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  • Having a number in

    - by Wiika
    Can someone give me a query that will return as a result rows ID 1 & 3? ID Name Hidden 1 Mika 1,4,2 2 Loca 0 3 Nosta 4 4 Like 2 Something like this SELECT * FROM table WHERE Hidden HAVING(4)

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  • getting notice like undefined index

    - by user2533308
    $result = mysql_query("SELECT * FROM customers WHERE loginid='$_POST[login]' AND accpassword='$_POST[password]'"); if(mysql_num_rows($result) == 1) { while($recarr = mysql_fetch_array($result)) { $_SESSION[customerid] = $recarr[customerid]; $_SESSION[ifsccode] = $recarr[ifsccode]; $_SESSION[customername] = $recarr[firstname]. " ". $recarr[lastname]; $_SESSION[loginid] = $recarr[loginid]; $_SESSION[accstatus] = $recarr[accstatus]; $_SESSION[accopendate] = $recarr[accopendate]; $_SESSION[lastlogin] = $recarr[lastlogin]; } $_SESSION["loginid"] =$_POST["login"]; header("Location: accountalerts.php"); } else { $logininfo = "Invalid Username or password entered"; } Notice: Undefined index:login and Notice: Undefined index:password try to help me out getting error message in second line

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  • PHP Longtext to display like the user wrote it

    - by yanike
    I need to know how to display information put in a database longtext field the way it was written. Like if a user writes in this below: My life is full of love I fly like wedding doves I blow passed stop signs That intersect with hate lines - I know what I am I know who I be If you can't accept me Then don't friend me I want it to display the text from the database just like the user wrote it in the textarea instead of it displaying in one like this: My life is full of love I fly like wedding doves I blow passed stop signs That intersect with hate lines I know what I am I know who I be If you can't accept me Then don't friend me How can I could it in PHP to display the information properly using PHP?

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  • Dummies guide to locking in innodb

    - by ming yeow
    The typical documentation on locking in innodb is way too confusing. I think it will be of great value to have a "dummies guide to innodb locking" I will start, and I will gather all responses as a wiki: The column needs to be indexed before row level locking applies. EXAMPLE: delete row where column1=10; will lock up the table unless column1 is indexed

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  • Alter Dilemma : How to use to set Primary and other attributes.

    - by Rachel
    I have following table in database AND I need to alter it to below mentioned schema. Initially I was drop the current database and creating new one using the create but I am not supposed to do that and use ALTER but am not sure as to how can I use ALTER to add primary key and other constraints. Any Suggestions !!! Code Current: CREATE TABLE `details` ( `KEY` varchar(255) NOT NULL, `ID` bigint(20) NOT NULL, `CODE` varchar(255) NOT NULL, `C_ID` bigint(20) NOT NULL, `C_CODE` varchar(64) NOT NULL, `CCODE` varchar(255) NOT NULL, `TCODE` varchar(255) NOT NULL, `LCODE` varchar(255) NOT NULL, `CAMCODE` varchar(255) NOT NULL, `OFCODE` varchar(255) NOT NULL, `OFNAME` varchar(255) NOT NULL, `PRIORITY` bigint(20) NOT NULL, `STDATE` datetime NOT NULL, `ENDATE` datetime NOT NULL, `INT` varchar(255) NOT NULL, `PHONE` varchar(255) NOT NULL, `TV` varchar(255) NOT NULL, `MTV` varchar(255) NOT NULL, `TYPE` varchar(255) NOT NULL, `CREATED` datetime NOT NULL, `MAIN` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Desired: CREATE TABLE `details` ( `id` bigint(20) NOT NULL, `code` varchar(255) NOT NULL, `cid` bigint(20) NOT NULL, `ccode` varchar(64) NOT NULL, `c_code` varchar(255) NOT NULL, `tcode` varchar(255) NOT NULL, `lcode` varchar(255) NOT NULL, `camcode` varchar(255) NOT NULL, `ofcode` varchar(255) NOT NULL, `ofname` varchar(255) NOT NULL, `priority` bigint(20) NOT NULL, `stdate` datetime NOT NULL, `enddate` datetime NOT NULL, `list` varchar(255) NOT NULL, `name` varchar(255) NOT NULL, `created` datetime NOT NULL, `date` datetime NOT NULL, `ofshn` int(20) NOT NULL, `ofcl` int(20) NOT NULL, `ofr` int(20) NOT NULL, PRIMARY KEY (`code`,`ccode`,`list`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Thanks !!!

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  • How do you sort php and sql arrays?

    - by Jon
    How can I sort this array by city or by id in descending order? if ($num > 0 ) { $i=0; while ($i < $num) { $city = mysql_result($result,$i,"city"); $state = mysql_result($result,$i,"state"); $id = mysql_result($result,$i,"id"); echo "$city"; echo "$state"; ++$i; } } else { echo "No results."; } ?>

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  • mysqldump on remote server

    - by Hulk
    If there are two machines client and server .From client how to do a mysqldump to the server such that the dump is avaliable on the client and not stored in the server Thanks..

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  • How to map to tables in database PHPMyAdmin

    - by thegrede
    I'm working now on a project which a user can save their own coupon codes on the websites, so I want to know what is the best to do that, Lets say, I have 1 table with the users, like this, userId | firstName | lastName | codeId and then I have a table of the coupon codes, like this, codeId | codeNumber So what I can do is to connect the codeId to userId so when someone saves the coupons goes the codeId from the coupon table into the codeId of the users table, But now what if when a user have multiple coupons what do I do it should be connected to the user? I have 2 options what to do, Option 1, Saving the codeId from coupons table into the codeId of users table like 1,2,3,4,5, Option 2 To make a new row into the coupons table and to connect the user to the code with adding another field in the coupon table userId and putting into it the user which has added the coupon his userId of the users table, So what of the two options is better to do? Thanks you guys.

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  • SQL Injection When Using MySQLi Prepared Statements

    - by Sev
    If all that is used to do any and all database queries is MySQLi prepared statements with bound parameters in a web-app, is sql injection still possible? Notes I know that there are other forms of attack other than sql-injection, but my question is specific to sql-injection attacks on that particular web application only.

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  • Find the % character in a LIKE query

    - by Jensen
    Hi, I've an SQL database and I would like to do a query who show all the datas containing the sign "%". Normally, to find a character (for example: "z") in a database I use a query like this : mysql_query("SELECT * FROM mytable WHERE tag LIKE '%z%'"); But here, I want to found the % character, but in SQL it's a joker so when I write: mysql_query("SELECT * FROM mytable WHERE tag LIKE '%%%'"); It show me all my datas. So how to found the % character in my SQL datas ? Thanks

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  • Search SQL Question Between Related Two Tables

    - by mTuran
    Hi, I am writing some kind of search engine for my web application and i have a problem. I have 2 tables first of is projects table: PROJECTS TABLE id int(11) NO PRI NULL auto_increment employer_id int(11) NO MUL NULL project_title varchar(100) NO MUL NULL project_description text NO NULL project_budget int(11) NO NULL project_allowedtime int(11) NO NULL project_deadline datetime NO NULL total_bids int(11) NO NULL average_bid int(11) NO NULL created datetime NO MUL NULL active tinyint(1) NO MUL NULL PROJECTS_SKILLS TABLE project_id int(11) NO MUL NULL skill_id int(11) NO MUL NULL For example: I want ask this query to database: 1-) Skills are 5 and 7. 2-) Order results by created 3-) project title contains "php" word. 4-) Returned rows should contain projects.* columuns. 5-) Projects should be distinct(i don't want same projects in return of query). Please write sql query that ensure these conditions. Thank You.

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  • about null values!

    - by user329820
    Hi I have a question that if we declare a variable and then do not set it explicitly to null value then it would be null outomatically ,i mean that the below code will return true or false ? thanks DECLARE @val CHAR(4) If @val = NULL

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  • PHP - How to get, and display the biggest values from a database?

    - by Dodi300
    Hello. Can anyone tell me how to get and display the biggest values from a database? I have multiple values in my database with the heading "gmd", but how would I get only the first 3 biggest ones to be displayed? How would I do it in this example: $query = "SELECT gmd FROM account"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { } Thanks.

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  • How Do I See The Final Text Of A Query Resulting From A Call To mysqli->prepare?

    - by Joshua
    After code like this: $stmt = $mysqli->prepare("SELECT District FROM City WHERE Name=?")) { $stmt->bind_param("s", $city); $stmt->execute(); $stmt->bind_result($district); $stmt->fetch(); printf("%s is in district %s\n", $city, $district); How Do I See The Actual SQL Statement That Was Executed? (It Should Look Something Like "SELECT District FROM City WHERE Name='Simi Valley';") I already realize that in this simplistic case it would be very easy to simply reconstruct the query... but how can I access it in a general way that will work for very complicated prepared statements, and cases where I don't necessarily already understand the intended structure of the query, etc. Isn't there some function or method that can be called on the statement object that will return the actual text of the SQL query, after binding?

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  • counting number of new entries in guest book

    - by Lucka
    I want to display the number of new(unseen) guest entries in the guest book of a user. I was thinking to count it so that, total number of entries in guestbook minus entries in guestbook at time of last login. However, I think that is not a good approach, because if the user logs in but does not go to his guestbook, in that case, the entries should be still "new", also if some new entry is posted in the user while he is online, it does not work in that case too. Any suggested please?

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  • How can I get the rank of rows relative to total number of rows based on a field?

    - by Arms
    I have a scores table that has two fields: user_id score I'm fetching specific rows that match a list of user_id's. How can I determine a rank for each row relative to the total number of rows, based on score? The rows in the result set are not necessarily sequential (the scores will vary widely from one row to the next). I'm not sure if this matters, but user_id is a unique field. Edit @Greelmo I'm already ordering the rows. If I fetch 15 rows, I don't want the rank to be 1-15. I need it to be the position of that row compared against the entire table by the score property. So if I have 200 rows, one row's rank may be 3 and another may be 179 (these are arbitrary #'s for example only). Edit 2 I'm having some luck with this query, but I actually want to avoid ties SELECT s.score , s.created_at , u.name , u.location , u.icon_id , u.photo , (SELECT COUNT(*) + 1 FROM scores WHERE score > s.score) AS rank FROM scores s LEFT JOIN users u ON u.uID = s.user_id ORDER BY s.score DESC , s.created_at DESC LIMIT 15 If two or more rows have the same score, I want the latest one (or earliest - I don't care) to be ranked higher. I tried modifying the subquery with AND id > s.id but that ended up giving me an unexpected result set and different ties.

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  • Replacement for PEAR: MDB2 on PHP 5.3

    - by mattweg
    I've been using pear packages in php for years. I'm in the process of upgrading/moving a sites that uses the MDB2 pear package and it has not been updated for PHP 5.3.X. In 5.3, MDB2 is returning those new annoying errors. Unknown: Assigning the return value of new by reference is deprecated in /usr/local/lib/php/MDB2.php on line 390 I know I can change my error reporting settings to get rid of them, but I'd rather not make any exceptions. Anyway, Is anyone else using MDB2 these days and have a solution? Are there similar database packages you recommend? Thanks. -Matt

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  • counting twice in a query, once using restrictions

    - by Andrew Heath
    Given the following tables: Table1 [class] [child] math boy1 math boy2 math boy3 art boy1 Table2 [child] [glasses] boy1 yes boy2 yes boy3 no If I want to query for number of children per class, I'd do this: SELECT class, COUNT(child) FROM Table1 GROUP BY class and if I wanted to query for number of children per class wearing glasses, I'd do this: SELECT Table1.class, COUNT(table1.child) FROM Table1 LEFT JOIN Table2 ON Table1.child=Table2.child WHERE Table2.glasses='yes' GROUP BY Table1.class but what I really want to do is: SELECT class, COUNT(child), COUNT(child wearing glasses) and frankly I have no idea how to do that in only one query. help?

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  • Best PHP timezone list

    - by jimbo
    I have looked over the PHP list of supported timezones, but the whole list is a little long to include in a drop-down menu, for the user to select his or her timezone. Is there a list with the main city/area on that can be used? My geography is terrible and add that to not knowing all the area and which timezone they fall into it could be a long day to construct the list my self! Thanks in advance

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  • Remove redundant SQL code

    - by Dave Jarvis
    Code The following code calculates the slope and intercept for a linear regression against a slathering of data. It then applies the equation y = mx + b against the same result set to calculate the value of the regression line for each row. Can the two separate sub-selects be joined so that the data and its slope/intercept are calculated without executing the data gathering part of the query twice? SELECT AVG(D.AMOUNT) as AMOUNT, Y.YEAR * ymxb.SLOPE + ymxb.INTERCEPT as REGRESSION_LINE, Y.YEAR as YEAR, MAKEDATE(Y.YEAR,1) as AMOUNT_DATE FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D, (SELECT ((avg(t.AMOUNT * t.YEAR)) - avg(t.AMOUNT) * avg(t.YEAR)) / (stddev( t.AMOUNT ) * stddev( t.YEAR )) as CORRELATION, ((sum(t.YEAR) * sum(t.AMOUNT)) - (count(1) * sum(t.YEAR * t.AMOUNT))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as SLOPE, ((sum( t.YEAR ) * sum( t.YEAR * t.AMOUNT )) - (sum( t.AMOUNT ) * sum(power(t.YEAR, 2)))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as INTERCEPT FROM ( SELECT AVG(D.AMOUNT) as AMOUNT, Y.YEAR as YEAR, MAKEDATE(Y.YEAR,1) as AMOUNT_DATE FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D WHERE $X{ IN, C.ID, CityCode } AND SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) < $P{Radius} AND S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND Y.YEAR BETWEEN 1900 AND 2009 AND M.YEAR_REF_ID = Y.ID AND M.CATEGORY_ID = $P{CategoryCode} AND M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR ) t ) ymxb WHERE $X{ IN, C.ID, CityCode } AND SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) < $P{Radius} AND S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND Y.YEAR BETWEEN 1900 AND 2009 AND M.YEAR_REF_ID = Y.ID AND M.CATEGORY_ID = $P{CategoryCode} AND M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR Question How do I execute the duplicate bits only once per query, instead of twice? The duplicate bit is the WHERE clause: $X{ IN, C.ID, CityCode } AND SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) < $P{Radius} AND S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND Y.YEAR BETWEEN 1900 AND 2009 AND M.YEAR_REF_ID = Y.ID AND M.CATEGORY_ID = $P{CategoryCode} AND M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' Related http://stackoverflow.com/questions/1595659/how-to-eliminate-duplicate-calculation-in-sql Thank you!

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  • Search a string to find which records in table are inside said string

    - by Improfane
    Hello, Say I have a string. Then I have a number of unique tokens or keywords, potentially a large number in a database. I want to search and find out which of these database strings are inside the string I provide (and get the IDs of them). Is there a way of using a query to search the provided string or must it be taken to application space? Am I right in thinking that this is not a 'full text search'? Would the best method be to insert it into the database to make it a full text search?

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  • Nested query to find details in table B for maximum value in table A

    - by jpatokal
    I've got a huge bunch of flights travelling between airports. Each airport has an ID and (x,y) coordinates. For a given list of flights, I want to find the northernmost (highest x) airport visited. Here's the query I'm currently using: SELECT name,iata,icao,apid,x,y FROM airports WHERE y=(SELECT MAX(y) FROM airports AS a , flights AS f WHERE (f.src_apid=a.apid OR f.dst_apid=a.apid) ) This works beautifully and reasonably fast as long as y is unique, but fails once it isn't. What I'd want to do instead is find the MAX(y) in the subquery, but return the unique apid for the airport with the highest y. Any suggestions?

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