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  • Crystal Reports : How to add an external assembly class?

    - by Sunil
    I am using VS2010, CrystalReport13 & MVC3. My problem is unable to add an external assembly in Crystal Report using "Database Expert" Option. I have a class named WeeklyReportModel in an external assembly. In my web project, data retrieving from DB as IEnumerable collection of WeeklyReportModel. I tried ProjectData - .NetObjects in Crystal Report for adding the WeeklyReportModel. But this external assembly is not showing under ".NetObjects". Then I tried other option as Create New Connection - ADO.Net – Make New Connection and pointed this External Assembly. It has been added under Ado.Net node, but while expanding displays as "...no items found..." Totally frustrated. Please help. External Assembly Class: namespace SMS.Domain { public class WeeklyReportModel { public int StoreId { get; set; } public string StoreName{ get; set; } public decimal Saturday { get; set; } public decimal Sunday { get; set; } public decimal Monday { get; set; } public decimal Tuesday { get; set; } public decimal Wednesday { get; set; } public decimal Thurday { get; set; } public decimal Friday { get; set; } public decimal Average { get; set; } public string DateRange { get; set; } } } In Controller-action[Data retrieving as Collection Of WeeklyReportModel] namespace SMS.UI.Controllers { public class ReportController : Controller { public ActionResult StoreWeeklyReport(string id) { DateTime weekStart, weekClose; string[] dateArray = id.Split('_'); weekStart = Convert.ToDateTime(dateArray[0].ToString()); weekClose = Convert.ToDateTime(dateArray[1].ToString()); SMS.Infrastructure.Report.AuditReport weeklyReport = new SMS.Infrastructure.Report.AuditReport(); IEnumerable<SMS.Domain.WeeklyReportModel> weeklyRpt = weeklyReport.ReportByStore().WeeklyReport(weekStart, weekClose); Session["WeeklyData"] = weeklyRpt; Response.Redirect("~/Reports/Weekly/StoreWeekly.aspx"); return View(); } } } Thanks in advance.

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  • uncheck all checkboxes except the one with a class?

    - by Dejan.S
    hi i try to check/uncheck all checkboxes that don't got a class to them. This is the code I got but it check the class boxes to. $(document).ready(function() { $('#ctl00_ContentPlaceHolder1_repReceivers_ctl00_chxAll').click( function() { if (!$("input[type='checkbox']").hasClass("testclass")) { $("input[type='checkbox']").attr('checked', $('#ctl00_ContentPlaceHolder1_repReceivers_ctl00_chxAll').is(':checked')); }}); }); any ideas where I go wrong?

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  • How does msbuild decide whether it needs to rebuild a C# library or not?

    - by Peter Mounce
    Per subject, how does msbuild decide whether it needs to rebuild a library (ie, invoke csc), or not, when it is run against a C# project file? I imagine (but want to confirm): If there's no output directory, rebuild (duh :) ) If a C# file has changed, rebuild If an included file marked copy-always has changed, rebuild or is it smart enough to not rebuild, but just copy the file to the existing output? If an included file marked copy-if-newer has changed, rebuild same question as above

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  • Geometry library for python (or C++) for CAD-like operations?

    - by gct
    I'm trying to put together a simple program that will let me visualize a series of consecutive cuts on a wood panel using a router with a particular cutting head. I'm trying to find a decent geometry library that will give me a shortcut through the CAD-like stuff. Specifically, I'd like to be able to define a rectangular solid (the wood panel) and then define a bit profile shape, and take cuts through the rectangular solid (sometimes on a straight line, sometimes on a circular arc). Does anyone know of anything that will do this?

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  • How to add the document library column named "Type (icon linked to document)" into list view?

    - by Sushant
    I am working with a list view. I want a column to have look similar to the document library column named "Type (icon linked to document)" column. I should also be able to set the path this hyperlinked icon should open. I tried a lot with existing site columns but could still not figure out how to do this. Has anyone implemented this earlier. Please share your expertise. Thanks in advance.

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  • Standard library function in R for finding the mode?

    - by Nick
    In statistical language R, mean() and median() are standard functions which do what you'd expect. mode() tells you the internal storage mode of the R object, not the value that occurs the most in its argument. But surely there is a standard library function that implements mode for a vector (or list).

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  • Why does the destructor of the class called twice ?

    - by dicaprio
    Apologies if the question sounds silly, I was following experts in SO and trying some examples myself, and this is one of them. I did try the search option but didn't find an answer for this kind. class A { public: A(){cout t; t.push_back(A()); // After this line , when the scope of the object is lost. } Why does the destructor of the class called twice ?

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  • C++ Library for implementing a web services api over legacy code?

    - by leeand00
    Does anyone know of any really good C++ Libraries for implementing a web services api over top of existing legacy code? I've got two portions that are in need of it: An old-school client/server api (No, not web based, that's the problem) An old cgi application that it integrates with the client and server. Let me know if you've had any luck in the past implementing something like this using the library.

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  • Why is jQuery's .removeClass() adding a space to the class attribute?

    - by Sosh
    I'm having some strange issues with .removeClass() and .addClass() in jQuery. Specifically it seems that when I use .removeClass() the class is indeed removed, but a single space is left in it's place. then when I .addClass("secondclass") I get class=" secondclass" (with the space in front). I'm using jQuery 1.4.1 Is this intended behaviour or a bug? How to stop it?

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  • How to map UID to user name using Perl library functions?

    - by Mike
    I'm looking for a way of mapping a uid (unique number representing a system user) to a user name using Perl. Please don't suggest greping /etc/passwd :) Edit As a clarification, I wasn't looking for a solution that involved reading /etc/passwd explicitly. I realize that under the hood any solution would end up doing this, but I was searching for a library function to do it for me.

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  • how to generate JMX MXBean compatible java class model from JAXB?

    - by yucubby
    From the JMX MXBean specification, a java class type J must satisfy Either if J has at least one public constructor with a ConstructorProperties annotation, Or if J has a public no-arg constructor, and for every getter in J with type T and name N there is a corresponding setter with the same name and type So how can I use JAXB to generate JAVA class model which satisfy the MXBean constrain? Thanks YU

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  • How to pickle and unpickle objects with self-references and from a class with slots?

    - by EOL
    Is it possible to pickle an object from a class with slots, when this object references itself through one of its attributes? Here is a simple example: import weakref import pickle class my_class(object): __slots__ = ('an_int', 'ref_to_self', '__weakref__') def __init__(self): self.an_int = 42 self.ref_to_self = weakref.WeakKeyDictionary({self: 1}) # __getstate__ and __setstate__ not defined: how should this be done? if __name__ == '__main__': obj = my_class() # How to make the following work? obj_pickled = pickle.dumps(obj) obj_unpickled = pickle.loads(obj_pickled) # Self-references should be kept: print "OK?", obj_unpickled == obj_unpickled.ref_to_self.keys()[0]

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  • Is there a C++ cross platform key/value API or library for C++?

    - by Tim
    We want to persist some user settings int he GUI part of our code. I used to do Win32 programming exclusively and the typical way this was done was with registry settings. I assume that this should be done with configuration files, but was wondering if there was a library or cross platform wrapper that made key/value pair persistence very easy.

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