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  • Select * from 'many to many' SQL relationship

    - by Rampant Creative Group
    I'm still learning SQL and my brain is having a hard time with this one. Say I have 3 tables: teams players and teams_players as my link table All I want to do is run a query to get each team and the players on them. I tried this: SELECT * FROM teams INNER JOIN teams_players ON teams.id = teams_players.team_id INNER JOIN players ON teams_players.player_id = players.id But it returned a separate row for each player on each team. Is JOIN the right way to do it or should I be doing something else? ----------------------------------------- Edit Ok, so from what I'm hearing, this isn't necessarily a bad way to do it. I'll just have to group the data by team while I'm doing my loop. I have not yet tried the modified SQL statements provided, but I will today and get back to you. To answer the question about structure - I guess I wasn't thinking about the returned row structure which is part of what lead to my confusion. In this particular case, each team is limited to 4 players (or less) so I guess the structure that would be helpful to me is something like the following: teams.id, teams.name, players.id, players.name, players.id, players.name, players.id, players.name, players.id, players.name, 1 Team ABC 1 Jim 2 Bob 3 Ned 4 Roy 2 Team XYZ 2 Bob 3 Ned 5 Ralph 6 Tom

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  • Echo autoincrement id doubt

    - by Marcelo
    Hi, can I print the id, even if it's autoincrement ? Because the way I'm doing I'm using an empty variable for id. $id= ""; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die ("Não conectou com a base $database"); mysql_query("INSERT INTO table1(id,...) VALUES ('".$id."',....)") or die(mysql_error()); mysql_close(); echo "Your id is :"; echo "".$id; I'm trying to print the id, but it's coming blank. I checked the table and there's an id number there. How can I print it then at? Thanks for the attention

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  • Data Modeling of Entity with Attributes

    - by StackOverflowNewbie
    I'm storing some very basic information "data sources" coming into my application. These data sources can be in the form of a document (e.g. PDF, etc.), audio (e.g. MP3, etc.) or video (e.g. AVI, etc.). Say, for example, I am only interested in the filename of the data source. Thus, I have the following table: DataSource Id (PK) Filename For each data source, I also need to store some of its attributes. Example for a PDF would be "numbe of pages." Example for audio would be "bit rate." Example for video would be "duration." Each DataSource will have different requirements for the attributes that need to be stored. So, I have modeled "data source attribute" this way: DataSourceAttribute Id (PK) DataSourceId (FK) Name Value Thus, I would have records like these: DataSource->Id = 1 DataSource->Filename = 'mydoc.pdf' DataSource->Id = 2 DataSource->Filename = 'mysong.mp3' DataSource->Id = 3 DataSource->Filename = 'myvideo.avi' DataSourceAttribute->Id = 1 DataSourceAttribute->DataSourceId = 1 DataSourceAttribute->Name = 'TotalPages' DataSourceAttribute->Value = '10' DataSourceAttribute->Id = 2 DataSourceAttribute->DataSourceId = 2 DataSourceAttribute->Name = 'BitRate' DataSourceAttribute->Value '16' DataSourceAttribute->Id = 3 DataSourceAttribute->DataSourceId = 3 DataSourceAttribute->Name = 'Duration' DataSourceAttribute->Value = '1:32' My problem is that this doesn't seem to scale. For example, say I need to query for all the PDF documents along with thier total number of pages: Filename, TotalPages 'mydoc.pdf', '10' 'myotherdoc.pdf', '23' ... The JOINs needed to produce the above result is just too costly. How should I address this problem?

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  • Showing all rows for keys with more than one row

    - by Leif Neland
    Table kal id integer primary key init char 4 indexed job char4 id init job --+----+------ 1 | aa | job1 2 | aa | job2 3 | bb | job1 4 | cc | job3 5 | cc | job5 I want to show all rows where init has more than one row id init job --+----+------ 1 | aa | job1 2 | aa | job2 4 | cc | job3 5 | cc | job5 I tried select * from kal where init in (select init from kal group by init having count(init)2); Actually, the table has 60000 rows, and the query was count(init)<40, but it takes humongus time, phpmyadmin and my patience runs out. Both select init from kal group by init having count(init)2) and select * from kal where init in ('aa','bb','cc') runs in "no time", less than 0.02 seconds. I've tried different subqueries, but all takes "infinite" time, more than a few minutes; I've actually never let them finish. Leif

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  • Altering constraint delete action

    - by Hobhouse
    I did this: ALTER TABLE `db`.`my_table` ADD CONSTRAINT FOREIGN KEY (`my_second_table_id`) REFERENCES `my_second_table` (`id`); I should have done this: ALTER TABLE `db`.`my_table` ADD CONSTRAINT FOREIGN KEY (`my_second_table_id`) REFERENCES `my_second_table` (`id`) ON DELETE SET NULL; Is it possible to ALTER this, or do I have to drop the constraint and add again?

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  • Webmail system script

    - by panidarapu
    Hello, I am planning to launch a free webmail service at mail(dot)com(dot)es where users can signup and have their free webmail account (for example like www.email.gr). I am looking for a free or low cost webmail system script to install on my website. Do you know any free or low cost scripts which would be suitable for this? Thanks

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  • Using memtables in sql. When is it reasonable and is it safe?

    - by Spiros
    I was just reading an update from a friend's project, mentioning the use of memtables to store data temporatily and then flush to a table on disk. Up to now, I have never faced a situation where I would use a memtable, or a situation where I would think the use of a mem table would be beneficial; so I wonder, when would someone use mem tables? what makes a memtable (appart from access speed) a reasonable choice? and how safe is it, even for temp data? there is always the limitation of available physical memory.

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  • can i use MAX function for each tuple in the retrieved data set

    - by kshama
    Hi, My table result contains fields: id count ____________ 1 3 2 2 3 2 From this table i have to form another table **score** which should look as follows id my_score ___________ 1 1.0000 2 0.6667 3 0.6667 That is my_score=count/MAX(count) but if i give the query as create TEMPORARY TABLE(select id,(count/MAX(count)) AS my_score from result); only 1 st row is retrieved.Can any one suggest the query so that my_score is calculated for all tuples. Thanks in advance.

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  • Basic join query understanding

    - by OM The Eternity
    I know this very silly, but can anybody help me in understanding what does this join query is doing in elabortive description? SELECT j1.* FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON (j1.trackid = j2.trackid AND j1.field = j2.field AND j1.changedone < j2.changedone) WHERE j1.operation = 'UPDATE' AND j1.trackid=$t_ids[$n] AND j2.id IS NULL I know its very silly, but i need to go ahead with my further need... Pls do help me...

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  • PHP is not called properly in IE using set interval function in Javascript

    - by Hemant
    Hi all, I am trying to show the message updated in DB using the following code var showtime = setInterval('redirect()',5000); ////Redirecting to DB Status ///// function redirect() { xmlhttp = GetXmlHttpObject(); if (xmlhttp==null) { alert ("Browser does not support HTTP Request"); return; } var url="isResultexist.php" xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } I am collecting the response from PHP here and using it to update the Messages on UI Problem here is it works fine 1st time when it called after 5sec but there after return the Same result even DB is updated, This works fine with Mozilla and google chrome browser regards hemant

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  • Is using Natural Join or Implicit column names not a good practice when writing SQL in a programming

    - by Jian Lin
    When we use Natural Join, we are joining the tables when both table have the same column names. But what if we write it in PHP and then the DBA add some more fields to both tables, then the Natural Join can break? The same goes for Insert, if we do a insert into gifts values (NULL, "chocolate", "choco.jpg", now()); then it will break the code as well as contaminating the table when the DBA adds some fields to the table (example as column 2 or 3). So it is always best to spell out the column names when the SQL statements are written inside a programming language and stored in a file in a big project.

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  • Shopping Cart Database Structure

    - by Paul Atkins
    Hi, I have been studying the database structure for shopping carts and notice that when storing order details the product information is repeated and stored again in the table. I was wondering what the reasoning behind this would be? Here is a small example of what i mean: Product Table product_id name desc price 1 product 1 This is product 1 27.00 Order Table order_id customer id order_total 1 3 34.99 Order Details Table order_details_id product_id product name price qty 1 1 product 1 27.00 1 So as you can see the product name and price are stored again in the order details table. Why is this? The only reason i can think of is because the product details may change after the order has been placed which may cause confusion. Is this correct? Thanks Paul

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  • Sql query - selecting top 5 rows and further selecting rows only if User is present

    - by Gublooo
    Hello, I kind of stuck on how to implement this query - this is pretty similar to the query I posted earlier but I'm not able to crack it. I have a shopping table where everytime a user buys anything, a record is inserted. Some of the fields are * shopping_id (primary key) * store_id * user_id Now what I need is to pull only the list of those stores where he's among the top 5 visitors: When I break it down - this is what I want to accomplish: * Find all stores where this UserA has visited * For each of these stores - see who the top 5 visitors are. * Select the store only if UserA is among the top 5 visitors. The corresponding queries would be: select store_id from shopping where user_id = xxx select user_id,count(*) as 'visits' from shopping where store_id in (select store_id from shopping where user_id = xxx) group by user_id order by visits desc limit 5 Now I need to check in this resultset if UserA is present and select that store only if he's present. For example if he has visited a store 5 times - but if there are 5 or more people who have visited that store more than 5 times - then that store should not be selected. So I'm kind of lost here. Thanks for your help

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  • PHP replace string help...

    - by MILESMIBALERR
    i am designing a site with a comment system and i would like a twitter like reply system. The if the user puts @a_registered_username i would like it to become a link to the user's profile. i think preg_replace is the function needed for this. $ALL_USERS_ROW *['USERNAME'] is the database query array for all the users and ['USERNAME'] is the username row. $content is the comment containing the @username i think this should not be very hard to solve for someone who is good at php. Does anybody have any idea how to do it?

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  • Using * in SELECT Query

    - by libregeek
    I am currently porting an application written in MySQL3 and PHP4 to MySQL5 and PHP5. On analysis I found several SQL queries which uses "select * from tablename" even if only one column(field) is processed in PHP. The table has almost 60 columns and it has a primary key. In most cases, the only column used is id which is the primary key. Will there be any performance boost if I use queries in which the column names are explicitly mentioned instead of * ? (In this application there is only one method which we need all the columns and all other methods return only a subset of the columns)

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  • Update multiple rows with one query?

    - by kavoir.com
    I found something that works with updating one field at here: http://www.karlrixon.co.uk/articles/sql/update-multiple-rows-with-different-values-and-a-single-sql-query/ UPDATE person SET name = CASE id WHEN 1 THEN 'Jim' WHEN 2 THEN 'Mike' WHEN 3 THEN 'Precious' END WHERE id IN (1,2,3) My question is how to update more than one field? Such as: UPDATE person SET name = CASE, sex = CASE id WHEN 1 THEN 'Jim', 'female' WHEN 2 THEN 'Mike' 'male' WHEN 3 THEN 'Precious', 'male' END WHERE id IN (1,2,3) Which doesn't work of course. Tried a few other combination and failed. Any idea? Thanks!

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  • SQL Query Returning Duplicate Results

    - by Jesse Bunch
    Hi, I've been working out this query now for a while and I thought I had it where I wanted it, but apparently not. There are two records in the database (orders). The query should return two different rows, but instead returns two rows that have exactly the same values. I think it may be something to do with the GROUP BY or derived tables I'm using but my eyes are tired and not seeing the problem. Can any of you help? Thanks in advance. SELECT orders.billerID, orders.invoiceDate, orders.txnID, orders.bName, orders.bStreet1, orders.bStreet2, orders.bCity, orders.bState, orders.bZip, orders.bCountry, orders.sName, orders.sStreet1, orders.sStreet2, orders.sCity, orders.sState, orders.sZip, orders.sCountry, orders.paymentType, orders.invoiceNotes, orders.pFee, orders.shipping, orders.tax, orders.reasonCode, orders.txnType, orders.customerID, customers.firstName AS firstName, customers.lastName AS lastName, customers.businessName AS businessName, orderStatus.statusName AS orderStatus, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax AS orderTotal, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax - IFNULL(payments.totalPayments, 0.00) AS orderBalance FROM orders LEFT JOIN customers ON orders.customerID = customers.id LEFT JOIN orderStatus ON orders.orderStatus = orderStatus.id LEFT JOIN ( SELECT orderItems.orderID, SUM(orderItems.itemPrice * orderItems.itemQuantity) as itemTotal FROM orderItems GROUP BY orderItems.orderID ) orderItems ON orderItems.orderID = orders.id LEFT JOIN ( SELECT payments.orderID, SUM(payments.amount) as totalPayments FROM payments GROUP BY payments.orderID ) payments ON payments.orderID = orders.id

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  • Take Current Snapshot of DB and send it to FTP in same PHP Scripts: Advice Needed

    - by Rachel
    Not sure if I can do it this way. I want to get current snapshot of the database and send it via FTP Server, both of this functionality should be implemented in PHP scripts. Here are the steps I am thinking on right now. In my php scripts(basically am extending an PDO into my Dao class and then preparing the query), $qry = SELECT * FROM MyTablename; $stmt = $this->prepare($qry); $stmt = $this->execute(); Now I will store $stmt in csv file using fputcsv or I will execute the sql command from the script itself and than try to store the result in the $file(csv file) note here that I do not have any csv file with me at this point to basically I will have to create one and let's say its $file, so then $file = fputcsv($stmt); or $file = exec("Select * from MyTablename"); Will this put all records in the file ? If yes, then I will use FTP Functionality to transfer file to the FTP Folder. I am not sure if this approach would work and also have concerns regarding the need of preparing the $qry Any suggestions or different approach advised would be highly appreciated. Thanks !!!

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  • Using a table-alias in Kohana queries?

    - by Aristotle
    I'm trying to run a simple query with $this->db in Kohana, but am running into some syntax issues when I try to use an alias for a table within my query: $result = $this->db ->select("ci.chapter_id, ci.book_id, ci.chapter_heading, ci.chapter_number") ->from("chapter_info ci") ->where(array("ci.chapter_number" => $chapter, "ci.book_id" => $book)) ->get(); It seems to me that this should work just fine. I'm stating that "chapter_info" ought to be known as "ci," yet this isn't taking for some reason. The error is pretty straight-forward: There was an SQL error: Table 'gb_data.chapter_info ci' doesn't exist - SELECT `ci`.`chapter_id`, `ci`.`book_id`, `ci`.`chapter_heading`, `ci`.`chapter_number` FROM (`chapter_info ci`) WHERE `ci`.`chapter_number` = 1 AND `ci`.`book_id` = 1 If I use the full table name, rather than an alias, I get the expected results without error. This requires me to write much more verbose queries, which isn't ideal. Is there some way to use shorter names for tables within Kohana's query-builder?

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  • SQL select statement

    - by kwokwai
    Hi all, I got a Table which has two fields: Point, and Level, with some sample data as follows: ----------------------- Point | Level ----------------------- 10 | Level 1 20 | Level 2 30 | Level 3 40 | Level 4 Suppose that there is a user who has 25 points, to find the Level in which this user is in, the Select statement I used was: Select Level from Table where Point < 30 AND Point > 20; But the Select SQL ststament is a hard-copy one where you can see the ponts 30 and 20 are fixed. I want to alter the Select statement so that the new SQL Select statement can be applied to all users with different points, but I don't know how to do it.

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  • Form is trying to save the login value of the submit button to my DB.

    - by Sergio Tapia
    Here's my Zend code: <?php require_once ('Zend\Form.php'); class Sergio_Form_registrationform extends Zend_Form { public function init(){ /*********************USERNAME**********************/ $username = new Zend_Form_Element_Text('username'); $alnumValidator = new Zend_Validate_Alnum(); $username ->setRequired(true) ->setLabel('Username:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($username); /*********************EMAIL**********************/ $email = new Zend_Form_Element_Text('email'); $alnumValidator = new Zend_Validate_Alnum(); $email ->setRequired(true) ->setLabel('EMail:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($email); /*********************PASSWORD**********************/ $password = new Zend_Form_Element_Password('password'); $alnumValidator = new Zend_Validate_Alnum(); $password ->setRequired(true) ->setLabel('Password:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($password); /*********************NAME**********************/ $name = new Zend_Form_Element_Text('name'); $alnumValidator = new Zend_Validate_Alnum(); $name ->setRequired(true) ->setLabel('Name:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($name); /*********************LASTNAME**********************/ $lastname = new Zend_Form_Element_Text('lastname'); $alnumValidator = new Zend_Validate_Alnum(); $lastname ->setRequired(true) ->setLabel('Last Name:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($lastname); /*********************DATEOFBIRTH**********************/ $dateofbirth = new Zend_Form_Element_Text('dateofbirth'); $alnumValidator = new Zend_Validate_Alnum(); $dateofbirth->setRequired(true) ->setLabel('Date of Birth:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($dateofbirth); /*********************AVATAR**********************/ $avatar = new Zend_Form_Element_File('avatar'); $alnumValidator = new Zend_Validate_Alnum(); $avatar ->setRequired(true) ->setLabel('Please select a display picture:'); $this->addElement($avatar); /*********************SUBMIT**********************/ $this->addElement('submit', 'login', array('label' => 'Login')); } } ?> Here's the code I use to save the values: public function saveforminformationAction(){ $form = new Sergio_Form_registrationform(); $request = $this->getRequest(); //if($request->isPost() && $form->isValid($_POST)){ $data = $form->getValues(); $db = $this->_getParam('db'); $db->insert('user',$data); //} } When trying to save the values, I recieve a ghastly error: Column 'login' not found.

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  • How to setup testing LAMP environment to work with outsourcing companies?

    - by Kelvin
    Hello Guys, I need to setup testing LAMP environment in my office to work with outsourcing companies. This is what I think should be done on my side: Setup testing web server with the same configuration as on production Setup testing SQL server with "fake data"? Outsourcers should have access only to some part of original code Outsourcers should use CVS to update their code Once testing is finished someone releases the update ............ How would you separate original code and database from testing environment, but keep it as close as possible to production? What is the general practice for setting up testing environment and how other companies deal with outsourcers? I will appreciate for any of your thoughts and ideas from your personal experience. Maybe someone can suggest some article on this topic. Thank you a lot!

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  • how do I insert an hidden token in my form to prevent double posts? (PHP)

    - by jpjp
    I want to prevent users from accidentally posting a comment twice. I use the PRG (post redirect get) method, so that I insert the data on another page then redirect the user back to the page which shows the comment. This allows users to refresh as many times as they want. However this doesn't work when the user goes back and clicks submit again or when they click submit 100 times really fast. I don't want 100 of the same comments. I looked at related questions on SO and found that a token is best. But I am having trouble using it. //makerandomtoken(20) returns a random 20 length char. <form method="post" ... > <input type="text" id="comments" name="comments" class="commentbox" /><br/> <input type="hidden" name="_token" value="<?php echo $token=makerandomtoken(20); ?>" /> <input type="submit" value="submit" name="submit" /> </form> if (isset($_POST['submit']) && !empty($comments)) { $comments= mysqli_real_escape_string($dbc,trim($_POST['comments'])); //how do I make the if-statment to check if the token has been already set once? if ( ____________){ //don't insert comment because already clicked submit } else{ //insert the comment into the database } } So I have the token as a hidden value, but how do I use that to prevent multiple clicking of submit.

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