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  • Why am I getting 'Heap Corruption'?

    - by fneep
    Please don't crucify me for this one. I decided it might be good to use a char* because the string I intended to build was of a known size. I am also aware that if timeinfo-tm_hour returns something other than 2 digits, things are going to go badly wrong. That said, when this function returns VIsual Studio goes ape at me about HEAP CORRUPTION. What's going wrong? (Also, should I just use a stringbuilder?) void cLogger::_writelogmessage(std::string Message) { time_t rawtime; struct tm* timeinfo = 0; time(&rawtime); timeinfo = localtime(&rawtime); char* MessageBuffer = new char[Message.length()+11]; char* msgptr = MessageBuffer; _itoa(timeinfo->tm_hour, msgptr, 10); msgptr+=2; strcpy(msgptr, "::"); msgptr+=2; _itoa(timeinfo->tm_min, msgptr, 10); msgptr+=2; strcpy(msgptr, "::"); msgptr+=2; _itoa(timeinfo->tm_sec, msgptr, 10); msgptr+=2; strcpy(msgptr, " "); msgptr+=1; strcpy(msgptr, Message.c_str()); _file << MessageBuffer; delete[] MessageBuffer; }

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  • Google Radar Chart: Not plotting data

    - by Hallik
    Hi. I have different types of data that I have normalized just with base10, so everything is on a 10 point scale. There are two data points, and the legend for them show up fine. All the points around the radar show up fine and so do the labels for them, but I don't see any filled in data. Outside of the labels and axis, the chart is blank. Below is the actual image tag I render, then I split up the variables on each line for easy readability. Anyone mind telling me why it isn't working? <img src="http://chart.apis.google.com/chart?cht=rs&amp;chm=B,3366CC60,0,1.0,5.0|B,CC4D3360,1,1.0,5.0&chs=600x500&chd=t:4.6756775443385,4.7031365524912,1.8646655408171,1.8358167047079,4.2483837215455,4.1367786166752,|5.0319252700625,5.0370797208146,1.8415340693163,1.8591105937857,4.3392150450337,4.1434876641017&chco=3366CC,CC4D33&chls=2.0,4.0,0.0|2.0,4.0,0.0&chxt=x&chxl=0:|Label1|Label2|label3|Label4|Label5|Label6&chxr=0,0.0,10.0&chdl=Data Object 1|Data Object 2&"/> cht=rs& chm=B,3366CC60,0,1.0,5.0|B,CC4D3360,1,1.0,5.0& chs=600x500& chd=t:4.6756775443385,4.7031365524912,1.8646655408171,1.8358167047079,4.2483837215455,4.1367786166752,|5.0319252700625,5.0370797208146,1.8415340693163,1.8591105937857,4.3392150450337,4.1434876641017& chco=3366CC,CC4D33& chls=2.0,4.0,0.0|2.0,4.0,0.0& chxt=x& chxl=0:|Label1|Label2|label3|Label4|Label5|Label6& chxr=0,0.0,10.0& chdl=Data Object 1|Data Object 2& This is the radar chart page, I can't tell what I am doing wrong. http://code.google.com/apis/chart/docs/gallery/radar_charts.html

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  • How can I handle these different HTML chunks in Perl?

    - by kkchaitu
    I need to write a single regular expression with the three possible cases. case1 <td width="100%" align="left" bgcolor="#001E5A"><font face="Arial" size="2" color="#FFFFFF"><font size="1"><b>[Punjabi Music]</font></b> <a id="listlinks" target="_scurl" href="http://www.apnaradio.com/">Apna Radio Broadcast Live 24x7: Indian - Pakistani - Punjabi - Bhangra and Hindi Music !!</a> </font></td> <td nowrap align="center" width="10" bgcolor="#001E5A">&nbsp;</td> case2 <td width="100%" align="left" bgcolor="#001E32"><font face="Arial" size="2" color="#FFFFFF"><font size="1"><b>[jazz]</font></b> <a id="listlinks" target="_scurl" href="http://www.dinnerjazzexcursion.com">Dinner Jazz Excursion</a> <br> <font size="1"><a id="chatstuff" href="aim:goim?screenname=NA">[ AIM ]</a>&nbsp;<font color="#FF0000">Now Playing:</font> Ken Peplowski - Indian Summer</font></font></td> <td nowrap align="center" width="10" bgcolor="#001E32">&nbsp;</td> case 3 <td width="100%" align="left" bgcolor="#001E5A"><font face="Arial" size="2" color="#FFFFFF"><font size="1"><b>[World Bollywood Hindi]</font></b> <a id="listlinks" target="_scurl" href="http://www.bollywoodmusicradio.com/">Bollywood Music Radio :: Indian Music :: Request your Hindi Songs</a> <br> <font size="1"><font color="#FF0000">Now Playing:</font> Bollywood Music Radio - Fear (2007) - Tu Hai Ishq @ 13:46</font></font></td> <td nowrap align="center" width="10" bgcolor="#001E5A">&nbsp;</td>

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  • AG_E_PARSER_PROPERTY_NOT_FOUND exception.

    - by Subhen
    Hi , Can any one plese explain why this error is happenin? I have created a usercontrol in another class and public partial class userControlImageFolder : RadioButton { public userControlImageFolder() { InitializeComponent(); } } Now in XAML it is a lot of code created by the designer like below: <UserControl x:Class="userControlFolder.userControlLocalFolder" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:System="clr-namespace:System;assembly=mscorlib" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" mc:Ignorable="d" Height="120" Width="150"> <UserControl.Resources> <Style x:Key="rdbfolder" TargetType="RadioButton"> <Setter Property="Background" Value="#FF448DCA"/> <Setter Property="Foreground" Value="#FF000000"/> <Setter Property="HorizontalContentAlignment" Value="Left"/> <Setter Property="VerticalContentAlignment" Value="Top"/> <Setter Property="Padding" Value="4,1,0,0"/> <Setter Property="BorderThickness" Value="1"/> <Setter Property="BorderBrush"> <Setter.Value> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FFA3AEB9" Offset="0"/> <GradientStop Color="#FF8399A9" Offset="0.375"/> <GradientStop Color="#FF718597" Offset="0.375"/> <GradientStop Color="#FF617584" Offset="1"/> </LinearGradientBrush> </Setter.Value> </Setter> <Setter Property="Template"> <Setter.Value> <ControlTemplate TargetType="RadioButton"> <Grid> <VisualStateManager.VisualStateGroups> <VisualStateGroup x:Name="CommonStates"> <VisualState x:Name="Normal"/> <VisualState x:Name="MouseOver"/> <VisualState x:Name="Pressed"/> <VisualState x:Name="Disabled"/> </VisualStateGroup> <VisualStateGroup x:Name="CheckStates"> <VisualState x:Name="Checked"> <Storyboard> <DoubleAnimationUsingKeyFrames BeginTime="00:00:00" Duration="00:00:00.0010000" Storyboard.TargetName="path3" Storyboard.TargetProperty="(UIElement.Opacity)"> <EasingDoubleKeyFrame KeyTime="00:00:00" Value="1"/> </DoubleAnimationUsingKeyFrames> <DoubleAnimationUsingKeyFrames BeginTime="00:00:00" Duration="00:00:00.0010000" Storyboard.TargetName="path4" Storyboard.TargetProperty="(UIElement.Opacity)"> <EasingDoubleKeyFrame KeyTime="00:00:00" Value="0.8"/> </DoubleAnimationUsingKeyFrames> </Storyboard> </VisualState> <VisualState x:Name="Unchecked"/> </VisualStateGroup> <VisualStateGroup x:Name="FocusStates"> <VisualState x:Name="Focused"/> <VisualState x:Name="Unfocused"/> </VisualStateGroup> <VisualStateGroup x:Name="ValidationStates"> <VisualState x:Name="Valid"/> <VisualState x:Name="InvalidUnfocused"/> <VisualState x:Name="InvalidFocused"/> </VisualStateGroup> </VisualStateManager.VisualStateGroups> <Grid.ColumnDefinitions> <ColumnDefinition Width="125"/> </Grid.ColumnDefinitions> <Path x:Name="path1" Stroke="#FFEFCD44" Width="Auto" Data="F1M12,1.087C12,1.087 28.814,1.087 49.294,1.087 53.671,1.087 58.215,13 62.799,13 91.625,13 122,13 122,13 127.523,13 132,17.477 132,23 132,23 132,98 132,98 132,103.523 127.523,108 122,108 122,108 12,108 12,108 6.477,108 2,103.523 2,98 2,98 2,12.337 2,12.337 2,6.815 6.477,1.087 12,1.087z" HorizontalAlignment="Stretch" Margin="0,1.765,-7.564,0" VerticalAlignment="Top" Height="108.5" UseLayoutRounding="False" d:LayoutOverrides="Width"> <Path.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FFE5B802" Offset="0.996"/> <GradientStop Color="#FFFFF3C1" Offset="0.009"/> <GradientStop Color="#FFC1A11F" Offset="0.16"/> </LinearGradientBrush> </Path.Fill> </Path> <Path x:Name="path2" Stretch="Fill" Width="Auto" Data="M47.476928,130.65616 C47.476928,130.65616 167.10104,89.928686 175.76116,103.61726 L175.20267,155.29888 C175.20267,155.29888 46.697497,161.72468 46.697497,161.72468 46.697497,161.72468 47.476928,130.65616 47.476928,130.65616 z" HorizontalAlignment="Stretch" Margin="2.5,38.07,-6.564,0" VerticalAlignment="Top" Height="61.919" UseLayoutRounding="False"> <Path.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FFE5B802" Offset="1"/> <GradientStop Color="#FFECC31C"/> <GradientStop Color="#FFE7C536" Offset="0.591"/> </LinearGradientBrush> </Path.Fill> </Path> <Path x:Name="path1_Copy" Stroke="#FFEFCD44" Width="Auto" Data="F1 M120.50496,0.49999992 C126.02796,0.49999992 130.50496,4.9769999 130.50496,10.5 130.50496,10.5 130.50496,76.333333 130.50496,76.333333 130.50496,81.856333 126.02796,86.333333 120.50496,86.333333 120.50496,86.333333 10.504963,86.333333 10.504963,86.333333 4.9819634,86.333333 0.5049634,81.856333 0.5049634,76.333333 0.5049634,76.333333 0.5049634,12.040168 0.5049634,12.040168 0.33018858,5.8202529 4.7881744,0.99969011 11.184806,0.94185195 39.903021,0.68218267 120.50496,0.49999992&#xa;120.50496,0.49999992 z" HorizontalAlignment="Stretch" Margin="1.497,23.434,-7.502,0" VerticalAlignment="Top" Height="86.833" UseLayoutRounding="False"> <Path.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FFE5B802" Offset="0.996"/> <GradientStop Color="#FFFFFB9D" Offset="0.009"/> <GradientStop Color="#FFF1D256" Offset="0.164"/> <GradientStop Color="#FFE2BC22" Offset="0.505"/> <GradientStop Color="#FFB5780F" Offset="0.948"/> </LinearGradientBrush> </Path.Fill> </Path> <Path x:Name="path3" Stroke="#FFEFCD44" Width="133" Data="F1M12,1.087C12,1.087 28.814,1.087 49.294,1.087 53.671,1.087 58.215,13 62.799,13 91.625,13 122,13 122,13 127.523,13 132,17.477 132,23 132,23 132,98 132,98 132,103.523 127.523,108 122,108 122,108 12,108 12,108 6.477,108 2,103.523 2,98 2,98 2,12.337 2,12.337 2,6.815 6.477,1.087 12,1.087z" HorizontalAlignment="Right" Margin="0,1.719,-8,0" VerticalAlignment="Top" Height="108.5" Opacity="0" UseLayoutRounding="False"> <Path.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FF6A5603" Offset="1"/> <GradientStop Color="#FFF3EFDE"/> <GradientStop Color="#FFDAB20D" Offset="0.349"/> </LinearGradientBrush> </Path.Fill> </Path> <Path x:Name="path4" Width="150" Data="F1 M30,0 C30,0 140,0 140,0 145.523,0 150,4.477 150,10 150,10 130,55 130,55 130,55 124.65027,67.742768 120,65 120,65 10,65 10,65 4.477,65 0,60.523 0,55 0,55 20,10 20,10 22.247647,3.2935648 24.477,0&#xa;30,0 z" HorizontalAlignment="Right" Margin="0,43.379,-31.05,0" VerticalAlignment="Top" Height="65.387" Opacity="0" UseLayoutRounding="False"> <Path.Fill> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="#FFE5B802" Offset="1"/> <GradientStop Color="White"/> <GradientStop Color="#FFFAD336" Offset="0.378"/> </LinearGradientBrush> </Path.Fill> </Path> </Grid> </ControlTemplate> </Setter.Value> </Setter> </Style> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="White"> <RadioButton HorizontalAlignment="Left" Style="{StaticResource rdbfolder}" VerticalAlignment="Top" Content="RadioButton" Height="120" Width="150"/> </Grid> </UserControl> I am sorry for pasting the whole code but this is might be the only way can help us. I create a dll out of it and uses in my other projects: using userControlFolder; userControlLocalFolder btnLocalFolder = new userControlLocalFolder(); Canvas.SetTop(btnLocalFolder, 100); gridRoot.Children.Add(btnLocalFolder); So while running it I get the above exception, AG_E_PARSER_PROPERTY_NOT_FOUND, Please help. Thanks, Subhen

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  • Play multiple audio files using AVAudioPlayer

    - by inScript09
    Hi all, I am planning on releasing 10 of my song recordings for free but bundled in an iphone app. They are not available on web or itunes or anywhere as of now. I am new to iphone sdk (latest) as you can imagine, so I have been going through the developer documentation, various forums and stackoverflow to learn. Apple's avTouch sample application was a great start. But I want my app to play all the 10 tracks one by one. All the songs are added to resources folder and are named as track1, track2...track10. In the avTouch app code I can see the following 2 parts which is where I think I need to make changes to achieve what I am looking for. But I am lost. // Load the array with the sample file NSURL *fileURL = [[NSURL alloc] initFileURLWithPath: [[NSBundle mainBundle] pathForResource:@"sample" ofType:@"m4a"]]; - (void)audioPlayerDidFinishPlaying:(AVAudioPlayer *)player successfully:(BOOL)flag { if (flag == NO) NSLog(@"Playback finished unsuccessfully"); [player setCurrentTime:0.]; [self updateViewForPlayerState]; } can anyone please help me on 1. how to load the array with all the 10 tracks which are added to resources folder 2. and when I hit play, player should start the first track. when the 1st track ends 2nd track should start and so on for the remaining tracks. Thank You

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  • Re-using aggregate level formulas in SQL - any good tactics?

    - by Cade Roux
    Imagine this case, but with a lot more component buckets and a lot more intermediates and outputs. Many of the intermediates are calculated at the detail level, but a few things are calculated at the aggregate level: DECLARE @Profitability AS TABLE ( Cust INT NOT NULL ,Category VARCHAR(10) NOT NULL ,Income DECIMAL(10, 2) NOT NULL ,Expense DECIMAL(10, 2) NOT NULL ) ; INSERT INTO @Profitability VALUES ( 1, 'Software', 100, 50 ) ; INSERT INTO @Profitability VALUES ( 2, 'Software', 100, 20 ) ; INSERT INTO @Profitability VALUES ( 3, 'Software', 100, 60 ) ; INSERT INTO @Profitability VALUES ( 4, 'Software', 500, 400 ) ; INSERT INTO @Profitability VALUES ( 5, 'Hardware', 1000, 550 ) ; INSERT INTO @Profitability VALUES ( 6, 'Hardware', 1000, 250 ) ; INSERT INTO @Profitability VALUES ( 7, 'Hardware', 1000, 700 ) ; INSERT INTO @Profitability VALUES ( 8, 'Hardware', 5000, 4500 ) ; SELECT Cust ,Profit = SUM(Income - Expense) ,Margin = SUM(Income - Expense) / SUM(Income) FROM @Profitability GROUP BY Cust SELECT Category ,Profit = SUM(Income - Expense) ,Margin = SUM(Income - Expense) / SUM(Income) FROM @Profitability GROUP BY Category SELECT Profit = SUM(Income - Expense) ,Margin = SUM(Income - Expense) / SUM(Income) FROM @Profitability Notice how the same formulae have to be used at the different aggregation levels. This results in code duplication. I have thought of using UDFs (either scalar or table valued with an OUTER APPLY, since many of the final results may share intermediates which have to be calculated at the aggregate level), but in my experience the scalar and multi-statement table-valued UDFs perform very poorly. Also thought about using more dynamic SQL and applying the formulas by name, basically. Any other tricks, techniques or tactics to keeping these kinds of formulae which need to be applied at different levels in sync and/or organized?

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  • SQL Query - group by more than one column, but distinct

    - by Ranhiru
    I have a bidding table, as follows: SellID INT FOREIGN KEY REFERENCES SellItem(SellID), CusID INT FOREIGN KEY REFERENCES Customer(CusID), Amount FLOAT NOT NULL, BidTime DATETIME DEFAULT getdate() Now in my website I need to show the user the current bids; only the highest bid but without repeating the same user. SELECT CusID, Max(Amount) FROM Bid WHERE SellID = 10 GROUP BY CusID ORDER BY Max(Amount) DESC This is the best I have achieved so far. This gives the CusID of each user with the maximum bid and it is ordered ascending. But I need to get the BidTime for each result as well. When I try to put the BidTime in to the query: SELECT CusID, Max(Amount), BidTime FROM Bid WHERE SellID = 10 GROUP BY CusID ORDER BY Max(Amount) DESC I am told that "Column 'Bid.BidTime' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause." Thus I tried: SELECT CusID, Max(Amount), BidTime FROM Bid WHERE SellID = 10 GROUP BY CusID, BidTime ORDER BY Max(Amount) DESC But this returns all the rows. No distinction. Any suggestions on solving this issue?

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  • SQL Server: A Grouping question that's annoying me

    - by user366729
    I've been working with SQL Server for the better part of a decade, and this grouping (or partitioning, or ranking...I'm not sure what the answer is!) one has me stumped. Feels like it should be an easy one, too. I'll generalize my problem: Let's say I have 3 employees (don't worry about them quitting or anything...there's always 3), and I keep up with how I distribute their salaries on a monthly basis. Month Employee PercentOfTotal -------------------------------- 1 Alice 25% 1 Barbara 65% 1 Claire 10% 2 Alice 25% 2 Barbara 50% 2 Claire 25% 3 Alice 25% 3 Barbara 65% 3 Claire 10% As you can see, I've paid them the same percent in Months 1 and 3, but in Month 2, I've given Alice the same 25%, but Barbara got 50% and Claire got 25%. What I want to know is all the distinct distributions I've ever given. In this case there would be two -- one for months 1 and 3, and one for month 2. I'd expect the results to look something like this (NOTE: the ID, or sequencer, or whatever, doesn't matter) ID Employee PercentOfTotal -------------------------------- X Alice 25% X Barbara 65% X Claire 10% Y Alice 25% Y Barbara 50% Y Claire 25% Seems easy, right? I'm stumped! Anyone have an elegant solution? I just put together this solution while writing this question, which seems to work, but I'm wondering if there's a better way. Or maybe a different way from which I'll learn something. WITH temp_ids (Month) AS ( SELECT DISTINCT MIN(Month) FROM employees_paid GROUP BY PercentOfTotal ) SELECT EMP.Month, EMP.Employee, EMP.PercentOfTotal FROM employees_paid EMP JOIN temp_ids IDS ON EMP.Month = IDS.Month GROUP BY EMP.Month, EMP.Employee, EMP.PercentOfTotal Thanks y'all! -Ricky

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  • Why do properties behave this way?

    - by acidzombie24
    from http://csharpindepth.com/Articles/Chapter8/PropertiesMatter.aspx using System; struct MutableStruct { public int Value { get; set; } public void SetValue(int newValue) { Value = newValue; } } class MutableStructHolder { public MutableStruct Field; public MutableStruct Property { get; set; } } class Test { static void Main(string[] args) { MutableStructHolder holder = new MutableStructHolder(); // Affects the value of holder.Field holder.Field.SetValue(10); // Retrieves holder.Property as a copy and changes the copy holder.Property.SetValue(10); Console.WriteLine(holder.Field.Value); Console.WriteLine(holder.Property.Value); } } 1) Why is a copy (of Property?) being made? 2) When changing the code to holder.Field.value and holder.Property.value = 10 i get the error below. That just blew my mind Error 1 Cannot modify the return value of 'MutableStructHolder.Property' because it is not a variable Why would i ever not be allowed to assign a value inside of a property!?! both property are get/set! and finally WHY would you EVER want behavior mentioned in 1 and 2. (It never came up for me, i always used get only properties). Please explain well, i cant imagine ever wanting the 2nd much less then the first. It is just so weird to me.

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  • Simple perl program failing to execute

    - by yves Baumes
    Here is a sample that fails: #!/usr/bin/perl -w # client.pl #---------------- use strict; use Socket; # initialize host and port my $host = shift || 'localhost'; my $port = shift || 55555; my $server = "10.126.142.22"; # create the socket, connect to the port socket(SOCKET,PF_INET,SOCK_STREAM,(getprotobyname('tcp'))[2]) or die "Can't create a socket $!\n"; connect( SOCKET, pack( 'Sn4x8', AF_INET, $port, $server )) or die "Can't connect to port $port! \n"; my $line; while ($line = <SOCKET>) { print "$line\n"; } close SOCKET or die "close: $!"; with the error: Argument "10.126.142.22" isn't numeric in pack at D:\send.pl line 16. Can't connect to port 55555! I am using this version of Perl: This is perl, v5.10.1 built for MSWin32-x86-multi-thread (with 2 registered patches, see perl -V for more detail) Copyright 1987-2009, Larry Wall Binary build 1006 [291086] provided by ActiveState http://www.ActiveState.com Built Aug 24 2009 13:48:26 Perl may be copied only under the terms of either the Artistic License or the GNU General Public License, which may be found in the Perl 5 source kit. Complete documentation for Perl, including FAQ lists, should be found on this system using "man perl" or "perldoc perl". If you have access to the Internet, point your browser at http://www.perl.org/, the Perl Home Page. While I am running the netcat command on the server side. Telnet does work.

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  • Generalizing Fibonacci sequeue with SICStus Prolog

    - by Christophe Herreman
    I'm trying to find a solution for a query on a generalized Fibonacci sequence (GFS). The query is: are there any GFS that have 885 as their 12th number? The initial 2 numbers may be restricted between 1 and 10. I already found the solution to find the Nth number in a sequence that starts at (1, 1) in which I explicitly define the initial numbers. Here is what I have for this: fib(1, 1). fib(2, 1). fib(N, X) :- N #> 1, Nmin1 #= N - 1, Nmin2 #= N - 2, fib(Nmin1, Xmin1), fib(Nmin2, Xmin2), X #= Xmin1 + Xmin2. For the query mentioned I thought the following would do the trick, in which I reuse the fib method without defining the initial numbers explicitly since this now needs to be done dynamically: fib2 :- X1 in 1..10, X2 in 1..10, fib(1, X1), fib(2, X2), fib(12, 885). ... but this does not seem to work. Is it not possible this way to define the initial numbers, or am I doing something terribly wrong? I'm not asking for the solution, but any advice that could help me solve this would be greatly appreciated.

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  • How to manually add a legend to a ggplot object

    - by Dan
    I have this data frame: structure(list(month_num = 1:24, founded_month = c(4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 1L, 2L, 3L), founded_year = c(2008L, 2008L, 2008L, 2008L, 2008L, 2008L, 2008L, 2008L, 2008L, 2009L, 2009L, 2009L, 2009L, 2009L, 2009L, 2009L, 2009L, 2009L, 2009L, 2009L, 2009L, 2010L, 2010L, 2010L), count = c(270L, 222L, 256L, 250L, 277L, 268L, 246L, 214L, 167L, 408L, 201L, 225L, 203L, 220L, 230L, 225L, 177L, 207L, 166L, 135L, 116L, 122L, 69L, 42L), month_abb = c("Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec", "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec", "Jan", "Feb", "Mar"), short_year = c("08", "08", "08", "08", "08", "08", "08", "08", "08", "09", "09", "09", "09", "09", "09", "09", "09", "09", "09", "09", "09", "10", "10", "10" ), proj = c(282, 246, 292, 298, 337, 340, 330, 310, 275, 528, 333, 369, 359, 388, 410, 417, 381, 423, 394, 375, 368, 386, 345, 330), label = c("Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec", "Jan\n09", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec", "Jan\n10", "Feb", "Mar")), .Names = c("month_num", "founded_month", "founded_year", "count", "month_abb", "short_year", "proj", "label"), row.names = c(NA, -24L), class = "data.frame") and i've got all of this done (I know the code's a bit ugly looking, pointers appreciated): p <- ggplot(m_summary2, aes(x = month_num, y = count)) p + geom_line(colour = rgb(0/255, 172/255, 0/255)) + geom_point(colour = rgb(0/255, 172/255, 0/255)) + geom_line(aes(x = m_summary2$month_num, y = m_summary2$proj), colour = rgb(18/255, 111/255, 150/255)) + geom_point(aes(x = m_summary2$month_num, y = m_summary2$proj), colour = rgb(18/255, 111/255, 150/255)) + scale_x_continuous("Month", breaks = m_summary2$month_num, labels = m_summary2$label) + scale_y_continuous("# Startups Founded") + opts(title = paste("# Startups Founded:", m_summary2$month_abb[1], m_summary2$short_year[1], "-", m_summary2$month_abb[nrow(m_summary2)], m_summary2$short_year[nrow(m_summary2)])) Now I would like to add a legend to clarify that the blue line is a projection and the green line is the current data. Thanks in advance!

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  • Function within function in R

    - by frespider
    Can you please explain to me why th code complain saying that Samdat is not found? I am trying to switch between the models as you can see, so i declared a functions that contains these specific models and I just need to call these function as one of the argument in the get.f function where the resampling will change the structure for each design matrix in the model. the code complain the Samdat is not found when it is found. Also, is there a way I can make the condition statement as if(Model == M1()) instead I have to create another argument M to set if(M==1) Can you explain please? dat <- cbind(Y=rnorm(20),rnorm(20),runif(20),rexp(20),rnorm(20),runif(20), rexp(20),rnorm(20),runif(20),rexp(20)) nam <- paste("v",1:9,sep="") colnames(dat) <- c("Y",nam) M1 <- function(){ a1 = cbind(Samdat[,c(2:5,7,9)]) b1 = cbind(Samdat[,c(2:4,6,8,7)]) c1 = b1+a1 list(a1=a1,b1=b1,c1=c1)} M2 <- function(){ a1= cbind(Samdat[,c(2:5,7,9)])+2 b1= cbind(Samdat[,c(2:4,6,8,7)])+2 c1 = a1+b1 list(a1=a1,b1=b1,c1=c1)} M3 <- function(){ a1= cbind(Samdat[,c(2:5,7,9)])+8 b1= cbind(Samdat[,c(2:4,6,8,7)])+8 c1 = a1+b1 list(a1=a1,b1=b1,c1=c1)} ################################################################# get.f <- function(asim,Model,M){ sse <-c() for(i in 1:asim){ set.seed(i) Samdat <- dat[sample(1:nrow(dat),nrow(dat),replace=T),] Y <- Samdat[,1] if(M==1){ a2 <- Model$a1 b2 <- Model$b1 c2 <- Model$c1 s<- a2+b2+c2 fit <- lm(Y~s) cof <- sum(summary(fit)$coef[,1]) coff <-Model$cof sse <-c(sse,coff) } else if(M==2){ a2 <- Model$a1 b2 <- Model$b1 c2 <- Model$c1 s<- c2+12 fit <- lm(Y~s) cof <- sum(summary(fit)$coef[,1]) coff <-Model$cof sse <-c(sse,coff) } else { a2 <- Model$a1 b2 <- Model$b1 c2 <- Model$c1 s<- c2+a2 fit <- lm(Y~s) cof <- sum(summary(fit)$coef[,1]) coff <- Model$cof sse <-c(sse,coff) } } return(sse) } get.f(10,Model=M1(),M=1) get.f(10,Model=M2(),M=2) get.f(10,Model=M3(),M=3)

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  • Q on Python serialization/deserialization

    - by neil
    What chances do I have to instantiate, keep and serialize/deserialize to/from binary data Python classes reflecting this pattern (adopted from RFC 2246 [TLS]): enum { apple, orange } VariantTag; struct { uint16 number; opaque string<0..10>; /* variable length */ } V1; struct { uint32 number; opaque string[10]; /* fixed length */ } V2; struct { select (VariantTag) { /* value of selector is implicit */ case apple: V1; /* VariantBody, tag = apple */ case orange: V2; /* VariantBody, tag = orange */ } variant_body; /* optional label on variant */ } VariantRecord; Basically I would have to define a (variant) class VariantRecord, which varies depending on the value of VariantTag. That's not that difficult. The challenge is to find a most generic way to build a class, which serializes/deserializes to and from a byte stream... Pickle, Google protocol buffer, marshal is all not an option. I made little success with having an explicit "def serialize" in my class, but I'm not very happy with it, because it's not generic enough. I hope I could express the problem. My current solution in case VariantTag = apple would look like this, but I don't like it too much import binascii import struct class VariantRecord(object): def __init__(self, number, opaque): self.number = number self.opaque = opaque def serialize(self): out = struct.pack('>HB%ds' % len(self.opaque), self.number, len(self.opaque), self.opaque) return out v = VariantRecord(10, 'Hello') print binascii.hexlify(v.serialize()) >> 000a0548656c6c6f Regards

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  • Why does Fabric display the disconnect from server message for almost 2 minutes?

    - by Matthew Rankin
    Fabric displays Disconnecting from username@server... done. for almost 2 minutes prior to showing a new command prompt whenever I issue a fab command. This problem exists when using Fabric commands issued to both an internal server and a Rackspace cloud server. Below I've included the auth.log from the server, and I didn't see anything in the logs on my MacBook. Any thoughts as to what the problem is? Server's SSH auth.log with LogLevel VERBOSE Apr 21 13:30:52 qsandbox01 sshd[19503]: Accepted password for mrankin from 10.10.100.106 port 52854 ssh2 Apr 21 13:30:52 qsandbox01 sshd[19503]: pam_unix(sshd:session): session opened for user mrankin by (uid=0) Apr 21 13:30:52 qsandbox01 sudo: mrankin : TTY=unknown ; PWD=/home/mrankin ; USER=root ; COMMAND=/bin/bash -l -c apache2ctl graceful Apr 21 13:30:53 qsandbox01 sshd[19503]: pam_unix(sshd:session): session closed for user mrankin Server Configuration OS: Ubuntu 9.10 OpenSSH: Ubuntu package version 1.5.1p1-6ubuntu2 Client Configuration OS: Mac OS X 10.6.3 Fabric ver 0.9 Vritualenv ver 1.4.7 pip ver 0.7 Thoughts on Cause of the Issue I don't know how long the problem has existed. However, I know that at one point I didn't have this problem. Things that have changed since then are that I have recreated my virtualenv's using virtualenv 1.4.7, virtualenvwrapper 2.1, and pip 0.7. Not sure if this is related, but it is a thought since I run my fabfiles from within a virtualenv.

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  • How to create a column containing a string of stars to inidcate levels of a factor in a data frame i

    - by PaulHurleyuk
    (second question today - must be a bad day) I have a dataframe with various columns, inculding a concentration column (numeric), a flag highlighting invalid results (boolean) and a description of the problem (character) dput(df) structure(list(x = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10), rawconc = c(77.4, 52.6, 86.5, 44.5, 167, 16.2, 59.3, 123, 1.95, 181), reason = structure(c(NA, NA, 2L, NA, NA, NA, 2L, 1L, NA, NA), .Label = c("Fails Acceptance Criteria", "Poor Injection"), class = "factor"), flag = c("False", "False", "True", "False", "False", "False", "True", "True", "False", "False" )), .Names = c("x", "rawconc", "reason", "flag"), row.names = c(NA, -10L), class = "data.frame") I can create a column with the numeric level of the reason column df$level<-as.numeric(df$reason) df x rawconc reason flag level 1 1 77.40 <NA> False NA 2 2 52.60 <NA> False NA 3 3 86.50 Poor Injection True 2 4 4 44.50 <NA> False NA 5 5 167.00 <NA> False NA 6 6 16.20 <NA> False NA 7 7 59.30 Poor Injection True 2 8 8 123.00 Fails Acceptance Criteria True 1 9 9 1.95 <NA> False NA 10 10 181.00 <NA> False NA and here's what I want to do to create a column with 'level' many stars, but it fails df$stars<-paste(rep("*",df$level)sep="",collapse="") Error: unexpected symbol in "df$stars<-paste(rep("*",df$level)sep" df$stars<-paste(rep("*",df$level),sep="",collapse="") Error in rep("*", df$level) : invalid 'times' argument rep("*",df$level) Error in rep("*", df$level) : invalid 'times' argument df$stars<-paste(rep("*",pmax(df$level,0,na.rm=TRUE)),sep="",collapse="") Error in rep("*", pmax(df$level, 0, na.rm = TRUE)) : invalid 'times' argument It seems that rep needs to be fed one value at a time. I feel that this should be possible (and my gut says 'use lapply' but my apply fu is v. poor) ANy one want to try ?

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  • Comparing two date ranges within the same table

    - by Danny Herran
    I have a table with sales per store as follows: SQL> select * from sales; ID ID_STORE DATE TOTAL ---------- -------- ---------- -------------------------------------------------- 1 1 2010-01-01 500.00 2 1 2010-01-02 185.00 3 1 2010-01-03 135.00 4 1 2009-01-01 165.00 5 1 2009-01-02 175.00 6 5 2010-01-01 130.00 7 5 2010-01-02 135.00 8 5 2010-01-03 130.00 9 6 2010-01-01 100.00 10 6 2010-01-02 12.00 11 6 2010-01-03 85.00 12 6 2009-01-01 135.00 13 6 2009-01-02 400.00 14 6 2009-01-07 21.00 15 6 2009-01-08 45.00 16 8 2009-01-09 123.00 17 8 2009-01-10 581.00 17 rows selected. What I need to do is to compare two date ranges within that table. Lets say I need to know the differences in sales between 01 Jan 2009 to 10 Jan 2009 AGAINST 01 Jan 2010 to 10 Jan 2010. I'd like to build a query that returns something like this: ID_STORE_A DATE_A TOTAL_A ID_STORE_B DATE_B TOTAL_B ---------- ---------- --------- ---------- ---------- ------------------- 1 2010-01-01 500.00 1 2009-01-01 165.00 1 2010-01-02 185.00 1 2009-01-02 175.00 1 2010-01-03 135.00 1 NULL NULL 5 2010-01-01 130.00 5 NULL NULL 5 2010-01-02 135.00 5 NULL NULL 5 2010-01-03 130.00 5 NULL NULL 6 2010-01-01 100.00 6 2009-01-01 135.00 6 2010-01-02 12.00 6 2009-01-02 400.00 6 2010-01-03 85.00 6 NULL NULL 6 NULL NULL 6 2009-01-07 21.00 6 NULL NULL 6 2009-01-08 45.00 6 NULL NULL 8 2009-01-09 123.00 6 NULL NULL 8 2009-01-10 581.00 So, even if there are no sales in one range or another, it should just fill the empty space with NULL. So far, I've come up with this quick query, but I the "dates" from sales to sales2 sometimes are different in each row: SELECT sales.*, sales2.* FROM sales LEFT JOIN sales AS sales2 ON (sales.id_store=sales2.id_store) WHERE sales.date >= '2010-01-01' AND sales.date <= '2010-01-10' AND sales2.date >= '2009-01-01' AND sales2.date <= '2009-01-10' ORDER BY sales.id_store ASC, sales.date ASC, sales2.date ASC What am I missing?

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  • ANOVA with 3 fixed factors in R

    - by TKBell
    Im trying to run a model with a response variable p and 3 fixed factors to get ANOVA. this is how my code looks like : #run it as 3 fixed factor model p1=c(37,38,37,41,41,40,41,42,41) p2=c(42,41,43,42,42,42,43,42,43) p3=c(30,31,31,31,31,31,29,30,28) p4=c(42,43,42,43,43,43,42,42,42) p5=c(28,30,29,29,30,29,31,29,29) p6=c(42,42,43,45,45,45,44,46,45) p7=c(25,26,27,28,28,30,29,27,27) p8=c(40,40,40,43,42,42,43,43,41) p9=c(37,38,37,41,41,40,41,42,41) p10=c(35,34,34,35,35,34,35,34,35) p = cbind(p1,p2,p3,p4,p5,p6,p7,p8,p9,p10) partnumber=c(rep(1,9),rep(2,9),rep(3,9),rep(4,9),rep(5,9),rep(6,9),rep(7,9),rep(8,9),rep(9,9),rep(10,9)) test=c(rep(c(rep(1:3,3)),10)) inspector = rep(c(rep(1,3),rep(2,3),rep(3,3)),10) fpartnumber = factor(partnumber) ftest = factor(test) finspector = factor(inspector) model=lm(p~fpartnumber*ftest*finspector) summary(model) anova(model) but when I run it I get this error : it says my variable length for fpartnumber is different , but when I checked the length of each variable and is 90. What is going on ? model=lm(y~fpartnumber*ftest*finspector) Error in model.frame.default(formula = yang ~ fpartnumber * ftest * finspector, : variable lengths differ (found for 'fpartnumber')

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  • If I'm using a 1d array to represent a square board, how can I take my index and check the sqaures a

    - by FrankTheTank
    If I have a 4x4 gameboard which I'm representing in my program as a 1d integer array of size 16. How can I get the indexs of the squares above, below, to the left and to the right any given index? So, for example: A = { 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 } Which represents this board 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Lets say I am currently on index #8 in the board (value = 7). How can I get the index for 4 (value = 3) , 5 (value = 6), 10 (value = 11) and realize that there is no right square because it is on the right hand edge of the board. I know I need to use some modulus math but I'm failing to come up with the right way to get the indexes for adjacent squares. I'm thinking something like... if ((i % 4) + 1 < 3) right = i + 1; if ((i % 4) - 1 > 0) left = i - 1; if ((i % 4) + 4 < 15) bottom = i + 4; if ((i % 4) - 4 > 0 ) top = i - 4; Does this seem like it is the right approach?

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  • iPhone: understanding field crash reports: unrecognized selector?

    - by quixoto
    Hi all, A user of my app out in the field seems to having bad crash-at-app-start issues. I got him to send me the .crash files from his PC. After "symbolicating" them according to this article, I get what looks from the stack like a unrecognized selector fail. But the top line of code corresponding to my process is an unambiguous message send that gets executed hundreds of times without issue in my app normally. Needless to say, I never repro this issue myself. Can the crash report lie? Could this stack indicate anything besides unrecognized selector? Thanks for any insight. Exception Type: EXC_CRASH (SIGABRT) Exception Codes: 0x00000000, 0x00000000 Crashed Thread: 0 Thread 0 Crashed: 0 libSystem.B.dylib 0x000790a0 __kill + 8 1 libSystem.B.dylib 0x00079090 kill + 4 2 libSystem.B.dylib 0x00079082 raise + 10 3 libSystem.B.dylib 0x0008d20a abort + 50 4 libstdc++.6.dylib 0x00044a1c __gnu_cxx::__verbose_terminate_handler() + 376 5 libobjc.A.dylib 0x000057c4 _objc_terminate + 104 6 libstdc++.6.dylib 0x00042dee __cxxabiv1::__terminate(void (*)()) + 46 7 libstdc++.6.dylib 0x00042e42 std::terminate() + 10 8 libstdc++.6.dylib 0x00042f12 __cxa_throw + 78 9 libobjc.A.dylib 0x000046a4 objc_exception_throw + 64 10 CoreFoundation 0x00094174 -[NSObject doesNotRecognizeSelector:] + 108 11 CoreFoundation 0x00093afa ___forwarding___ + 482 12 CoreFoundation 0x000306c8 _CF_forwarding_prep_0 + 40 13 MyAppProcess 0x000147c6 -[ImageLoader imageSmallForColor:style:] (ImageLoader.m:180) .... /* many more frames... */

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  • bash and flock (file lock) - Doesn't seem to be locking....

    - by Rory
    I am playing with using flock, a bash command for file locks to prevent 2 different instances of the code from running more than once. I am using this testing code: ( ( flock -x 200 ; sleep 10 ; echo "original finished" ; ) 200>./test.lock ) & ( sleep 2 ; ( flock -x -w 2 200 ; echo "a finished" ) 200>./test.lock ) & I am running 2 subshells (backgrounded). The (flock NUM; ...) NUM>FILE syntax is from flock's man page. I expect that the first subshell will get an exclusive lock on test.lock, then wait 10 seconds, then print "original finished", all the time holding the lock. The second subshell will start at more or less the same time, wait 2 seconds, then try to get a lock on test.lock, but timeout after 2 seconds. If it gets a lock, then it'll print "a finished". If it doesn't get the lock, that subshell should stop, and nothing should be printed. Since the first subshell is waiting longer, it will keep the lock for 10 seconds, so the second subshell should not get the lock, and shouldn't finish. i.e. one should see "original finished" printed and not both. What actually happens is that "a finished" is printed, then "original finished" is printed. This implies that that the second subshell is either (a) not using the same lock as the first subhsell or (b) that it fails to get the lock, but continues to execute or (c) something else. Why don't those locks work?

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  • Checking if an array contains all elements of another array

    - by mozcelikors
    I'm designing an electrical engineering application. However, i'm stuck on this: I have the following array <?php // Static Array $GroupOfEight = array ( array(0,1,3,2,4,5,7,6), array(4,5,6,7,16,12,13,14), array(12,13,15,14,8,9,11,10), array(2,6,14,10,3,7,15,11), array(1,3,5,7,13,15,9,11), array(0,4,12,8,1,5,13,9), array(0,1,3,2,8,9,11,10) ); ?> And I have another array, but this one is one dimensional. <?php $myStack = array(0,1,3,2,4,5,7,6); //Dynamic, gets value by POST method. ?> What I want to do is to check if $myStack is equal to any sub array of $GroupOfEight array. ( Number ordering is not important. The script should just check if every elements contained. It's not important if their order is same or not. ) Here is what I've done to solve the issue so far: <?php //Check if stackArray contains 8group for($i=0; $i<count($GroupOfEight);$i++) for($j=0; $j<count($GroupOfEight[$i]); $j++){ //$containsSearch = count(array_intersect($search_this,$all)) == count($search_this); $containsSearch = count(array_intersect($stackArray,$GroupOfEight[$j])) == count($stackArray); echo $containsSearch; } ?> Please help me correct my code or introduce me the solution of this issue, Thanks.

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  • DDD: Persisting aggregates

    - by Mosh
    Hello, Let's consider the typical Order and OrderItem example. Assuming that OrderItem is part of the Order Aggregate, it an only be added via Order. So, to add a new OrderItem to an Order, we have to load the entire Aggregate via Repository, add a new item to the Order object and persist the entire Aggregate again. This seems to have a lot of overhead. What if our Order has 10 OrderItems? This way, just to add a new OrderItem, not only do we have to read 10 OrderItems, but we should also re-insert all these 10 OrderItems again. (This is the approach that Jimmy Nillson has taken in his DDD book. Everytime he wants to persists an Aggregate, he clears all the child objects, and then re-inserts them again. This can cause other issues as the ID of the children are changed everytime because of the IDENTITY column in database.) I know some people may suggest to apply Unit of Work pattern at the Aggregate Root so it keeps track of what has been changed and only commit those changes. But this violates Persistence Ignorance (PI) principle because persistence logic is leaking into the Domain Model. Has anyone thought about this before? Mosh

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  • XSLT multiple string replacement with recursion

    - by John Terry
    I have been attempting to perform multiple (different) string replacement with recursion and I have hit a roadblock. I have sucessfully gotten the first replacement to work, but the subsequent replacements never fire. I know this has to do with the recursion and how the with-param string is passed back into the call-template. I see my error and why the next xsl:when never fires, but I just cant seem to figure out exactly how to pass the complete modified string from the first xsl:when to the second xsl:when. Any help is greatly appreciated. <xsl:template name="replace"> <xsl:param name="string" select="." /> <xsl:choose> <xsl:when test="contains($string, '&#13;&#10;')"> <xsl:value-of select="substring-before($string, '&#13;&#10;')" /> <br/> <xsl:call-template name="replace"> <xsl:with-param name="string" select="substring-after($string, '&#13;&#10;')"/> </xsl:call-template> </xsl:when> <xsl:when test="contains($string, 'TXT')"> <xsl:value-of select="substring-before($string, '&#13;TXT')" /> <xsl:call-template name="replace"> <xsl:with-param name="string" select="substring-after($string, '&#13;')" /> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$string"/> </xsl:otherwise> </xsl:choose> </xsl:template>

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  • Triangle numbers problem....show within 4 seconds

    - by Daredevil
    The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms would be: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ... Let us list the factors of the first seven triangle numbers: 1: 1 3: 1,3 6: 1,2,3,6 10: 1,2,5,10 15: 1,3,5,15 21: 1,3,7,21 28: 1,2,4,7,14,28 We can see that 28 is the first triangle number to have over five divisors. Given an integer n, display the first triangle number having at least n divisors. Sample Input: 5 Output 28 Input Constraints: 1<=n<=320 I was obviously able to do this question, but I used a naive algorithm: Get n. Find triangle numbers and check their number of factors using the mod operator. But the challenge was to show the output within 4 seconds of input. On high inputs like 190 and above it took almost 15-16 seconds. Then I tried to put the triangle numbers and their number of factors in a 2d array first and then get the input from the user and search the array. But somehow I couldn't do it: I got a lot of processor faults. Please try doing it with this method and paste the code. Or if there are any better ways, please tell me.

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