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  • My servers been hacked EMERGENCY

    - by Grant unwin
    I'm on my way into work at 9.30 pm on a Sunday because our server has been compromised somehow and was resulting in a DOS attack on our provider. The servers access to the Internet has been shut down which means over 5-600 of our clients sites are now down. Now this could be an FTP hack, or some weakness in code somewhere I'm not sure till j get there. Does anyone have any tips on how I can track this down quickly. Were in for a whole lot of litigation if I dont get the server back up asap. Any help appreciated.

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  • InnoDb Overhead?

    - by Rimary
    I just converted several large tables from MyISAM to InnoDB. When I view the tables in phpMyAdmin, they are showing a significant amount of overhead (One table has 6.8GB). Optimizing the tables (which isn't a supported command on InnoDB) has no affect like it does on MyISAM. Is this a result of InnoDB having the ever growing data file that never returns space even after deletes? If that's the case, I've never seen overhead like this before from other InnoDB tables. Is there a way to clean this up? Edit: Here are the things I've tried (with no success): Optimize Table Reorder table by primary key Defragment table

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  • When and how often to start connection to database in php?

    - by AndHeiberg
    When and how often is it good practice to start the connection to your database in php? I'm new to databases, and I'm wondering when I should start by database connection. I'm creating a api with an index, controllers and model. Should I start the connection in the index and then pass it to all the other files, start the connection at the top of all files and call it as a global in functions as needed or start and end the connection in every function?

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  • Performance Drop Lingers after Load [closed]

    - by Charles
    Possible Duplicate: How do you do Load Testing and Capacity Planning for Databases I'm noticing a drop in performance after subsequent load tests. Although our cpu and ram numbers look fine, performance seems to degrade over time as sustained load is applied to the system. If we allow more time between the load tests, the performance gets back to about 1,000 ms, but if you apply load every 3 minutes or so, it starts to degrade to a point where it takes 12,000 ms. None of the application servers are showing lingering apache processes and the number of database connections cools down to about 3 (from a sustained 20). Is there anything else I should be looking out for here?

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  • Wampserver not working in Windows 8

    - by user1873067
    I recently upgraded my Windows 7 to Windows 8 successfully. Other application are working perfectly except wampserver. When I double click on the desk top icon, it shows red on the tray bar and then the color changes but when I click Start All Services, nothing happens. Localhost does not open in webbrowser. Skype is not running on my computer, i don't know if there is other application using the same port in Win8. Please help!

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  • How many VPS do I need for my website? [duplicate]

    - by michael
    This question already has an answer here: How do you do load testing and capacity planning for web sites? 3 answers I made a website which aims at simulating a trading market. There are a list of prices and corresponding volumes that people want to purchase. Users can purchase at any price any time. My website retrieves the prices and volumes from my database every 2 seconds (I have to update the user's browser frequently to allow them to see the current market). Users' database INSERT query can be sent any time if they purchase. I used ajax to post or get data from my database (sometimes nested ajax calls). So, every 2 seconds, each user will send or retrieve data by using more than 20 database queries (in order to show a users the current prices and volumes). Also, I may have 200 users at a time. I was not using VPS before, and I got banned because of using too much CPU resources on my host. Now, I've purchased VPS*2 from a hosting servers. I have: CPU Speed: 2000 Mhz Memory: 2048 MB Disk Space: 20000 MB Bandwidth: 2000 GB Connection: 40 Mb/s Dedicated IP's 2 IP's Is this enough for my 200 users? Also, which VPS OS is suitable for me? Thank you.

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  • Dropdown dependent values to be fetch from multiple models using ajax in Yii

    - by newuser
    I searched all the documentation over Yii but not got the answer of it.So I came here finally. I have the following schema Table Schools +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_name | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ Table Students +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_id | int(10) | NO | FK | | | | student_name | varchar(100) | NO | | | | | roll_no | varchar(80) | NO | | | | | class | varchar(20) | NO | | | | | | subjects | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ I have made models and CRUD for the both models.In models my relation is like this In Students.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'School' => array(self::BELONGS_TO,'Schools','school_id'), ); } In Schools.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'student' => array(self::HAS_MANY, 'Students', 'school_id'), ); } Now I made the two models rendered in a single page so that I can enter all the respective fields in a single form. In the _form.php file of Students I have made some change in student_name like this <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php echo $form->dropdownList($model,'student_name', CHtml::listData(Students::model()->findAll(), 'id', 'student_name'), array('empty'=>array('Select'=>'--Select One---'))); ?> <?php echo $form->error($model,'student_name'); ?> Now for this piece of code I got all the student name from the Student model. So my problem is when I am getting the student name from the dropdown list and going to select a student it will also fetch all the respective values of the student to be rendered in the _form.php without click on save button.So that user don't have to put it again manually. I think ajax and json encode will work here but don't know how to make them work here. [Update] Here is StudentsController code public function actionDisCoor() { $model = School::model()->findByPk($_POST['Students']['student_id']); $data=CHtml::listData($data,'id','name'); foreach($data as $value=>$name) { echo CHtml::tag('option',array('value'=>$value),CHtml::encode($name),true); } } Here is _form.php code for Students <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php $List = CHtml::listData(Students::model()->findAll(), 'id', 'student_name'); ?> <?php echo $form->dropdownList($model,'student_name',$List, array('onChange'=>CHtml::ajax(array( 'url' => CController::createUrl('DisCoor'), 'type' => 'POST', 'update'=>'#school_id', )),'style'=>'width:180px;' ) )?> <?php echo $form->error($model,'student_name'); ?> </div> After all that when I saw in firebug I got the error.Here is the screen shot

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  • Need help displaying a dynamic table

    - by Gideon
    I am designing a job rota planner for a company and need help displaying a dynamic table containing the staff details. I have the following tables in MySQL database: Staff, Event, and Job. The staff table holds staff details (staffed, name, address...etc), the Event table (eventide, eventName, Fromdate, Todate...etc) and the Job table holds (Jobid, Jobdate, Eventid(fk), Staffid (fk)). I need to dynamically display the available staff list from the staff table when the user selects the EVENT and the DATE (3 drop downs: date, month, and year) from a PHP form. I need to display staff members that have not been assigned work on the selected date by checking the Jobdate in the Job table. I have been at this for all day and can't get around it. I am still learning PHP and would surely appreciate any help I can get. My current code displays all staff members when an event is selected: if(isset($_POST['submit'])) { $eventId = $_POST['eventradio']; } $timePeriod = $_POST['timeperiod']; $Day = $_POST['day']; $Month = $_POST['month']; $Year = $_POST['year']; $dateValue = $Year."-".$Month."-".$Day; $selectedDate = date("Y-m-d", strtotime($dateValue)); //construct the available staff list if ($selectedDate) { $staffsql = "SELECT s.StaffId, s.LastName, s.FirstName FROM Staff s WHERE s.StaffId NOT IN (SELECT J.StaffId FROM Job J WHERE J.JobDate != ".$selectedDate.")"; $staffResult = mysql_query($staffsql) or die (mysql_error()); } if ($staffResult){ echo "<p><table cellspacing='1' cellpadding='3'>"; echo "<th colspan=6>List of Available Staff</th>"; echo "</tr><tr><th> Select</th><th>Id</th><th></th><th>Last Name </th><th></th><th>First Name </th></tr>"; while ($staffarray = mysql_fetch_array($staffResult)) { echo "<tr onMouseOver= this.bgColor = 'red' onMouseOut =this.bgColor = 'white' bgcolor= '#FFFFFF'> <td align=center><input type='checkbox' name='selectbox[]' id='selectbox[]' value=".$staffarray['StaffId']."> </td><td align=left>".$staffarray['StaffId']." </td><td>&nbsp&nbsp</td><td align=center>".$staffarray['LastName']." </td><td>&nbsp&nbsp</td><td align=center>".$staffarray['FirstName']." </td></tr>"; } echo "</table>"; } else { echo "<br> The Staff list can not be displayed!"; } echo "</td></tr>"; echo "<tr><td></td>"; echo "<td align=center><input type='submit' name='Submit' value='Assign Staff'>&nbsp&nbsp"; echo "<input type='reset' value='Start Over'>"; echo "</td></tr>"; echo "</table>";

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  • PHP errors -> Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt | Warning: mysqli_stmt::c

    - by Tunji Gbadamosi
    I keep getting this error while trying to modify some tables. Here's my code: /** <- line 320 * * @param array $guests_array * @param array $tickets_array * @param integer $seat_count * @param integer $order_count * @param integer $guest_count */ private function book_guests($guests_array, $tickets_array, &$seat_count, &$order_count, &$guest_count){ /* @var $guests_array ArrayObject */ $sucess = false; if(sizeof($guests_array) >= 1){ //$this->mysqli->autocommit(FALSE); //insert the guests into guest, person, order, seat $menu_stmt = $this->mysqli->prepare("SELECT id FROM menu WHERE name=?"); $menu_stmt->bind_param('s',$menu); //$menu_stmt->bind_result($menu_id); $table_stmt = $this->mysqli->prepare("SELECT id FROM tables WHERE name=?"); $table_stmt->bind_param('s',$table); //$table_stmt->bind_result($table_id); $seat_stmt = $this->mysqli->prepare("SELECT id FROM seat WHERE name=? AND table_id=?"); $seat_stmt->bind_param('ss',$seat, $table_id); //$seat_stmt->bind_result($seat_id); for($i=0;$i<sizeof($guests_array);$i++){ $menu = $guests_array[$i]['menu']; $table = $guests_array[$i]['table']; $seat = $guests_array[$i]['seat']; //get menu id if($menu_stmt->execute()){ $menu_stmt->bind_result($menu_id); while($menu_stmt->fetch()) ; } $menu_stmt->close(); //get table id if($table_stmt->execute()){ $table_stmt->bind_result($table_id); while($table_stmt->fetch()) ; } $table_stmt->close(); //get seat id if($seat_stmt->execute()){ $seat_stmt->bind_result($seat_id); while($seat_stmt->fetch()) ; } $seat_stmt->close(); $dob = $this->create_date($guests_array[$i]['dob_day'], $guests_array[$i]['dob_month'], $guests_array[$i]['dob_year']); $id = $this->add_person($guests_array[$i]['first_name'], $guests_array[$i]['surname'], $dob, $guests_array[$i]['sex']); if(is_string($id)){ $seat = $this->add_seat($table_id, $seat_id, $id); /* @var $tickets_array ArrayObject */ $guest = $this->add_guest($id,$tickets_array[$i+1],$menu_id, $this->volunteer_id); /* @var $order integer */ $order = $this->add_order($this->volunteer_id, $table_id, $seat_id, $id); if($guest == 1 && $seat == 1 && $order == 1){ $seat_count += $seat; $guest_count += $guest; $order_count += $order; $success = true; } } } } return $success; } <- line 406 Here are the warnings: The person PRSN10500000LZPH has been added to the guest tablePRSN10500000LZPH added to table (1), seat (1)The order for person(PRSN10500000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (1)PRSN10600000LZPH added to table (1), seat (13)The person PRSN10600000LZPH has been added to the guest tableThe order for person(PRSN10600000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (13) Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 358 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 363 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 366 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 371 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 374 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 379 PRSN10700000LZPH added to table (1), seat (13)The person PRSN10700000LZPH has been added to the guest tableThe order for person(PRSN10700000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (13) Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 358 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 363 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 366 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 371 Warning: mysqli_stmt::execute(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 374 Warning: mysqli_stmt::close(): Couldn't fetch mysqli_stmt in /Users/olatunjigbadamosi/Sites/ST_Ambulance/FormDB.php on line 379 PRSN10800000LZPH added to table (1), seat (13)The person PRSN10800000LZPH has been added to the guest tableThe order for person(PRSN10800000LZPH) is registered with volunteer (PRSN10500000LZPH) at table (1) and seat (13)

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  • User welcome message in php

    - by user225269
    How do I create a user welcome message in php. So that the user who has been logged on will be able to see his username. I have this code, but it doesn't seem to work. <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM users WHERE Username='$username'"); while($row = mysql_fetch_array($result)) { echo $row['Username']; echo "<br />"; } ?> I'm trying to make use of the data that is inputted in this login form: <form name="form1" method="post" action="verifylogin.php"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="myusername" type="text" id="idnum" maxlength="5"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="mypassword" type="password" id="lname" maxlength="15"></td> </tr> <td align="right" width="30"><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td align="right" width="30"><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> But this, verifylogin.php, seems to be in the way. <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $myusername=$_POST['myusername']; $mypassword=$_POST['mypassword']; $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count==1){ session_register("myusername"); session_register("mypassword"); header("location:userpage.php"); } else { echo "Wrong Username or Password"; } ?> How do I do it? I always get this error when I run it: Notice: Undefined variable: username in C:\wamp\www\exp\userpage.php on line 53 Can you recommend of an easier on how I can achieve the same thing?

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  • Linq-to-XML query to select specific sub-element based on additional criteria

    - by BrianLy
    My current LINQ query and example XML are below. What I'd like to do is select the primary email address from the email-addresses element into the User.Email property. The type element under the email-address element is set to primary when this is true. There may be more than one element under the email-addresses but only one will be marked primary. What is the simplest approach to take here? Current Linq Query (User.Email is currently empty): var users = from response in xdoc.Descendants("response") where response.Element("id") != null select new User { Id = (string)response.Element("id"), Name = (string)response.Element("full-name"), Email = (string)response.Element("email-addresses"), JobTitle = (string)response.Element("job-title"), NetworkId = (string)response.Element("network-id"), Type = (string)response.Element("type") }; Example XML: <?xml version="1.0" encoding="UTF-8"?> <response> <response> <contact> <phone-numbers/> <im> <provider></provider> <username></username> </im> <email-addresses> <email-address> <type>primary</type> <address>[email protected]</address> </email-address> </email-addresses> </contact> <job-title>Account Manager</job-title> <type>user</type> <expertise nil="true"></expertise> <summary nil="true"></summary> <kids-names nil="true"></kids-names> <location nil="true"></location> <guid nil="true"></guid> <timezone>Eastern Time (US &amp; Canada)</timezone> <network-name>Domain</network-name> <full-name>Alice</full-name> <network-id>79629</network-id> <stats> <followers>2</followers> <updates>4</updates> <following>3</following> </stats> <mugshot-url> https://assets3.yammer.com/images/no_photo_small.gif</mugshot-url> <previous-companies/> <birth-date></birth-date> <name>alice</name> <web-url>https://www.yammer.com/domain.com/users/alice</web-url> <interests nil="true"></interests> <state>active</state> <external-urls/> <url>https://www.yammer.com/api/v1/users/1089943</url> <network-domains> <network-domain>domain.com</network-domain> </network-domains> <id>1089943</id> <schools/> <hire-date nil="true"></hire-date> <significant-other nil="true"></significant-other> </response> <response> <contact> <phone-numbers/> <im> <provider></provider> <username></username> </im> <email-addresses> <email-address> <type>primary</type> <address>[email protected]</address> </email-address> </email-addresses> </contact> <job-title>Office Manager</job-title> <type>user</type> <expertise nil="true"></expertise> <summary nil="true"></summary> <kids-names nil="true"></kids-names> <location nil="true"></location> <guid nil="true"></guid> <timezone>Eastern Time (US &amp; Canada)</timezone> <network-name>Domain</network-name> <full-name>Bill</full-name> <network-id>79629</network-id> <stats> <followers>3</followers> <updates>1</updates> <following>1</following> </stats> <mugshot-url> https://assets3.yammer.com/images/no_photo_small.gif</mugshot-url> <previous-companies/> <birth-date></birth-date> <name>bill</name> <web-url>https://www.yammer.com/domain.com/users/bill</web-url> <interests nil="true"></interests> <state>active</state> <external-urls/> <url>https://www.yammer.com/api/v1/users/1089920</url> <network-domains> <network-domain>domain.com</network-domain> </network-domains> <id>1089920</id> <schools/> <hire-date nil="true"></hire-date> <significant-other nil="true"></significant-other> </response> </response>

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  • phpMyAdmin 3.2.4 error #1227 - Access denied; you need the SUPER privilege for this operation

    - by CheeseConQueso
    I want to make a simple sql trigger on inserts... something like this CREATE TRIGGER filter AFTER INSERT ON table FOR EACH ROW DELETE FROM table WHERE field LIKE "%chicken%" OR field LIKE "%egg%"; After running it through phpMyAdmin 3.2.4 & MySQL 5.0.45 you get an error that says #1227 - Access denied; you need the SUPER privilege for this operation Is this syntax wrong or do I have to change something else to get past this error?

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  • Select videos using UIImagePickerController in 2G/3G

    - by Raj
    Hi, I am facing a problem where-in I cannot select videos from the photo album in iPhone 2G/3G device. The default photos application does show videos and is capable of playing them, which in turn means that UIImagePickerController should clearly be capable of showing videos in photo album and selecting them. I have coded this to determine whether the device is capable of snapping a photo, recording video, selecting photos and selecting videos: // Check if camera and video recording are available: [self setCameraAvailable:NO]; [self setVideoRecordingAvailable:NO]; [self setPhotoSelectionAvailable:NO]; [self setVideoSelectionAvailable:NO]; // For live mode: NSArray *availableTypes = [UIImagePickerController availableMediaTypesForSourceType:UIImagePickerControllerSourceTypeCamera]; NSLog(@"Available types for source as camera = %@", availableTypes); if ([UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypeCamera]) { if ([availableTypes containsObject:(NSString*)kUTTypeMovie]) [self setVideoRecordingAvailable:YES]; if ([availableTypes containsObject:(NSString*)kUTTypeImage]) [self setCameraAvailable:YES]; } // For photo library mode: availableTypes = [UIImagePickerController availableMediaTypesForSourceType:UIImagePickerControllerSourceTypePhotoLibrary]; NSLog(@"Available types for source as photo library = %@", availableTypes); if ([availableTypes containsObject:(NSString*)kUTTypeImage]) [self setPhotoSelectionAvailable:YES]; if ([availableTypes containsObject:(NSString*)kUTTypeMovie]) [self setVideoSelectionAvailable:YES]; The resulting logs for 3G device is as follows: 2010-05-03 19:09:09.623 xyz [348:207] Available types for source as camera = ( "public.image" ) 2010-05-03 19:09:09.643 xyz [348:207] Available types for source as photo library = ( "public.image" ) As the logs state, for photo library the string equivalent of kUTTypeMovie is not available and hence the UIImagePickerController does not show up (or rather throws exception if we set the source types array which includes kUTTypeMovie) the movie files in photo library. I havent tested for 3GS, but I am sure that this problem does not exist in it with reference to other threads. I have built the app for both 3.0 (base SDK) and 3.1 but with the same results. This issue is already discussed in the thread: http://www.iphonedevsdk.com/forum/iphone-sdk-development/36197-uiimagepickercontroller-does-not-show-movies-albums.html But it does not seem to host a solution. Any solutions to this problem? Thanks and Regards, Raj Pawan

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  • SQLite UPSERT - ON DUPLICATE KEY UPDATE

    - by Alix Axel
    MySQL has something like this: INSERT INTO visits (ip, hits) VALUES ('127.0.0.1', 1) ON DUPLICATE KEY UPDATE hits = hits + 1; As far as I'm know this feature doesn't exist in SQLite, what I want to know is if there is any way to archive the same effect without having to execute two queries. Also, if this is not possible, what do you prefer: SELECT + (INSERT or UPDATE) or UPDATE (+ INSERT if UPDATE fails)

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  • Sql Query - Limiting query results

    - by Gublooo
    I am quite certain we cannot use the LIMIT clause for what I want to do - so wanted to find if there are any other ways we can accomplish this. I have a table which captures which user visited which store. Every time a user visits a store, a row is inserted into this table. Some of the fields are shopping_id (primary key) store_id user_id Now what I want is - for a given set of stores, find the top 5 users who have visited the store max number of times. I can do this 1 store at a time as: select store_id,user_id,count(1) as visits from shopping where store_id = 60 group by user_id,store_id order by visits desc Limit 5 This will give me the 5 users who have visited store_id=60 the max times What I want to do is provide a list of 10 store_ids and for each store fetch the 5 users who have visited that store max times select store_id,user_id,count(1) as visits from shopping where store_id in (60,61,62,63,64,65,66) group by user_id,store_id order by visits desc Limit 5 This will not work as the Limit at the end will return only 5 rows rather than 5 rows for each store. Any ideas on how I can achieve this. I can always write a loop and pass 1 store at a time but wanted to know if there is a better way

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  • phpexcel write excel and save ?

    - by boss
    code: <?php /** PHPExcel */ require_once '../Classes/PHPExcel.php'; /** PHPExcel_IOFactory */ require_once '../Classes/PHPExcel/IOFactory.php'; // Create new PHPExcel object $objPHPExcel = new PHPExcel(); // Set properties $objPHPExcel->getProperties()->setCreator("Maarten Balliauw") ->setLastModifiedBy("Maarten Balliauw") ->setTitle("Office 2007 XLSX Test Document") ->setSubject("Office 2007 XLSX Test Document") ->setDescription("Test document for Office 2007 XLSX, generated using PHP classes.") ->setKeywords("office 2007 openxml php") ->setCategory("Test result file"); $result = 'select * from table1'; for($i=0;$i<count($result);$i++){ $result1 = 'select * from table2 where table1_id = ' . $result[$i]['table1_id']; for ($j=0;$j<count($result1);$j++) { $objPHPExcel->setActiveSheetIndex(0)->setCellValue('A' . $j, $result1[$j]['name']); } // Set active sheet index to the first sheet, so Excel opens this as the first sheet $objPHPExcel->setActiveSheetIndex(0); // Save Excel 2007 file $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel2007'); $objWriter->save(str_replace('.php', '.xlsx', __FILE__)); // Echo done echo date('H:i:s') . " Done writing file.\r\n"; } ?> The above code executes and save n no of .xlsx files in the folder, but the problem im getting is biggest count(result1) in the for loop executing in all saved excel files. Please give me the solution.

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  • mysqldump table names prefix

    - by Bogdan Gusiev
    I have two mysql databases that have almost the same structure and representing the data of the same web app but one of them represents the current version and second one was made long time ago. How can I create the database with both dumps inside but with old_ prefix for tables from the first and new_ prefix for tables from the second database? Is there any mysqldump options to setup the prefix or other solution?

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  • Disable button until tabs have ben read...

    - by jimbo
    I have some tabs which have been created using Javascript and Mootools, my client wants the 'next button' at the bottom of the page to be disabled, until the tabs have been read(clicked). The page is dynamic (created with PHP and MySQL) and there could be two tabs or three, depending on the set-up. I am struggling today to think of the best solution. Any help more than welcome...

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  • Convert the uploaded files to specific file format which can not download

    - by Avinash
    Hi, I have a problem regarding to prevent download and saving of uploaded files. My users can upload multiple files types like doc, pdf, ppt,etc.... This all file types are easily download if any one have url. So what is the better way to prevent the download of the file. Or i convert the uploaded files to some specific format which can not download easily (e.g flash).. I am running on php and mysql. Thanks Avinash

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