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  • Access shell methods in controller? Cake PHP 1.3

    - by anonymous coward
    I wrote a shell method in CakePHP 1.3 that has a return value. I'd like to be able to access that method from within a controller, so that I can pass its return value into the View. I'm not sure how to access those methods appropriately from within the controller. Have I done it wrong? I could easily duplicate the code, but I'd like to "keep it DRY", and the actual functionality, I believe, doesn't belong with this particular controller - I just need it's return value in this particular view.

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  • Error during data INSERT in php

    - by nectar
    here my code- $sql = "INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES "; for($i=0; $i0) { $sql .= ", "; } $sql .= "('$pin[$i]', '$ownerid', 'Free', '1')"; } $sql .= ";"; echo $sql; mysql_query($sql); if(mysql_affected_rows() 0) { echo "done"; } else { echo "Fail"; } output: ** INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES ('13837927', 'admin', 'Free', '1'), ('59576082', 'admin', 'Free', '1'); Fail why it is not inserting values when $sql query is right?

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  • Mail php function does'nt send the email

    - by Mamadou
    Hello everybody, I have the following code wich work on some server and does not work in an other: $Name = "myname"; //senders name $email_sender = "[email protected]"; //senders e-mail adress $recipient = $email; //recipient $mail_body = "The text for the mail..."; //mail body $subject = "Subject for reviever"; //subject $header = "From: ". $Name . " <" . $email_sender . ">\r\n"; $status = mail($recipient, $subject, $mail_body, $header); print('ENVOI '. $status); the $status variable is true but i dont see any email.

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  • My cookies won't stay (PHP).

    - by RemiX
    I'm building an autologin system using cookies, but one fundamental part of the functionality of the cookies fails: they are non-persistent over different sessions - or even pages! In my login script, I set the cookies like this: setcookie('userID', $userID, time()+86400); // (edited after replies) $userID has a value. Then I print the $_COOKIE variable and it says array(['base_usid'] = 1); So that's good, but when I click the home page and print the $_COOKIE variable there, it says NULL. Does anyone see the problem?

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  • What pattern is this? php

    - by user151841
    I have several classes that are basically interfaces to database rows. Since the class assumes that a row already exists ( __construct expects a field value ), there is a public static function that allows creation of the row and returns an instance of the class. Here's an example ( without the actual database inserts ): class selfStarter { public $type; public function __construct( $type ) { $this->type = $type; } public static function create( $type ) { if ( ! empty($type) ) { $starter = & new selfStarter($type); return $starter; } } } $obj1 = selfStarter::create( "apple" ); $obj2 = & new selfStarter( "banana" ); What is this pattern called?

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  • PHP/MySQL Interview - How would you have answered?

    - by martincarlin87
    I was asked this interview question so thought I would post it here to see how other users would answer: Please write some code which connects to a MySQL database (any host/user/pass), retrieves the current date & time from the database, compares it to the current date & time on the local server (i.e. where the application is running), and reports on the difference. The reporting aspect should be a simple HTML page, so that in theory this script can be put on a web server, set to point to a particular database server, and it would tell us whether the two servers’ times are in sync (or close to being in sync). This is what I put: // Connect to database server $dbhost = 'localhost'; $dbuser = 'xxx'; $dbpass = 'xxx'; $dbname = 'xxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die (mysql_error()); // Select database mysql_select_db($dbname) or die(mysql_error()); // Retrieve the current time from the database server $sql = 'SELECT NOW() AS db_server_time'; // Execute the query $result = mysql_query($sql) or die(mysql_error()); // Since query has now completed, get the time of the web server $php_server_time = date("Y-m-d h:m:s"); // Store query results in an array $row = mysql_fetch_array($result); // Retrieve time result from the array $db_server_time = $row['db_server_time']; echo $db_server_time . '<br />'; echo $php_server_time; if ($php_server_time != $db_server_time) { // Server times are not identical echo '<p>Database server and web server are not in sync!</p>'; // Convert the time stamps into seconds since 01/01/1970 $php_seconds = strtotime($php_server_time); $sql_seconds = strtotime($db_server_time); // Subtract smaller number from biggest number to avoid getting a negative result if ($php_seconds > $sql_seconds) { $time_difference = $php_seconds - $sql_seconds; } else { $time_difference = $sql_seconds - $php_seconds; } // convert the time difference in seconds to a formatted string displaying hours, minutes and seconds $nice_time_difference = gmdate("H:i:s", $time_difference); echo '<p>Time difference between the servers is ' . $nice_time_difference; } else { // Timestamps are exactly the same echo '<p>Database server and web server are in sync with each other!</p>'; } Yes, I know that I have used the deprecated mysql_* functions but that aside, how would you have answered, i.e. what changes would you make and why? Are there any factors I have omitted which I should take into consideration? The interesting thing is that my results always seem to be an exact number of minutes apart when executed on my hosting account: 2012-12-06 11:47:07 2012-12-06 11:12:07

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  • Add 30 seconds to the time with PHP

    - by Sam
    Hey all, just wondering how I can add 30 seconds on to this? $time = date("m/d/Y h:i:s a", time()); Thankyou, again. I wasn't sure how to do it because it is showing lots of different units of time, when I only want to add 30 seconds.

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  • php,codigniter, upload the zip file problem

    - by user345804
    function upload( &$data = array() ) { $config['upload_path'] = 'system/application/orginalimage/'; $config['allowed_types'] = 'gif|jpg|png|zip'; $config['allowed_type'] = 'application/zip'; $config['allowed_type'] = 'application/x-zip-compressed'; $config['allowed_type'] = 'application/x-compress'; $config['allowed_type'] = 'application/x-compressed'; $config['allowed_type'] = 'application/octet-stream'; $config['allowed_type'] = 'multipart/x-zip'; $config['max_size'] = '100'; $config['max_width'] = '1024'; $config['max_height'] = '768'; $this->load->library('upload', $config); if ( $this->upload->do_upload( 'uploadimage')) { $data = $this->upload->data() ; return true ; } return false ; } uploading a zip file is not working help me

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  • PHP foreach help

    - by sea_1987
    Hello I have an array that looks like this, Array ( [cfi_title] => Mr [cfi_firstname] => Firstname [cfi_surname] => Lastname [cfi_email] => [email protected] [cfi_subscribe_promotional] => [cfi_tnc] => [friendsName] => Array ( [0] => Firstname 1 [1] => Firstname 2 [2] => Firstname 3 ) [friendsEmail] => Array ( [0] => [email protected] [1] => [email protected] [2] => [email protected] ) [submit_form] => Submit ) My dilema is I need to save the values from the friendsName and friendsEmail arrays into a database, I know I can loop through them but how can I send the matching data, for example I need to save [friendsName][0] and friendsEmail][0] on the same row of database? I know I need to use a foreach but I just cannot figure out the logic.

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  • php for-loop issue

    - by rajesh1984
    Heya, I have a loop which generates a table code for a specific number of times. What I'm having problems with is to echo a variable inside the loop. The loop runs 10 times, and there are 10 text messages sent to the page, so my problem is how do I get each of the looped tables to echo one of the text messages each time?

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  • Problem with unlink() in php!

    - by Holicreature
    I'm creating a temp image always named 1.png under specific folder and once i read the image_contents and process, i use unlink() to delete that specific image from that folder. But sometimes the image file is not deleted and the same image is file is read and processed. That script is working otherwise fine... There is no permission related issues , as the files are deleted sometimes... Will there be any issue when the script is repeatedly called and the image with the name is already present and not deleted etc.. ??? Please suggest me what would be the problem extension_loaded('ffmpeg'); $max_width = 120; $max_height = 72; $path ="/home/fff99/public_html/temp/"; ..... ..... $nname = "/home/friend99/public_html/temp/".$imgname; $fileo = fopen($nname,"rb"); if($fileo) { $imgData = addslashes(file_get_contents($nname)); .... ... .. } unlink('$nname');

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  • hidden post parameter , php curl

    - by Michael
    I'm trying to replicate the browser post parameters on http://www.ebayclassifieds.com/m/PostAd?scrid=3465450-2253858851033189948 but for some reasons I can't find where the values for 2 of them are comming from . The parameters are btn-previwe-ad.x and btn-previwe-ad.y but I can't find such as parameters in the html source itself or any hidden value.

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  • php multidimensional array if loop

    - by user1091558
    I have a multidimensional array like this array[value][1][1] Now i would like to implement if loop like this if ($value = array[value][1][1]) { echo "It works"; } Now it works if i assign the values like [1][1],[2][1]. Is it possible to compare the whole array. I mean if the array looks like array[value][1][1],array[value][2][1],..........,array[value][n][1] It works should be echoed. I tried like this. if ($value = array[value][][]) { echo "It works"; } But its not working. Can anyone give me the correct syntax?

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  • unix timestamps and php

    - by sea_1987
    I have a list of unix timestamps in a database, and I wanting to select the ones that are from today. i.e If today is Tueday, I want to get all the timestamps that were made today? Is it possible? Is there such a things as strtotime("Today")? Any help would be great

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  • Problem with php GD image not creating

    - by ThinkingInBits
    With the following code, my browser is returning 'image not created or saved'. I assure you the location of the image exists. So the line within the if statement is returning false for some reason, and yes GD is installed. Any ideas? if ($img = @imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { $image_width = imagesx($img); $image_height = imagesy($img); $target_width = 150; $target_height = 150; if ($image_width > $image_height) { $percentage = ($target_width / $image_width); } else { $percentage = ($target_height / $image_height); } $new_image_width = round($image_width * $percentage); $new_image_height = round($image_height * $percentage); $imgResized = imagecreatetruecolor($new_image_width, $new_image_height); imagecopyresampled($imgResized, $img, 0, 0, 0, 0, $new_image_width, $new_image_height, $image_width, $image_height); imagejpeg($imgResized, $this->path, 100); imagedestroy($img); imagedestroy($imgResized); $this->storeThumbnailLocation(); } else { die ("image was not created or saved"); }

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  • Php function within SQL statement syntax

    - by Vafello
    I have the following code. I would like username to take the value of the getUserName function however I am fighting with syntax. Can anybody tell me what should be the correct one? $query = "SELECT user FROM users_entity WHERE username = getUserName()";

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  • PHP: Remove the first and last item of the array

    - by phpBOY
    Hi, Suppose I have this array: $array = array('10', '20', '30.30', '40', '50'); Questions What is the fastest/easiest way to remove the first item from the above array? What is the fastest/easiest way to remove the last item from the above array? So the resulting array contains only these values: '20' '30.30' '40'

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  • Regular Expressions, avoiding HTML tags in PHP

    - by Jason Axelrod
    I have actually seen this question quite a bit here, but none of them are exactly what I want... Lets say I have the following phrase: Line 1 - This is a TEST phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST">TEST</a> link. Okay, simple right? I am trying the following code: $linkPin = '#(\b)TEST(\b)(?![^<]*>)#i'; $linkRpl = '$1<a href="newurl">TEST</a>$2'; $html = preg_replace($linkPin, $linkRpl, $html); As you can see, it takes the word TEST, and replaces it with a link to test. The regular expression I am using right now works good to avoid replacing the TEST in line 2, it also avoids replacing the TEST in the href of line 3. However, it still replaces the text encapsulated within the tag on line 3 and I end up with: Line 1 - This is a <a href="newurl">TEST</a> phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST"><a href="newurl">TEST</a></a> link. This I do not want as it creates bad code in line 3. I want to not only ignore matches inside of a tag, but also encapsulated by them. (remember to keep note of the / in line 2)

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  • Pass variable number of variables to a class in PHP

    - by user325282
    I need to pass a variable number of strings to instantiate different classes. I can always do a switch on the size of the array: switch(count($a)) { case 1: new Class(${$a[0]}); break; case 2: new Class(${$a[0]}, ${$a[1]}); break; etc... There has to be a better way to do this. If I have an array of strings ("variable1", "variable2", 'variable3", ...), how can I instantiate a Class without manually accounting for every possibility?

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