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  • htaccess in php

    - by Badshah
    I am using htaccess in my projec.there is login section i want to show the my account page as http:///www/domain.com/username . But there is a problem because i have also made a cms which is open as http:///www/domain.com/cms . Although i have validate the user name But there is same page open when i open the cms or user profile page. I have pass the regular expression in htaccess but stil not required result is come

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  • My IF statement is changing variables in PHP

    - by user1902509
    I am fairly new to the whole programming thing, so forgive me if this is a stupid question. It seems odd that I haven't run into it before. I am trying to make an order form for a cake. You fill out the form, submit it, and it will then display the order in a new window, where you then hit "submit," and upload it to the Database. I have a series of If Statements to check for errors in the form before submitting it. Here is a simplified version of the code. Writing means any writing you want on the cake, Name is your name, and cake is what type of cake you want (the default is "None"). try { $name = trim($params->name); $cake = trim($params->cake); $writing = trim($params->writing); if (strlen($name) < 3){ throw new Exception("Please enter Your name."); } if ($cake = "None") { throw new Exception("Please select a Cake" } if ($cake = "Caramel Apple Pie" or $cake = "Pumpkin Pie" or $cake = "Eggnog Pie" and strlen($writing) > 1) { throw new Exception("We are sorry, but you can't write on any of our specialty pies."); } } catch(Exception $x) { $error = $x->getmessage(); } So what is happening is that when I go and hit submit the first time, the correct cake type comes up, but when you submit it the second time, the error comes up saying that I have "None" selected. All the other values are there and remain the same. I think the problem is that the first "IF" statement (Where it says "If($cake = "None")) is automatically changing $cake to "None" because I have tried commenting just that statement out, and it will then change the cake to be "Caramel Apple Pie," which is in the top of the next IF statement. Anyone know why it is doing this? And how to fix it?

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  • Inheriting database connection in PHP OOP

    - by vrode
    My abstract class Database is made for database interaction and any child of this class (UserDatabase, ActionDatabase, EventDatabase) inherits its database connection which is defined as static. `abstract class Database { static $connection = mysql_connect( ); } class UserDatabase extends Database { ... public function __construct( ) { $connection ? "connected" : "not connected"; $this-table = "users"; mysql_query( "FROM " . $this-table . " SELECT *" ); } } ` Does that mean, that my database connection is only set up and stored in memory once and passed on to subclasses as reference without being replicated for each instance? Is this how you would implement you OOP-correct database interface?

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  • == and === operators in php

    - by Lizard
    Lets say I have a variable that will always be a string. Now take the code below: if($myVar === "teststring") Note $myVar will always be a string, so my questions is Which is quicker/best, using === (Indentity) or the == (Equality)?

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  • SQL return error within PHP

    - by Luke
    I use GET to get the id of a result. $id = $_GET['id']; I then use the following code: <? $q = $database->friendlyDetails($id); while( $row=mysql_fetch_assoc($q) ) { $hu = $row['home_user']; $ht = $row['home_team']; $hs = $row['home_score']; $au = $row['away_user']; $at = $row['away_team']; $as = $row['away_score']; $game = $row['game']; $name = $row['name']; $match = $row['match_report1']; $compid = $row['compid']; $date = $row['date_submitted']; $sub = $row['user_submitted']; } ?> And friendDetails- function friendlyDetails($i) { $q = "SELECT * FROM ".TBL_SUB_RESULTS." INNER JOIN ".TBL_FRIENDLY." ON ".TBL_FRIENDLY.".id = ".TBL_SUB_RESULTS.".compid WHERE ".TBL_SUB_RESULTS.".id = '$i'"; return mysql_query($q, $this->connection); } For some reason, the code will only return what is under id =1. Can anyone see anything obvious I am doing wrong?

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  • get all fields value from mysql using php

    - by zahir hussain
    hi i want to know how to get all fields value search by array. i have array that s my table is id content 1 zahr 2 hai . . . and so on $a = {2,3,4,5,43,32}; i have to take the contents by this id(from array "a"). i know, i can use "for" loop for getting each element from mysql. but i would like to use any filters or any predefined function thanks and advance

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  • PHP use function return value as array

    - by Richard Knop
    Why is it that this works: $cacheMatchesNotPlayed = $cache->load('externalData'); $cacheMatchesNotPlayed = $cacheMatchesNotPlayed['matchesNotPlayed']; But this doesn't work: $cacheMatchesNotPlayed = $cache->load('externalData')['matchesNotPlayed']; Is there some reason for it? The second bit is easier to write.

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  • PHP - Get a specific value in an array

    - by Charles Yeung
    Hi Suppose I have the code below: [taxonomy] => Array ( [118] => stdClass Object ( [tid] => 118 [vid] => 4 [name] => A [description] => [weight] => 4 ) [150] => stdClass Object ( [tid] => 150 [vid] => 5 [name] => B [description] => [weight] => 0 ) ) How can I only get the tid number and exclude others, could someone please give me a suggestion? Thanks you

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  • PHP's preg_split question

    - by WekiLol
    I want to split text by the letter-followed-by-period rule. So I do this: $text = 'One two. Three test. And yet another one'; $splitted_text = preg_split("/\w\./", $text); print_r($splitted_text); Then I get this: Array ( [0] => One tw [1] => Three tes [2] => And yet another one ) But I do need it to be like this: Array ( [0] => One two [1] => Three test [2] => And yet another one ) How to settle the matter?

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  • PHP getting a bunch of weird code \u0644\u064a\u0646\u0643 \u0627\u0644

    - by Webby
    Hello I'm getting a bunch of weird html output in users messages e.g. \u0644\u064a\u0646\u0643 \u0627\u0644 \u0639\u0627\u0645\u0644 I assume their aribic characters decoded? How can I perhaps preg replace all these codes with something a little more useful? because search results are filled with pages and pages of this stuff Perhaps even display them as they're supposed to be? Any advice what to do with such strings and how to implement them appreciated.. Please keep in mind this stuff is mixed in been common language letters / numbers many thanks

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  • PHP: prepared statement, IF statement help needed

    - by JGreig
    I have the following code: $sql = "SELECT name, address, city FROM tableA, tableB WHERE tableA.id = tableB.id"; if (isset($price) ) { $sql = $sql . ' AND price = :price '; } if (isset($sqft) ) { $sql = $sql . ' AND sqft >= :sqft '; } if (isset($bedrooms) ) { $sql = $sql . ' AND bedrooms >= :bedrooms '; } $stmt = $dbh->prepare($sql); if (isset($price) ) { $stmt->bindParam(':price', $price); } if (isset($sqft) ) { $stmt->bindParam(':price', $price); } if (isset($bedrooms) ) { $stmt->bindParam(':bedrooms', $bedrooms); } $stmt->execute(); $result_set = $stmt->fetchAll(PDO::FETCH_ASSOC); What I notice is the redundant multiple IF statements I have. Question: is there any way to clean up my code so that I don't have these multiple IF statements for prepared statements?

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  • jquerycropping,codiegniter,php

    - by user345804
    I want to crop the image using jquery,codigniter in jquery i get four coordinate of image x1=249 x2=326 y1=194 y2=271 w=77 h=77 in codiegniter done the query function do_crop() { $x=249; $y=194; $w=77; $h=77; $path= 'system/application/'; $config = array( 'image_library' => 'gd2', 'source_image' => $path.'/jag1/flowers.jpg' , 'new_image' => $path.'/jag2/flowers.jpg', 'maintain_ration' => false, 'width' => $w, 'height' => $h, 'x_axis' => $x, 'y_axis' => $y ); $this->load->library('image_lib'); $this->image_lib->initialize($config); if ( ! $this->image_lib->crop()) { echo $this->image_lib->display_errors(); } $this->image_lib->clear(); } i get cropped image. But problem is don't get exact cropped image x,y coordinate problem

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  • sql select with php variable

    - by user1572526
    I'm trying to print out a html-table from db-table 'dimensions'. I only want dimensions from the selected pipetype which I get from a dropdownbox. For now I just put in "Steel" manually. Steel has pipe_id = 2 in db-table 'pipes'. I've run the first query in my db-tool and it returns 2 so there's nothing wrong there. The second query returns nothing. But when I manually set $wq = 2 (which I comment out below) it prints out the html-table perfectly. What am I doing wrong here? $wq="SELECT pipe_id FROM pipes WHERE title_en = 'Steel'"; //$wq = '2'; $sql="SELECT * FROM dimensions WHERE pipe_id = '".$wq."'";

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  • PHP - Check for whitespace at beginning of string

    - by ITg
    I need to use preg_match to check that only a-z0-9. is used (including full stop(.)). I don't want to replace anything. My problem is that it doesn't notice white space at beginning of a string. Also, if anyone knows how to check there is no two full stops in a row, I would be very grateful. What I have so far: ("/[^a-z0-9.]+$/",$request) Thanks !

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  • php | Multidimensional array sorting

    - by user889349
    I have an array and need to be sorted (based on id): Array ( [0] => Array ( [qty] => 1 [id] => 3 [name] => Name1 [sku] => Model 1 [options] => [price] => 100.00 ) [1] => Array ( [qty] => 2 [id] => 1 [name] => Name2 [sku] => Model 1 [options] => Color: <em>Black (+10$)</em>. Memory: <em>32GB (+99$)</em>. [price] => 209.00 ) ) Is it possible to sort my array to get output (id based)? Array ( [0] => Array ( [qty] => 2 [id] => 1 [name] => Name2 [sku] => Model 1 [options] => Color: <em>Black (+10$)</em>. Memory: <em>32GB (+99$)</em>. [price] => 209.00 ) [1] => Array ( [qty] => 1 [id] => 3 [name] => Name1 [sku] => Model 1 [options] => [price] => 100.00 ) ) Thanks!

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  • unhandled errors in php

    - by lexus
    How can I know during runtime that my code threw a Warning? example try { echo (25/0); } catch (exception $exc) { echo "exception catched"; } throws a "Warning: Division by zero" error that i can not handle on my code.

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  • How to pass parameters dynamically in PHP?

    - by user198729
    I need to pass the $route to its inner function,but failed: function compilePath( $route ) { preg_replace( '$:([a-z]+)$i', 'pathOption' , $route['path'] ); function pathOption($matches) { global $route;//fail to get the $route } } I'm using php5.3,is there some feature that can help?

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