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  • Multi choice form field in Django

    - by Dingo
    Hi! I'am developing application on app-engine-path. I would like to make form with multichoice (acceptably languages for user). Code look like this: Language settings: settings.LANGUAGES = ((u"cs", u"Ceština"), (u"en", u"English")) Form model: class UserForm(forms.ModelForm): first_name = forms.CharField(max_length=100) last_name = forms.CharField(max_length=100) languages = forms.MultipleChoiceField(widget=forms.CheckboxSelectMultiple, choices=settings.LANGUAGES) The form is rendered o.k. (all languages have checkbox. IDs, NAMEs is ok.) But if I save some languages for user, those languages don't check checkboxes. User model look like this class User(User): #... languages = db.StringListProperty() #... and view: def edit_profile(request): user = request.user if request.method == 'POST': form = UserForm(request.POST) if form.is_valid(): # ... else: form = UserForm(instance=user) data = {"user":user, "form": form} return render_to_response(request, 'user_profile/user_profile.html', data)

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  • How can I display multiple django modelformset forms in a grouped fieldsets?

    - by JT
    I have a problem with needing to provide multiple model backed forms on the same page. I understand how to do this with single forms, i.e. just create both the forms call them something different then use the appropriate names in the template. Now how exactly do you expand that solution to work with modelformsets? The wrinkle, of course, is that each 'form' must be rendered together in the appropriate fieldset. For example I want my template to produce something like this: <fieldset> <label for="id_base-0-desc">Home Base Description:</label> <input id="id_base-0-desc" type="text" name="base-0-desc" maxlength="100" /> <label for="id_likes-0-icecream">Want ice cream?</label> <input type="checkbox" name="likes-0-icecream" id="id_likes-0-icecream" /> </fieldset> <fieldset> <label for="id_base-1-desc">Home Base Description:</label> <input id="id_base-1-desc" type="text" name="base-1-desc" maxlength="100" /> <label for="id_likes-1-icecream">Want ice cream?</label> <input type="checkbox" name="likes-1-icecream" id="id_likes-1-icecream" /> </fieldset> I am using a loop like this to process the results (after form validation) base_models = base_formset.save(commit=False) like_models = like_formset.save(commit=False) for base_model, likes_model in map(None, base_models, likes_models): which works as I'd expect (I'm using map because the # of forms can be different). The problem is that I can't figure out a way to do the same thing with the templating engine. The system does work if I layout all the base models together then all the likes models after wards, but it doesn't meet the layout requirements. EDIT: Updated the problem statement to be more clear about what exactly I'm processing (I'm processing models not forms in the for loop)

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  • Beautiful Soup Unicode encode error

    - by iamrohitbanga
    I am trying the following code with a particular HTML file from BeautifulSoup import BeautifulSoup import re import codecs import sys f = open('test1.html') html = f.read() soup = BeautifulSoup(html) body = soup.body.contents para = soup.findAll('p') print str(para).encode('utf-8') I get the following error: UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 9: ordinal not in range(128) How do I debug this?

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  • How can I conditionally only log something if it's a certain Class?

    - by BryanWheelock
    Something like this: if self.class == "User": logging.debug("%s non_pks were found" % (str(len(non_pks))) ) In [2]: user = User.objects.get(pk=1) In [3]: user.class Out[3]: In [4]: if user.class == 'django.contrib.auth.models.User': print "yes" ...: In [5]: user.class == 'django.contrib.auth.models.User' Out[5]: False In [6]: user.class == 'User' Out[6]: False In [7]: user.class == "" Out[7]: False

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  • How do I require that an element has either one set of attributes or another in an XSD schema?

    - by Eli Courtwright
    I'm working with an XML document where a tag must either have one set of attributes or another. For example, it needs to either look like <tag foo="hello" bar="kitty" /> or <tag spam="goodbye" eggs="world" /> e.g. <root> <tag foo="hello" bar="kitty" /> <tag spam="goodbye" eggs="world" /> </root> So I have an XSD schema where I use the xs:choice element to choose between two different attribute groups: <xsi:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema" attributeFormDefault="unqualified" elementFormDefault="qualified"> <xs:element name="root"> <xs:complexType> <xs:sequence> <xs:element maxOccurs="unbounded" name="tag"> <xs:choice> <xs:complexType> <xs:attribute name="foo" type="xs:string" use="required" /> <xs:attribute name="bar" type="xs:string" use="required" /> </xs:complexType> <xs:complexType> <xs:attribute name="spam" type="xs:string" use="required" /> <xs:attribute name="eggs" type="xs:string" use="required" /> </xs:complexType> </xs:choice> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xsi:schema> However, when using lxml to attempt to load this schema, I get the following error: >>> from lxml import etree >>> etree.XMLSchema( etree.parse("schema_choice.xsd") ) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "xmlschema.pxi", line 85, in lxml.etree.XMLSchema.__init__ (src/lxml/lxml.etree.c:118685) lxml.etree.XMLSchemaParseError: Element '{http://www.w3.org/2001/XMLSchema}element': The content is not valid. Expected is (annotation?, ((simpleType | complexType)?, (unique | key | keyref)*))., line 7 Since the error is with the placement of my xs:choice element, I've tried putting it in different places, but no matter what I try, I can't seem to use it to define a tag to have either one set of attributes (foo and bar) or another (spam and eggs). Is this even possible? And if so, then what is the correct syntax?

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  • pythonic way to associate list elements with their indices

    - by Dragan Chupacabrovic
    Hello Everybody, I have a list of values and I want to put them in a dictionary that would map each value to it's index. I can do it this way: >>> t = (5,6,7) >>> d = dict(zip(t, range(len(t)))) >>> d {5: 0, 6: 1, 7: 2} this is not bad, but I'm looking for something more elegant. I've come across the following, but it does the opposite of what I need: >>> d = dict(enumerate(t)) >>> d {0: 5, 1: 6, 2: 7} Please share your solutions, Thank you

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  • registration 0.8 alpha activation problem

    - by craphunter
    Got the following error: Exception Type: TypeError at /accounts/account/activate/success/ Exception Value: activate() takes at least 2 non-keyword arguments (1 given) My view: def activate(request, backend, template_name='registration/activation_complete.html', success_url=None, extra_context=None, **kwargs): backend = get_backend(backend) account = backend.activate(request, **kwargs) if account: if success_url is None: to, args, kwargs = backend.post_activation_redirect(request, account) return redirect(to, *args, **kwargs) else: return redirect(success_url) if extra_context is None: extra_context = {} context = RequestContext(request) for key, value in extra_context.items(): context[key] = callable(value) and value() or value return render_to_response(template_name, kwargs, context_instance=context) My url: urlpatterns = patterns('', url(r'^activate/complete/$', direct_to_template, { 'template': 'registration/activation_complete.html' }, name='registration_activation_complete'), # Activation keys get matched by \w+ instead of the more specific # [a-fA-F0-9]{40} because a bad activation key should still get to the view; # that way it can return a sensible "invalid key" message instead of a # confusing 404. url(r'^activate/(?P<activation_key>\w+)/$', activate, { 'backend': 'registration.backends.default.DefaultBackend' }, name='registration_activate'), url(r'^register/$', register, { 'backend': 'registration.backends.default.DefaultBackend' }, name='registration_register'), url(r'^register/complete/$', direct_to_template, { 'template': 'registration/registration_complete.html' }, name='registration_complete'), url(r'^register/closed/$', direct_to_template, { 'template': 'registration/registration_closed.html' }, name='registration_disallowed'), (r'', include('registration.auth_urls')), url(r'^account/activate/(?P<activation_key>\w+)/$', 'registration.views.activate', {'success_url': 'account/activate/success/'}, name='registration_activate2'), url(r'^account/activate/success/$', direct_to_template, {'template': 'registration/activation_complete.html'}, name='registration_activation_complete'), ) What do I do wrong? Thanks!

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  • Django model manager didn't work with related object when I do aggregated query

    - by Satoru.Logic
    Hi, all. I'm having trouble doing an aggregation query on a many-to-many related field. Let's begin with my models: class SortedTagManager(models.Manager): use_for_related_fields = True def get_query_set(self): orig_query_set = super(SortedTagManager, self).get_query_set() # FIXME `used` is wrongly counted return orig_query_set.distinct().annotate( used=models.Count('users')).order_by('-used') class Tag(models.Model): content = models.CharField(max_length=32, unique=True) creator = models.ForeignKey(User, related_name='tags_i_created') users = models.ManyToManyField(User, through='TaggedNote', related_name='tags_i_used') objects_sorted_by_used = SortedTagManager() class TaggedNote(models.Model): """Association table of both (Tag , Note) and (Tag, User)""" note = models.ForeignKey(Note) # Note is what's tagged in my app tag = models.ForeignKey(Tag) tagged_by = models.ForeignKey(User) class Meta: unique_together = (('note', 'tag'),) However, the value of the aggregated field used is only correct when the model is queried directly: for t in Tag.objects.all(): print t.used # this works correctly for t in user.tags_i_used.all(): print t.used #prints n^2 when it should give n Would you please tell me what's wrong with it? Thanks in advance.

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  • Django models: Use multiple values as a key?

    - by Rosarch
    Here is a simple model: class TakingCourse(models.Model): course = models.ForeignKey(Course) term = models.ForeignKey(Term) Instead of Django creating a default primary key, I would like to use both course and term as the primary key - taken together, they uniquely identify a tuple. Is this allowed by Django? On a related note: I am trying to represent users taking courses in certain terms. Is there a better way to do this? class Course(models.Model): name = models.CharField(max_length=200) requiredFor = models.ManyToManyField(RequirementSubSet, blank=True) offeringSchool = models.ForeignKey(School) def __unicode__(self): return "%s at %s" % (self.name, self.offeringSchool) class MyUser(models.Model): user = models.ForeignKey(User, unique=True) takingReqSets = models.ManyToManyField(RequirementSet, blank=True) takingTerms = models.ManyToManyField(Term, blank=True) takingCourses = models.ManyToManyField(TakingCourse, blank=True) school = models.ForeignKey(School) class TakingCourse(models.Model): course = models.ForeignKey(Course) term = models.ForeignKey(Term) class Term(models.Model): school = models.ForeignKey(School) isPrimaryTerm = models.BooleanField()

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  • Sorting and indexing into a list in a Django template?

    - by slypete
    How can you perform complex sorting on an object before passing it to the template? For example, here is my view: @login_required def overview(request): physicians = PhysicianGroup.objects.get(pk=physician_group).physicians for physician in physicians.all(): physician.service_patients.order_by('bed__room__unit', 'bed__room__order', 'bed__order') return render_to_response('hospitalists/overview.html', RequestContext(request, {'physicians': physicians,})) The physicians object is not ordered correctly in the template. Why not? Additionally, how do you index into a list inside the template? For example, (this doesn't work): {% for note_type in note_types %} <div><h3>{{ note_type }}</h3> {% for notes in note_sets.index(parent.forloop.counter0) %} #only want to display the notes of this note_type! {% for note in notes %} <p>{{ note }}</p> {% endfor %} {% endfor %} </div> {% endfor %}

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  • RabbitMQ serializing messages from queue with multiple consumers

    - by Refefer
    Hi there, I'm having a problem where I have a queue set up in shared mode and multiple consumers bound to it. The issue is that it appears that rabbitmq is serializing the messages, that is, only one consumer at a time is able to run. I need this to be parallel, however, I can't seem to figure out how. Each consumer is running in its own process. There are plenty of messages in the queue. I'm using py-amqplib to interface with RabbitMQ. Any thoughts?

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  • In Django how display all of the values aftere the for loop is finished instead of displaying them one by one

    - by Igor
    Hello, In my django project in the view I call the last 6 values in the column and send them to the template. I then would like to pass into google charts api those 6 values and have a graph. At the moment for some reason I get 6 different graphs. {% for foodbag in foodbags %} <img src="http://chart.apis.google.com/chart?chxl=0:|0|1|2|3|4|5|6&chxr=2,0,0&chxs=0,1,676767,10.5,1,l,676767|2,676767,5.5,0,l,676767&chxt=x,y&chs=300x170&cht=bvg&chco=76A4FB&chd=t:{{foodbag.12}},0&chma=0,5|5,5&chdlp=t&chtt=Food+Bags"/> {% endfor %} I'm not sure how to replace string chd=t:{{foodbag.12}}, with the 6 values I am trying to extract from foodbags. I would really appreciate the help. Thank you

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  • Pylons/Routes Did url_for() change within templates?

    - by Charles Merram
    I'm getting an error: GenerationException: url_for could not generate URL. Called with args: () {} from this line of a mako template: <p>Your url is ${h.url_for()}</p> Over in my helpers.py, I do have: from routes import url_for Looking at the Routes-1.12.1-py2.6.egg/routes/util.py, I seem to go wrong about line it calls _screenargs(). This is simple functionality from the Pylons book. What silly thing am I doing wrong? Was there a new url_current()? Where?

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  • Absolute path of a file object

    - by Morgoth
    This has been discussed on StackOverflow before - I am trying to find a good way to find the absolute path of a file object, but I need it to be robust to os.chdir(), so cannot use f = file('test') os.path.abspath(f.name) Instead, I was wondering whether the following is a good solution - basically extending the file class so that on opening, the absolute path of the file is saved: class File(file): def __init__(self, filename, *args, **kwargs): self.abspath = os.path.abspath(filename) file.__init__(self, filename, *args, **kwargs) Then one can do f = File('test','rb') os.chdir('some_directory') f.abspath # absolute path can be accessed like this Are there any risks with doing this?

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  • Help me understand Inorder Traversal without using recursion

    - by vito
    I am able to understand preorder traversal without using recursion, but I'm having a hard time with inorder traversal. I just don't seem to get it, perhaps, because I haven't understood the inner working of recursion. This is what I've tried so far: def traverseInorder(node): lifo = Lifo() lifo.push(node) while True: if node is None: break if node.left is not None: lifo.push(node.left) node = node.left continue prev = node while True: if node is None: break print node.value prev = node node = lifo.pop() node = prev if node.right is not None: lifo.push(node.right) node = node.right else: break The inner while-loop just doesn't feel right. Also, some of the elements are getting printed twice; may be I can solve this by checking if that node has been printed before, but that requires another variable, which, again, doesn't feel right. Where am I going wrong? I haven't tried postorder traversal, but I guess it's similar and I will face the same conceptual blockage there, too. Thanks for your time! P.S.: Definitions of Lifo and Node: class Node: def __init__(self, value, left=None, right=None): self.value = value self.left = left self.right = right class Lifo: def __init__(self): self.lifo = () def push(self, data): self.lifo = (data, self.lifo) def pop(self): if len(self.lifo) == 0: return None ret, self.lifo = self.lifo return ret

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  • Find elements based on xsd type with lxml

    - by joet3ch
    I am trying to get a list of elements with a specific xsd type with lxml 2.x and I can't figure out how to traverse the xsd for specific types. Example of schema: <xsd:element name="ServerOwner" type="srvrs:string90" minOccurs="0"> <xsd:element name="HostName" type="srvrs:string35" minOccurs="0"> Example xml data: <srvrs:ServerOwner>John Doe</srvrs:ServerOwner> <srvrs:HostName>box01.example.com</srvrs:HostName> The ideal function would look like: elements = getElems(xml_doc, 'string90') def getElems(xml_doc, xsd_type): ** xpath or something to find the elements and build a dict return elements

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  • Using Multiple File Handles for Single File

    - by Ryan Rosario
    I have an O(n^2) operation that requires me to read line i from a file, and then compare line i to every line in the file. This repeats for all i. I wrote the following code to do this with 2 file handles, but it does not yield the result I am looking for. I imagine this is a simple error on my part. IN1 = open("myfile.dat","r") IN2 = open("myfile.dat","r") for line1 in IN1: for line2 in IN2: print line1.strip(), line2.strip() IN1.close() IN2.close() The result: Hello Hello Hello World Hello This Hello is Hello an Hello Example Hello of Hello Using Hello Two Hello File Hello Pointers Hello to Hello Read Hello One Hello File The output should contain 15^2 lines.

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  • wx read image from clipboard

    - by Moayyad Yaghi
    hello how can i read image from clipboard ? i was only able to raed text using wx.clipboard. but not images is it possible to read images with wx.clipboard? or there is another way? i use python2.5 and windows vita 64 bit thanks in advance

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  • PyGTK: Doubleclick on CellRenderer

    - by rami
    Hello! In my PyGTK application I currently use 'editable' to make cells editable. But since my cell contents sometimes are really really large I want to ask the user for changes in a new window when he doubleclicks on a cell. But I could not find out how to hook on double-clicks on specific cellrenderers - I don't want to edit the whole row and I also don't want to set this callback for the whole row, only for columns where too long content can occur. How can I do this with CellRendererText() or something similar. My currently cell-generating code is: cols[i] = gtk.TreeViewColumn(coltitle) cells[i] = gtk.CellRendererText() cols[i].pack_start(cells[i]) cols[i].add_attribute(cells[i], 'text', i) cols[i].set_sizing(gtk.TREE_VIEW_COLUMN_FIXED) cols[i].set_fixed_width(100) cells[i].set_property('editable', True) cells[i].connect('edited', self.edited, (i, ls)) cols[i].set_resizable(True) mytreeview.append_column(cols[i]) Thanks!

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  • GUI freezes when executing def function. Use threads?

    - by wtzolt
    Hi, I've made a small program which has 2 buttons and each does certain thing. Here's a simplified version of the code. Thing is it works fine except that the button freezes and stays in a clicked position and whole GUI freezes until the command is completed. As far as I know threads would be best to use in this situation, but I have no idea how to implement it in this example. I use glade and pygtk for gui. def do1: t = 2 #do something time.sleep(t) #do something time.sleep(t) def do2: t = 3 #do something time.sleep(t) #do something time.sleep(t) class we: wTree = None def __init__( self ): self.wTree = gtk.glade.XML( "ui.glade" ) dic = { "on_buttonSone" : self.sone, "on_buttonStwo" : self.stwo, } self.wTree.signal_autoconnect( dic ) gtk.main() def sone(self, widget): i = 0 while i < 3: t = 1 #do something i += 1 time.sleep(t) self.wTree.get_widget("entryResult").set_text("Done.") def stwo(self, widget): start = time.clock() array = ['A','B'] adict = {'A':do1,'B':do2} for f in array: adict[f]() end = time.clock() elapsed = end - start gg = round(elapsed,2) self.wTree.get_widget("entryResult").set_text(str(gg)) go=we()

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  • Datastore performance, my code or the datastore latency

    - by fredrik
    I had for the last month a bit of a problem with a quite basic datastore query. It involves 2 db.Models with one referring to the other with a db.ReferenceProperty. The problem is that according to the admin logs the request takes about 2-4 seconds to complete. I strip it down to a bare form and a list to display the results. The put works fine, but the get accumulates (in my opinion) way to much cpu time. #The get look like this: outputData['items'] = {} labelsData = Label.all() for label in labelsData: labelItem = label.item.name if labelItem not in outputData['items']: outputData['items'][labelItem] = { 'item' : labelItem, 'labels' : [] } outputData['items'][labelItem]['labels'].append(label.text) path = os.path.join(os.path.dirname(__file__), 'index.html') self.response.out.write(template.render(path, outputData)) #And the models: class Item(db.Model): name = db.StringProperty() class Label(db.Model): text = db.StringProperty() lang = db.StringProperty() item = db.ReferenceProperty(Item) I've tried to make it a number of different way ie. instead of ReferenceProperty storing all Label keys in the Item Model as a db.ListProperty. My test data is just 10 rows in Item and 40 in Label. So my questions: Is it a fools errand to try to optimize this since the high cpu usage is due to the problems with the datastore or have I just screwed up somewhere in the code? ..fredrik

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