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  • Normalization of database for timesheet tool and ensure data integrity

    - by fireeyedboy
    I'm creating a timesheet application. I have the following entities (amongst others): Company Employee = an employee associated with a company Client = a client associated with a company So far I have the following (abbreviated) database setup: Company - id - name Employee - id - companyId (FK to Company.id) - name Client - id - companyId (FK to Company.id) - name Now, I want an employee to be associated with a client, but only if that client is associated with the company the employee works for. How would you guarantee this data integrity on a database level? Or should I just depend on the application to guarantee this data integrity? I thought about creating a many to many table like this: EmployeeClient - employeeId (FK to Employee.id) - companyId \ (combined FK to Client.companyId, Client.id) - clientId / Thus, when I insert a client for an employee along with the employee's company id, the database should prevent this when the client is not associated with the employee's company id. Does this make sense? Because this still doesn't guarantee the employee is associated with the company. How do you deal with these things? UPDATE The scenario is as followed: A company has multiple employees. Employees will only be linked to one company. A company has multiple clients also. Clients will only be linked to one company. (Company is a sandbox, so to speak). An employee of a company can be linked to a client of it's company, but only if the client is part of the company's clientele. In other words: The application will allow a company to create/add employees and create/add clients (hence the companyId FK in the Employee and Client tables). Next, the company will be allowed to assign certain clients to certain of it's employees (EmployeeClient table). Imagine an employee working on projects for a few clients for which s/he can write billable hours, but the employee must not be allowed to write billable hours for clients they are not assigned to by their employer (the company). So, employees will not automatically have access to all their company's clients, but only to those that the company has selected for them. Hopefully this has shed some more light on the matter.

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  • Enter ID instead of name on submit (form)

    - by Derek
    In my activities table, I have a user ID and a project ID. When a user (of admin level) creates an activity they select from a drop down menu a project. Here is the select query to draw up appropriate values: $sql = "SELECT usersprojects_tb.projectid, projects.projectname FROM projects INNER JOIN usersprojects on projects.projectid = usersprojects.projectid WHERE usersprojects.userid = '".$_SESSION['SESS_USERID']."'"; And for the tag with the dropdown menu, I have this: <?php echo $row['projectname']?> I have tried submitting the form with 'projectid' here instead and the project ID is stored successfully in my activies table. However, the user needs to see the project names (IDs arent exactly user-friendly!) And with 'projectname' as displayed, they can select the names of the available projects (to associate an activity with) but the project ID is not stored, how I link this up, so that when the project name is sent, the ID for this project is stored properly in my activities table. I'm also having the exact same problem with the users drop down. As the admin user selects a user from the drop down to assign the task to. I exactly what I want, but I think I may be using the wrong syntax! Any help is much appreciated. Thanks.

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  • Establishing persistent connection to a database in Java

    - by gmile
    I've ran through several examples over the web, and found that every single time I need something from the DB, I should write the following code: try { // Step 1: Load the JDBC driver. Class.forName("mysql_driver_name"); // Step 2: Establish the connection to the database. String url = "jdbc:string_to_mysql_server"; Connection conn = DriverManager.getConnection(url,"user1","password"); // fetch from the DB ... } catch (Exception e) { System.err.println("Got an exception! "); System.err.println(e.getMessage()); } It's very annoying to put up this code every time I want something from the DB, so the question is - is there a way to only once connect entirely all my app to the DB somehow at the very start point, avoiding copy-pasting mentioned code, and then be able to do everything I want with DB? I've quickly looked through NetBeans's Project menu, but didn't find any clue on how to configurate a persistent connection to a selected DB. If it's important, i'm writing a purely desktop app, i.e. using Java EE. Also, it's worth mentioning that I'm a kinda beginner in Java.

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  • Dropdown dependent values to be fetch from multiple models using ajax in Yii

    - by newuser
    I searched all the documentation over Yii but not got the answer of it.So I came here finally. I have the following schema Table Schools +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_name | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ Table Students +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_id | int(10) | NO | FK | | | | student_name | varchar(100) | NO | | | | | roll_no | varchar(80) | NO | | | | | class | varchar(20) | NO | | | | | | subjects | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ I have made models and CRUD for the both models.In models my relation is like this In Students.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'School' => array(self::BELONGS_TO,'Schools','school_id'), ); } In Schools.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'student' => array(self::HAS_MANY, 'Students', 'school_id'), ); } Now I made the two models rendered in a single page so that I can enter all the respective fields in a single form. In the _form.php file of Students I have made some change in student_name like this <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php echo $form->dropdownList($model,'student_name', CHtml::listData(Students::model()->findAll(), 'id', 'student_name'), array('empty'=>array('Select'=>'--Select One---'))); ?> <?php echo $form->error($model,'student_name'); ?> Now for this piece of code I got all the student name from the Student model. So my problem is when I am getting the student name from the dropdown list and going to select a student it will also fetch all the respective values of the student to be rendered in the _form.php without click on save button.So that user don't have to put it again manually. I think ajax and json encode will work here but don't know how to make them work here. [Update] Here is StudentsController code public function actionDisCoor() { $model = School::model()->findByPk($_POST['Students']['student_id']); $data=CHtml::listData($data,'id','name'); foreach($data as $value=>$name) { echo CHtml::tag('option',array('value'=>$value),CHtml::encode($name),true); } } Here is _form.php code for Students <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php $List = CHtml::listData(Students::model()->findAll(), 'id', 'student_name'); ?> <?php echo $form->dropdownList($model,'student_name',$List, array('onChange'=>CHtml::ajax(array( 'url' => CController::createUrl('DisCoor'), 'type' => 'POST', 'update'=>'#school_id', )),'style'=>'width:180px;' ) )?> <?php echo $form->error($model,'student_name'); ?> </div> After all that when I saw in firebug I got the error.Here is the screen shot

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  • Document Similarity: Comparing two documents efficiently

    - by seanieb
    I have a loop that calculates the similarity between two documents. It collects all the tokens in a document and their scores, and places them in dictionary. It then compares the dictionaries This is what I have so far, it works, but is super slow: # Doc A cursor1.execute("SELECT token, tfidf_norm FROM index WHERE doc_id = %s", (docid[i][0])) doca = cursor1.fetchall() #convert tuple to a dictionary doca_dic = dict((row[0], row[1]) for row in doca) #Doc B cursor2.execute("SELECT token, tfidf_norm FROM index WHERE doc_id = %s", (docid[j][0])) docb = cursor2.fetchall() #convert tuple to a dictionary docb_dic = dict((row[0], row[1]) for row in docb) # loop through each token in doca and see if one matches in docb for x in doca_dic: if docb_dic.has_key(x): #calculate the similarity by summing the products of the tf-idf_norm similarity += doca_dic[x] * docb_dic[x] print "similarity" print similarity I'm pretty new to Python, hence this mess. I need to speed it up, any help would be appreciated. Thanks.

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  • Syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in PHP

    - by pmms
    mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $result=mysql_query("select * from jos_users INTO OUTFILE 'users.csv' FIELDS ESCAPED BY '""' TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY '\n' "); header("Content-type: text/plain"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Content-Transfer-Encoding: binary"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; in the above code in query string i.e string in side mysql_quey we are getting following error Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in C:\wamp\www\samples\mysql_excel\exel_outfile.php on line 8 in query string '\n' charter is not identifying as string thats why above error getting

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  • IF expression in SQL

    - by chupinette
    INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, I.name,I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV<br/> WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id; I have a table called temp_quotations(temp_item_id,item_name)having values (1,grinder), (2,drill), (3,kit) I have another table called item(item_id,name,other_name,discounted_price) having values (1,grinder A,100),(2,kit A,200) When I execute this sql, it insert values in table item_quotation(item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) for example in this case it will insert (1,1,grinder,grinder A,150,100) (2,1,kit,kit A, 250,200) Since the item drill is not found in table item, it wont display it in table item_quotations. I want to write an if statement within that sql so that when the item_name from temp_quotation does not match the name from item, it displays not found in the place of item_name. This is what i tried but it does not display "not found": INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, IF(I.name LIKE CONCAT( '%', T.item_name, '%' ),I.name,'not found'),I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id;

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  • Merging sql queries to get different results by date

    - by pedalpete
    I am trying to build a 'recent events' feed and can't seem to get either my query correct, or figure out how to possible merge the results from two queries to sort them by date. One table holds games/, and another table holds the actions of these games/. I am trying to get the recent events to show users 1) the actions taken on games that are publicly visible (published) 2) when a new game is created and published. So, my actions table has actionId, gameid, userid, actiontype, lastupdate My games table has gameid, startDate, createdby, published, lastupdate I currently have a query like this (simplified for easy understanding I hope). SELECT actionId, actions.gameid, userid, actiontype, actions.lastupdate FROM actions JOIN ( SELECT games.gameid, startDate, createdby, published, games.lastupdate FROM games WHERE published=1 AND lastupdate>today-2 ) publishedGames on actions.gameid=games.gameid WHERE actions.type IN (0,4,5,6,7) AND actions.lastupdate>games.lastupdate and published=1 OR games.lastupdate>today-2 AND published=1 This query is looking for actions from published games where the action took place after the game was published. That pretty much takes care of the first thing that needs to be shown. However, I also need to get the results of the SELECT games.gameid, startDate, createdby, published, games.lastupdate FROM games WHERE published=1 AND startDate>today-2 so I can include in the actions list, when a new game has been published. When I run the query as I've got it written, I get all the actionids, and their gameids, but I don't get a row which shows the gameid when it was published. I understand that it may be possible that I need to run two seperate queries, and then somehow merge the results afterword with php, but I'm completely lost on where to start with that as well.

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  • Why does this query only select a single row?

    - by Joe
    SELECT * FROM tbl_houses WHERE (SELECT HousesList FROM tbl_lists WHERE tbl_lists.ID = '123') LIKE CONCAT('% ', tbl_houses.ID, '#') It only selects the row from tbl_houses of the last occuring tbl_houses.ID inside tbl_lists.HousesList I need it to select all the rows where any ID from tbl_houses exists within tbl_lists.HousesList

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  • How can I replace/speed up a text search query which uses LIKE ?

    - by Jules
    I'm trying to speed up my query... select PadID from Pads WHERE (keywords like '%$search%' or ProgramName like '%$search%' or English45 like '%$search%') AND RemovemeDate = '2001-01-01 00:00:00' ORDER BY VersionAddDate DESC I've done some work already, I have a keywords table so I can add ... PadID IN (SELECT PadID FROM Keywords WHERE word = '$search') ... However its going to be a nightmare to split up the words from English45 and ProgramName into a word table. Any ideas ? EDIT : (also provided actual table names)

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  • Rails Unit Testing with MyISAM Tables

    - by tadman
    I've got an application that requires the use of MyISAM on a few tables, but the rest are the traditional InnoDB type. The application itself is not concerned with transactions where it applies to these records, but performance is a concern. The Rails testing environment assumes the engine used is transactional, though, so when the test database is generated from the schema.rb it is imported with the same engine. Is it possible to over-ride this behaviour in a simple manner? I've resorted to an awful hack to ensure the tables are the correct type by appending this to test_helper.rb: (ActiveRecord::Base.connection.select_values("SHOW TABLES") - %w[ schema_info ]).each do |table_name| ActiveRecord::Base.connection.execute("ALTER TABLE `#{table_name}` ENGINE=InnoDB") end Is there a better way to make a MyISAM-backed model be testable?

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  • Programming advice - Which Loops?

    - by GaxZE
    Theres no easy way to say this so ill just say it in the form of a story. Im looking for advice on which loops and where. Here goes: out of 200-odd fields in the database, i need to run the following against each field. extract allowed values using extract function place allowed values into an array loop the array to be inserted into a db table first check records dont already exist. if they dont exist insert into table. ive found myself playing with this for the past two days and getting tangled and tangled in loops. wondering if anybody can guide.

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  • Echo autoincrement id doubt

    - by Marcelo
    Hi, can I print the id, even if it's autoincrement ? Because the way I'm doing I'm using an empty variable for id. $id= ""; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die ("Não conectou com a base $database"); mysql_query("INSERT INTO table1(id,...) VALUES ('".$id."',....)") or die(mysql_error()); mysql_close(); echo "Your id is :"; echo "".$id; I'm trying to print the id, but it's coming blank. I checked the table and there's an id number there. How can I print it then at? Thanks for the attention

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  • Symfony sfDoctrinePager with multiple tables

    - by Zoja
    I was wondering how to get this to run. In my application I have a Category table and Product table. I need to have a pager which combines both Categories and Products for display in one list (first categories then products). Is there a way to get this going ? I tried left joining in the pager's query, but doesn't seem to do the trick.

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  • Aggregate Functions on subsets of data based on current row values with SQL

    - by aasukisuki
    Hopefully that title makes sense... Let's say I have an employee table: ID | Name | Title | Salary ---------------------------- 1 | Bob | Manager | 15285 2 | Joe | Worker | 10250 3 | Al | Worker | 11050 4 | Paul | Manager | 16025 5 | John | Worker | 10450 What I'd like to do is write a query that will give me the above table, along with an averaged salary column, based on the employee title: ID | Name | Title | Salary | Pos Avg -------------------------------------- 1 | Bob | Manager | 15285 | 15655 2 | Joe | Worker | 10250 | 10583 3 | Al | Worker | 11050 | 10583 4 | Paul | Manager | 16025 | 15655 5 | John | Worker | 10450 | 10583 I've tried doing this with a sub-query along the lines of: Select *, (select Avg(e2.salary) from employee e2 where e2.title = e.title) from employee e But I've come to realize that the sub-query is executed first, and has no knowledge of the table alias'd e I'm sure I'm missing something REALLY obvious here, can anyone point me in the right diretion?

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  • Hibernate constraint ConstraintViolationException. Is there an easy way to ignore duplicate entries?

    - by vincent
    Basically I've got the below schema and I'm inserting records if they don't exists. However when it comes to inserting a duplicate it throws and error as I would expect. My question is whether there is an easy way to make Hibernate to just ignore inserts which would in effect insert duplicates? CREATE TABLE IF NOT EXISTS `method` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `name` varchar(10) DEFAULT NULL, PRIMARY KEY (`id`), UNIQUE KEY `name` (`name`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; SEVERE: Duplicate entry 'GET' for key 'name' Exception in thread "pool-11-thread-4" org.hibernate.exception.ConstraintViolationException: could not insert:

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  • Make A HTML/PHP Link

    - by Will Evans
    I have the code below: $result = mysql_query("SELECT link, notes FROM links WHERE username='will';"); $html .= "<ul>"; while ($row = mysql_fetch_array($result)) { //loop extract($row); $html .= "<li>{$link} - {$notes}</li>"; } I need the bit where it says {$link} to become a clickable link which opens a new window. How would I do this? When I put tags around it you get this error: The error is: Parse error: syntax error, unexpected '{' in /data/www/vhosts/themacsplash.com/httpdocs/ClipBoy/will.php on line 18 Line 18 is $html .= "{$link} - {$notes}";

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  • How to access stdClass variables stdClass Object([max(id)])=>64)

    - by Theopile
    I need the very last valid entry in a database table which would be the row with the greatest primary key. So using mysqli, my query is "SELECT MAX(id) FROM table LIMIT 1". This query returns the correct number(using print_r()) but I cannot figure out how to access it. Here is the main code. Note that the $this-link refers to class with a mysqli connection. $q="select max(id) from stones limit 1"; $qed=$this->link->query($q) or die(mysqli_error()); if($qed){ $row=$qed->fetch_object(); print_r($row); echo $lastid=$row;//here is the problem } The valid line print_r($row) echos out "stdClass Object ( [max(id)] = 68 )"

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  • Using a table-alias in Kohana queries?

    - by Aristotle
    I'm trying to run a simple query with $this->db in Kohana, but am running into some syntax issues when I try to use an alias for a table within my query: $result = $this->db ->select("ci.chapter_id, ci.book_id, ci.chapter_heading, ci.chapter_number") ->from("chapter_info ci") ->where(array("ci.chapter_number" => $chapter, "ci.book_id" => $book)) ->get(); It seems to me that this should work just fine. I'm stating that "chapter_info" ought to be known as "ci," yet this isn't taking for some reason. The error is pretty straight-forward: There was an SQL error: Table 'gb_data.chapter_info ci' doesn't exist - SELECT `ci`.`chapter_id`, `ci`.`book_id`, `ci`.`chapter_heading`, `ci`.`chapter_number` FROM (`chapter_info ci`) WHERE `ci`.`chapter_number` = 1 AND `ci`.`book_id` = 1 If I use the full table name, rather than an alias, I get the expected results without error. This requires me to write much more verbose queries, which isn't ideal. Is there some way to use shorter names for tables within Kohana's query-builder?

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  • How to setup testing LAMP environment to work with outsourcing companies?

    - by Kelvin
    Hello Guys, I need to setup testing LAMP environment in my office to work with outsourcing companies. This is what I think should be done on my side: Setup testing web server with the same configuration as on production Setup testing SQL server with "fake data"? Outsourcers should have access only to some part of original code Outsourcers should use CVS to update their code Once testing is finished someone releases the update ............ How would you separate original code and database from testing environment, but keep it as close as possible to production? What is the general practice for setting up testing environment and how other companies deal with outsourcers? I will appreciate for any of your thoughts and ideas from your personal experience. Maybe someone can suggest some article on this topic. Thank you a lot!

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  • Update multiple rows with one query?

    - by kavoir.com
    I found something that works with updating one field at here: http://www.karlrixon.co.uk/articles/sql/update-multiple-rows-with-different-values-and-a-single-sql-query/ UPDATE person SET name = CASE id WHEN 1 THEN 'Jim' WHEN 2 THEN 'Mike' WHEN 3 THEN 'Precious' END WHERE id IN (1,2,3) My question is how to update more than one field? Such as: UPDATE person SET name = CASE, sex = CASE id WHEN 1 THEN 'Jim', 'female' WHEN 2 THEN 'Mike' 'male' WHEN 3 THEN 'Precious', 'male' END WHERE id IN (1,2,3) Which doesn't work of course. Tried a few other combination and failed. Any idea? Thanks!

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  • SQL Query Returning Duplicate Results

    - by Jesse Bunch
    Hi, I've been working out this query now for a while and I thought I had it where I wanted it, but apparently not. There are two records in the database (orders). The query should return two different rows, but instead returns two rows that have exactly the same values. I think it may be something to do with the GROUP BY or derived tables I'm using but my eyes are tired and not seeing the problem. Can any of you help? Thanks in advance. SELECT orders.billerID, orders.invoiceDate, orders.txnID, orders.bName, orders.bStreet1, orders.bStreet2, orders.bCity, orders.bState, orders.bZip, orders.bCountry, orders.sName, orders.sStreet1, orders.sStreet2, orders.sCity, orders.sState, orders.sZip, orders.sCountry, orders.paymentType, orders.invoiceNotes, orders.pFee, orders.shipping, orders.tax, orders.reasonCode, orders.txnType, orders.customerID, customers.firstName AS firstName, customers.lastName AS lastName, customers.businessName AS businessName, orderStatus.statusName AS orderStatus, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax AS orderTotal, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax - IFNULL(payments.totalPayments, 0.00) AS orderBalance FROM orders LEFT JOIN customers ON orders.customerID = customers.id LEFT JOIN orderStatus ON orders.orderStatus = orderStatus.id LEFT JOIN ( SELECT orderItems.orderID, SUM(orderItems.itemPrice * orderItems.itemQuantity) as itemTotal FROM orderItems GROUP BY orderItems.orderID ) orderItems ON orderItems.orderID = orders.id LEFT JOIN ( SELECT payments.orderID, SUM(payments.amount) as totalPayments FROM payments GROUP BY payments.orderID ) payments ON payments.orderID = orders.id

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  • SQL select statement

    - by kwokwai
    Hi all, I got a Table which has two fields: Point, and Level, with some sample data as follows: ----------------------- Point | Level ----------------------- 10 | Level 1 20 | Level 2 30 | Level 3 40 | Level 4 Suppose that there is a user who has 25 points, to find the Level in which this user is in, the Select statement I used was: Select Level from Table where Point < 30 AND Point > 20; But the Select SQL ststament is a hard-copy one where you can see the ponts 30 and 20 are fixed. I want to alter the Select statement so that the new SQL Select statement can be applied to all users with different points, but I don't know how to do it.

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  • Take Current Snapshot of DB and send it to FTP in same PHP Scripts: Advice Needed

    - by Rachel
    Not sure if I can do it this way. I want to get current snapshot of the database and send it via FTP Server, both of this functionality should be implemented in PHP scripts. Here are the steps I am thinking on right now. In my php scripts(basically am extending an PDO into my Dao class and then preparing the query), $qry = SELECT * FROM MyTablename; $stmt = $this->prepare($qry); $stmt = $this->execute(); Now I will store $stmt in csv file using fputcsv or I will execute the sql command from the script itself and than try to store the result in the $file(csv file) note here that I do not have any csv file with me at this point to basically I will have to create one and let's say its $file, so then $file = fputcsv($stmt); or $file = exec("Select * from MyTablename"); Will this put all records in the file ? If yes, then I will use FTP Functionality to transfer file to the FTP Folder. I am not sure if this approach would work and also have concerns regarding the need of preparing the $qry Any suggestions or different approach advised would be highly appreciated. Thanks !!!

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