Problem in using a second call to send() in C
- by Paulo Victor
Hello. Right now I'm working in a simple Server that receives from client a code referring to a certain operation. The server receives this data and send back the signal that it's waiting for the proper data.
/*Server Side*/
if (codigoOperacao == 0)
{
printf("A escolha foi 0\n");
int bytesSent = SOCKET_ERROR;
char sendBuff[1080] = "0";
/*Here "send" returns an error msgm while trying to send back the signal*/
bytesSent = send(socketEscuta, sendBuff, 1080, 0);
if (bytesSent == SOCKET_ERROR)
{
printf("Erro ao enviar");
return 0;
}
else
{
printf("Bytes enviados : %d\n", bytesSent);
char structDesmontada[1080] = "";
bytesRecv = recebeMensagem(socketEscuta, structDesmontada);
printf("structDesmontada : %s", structDesmontada);
}
}
Following here is the client code responsible for sending the operation code and receiving the signal
char sendMsg[1080] = "0";
char recvMsg[1080] = "";
bytesSent = send(socketCliente, sendMsg, sizeof(sendMsg), 0);
printf("Enviei o codigo (%d)\n", bytesSent);
/*Here the program blocks in a infinite loop since the server never send anything*/
while (bytesRecv == SOCKET_ERROR)
{
bytesRecv = recv(socketCliente, recvMsg, 1080, 0);
if (bytesRecv > 0)
{
printf("Recebeu\n");
}
Why this is happening only in the second attempt to send some data? Because the first call to send() works fine.
Hope someone can help!!
Thnks
