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  • Dropdown dependent values to be fetch from multiple models using ajax in Yii

    - by newuser
    I searched all the documentation over Yii but not got the answer of it.So I came here finally. I have the following schema Table Schools +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_name | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ Table Students +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_id | int(10) | NO | FK | | | | student_name | varchar(100) | NO | | | | | roll_no | varchar(80) | NO | | | | | class | varchar(20) | NO | | | | | | subjects | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ I have made models and CRUD for the both models.In models my relation is like this In Students.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'School' => array(self::BELONGS_TO,'Schools','school_id'), ); } In Schools.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'student' => array(self::HAS_MANY, 'Students', 'school_id'), ); } Now I made the two models rendered in a single page so that I can enter all the respective fields in a single form. In the _form.php file of Students I have made some change in student_name like this <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php echo $form->dropdownList($model,'student_name', CHtml::listData(Students::model()->findAll(), 'id', 'student_name'), array('empty'=>array('Select'=>'--Select One---'))); ?> <?php echo $form->error($model,'student_name'); ?> Now for this piece of code I got all the student name from the Student model. So my problem is when I am getting the student name from the dropdown list and going to select a student it will also fetch all the respective values of the student to be rendered in the _form.php without click on save button.So that user don't have to put it again manually. I think ajax and json encode will work here but don't know how to make them work here. [Update] Here is StudentsController code public function actionDisCoor() { $model = School::model()->findByPk($_POST['Students']['student_id']); $data=CHtml::listData($data,'id','name'); foreach($data as $value=>$name) { echo CHtml::tag('option',array('value'=>$value),CHtml::encode($name),true); } } Here is _form.php code for Students <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php $List = CHtml::listData(Students::model()->findAll(), 'id', 'student_name'); ?> <?php echo $form->dropdownList($model,'student_name',$List, array('onChange'=>CHtml::ajax(array( 'url' => CController::createUrl('DisCoor'), 'type' => 'POST', 'update'=>'#school_id', )),'style'=>'width:180px;' ) )?> <?php echo $form->error($model,'student_name'); ?> </div> After all that when I saw in firebug I got the error.Here is the screen shot

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  • SQL Like question

    - by mike
    Is there a way to reverse the SQL Like operator so it searches a field backwards? For example, I have a value in a field that looks like this "Xbox 360 Video Game". If I write a query like below, it returns the result fine. SELECT id FROM table WHERE title like "%Xbox%Game%" However, when I search like this, it doesn't find any results. SELECT id FROM table WHERE title like "%Video%Xbox%" I need it to match in any direction. How can I get around this?

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  • again new query. i am trying to solve this from one hour. please help

    - by Dharmendra
    Query : List the film title and the leading actor for all of 'Julie Andrews' films. there are three tables : movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord) select movie.title,actor.name as cont from movie join casting on (movie.id=casting.movieid) join actor on (casting.actorid=actor.id) where actor.name='Julie andrews' actually i can' get how to find the leading actor.

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  • How would I UPDATE these table entries with SQL and PHP?

    - by CT
    I am working on an Asset Database problem. I enter assets into a database. Every object is an asset and has variables within the asset table. An object is also a type of asset. In this example the type is server. Here is the Query to retrieve all necessary data: SELECT asset.id ,asset.company ,asset.location ,asset.purchaseDate ,asset.purchaseOrder ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serialNumber ,server.esc ,server.warranty ,server.user ,server.prevUser ,server.cpu ,server.memory ,server.hardDrive FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = '$id' I then assign all results into single php variables. How would I write a query/script to update an asset?

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  • How can "set timestamp" be a slow query?

    - by Peder
    My slow query log is full of entries like the following # Query_time: 1.016361 Lock_time: 0.000000 Rows_sent: 0 Rows_examined: 0 SET timestamp=1273826821; COMMIT; I guess the set timestamp command is issued by replication but I don't understand how set timestamp can take over a second. Any ideas?

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  • How to display external database data in VBulletin 4 Forums Custom PHP Block?

    - by NJTechGuy
    Hi guys! I want to display data feed from an external database in a sidebar in the forums section. PHP Block Code : $host = 'db.123.net'; $dbUser = 'db49'; $dbPass = 'iReVbY'; $db = 'db6578h8'; mysql_connect("$host", "$dbUser", "$dbPass") or die(mysql_error()); mysql_select_db("$db") or die(mysql_error()); ob_start(); $result = mysql_query("SELECT id, title from abc") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { print"<center>"; print "<a href=\"http://abc.com/?id=" . $row['id'] . "\"></a>"; print "</center>"; } $output .= ob_get_contents(); return $output; ob_end_clean(); How do I return an array to display in a PHP block in the sidebar (forums section)? Please help me out of this! Thank you..

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  • Thoughts/Input about Database Design for a CMS

    - by dallasclark
    I'm just about to expand the functionality of our own CMS but was thinking of restructuring the database to make it simpler to add/edit data types and values. Currently, the CMS is quite flat - the CMS requires a field in the database for every type of stored value (manually created). The first option that comes to mind is simply a table which keeps the data types (ie: Address 1, Suburb, Email Address etc) and another table which holds values for each of these data types. Just like how Wordpress keeps values in the 'options' table, PHP serialize would be used to store an array of values. The second option is how Drupal works, the CMS creates tables for every data type. Unlike Wordpress, this can be a bit of an overkill but really useful for SQL queries when ordering and grouping by a particular value. What's everyone's thoughts?

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  • How to sekect latest chnge done in the given Table structure?

    - by OM The Eternity
    I have a Table structure as id, trackid, table_name, operation, oldvalue, newvalue, field, changedonetime Now if I have 3 rows for the same "trackid" same "field", then how can i select the latest out of the three? i.e. for e.g.: id = 100 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPL newvalue = IPLcccc field = name live = 0 changedonetime = 2010-04-30 17:54:39 and id = 101 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPLcccc newvalue = IPL2222 field = name live = 0 changedonetime = 2010-04-30 18:54:39 As u can see above the secind entry is the latest change, Now what query I shoud use to get the only one and Latest row out of many such rows...

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  • i demand you all men to help

    - by Hello you all men
    you all men i demand answer, you say not real question?? many page get big load for long time and now we are suspended and http://stackoverflow.com/questions/2890840/how-can-we-make-our-website-scalable and please you help men very sorry -bern

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  • SQL Count Query with Grouping by multiple Columns

    - by Christian
    I have a table with three filled columns named "Name", "City" and "Occupation". I want to create a new column in the same table that contains the number of people who have the same occupation. "Name" | "City" | "Occupation" ------------------------------ Amy | Berlin | Plumber Bob | Berlin | Plumber Carol | Berlin | Lawyer David | London | Plumber I want to have a table that contains: "Name" | "City" | "Occupation" | "Number" --------------------------------------- Amy | Berlin | Plumber | 2 Bob | Berlin | Plumber | 2 Carol | Berlin | Lawyer | 1 David | London | Plumber | 1 How does the SQL Query that creates the new columns have to look like? I want to actually create a new column in the database that I can access later.

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  • SQL, PHP: want to get the collums of a table INFORMATION_SCHEMA gives acces denied --> alternative?

    - by matthy
    hi what i am trying to do is get all the collums of a table (the table can be empty) example of what i did before: SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE table_name = 'aTable' AND table_schema = 'theDatabase' it works perfectly on localhost however on my provider it gives: #1142 - SELECT command denied to user 'username'@'localhost' for table 'COLUMNS' is there an alternative that doesn't use the INFORMATION_SCHEMA??

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  • I need help with creating a data structure in PHP

    - by alex
    What I need to do is have a data structure that shows jobs organised into 14 day periods, but only when an id is the same. I've implemented all sorts of stuff, but they have failed miserably. Ideally, maybe a SQL expert could handle all of this in the query. Here is some of my code. You can assume all library stuff works as expected. $query = 'SELECT date, rig_id, comments FROM dor ORDER BY date DESC'; $dors = Db::query(Database::SELECT, $query)->execute()->as_array(); This will return all jobs, but I need to have them organised by 14 day period with the same rig_id value. $hitches = array(); foreach($dors as $dor) { $rigId = $dor['rig_id']; $date = strtotime($dor['date']); if (empty($hitches)) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } else { $found = false; foreach($hitches as $key => $hitch) { $hitchStartDate = $hitch['startDate']; $dateDifference = abs($hitchStartDate - $date); $isSameHitchTimeFrame = $dateDifference < (Date::DAY * 14); if ($rigId == $hitch['rigId'] AND $isSameHitchTimeFrame) { $found = true; $hitches[$key]['dors'][] = $dor; } } if ($found === false) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } } } This seems to work OK splitting up by rig_id, but not by date. I also think I'm doing it wrong because I need to check the earliest date. Is it possible at all to do any of this in the database query? To recap, here is my problem I have a list of jobs with all have a rig_id (many jobs can have the same) and a date. I need the data to be organised into hitches. That is, the rig_id must be the same per hitch, and they must span a 14 day period, in which the next 14 days with the same rig_id will be a new hitch. Can someone please point me on the right track? Cheers

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  • Aggregate Functions on subsets of data based on current row values with SQL

    - by aasukisuki
    Hopefully that title makes sense... Let's say I have an employee table: ID | Name | Title | Salary ---------------------------- 1 | Bob | Manager | 15285 2 | Joe | Worker | 10250 3 | Al | Worker | 11050 4 | Paul | Manager | 16025 5 | John | Worker | 10450 What I'd like to do is write a query that will give me the above table, along with an averaged salary column, based on the employee title: ID | Name | Title | Salary | Pos Avg -------------------------------------- 1 | Bob | Manager | 15285 | 15655 2 | Joe | Worker | 10250 | 10583 3 | Al | Worker | 11050 | 10583 4 | Paul | Manager | 16025 | 15655 5 | John | Worker | 10450 | 10583 I've tried doing this with a sub-query along the lines of: Select *, (select Avg(e2.salary) from employee e2 where e2.title = e.title) from employee e But I've come to realize that the sub-query is executed first, and has no knowledge of the table alias'd e I'm sure I'm missing something REALLY obvious here, can anyone point me in the right diretion?

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  • Why does my Doctrine DBAL query return no results when quoted?

    - by braveterry
    I'm using the Doctrine DataBase Abstraction Layer (DBAL) to perform some queries. For some reason, when I quote a parameter before passing it to the query, I get back no rows. When I pass it unquoted, it works fine. Here's the relevant snippet of code I'm using: public function get($game) { load::helper('doctrinehelper'); $conn = doctrinehelper::getconnection(); $statement = $conn->prepare('SELECT games.id as id, games.name as name, games.link_url, games.link_text, services.name as service_name, image_url FROM games, services WHERE games.name = ? AND services.key = games.service_key'); $quotedGame = $conn->quote($game); load::helper('loghelper'); $logger = loghelper::getLogger(); $logger->debug("Quoted Game: $quotedGame"); $logger->debug("Unquoted Game: $game"); $statement->execute(array($quotedGame)); $resultsArray = $statement->fetchAll(); $logger->debug("Number of rows returned: " . count($resultsArray)); return $resultsArray; } Here's what the log shows: 01/01/11 17:00:13,269 [2112] DEBUG root - Quoted Game: 'Diablo II Lord of Destruction' 01/01/11 17:00:13,269 [2112] DEBUG root - Unquoted Game: Diablo II Lord of Destruction 01/01/11 17:00:13,270 [2112] DEBUG root - Number of rows returned: 0 If I change this line: $statement->execute(array($quotedGame)); to this: $statement->execute(array($game)); I get this in the log: 01/01/11 16:51:42,934 [2112] DEBUG root - Quoted Game: 'Diablo II Lord of Destruction' 01/01/11 16:51:42,935 [2112] DEBUG root - Unquoted Game: Diablo II Lord of Destruction 01/01/11 16:51:42,936 [2112] DEBUG root - Number of rows returned: 1 Have I fat-fingered something?

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  • Do a query only if there are no results on previous query

    - by yes123
    Hi guys: I do this query(1): (1)SELECT * FROM t1 WHERE title LIKE 'key%' LIMIT 1 I need to do a second(2) query only if this previous query has no results (2)SELECT * FROM t1 WHERE title LIKE '%key%' LIMIT 1 basically i need only 1 row who got the most close title to my key. Atm i am using an UNION query with a custom field to order it and a LIMIT 1. Problem is I don't want to do the others query if already the first made the result. Thanks

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  • Should I include user_id in multiple tables?

    - by Drarok
    I'm at the planning stages of a multi-user application where each user will only have access their own data. There'll be a few tables that relate to each other, so I could use JOINs to ensure they're accessing only their data, but should I include user_id in each table? Would this be faster? It would certainly make some of the queries easier in the long run. Thanks!

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  • Access 2007 file picker, replaces all rows with the same choice.

    - by SqlStruggle
    This code is from an Access 2007 project I've been struggling with. The actual mean part is the part where I should put something like "update only current form" DoCmd.RunSQL "Update Korut Set [PikkuKuva]=('" & varFile & "') ;" Could someone please help me with this?` If I use it now, it updates all the tables with the same file picked. Heres the whole code. ' This requires a reference to the Microsoft Office 11.0 Object Library. Dim fDialog As Office.FileDialog Dim varFile As Variant Dim filePath As String ' Set up the File dialog box. Set fDialog = Application.FileDialog(msoFileDialogFilePicker) With fDialog ' Allow the user to make multiple selections in the dialog box. .AllowMultiSelect = False ' Set the title of the dialog box. .Title = "Valitse Tiedosto" ' Clear out the current filters, and then add your own. .Filters.Clear .Filters.Add "All Files", "*.*" ' user picked at least one file. If the .Show method returns ' False, the user clicked Cancel. If .Show = True Then ' Loop through each file that is selected and then add it to the list box. For Each varFile In .SelectedItems DoCmd.SetWarnings True DoCmd.RunSQL "Update Korut Set [PikkuKuva]=('" & varFile & "') ;" Next Else MsgBox "You clicked Cancel in the file dialog box." End If End With

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  • Normalization of database for timesheet tool and ensure data integrity

    - by fireeyedboy
    I'm creating a timesheet application. I have the following entities (amongst others): Company Employee = an employee associated with a company Client = a client associated with a company So far I have the following (abbreviated) database setup: Company - id - name Employee - id - companyId (FK to Company.id) - name Client - id - companyId (FK to Company.id) - name Now, I want an employee to be associated with a client, but only if that client is associated with the company the employee works for. How would you guarantee this data integrity on a database level? Or should I just depend on the application to guarantee this data integrity? I thought about creating a many to many table like this: EmployeeClient - employeeId (FK to Employee.id) - companyId \ (combined FK to Client.companyId, Client.id) - clientId / Thus, when I insert a client for an employee along with the employee's company id, the database should prevent this when the client is not associated with the employee's company id. Does this make sense? Because this still doesn't guarantee the employee is associated with the company. How do you deal with these things? UPDATE The scenario is as followed: A company has multiple employees. Employees will only be linked to one company. A company has multiple clients also. Clients will only be linked to one company. (Company is a sandbox, so to speak). An employee of a company can be linked to a client of it's company, but only if the client is part of the company's clientele. In other words: The application will allow a company to create/add employees and create/add clients (hence the companyId FK in the Employee and Client tables). Next, the company will be allowed to assign certain clients to certain of it's employees (EmployeeClient table). Imagine an employee working on projects for a few clients for which s/he can write billable hours, but the employee must not be allowed to write billable hours for clients they are not assigned to by their employer (the company). So, employees will not automatically have access to all their company's clients, but only to those that the company has selected for them. Hopefully this has shed some more light on the matter.

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  • Make A HTML/PHP Link

    - by Will Evans
    I have the code below: $result = mysql_query("SELECT link, notes FROM links WHERE username='will';"); $html .= "<ul>"; while ($row = mysql_fetch_array($result)) { //loop extract($row); $html .= "<li>{$link} - {$notes}</li>"; } I need the bit where it says {$link} to become a clickable link which opens a new window. How would I do this? When I put tags around it you get this error: The error is: Parse error: syntax error, unexpected '{' in /data/www/vhosts/themacsplash.com/httpdocs/ClipBoy/will.php on line 18 Line 18 is $html .= "{$link} - {$notes}";

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  • Audit Table using Triggers

    - by Jose
    DROP TABLE IF EXISTS `actividades`.`act_actividad_audit`; CREATE TABLE `actividades`.`act_actividad_audit` ( `fe_creacion` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP, `usr_digitador` char(10) NOT NULL, `ip_digitador` char(15) NOT NULL, `id_act_actividad` int(10) unsigned NOT NULL, `titulo` char(64) NOT NULL, `act_prioridad_id` int(10) unsigned NOT NULL, `act_motivo_id` int(10) unsigned NOT NULL, `detalle` text, `detalle_tecnico` text, `hostname_id` int(10) unsigned NOT NULL, `hostname_nombre` char(50) NOT NULL, `es_SMOP` tinyint(1) NOT NULL, `url_SMOP` text, `es_tecnico` tinyint(1) NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1 COMMENT='Auditoria Actividad General'; I want to populate that audit table with a trigger but how can i send or fill the values for usr_digitador or ip_digitador if that values are on client side.? please help

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  • How can I protect this code from SQL Injection? A bit confused.

    - by Craig Whitley
    I've read various sources but I'm unsure how to implement them into my code. I was wondering if somebody could give me a quick hand with it? Once I've been shown how to do it once in my code I'll be able to pick it up I think! This is from an AJAX autocomplete I found on the net, although I saw something to do with it being vulnerable to SQL Injection due to the '%$queryString%' or something? Any help really appreciated! if ( isset( $_POST['queryString'] ) ) { $queryString = $_POST['queryString']; if ( strlen( $queryString ) > 0 ) { $query = "SELECT game_title, game_id FROM games WHERE game_title LIKE '%$queryString%' || alt LIKE '%$queryString%' LIMIT 10"; $result = mysql_query( $query, $db ) or die( "There is an error in database please contact [email protected]" ); while ( $row = mysql_fetch_array( $result ) ) { $game_id = $row['game_id']; echo '<li onClick="fill(\'' . $row['game_title'] . '\',' . $game_id . ');">' . $row['game_title'] . '</li>'; } } }

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  • Cast integer to real

    - by Dave Jarvis
    Question How do you cast an INTEGER value as a REAL value? Attempts CAST( Y.YEAR AS REAL), but that failed (the documentation indicates you cannot CAST or CONVERT values to REALs. Y.YEAR + 0.0, but that failed, too. Error Message Using udf_slope fails due to: Can't initialize function 'slope'; slope() requires a real as parameter 2 Code SELECT D.AMOUNT, Y.YEAR, slope(D.AMOUNT, Y.YEAR + 0.0) as SLOPE, intercept(D.AMOUNT, Y.YEAR + 0.0) as INTERCEPT FROM YEAR_REF Y, DAILY D Here, D.AMOUNT is a FLOAT and Y.YEAR is an INTEGER. Thank you!

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  • SQL joining 3 tables when 1 table is emty

    - by AdRock
    I am trying to write a query that connects 3 tables. The first table is info about each festival The second table is the number of votes for each festival The third table is reviews for each festival I want to join all 3 tables so i get all the feilds from table1, join table1 with table2 on the festivalid but i also need to count the number of records in table 3 that applys to each festival. The first 2 tables give me a result becuase they both have data in them but table 3 is empty becuase there are no reviews yet so adding that to my query fives me no results SELECT f.*, v.total, v.votes, v.festivalid, r.reviewcount as count FROM festivals f INNER JOIN vote v ON f.festivalid = v.festivalid INNER JOIN (SELECT festivalid, count(*) as reviewcount FROM reviews) GROUP BY festivalid) as r on r.festivalid = v.festivalid

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  • Rails Unit Testing with MyISAM Tables

    - by tadman
    I've got an application that requires the use of MyISAM on a few tables, but the rest are the traditional InnoDB type. The application itself is not concerned with transactions where it applies to these records, but performance is a concern. The Rails testing environment assumes the engine used is transactional, though, so when the test database is generated from the schema.rb it is imported with the same engine. Is it possible to over-ride this behaviour in a simple manner? I've resorted to an awful hack to ensure the tables are the correct type by appending this to test_helper.rb: (ActiveRecord::Base.connection.select_values("SHOW TABLES") - %w[ schema_info ]).each do |table_name| ActiveRecord::Base.connection.execute("ALTER TABLE `#{table_name}` ENGINE=InnoDB") end Is there a better way to make a MyISAM-backed model be testable?

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