only when I call fetchrow, but the code I am presented with (to fix) does not call execute or fetch.I would have expected it to, so I cannot tell if it is just that I don't get it, or that the missing execute statement is the problem. It also does not insert the record, but it does not throw an error I can find. Also, I am a little confused by the =& notation. I looked it up on google, and found a few mentions of it, but I am still not clear on it. Thanks.

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  • Mysql concurrency: what happens if a locked table is accessed?

    - by PixelSapiens
    the question is rather simple but I couldn't find a precise answer: in a myisam db, what happens if a php file locks a table (with an atomic operation, say an INSERT) and another php file tries to access the same table (reading or writing)? Now, while it is obvious that the second session will not be able to access the table, what exactly happens? Does it return some kind of error? Does is wait in queue until it is able to access it? Thanks in advance!

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  • MySql - Select from - Don't Show Duplicate Words - maybe "on duplicate key"?

    - by ali
    hi, how can I insert "on duplicate key" in this Code to remove duplicate words? or is there a better method that you know? thank you!! this is my code: function sm_list_recent_searches($before = '', $after = '', $count = 20) { // List the most recent successful searches. global $wpdb, $table_prefix; $count = intval($count); $results = $wpdb->get_results( "SELECT `terms`, `datetime` FROM `{$table_prefix}searchmeter_recent` WHERE 3 < `hits` AND CHAR_LENGTH(`terms`) > 4 ORDER BY `datetime` DESC LIMIT $count"); if (count($results)) { foreach ($results as $result) { echo '<a href="'. get_settings('home') . '/search/' . urlencode($result->terms) . '">'. htmlspecialchars($result->terms) .'</a>'.", "; } } }

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  • rookie MySql question about paging; Is one query enough?

    - by Camran
    I have managed to get paging to work, almost. I want to display to the user, total nr of records found, and the currently displayed records. Ex: 4000 found, displaying 0-100. I am testing this with the nr 2 (because I don't have that many records, have like 20). So I am using LIMIT $start, $nr_results; Do I have to make two queries in order to display the results the way I want, one query fetching all records and then make a mysql_num_rows to get all records, then the one with the LIMIT ? I have this: mysql_num_rows($qry_result); $total_pages = ceil($num_total / $res_per_page); //$res_per_page==2 and $num_total = 2 if ($p - 10 < 1) { $pagemin=1; } else { $pagemin = $p - 10; } if ($p + 10 $total_pages) { $pagemax = $total_pages; } else { $pagemax = $p + 10; } Here is the query: SELECT mt.*, fordon.*, boende.*, elektronik.*, business.*, hem_inredning.*, hobby.* FROM classified mt LEFT JOIN fordon ON fordon.classified_id = mt.classified_id LEFT JOIN boende ON boende.classified_id = mt.classified_id LEFT JOIN elektronik ON elektronik.classified_id = mt.classified_id LEFT JOIN business ON business.classified_id = mt.classified_id LEFT JOIN hem_inredning ON hem_inredning.classified_id = mt.classified_id LEFT JOIN hobby ON hobby.classified_id = mt.classified_id ORDER BY modify_date DESC LIMIT 0, 2 Thanks, if you need more input let me know. Basically Q is, do I have to make two queries?

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  • How do I add a one-to-one relationship in MYSQL?

    - by alex
    +-------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+-------------+------+-----+---------+-------+ | pid | varchar(99) | YES | | NULL | | +-------+-------------+------+-----+---------+-------+ 1 row in set (0.00 sec) +-------+---------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+---------------+------+-----+---------+-------+ | pid | varchar(2000) | YES | | NULL | | | recid | varchar(2000) | YES | | NULL | | +-------+---------------+------+-----+---------+-------+ 2 rows in set (0.00 sec) This is my table. pid is just the id of the user. "recid" is a recommended song for that user. I hope to have a list of pid's, and then recommended songs for each person. Of course, in my 2nd table, (pid, recid) would be unique key. How do I do a one-to-one query for this ?

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  • Is there any way to modify a column before it is ordered in MySQL?

    - by George Edison
    I have a table with a field value which is a varchar(255). The contents of the field can be quite varied: $1.20 $2994 $56 + tax (This one can be ignored or truncated to $56 if necessary) I have a query constructed: SELECT value FROM unnamed_table ORDER BY value However, this of course uses ASCII string comparison to order the results and does not use any numerical type of comparison. Is there a way to truly order by value without changing the field type to DECIMAL or something else? In other words, can the value field be modified ('$' removed, value converted to decimal) on the fly before the results are sorted?

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