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  • gcc returns error with nested class

    - by Nate
    Howdy, I am attempting to use the fully qualified name of my nested class as below, but the compiler is balking! template <class T> class Apple { //constructors, members, whatevers, etc... public: class Banana { public: Banana() { //etc... } //other constructors, members, etc... }; }; template <class K> class Carrot{ public: //etc... void problemFunction() { Apple<int>::Banana freshBanana = someVar.returnsABanana(); //line 85 giveMonkey(freshBanana); //line 86 } }; My issue is, the compiler says: Carrot.h:85: error: expected ';' before 'freshBanana' Carrot.h:86: error: 'freshBanana' was not declared in this scope I had thought that using the fully qualified name permitted me to access this nested class? It's probably going to smack me in the face, but what on earth am I not seeing here??

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  • How to debug .net error where message is masked in Ajax call

    - by Matt Thrower
    Hi, I'm currently working on a page which makes use of the MS Ajax UpdatePanel. However I've run into a strange problem. If I simply compile and view my page, one of the button click events results in an error. However, because the button affects items inside an UpdatePanel the actual exception is hidden from me: all I'm getting is a HTTP 500 error returned to me through the UpdatePanel Javascript. What's odd about this is that if I step through the code line by line in Visual Studio, I don't get the error. The button doesn't cause the behaviour I'm expecting, but it throws no errors. Because the step through isn't causing an error to be thrown, I'm at a loss how I can get to the actual exception message so I can find out where the error is being thrown and debug it. Suggestions gratefully received. Cheers, Matt

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  • exception with Linq to SQL using sdf file

    - by Ben
    Hi, I've set up a project with an SDF local database file and am trying to access it using an LINQ To SQL (".dbml") file. I have used the connection string provided by the sdf file and can instanciate the object with out a problem: thisDataContext = new MyDataContext(GetConnectionString()); However, whenever i try to access any information from it eg var collection = (from MyObject p in thisDataContext.MyTable select p); I get the error - "The table name is not valid. [ Token line number (if known) = 2,Token line offset (if known) = 14,Table name = Person ]" I am using Visual Studio 2008 SP1 .Net 3.5 and SQL 2008 CE. I gather something similar happened for SQL 2005 CE and a Hotfix was released, but i would have thought the fix would have been fixed in this version before release. Does anyone know the fix for this? Thanks

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  • Android table width queries

    - by user1653285
    I have a table layout (code below), but I have am having a bit of a problem with the width of the cells. The picture below shows the problem. There should be a white border on the right hand side of the screen. I also want the text "Auditorium" not to wrap onto a new line (I would prefer that "13th -" get put onto the new line instead, I don't want to put \n in there because then it would mean it goes onto a new line at that point on bigger screens/landscape view). How can I fix those two problems? <?xml version="1.0" encoding="utf-8"?> <ScrollView xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="#013567" > <TableLayout android:layout_width="match_parent" android:layout_height="wrap_content" android:shrinkColumns="*" android:stretchColumns="*" > <TableRow android:layout_width="match_parent" android:layout_height="wrap_content" > <TextView android:layout_width="match_parent" android:layout_height="match_parent" android:background="@drawable/textlines" android:gravity="center" android:text="@string/meeting_5" android:textColor="#fff" > </TextView> <TextView android:layout_width="match_parent" android:layout_height="match_parent" android:background="@drawable/textlines" android:gravity="center" android:text="@string/meeting_5_date" android:textColor="#fff" > </TextView> <TextView android:layout_width="match_parent" android:layout_height="match_parent" android:background="@drawable/textlines" android:gravity="center" android:text="@string/meeting_5_location" android:textColor="#fff" > </TextView> </TableRow> <TableRow android:layout_width="match_parent" android:layout_height="wrap_content" > <TextView android:layout_width="match_parent" android:layout_height="match_parent" android:background="@drawable/textlines" android:gravity="center" android:text="@string/AGM" android:textColor="#fff" > </TextView> <TextView android:layout_width="match_parent" android:layout_height="match_parent" android:background="@drawable/textlines" android:gravity="center" android:text="@string/AGM_date" android:textColor="#fff" > </TextView> <TextView android:layout_width="match_parent" android:layout_height="match_parent" android:background="@drawable/textlines" android:gravity="center" android:text="@string/AGM_location" android:textColor="#fff" > </TextView> </TableRow> </TableLayout>

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  • Convert Chunk of Data into Tabular Format Using Perl

    - by neversaint
    I have a data that looks like this 1:SRX000566 Submitter: WoldLab Study: RNASeq expression profiling for ENCODE project(SRP000228) Sample: Human cell line GM12878(SRS000567) Instrument: Solexa 1G Genome Analyzer Total: 4 runs, 62.7M spots, 2.1G bases Run #1: SRR002055, 11373440 spots, 375323520 bases Run #2: SRR002063, 22995209 spots, 758841897 bases Run #3: SRR005091, 13934766 spots, 459847278 bases Run #4: SRR005096, 14370900 spots, 474239700 bases 2:SRX000565 Submitter: WoldLab Study: RNASeq expression profiling for ENCODE project(SRP000228) Sample: Human cell line GM12878(SRS000567) Instrument: Solexa 1G Genome Analyzer Total: 3 runs, 51.2M spots, 1.7G bases Run #1: SRR002052, 12607931 spots, 416061723 bases Run #2: SRR002054, 12880281 spots, 425049273 bases Run #3: SRR002060, 25740337 spots, 849431121 bases 3:SRX012407 Submitter: GEO Study: GSE17153: Illumina sequencing of small RNAs from C. elegans embryos(SRP001363) Sample: Caenorhabditis elegans(SRS006961) Instrument: Illumina Genome Analyzer II Total: 1 run, 3M spots, 106.8M bases Run #1: SRR029428, 2965597 spots, 106761492 bases Is there a compact way to convert them into tabular format (tab separated). Hence 1 entry/row per chunk. In these case 3 rows. I tried this but doesn't seem to work. perl -laF/\n/ -000ne"print join chr(9),@F" myfile.txt

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  • Error: java.security.AccessControlException: Access denied

    - by RMD
    Hi, I have to connect to a https url with username and password to read a file. I am not able to connect to the server (see the error log below). I do not have much java experience so I need help with this code. I would really appreciate some help to solve this! Thank you. Raquel CODE: import lotus.domino.; import java.net.; import java.io.*; import javax.net.ssl.HttpsURLConnection; public class JavaAgent extends AgentBase { public void NotesMain() { try { String username = "123"; String password = "456"; String input = username + ":" + password; String encoding = new sun.misc.BASE64Encoder().encode (input.getBytes()); //Open the URL and read the text into a Buffer String urlName = "https://server.org/Export.mvc/GetMeetings?modifiedSince=4/9/2010"; URL url = new URL(urlName); HttpsURLConnection connection = (HttpsURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); connection.setRequestProperty("Content-Length", String.valueOf (encoding.length())); connection.setUseCaches(false); connection.setDoInput(true); connection.setDoOutput(true); connection.setAllowUserInteraction(true); connection.setRequestProperty("Authorization", "Basic " + encoding); connection.setRequestProperty("Cookie", "LocationCode=Geneva"); connection.connect(); BufferedReader rd = null; try{ rd = new BufferedReader(new InputStreamReader(connection.getInputStream())); } catch (IOException e) { System.out.println("Read failed"); System.exit(-1); } String line; while((line = rd.readLine()) != null) { System.out.println(line.toString()); } rd.close(); connection.disconnect(); } catch(Exception e) { e.printStackTrace(); } } } LOG: java.security.AccessControlException: Access denied (java.lang.RuntimePermission exitVM.-1) at java.security.AccessController.checkPermission(AccessController.java:108) at java.lang.SecurityManager.checkPermission(SecurityManager.java:532) at COM.ibm.JEmpower.applet.AppletSecurity.superDotCheckPermission(AppletSecurity.java:1449) at COM.ibm.JEmpower.applet.AppletSecurity.checkRuntimePermission(AppletSecurity.java:1311) at COM.ibm.JEmpower.applet.AppletSecurity.checkPermission(AppletSecurity.java:1611) at COM.ibm.JEmpower.applet.AppletSecurity.checkPermission(AppletSecurity.java:1464) at java.lang.SecurityManager.checkExit(SecurityManager.java:744) at java.lang.Runtime.exit(Runtime.java:99) at java.lang.System.exit(System.java:275) at JavaAgent.NotesMain(Unknown Source) at lotus.domino.AgentBase.runNotes(Unknown Source) at lotus.domino.NotesThread.run(Unknown Source)

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  • Amazon EC2 EBS automatic backup one-liner works manually but not from cron

    - by dan
    I am trying to implement an automatic backup system for my EBS on Amazon AWS. When I run this command as ec2-user: /opt/aws/bin/ec2-create-snapshot --region us-east-1 -K /home/ec2-user/pk.pem -C /home/ec2-user/cert.pem -d "vol-******** snapshot" vol-******** everything works fine. But if I add this line into /etc/crontab and restart the crond service: 15 12 * * * ec2-user /opt/aws/bin/ec2-create-snapshot --region us-east-1 -K /home/ec2-user/pk.pem -C /home/ec2-user/cert.pem -d "vol-******** snapshot" vol-******** that doesn't work. I checked var/log/cron and there is this line, therefore the command gets executed: Dec 13 12:15:01 ip-10-204-111-94 CROND[4201]: (ec2-user) CMD (/opt/aws/bin/ec2-create-snapshot --region us-east-1 -K /home/ec2-user/pk.pem -C /home/ec2-user/cert.pem -d "vol-******** snapshot" vol-******** ) Can you please help me to troubleshoot the problem? I guess is some environment problem - maybe the lack of some variable. If that's the case I don't know what to do about it. Thanks.

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  • How to log in to a website using installed twill?

    - by brilliant
    Hello, everybody!!!! I have just successfully installed TWILL on my computer with the help of one very supportive member of "StackOverflow" (you can check it out HERE) and have tried to run one of the simple examples on the twill documentation page (you can see that page HERE). Here is that example: Let's say my username on www.slash.org is lynxye and my password is mammal. When I try to enter that example code into my Python prompt, I can only type and enter the first line of the code because when I click on "Enter" to start a new line, I get some error messages right away: The same happens when I try to enter this code into my terminal: I think I miss out on some basics here. Perhaps, I need to create a file that would contain that code and then run that file somehow, but I really don't know where I need to create that file and with what extensdion. Can anyone, please, help me with this?

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  • ungetc in Python

    - by Dragos Toader
    Some file read (readlines()) functions in Python copy the file contents to memory (as a list) I need to process a file that's too large to be copied in memory and as such need to use a file pointer (to access the file one byte at a time) -- as in C getc(). The additional requirement I have is that I'd like to rewind the file pointer to previous bytes like in C ungetc(). Is there a way to do this in Python? Also, in Python, I can read one line at a time with readline() Is there a way to read the previous line going backward?

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  • Parse values from a text file in C

    - by Mohit Deshpande
    Say I have written to a text file in this format: key1/value1 key2/value2 akey/withavalue anotherkey/withanothervalue I have a linked list like: struct Node { char *key; char *value; struct Node *next; }; to hold the values. How would I read key1 and value1? I was thinking of putting line by line in a buffer and using strtok(buffer, '/'). Would that work? What other ways could work, maybe a bit faster or less prone to error? Please include a code sample if you can!

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  • NSInteger differences between CLI and GUI ?

    - by d11wtq
    I've been building a framework and writing unit tests in GHUnit. One of my Framework's accessor methods returns an NSInteger. I assert the expected value in the tests like this: GHAssertEquals(1320, request.port, @"Port number should be 1320"); When running my tests with an AppKit UI based frontend this assertion passes. However, when I run my tests on the command line, it fails with a type-mismatch unless I type-cast my hard-coded 1320 as (NSInteger). What's causing the difference in the way the integer is being interpreted by the compiler? Is xcodebuild on the command line using a different data-type for hard coded integers?

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  • Using a .txt file Resource in VB

    - by Tony C
    Right now i have a line of code, in vb, that calls a text file, like this: Dim fileReader As String fileReader = My.Computer.FileSystem.ReadAllText("data5.txt") data5.txt is a resource in my application, however the application doesn't run because it can't find data5.txt. I'm pretty sure there is another code for finding a .txt file in the resource that i'm overlooking, but i can't seem to figure it out. So does anyone know of a simple fix for this? or maybe another whole new line of code? Thanks in advance!

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  • Need Simple way to access XML in VB.Net - Pain with Linq-to-Xml

    - by aiart
    Dim myXDoc As XDocument = _ I want to access this in a simple way in VB.Net - Like: Dim Integer SizeXStr = CInt(MyZDoc.Cameras(1).Camera_Desc.@SizeX) ' where (1) is an index Why isn't this implemented in VB.Net? Better yet, type the values with a Schema and eliminate the conversion. Is this so hard? How do I access, in a simple way, data in XML - this would be VERY VERY useful! I have been using Query to try to get the values - when I use MsgBox() to display results, they display, but my main Windows Form is Trashed - changed colors, etc. The system has Bugs. Instead, I have to create an elaborate structure of arrays of objects and read the XML line-by-line and do the same for saving - this is the dark ages. Art

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  • serializing JSON files with newlines in Python

    - by user248237
    I am using json and jsonpickle sometimes to serialize objects to files, using the following function: def json_serialize(obj, filename, use_jsonpickle=True): f = open(filename, 'w') if use_jsonpickle: import jsonpickle json_obj = jsonpickle.encode(obj) f.write(json_obj) else: simplejson.dump(obj, f) f.close() The problem is that if I serialize a dictionary for example, using "json_serialize(mydict, myfilename)" then the entire serialization gets put on one line. This means that I can't grep the file for entries to be inspected by hand, like I would a CSV file. Is there a way to make it so each element of an object (e.g. each entry in a dict, or each element in a list) is placed on a separate line in the JSON output file? thanks.

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  • gethostname() returns accurate hostname, bind() doesn't like it

    - by user2072848
    Doing a python socket tutorial, entire codebase is as follows import socket as so s = so.socket() host = so.gethostname() port = 12345 s.bind((host, port)) s.listen(5) while True: c, addr = s.accept() print 'Got connection from', addr c.send('Thank you for connecting') c.close() and error message: Traceback (most recent call last): File "server.py", line 13, in <module> s.bind((host, port)) File "/Users/solid*name*/anaconda/lib/python2.7/socket.py", line 224, in meth return getattr(self._sock,name)(*args) socket.gaierror: [Errno 8] nodename nor servname provided, or not known Printing hostname gives me super*name* Which is, in fact, my computer's hostname.

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  • A better JavaScript version of addslashes and stripslashes?

    - by karlthorwald
    I am using these 2 functions: http://javascript.about.com/library/bladdslash.htm But JSLint complains 'Bad Escapement' on this line: str=str.replace(/\\0/g,'\0'); [Edit] I converted to 2 lines, and now the first line is the one that fails JLint: var rep = '\0'; str=str.replace(/\\0/g,rep); So it is the '\0' can you help? I could try something but I want to understand what is going on. [/Edit] Can you make a better version and explain? I would like a version that passes JSLint and still works.

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  • Create new field in a table that already exists - flex/air sqlite?

    - by Adam
    I've got a flex/air app I've been working on, it uses a local sqlite database that is created on the initial application start. I've added some features to the application and in the process I had to add a new field to one of the database tables. My questions is how to I go about getting the application to create one new field that is located in a table that already exists? this is a the line that creates the table stmt.text = "CREATE TABLE IF NOT EXISTS tbl_status ("+"status_id INTEGER PRIMARY KEY AUTOINCREMENT,"+" status_status TEXT)"; And now I'd like to add a status_default field. thanks! Thanks - MPelletier I've add the code you provided and it does add the field, but now the next time I restart my app I get an error - 'status_default' already exists'. So how can I go about adding some sort of a IF NOT EXISTS statement to the line you provided?

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  • Ruby on Rails: How to verify haml files syntax within rails project?

    - by Acidburn2k
    I've installed HAML into my project and it is working like a charm - the templates are beeing rendered without a problem. My question is how can I do the rendering on the command line, by using HAML program. That would be super for debugging purposes, meantime while I try to compile HAML file I get the error on first Rails related Ruby code to be found: % cat app/views/dashboard/index.html.haml - title "Home" %p Lorem ipsum dolor sit amet... % haml app/views/dashboard/index.html.haml Exception on line 1: undefined method `title' for #<Object:0xb73283b0> Use --trace for backtrace. Page is rendered fine returned correctly through the webserver.

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  • Finding out what user Apache is running as?

    - by AP257
    I want to secure a file upload directory on my server as described beautifully here, but I have one problem before I can follow these instructions. I don't know what user Apache is running as. I've found a suggestion that you can look in httpd.conf and there will be a "User" line, but there is no such line in my httpd.conf file, so I guess Apache is running as the default user. I can't find out what that is, though. So, my question is (are): how do I find out what the default user is do I need to change the default user if the answer is yes and I change the default user by editing httpd.conf, is it likely to screw anything up? Thanks!

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  • DotNetOpenAuth OpenIdTextBox For Google/Yahoo

    - by user300992
    If I want to integrate DotNetOpenAuth (primary for people to use their Google/Yahoo accounts to login, not act as provider) into my existing site, is this one line control good enough? <rp:OpenIdTextBox ID="OpenIdTextBox1" runat="server" /> Say, if a user wants to login as Google, I can simply set the textbox to "https://www.google.com/accounts/o8/id" and then they can login. I tried it with my Google account, it seems working and I can get the token from HttpContext.Current.User.Identity.Name. Is this "one line" solution secure enough for production? or is it a "must" that I have to use "OpenIdSelector" or "OpenIDLogin" control? I also opened the .net template and some samples, they are very complicated. There are PAPE policies, xrds.aspx (for discovery), ConsumerKey + ConsumerSecret...etc. As a newbie, I am very confused. Any tips on this will be really appreciated. Thanks

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  • Showing HTML comment strings (<!-- -->) in HTML files

    - by Andrei
    Hello all. I'm building a source code search engine, and I'm returning the results on a HTML page (aspx to be exact, but the view logic is in HTML). When someone searches a string, I also return the whole line of code where this string can be found in a file. However, some lines of code come from HTML/aspx files and these lines contain HTML specific comments (). When I try to print this line on the HTML page, it interprets it as a comment and does not show it on the screen....how should I go about solving this so that it actually shows up? Any help would be welcomed. Thanks. edit: err...i see now that firebug could help me with this: <!-- -->

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  • Invalid Argument IE 8 jQuery

    - by Deshiknaves
    Hi, I have this particular script that runs so that the flash elements don't show up on top of my slide out navigation. This redraws that flash element with wmode as opaque and so it shows up under the navigation. Works perfectly with Chrome and FireFox but not with IE. In IE I get an Invalid Argument in jquery.min.js code 0 Line 103 char 460. Can anyone help me as to why? If I comment out the second line of code inside the function then there is no error, but then doesn't work in FireFox. Any help is appriciated. $(window).load(function(){ $('embed').attr('wmode','opaque'); $('object').append('<param name="wmode" value="opaque">'); $('object').wrap('<div>'); });

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  • django urls.py regex isn't working

    - by Phil
    This is for Django 1.2.5 and Python 2.7 on Wamp Server running apache version 2.2.17. My problem is that the my URLConf in urls.py isn't redirecting, it's just throwing a 404 error. urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: #from django.contrib import admin #admin.autodiscover() urlpatterns = patterns('', (r'^app/$', include('app.views.index')), # Uncomment the admin/doc line below to enable admin documentation: #(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: #(r'^admin/', include(admin.site.urls)), ) views.py from django.http import HttpResponse def index(request): return HttpResponse("Hello World") I'm getting the following error: ImportError at /app/ No module named index I'm stumped as I'm only learning Django, can anybody see something wrong with my code? Here's my PythonPath: ['C:\Windows\system32\python27.zip', 'C:\Python27\Lib', 'C:\Python27\DLLs', 'C:\Python27\Lib\lib-tk', 'C:\wamp\bin\apache\Apache2.2.17', 'C:\wamp\bin\apache\apache2.2.17\bin', 'C:\Python27', 'C:\Python27\lib\site-packages', 'c:\wamp\www\seetwo']

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