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  • Amazon S3 - Storage Class and Server Side Encryption

    - by Steven
    Ahhh! I am using Amazon S3 for some low price storage to clear down out SAN. I created the bucket and created a root folder. I set the storage class to standard and server side encryption AES. I started a copy job to move the files, some files copied over and i checked the files: Reduced Redundancy Encryption set to none WTF? So i deleted all files and folders. I manuallyed created the folder structure and again set the storage class and encryption level. I coped some files and bamm, still showing (at a file level as Reduced and no encryption). So my question is this, is it really raid'd and encrypted just not showing it properly (as the root folder is, how can the file not be??) or (b) am i being a huge tool and missing something?

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  • Is this one network or two networks?

    - by colemik
    I have this simple question and really don't know the answer. Does the drawing below show one network or two networks? This is a question about the definition of a network from the OSI / TCP/IP model point of view: From one point of view, those are two L2 networks connected with a bridge. From another point of view, this is one L3 network, that can have a common L3 address space (like 10.1.1.0). PS If this question is too dumb, please move it to Superuser.

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  • Moving the home directory to a new drive

    - by Mellowcandle
    I have no more space left on my hard-drive. So I bought a new one and I would like this hard-drive to be the home folder. I thought of copying all the stuff I have on the home folder to the hard-drive partition. and creating a symbolic-link from ~ to there. The problem I have is that I can't really delete the home folder while I'm logged in as the current user. Is there a way to log out, and log in as root in Linux Mint? I want to be able to do this without a live-CD solution.

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  • Tar an gzip together, but the other way round?

    - by Boldewyn
    Gzipping a tar file as whole is drop dead easy and even implemented as option inside tar. So far, so good. However, from an archiver's point of view, it would be better to tar the gzipped single files. (The rationale behind it is, that data loss is minified, if there is a single corrupt gzipped file, than if your whole tarball is corrupted due to gzip or copy errors.) Has anyone experience with this? Are there drawbacks? Are there more solid/tested solutions for this than find folder -exec gzip '{}' \; tar cf folder.tar folder

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  • Windows 2003 Server - File Permissions

    - by nickstan
    I have a Windows 2003 web server with a tree of folders that contains around 100GB of small images. I need to update the permissions on this folder to add a new user with access. I tried to do this by right clicking on the folder and adding the new user but the process never completed. I left it running for around an hour but it started to heavily impact the peformance of the server. Is there any other way to change these folder permissions without affecting server performance? Many Thanks Nick

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  • [Silverlight 4] New PathListBox Control

    - by FernandoCortes
    One of the new features of Silverlight 4 is the new PathListBox Control. This control is basically a Listbox control witch takes the layout of a shape that you want, so we can represent our data as we want without limits.   So we are ready to open the new Microsoft Blend 4 Beta. First, we going to create a new Silverlight Data Driven Application (MVVM) project.   Open the main view (MainView.xaml), you can find it in Views folder, i look for the new control.   Once you add the PathListbox Control to the main layout of the MainView.xaml, we will add a Line Shape. Now, we are in the main step. Set the LayoutPaths property of the PathListbox control with the line shape that is just created.   The final step is set the ItemsSource property of the PathListbox control. We are going to use a mock object collection from the main view model. I have created the object collection on the main view model created by the Silverlight MVVM project template.   This is the result that we can improve with some animations. This a basic basic use of the PathListbox but using your imagination you can do very cool things.

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  • Shortcut with arguments in Debian

    - by Duncan
    I have a volume on a debian server which contains a large number of images at full resolution in various folders. What I'd like to do is have a separate sort of browse proxy folder which contains lower quality browse copies of these to enable users to access them for viewing over lower speed dial in accounts. I'd ideally like these to be created on the fly using ImageMagick so there isnt the need to store the large number of browse copies full time and worry about keeping them up to date etc The way I'd invisaged this happening is the browse proxy folder containing a duplicate file and folder structure but with symlinks pointing to a script to transform them with the file path as an argument. Except I know this isnt possible with symlinks so am wondering if there's another way of doing this on linux. On windows shortcuts can take arguments and I'm wondering how to do the same on a Linux platform? (or perhaps I'm going about this the wrong way?)

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  • Uninstalling hard deleted application from Windows7

    - by Gnanasuriyan A
    Unfortunately, I have hard deleted the microsoft sql server folder present in program files folder. So now I need to uninstall the MSSQL server from my machine. I have tried but I got an error something like "The source folder is missing". For resolving this issue, I have manually deleted the MS SQL services using "sc delete" command and I have deleted the MSSQL entry from regedit file also. But still MS SQL server entry available in "Programs and Features" list. Please guide me for solving this issue even I can't able to re install the MSSQL server once again. Thank you guys... Gnanasuriyan A.

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  • Ubuntu 12.04 "stuttering"

    - by Totte
    When I log in to the desktop Ubuntu seems to "stutter". Doing pretty much anything causes the cursor to freeze for a few seconds, and the rest of the screen updates something like every 15 seconds (during these 15 seconds I can still move the cursor). For example, opening the home folder I first see no effect, followed by a semi-transparent home folder, and finally the folder as it should be (this can take like 30 seconds); no animation, just three individual frames. Also, I sometimes don't see a window for a program, even though the program in question is supposed to be "up". Since this is my first experience of Linux, I confess I have no idea where to start - searching the web I only found problems with complete freezes/crashes requiring rebooting, as opposed to this "stuttering". I installed Ubuntu 12.04 32bit from a bootable USB stick a couple of days ago, right after a fresh Vista 32bit install. Thinking the stuttering might stop if I updated Ubuntu, I managed to install approx 270 updates through the Update Manager, but the stuttering was still there. Apart from the updates, I haven't installed any software other than what was included on the bootable USB stick. Vista and Ubuntu are on a single Crucial m4 SSD, in a dual-boot setup, with GRUB. CPU: Intel Core 2 Quad Q6600 GPU: Nvidia GeForce 8800 GTX (with the recommended proprietary drivers) RAM: 2GB DDR2

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  • Mobile (Client) to Amazon S3 (Server) - Architecture

    - by wasabii
    let's start off with the problem statement: My iOS application has a login form. When the user logs in, a call is made to my API and access granted or denied. If access was granted, I want the user to be able to upload pictures to his account and/or manage them. As storage I've picked Amazon S3, and I figured it'd be a good idea to have one bucket called "myappphotos" for instance, which contains lots of folders. The folder names are hashes of a user's email and a secret key. So, every user has his own, unique folder in my Amazon S3 bucket. Since I've just recently started working with AWS, here's my question: What are the best practices for setting up a system like this? I want the user to be able to upload pictures directly to Amazon S3, but of course I cannot hard-code the access key. So I need my API to somehow talk to Amazon and request an access token of sorts - only for the particular folder that belongs to the user I'm making the request for. Can anyone help me out and/or guide me to some sources where a similar problem was addressed? Don't think I'm the first one and the amazon documentation is so extensive that I don't really know where to start looking. Thanks a lot!

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  • I installed XAMPP on Ubuntu, and its running without any of its files.

    - by CDeanMartin
    I installed XAMPP on Ubuntu, and its running without any of its files. Well, not really, but it sure seems that way. I followed the directions on the Apache Friends website to the letter. XAMPP works fine, it's sample apps run like a charm. But I have no idea how it is running. The installation should have created an otf folder, or a XAMPP folder, or an htdoc file according to the tutorials. But there is no trace of any of these files or folders anywhere in the file browser. Are there any linux utilities as good as the Windows Explorer that can find my missing files? I particularly need to find the var/www folder to put my .php files in.

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  • Google Apps Premier - Viewing shared calendars in outlook

    - by aseaman
    We currently migrated from exchange to Google Apps Email and have been having issues when it comes to viewing shared calendars from within Outlook. Users are able to view other calendars from within the Google calendar tool but they cannot see these calendars in Outlook. It appears that users with the "Manage Changes" permission are able to view other calendars but they are also able to see any private appointments that a user has created as well. Is anyone aware of any 3rd party tools or workarounds that allow users to view shared calendars within Outlook without having to use the Google calendar tool?

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  • MWE function error message saying "use of undeclared indentifier" [migrated]

    - by nimbus
    I'm unsure about how to make MWE with Objective C, so if you need anything else let me know. I am trying running through a tutorial on building an iPhone app and have gotten stuck defining a function. I keep getting an error message saying "use of undeclared indentifier". However I believe I have initiated the function. In the view controller I have: if (scrollAmount > 0) { moveViewUp = YES; [scrollTheView:YES]; } else{ moveViewUp = NO; } with the function under it - (void)scrollTheView:(BOOL)movedUp { [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:0.3]; CGRect rect = self.view.frame; if (movedUp){ rect.origin.y -= scrollAmount; } else { rect.origin.y += scrollAmount; } self.view.frame = rect; [UIView commitAnimations]; } I have initiated the function in the header file (that I have imported). - (void)scrollTheView:(BOOL)movedUp;

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  • Entire folders deleted from My Documents periodically with remote logins

    - by darron
    I've got a customer who thinks our application is constantly deleting all it's data. It's really becoming a major problem for them. The problem is, there's no way it's us. They are losing not only our entire data folder (which we locate in the user's "My Documents" folder to make it easy to find), but some local settings files which are in entirely different places within the general user profile. It REALLY looks like the entire user is either getting reset, or is somehow synchronizing with a more... blank profile somewhere else. They're running this on some kind of virtualized Citrix guest OS. I see references to a "group policy folder redirection" that could do this... maybe roaming profiles? Any ideas? Help!

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  • Encrypt ONE system directory?

    - by acidzombie24
    I dont want to encrypt my whole hard drive. But one app i ENJOY using stores my password in a not so secure way in the AppData folder. I would like to encrypt the folder. One note is the folder is inside my user/name directory. Maybe that will help or hinder the solution. I am fine with encrypting all of AppData if necessary. However i prefer not to encrypt C:\Users\NAME\ since it is heavily used by many apps. C:\Users\NAME\AppData\Local\APPNAME

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  • VCS for single user using file sync service

    - by StackUnder
    I'm trying to setup a version control for my one man project. My project files are in sync thanks to live mesh (but I could be using dropbox for that matter), between my laptop, my home pc and my office pc. I'm now using Netbeans with local file history. Sometimes it helps to revert to a previous state of one file. But imagine a situation when multiple files have problems. Correct me if I'm wrong but I would have to go to every file and revert to previous "safe" state. I don't like this approach, so I'm considering using a version control between SVN and GIT. I have some previous experience with SVN (TortoiseSVN) and I know that I can create a file:// repo. So, what a want to do is setup a VCS inside my synced folder just to have the ability to "revert" to a previous version if something goes wrong. Since everything's been synced to all computers, I wouldn't ever need to run an update. The file tree organization would be the following: C:...\SyncedFolder\MyProject\ Inside MyProject folder are all the project files plus a directory that has SVN or GIT info of my project (the repo/master). What VCS is best for this situation: SVN or GIT? Does SVN need to store all files from HEAD revision, thus "duplicating" all my project inside my synced folder? Does GIT eliminates this problem? Is this the best approach?

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  • ORA-00900 Super Easy Fix (for some cases)

    - by Bunch
    Here is a really easy fix for some ORA-00900 errors. Well at least the one I saw the other day. This was something that I did not come across when searching either. I found lots of other ideas on what the problem might be but not the fix. Since I am fairly new to PL/SQL (TSQL only for a long time) this one stumped me for a while. Until I asked someone and they saw the error in about two seconds. When using the Command Window to add a view I was receiving an ORA-00900 error. So I checked that everything the view was referencing was there and that the permissions looked OK. The code for the view was fairly simple and it ran just fine in a regular SQL Window. It ended up that the Command Window did not like the space I had between the list of items in the select before the from. Bad: col1,col2,                               <--- does not like the empty linefrom tblSomething Good: col1,col2,from tblSomething I will just chalk that up to my familiarity with PL/SQL. Tags: PLSQL

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  • Someone to clarify /tags and /branches in SVN (subversion)?

    - by JoeM
    I created folders /tags, /branches and /trunk on SVN server. I put initial project file into /trunk. But other folders confuses me. What should I put in /tags? I see most people do not ever use this folder. Is this like a temp folder or so? As I understood, the purpose of branches is to host a different versions. So I will have /branches/myapp_v1.0.0, /branches/myapp_v1.0.1, etc. Right? If this is true, how do I "tell" subversion tool (tortoise on windows, svn on linux) to upload project files into such and such folder?

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  • Why is the word PERSONAL still relevant in the term PC? [closed]

    - by Bill
    I have spent half an hour trying to change an icon on my Win-7-64 machine (Why Can't I Change the Icon). One reasonable suggestion (reasonable in terms of having a solution, not reasonable in terms of having to jump through these hoops for such a basic requirement) was to delete the old icon from the %userprofile% \ Local Settings..., however when I click on this folder in Windows Explorer I am told the folder is not accessible - Access Denied. Well! It's my PERSONAL computer isn't it? Isn't that what PC stands for? It's MY computer - why can't I get access to that folder? It's about time we started calling these machines MCs (Microsoft Computer), or WCs (Windows Computer) - because they sure as hell aint PERSONAL damn computers!!!!

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  • Multi-level navigation controller on left-hand side of UISplitView with a small twist.

    - by user141146
    Hi. I'm trying make something similar to (but not exactly like) the email app found on the iPad. Specifically, I'd like to create a tab-based app, but each tab would present the user with a different UISplitView. Each UISplitView contains a Master and a Detail view (obviously). In each UISplitView I would like the Master to be a multi-level navigational controller where new UIViewControllers are pushed onto (or popped off of) the stack. This type of navigation within the UISplitView is where the application is similar to the native email app. To the best of my knowledge, the only place that has described a decent "splitviewcontroller inside of a uitabbarcontroller" is here: http://stackoverflow.com/questions/2475139/uisplitviewcontroller-in-a-tabbar-uitabbarcontroller and I've tried to follow the accepted answer. The accepted solution seems to work for me (i.e., I get a tab-bar controller that allows me to switch between different UISplitViews). The problem is that I don't know how to make the left-hand side of the UISplitView to be a multi-level navigation controller. Here is the code I used within my app delegate to create the initial "split view 'inside' of a tab bar controller" (it's pretty much as suggested in the aforementioned link). - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { NSMutableArray *tabArray = [NSMutableArray array]; NSMutableArray *array = [NSMutableArray array]; UISplitViewController *splitViewController = [[UISplitViewController alloc] init]; MainViewController *viewCont = [[MainViewController alloc] initWithNibName:@"MainViewController" bundle:nil]; [array addObject:viewCont]; [viewCont release]; viewCont = [[DetailViewController alloc] initWithNibName:@"DetailViewController" bundle:nil]; [array addObject:viewCont]; [viewCont release]; [splitViewController setViewControllers:array]; [tabArray addObject:splitViewController]; [splitViewController release]; array = [NSMutableArray array]; splitViewController = [[UISplitViewController alloc] init]; viewCont = [[Master2 alloc] initWithNibName:@"Master2" bundle:nil]; [array addObject:viewCont]; [viewCont release]; viewCont = [[Slave2 alloc] initWithNibName:@"Slave2" bundle:nil]; [array addObject:viewCont]; [viewCont release]; [splitViewController setViewControllers:array]; [tabArray addObject:splitViewController]; [splitViewController release]; // Add the tab bar controller's current view as a subview of the window [tabBarController setViewControllers:tabArray]; [window addSubview:tabBarController.view]; [window makeKeyAndVisible]; return YES; } the class MainViewController is a UIViewController that contains the following method: - (IBAction)push_me:(id)sender { M2 *m2 = [[[M2 alloc] initWithNibName:@"M2" bundle:nil] autorelease]; [self.navigationController pushViewController:m2 animated:YES]; } this method is attached (via interface builder) to a UIButton found within MainViewController.xib Obviously, the method above (push_me) is supposed to create a second UIViewController (called m2) and push m2 into view on the left-side of the split-view when the UIButton is pressed. And yet it does nothing when the button is pressed (even though I can tell that the method is called). Thoughts on where I'm going wrong? TIA!

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  • ASP.NET MVC : AJAX ActionLink - Persist Data

    - by Mio
    Hi guys, I'm really new at this and I was searching the web for an answer to my question and I couldn't find it, so here I am posting my question :) I'm trying to create a new record in my table Facility. For my goreign keys I'm displaying the choices in tables instead of a dropdowns. When the user clicks on the select link which is an Ajax.ActionLink(), I wanna retrieve the right record from the DB and set the foreign key of my object Facility to the one slected and replace the Div by a new Partial View. The problem is when I try to submit the form, the Facility object doesnt seem to have the foreign key that I've just set in my ajax fuction in my controller. And if the user has enter some data in the other fields of the create form, I don't them to lose what they already entered. Here's my code. Model only contains a Facility. public ActionResult Create() { Model.Facility = new Facility(); return View(Model); } This is part of my Create View <div id="FacilityTypePartialView"> <% Html.RenderPartial("FacilityType"); %> </div> This is my Partial View FacilityType <% if (Model.IsNewFacility()) { %> <p> Id: <%= Html.Encode(Model.Facility.FacilityType.FId)%> </p> <p> Type: <%= Html.Encode(Model.Facility.FacilityType.FType)%> </p> <p> Description: <%= Html.Encode(Model.Facility.FacilityType.FDescription) %> </p> <% } %> <p> <%= Html.ActionLink("Manage Facility Type", "Index","FacilityType") %> </p> <table id="FacilityTypesList"> <tr> <th> Select </th> <th> FId </th> <th> FType </th> <th> FDescription </th> </tr> <% foreach (var item in Model.GetFacilityTypes()) { %> <tr> <td> <%=Ajax.ActionLink("Select", "FacilityTypeSelect", new { id = item.FId}, new AjaxOptions { UpdateTargetId = "FacilityTypePartialView" })%> </td> <td> <%= Html.Encode(item.FId) %> </td> <td> <%= Html.Encode(item.FType) %> </td> <td> <%= Html.Encode(item.FDescription) %> </td> </tr> <% } %> </table> Here's y Ajax Funcion public PartialViewResult FacilityTypeSelect(int id) { Facility facility = new Facility(); facility.FacilityType = _repository.GetFacilityType(id); Model.Facility = facility; if (this.Request.IsAjaxRequest() == false) { return PartialView("FacilityType/FacilityType", Model); } else { return PartialView("FacilityType/FacilityTypeSelected", Model); } } Finally, my Post method [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create( Facility facility) { Model.Facility = facility; if (ModelState.IsValid) { try { _repository.AddEntity(facility); _repository.Save(); return RedirectToAction("Details", new { id = facility.Id }); } catch { } } return View("Create", Model); } My Faciliy object coming from the View have the Facility.FacilityType set to nothing.

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  • Android - Custom Adapter Problem

    - by Ryan
    Hello, I seem to be having a problem with my Custom Adapter view. When I display the list, it only displays a white screen. Here is how it works: 1.) I send a JSON request 2.) populate the ArrayList with the returned results 3.) create a custom adapter 4.) then bind the adapter. Here is steps 2-4 private void updateUI() { ListView myList = (ListView) findViewById(android.R.id.list); itemList = new ArrayList(); Iterator it = data.entrySet().iterator(); while (it.hasNext()) { //Get the key name and value for it Map.Entry pair = (Map.Entry)it.next(); String keyName = (String) pair.getKey(); String value = pair.getValue().toString(); if (value != null) { ListItem li = new ListItem(keyName, value, false); itemList.add(li); } } CustomAdapter mAdapter = new CustomAdapter( mContext, itemList); myList.setAdapter(mAdapter); //Bind the adapter to the list //Tell the dialog it's cool now. dismissDialog(0); //Show next screen flipper.setInAnimation(inFromRightAnimation()); flipper.setOutAnimation(outToRightAnimation()); flipper.showNext(); } And here is my CustomAdapter class: import java.util.List; import android.R.color; import android.content.Context; import android.view.View; import android.view.ViewGroup; import android.widget.BaseAdapter; import android.widget.ImageView; import android.widget.RelativeLayout; import android.widget.TextView; class MyAdapterView extends RelativeLayout { public MyAdapterView(Context c, ListItem li) { super( c ); RelativeLayout rL = new RelativeLayout(c); RelativeLayout.LayoutParams containerParams = new RelativeLayout.LayoutParams( ViewGroup.LayoutParams.FILL_PARENT, ViewGroup.LayoutParams.FILL_PARENT); rL.setLayoutParams(containerParams); rL.setBackgroundColor(color.white); ImageView img = new ImageView (c); img.setImageResource(li.getImage()); img.setPadding(5, 5, 10, 5); rL.addView(img, 48, 48); TextView top = new TextView(c); top.setText(li.getTopText()); top.setTextColor(color.black); top.setTextSize(20); top.setPadding(0, 20, 0, 0); rL.addView(top,ViewGroup.LayoutParams.FILL_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT); TextView bot = new TextView( c ); bot.setText(li.getBottomText()); bot.setTextColor(color.black); bot.setTextSize(12); bot.setPadding(0, 0, 0, 10); bot.setAutoLinkMask(1); rL.addView(bot,ViewGroup.LayoutParams.FILL_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT); } } public class CustomAdapter extends BaseAdapter { private Context context; private List itemList; public CustomAdapter(Context c, List itemL ) { this.context = c; this.itemList = itemL; } public int getCount() { return itemList.size(); } public Object getItem(int position) { return itemList.get(position); } public long getItemId(int position) { return position; } @Override public View getView(int position, View convertView, ViewGroup parent) { ListItem li = itemList.get(position); return new MyAdapterView(this.context, li); } } Does anyone have any idea why this displays a white screen upon completion?? Thanks in advance!

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  • Android ListActivity OnListItemClick error with Webviews

    - by Tista
    I've been figuring how to popup a webview all day when a row in my ListActivity is clicked. I can't even show a Toast when it's clicked. Need help I'm still new with Android, a web developer trying to learn. Thanks before. package com.mf.ar; import org.json.JSONArray; import org.json.JSONException; import org.json.JSONObject; import android.app.Activity; import android.app.AlertDialog; import android.app.ListActivity; import android.os.Bundle; import android.util.Log; import android.view.View; import android.view.Window; import android.webkit.WebChromeClient; import android.webkit.WebView; import android.webkit.WebViewClient; import android.widget.ArrayAdapter; import android.widget.Toast; public class ListViewer extends ListActivity { private String mJSON; private String[] listRows; private String[] listRowsURI; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //setContentView(R.layout.listview); Bundle the = getIntent().getExtras(); this.mJSON = the.getString("JSON"); Log.i("ListViewIntentJSON", this.mJSON); try { JSONObject UrbJSON = new JSONObject(mJSON); JSONObject UrbQuery = UrbJSON.getJSONObject("query"); int rows = UrbQuery.getInt("row"); Log.i("UrbRows", String.format("%d",rows)); JSONArray resultArray = UrbJSON.getJSONArray("result"); this.listRows = new String[rows]; for(int i=0; i<rows; i++) { this.listRows[i] = resultArray.getJSONObject(i). getString("business_name").toString(); } this.listRowsURI = new String[rows]; for(int i=0; i<rows; i++) { this.listRowsURI[i] = resultArray.getJSONObject(i). getString("business_uri_mobile").toString(); } } catch(JSONException e) { e.printStackTrace(); } this.setListAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, ListViewer.this.listRows)); } @Override protected void onListItemClick(android.widget.ListView l, View v, int position, long id) { super.onListItemClick(l, v, position, id); String theURI = ListViewer.this.listRowsURI[position].toString(); /*String theURI = ListViewer.this.listRowsURI[position].toString(); //String theURI = "http://www.mediafusion.web.id"; WebView webview = new WebView(this); //setContentView(webview); //addContentView(webview, null); webview.getSettings().setJavaScriptEnabled(true); getWindow().requestFeature(Window.FEATURE_PROGRESS); final Activity activity = this; webview.setWebChromeClient(new WebChromeClient() { public void onProgressChanged(WebView view, int progress) { // Activities and WebViews measure progress with different scales. // The progress meter will automatically disappear when we reach 100% activity.setProgress(progress * 1000); } }); webview.setWebViewClient(new WebViewClient() { public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) { Toast.makeText(activity, "Oh no! " + description, Toast.LENGTH_SHORT).show(); } }); webview.loadUrl(theURI);*/ Toast.makeText(ListViewer.this.getApplicationContext(), theURI, Toast.LENGTH_SHORT); } }

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  • How to "DRY up" C# attributes in Models and ViewModels?

    - by DanM
    This question was inspired by my struggles with ASP.NET MVC, but I think it applies to other situations as well. Let's say I have an ORM-generated Model and two ViewModels (one for a "details" view and one for an "edit" view): Model public class FooModel // ORM generated { public int Id { get; set; } public string FirstName { get; set; } public string LastName { get; set; } public string EmailAddress { get; set; } public int Age { get; set; } public int CategoryId { get; set; } } Display ViewModel public class FooDisplayViewModel // use for "details" view { [DisplayName("ID Number")] public int Id { get; set; } [DisplayName("First Name")] public string FirstName { get; set; } [DisplayName("Last Name")] public string LastName { get; set; } [DisplayName("Email Address")] [DataType("EmailAddress")] public string EmailAddress { get; set; } public int Age { get; set; } [DisplayName("Category")] public string CategoryName { get; set; } } Edit ViewModel public class FooEditViewModel // use for "edit" view { [DisplayName("First Name")] // not DRY public string FirstName { get; set; } [DisplayName("Last Name")] // not DRY public string LastName { get; set; } [DisplayName("Email Address")] // not DRY [DataType("EmailAddress")] // not DRY public string EmailAddress { get; set; } public int Age { get; set; } [DisplayName("Category")] // not DRY public SelectList Categories { get; set; } } Note that the attributes on the ViewModels are not DRY--a lot of information is repeated. Now imagine this scenario multiplied by 10 or 100, and you can see that it can quickly become quite tedious and error prone to ensure consistency across ViewModels (and therefore across Views). How can I "DRY up" this code? Before you answer, "Just put all the attributes on FooModel," I've tried that, but it didn't work because I need to keep my ViewModels "flat". In other words, I can't just compose each ViewModel with a Model--I need my ViewModel to have only the properties (and attributes) that should be consumed by the View, and the View can't burrow into sub-properties to get at the values. Update LukLed's answer suggests using inheritance. This definitely reduces the amount of non-DRY code, but it doesn't eliminate it. Note that, in my example above, the DisplayName attribute for the Category property would need to be written twice because the data type of the property is different between the display and edit ViewModels. This isn't going to be a big deal on a small scale, but as the size and complexity of a project scales up (imagine a lot more properties, more attributes per property, more views per model), there is still the potentially for "repeating yourself" a fair amount. Perhaps I'm taking DRY too far here, but I'd still rather have all my "friendly names", data types, validation rules, etc. typed out only once.

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  • ZendX_JQuery dialogContainer usage

    - by Kalle Johansson
    Hi ! I'm aming to make use of the ZendX_JQuery dialogContainer view helper, in order to produce a modal window, were users can input specified information(for example send a message). I'm trying to use the dialogContainer view helper in this fashion. First of, include the ZendX library in the applications library folder. Secondly, include the following row in the initViewHelper method within the Bootstrap.php file "$view-addHelperPath('ZendX/JQuery/View/Helper/', 'ZendX_JQuery_View_Helper');" third, adding the following conditional enabling of js in the layout.phtml "<?php if($this->jQuery()->isEnabled()){ $this->jQuery()->setLocalPath($this->baseUrl() .'/js/jquery/js/jquery-1.4.2.min.js') ->setUiLocalPath($this->baseUrl() .'/js/jquery/js/jquery-ui-1.8.custom.min.js') ->addStylesheet($this->baseUrl() .'/js/jquery/css/ui-lightness/jquery-ui-1.8.custom.css'); echo $this->jQuery(); } ?>" fourth, creating my Application_Form_JQueryForm extending ZendX_JQuery_Form "<?php class Application_Form_JQueryForm extends ZendX_JQuery_Form { private $form; public function init() { $this->form = $this->setAction(Zend_Controller_Front::getInstance()->getBaseUrl() . '/index/index') ->setMethod('post'); $this->form->setDecorators(array( 'FormElements', 'Form', array ('DialogContainer', array( 'id' => 'tabContainer', 'style' => 'width: 600px;', 'title' => 'Send a private message to Kalle', 'JQueryParams' => array( 'tabPosition' => 'top', ), )), )); $topic = new Zend_Form_Element_Text('topic'); $topic->setValue('topic') ->setRequired(true) ->setValidators(array('validators' => array( 'validator' => 'StringLength', 'options' => array(1,15) ))) ->setDecorators(array( 'ViewHelper', 'Description', 'Errors', array('HtmlTag', array('tag' => 'dl')))); $textarea = new Zend_Form_Element_Textarea('textarea'); $textarea->setValue('post a comment') ->setAttribs(array( 'rows' => 4, 'cols' => 20 )) ->setRequired(true) ->setValidators(array('validators' => array( 'validator' => 'StringLength', 'options' => array(1,15) ))) ->setDecorators(array( 'ViewHelper', 'Description', 'Errors', array('HtmlTag', array('tag' => 'dl')))); $submit = new Zend_Form_Element_Submit('submit'); $submit->setLabel('Send your comment') ->setDecorators(array( 'ViewHelper', 'Description', 'Errors', array('Description', array('escape' => false, 'tag' => 'span')), array('HtmlTag', array('tag' => 'dl')))) ->setDescription('or <a href="/index/index/send/false">Cancel</a>'); $this->form->addElements(array($topic, $textarea, $submit)); } }" This form is then instanciated in the controllers action method, and called in the view. And so to the problem of mine, no matter what i try, in order to for instance set, the width of the dialogContainer or any other parameter (color, css, height, so on and so forth), this being in the JQueryForm's setDecorator part for the form, i can't seem to get any change whatsoever in the resulting modal when called in the view, any help in the proper direction would be greatly appreciated Thanks in advance, Kalle Johansson

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