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  • PHP/MySQL allowing current user to edit there account information

    - by user1837896
    i have created 2 pages update.php edit.php we start on edit.php so here is edit.php's script <?php session_start(); $id = $_SESSION["id"]; $username = $_POST["username"]; $fname = $_POST["fname"]; $password = $_POST["password"]; $email = $_POST["email"]; mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); echo "MySQL Connection Established! <br>"; mysql_select_db("a2670376_Pass") or die(mysql_error()); echo "Database Found! <br>"; $query = "UPDATE members SET username = '$username', fname = '$fname', password = '$password' WHERE id = '$id'"; $res = mysql_query($query); if ($res) echo "<p>Record Updated<p>"; else echo "Problem updating record. MySQL Error: " . mysql_error(); ?> <form action="update.php" method="post"> <input type="hidden" name="id" value="<?=$id;?>"> ScreenName:<br> <input type='text' name='username' id='username' maxlength='25' style='width:247px' name="username" value="<?=$username;?>"/><br> FullName:<br> <input type='text' name='fname' id='fname' maxlength='20' style='width:248px' name="ud_img" value="<?=$fname;?>"/><br> Email:<br> <input type='text' name='email' id='email' maxlength='50' style='width:250px' name="ud_img" value="<?=$email;?>"/><br> Password:<br> <input type='text' name='password' id='password' maxlength='25' style='width:251px' value="<?=$password;?>"/><br> <input type="Submit"> </form> now here is the update.php page where i am having the MAJOR problem <?php session_start(); mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); mysql_select_db("a2670376_Pass") or die(mysql_error()); $id = (int)$_SESSION["id"]; $username = mysql_real_escape_string($_POST["username"]); $fname = mysql_real_escape_string($_POST["fname"]); $email = mysql_real_escape_string($_POST["email"]); $password = mysql_real_escape_string($_POST["password"]); $query="UPDATE members SET username = '$username', fname = '$fname', email = '$email', password = '$password' WHERE id='$id'"; mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ echo "<p>($id) Record Updated<p>"; }else{ echo "<p>($id) Not Updated<p>"; } ?> now on edit.php i fill out the form to edit the account "test" while i am logged into it now once the form if filled out i click on |Submit!| button and it takes me to update.php and it returns this (0) Not Updated (0) <= id of user logged in Not Updated <= MySql Error from mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ i want it to update the user logged in and if i am not mistaken in this script it says $id = (int)$_SESSION["id"]; witch updates the user with the id of the person who is logged in but it isnt updating its saying that no tables were effected if it helps heres my MySql Database picture just click here http://i50.tinypic.com/21juqfq.png if this could possibly be any help to find the solution i have 2 more files delete.php and delete_ac.php they have can remove users from my sql database and they show the user id and it works there are no bugs in this script at all PLEASE DO NOT MAKE SUGGESTIONS FOR THE SCRIPTS BELOW delete.php first <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="PASSWORD"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // select record from mysql $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); ?> <table border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" style="bgcolor: #FFFFFF"><strong><img src="http://i47.tinypic.com/u6ihk.png" height="30" widht="30">Delete data in mysql</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>UserName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>FullName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Password</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Date</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Ip</strong></td> <td align="center" bgcolor="#FFFFFF">&nbsp;</td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['username']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['fname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['password']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['date']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['ip']; ?></td> <td bgcolor="#FFFFFF"><a href="delete_ac.php?id=<? echo $rows['id']; ?>">delete</a></td> </tr> <?php // close while loop } ?> </table> <?php // close connection; sql_close(); ?> and now delete_ac.php <table width="500" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" bgcolor="#FFFFFF"><strong><img src="http://t2.gstatic.com/images? q=tbn:ANd9GcS_kwpNSSt3UuBHxq5zhkJQAlPnaXyePaw07R652f4StmvIQAAf6g" height="30" widht="30">Removal Of Account</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"> <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="javascript00"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Delete data in mysql from row that has this id $sql="DELETE FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); // if successfully deleted if($result){ echo "Deleted Successfully"; echo "<BR>"; echo "<a href='delete.php'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?> </td> </tr> </table>

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  • ORDER BY column_name help (via link in HTML table view) (PHP MySQL

    - by Derek
    My output for my table in HTML has several columns such as userid, name, age, dob. The table heading is simply the title of the column name, I want this to be a link, and when clicked, the selected column is sorted in order, ASC, and then DESC (on next click). I thought this was pretty straight forward but I'm having some difficulty. So far, I have produced this, and no output is taken, apart from the URL works by displaying 'users.php?orderby=userid' <?php if(isset($_GET['orderby'])){ $orderby = $_GET['orderby']; $query_sv = "SELECT * FROM users BY ".mysql_real_escape_string($orderby)." ASC"; } //default query else{ $query_sv = "SELECT * FROM users BY user_id DESC"; } ?> <tr> <th><a href="<?php echo $_SERVER['php_SELF']."?orderby=userid";?>">User ID</a></th> Hoefully if I get this working, I can sort the users by D.O.B. next also using the same principles. Does anyone have any ideas?

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  • How do i make divs go into another row when full?

    - by acidzombie24
    My code is something like the below. When theres 3 images everything is fine once theres 4 it gets full and moves the entire div.top into another row. How do i make the div inside top just start a new row instead? I tried writing .top width=500px but once it hits or passes it instead the images inside are squeeze together instead of each being 150x150. I tried max-width on top instead and in opera and chrome i see the border of top as 500width but the images continue to render pass it. (i have a firefox problem with my div so the width looks fixed to something else). So how do i make these divs go into another row? and not try to squeeze together <div class="top"> <div><a href><img/></a></div> <div><a href><img/></a></div> <div><a href><img/></a></div> </div>

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  • Web application starter kit

    - by Steve Robillard
    I am looking for a site that allows you to input a project name, choose a doctype, a js library etc. and then generates the directory structure and files to start a web project. I know about project deploy, but it is no longer maintained. There was a new one that was created within the last 2 or 3 months, but for the life of me I can't find it either through Google nor my delicious bookmarks. Any help would be greatly appreciated. Thanks, Steve

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  • Looking for icon shop

    - by citronas
    I'm looking for nice icons for my webapplications. Some of these applications are commercial applications. I want to polish them up by using nice looking icons, but where do I find specific icons/grafics? Does anybody know a icon shop, that allows me to buy single icons for commercial use? Payable via paypal or credit card.

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  • What should I use to define image height/width resolution?

    - by Tedy
    I've read all over the Internet that I should not define fonts (or anything) with absolute pixel height/width/size and instead, use EM ... so that on higher resolution displays, my web site can scale appropriately. However, what do I use to define IMAGE height/width ... because images won't scale well (they look pixelated)

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  • Can one form have multiple actions?

    - by Brook Julias
    I am wanting to submit a form to different places based on selections made in the form. If the user wants to delete elements go to page 1. If the user wants to edit/update elements go to page 2. If the user wants to group/attach elements go to page 3.

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  • blank space on google home page

    - by topgun_ivard
    2 questions, i was doing nothing productive, and tried selecting the google home page (a left click drag and select whole page) on google.com i see that beside the search box, on the left side, there is an empty space &nbsp; i looked up the source code and there indeed was a <td width=25%>&nbsp;</td> stupid as it may sound, but i was still curious to know why the blank space is out there..or is it just a simple typo?? :) also, any idea what window.lol&&lol() does? curious yet again, google search didnt get me any result and i thought i would turn to stackoverflow to enlighten me... thanks, ivar

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  • SPAN inside A inside H1 display in Chrome 5

    - by devils-avacado
    <h1> <a>Lorem ipsum <span>dolor</span> </a> </h1> In Chrome the contents of the SPAN have a line break in front of them, "dolor" is displayed on the line below, even with display:inline explicitly set. Expected it to display on same line as "Lorem ipsum". Displays fine in IE8 and FF3.5. Any fixes? Chrome 5.0.375.38 on Win7 x64

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  • how to send a POST value to a server with a PHP script waiting for it from iPhone app

    - by Sam Jarman
    Hi In my iPhone app - I am trying to get what the user types in a box emailed to me. I am going to use a PHP script sitting on my server, and try send the data to it for it to be processed. Promblem is... how do i do this? Im using the ASIHTTPRequest wrapper and have some code like this ASIFormDataRequest *request = [[[ASIFormDataRequest alloc] initWithURL:url] autorelease]; [request setPostValue:@"[email protected]" forKey:@"address"]; [request setPostValue:@"mymessagehere" forKey:@"message"]; and have this simple php script which i plan to use here http://www.w3schools.com/PHP/php_mail.asp How do I go about joining these up? Any tutorial links/blog post/ideas appreciated

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  • How to condense onclick code to be dynamic

    - by opbeta
    I am trying to get this onclick function code to be dynamic. I do not want to have 50 blocks of code for all the states. He is a quick snippet of the code var Ohio=function(){ document.getElementById('texas').style.display='none'; document.getElementById('florida').style.display='none'; document.getElementById('ohio').style.display='block'; } and so on and so forth..... How would I go about condensing this to make it smaller and dynamic?

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  • JQuery Validate Dynamic Table

    - by Richard
    I'm using the JQuery validation plug to validate my entire form. I also have a dynamic table on my registration page where the user can register more people. I can validate the rest of the form fine but my goal is to validate the table inputs just the same. Here is my jfiddle code: tables I don't know why the add line won't work there but it definitely works on my page. Anyway, that code ends up validate ONLY the first row of my table, but I want it to validate every single row. Can anyone see any problems with the code?

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  • any suggestions on this css print problem

    - by user225269
    I have this code on my print.css: #header, #tae, #nav, .noprint {display: none;} width: 100%; margin: 0; float: none; In order not to display the elements within those div tags. But I don't know with the code below why it isn't cooperating. If I place the div tags on it. And then I hit the print button. I see no output. Here it is: <div id="tae"> <table border="0" align="center" cellpadding="0" cellspacing="0" class="bg1"> <tr> <td class="text1" style="height: 50px;">xd627 information management system</td> </tr> <tr> <td class="bg5"><table border="0" cellspacing="0" cellpadding="0" style="height: 62px; padding-top: 15px;"> <tr align="center"> <td><a href="userpage.php" class="link1">Homepage</a></td> <td><a href="RegStuds.php" class="link1">Database</a></td> <td><a href="#" class="link1">About</a></td> <td>&nbsp;</td> <td>&nbsp;</td> <td>&nbsp;</td> </tr> </table></td> </tr> <tr> <td valign="top" class="bg6">&nbsp;</td> </tr> <tr> <td><table width="780" border="0" cellspacing="0" cellpadding="0"> <tr valign="top"> <td width="20">&nbsp;</td> <td width="297"><table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr> <td><img src="images/spacer.gif" alt="" width="30" height="30" /></td> </tr> </tr> <tr> <td class="text2"> </div> <div id="max"> <?php //some php code in here showing a mysql table. ?> </div> What's wrong with my code? Does the php script depend on the one where I put the div tag in? What do I do? All I want to show up in my page when printed is the mysql table. I'm using Universal Document Converter to simulate printing.

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  • What route to take to become a systems developer?

    - by Ramin
    In the past I have done a lot of Java and Python coding. Mostly, I worked on web apps and some simple console or gui apps. I also have a formal education in computer science. What route should I take to become a systems developer? I always did like C++, but never had a chance to use it for anything. Would mastering C++ be one of the steps? If so what resources can you suggest? Also, I would like to know how much different is the work between plain old development and systems development. There seem to be a lot of overlapping between the two.

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  • Flash animations with Javascript?

    - by RichardBlizzard
    Hi all, How does something like this work without Flash? http://www.dirtyphonebook.com/dashboard/425-205-1921 I right-clicked on it but there's no Flash menu. I love Flash because its stable and works. But is using some sort of Javascript hack for this kind of complex behavior actually a good idea?

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  • What does this JavaScript error mean?

    - by Tommy
    Using the “Venkman” JavaScript debugger for Mozilla and getting the following error: XML Parsing Error: not well-formed Location: x-jsd:source?location=http%3A%2F%2F192.168.1.150%2Fscript.js&instance=337 Line Number 557, Column 50:<line><margin x='t'> - </margin><num> 554</num> ?? valid = false;</line> Functions works but I don't understand the error. Any help is appreciated. Thanks. function ValidateCheckBoxes() { var valid; $(document).ready(function(){ if($('input[@name=boxesA]:checked').size() == 0) {     valid = false; } else { valid = true; } }); return valid; }

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  • In the following list, how do I prevent jQuery from interacting with part of it.

    - by kylex
    I have the following list structure: <ul> <li>One</li> <li class="topActive">Two <ul> <li class="active">Two-1 <ul> <li>Two-1-1</li> </ul> </li> <li>Two-2</li> </ul> </li> <li>Three <ul> <li>Three-1</li> </ul> </li> </ul> with the following jQuery: $("ul>li>ul").hide(); $("ul>li>ul>li>ul").hide(); $("ul>li>ul>li>ul>ul>li").hide(); $('.active').parents().show();????????? $("ul>li").hoverIntent( function(){ $(this).children('ul').slideDown('fast'); }, function(){ $(this).children('ul').slideUp('fast'); } ); $("ul>li>ul>li").hoverIntent( function(){ $(this).children('ul').slideDown('fast'); }, function(){ $(this).children('ul').slideUp('fast'); } ); What I would like is this: When an li class is topActive, everything within that class down to the current class can not be affected by the jQuery that causes the list to slide up and down. so in the case provided the following would show, along with the top level: One Two Two-1 Two-2 Three And when I mouse over either, Two, or Two-1 or Two-2 nothing happens, but if I mouse over Three, the jQuery will cause it to slide up or slide down. In this example: <ul> <li>One</li> <li class="topActive">Two <ul> <li class="active">Two-1 <ul> <li>Two-1-1</li> </ul> </li> <li>Two-2</li> </ul> </li> <li>Three <ul> <li>Three-1</li> </ul> </li> </ul> When I mouseover Two-1, it will slide down, but when I mouse out Two-1 will remain. One Two Two-1 Two-2 Three Any suggestsions for either a CSS or jQuery implementation (or mixture of the two)?

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