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• how to save django object using dictionary?

  - by shahjapan

  is there a way that I can save the model by using dictionary for e.g. this is working fine, p1 = Poll.objects.get(pk=1) p1.name = 'poll2' p1.descirption = 'poll2 description' p1.save() but what if I have dictionary like { 'name': 'poll2', 'description: 'poll2 description' } is there a simple way to save the such dictionary direct to Poll

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• How can I handle dynamic calculated attributes in a model in Django?

  - by bullfish

  In Django I calculate the breadcrumb (a list of fathers) for an geographical object. Since it is not going to change very often, I am thinking of pre calculating it once the object is saved or initialized. 1.) What would be better? Which solution would have a better performance? To calculate it at _init_ or to calculate it when the object is saved (the object takes about 500-2000 characters in the DB)? 2.) I tried to overwrite the _init_ or save() methods but I don't know how to use attributes of the just saved object. Accessing *args, **kwargs did not work. How can I access them? Do I have to save, access the father and then save again? 3.) If I decide to save the breadcrumb. Whats the best way to do it? I used http://www.djangosnippets.org/snippets/1694/ and have crumb = PickledObjectField(). Thats the method to calculate the attribute crumb() def _breadcrumb(self): breadcrumb = [ ] x = self while True: x = x.father try: if hasattr(x, 'country'): breadcrumb.append(x.country) elif hasattr(x, 'region'): breadcrumb.append(x.region) elif hasattr(x, 'city'): breadcrumb.append(x.city) else: break except: break breadcrumb.reverse() return breadcrumb Thats my save-Method: def save(self,*args, **kwargs): # how can I access the father ob the object? father = self.father # does obviously not work father = kwargs['father'] # does not work either # the breadcrumb gets calculated here self.crumb = self._breadcrumb(father) super(GeoObject, self).save(*args,**kwargs) Please help me out. I am working on this for days now. Thank you.

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• Incremement Page Hit Count in Django

  - by Andrew C

  I have a table with an IntegerField (hit_count), and when a page is visited (ie. http://site/page/3) I want record id 3 'hit_count' column in the database to increment by 1. The query should be like: update table set hit_count = hit_count + 1 where id=3 Can I do this with the standard Django Model conventions? Or should I just write the query by hand? I'm starting a new project, so I am trying to avoid hacks. We'll see how long this lasts! Thanks!

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• Polymorphic :has_many, :through as module in Rails 3.1 plugin

  - by JohnMetta

  I've search everywhere for a pointer to this, but can't find one. Basically, I want to do what everyone else wants to do when they create a polymorphic relationship in a :has_many, :through way… but I want to do it in a module. I keep getting stuck and think I must be overlooking something simple. To wit: module ActsPermissive module PermissiveUser def self.included(base) base.extend ClassMethods end module ClassMethods def acts_permissive has_many :ownables has_many :owned_circles, :through => :ownables end end end class PermissiveCircle < ActiveRecord::Base belongs_to :ownable, :polymorphic => true end end With a migration that looks like this: create_table :permissive_circles do |t| t.string :ownable_type t.integer :ownable_id t.timestamps end The idea, of course, is that whatever loads acts_permissive will be able to have a list of circles that it owns. For simple tests, I have it "should have a list of circles" do user = Factory :user user.owned_circles.should be_an_instance_of Array end which fails with: Failure/Error: @user.circles.should be_an_instance_of Array NameError: uninitialized constant User::Ownable I've tried: using :class_name => 'ActsPermissive::PermissiveCircle' on the has_many :ownables line, which fails with: Failure/Error: @user.circles.should be_an_instance_of Array ActiveRecord::HasManyThroughSourceAssociationNotFoundError: Could not find the source association(s) :owned_circle or :owned_circles in model ActsPermissive::PermissiveCircle. Try 'has_many :owned_circles, :through => :ownables, :source => <name>'. Is it one of :ownable? while following the suggestion and setting :source => :ownable fails with Failure/Error: @user.circles.should be_an_instance_of Array ActiveRecord::HasManyThroughAssociationPolymorphicSourceError: Cannot have a has_many :through association 'User#owned_circles' on the polymorphic object 'Ownable#ownable' Which seems to suggest that doing things with a non-polymorphic-through is necessary. So I added a circle_owner class similar to the setup here: module ActsPermissive class CircleOwner < ActiveRecord::Base belongs_to :permissive_circle belongs_to :ownable, :polymorphic => true end module PermissiveUser def self.included(base) base.extend ClassMethods end module ClassMethods def acts_permissive has_many :circle_owners, :as => :ownable has_many :circles, :through => :circle_owners, :source => :ownable, :class_name => 'ActsPermissive::PermissiveCircle' end end class PermissiveCircle < ActiveRecord::Base has_many :circle_owners end end With a migration: create_table :permissive_circles do |t| t.string :name t.string :guid t.timestamps end create_table :circle_owner do |t| t.string :ownable_type t.string :ownable_id t.integer :permissive_circle_id end which still fails with: Failure/Error: @user.circles.should be_an_instance_of Array NameError: uninitialized constant User::CircleOwner Which brings us back to the beginning. How can I do what seems to be a rather common polymorphic :has_many, :through on a module? Alternatively, is there a good way to allow an object to be collected by arbitrary objects in a similar way that will work with a module?

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• Difference in Django object creation call

  - by PhilGo20

  I'd like to know if there's a difference between the following two calls to create an object in Django Animal.objects.create(name="cat", sound="meow") and Animal(name="cat", sound="meow") I see both in test cases and I want to make sure I am not missing something. thanks

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• Saving model object in django throws no error but attribute value doesn't change

  - by Pilgrim

  Hi. I get a model object, change an attribute, save it and it still has the old attribute: >>> g = SiteProfile.objects.get(pk=3) >>> g.renew_date datetime.date(2010, 4, 11) >>> g.renew_date = date.today()+timedelta(days=365) >>> g.renew_date datetime.date(2011, 4, 11) >>> g.save() >>> g.renew_date datetime.datetime(2010, 4, 11, 16, 57, 4, 192684) Anyone know if this is an issue with the database or something else?

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• Django: How can I protect against concurrent modification of data base entries

  - by Ber

  If there a way to protect against concurrent modifications of the same data base entry by two or more users? It would be acceptable to show an error message to the user performing the second commit/save operation, but data should not be silently overwritten. I think locking the entry is not an option, as a user might use the "Back" button or simply close his browser, leaving the lock for ever.

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• Change model name in rails easily

  - by Kenji Crosland

  I'm going to need to change one of my model names. Is there anything out there that will replace every instance of the original model name in the controllers views and tests or do I have to do it all manually, page by page?

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• Rails link from one model to another based on db field?

  - by Danny McClelland

  Hi Everyone, I have a company model and a person model with the following relationships: class Company < ActiveRecord::Base has_many :kases has_many :people def to_s; companyname; end end class Person < ActiveRecord::Base has_many :kases # foreign key in join table belongs_to :company end In the create action for the person, I have a select box with a list of the companies, which assigns a company_id to that person's record: <%= f.select :company_id, Company.all.collect {|m| [m.companyname, m.id]} %> In the show view for the person I can list the company name as follows: <%=h @person.company.companyname %> What I am trying to work out, is how do I make that a link to the company record? I have tried: <%= link_to @person.company.companyname %> but that just outputs the company name inside a href tag but links to the current page. Thanks, Danny

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• How can I copy a queryset to a new model in django admin?

  - by user3806832

  I'm trying to write an action that allows the user to select the queryset and copy it to a new table. So: John, Mark, James, Tyler and Joe are in a table 1( called round 1) The user selects the action that say to "move to next round" and those same instances that were chosen are now also in the table for "round 2". I started trying with an action but don't really know where to go from here: def Round_2(modeladmin, request, queryset): For X in queryset: X.pk = None perform.short_description = "Move to Round 2" How can I copy them to the next table with all of their information (pk doesn't have to be the same)? Thanks

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• changing the saved contents of the model , edit model fileds once saved

  - by imran-glt

  hi I have extended the user model and added extra fields to it i.e "latitude" "longitude" and status and than save it. up to here it works fine. but i want to allow the user to change his/her "latitude" "longitude" whenever he/she needs like the hotmail and yahoo allows change account feature. in my case the user only wants to chage the latitude and longitude i tried it in this way but it didnt work. is this the right way to do it ...... or is there any other way to change the saved contents view.py def status_change(request): print "status_change function called" if request.method == "POST": rform = registerForm(data = request.POST) uform = UserForm(data = request.POST) if rform.is_valid(): user = uform.save() register = rform.save() register.user = user register.save() return render_to_response('home.html') else: rform = registerForm() return render_to_response('status_change.html',{'rform':rform})

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• How can I support conditional validation of model properties

  - by Jeff

  I currently have a form that I am building that needs to support two different versions. Each version might use a different subset of form fields. I have to do this to support two different clients, but I don't want to have entirely different controller actions for both. So, I am trying to come up with a way to use a strongly typed model with validation attributes but have some of these attributes be conditional. Some approaches I can think of is similar to steve sanderson's partial validation approach. Where I would clear the model errors in a filter OnActionExecuting based on which version of the form was active. The other approach I was thinking of would to break the model up into pieces using something like class FormModel { public Form1 Form1Model {get; set;} public Form2 FormModel {get; set;} } and then we would validate appropriately depending on

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• Django: FloatField or DecimalFied for Currency ?

  - by Hellnar

  I am curious which one would be better fitting as a currency field ? I will do simple operations such as taking difference, the percentage between old and new prices. I plan to keep two digits after the zero (ie 10.50) and majority of the time if these digits are zero, I will be hiding these numbers and display it as "10"

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• How to change Zend_Db_Table name within a Model to insert in multiple tables

  - by jwhat

  Using Zend Framework, I've created a Model to insert a record into a database. My question is, after $this->insert($data) how can I switch the active table so that I can insert a record into another table? Here's my code so far: class Model_DbTable_Foo extends Zend_Db_Table_Abstract { protected $_name = 'foo'; public function addFoo($params) { $data = array( 'foo' => $params['foo'], ); $this->insert($data); $foo_id = $this->getAdapter()->lastInsertId(); $data2 = array( 'bar' => $params['bar'] ); // I need to change the Db Table name here. $this->insert($data2); $bar_id = $this->getAdapter()->lastInsertId(); } }

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• Django IntegrityError: foreign key violation upon delete

  - by Lukasz Korzybski

  I have Order and Shipment model. Shipment has a foreign key to Order. class Order(...): ... class Shipment() order = m.ForeignKey('Order') ... Now in one of my views I want do delete order object along with all related objects. So I invoke order.delete(). I have Django 1.0.4, PostgreSQL 8.4 and I use transaction middleware, so whole request is enclosed in single transaction. The problem is that upon order.delete() I get: ... File "/usr/local/lib/python2.6/dist-packages/django/db/backends/__init__.py", line 28, in _commit return self.connection.commit() IntegrityError: update or delete on table "main_order" violates foreign key constraint "main_shipment_order_id_fkey" on table "main_shipment" DETAIL: Key (id)=(45) is still referenced from table "main_shipment". I checked in connection.queries that proper queries are executed in proper order. First shipment is deleted, after that django executes delete on order row: {'time': '0.000', 'sql': 'DELETE FROM "main_shipment" WHERE "id" IN (17)'}, {'time': '0.000', 'sql': 'DELETE FROM "main_order" WHERE "id" IN (45)'} Foreign key have ON DELETE NO ACTION (default) and is initially deferred. I don't know why I get foreign key constraint violation. I also tried to register pre_delete signal and manually delete shipment objects before delete on order is called, but it resulted in the same error. I can change ON DELETE behaviour for this key in Postgres but it would be just a hack, I wonder if anyone has a better idea what's going on here. There is also a small detail, my Order model inherits from Cart model, so it actually doesn't have id field but cart_ptr_id and after DELETE on order is executed there is also DELETE on cart, but it seems unrelated? to the shipment-order problem so I simplified it in the example.

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• How do you serialize a model instance in Django?

  - by Jason Christa

  There is a lot of documentation on how to serialize a Model QuerySet but how do you just serialize to json the fields of a Model Instance?

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• Is it possible to replace values in a queryset before sending it to your template?

  - by Issy

  Hi Guys, Wondering if it's possible to change a value returned from a queryset before sending it off to the template. Say for example you have a bunch of records Date | Time | Description 10/05/2010 | 13:30 | Testing... etc... However, based on the day of the week the time may change. However this is static. For example on a monday the time is ALWAYS 15:00. Now you could add another table to configure special cases but to me it seems overkill, as this is a rule. How would you replace that value before sending it to the template? I thought about using the new if tags (if day=1), but this is more of business logic rather then presentation. Tested this in a custom template tag def render(self, context): result = self.model._default_manager.filter(from_date__lte=self.now).filter(to_date__gte=self.now) if self.day == 4: result = result.exclude(type__exact=2).order_by('time') else: result = result.order_by('type') result[0].time = '23:23:23' context[self.varname] = result return '' However it still displays the results from the DB, is this some how related to 'lazy' evaluation of templates? Thanks! Update Responding to comments below: It's not stored wrong in the DB, its stored Correctly However there is a small side case where the value needs to change. So for example I have a From Date & To date, my query checks if todays date is between those. Now with this they could setup a from date - to date for an entire year, and the special cases (like mondays as an example) is taken care off. However if you want to store in the DB you would have to capture several more records to cater for the side case. I.e you would be capturing the same information just to cater for that 1 day when the time changes. (And the time always changes on the same day, and is always the same)

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• Django get_FOO_display and distinct()

  - by datakid

  I've seen answers to both halves of my question, but I can't work out how to marry the two. I have a book model, and a translatedBook model. The translatedBook has a langage set up as model choices in the usual way: LANGUAGES = ( (u'it', u'Italian'), (u'ja', u'Japanese'), (u'es', u'Spanish'), (u'zh-cn', u'Simplified Chinese'), (u'zh-tw', u'Traditional Chinese'), (u'fr', u'French'), (u'el', u'Greek'), (u'ar', u'Arabic'), (u'bg', u'Bulgarian'), (u'bn', u'Bengali'), etc I know that to get "Italian" I have to do translatedBook.get_language_display on a Book object. But how do I get a list of distinct languages in their long format? I've tried: lang_avail = TargetText.objects.values('language').distinct().order_by('language') lang_avail = TargetText.objects.distinct().order_by('language').values('language'). lang_avail = TargetText.objects.all().distinct('language').order_by('language') but I can't seem to get what I want - which is a list like: "English, Italian, Simplified Chinese, Spanish" The final lang_avail listed above didn't return the list of 5, it returned the list of 355 (ie, # of books) with multiple repeats....

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• Select distinct users with referrals

  - by Mark

  I have a bunch of Users. Since Django doesn't really let me extend the default User model, they each have Profiles. The Profiles have a referred_by field (a FK to User). I'm trying to get a list of Users with = 1 referral. Here's what I've got so far Profile.objects.filter(referred_by__isnull=False).values_list('referred_by', flat=True) Which gives me a list of IDs of the users who have referrals... but I need it to be distinct, and I want the User object, not their ID. Or better yet, it would be nice if it could return the number of referrals a user has. Any ideas?

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• Google App Engine getting verbose_name of a property from an instance

  - by Brian M. Hunt

  Given a model likeso: from google.appengine.ext import db class X(db.Model): p = db.StringProperty(verbose_name="Like p, but more modern.") How does one access verbose_name from x=X() (an instance of X)? One might expect that x.p.verbose_name would work, or alternatively x.properties()['p'].verbose_name, but neither seems to work. Thanks! EDIT: x.name.verbose_name = x.p.verbose_name

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• How do I define an ImageField in a Django abstract model?

  - by blackrobot

  I have an abstract Django model and I want to define an ImageField inside of it. The problem is that when I do define it, it raises an error because I don't have an "upload_to" attribute. Is there a way to still define it and have a separate folder for each inheriting class?

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• Rails setting OR conditions in validate_presence_of in a model?

  - by Jty.tan

  In a rails model, is it possible to do something like class Example < ActiveRecord::Base #associations validates_presence_of :item_id, (:user_id OR :user_email) #functions end Where the model has 3 columns of :item_id, :user_id, and :user_email? I want the model to be valid as long as I have a :user_id or a :user_email. Idea being that if the item is recommended to a person who isn't currently signed up, it can be associated via email address for when the recommended person signs up. Or is there a different method that I can use instead?

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• in Rails, with check_box_tag, how do I keep the checkboxes checked after submitting query?

  - by Sebastien Paquet

  Ok, I know this is for the Saas course and people have been asking questions related to that as well but i've spent a lot of time trying and reading and I'm stuck. First of all, When you have a model called Movie, is it better to use Ratings as a model and associate them or just keep Ratings in an array floating in space(!). Second, here's what I have now in my controller: def index @movies = Movie.where(params[:ratings].present? ? {:rating => (params[:ratings].keys)} : {}).order(params[:sort]) @sort = params[:sort] @ratings = Ratings.all end Now, I decided to create a Ratings model since I thought It would be better. Here's my view: = form_tag movies_path, :method => :get do Include: - @ratings.each do |rating| = rating.rating = check_box_tag "ratings[#{rating.rating}]" = submit_tag "Refresh" I tried everything that is related to using a conditional ternary inside the checkbox tag ending with " .include?(rating) ? true : "" I tried everything that's supposed to work but it doesn't. I don't want the exact answer, I just need guidance.Thanks in advance!

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• create a new model instance version instead of update

  - by pablo

  Hi, I have a model with a version field - autocreate timestamp. When a model instance is being saved I want to create a new instance with a new timestamp instead of updating the old model instance. Is it possible? I thought of overriding the model save() method but I don't know how to create a new instance without creating a infinite save() loop. Thanks

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• Django: How/Where to store a value for a session without unnecessary DB hits

  - by GerardJP

  Hi all, I have an extended userprofile with AUTH_PROFILE_MODULE (ref: http://tinyurl.com/yhracqq) I would like to set a user.is_guru() method similar to user.is_active(). This would results for al views (or rather templates) to e.g. disable/enable certain user messages, displaying of widgets, etc. The boolean is stored in the extended user profile model, but I want to avoid hitting the DB for every view. So the questions is .. Do I use a context_processor, a template tag, session_dict or what have you to, possible cached, store this info for the duration of the users visit. Note: I dont have performance issues, so it's definitely filed under premature optimization. I just want to avoid generating extra work in the future :). Any pointers are very welcome. Thanx and greetz! Gerard.

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