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  • How to design tag database structure?

    - by liuxingruo
    I have a subjects database, and I want to create a new tag database to tag the subjects, but I have no idea how to design the new tag database structure. I'm assuming the new database looks like this: tag_id tag_name tagged_subject_ids 1 tag1 1, 2, 3, 5, 10 2 tag2 2, 4, 5, 6, 10, 12 so, if I want to select the tags belong to subject 1: SELECT tag_name FROM tag_database WHERE tagged_subject_ids LIKE '1'; I think the way that I select tag may be very slow, so please help me. Thanks!

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  • PHP: How To Integrate HTML Purifier To Fileter User Submitted Data?

    - by TaG
    I have this script that collects data from users and I wanted to check their data for malicious code like XSS and SQL injections by using HTML Purifier http://htmlpurifier.org/ but how do I add it to my php form submission script? Here is my HTML purifier code require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $clean_html = $purifier->purify($dirty_html); Here is my PHP form submission code. if (isset($_POST['submitted'])) { // Handle the form. $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $_POST['about_me']); $interests = mysqli_real_escape_string($mysqli, $_POST['interests']); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } }

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  • i demand you all men to help

    - by Hello you all men
    you all men i demand answer, you say not real question?? many page get big load for long time and now we are suspended and http://stackoverflow.com/questions/2890840/how-can-we-make-our-website-scalable and please you help men very sorry -bern

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  • Improving the speed of php

    - by cast01
    I'm currently working on a website in PHP, and I'm wondering what the best practices/methods are to reduce the time requests take. I've build the site in a modular way, so a page would consist of a number of modules, and each of these would need to request information. For example, I have a cart module, that (if a cart is set) will fetch the cart with the id (stored in a session variable) from the database and return its contents. I have another module that lists categories and this needs to fetch the categories from the database. My system is built with models, and each model might also make a request, for example a category model will make a request to get products in that category.

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  • ZIP Numerous Blob Files

    - by Michael
    I have a database table that contains numerous PDF blob files. I am attempting to combine all of the files into a single ZIP file that I can download and then print. Please help! <?php include 'config.php'; include 'connect.php'; $session= $_GET[session]; $query = " SELECT $tbl_uploads.username, $tbl_uploads.description, $tbl_uploads.type, $tbl_uploads.size, $tbl_uploads.content, $tbl_members.session FROM $tbl_uploads LEFT JOIN $tbl_members ON $tbl_uploads.username = $tbl_members.username WHERE $tbl_members.session= '$session'"; $result = mysql_query($query) or die('Error, query failed'); while(list($username, $description, $type, $size, $content) = mysql_fetch_array($result)) { header("Content-length: $size"); header("Content-type: $type"); header("Content-Disposition: inline; filename=$username-$description.pdf"); echo $content; } $files = array('File 1 from database', 'File 2 from database'); $zip = new ZipArchive; $zip->open('file.zip', ZipArchive::CREATE); foreach ($files as $file) { $zip->addFile($file); } $zip->close(); header('Content-Type: application/zip'); header('Content-disposition: attachment; filename=filename.zip'); header('Content-Length: ' . filesize($zipfilename)); readfile($zipname); mysql_close($link); exit; ?>

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  • many-to-many query

    - by kofto4ka
    Hello, guys! I have a problem and I dont know what is better solution. Okay, I have 2 tables: posts(id, title), posts_tags(post_id, tag_id). I have next task: must select posts with tags ids for example 4, 10 and 11. Not exactly, post could have any other tags at the same time. So, how I could do it more optimized? Creating temporary table in each query? Or may be some kind of stored procedure? In the future, user could ask script to select posts with any count of tags (it could be 1 tag only or 10 at the same time) and I must be sure that method that I will choose would be the best method for my problem. Sorry for my english, thx for attention.

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  • same table, 1 field to 2 field query

    - by edib
    I have 2 tables: 1st holds employees (of ones in any position) and the 2nd holds manager employee relations with id numbers. I want to write a query like 1st field: name(employee), 2nd field: name(manager) How can I do that?

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  • SQL Count Query with Grouping by multiple Columns

    - by Christian
    I have a table with three filled columns named "Name", "City" and "Occupation". I want to create a new column in the same table that contains the number of people who have the same occupation. "Name" | "City" | "Occupation" ------------------------------ Amy | Berlin | Plumber Bob | Berlin | Plumber Carol | Berlin | Lawyer David | London | Plumber I want to have a table that contains: "Name" | "City" | "Occupation" | "Number" --------------------------------------- Amy | Berlin | Plumber | 2 Bob | Berlin | Plumber | 2 Carol | Berlin | Lawyer | 1 David | London | Plumber | 1 How does the SQL Query that creates the new columns have to look like? I want to actually create a new column in the database that I can access later.

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  • storing data at remote server using php

    - by VIPUL GOYAL
    I want to send data to php file and execute insert query in it to store data in database. When i execute this code, it executes but database does not get updated. Code of PHP file Java code------------------------------Remote.java------------------------------ public class Remote extends Activity { EditText name; Button s; String r; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); name= (EditText)findViewById(R.id.editText1); s=(Button)findViewById(R.id.button1); s.setOnClickListener(new OnClickListener() { public void onClick(View v) { try { r = name.getText().toString(); ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>(); postParameters.add(new BasicNameValuePair("username", r)); CustomHttpClient.executeHttpPost("http://vipul.eu5.org/abc.php", postParameters); //Enetr Your remote PHP,ASP, Servlet file link } catch (Exception e) { e.printStackTrace(); } } }); } } -----------------------------CustomHttpClient.java---------------------------- public class CustomHttpClient { private static HttpClient getHttpClient() { if (mHttpClient == null) { mHttpClient = new DefaultHttpClient(); final HttpParams params = mHttpClient.getParams(); HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT); HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT); ConnManagerParams.setTimeout(params, HTTP_TIMEOUT); } return mHttpClient; } /** * Performs an HTTP Post request to the specified url with the * specified parameters. * * @param url The web address to post the request to * @param postParameters The parameters to send via the request * @return The result of the request * @throws Exception */ public static void executeHttpPost(String url, ArrayList postParameters) throws Exception { try { HttpClient client = getHttpClient(); HttpPost request = new HttpPost(url); UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters); request.setEntity(formEntity); HttpResponse response = client.execute(request); } catch(Exception e) { } } }

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  • again new query. i am trying to solve this from one hour. please help

    - by Dharmendra
    Query : List the film title and the leading actor for all of 'Julie Andrews' films. there are three tables : movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord) select movie.title,actor.name as cont from movie join casting on (movie.id=casting.movieid) join actor on (casting.actorid=actor.id) where actor.name='Julie andrews' actually i can' get how to find the leading actor.

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  • SQL where clause to work with Group by clause after performing a count()

    - by Matt
    Tried my usual references at w3schools and google. No luck I'm trying to produce the following results. QTY is a derived column | Position | QTY -------------------- 1 Clerk 2 2 Mgr 2 Here's what I'm not having luck with: SELECT Position, Count(position) AS 'QTY' FROM tblemployee Where ('QTY' != 1) GROUP BY Position I know that my Position is set up as varchar(255) Count produces a integer data and my where clasue is accurate so that leads me to believe that that Count() is jamming me up. Please throw up an example so I can reference later. Thanks for the help!

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  • how escape quotes when inserting into database in PHP

    - by Mauro74
    Hi all, I'm quite new to PHP so sorry if sounds such an easy problem... :) I'm having an error message when inserting content which contains quotes into my db. here's what I tried trying to escape the quotes but didn't work: $con = mysql_connect("localhost","xxxx","xxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("test", $con); $nowdate = date('d-m-Y') $title = sprintf($_POST[title], mysql_real_escape_string($_POST[title])); $body = sprintf($_POST[body], mysql_real_escape_string($_POST[body])); $sql="INSERT INTO articles (title, body, date) VALUES ('$title','$body','$nowdate'),"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); Could you provide any solution please? Thanks in advance. Mauro

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  • How to make a Round Robin? or Is there an easier way other than Round Robin?

    - by candies
    The problem that I face is in what way if there is issue like the example below: Codes 1000, 2000, 3000, 4000, 5000 ID 1, 2, 3 ======================================== This: ID number 1 has codes 1000, 2000, 3000, 4000 ID number 2 has codes 2000, 4000, 3000 ID number 3 has codes 3000, 4000, 5000 ======================================== When all the fields are connected, each ID has found the same codes. From the example above, I want to produce fair result and adjusted to the code that it had before on each ID as below: ======================================== To be: ID number 1 has codes 1000, 2000 (1000 must be on number 1 cause only it has than other) ID number 2 has codes 3000, 4000 ID number 3 has codes 5000 (5000 must be on number 3 cause only it has than other) ======================================== Some say using Round Robin, but I never heard Round Robin before and I don't have idea how to use it, such a blank mind. Is there another easier way like to use PHP may be? I'm lost. Thanks.

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  • Modifying my website to allow anonymous comments

    - by David
    I write the code for my own website as an educational/fun exercise. Right now part of the website is a blog (like every other site out there :-/) which supports the usual basic blog features, including commenting on posts. But I only have comments enabled for logged-in users; I want to alter the code to allow anonymous comments - that is, I want to allow people to post comments without first creating a user account on my site, although there will still be some sort of authentication involved to prevent spam. Question: what information should I save for anonymous comments? I'm thinking at least display name and email address (for displaying a Gravatar), and probably website URL because I eventually want to accept OpenID as well, but would anything else make sense? Other question: how should I modify the database to store this information? The schema I have for the comment table is currently comment_id smallint(5) // The unique comment ID post_id smallint(5) // The ID of the post the comment was made on user_id smallint(5) // The ID of the user account who made the comment comment_subject varchar(128) comment_date timestamp comment_text text Should I add additional fields for name, email address, etc. to the comment table? (seems like a bad idea) Create a new "anonymous users" table? (and if so, how to keep anonymous user ids from conflicting with regular user ids) Or create fake user accounts for anonymous users in my existing users table? Part of what's making this tricky is that if someone tries to post an anonymous comment using an email address (or OpenID) that's already associated with an account on my site, I'd like to catch that and prompt them to log in.

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  • Databases design - one link table or multiple link tables?

    - by David
    Hi there, I'm working on a front end for a database where each table essentially has a many to many relationship with all other tables. I'm not a DB admin, just a few basic DB courses. The typical solution in this case, as I understand it, would be multiple link tables to join each 'real' table. Here's what I'm proposing instead: one link table that has foreign key dependencies to all other PKs of the other tables. Is there any reason this could turn out badly in terms of scalability, flexibility, etc down the road?

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  • How to implement filter system in SQL?

    - by sadvaw
    Right now I am planning to add a filter system to my site. Examples: (ID=apple, COLOR=red, TASTE=sweet, ORIGIN=US) (ID=mango, COLOR=yellow, TASTE=sweet, ORIGIN=MEXICO) (ID=banana, COLOR=yellow, TASTE=bitter-sweet, ORIGIN=US) so now I am interested in doing the following: SELECT ID FROM thisTable WHERE COLOR='yellow' AND TASTE='SWEET' But my problem is I am doing this for multiple categories in my site, and the columns are NOT consistent. (like if the table is for handphones, then it will be BRAND, 3G-ENABLED, PRICE, COLOR, WAVELENGTH, etc) how could I design a general schema that allows this? Right now I am planning on doing: table(ID, KEY, VALUE) This allows arbitary number of columns, but for the query, I am using SELECT ID FROM table WHERE (KEY=X1 AND VALUE=V1) AND (KEY=X2 AND VALUE=V2), .. which returns an empty set. Can someone recommend a good solution to this? Note that the number of columns WILL change regularly

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  • Do a query only if there are no results on previous query

    - by yes123
    Hi guys: I do this query(1): (1)SELECT * FROM t1 WHERE title LIKE 'key%' LIMIT 1 I need to do a second(2) query only if this previous query has no results (2)SELECT * FROM t1 WHERE title LIKE '%key%' LIMIT 1 basically i need only 1 row who got the most close title to my key. Atm i am using an UNION query with a custom field to order it and a LIMIT 1. Problem is I don't want to do the others query if already the first made the result. Thanks

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  • [PHP] Associate different data

    - by Alex Cane
    I will try to be as clear as possible because I can't get anybody to help me around, I am trying to associate some data from a 'videos' table with their respective ID. Lets say, I have column ID, title, serie, season, episode. I am getting my data : <? $result = mysql_query("SELECT * FROM videos WHERE serie = '".$row['serie']."' AND season = '".$row['season']."'"); $total_rows = mysql_num_rows($result); ?> (that is in the page where you see the video itself) So now I can get the number of episodes from a serie and season. What I'm trying to do is have a link for the next episode, and aa link for the previous one. In the URL I am working with the id, so http://website.com/view/id/'video id here'/ So how can I get the ID of the following and previous episodes of the same season AND serie? Help will be much appreciated! The easiest thing I thought of is <?=$row['id'] + 1?> <?=$row['id'] - 1?> But the thing is that it's mixed videos, so it wont work 100%

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  • Thoughts/Input about Database Design for a CMS

    - by dallasclark
    I'm just about to expand the functionality of our own CMS but was thinking of restructuring the database to make it simpler to add/edit data types and values. Currently, the CMS is quite flat - the CMS requires a field in the database for every type of stored value (manually created). The first option that comes to mind is simply a table which keeps the data types (ie: Address 1, Suburb, Email Address etc) and another table which holds values for each of these data types. Just like how Wordpress keeps values in the 'options' table, PHP serialize would be used to store an array of values. The second option is how Drupal works, the CMS creates tables for every data type. Unlike Wordpress, this can be a bit of an overkill but really useful for SQL queries when ordering and grouping by a particular value. What's everyone's thoughts?

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  • Access 2007 file picker, replaces all rows with the same choice.

    - by SqlStruggle
    This code is from an Access 2007 project I've been struggling with. The actual mean part is the part where I should put something like "update only current form" DoCmd.RunSQL "Update Korut Set [PikkuKuva]=('" & varFile & "') ;" Could someone please help me with this?` If I use it now, it updates all the tables with the same file picked. Heres the whole code. ' This requires a reference to the Microsoft Office 11.0 Object Library. Dim fDialog As Office.FileDialog Dim varFile As Variant Dim filePath As String ' Set up the File dialog box. Set fDialog = Application.FileDialog(msoFileDialogFilePicker) With fDialog ' Allow the user to make multiple selections in the dialog box. .AllowMultiSelect = False ' Set the title of the dialog box. .Title = "Valitse Tiedosto" ' Clear out the current filters, and then add your own. .Filters.Clear .Filters.Add "All Files", "*.*" ' user picked at least one file. If the .Show method returns ' False, the user clicked Cancel. If .Show = True Then ' Loop through each file that is selected and then add it to the list box. For Each varFile In .SelectedItems DoCmd.SetWarnings True DoCmd.RunSQL "Update Korut Set [PikkuKuva]=('" & varFile & "') ;" Next Else MsgBox "You clicked Cancel in the file dialog box." End If End With

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  • How to sekect latest chnge done in the given Table structure?

    - by OM The Eternity
    I have a Table structure as id, trackid, table_name, operation, oldvalue, newvalue, field, changedonetime Now if I have 3 rows for the same "trackid" same "field", then how can i select the latest out of the three? i.e. for e.g.: id = 100 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPL newvalue = IPLcccc field = name live = 0 changedonetime = 2010-04-30 17:54:39 and id = 101 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPLcccc newvalue = IPL2222 field = name live = 0 changedonetime = 2010-04-30 18:54:39 As u can see above the secind entry is the latest change, Now what query I shoud use to get the only one and Latest row out of many such rows...

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  • How can I write this query in Django? (datetime)

    - by alex
    | time_before | datetime | YES | MUL | NULL | | | time_after | datetime | YES | MUL | NULL | | the_tag = Tag.objects.get(id=tag_id) Log.objects.filter(blah).extra(where=['last_updated >'+the_tag.time_before, 'last_updated' < the_tag.time_after]) Ok. Basically, I have an object that's called "the_tag". I want to select from Log where log.last_updated (which is a datetime field) is between the tag's time. But, I don't know how to write the last part of this Django query.

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  • SQL Like question

    - by mike
    Is there a way to reverse the SQL Like operator so it searches a field backwards? For example, I have a value in a field that looks like this "Xbox 360 Video Game". If I write a query like below, it returns the result fine. SELECT id FROM table WHERE title like "%Xbox%Game%" However, when I search like this, it doesn't find any results. SELECT id FROM table WHERE title like "%Video%Xbox%" I need it to match in any direction. How can I get around this?

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  • Audit Table using Triggers

    - by Jose
    DROP TABLE IF EXISTS `actividades`.`act_actividad_audit`; CREATE TABLE `actividades`.`act_actividad_audit` ( `fe_creacion` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP, `usr_digitador` char(10) NOT NULL, `ip_digitador` char(15) NOT NULL, `id_act_actividad` int(10) unsigned NOT NULL, `titulo` char(64) NOT NULL, `act_prioridad_id` int(10) unsigned NOT NULL, `act_motivo_id` int(10) unsigned NOT NULL, `detalle` text, `detalle_tecnico` text, `hostname_id` int(10) unsigned NOT NULL, `hostname_nombre` char(50) NOT NULL, `es_SMOP` tinyint(1) NOT NULL, `url_SMOP` text, `es_tecnico` tinyint(1) NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1 COMMENT='Auditoria Actividad General'; I want to populate that audit table with a trigger but how can i send or fill the values for usr_digitador or ip_digitador if that values are on client side.? please help

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