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  • What is wrong with this trigger in mysql?

    - by Jimit
    Hi all, Below is trigger that I need to create but It is not getting created.Please any buddy can explain me what is wrong with this trigger ? Help me please. DELIMITER $$ CREATE TRIGGER property_history_update AFTER UPDATE ON `properties` FOR EACH ROW BEGIN IF OLD.ListPrice != NEW.ListPrice THEN INSERT INTO `property_history` SET ListingKey=OLD.ListingKey,ListPrice = NEW.ListPrice, ListingStatus = OLD.ListingStatus,LastUpdatedTime = NEW.LocalLastModifiedOn; END IF; END$$ DELIMITER ;

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  • Why does this MySQL Query hang?

    - by zzapper
    SELECT * FROM tbl_order_head AS o INNER JOIN tbl_orders_log AS c ON o.PAYMENT_TRANSACTION_LOG_ID=c.TRANSACTION_ID WHERE o.VISUAL_ID = '77783'; tbl_order_head 67,000 (30 fields) records, tbl_orders_log 17000 (5 fields) records. I don't know if it would eventually return as I am running it on a live server and fear overloading. I am doing similar queries and much more complex queries successfully.

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  • MySQL parameter resource error

    - by Derek
    Here is my error: Warning: mysql_query() expects parameter 2 to be resource, null given... This refers to line 23 of my code which is: $result = mysql_query($sql, $connection) My entire query code looks like this: $query = "SELECT * from users WHERE userid='".intval( $_SESSION['SESS_USERID'] )."'"; $result = mysql_query($query, $connection) or die ("Couldn't perform query $query <br />".mysql_error()); $row = mysql_fetch_array($result); I don't have a clue what has happpened here. All I wanted to do was to have the value of the users 'fullname' displayed in the header section of my web page. So I am outputting this code immediately after to try and achieve this: echo 'Hello '; echo $row['fullname']; Before this change, I had it working perfectly, where the session variable of fullname was echoed $_SESSION['SESS_NAME']. However, because my user can update their information (including their name), I wanted the name displayed in the header to be updated accordingly, and not displaying the session value.

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  • define mysql indexing

    - by Bharanikumar
    Hi Am not sure, This is the right place to post this question , But in our stack overflow only am getting clear vision solutions , What is indexing and what is fulltext , for the above both questions i know the ans, but i cant expose that ans in the exact way to the interviewer , (indexing means somthing like index in book) (fulltext means for search string), Can please give me very simple defination for this questions , Advance thanks

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  • Testing + production server and syncing MySQL data

    - by Matthew
    I have a web application running on LAMP with a testing server and a production server. Is there a standard practice for keeping the data on the testing server in sync with the production server? The data on the testing server gets out of date pretty quick and I feel like there must be an easier way than just dumping the production server and copying it onto the testing server every so often. It's not important that the data is in total sync, just that the testing server represents the production enviornment as accurately as possible.

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  • MYSQL JOIN SELECT Statment - omit duplicated

    - by mouthpiec
    Hi, I am tying to join the following 2 queries but I am having duplicated .... it is possible to remove duplacted fro this: ( SELECT bar_id, bar_name, town_name, bar_telephone, (subscription_type_id *2) AS subscription_type_id FROM bar, sportactivitybar, towns, subscriptiontype WHERE sport_activity_id_fk =14 AND bar_id = bar_id_fk AND town_id = town_id_fk AND subscription_type_id = subscription_type_id_fk ) UNION ( SELECT bar_id, bar_name, town_name, bar_telephone, subscription_type_id FROM bar, towns, subscriptiontype WHERE town_id = town_id_fk AND subscription_type_id = subscription_type_id_fk ) ORDER BY subscription_type_id DESC , RAND( ) Please note that I need to omit those duplicates that will have a lower subscription_type_id

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  • PHP MYSQL Add up number of entries in single table and display in HTML

    - by Derek
    I have a table called activities which contains a number of activities for projects (for example 6 activities are related to one project). On a manage projects page, you can see the projects, and I have one column which needs to display the number of tasks associated with the project (in that particular row). So basically, I need a query or PHP calculation that can add up the number of tasks for the project and then display this number dynamically! I know exactly what I need, just do not know how to implement it. Any help is much appreciated! Thanks.

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  • batch update mysql table

    - by Yang
    I have a table with a column called time, "HH:MM:SS". How can I do a batch update so that the value increment by 1 hour? Is it something like: update <table_name> set <time_column> = <time_column> + 3600 where ...

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  • Mysql - multiple values and between

    - by realshadow
    Hey, I need to select 10 products and display them. Each product has 3 different prices. The select to get the prices looks like this: SELECT * FROM products_loans WHERE CODE IN('10X15/12', '10X15/Q10-10', '10X15/Q20-10') AND 550 BETWEEN PRICE_FROM AND PRICE_TO; Where 550 is the base price. Now this select returns 3 rows, but I want to modify it so it will return 30 results. I dont like the idea to execute 10 queries at once. I know I can easily achieve that with "OR", but I would like to ask if there is some other more elegant way to this. The select "should" look like this: SELECT * FROM products_loans WHERE KOD IN('10X15/12', '10X15/Q10-10', '10X15/Q20-10') AND (550, 325, 780) BETWEEN CENA_OD AND CENA_DO; Note that there is no "price" column or anything in the table which I could use to do a JOIN and I cant modify the table.

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  • mysql problem left join and from_unixtime

    - by moustafa
    i have this SELECT COUNT(1) cnt, a.auther_id FROM `posts` a LEFT JOIN users u ON a.auther_id = u.id GROUP BY a.auther_id ORDER BY cnt DESC LIMIT 20 its work fine bu now i want select from posts which added from 1 day tried to use WHERE from_unixtime(post_time) >= SUBDATE(NOW(),1) but its didnot worked any one have idea

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  • Generating Unordered List with PHP + CodeIgniter from a MySQL Database

    - by Tim
    Hello Everyone, I am trying to build a dynamically generated unordered list in the following format using PHP. I am using CodeIgniter but it can just be normal php. This is the end output I need to achieve. <ul id="categories" class="menu"> <li rel="1"> Arts &amp; Humanities <ul> <li rel="2"> Photography <ul> <li rel="3"> 3D </li> <li rel="4"> Digital </li> </ul> </li> <li rel="5"> History </li> <li rel="6"> Literature </li> </ul> </li> <li rel="7"> Business &amp; Economy </li> <li rel="8"> Computers &amp; Internet </li> <li rel="9"> Education </li> <li rel="11"> Entertainment <ul> <li rel="12"> Movies </li> <li rel="13"> TV Shows </li> <li rel="14"> Music </li> <li rel="15"> Humor </li> </ul> </li> <li rel="10"> Health </li> And here is my SQL that I have to work with. -- -- Table structure for table `categories` -- CREATE TABLE IF NOT EXISTS `categories` ( `id` mediumint(8) NOT NULL auto_increment, `dd_id` mediumint(8) NOT NULL, `parent_id` mediumint(8) NOT NULL, `cat_name` varchar(256) NOT NULL, `cat_order` smallint(4) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; So I know that I am going to need at least 1 foreach loop to generate the first level of categories. What I don't know is how to iterate inside each loop and check for parents and do that in a dynamic way so that there could be an endless tree of children. Thanks for any help you can offer. Tim

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  • MySQL sub query

    - by Juddling
    UPDATE members SET money=money+100 WHERE username IN (SELECT username FROM forum); Lets say I wanted to give each of my members 100 money for each post in my forum. This query works but if one member has posted more than once, they only get 100. Could someone correct this query please?

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  • A typical mysql query( how to use subquery column into main query)

    - by I Like PHP
    I HAVE TWO TABLES shown below table_joining id join_id(PK) transfer_id(FK) unit_id transfer_date joining_date 1 j_1 t_1 u_1 2010-06-05 2010-03-05 2 j_2 t_2 u_3 2010-05-10 2010-03-10 3 j_3 t_3 u_6 2010-04-10 2010-01-01 4 j_5 NULL u_3 NULL 2010-06-05 5 j_6 NULL u_4 NULL 2010-05-05 table_transfer id transfer_id(PK) pastUnitId futureUnitId effective_transfer_date 1 t_1 u_3 u_1 2010-06-05 2 t_2 u_6 u_1 2010-05-10 3 t_3 u_5 u_3 2010-04-10 now i want to know total employee detalis( using join_id) which are currently working on unit u_3 . means i want only join_id j_1 (has transfered but effective_transfer_date is future date, right now in u_3) j_2 ( tansfered and right now in `u_3` bcoz effective_transfer_date has been passed) j_6 ( right now in `u_3` and never transfered) what i need to take care of below steps( as far as i know ) <1> first need to check from table_joining whether transfer_id is NULL or not <2> if transfer_id= is NULL then see unit_id=u_3 where joining_date <=CURDATE() ( means that person already joined u_3) <3> if transfer_id is NOT NULL then go to table_transfer using transfer_id (foreign key reference) <4> now see the effective_transfer_date regrading that transfer_id whether effective_transfer_date<=CURDATE() <5> if transfer date has been passed(means transfer has been done) then return futureUnitID otherwise return pastUnitID i used two separate query but don't know how to join those query?? for step <1 ans <2 SELECT unit_id FROM table_joining WHERE joining_date<=CURDATE() AND transfer_id IS NULL AND unit_id='u_3' for step<5 SELECT IF(effective_transfer_date <= CURDATE(),futureUnitId,pastUnitId) AS currentUnitID FROM table_transfer // here how do we select only those rows which have currentUnitID='u_3' ?? please guide me the process?? i m just confused with JOINS. i think using LEFT JOIN can return the data i need, or if we use subquery value to main query? but i m not getting how to implement ...please help me. Thanks for helping me alwayz

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  • MySQL Database Design with Internationalization

    - by Some name
    Hello, I'm going to start work on a medium sized application, and i'm planning it's db design. One thing that I'm not sure about is this. I will have many tables which will need internationalization, such as: "membership_options, gender_options, language_options etc" Each of these tables will share common i18n fields, like: "title, alternative_title, short_description, description" In your opinion which is the best way to do it? Have an i18n table with the same fields for each of the tables that will need them? or do something like: Membership table Gender table ---------------- -------------- id | created_at id | created_at 1 - 22.03.2001 1 - 14.08.2002 2 - 22.03.2001 2 - 14.08.2002 General translation table ------------------------- record_id | table_name | string_name | alternative_title| .... |id_language 1 - membership regular null 1 (english) 1 - membership normale null 2 (italian) 1 - gender man null 1(english) 1 -gender uomo null 2(italian) This would avoid me repeating something like: membership_translation table ----------------------------- membership_id | name | alternative_title | id_lang 1 regular null 1 1 normale null 2 gender_translation table ----------------------------- gender_id | name | alternative_title | id_lang 1 man null 1 1 uomo null 2 and so on, so i would probably reduce the number of db tables, but i'm not sure about performance.I'm not much of a DB designer, so please let me know.

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  • Java/MySQL: Working with data in classes

    - by skiwi
    What is the best way to deal with accessing/modifying tables in a database? I have read about the Data Access Object approach, but none of the resources I have found so far indicate a clear implementation of it. So assume you have a database with a table called accounts that has columns id, name, password and email. How would you properly access it within Java? I mean most people know how to do SQL statements, but that is not really the point. I hope people here can be of help. Regards.

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  • MySQL float values jumping around on insert?

    - by dubayou
    So i have a SQL table setup as such CREATE TABLE IF NOT EXISTS `points` ( `id` int(11) NOT NULL auto_increment, `lat` float(10,6) NOT NULL, `lng` float(10,6) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM; And im inserting stuff like INSERT INTO `points` (`lat`, `lng`) VALUES ('89.123456','-12.123456'); Gives me a row with lat and lng being 89.123459 and -12.123455 Whats up?

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  • Re-order mysql rows using PHP

    - by dave e
    | id | url | title | menu_id | ------+--------+--------+---------- | 1 | http://| link 1 | 1 | | 2 | http://| link 2 | 2 | | 3 | http://| link 3 | 3 | | 4 | http://| link 4 | 4 | Hi, I was wondering if its possible using PHP to reorder the above to something like below. I am trying to generate a menu which can easily be reordered by clicking an up or down arrow. I have no idea where to start. Any help would be much appreciated. | id | url | title | menu_id | ------+--------+--------+---------- | 1 | http://| link 1 | 2 | | 2 | http://| link 2 | 4 | | 3 | http://| link 3 | 3 | | 4 | http://| link 4 | 1 |

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  • connecting to phpMyAdmin database with PHP/MySQL

    - by user303955
    I've made a database using phpMyAdmin , now I want to make a register form for my site where peaple can register .I know how to work with input tags in HTML and I know how to insert data into a database but my problem is that I don't know how I can connect to the database that is already made in phpMyAdmin.

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  • Mysql partition error?

    - by drake
    I have a kinda table like this: CREATE TABLE test ( id MEDIUMINT NOT NULL AUTO_INCREMENT, user VARCHAR(30), time VARCHAR(30), status VARCHAR(30), origin VARCHAR(30), PRIMARY KEY (id) ) ENGINE=MyISAM; PARTITION BY RANGE(id) ( PARTITION p0 VALUES LESS THAN (500000), PARTITION p1 VALUES LESS THAN (1000000), PARTITION p2 VALUES LESS THAN (1500000), PARTITION p3 VALUES LESS THAN (2000000), PARTITION p4 VALUES LESS THAN (2500000) ) I have Three questions: 1) I have here an #1064 error; 2) How can i set split test.user as alphabetic range in partition; 3) How can i check that the partition was successful;

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  • Datetime NOW PHP mysql (+ PDO variant)

    - by Chris
    Thanks for looking. All helpful answers/comments are up voted. In php, you can use NOW() like this: mysql_query("INSERT INTO tablename (id, value, time_created) VALUES ('{$id}', '{$value}', NOW())"); How can I do the same thing in PDO. When I bind like this, I get an error: $stmt->bindParam(':time_added', NOW(), PDO::PARAM_STR); Is it the PDO:PARAM_STR?

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  • How to build unlimited level of menu through PHP and mysql

    - by Starx
    Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu now there is not problem while creating submenu inside another submenu now this is way I fetch the submenu for the top menu <ul class="topmenu"> <? $list = $obj -> childmenu($parentid); //this list contains the array of submenu under $parendid foreach($list as $menu) { extract($menu); echo '<li><a href="#">'.$name.'</a></li>'; } ?> </ul> What I want to do is. I want to check if a new menu has other child menu and I want to keep on checking until it searches every child menu that is available and I want to display its child menu inside its particular list item like this Home ........

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  • problem in mysql query with join and limit the time

    - by moustafa
    i have this SELECT COUNT(1) cnt, a.auther_id FROM `posts` a LEFT JOIN users u ON a.auther_id = u.id GROUP BY a.auther_id ORDER BY cnt DESC LIMIT 20 its work fine bu now i want select from posts which added from 1 day tried to use WHERE from_unixtime(post_time) >= SUBDATE(NOW(),1) but its didnot worked any one have idea

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  • mysql query and index

    - by parm.95
    Does this query will be faster with a index on "t.type1" and "x.type1" or only index on "x.type1" is enought? SELECT t.id, x.id FROM t INNER JOIN x ON x.type1=t.type1 WHERE t.id=1

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  • searching for multiple columns mysql and php

    - by addi
    i'm trying to search for multiple columns using this code: <?php // Connection Database $search = $_POST ['Search']; mysql_connect("xxxxxx", "xxxxxx", "xxxxx") or die ("Error Connecting to Database"); mysql_select_db("xxxxx") or die('Error'); $data = mysql_query("SELECT CourseName, CourseDescription, CourseLeader FROM course MATCH (CourseName, CourseDescription, CourseLeader) AGAINST ('". $search ."') or die('Error'); Print "<table border cellpadding=3>"; while($info = mysql_fetch_array( $data )) { Print "<tr>"; Print "<th>Course Name:</th> <td>".$info['CourseName'] . "</td> "; Print "<th>Course Description:</th><td>".$info['CourseDescription'] . "</td> "; Print "<th>Course Leader:</th><td>".$info['CourseLeader'] . " </td></tr>"; } Print "</table>"; ?> i'm getting the following error: Parse error: syntax error, unexpected T_STRING in /home/a7105766/public_html/website/scripts/coursesearchdb.php on line 30 what am I doing wrong?? cheers

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