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  • Parsing XHTML results from Bing

    - by Nir
    Hello, i am trying to parse received search queries from bing search engines which are received in xhtml in java. I am using sax XmlReader to read the results but i keep on getting errors. here is my code-this one is for the hadler of the reader: import org.xml.sax.Attributes; import org.xml.sax.SAXException; import org.xml.sax.helpers.DefaultHandler; public class XHTMLHandler extends DefaultHandler{ public XHTMLHandler() { super(); } public void startDocument () { System.out.println("Start document"); } public void endDocument () { System.out.println("End document"); } public void startElement (String uri, String name,String qName, Attributes atts) { if ("".equals (uri)) System.out.println("Start element: " + qName); else System.out.println("Start element: {" + uri + "}" + name); } public void endElement (String uri, String name, String qName) { if ("".equals (uri)) System.out.println("End element: " + qName); else System.out.println("End element: {" + uri + "}" + name); } public void startPrefixMapping (String prefix, String uri) throws SAXException { } public void endPrefixMapping (String prefix) throws SAXException { } public void characters (char ch[], int start, int length) { System.out.print("Characters: \""); for (int i = start; i < start + length; i++) { switch (ch[i]) { case '\\': System.out.print("\\\\"); break; case '"': System.out.print("\\\""); break; case '\n': System.out.print("\\n"); break; case '\r': System.out.print("\\r"); break; case '\t': System.out.print("\\t"); break; default: System.out.print(ch[i]); break; } } System.out.print("\"\n"); } } and this is the program itself: import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; import java.net.HttpRetryException; import java.net.HttpURLConnection; import java.net.URL; import org.xml.sax.InputSource; import org.xml.sax.SAXException; import org.xml.sax.XMLReader; import org.xml.sax.helpers.XMLReaderFactory; public class Searching { private String m_urlBingSearch = "http://www.bing.com/search?q="; private HttpURLConnection m_httpCon; private OutputStreamWriter m_streamWriter; //private BufferedReader m_bufferReader; private URL m_serverAdress; private StringBuilder sb; private String m_line; private InputSource m_inputSrc; public Searching() { m_httpCon = null; m_streamWriter = null; //m_bufferReader = null; m_serverAdress = null; sb = null; m_line = new String(); } public void SearchBing(String searchPrms) throws SAXException,IOException { //set up connection sb = new StringBuilder(); sb.append(m_urlBingSearch); sb.append(searchPrms); m_serverAdress = new URL(sb.toString()); m_httpCon = (HttpURLConnection)m_serverAdress.openConnection(); m_httpCon.setRequestMethod("GET"); m_httpCon.setDoOutput(true); m_httpCon.setConnectTimeout(10000); m_httpCon.connect(); //m_streamWriter = new OutputStreamWriter(m_httpCon.getOutputStream()); //m_bufferReader = new BufferedReader(new InputStreamReader(m_httpCon.getInputStream())); XMLReader reader = XMLReaderFactory.createXMLReader(); XHTMLHandler handle = new XHTMLHandler(); reader.setContentHandler(handle); reader.setErrorHandler(handle); //reader.startPrefixMapping("html", "http://www.w3.org/1999/xhtml"); handle.startPrefixMapping("html", "http://www.w3.org/1999/xhtml"); m_inputSrc = new InputSource(m_httpCon.getInputStream()); reader.parse(m_inputSrc); m_httpCon.disconnect(); } public static void main(String [] args) throws SAXException,IOException { Searching s = new Searching(); s.SearchBing("beatles"); } } this is my error message: Exception in thread "main" java.io.IOException: Server returned HTTP response code: 503 for URL: http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.setupCurrentEntity(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.startEntity(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.startDTDEntity(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDTDScannerImpl.setInputSource(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$DTDDriver.dispatch(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$DTDDriver.next(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$PrologDriver.next(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source) at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(Unknown Source) at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(Unknown Source) at Searching.SearchBing(Searching.java:57) at Searching.main(Searching.java:65) can someone please help? i think it has something to do with dtd but i don't know hot to fix it

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  • jquery animation problem using stop

    - by Flanders
    Hi! When running a Jquery animation like slideDown(), it looks like a number of element-specific css properties is set to be updated at a specific interval and when the animation is complete these properties are unset and the display property is simply set to auto or whatever. At least in firebug you can't see those temporary properties any more. The problem I've encountered is the scenario where we stop the slide down with stop(). The element is then left with the current temporary css values. Which is fine because it has to, but let us say that I stoped the slidedown because I have decided to slide it back up again a bit prematurely. It would look something like this: $(this).slideDown(2000) //The below events is not in queue but will rather start execute almost simultaneously as the above line. (dont remember the exact syntax) $(this).delay(1000).stop().slideUp(2000) The above code might not make much sense, but the point is: After 1 second of sliding down the animation is stopped and it starts to slide back up. Works like a charm. BUT!!! And here is the problem. Once it it has slid back up the elements css properties are reset to the exact values it had 1000ms into the slideDown() animation (when stop() was called). If we now try to run the following: $(this).slideDown(2000) It will slide down to the very point the prior slideDown was aborted and not further at half the speed (since it uses the same time for approximately half the height). This is because the css properties were saved as I see it. But it is not especially wished for. Of course I want it to slide all the way down this time. Due to UI interaction that is hard to predict everything might soon break. The longer animations we use increases the risk of something like this happening. Is this to be considered a bug, or am I doing something wrong? Or maybe it's just a feature that is not supported? I guess I can use a callback function to reset the css properties, but depending on the animation used, different css properties are used to render it, and covering your back would result in quite a not-so-fancy solution.

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  • Concatenate, sort and swap array in Java

    - by sblck
    I am trying to concatenate two arrays into new array, sort in order, and swap two values of index. I'm kind of new to java and only use C before so having a hard time handling an Object. In main method it declares two object arrays IntVector vector = new IntVector(3); and IntVector vector2 = new IntVector(3); I can only do this if the types are int[], but I want to use as an object How should I code the concat, sort, and swap method? public class IntVector { private int[] items_; private int itemCount_; private IntVector(int[] data, int n) { items_ = data.clone(); itemCount_ = n; } public IntVector(int itemSize) { itemCount_ =0; if(itemSize<1) itemSize =10; items_ = new int[itemSize]; } public void push(int value) { if(itemCount_ + 1 >= items_.length) overflow(); items_[itemCount_++] = value; } public void log() { for (int i=0 ; i<itemCount_; ++i) { System.out.print(items_[i]); if(i<itemCount_ -1) System.out.println(); } } public void overflow() { int[] newItems = new int[items_.length * 2]; for(int i=0 ; i<itemCount_; ++i) { newItems[i] = items_[i]; } items_=newItems; } public int getValue(int index) { if(index < 0 || index >= itemCount_) { System.out.println("[error][IntVector][setValue] Incorrect index=" + index); return 0; } return items_[index]; } public void setValue(int index, int value) { if(index < 0 || index >= itemCount_) { System.out.println("[error][IntVector][setValue] Incorrect index=" + index); return ; } items_[index] = value; } public IntVector clone() { return new IntVector(items_, itemCount_); } public IntVector concat() { return null; } public IntVector sort() { return null; } public IntVector swap() { return null; } public static void main(String[] args) { IntVector vector = new IntVector(3); IntVector vector2 = new IntVector(3); vector.push(8); vector.push(200); vector.push(3); vector.push(41); IntVector cloneVector = vector.clone(); vector2.push(110); vector2.push(12); vector2.push(7); vector2.push(141); vector2.push(-32); IntVector concatResult = vector.concat(vector2); IntVector sortResult = concatResult.sort(); IntVector swapResult = sortResult.clone(); //swapResult.swap(1,5); System.out.print("vector : "); vector.log(); System.out.print("\n\ncloneVector : "); cloneVector.log(); System.out.print("\n\nvector2 : "); vector2.log(); System.out.print("\n\nconcatvector : "); concatResult.log(); System.out.print("vector : "); vector.log(); System.out.print("vector : "); vector.log(); } }

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  • Python lxml - returns null list

    - by Chris Finlayson
    I cannot figure out what is wrong with the XPATH when trying to extract a value from a webpage table. The method seems correct as I can extract the page title and other attributes, but I cannot extract the third value, it always returns an empty list? from lxml import html import requests test_url = 'SC312226' page = ('https://www.opencompany.co.uk/company/'+test_url) print 'Now searching URL: '+page data = requests.get(page) tree = html.fromstring(data.text) print tree.xpath('//title/text()') # Get page title print tree.xpath('//a/@href') # Get href attribute of all links print tree.xpath('//*[@id="financial"]/table/tbody/tr/td[1]/table/tbody/tr[2]/td[1]/div[2]/text()') Unless i'm missing something, it would appear the XPATH is correct: Chrome screenshot I checked Chrome console, appears ok! So i'm at a loss $x ('//*[@id="financial"]/table/tbody/tr/td[1]/table/tbody/tr[2]/td[1]/div[2]/text()') [ "£432,272" ]

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  • JS and Jquery problem

    - by Sonny
    hi i got the problem the script.js gives me <div id="gracze"> <div id="10" class="char" style="z-index: 19; top: 592px; left: 608px; "></div> <div id="14" class="char" style="z-index: 25; top: 784px; left: 608px; "></div> </div> instead <div id="gracze"> <div id="4" class="char" ... ></div> <div id="10" class="char" style="z-index: 19; top: 592px; left: 608px; "></div> <div id="14" class="char" style="z-index: 25; top: 784px; left: 608px; "></div> </div> get_players.php 4/62/6 10/19/19 14/19/25 script.js function get_players() { $.ajax({ type: "POST", url: "get_players.php", dataType: "html", success: function(data) { var str = data; var chars = str.split("<br />"); var lol = chars.length; for(var i = lol; i--; ) { chars[i] = chars[i].split('/'); var o = document.getElementById(chars[i][0]); var aimt = i; if (!o) { if (aimt!=chars.length-1 && aimt != 0) { $('#gracze').html('<div id="'+chars[aimt][0]+'" class="char"></div>'+$('#gracze').html()); $('#'+chars[aimt][0]).css("top", chars[aimt][2]*32-16+"px"); $('#'+chars[aimt][0]).css("left", chars[aimt][1]*32+"px"); $('#'+chars[aimt][0]).css("z-index", chars[aimt][1]*32); } } else { $('#'+chars[aimt][0]).animate({ "top": chars[aimt][2]*32-16+"px", "left": chars[aimt][1]*32+"px" }, { duration: 275}); //$('#'+chars[aimt][0]).css("top", chars[aimt][1]*32-16+"px"); //$('#'+chars[aimt][0]).css("left", chars[aimt][2]*32+"px"); $('#'+chars[aimt][0]).css("z-index", chars[aimt][2]); } } }}); setTimeout("get_players();", 1000); } I think it's because of for(var i = lol; i--; ) {

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  • How to store <TR> id value in array, when I toggle?

    - by James123
    I am toggling 'tr.subCategory1'and its siblings .RegText. at the same time I am trying to store its ids in the array like this list_Visible_Ids[$(this).attr('id')] = $(this).css('display') != 'none' ? 1 : null; (When I collapsed I need store 'null' in array at its id place, If I expand I need store I need store 1 at its id place). But everytime alert($(this).css('display')) showing block. How can I handle this?. So When I collapsed or expanded it is storing 1 only. $(document).ready(function() { $('tr[@class^=RegText]').hide().children('td'); list_Visible_Ids = []; var idsString, idsArray; idsString = $('#myVisibleRows').val(); idsArray = idsString.split(','); $.each(idsArray, function() { if (this != "" || this != null) { $('#' + this).siblings('.RegText').toggle(); list_Visible_Ids[this] = 1; } }); $('tr.subCategory1') .css("cursor", "pointer") .attr("title", "Click to expand/collapse") .click(function() { $(this).siblings('.RegText').toggle(); $(this).siblings('.VolumeRegText').toggle(); //alert($(this).css('display')) list_Visible_Ids[$(this).attr('id')] = $(this).css('display') != 'none' ? 1 : null; }); $('#form1').submit(function() { idsString = ''; for (var index in list_Visible_Ids) { idsString += (idsString != '' ? ',' : '') + index; } $('#myVisibleRows').val(idsString); form1.submit(); }); });

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  • Fortran severe (40) Error... Help?!

    - by Taka
    I can compile but when I run I get this error "forrtl: severe (40): recursive I/O operation, unit -1, file unknown" if I set n = 29 or more... Can anyone help with where I might have gone wrong? Thanks. PROGRAM SOLUTION IMPLICIT NONE ! Variable Declaration INTEGER :: i REAL :: dt DOUBLE PRECISION :: st(0:9) DOUBLE PRECISION :: stmean(0:9) DOUBLE PRECISION :: first_argument DOUBLE PRECISION :: second_argument DOUBLE PRECISION :: lci, uci, mean REAL :: exp1, n REAL :: r, segma ! Get inputs WRITE(*,*) 'Please enter number of trials: ' READ(*,*) n WRITE(*,*) dt=1.0 segma=0.2 r=0.1 ! For n Trials st(0)=35.0 stmean(0)=35.0 mean = stmean(0) PRINT *, 'For ', n ,' Trials' PRINT *,' 1 ',st(0) ! Calculate results DO i=0, n-2 first_argument = r-(1/2*(segma*segma))*dt exp1 = -(1/2)*(i*i) second_argument = segma*sqrt(dt)*((1/sqrt(2*3.1416))*exp(exp1)) st(i+1) = st(i) * exp(first_argument+second_argument) IF(st(i+1)<=20) THEN stmean(i+1) = 0.0 st(i+1) = st(i) else stmean(i+1) = st(i+1) ENDIF PRINT *,i+2,' ',stmean(i+1) mean = mean+stmean(i+1) END DO ! Output results uci = mean+(1.96*(segma/sqrt(n))) lci = mean-(1.96*(segma/sqrt(n))) PRINT *,'95% Confidence Interval for ', n, ' trials is between ', lci, ' and ', uci PRINT *,'' END PROGRAM SOLUTION

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  • Instantiating a class within a class

    - by Ink-Jet
    Hello. I'm trying to instantiate a class within a class, so that the outer class contains the inner class. This is my code: #include <iostream> #include <string> class Inner { private: std::string message; public: Inner(std::string m); void print() const; }; Inner::Inner(std::string m) { message = m; } void Inner::print() const { std::cout << message << std::endl; std::cout << message << std::endl; } class Outer { private: std::string message; Inner in; public: Outer(std::string m); void print() const; }; Outer::Outer(std::string m) { message = m; } void Outer::print() const { std::cout << message << std::endl; } int main() { Outer out("Hello world."); out.print(); return 0; } "Inner in", is my attempt at containing the inner within the outer, however, when I compile, i get an error that there is no matching function for call to Inner::Inner(). What have I done wrong? Thanks.

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  • Reading a series of input / output in Python

    - by PulpFiction
    Hello everyone. For my app, I need to print out a series of outputs and then accepts inputs from the user. What would be the best way of doing this? Like: print '1' x = raw_input() print '2' y = raw_input() Something like this, but it would go on for at least 10 times. My only concern with doing the above is that it would make up for poor code readability. How should I do it? Should I create a function like this: def printOut(string): print string Or is there a better way?

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  • What is the '@(' doing in this Perl code?

    - by Anthony Veckey
    In this code snippet: use strict; use warnings; use Data::Dumper; my $r = [qw(testing this thing)]; print Dumper($r); foreach my $row (@({$r}) { print "$row\n"; $row .= 'mod'; } print Dumper($r); print Dumper(@({$r}); I figured out that the '(' after the '@' in the foreach is causing this not to loop correctly. I have no idea why this code even works as there is no ending parenthesis. What is this doing? It looks to be creating a new variable on the fly, but shouldn't 'use strict' have fired or something? Please help explain what that '@(' is doing and why it still runs without an ending parenthesis.

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  • Python Continue Loop

    - by Rob B.
    I am using the following code from this tutorial (http://jeriwieringa.com/blog/2012/11/04/beautiful-soup-tutorial-part-1/). from bs4 import BeautifulSoup soup = BeautifulSoup (open("43rd-congress.html")) final_link = soup.p.a final_link.decompose() trs = soup.find_all('tr') for tr in trs: for link in tr.find_all('a'): fulllink = link.get ('href') print fulllink #print in terminal to verify results tds = tr.find_all("td") try: #we are using "try" because the table is not well formatted. This allows the program to continue after encountering an error. names = str(tds[0].get_text()) # This structure isolate the item by its column in the table and converts it into a string. years = str(tds[1].get_text()) positions = str(tds[2].get_text()) parties = str(tds[3].get_text()) states = str(tds[4].get_text()) congress = tds[5].get_text() except: print "bad tr string" continue #This tells the computer to move on to the next item after it encounters an error print names, years, positions, parties, states, congress However, I get an error saying that 'continue' is not properly in the loop on line 27. I am using notepad++ and windows powershell. How do I make this code work?

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  • OnClientClick event for keeping track of prints?

    - by Ram
    Hello, I am trying to keep track of prints that are made for a page. The page has Print this page link. And the code for it is like below: This is written in .cs file as there are many conditions for displaying this. And i am appending here using String Builder. sbOutput.AppendFormat("<td align=\"right\" valign=\"bottom\"><div style =\"float:right;text-align:right; valign:bottom;width:200px\"class=\"print_button notPrinted\"><a class=\"notPrinted\" href=\"#\" onclick=\"window.print();\">PRINT THIS COUPON </a><img src=\"images/print-icon-34x34.gif\" class=\"notPrinted\" align=\"absmiddle\" /></div> </td></tr></table>", couponid, Userid, locationid); Do i have to use onclientclick or something else?? Thanks so much in advance.

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  • mvc partial views loses track of the images folder when using jquery

    - by jvelez
    This is what I have and it works: $(function(){ $('.slide-out-div').tabSlideOut({ tabHandle: '.handle', //class of the element that will become your tab pathToTabImage: 'http://mhmiisdev2/images/contact_tab.gif', //path to the image for the tab //Optionally can be set using css imageHeight: '122px', //height of tab image //Optionally can be set using css imageWidth: '40px', //width of tab image //Optionally can be set using css tabLocation: 'right', //side of screen where tab lives, top, right, bottom, or left speed: 300, //speed of animation action: 'click', //options: 'click' or 'hover', action to trigger animation topPos: '200px', //position from the top/ use if tabLocation is left or right leftPos: '20px', //position from left/ use if tabLocation is bottom or top fixedPosition: true //options: true makes it stick(fixed position) on scroll }); }); This is what I want and it doesnt work when I change from one controller to another controller. NOTICE THE IMAGE PATH IS NOT ABSOLUTE $(function(){ $('.slide-out-div').tabSlideOut({ tabHandle: '.handle', //class of the element that will become your tab pathToTabImage: '/images/contact_tab.gif', //path to the image for the tab //Optionally can be set using css imageHeight: '122px', //height of tab image //Optionally can be set using css imageWidth: '40px', //width of tab image //Optionally can be set using css tabLocation: 'right', //side of screen where tab lives, top, right, bottom, or left speed: 300, //speed of animation action: 'click', //options: 'click' or 'hover', action to trigger animation topPos: '200px', //position from the top/ use if tabLocation is left or right leftPos: '20px', //position from left/ use if tabLocation is bottom or top fixedPosition: true //options: true makes it stick(fixed position) on scroll }); }); the html for completeness.... <div class="slide-out-div"> <a class="handle" href="http://link-for-non-js-users.html">Content</a> <h3>Medical Variance Reports</h3> <div> <ul> <li><a href="http://mhmssrs2/Reports/Pages/Report.aspx?" target="_blank">Individual Medicines</a></li> </ul> </div> </div> I suspect somehow pathToTabImage: /images/contact_tab.gif' loses its context when browsing throught controllers. Help me understand...

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  • Why is the data I am printing not in a table format

    - by udaya
    Hi This is my program .when i submit the print button i can print the datas but they are not aligned in the table formatthe format in which i need the print to be...How can i print in the correct format <html> <head> <script type="text/javascript" src="http://jqueryjs.googlecode.com/files/jquery-1.3.1.min.js" > </script> <script type="text/javascript"> function PrintElem(elem) { //alert('ddd'); Popup($(elem).text()); } function Popup(data) { var mywindow = window.open('', 'mydiv', 'height=400,width=600'); mywindow.document.write('<html><head><title>my div</title>'); /*optional stylesheet*/ //mywindow.document.write('<link rel="stylesheet" href="main.css" type="text/css" />'); mywindow.document.write('</head><body >'); mywindow.document.write(data); mywindow.document.write('</body></html>'); mywindow.document.close(); mywindow.print(); return true; } </script> </head> <body> <div id="mydiv"> <table width="200" border="1"> <tr> <td>sss</td> <td>sssss;</td> <td>snssbsp;</td> </tr> <tr> <td>ssss;</td> <td>sssnbsp;</td> <td>snbsp;</td> </tr> <tr> <td>snbsp;</td> <td>snbsp;</td> <td>snbsp;</td> </tr> </table> </div> <input type="button" value="Print Div" onClick="PrintElem('#mydiv')" /> </body> </html>

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  • Does dict.update affect a function's argspec?

    - by sbox32
    import inspect class Test: def test(self, p, d={}): d.update(p) return d print inspect.getargspec(getattr(Test, 'test'))[3] print Test().test({'1':True}) print inspect.getargspec(getattr(Test, 'test'))[3] I would expect the argspec for Test.test not to change but because of dict.update it does. Why?

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  • PHP object help -> unexpected T_OBJECT_OPERATOR

    - by php-b-grader
    Please help me understand: print gettype(new CustomerObject()) prints: "object" (so it is an object) BUT print gettype((new CustomerObject())->get_customer()); prints: unexpected T_OBJECT_OPERATOR If I do it over two lines it works fine $object = new Customer($order->customer_id); print gettype($object); prints: object $customer = $object->get_customer(); print gettype($customer); prints: array It appears that the lines cannot be joined into a single call. Is this correct? and what is the logic behind that?

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  • How to test that variable is not equal to multiple things? Python

    - by M830078h
    This is the piece of code I have: choice = "" while choice != "1" and choice != "2" and choice != "3": choice = raw_input("pick 1, 2 or 3") if choice == "1": print "1 it is!" elif choice == "2": print "2 it is!" elif choice == "3": print "3 it is!" else: print "You should choose 1, 2 or 3" While it works, I feel that it's really clumsy, specifically the while clause. What if I have more acceptable choices? Is there a better way to make the clause?

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  • Sleeping a thread blocking stdin

    - by Sid
    Hey, I'm running a function which evaluates commands passed in using stdin and another function which runs a bunch of jobs. I need to make the latter function sleep at regular intervals but that seems to be blocking the stdin. Any advice on how to resolve this would be appreciated. The source code for the functions is def runJobs(comps, jobQueue, numRunning, limit, lock): while len(jobQueue) >= 0: print(len(jobQueue)); if len(jobQueue) > 0: comp, tasks = find_computer(comps, 0); #do something time.sleep(5); def manageStdin(): print "Global Stdin Begins Now" for line in fileinput.input(): try: print(eval(line)); except Exception, e: print e; --Thanks

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  • How do I get the key of an item when doing a FOR loop through a dictionary or list in Python?

    - by Mike Hayes
    Hi I am new to Python. Say I have a list: list = ['A','B','C','D'] The key for each item respectively here is 0,1,2,3 - right? Now I am going to loop through it with a for loop... for item in list: print item That's great, I can print out my list. How do I get the key here? For example being able to do: print key print item on each loop? If this isn't possible with a list, where keys are not declared myself, is it possible with a Dictionary? Thanks

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  • Github + keep file but dont track changes

    - by Mike
    I have a codeigniter framework thats using github. Within this application I have several files that i will want to have in the repo but not track any changes on.. Example is: i deploy a new installation of this framework to a new client, i want the following files to be downloaded (they have default values 'CHANGEME') and i just have to make changes specific to this client IE(database credentials, email address info, custom css styling). // the production config files i want the files but they need to be updated to specific client needs application/config/production/config.php application/config/production/database.php application/config/production/tank_auth.php // index page, defines the environment (production|development) /index.php // all of the css/js cache (keep the folder but not the contents) /assets/cache/* // production user based styling (color, fonts etc) needs to be updated specific to client needs /assets/frontend/css/user/frontend-user.css currently if i run git clone [email protected]:user123/myRepo.git httpdocs and then i edit the files above, all is great.. until i release a hotfix or patch and run git pull. All of my changes are then overwritten.

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  • Python server open all ports

    - by user1670178
    I am trying to open all ports using this code, why can I not create a loop to perform this function? http://www.kellbot.com/2010/02/tutorial-writing-a-tcp-server-in-python/ #!/usr/bin/python # This is server.py file ##server.py from socket import * #import the socket library n=1025 while n<1050: ##let's set up some constants HOST = '' #we are the host PORT = n #arbitrary port not currently in use ADDR = (HOST,PORT) #we need a tuple for the address BUFSIZE = 4096 #reasonably sized buffer for data ## now we create a new socket object (serv) ## see the python docs for more information on the socket types/flags serv = socket( AF_INET,SOCK_STREAM) ##bind our socket to the address serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow serv = socket( AF_INET,SOCK_STREAM) ##bind our socket to the address serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow print 'listening...' n=n+1 conn,addr = serv.accept() #accept the connection print '...connected!' conn.send('TEST') conn.close() How do I make this work so that I can specify input range and have the server open all ports up to 65535? #!/usr/bin/python # This is server.py file from socket import * #import the socket library startingPort=input("\nPlease enter starting port: ") startingPort=int(startingPort) #print startingPort def connection(): ## let's set up some constants HOST = '' #we are the host PORT = startingPort #arbitrary port not currently in use ADDR = (HOST,PORT) #we need a tuple for the address BUFSIZE = 4096 #reasonably sized buffer for data def socketObject(): ## now we create a new socket object (serv) serv = socket( AF_INET,SOCK_STREAM) def bind(): ## bind our socket to the address serv = socket( AF_INET,SOCK_STREAM) serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow serv = socket( AF_INET,SOCK_STREAM) print 'listening...' def accept(): conn,addr = serv.accept() #accept the connection print '...connected!' conn.send('TEST') def close(): conn.close() ## Main while startingPort<65535: connection() socketObject() bind() accept() startingPort=startingPort+1

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  • I can I separate multiple logical pages in a text file I create in Perl?

    - by Micah
    So far, I've been successful with generating output to individual files by opening a file for output as part of outer loop and closing it after all output is written. I had used a counting variable ($x) and appended .txt onto it to create a filename, and had written it to the same directory as my perl script. I want to step the code up a bit, prompt for a file name from the user, open that file once and only once, and write my output one "printed letter" per page. Is this possible in plain text? From what I understand, chr(12) is an ascii line feed character and will get me close to what I want, but is there a better way? Thanks in advance, guys. :) sub PersonalizeLetters{ print "\n\n Beginning finalization of letters..."; print "\n\n I need a filename to save these letters to."; print "\n Filename > "; $OutFileName = <stdin>; chomp ($OutFileName); open(OutFile, ">$OutFileName"); for ($x=0; $x<$NumRecords; $x++){ $xIndex = (6 * $x); $clTitle = @ClientAoA[$xIndex]; $clName = @ClientAoA[$xIndex+1]; #I use this 6x multiplier because my records have 6 elements. #For this routine I'm only interested in name and title. #Reset OutLetter array #Midletter has other merged fields that aren't specific to who's receiving the letter. @OutLetter = @MiddleLetter; for ($y=0; $y<=$ifLength; $y++){ #Step through line by line and insert the name. $WorkLine = @OutLetter[$y]; $WorkLine =~ s/\[ClientTitle\]/$clTitle/; $WorkLine =~ s/\[ClientName\]/$clName/; @OutLetter[$y] = $WorkLine; } print OutFile "@OutLetter"; #Will chr(12) work here, or is there something better? print OutFile chr(12); $StatusX = $x+1; print "Writing output $StatusX of $NumRecords... \n\n"; } close(OutFile); }

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