Search Results

Search found 14399 results on 576 pages for 'python noob'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 329/576 | < Previous Page | 325 326 327 328 329 330 331 332 333 334 335 336  | Next Page >

  • Should I mix wxpython and pyobjc ?

    - by Anurag Uniyal
    I have a wxPython based app which I am porting to Mac OS X, in that I need to show some alerts which should look like native mac alerts, so I am using pyobjc for that e.g. import Cocoa import wx app = wx.PySimpleApp() frame = wx.Frame(None, title="mac alert test") app.SetTopWindow(frame) frame.Show() def onclick(event): Cocoa.CFUserNotificationDisplayAlert(0, 3, 0, 0, 0, "Should i mix wxpython and objc", "hmmm...", "Cool", "Not Cool", "Whatever") frame.Bind(wx.EVT_LEFT_DOWN, onclick) app.MainLoop() Is there any thing wrong in such mixing of wx and objc code, any failure points ?

    Read the article

  • s/mime v3 with M2Crypto

    - by Arye
    Dear list, I would like to send a mail with a s/mime v3 attachment through SMTP. The excellent HOWTO below describes the procedure in detail for s/mime v2. http://sandbox.rulemaker.net/ngps/m2/howto.smime.html I would greatly appreciate any help in doing the same for s/mime v3. Arye.

    Read the article

  • How to stop a QDialog from executing while still in the __init__ statement(or immediatly after)?

    - by Jonathan
    I am wondering how I can go about stopping a dialog from opening if certain conditions are met in its __init__ statement. The following code tries to call the 'self.close()' function and it does, but (I'm assuming) since the dialog has not yet started its event loop, that it doesn't trigger the close event? So is there another way to close and/or stop the dialog from opening without triggering an event? Example code: from PyQt4 import QtCore, QtGui class dlg_closeInit(QtGui.QDialog): ''' Close the dialog if a certain condition is met in the __init__ statement ''' def __init__(self): QtGui.QDialog.__init__(self) self.txt_mytext = QtGui.QLineEdit('some text') self.btn_accept = QtGui.QPushButton('Accept') self.myLayout = QtGui.QVBoxLayout(self) self.myLayout.addWidget(self.txt_mytext) self.myLayout.addWidget(self.btn_accept) self.setLayout(self.myLayout) # Connect the button self.connect(self.btn_accept,QtCore.SIGNAL('clicked()'), self.on_accept) self.close() def on_accept(self): # Get the data... self.mydata = self.txt_mytext.text() self.accept() def get_data(self): return self.mydata def closeEvent(self, event): print 'Closing...' if __name__ == '__main__': import sys app = QtGui.QApplication(sys.argv) dialog = dlg_closeInit() if dialog.exec_(): print dialog.get_data() else: print "Failed"

    Read the article

  • Migration for creating and deleting model in South

    - by Almad
    I've created a model and created initial migration for it: db.create_table('tvguide_tvguide', ( ('id', models.AutoField(primary_key=True)), ('date', models.DateField(_('Date'), auto_now=True, db_index=True)), )) db.send_create_signal('tvguide', ['TVGuide']) models = { 'tvguide.tvguide': { 'channels': ('models.ManyToManyField', ["orm['tvguide.Channel']"], {'through': "'ChannelInTVGuide'"}), 'date': ('models.DateField', ["_('Date')"], {'auto_now': 'True', 'db_index': 'True'}), 'id': ('models.AutoField', [], {'primary_key': 'True'}) } } complete_apps = ['tvguide'] Now, I'd like to drop it: db.drop_table('tvguide_tvguide') However, I have also deleted corresponding model. South (at least 0.6.2) is however trying to access it: (venv)[almad@eva-03 project]$ ./manage.py migrate tvguide Running migrations for tvguide: - Migrating forwards to 0002_removemodels. > tvguide: 0001_initial Traceback (most recent call last): File "./manage.py", line 27, in <module> execute_from_command_line() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 353, in execute_from_command_line utility.execute() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 222, in execute output = self.handle(*args, **options) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/management/commands/migrate.py", line 91, in handle skip = skip, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 581, in migrate_app result = run_forwards(mapp, [mname], fake=fake, db_dry_run=db_dry_run, verbosity=verbosity) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 388, in run_forwards verbosity = verbosity, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 287, in run_migrations orm = klass.orm File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 62, in __get__ self.orm = FakeORM(*self._args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 45, in FakeORM _orm_cache[args] = _FakeORM(*args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 106, in __init__ self.models[name] = self.make_model(app_name, model_name, data) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 307, in make_model tuple(map(ask_for_it_by_name, bases)), File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 23, in ask_for_it_by_name ask_for_it_by_name.cache[name] = _ask_for_it_by_name(name) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 17, in _ask_for_it_by_name return getattr(module, bits[-1]) AttributeError: 'module' object has no attribute 'TVGuide' Is there a way around?

    Read the article

  • QTreeWidget insertTopLevelItem - index given not accurately displayed in Tree?

    - by mleep
    I am unable to properly insert a QTreeWidgetItem at a specific index, in this case I am removing all QTreeWidgetItems from the tree, doing a custom sort on their Date Objects and then inserting them back into the QTreeWidget. However, upon inserting (even one at a time) the QTreeWidgetItem is not inserted into the correct place. The code below prints out: index 0: 0 index 0: 1 index 1: 0 index 0: 2 index 1: 1 index 2: 0 index 0: 3 index 1: 2 index 2: 0 index 3: 1 index 0: 4 index 1: 2 index 2: 0 index 3: 1 index 4: 3 print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]) self.insertTopLevelItem(0, childrenList[1]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]), ' index 1: ',\ self.indexOfTopLevelItem(childrenList[1]) self.insertTopLevelItem(0, childrenList[2]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]), ' index 1: ',\ self.indexOfTopLevelItem(childrenList[1]), ' index 2: ', \ self.indexOfTopLevelItem(childrenList[2]) self.insertTopLevelItem(0, childrenList[3]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]), ' index 1: ',\ self.indexOfTopLevelItem(childrenList[1]), ' index 2: ',\ self.indexOfTopLevelItem(childrenList[2]), 'index 3: ',\ self.indexOfTopLevelItem(childrenList[3]) self.insertTopLevelItem(0, childrenList[4]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]),\ ' index 1: ', self.indexOfTopLevelItem(childrenList[1]),\ ' index 2: ', self.indexOfTopLevelItem(childrenList[2]),\ 'index 3: ', self.indexOfTopLevelItem(childrenList[3]),\ 'index 4: ', self.indexOfTopLevelItem(childrenList[4])

    Read the article

  • Web Security: Worst-Case Situation

    - by Yongho
    I currently have built a system that checks user IP, browser, and a random-string cookie to determine if he is an admin. In the worst case, someone steals my cookie, uses the same browser I do, and masks his IP to appear as mine. Is there another layer of security I should add onto my script to make it more secure?

    Read the article

  • django-mptt: how to successfully move nodes around

    - by Parand
    django-mptt seems determined to drive me out of my mind. I'm trying to do something relatively simple: I'm going to delete a node, and need to do something reasonable with the node's children. Namely, I'd like to move them up one level so they're children of their current parent's parent. That is, if the tree looks like: Root | Grandpa | Father | | C1 C2 I'm going to delete Father, and would like C1 and C2 to be children of Grandpa. Here's the code I'm using: class Node(models.Model): first_name = models.CharField(max_length=80, blank=True) parent = models.ForeignKey('self', null=True, blank=True, related_name='children') def reparent_children(self, parent): print "Reparenting" for child in self.get_children(): print "Working on", child.first_name, "to parent", parent.email parent = Node.objects.get(id=parent.id) child.move_to(parent, 'last-child') child.save() So I'd call: father.reparent_children(grandpa) father.parent = None father.save() This works - almost. The children report their parents as Grandpa: c1.parent == grandpa # True Grandpa counts C1 and C2 among its children c1 in grandpa.children.all() # True However, Root disowns these kids. c1.get_root() == father # c1's root is father, instead of Root c1 in root.get_descendants() # False How do I get the children to move and their root not get corrupted?

    Read the article

  • In Django, can you add a method to querysets?

    - by Paul D. Waite
    In Django, if I have a model class, e.g. from django.db import models class Transaction(models.Model): ... then if I want to add methods to the model, to store reasonably complex filters, I can add a custom model manager, e.g. class TransactionManager(models.Manager): def reasonable_complex_filter(self): return self.get_query_set().filter(...) class Transaction(models.Model): objects = TransactionManager() And then I can do: >>> Transaction.objects.reasonably_complex_filter() Is there any way I can add a custom method that can be chained to the end of a query set from the model? I.e. add the custom method in such a way that I can do this: >>> Transaction.objects.filter(...).reasonably_complex_filter()

    Read the article

  • Using scipy.interpolate.splrep function

    - by Koustav Ghosal
    I am trying to fit a cubic spline to a given set of points. My points are not ordered. I CANNOT sort or reorder the points, since I need that information. But since the function scipy.interpolate.splrep works only on non-duplicate and monotonically increasing points I have defined a function that maps the x-coordinates to a monotonically increasing space. My old points are: xpoints=[4913.0, 4912.0, 4914.0, 4913.0, 4913.0, 4913.0, 4914.0, 4915.0, 4918.0, 4921.0, 4925.0, 4932.0, 4938.0, 4945.0, 4950.0, 4954.0, 4955.0, 4957.0, 4956.0, 4953.0, 4949.0, 4943.0, 4933.0, 4921.0, 4911.0, 4898.0, 4886.0, 4874.0, 4865.0, 4858.0, 4853.0, 4849.0, 4848.0, 4849.0, 4851.0, 4858.0, 4864.0, 4869.0, 4877.0, 4884.0, 4893.0, 4903.0, 4913.0, 4923.0, 4935.0, 4947.0, 4959.0, 4970.0, 4981.0, 4991.0, 5000.0, 5005.0, 5010.0, 5015.0, 5019.0, 5020.0, 5021.0, 5023.0, 5025.0, 5027.0, 5027.0, 5028.0, 5028.0, 5030.0, 5031.0, 5033.0, 5035.0, 5037.0, 5040.0, 5043.0] ypoints=[10557.0, 10563.0, 10567.0, 10571.0, 10575.0, 10577.0, 10578.0, 10581.0, 10582.0, 10582.0, 10582.0, 10581.0, 10578.0, 10576.0, 10572.0, 10567.0, 10560.0, 10550.0, 10541.0, 10531.0, 10520.0, 10511.0, 10503.0, 10496.0, 10490.0, 10487.0, 10488.0, 10488.0, 10490.0, 10495.0, 10504.0, 10513.0, 10523.0, 10533.0, 10542.0, 10550.0, 10556.0, 10559.0, 10560.0, 10559.0, 10555.0, 10550.0, 10543.0, 10533.0, 10522.0, 10514.0, 10505.0, 10496.0, 10490.0, 10486.0, 10482.0, 10481.0, 10482.0, 10486.0, 10491.0, 10497.0, 10506.0, 10516.0, 10524.0, 10534.0, 10544.0, 10552.0, 10558.0, 10564.0, 10569.0, 10573.0, 10576.0, 10578.0, 10581.0, 10582.0] Plots: The code for the mapping function and interpolation is: xnew=[] ynew=ypoints for c3,i in enumerate(xpoints): if np.isfinite(np.log(i*pow(2,c3))): xnew.append(np.log(i*pow(2,c3))) else: if c==0: xnew.append(np.random.random_sample()) else: xnew.append(xnew[c3-1]+np.random.random_sample()) xnew=np.asarray(xnew) ynew=np.asarray(ynew) constant1=10.0 nknots=len(xnew)/constant1 idx_knots = (np.arange(1,len(xnew)-1,(len(xnew)-2)/np.double(nknots))).astype('int') knots = [xnew[i] for i in idx_knots] knots = np.asarray(knots) int_range=np.linspace(min(xnew),max(xnew),len(xnew)) tck = interpolate.splrep(xnew,ynew,k=3,task=-1,t=knots) y1= interpolate.splev(int_range,tck,der=0) The code is throwing an error at the function interpolate.splrep() for some set of points like the above one. The error is: File "/home/neeraj/Desktop/koustav/res/BOS5/fit_spline3.py", line 58, in save_spline_f tck = interpolate.splrep(xnew,ynew,k=3,task=-1,t=knots) File "/usr/lib/python2.7/dist-packages/scipy/interpolate/fitpack.py", line 465, in splrep raise _iermessier(_iermess[ier][0]) ValueError: Error on input data But for other set of points it works fine. For example for the following set of points. xpoints=[1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1630.0, 1630.0, 1630.0, 1631.0, 1631.0, 1631.0, 1631.0, 1630.0, 1629.0, 1629.0, 1629.0, 1628.0, 1627.0, 1627.0, 1625.0, 1624.0, 1624.0, 1623.0, 1620.0, 1618.0, 1617.0, 1616.0, 1615.0, 1614.0, 1614.0, 1612.0, 1612.0, 1612.0, 1611.0, 1610.0, 1609.0, 1608.0, 1607.0, 1607.0, 1603.0, 1602.0, 1602.0, 1601.0, 1601.0, 1600.0, 1599.0, 1598.0] ypoints=[10570.0, 10572.0, 10572.0, 10573.0, 10572.0, 10572.0, 10571.0, 10570.0, 10569.0, 10565.0, 10564.0, 10563.0, 10562.0, 10560.0, 10558.0, 10556.0, 10554.0, 10551.0, 10548.0, 10547.0, 10544.0, 10542.0, 10541.0, 10538.0, 10534.0, 10532.0, 10531.0, 10528.0, 10525.0, 10522.0, 10519.0, 10517.0, 10516.0, 10512.0, 10509.0, 10509.0, 10507.0, 10504.0, 10502.0, 10500.0, 10501.0, 10499.0, 10498.0, 10496.0, 10491.0, 10492.0, 10488.0, 10488.0, 10488.0, 10486.0, 10486.0, 10485.0, 10485.0, 10486.0, 10483.0, 10483.0, 10482.0, 10480.0] Plots: Can anybody suggest what's happening ?? Thanks in advance......

    Read the article

  • Good example usage of get_or _create in Django views and raising a Form error

    - by Rik Wade
    I would like to use get_or_create to check whether an object already exists in my database. If it does not, then it will be created. If it does exist, then I will not create the new object, but need to raise a form error to inform the user that they need to enter different data (for example, a different username). The view contains: p, created = Person.objects.get_or_create( email = registration_form.cleaned_data['email'], defaults = { 'creationDate': datetime.datetime.now(), 'dateOfBirth': datetime.date(1970,1,1) }) So 'p' will contain the existing Person if it exists, or the new Person if not. I would like to act on the boolean value in 'created' in order to skip over saving the Person and re-display the registration_form and raise an appropriate form validation error. The alternative I'm considering is doing a check in a custom Form validation method to see whether a Person exists with the data in the provided 'email' field, and just raising a validation error.

    Read the article

  • [PyGTK] How to Create a Multiline Button

    - by EShull
    I'm trying to create a multiline button with PyGTK. I have a label added to my subclass of gtk.Button, but I'm having trouble sizing the label to the button. If the label makes it's own size, there is no text wrapping even with label.set_line_wrap(True) because the label simply resizes beyond the bounds of the button. I would set the size of the label to that of the button, but unless I explicitly set the size of the button using set_size_request, I haven't been able to find out how big the button is (it's packed in a table). Any suggestions?

    Read the article

  • Extended Django base-class with multiple instances

    - by Gijs
    I'm modeling a simple movie database using Django. models.py defines a base model Person. I extend Person into Actor and Director, which works as I imagined. Persons must be unique. When (in the Admin) I create an instance of Actor, and this person is also a Director, it won't save because of the unique = True. Any ideas how to solve this problem? (generic foreign keys?) Thx

    Read the article

  • Inline editing of ManyToMany relation in Django

    - by vorpyg
    After working through the Django tutorial I'm now trying to build a very simple invoicing application. I want to add several Products to an Invoice, and to specify the quantity of each product in the Invoice form in the Django admin. Now I've to create a new Product object if I've got different quantites of the same Product. Right now my models look like this (Company and Customer models left out): class Product(models.Model): description = models.TextField() quantity = models.IntegerField() price = models.DecimalField(max_digits=10,decimal_places=2) tax = models.ForeignKey(Tax) class Invoice(models.Model): company = models.ForeignKey(Company) customer = models.ForeignKey(Customer) products = models.ManyToManyField(Product) invoice_no = models.IntegerField() invoice_date = models.DateField(auto_now=True) due_date = models.DateField(default=datetime.date.today() + datetime.timedelta(days=14)) I guess the quantity should be left out of the Product model, but how can I make a field for it in the Invoice model?

    Read the article

  • Edit nested dictionary with limited information

    - by user1082764
    How can i change the 'space' of 'albert' if i dont know if he is a donkey or a zebra? self.object_attr = {'donkey': { 'name': 'roger', 'zone': 'forrest', 'space': [0, 0]}{ 'name': 'albert', 'zone': 'forrest', 'space': [1, 1]} 'zebra': { 'name': 'roger', 'zone': 'forrest', 'space': [0, 0]}{ 'name': 'albert', 'zone': 'forrest', 'space': [1, 1]}} This can search for albert in the dictionary but how can i change his location? for i in self.object_attr for j in self.object_attr[x][name] if j == 'albert'

    Read the article

  • Fetch Facebook ID with PyFacebook, "Session key is required"

    - by ensnare
    I'm trying to fetch the logged in user's ID with Facebook + PyFacebook via: #Establish connection to Facebook via API f = Facebook(config['app_conf']['pyfacebook.apikey'], config['app_conf']['pyfacebook.secret']) #Get the current Facebook ID facebook_id = f.users.getLoggedInUser() But I keep getting the error: FacebookError: Error 453: A session key is required for calling this method What am I doing wrong? Thanks.

    Read the article

  • Django Admin Page missing CSS

    - by super9
    I saw this question and recommendation from Django Projects here but still can't get this to work. My Django Admin pages are not displaying the CSS at all. This is my current configuration. settings.py ADMIN_MEDIA_PREFIX = '/media/admin/' httpd.conf <VirtualHost *:80> DocumentRoot /home/django/sgel ServerName ec2-***-**-***-***.ap-**********-1.compute.amazonaws.com ErrorLog /home/django/sgel/logs/apache_error.log CustomLog /home/django/sgel/logs/apache_access.log combined WSGIScriptAlias / /home/django/sgel/apache/django.wsgi <Directory /home/django/sgel/media> Order deny,allow Allow from all </Directory> <Directory /home/django/sgel/apache> Order deny,allow Allow from all </Directory> LogLevel warn Alias /media/ /home/django/sgel/media/ </VirtualHost> <VirtualHost *:80> ServerName sgel.com Redirect permanent / http://www.sgel.com/ </VirtualHost> In addition, I also ran the following to create (I think) the symbolic link ln -s /home/djangotest/sgel/media/admin/ /usr/lib/python2.6/site-packages/django/contrib/admin/media/ UPDATE In my httpd.conf file, User django Group django When I run ls -l in my /media directory drwxr-xr-x 2 root root 4096 Apr 4 11:03 admin -rw-r--r-- 1 root root 9 Apr 8 09:02 test.txt Should that root user be django instead? UPDATE 2 When I enter ls -la in my /media/admin folder total 12 drwxr-xr-x 2 root root 4096 Apr 13 03:33 . drwxr-xr-x 3 root root 4096 Apr 8 09:02 .. lrwxrwxrwx 1 root root 60 Apr 13 03:33 media -> /usr/lib/python2.6/site-packages/django/contrib/admin/media/ The thing is, when I navigate to /usr/lib/python2.6/site-packages/django/contrib/admin/media/, the folder was empty. So I copied the CSS, IMG and JS folders from my Django installation into /usr/lib/python2.6/site-packages/django/contrib/admin/media/ and it still didn't work

    Read the article

  • Modifying Bresenham's line algorithm

    - by sphennings
    I'm trying to use Bresenham's line algorithm to compute Field of View on a grid. The code I'm using calculates the lines without a problem but I'm having problems getting it to always return the line running from start point to endpoint. What do I need to do so that all lines returned run from (x0,y0) to (x1,y1) def bresenham_line(self, x0, y0, x1, y1): steep = abs(y1 - y0) > abs(x1 - x0) if steep: x0, y0 = y0, x0 x1, y1 = y1, x1 if x0 > x1: x0, x1 = x1, x0 y0, y1 = y1, y0 if y0 < y1: ystep = 1 else: ystep = -1 deltax = x1 - x0 deltay = abs(y1 - y0) error = -deltax / 2 y = y0 line = [] for x in range(x0, x1 + 1): if steep: line.append((y,x)) else: line.append((x,y)) error = error + deltay if error > 0: y = y + ystep error = error - deltax return line

    Read the article

  • How do I pass a lot of parameters to views in Django?

    - by Mark
    I'm very new to Django and I'm trying to build an application to present my data in tables and charts. Till now my learning process went very smooth, but now I'm a bit stuck. My pageview retrieves large amounts of data from a database and puts it in the context. The template then generates different html-tables. So far so good. Now I want to add different charts to the template. I manage to do this by defining <img src=".../> tags. The Matplotlib chart is generate in my chartview an returned via: response=HttpResponse(content_type='image/png') canvas.print_png(response) return response Now I have different questions: the data is retrieved twice from the database. Once in the pageview to render the tables, and again in the chartview for making the charts. What is the best way to pass the data, already in the context of the page to the chartview? I need a lot of charts, each with different datasets. I could make a chartview for each chart, but probably there is a better way. How do I pass the different dataset names to the chartview? Some charts have 20 datasets, so I don't think that passing these dataset parameters via the url (like: <imgm src="chart/dataset1/dataset2/.../dataset20/chart.png />) is the right way. Any advice?

    Read the article

  • Django - provide additional information in template

    - by Ninefingers
    Hi all, I am building an app to learn Django and have started with a Contact system that currently stores Contacts and Addresses. C's are a many to many relationship with A's, but rather than use Django's models.ManyToManyField() I've created my own link-table providing additional information about the link, such as what the address type is to the that contact (home, work etc). What I'm trying to do is pass this information out to a view, so in my full view of a contact I can do this: def contact_view_full(request, contact_id): c = get_object_or_404(Contact, id=contact_id) a = [] links = ContactAddressLink.objects.filter(ContactID=c.id) for link in links: b = Address.objects.get(id=link.AddressID_id) a.append(b) return render_to_response('contact_full.html', {'contact_item': c, 'addresses' : a }, context_instance=RequestContext(request)) And so I can do the equivalent of c.Addresses.all() or however the ManyToManyField works. What I'm interested to know is how can I pass out information about the link in the link object with the 'addresses' : a information, so that when my template does this: {% for address in addresses %} <!-- ... --> {% endfor %} and properly associate the correct link object data with the address. So what's the best way to achieve this? I'm thinking a union of two objects might be an idea but I haven't enough experience with Django to know if that's considered the best way of doing it. Suggestions? Thanks in advance. Nf

    Read the article

  • How to keep text inside a circle using Cairo?

    - by miguelrios
    I a drawing a graph using Cairo (pycairo specifically) and I need to know how can I draw text inside a circle without overlapping it, by keeping it inside the bounds of the circle. I have this simple code snippet that draws a letter "a" inside the circle: ''' Created on May 8, 2010 @author: mrios ''' import cairo, math WIDTH, HEIGHT = 1000, 1000 #surface = cairo.PDFSurface ("/Users/mrios/Desktop/exampleplaces.pdf", WIDTH, HEIGHT) surface = cairo.ImageSurface (cairo.FORMAT_ARGB32, WIDTH, HEIGHT) ctx = cairo.Context (surface) ctx.scale (WIDTH/1.0, HEIGHT/1.0) # Normalizing the canvas ctx.rectangle(0, 0, 1, 1) # Rectangle(x0, y0, x1, y1) ctx.set_source_rgb(255,255,255) ctx.fill() ctx.arc(0.5, 0.5, .4, 0, 2*math.pi) ctx.set_source_rgb(0,0,0) ctx.set_line_width(0.03) ctx.stroke() ctx.arc(0.5, 0.5, .4, 0, 2*math.pi) ctx.set_source_rgb(0,0,0) ctx.set_line_width(0.01) ctx.set_source_rgb(255,0,255) ctx.fill() ctx.set_source_rgb(0,0,0) ctx.select_font_face("Georgia", cairo.FONT_SLANT_NORMAL, cairo.FONT_WEIGHT_BOLD) ctx.set_font_size(1.0) x_bearing, y_bearing, width, height = ctx.text_extents("a")[:4] print ctx.text_extents("a")[:4] ctx.move_to(0.5 - width / 2 - x_bearing, 0.5 - height / 2 - y_bearing) ctx.show_text("a") surface.write_to_png ("/Users/mrios/Desktop/node.png") # Output to PNG The problem is that my labels have variable amount of characters (with a limit of 20) and I need to set the size of the font dynamically. It must fit inside the circle, no matter the size of the circle nor the size of the label. Also, every label has one line of text, no spaces, no line breaks. Any suggestion?

    Read the article

  • Django: reverse lookup URL of feeds?

    - by Santa
    I am having trouble doing a reverse URL lookup for Django-generated feeds. I have the following setup in urls.py: feeds = { 'latest': LatestEntries, } urlpatterns = patterns('', # ... # enable feeds (RSS) url(r'^feeds/(?P<url>.*)/$', 'django.contrib.syndication.views.feed', {'feed_dict': feeds}, name='feeds_view'), ) I have tried using the following template tag: <a href="{% url feeds_view latest %}">RSS feeds</a> But the resulting link is not what want (http://my.domain.com/feeds//). It should be http://my.domain.com/feeds/latest/. For now, I am using a hack to generate the URL for the template: <a href="http://{{ request.META.HTTP_HOST }}/feeds/latest">RSS feeds</a> But, as you can see, it clearly is not DRY. Is there something I am missing?

    Read the article

  • Copying contents of a module

    - by Hulk
    If there exists an old data of a model say , query=Emp.objects.filter(pk=profile.id) Is there a easier way to copy the same values into the same model again.. Now that the id will be different so.. I have this requirement. Thanks..

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 325 326 327 328 329 330 331 332 333 334 335 336  | Next Page >