Search Results

Search found 12044 results on 482 pages for 'foreach loop'.

Page 365/482 | < Previous Page | 361 362 363 364 365 366 367 368 369 370 371 372  | Next Page >

  • Console.WriteLine does not show up in Output window

    - by Luke
    I have put some Console.WriteLine calls in to test, but they aren't appearing in the output box? public static ArrayList myDeliveries = new ArrayList(); public mainForm() { InitializeComponent(); } private void mainForm_Load(object sender, EventArgs e) { if (!File.Exists("../../MealDeliveries.txt")) { MessageBox.Show("File not found!"); return; } using (StreamReader sr = new StreamReader("../../MealDeliveries.txt")) { //first line is delivery name string strDeliveryName = sr.ReadLine(); Console.WriteLine("some tetttttttttt23423423423423423ttttttttttttttttttttttt"); while (strDeliveryName != null) { //other lines Delivery d = new Delivery(strDeliveryName, sr.ReadLine(), sr.ReadLine(), sr.ReadLine(), sr.ReadLine(), sr.ReadLine(), sr.ReadLine()); mainForm.myDeliveries.Add(d); //check for further values strDeliveryName = sr.ReadLine(); } } displayDeliveries(); } private void displayDeliveries() { lstDeliveryDetails.Items.Clear(); Console.WriteLine("some tettttttttttttttttttttttttttttttttt"); Console.WriteLine(mainForm.myDeliveries.Count); foreach (Delivery d in mainForm.myDeliveries) { lstDeliveryDetails.Items.Add(d.DeliveryName); } } Can anyone help??

    Read the article

  • How to create a class by reading from another class (.cs) file with Powershell?

    - by Razcer
    I have this POGO ( simple putter getter) class that I am trying to read in PowerShell using System; using System.Runtime.Serialization; namespace MyApp.VM { [Serializable] public class MyClassVM { public Int64 CtrId { get; set; } public string CtrName { get; set; } public string CtrPhone { get; set; } public string CtrZip { get; set; } public DateTime AddDate { get; set; } } } Here is the ps1 code that is trying to read the class from a file. function Build-Pogo { $FileDir = "D:\YourDirectoryOfPogo" $ClassName = "MyClassVM" $FileName = $FileDir + "\" + $ClassName + ".cs" # Build the class from the file $AllLines = [string]::join([environment]::newline, (Get-Content $FileName)) Add-Type -TypeDefinition $AllLines # spin thru each property for class $ClassHandle = New-Object -typeName $ClassName $ClassHandle | ForEach-Object {Write-Host $_.name -foregroundcolor cyan} } *Note the last line is placeholder for more complex logic to come later. This breaks at the Add-Type with this error message for each get/set in the file. 'MyApp.VM.MyClassVM.CtrId.get' must declare a body because it is not marked abstract or extern Any info on what I'm doing wrong will be greatly appreciated.

    Read the article

  • Pass 2-dimensional array trough view

    - by Mikael
    Hi, I'm trying to print a 2-dimensional array but can't figure it out. My controller uses this code: public ActionResult Test(string str) { DateTimeOffset offset = new DateTimeOffset(DateTime.Now); offset = offset.AddHours(-5); string[,] weekDays = new string[7,2]; for (int i = 0; i < 7; i++) { weekDays[i,0] = String.Format("{0:yyyy-MM-dd:dddd}", offset); //Date weekDays[i,1] = String.Format("{0:dddd}", offset); //Text offset = offset.AddHours(24); } weekDays[0,1] = "Today"; ViewData["weekDays"] = weekDays; return View(); } Now I wan't to print this array of weekdays as a dropdown-list and i thought this would work: <% foreach (var item in (string[,])ViewData["weekDays"]) { %> <option value=" <%= item[0] %> "> <%= item[1] %> </option> <% } %> But that's not the case, this code output just the first char of the string. So anyone got a suggestion? Thanks! /M

    Read the article

  • Cakephp 2.2 Blog Tutorial undefined constant errors

    - by user1741925
    Have copy pasted the code from Blog tutorial in cakephp 2.2 but its not working. Getting the following errors. Notice (8): Use of undefined constant Html Notice (8): Use of undefined constant Form Notice (8): Use of undefined constant posts Notice (8): Use of undefined constant all Notice (8): Undefined index: all Below is the code for PostsController and index.ctp. <?php class PostsController extends AppController { public $helpers = array(’Html’, ’Form’); public function index() { $this->set(’posts’, $this->Post->find(’all’)); } public function view($id = null) { $this->Post->id = $id; $this->set(’post’, $this->Post->read()); } } ?> index.ctp <h1>Blog posts</h1> <table> <tr> <th>Id</th> <th>Title</th> <th>Created</th> </tr> <?php foreach ($posts as $post): ?> <tr> <td><?php echo $post[’Post’][’id’]; ?></td> <td> <?php echo $post[’Post’][’title’]; ?> </td> <td><?php echo $post[’Post’][’created’]; ?></td> </tr> <?php endforeach; ?> <?php unset($post); ?> </table>

    Read the article

  • Entityframework duplicate record on second insert

    - by Delysid
    I am building an application for recipe/meal planning, and i have come across a problem i cant seem to figure out. i have a table for units of measure, where i keep the used units in, i only want unique units in here (for grocery list calculation and so forth) but if i use a unit from the table on a recipe, the first time it is okay, nothing is inserted in units of measure, but the second time i get a "duplicate". i suspect it has something to do with entitykey, because the primary key is identity column on the sql server (2008 r2) for some reason it works to change the objectstate on some objects (courses, see code) and that does not generate a duplicate, but that does not work on the unit of measure my insert methods looks like this : public recipe Create(recipe recipe) { using (RecipeDataContext ctx = new RecipeDataContext()) { foreach (recipe_ingredient rec_ing in recipe.recipe_ingredient) { if (rec_ing.ingredient.ingredient_id == 0) { ingredient ing = (from _ing in ctx.ingredients where _ing.name == rec_ing.ingredient.name select _ing).FirstOrDefault(); if (ing != null) { rec_ing.ingredient_id = ing.ingredient_id; rec_ing.ingredient = null; } } if (rec_ing.unit_of_measure.unit_of_measure_id == 0) { unit_of_measure _uom = (from dbUom in ctx.unit_of_measure where dbUom.unit == rec_ing.unit_of_measure.unit select dbUom).FirstOrDefault(); if (_uom != null) { rec_ing.unit_of_measure_id = _uom.unit_of_measure_id; rec_ing.unit_of_measure = null; } } ctx.Recipes.AddObject(recipe); //for some reason it works to change object state of this, and not generate a duplicate ctx.ObjectStateManager.ChangeObjectState(recipe.courses[0], EntityState.Unchanged); } ctx.SaveChanges(); } return recipe; } My datamodel looks like this : http://i.imgur.com/NMwZv.png

    Read the article

  • How to pass values from array into mysql with php

    - by moustafa
    my original code is this <tr> <th> <label for="user_level"> User Level: * <?php echo isset($valid_user_level) ? $valid_user_level : NULL; ?> </label> </th> </tr> <td> <select name="user_level" id="user_level" class="sel"> <option value="">Select one…</option> <option value="1">User</option> <option value="5">Admin</option> </select> </td> this give me the option to select one of choice from the drop down menu i.e. user and when user is selected and the submit button is pressed this will insert the value 1 into the database which will when the user logs in tell the system that they are are normal user. I want to change the code to the following <tr> <td> <select name="user_level" id="user_level" class="sel"> <option value="">Select one…</option> <?php if(!empty($level)) { foreach($level as $value) { echo "<option value='{$value}'"; echo getSticky(2,'user_level',$value); echo ">{$value}</option>"; } } ?> </select> </td> </tr> With this being my array query $level = array('User','Admin'); How can I pass the values of 1 for user level and 5 for admin in this code so when the user is selected it inouts 1 into the database?

    Read the article

  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    I having been looking around for an answer to this and have not found an answer anywhere, I am hoping someone has done this before! I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="primary[1][text]" /> <input type="file" name="primary[1][file]" /> <input type="text" class="a" name="secondary[1][text][]" /> <input type="file" name="secondary[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="primary[2][text]" /> <input type="file" name="primary[2][file]" /> <input type="text" class="a" name="secondary[2][text][]" /> <input type="file" name="secondary[2][file][]" /> To complicate matters, the "secondary" form fields can also be duplicated (thus the [] at the end of the secondary name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $f_num) { echo $f['file']['name']; } but I get an "Undefined index: file... " error.

    Read the article

  • retrieve only sub-pages (wordpress)

    - by Radek
    I want to list all sub-pages only one level though of one particular page. I was reading Function Reference/get pages and thought that $pages = get_pages( array( 'child_of' => $post->ID, 'parent' => $post->ID)) ; will do the trick but it is not working. It lists all pages on the same level like the page I call that code from. If I omit parent option I will get all pages even with sub-pages that I want. But I want only sub-pages. The whole function is like function about_menu(){ if (is_page('about')){ $pages = get_pages( array( 'child_of' => $post->ID, 'parent' => $post->ID)) ; foreach($pages as $page) { ?> <h2><a href="<?php echo get_page_link($page->ID) ?>"><?php echo $page->post_title ?></a></h2> <?php } } } and mine is second one

    Read the article

  • Require reasonably random results from an SQL SELECT query within a Joomla article (Cache enabled)

    - by Shrinivas
    Setup: Joomla website on LAMP stack I have a MySQL table containing some records, these are queried by a simple SELECT on the Joomla article, as pasted below. This specific Joomla website has Caching turned on in Joomla's Global Configuration. I need to randomize the order in which I display the resultset, each time the page is loaded. Regular php/mysql would offer me two approaches for this: 1. use 'order by RAND()' or any of a number of methods to allow a SELECT query to return reasonably random results. 2. once php gets the result from the SELECT into an array, shuffle the array to get a reasonably random order of array items. However, as this Joomla instance has Caching turned ON in its Global Configuration, either of the above approaches fails. The first time I load the page the order is randomized, however any further reloads do not cause the order to change, as the page is delivered from cache. The instant the Cache is disabled, both approaches (shuffle/order by rand) work perfectly. What am I missing? How do I override the Global Cache for this specific article? A very simple requirement, that is met by both php and mysql reasonably well, is blocked by the Joomla Cache that I cannot turn off. The php that returns results from the database. <pre> $db = JFactory::getDBO(); $select = "SELECT id FROM jos_mytable;"; //order by RAND() $db->setQuery($select); echo $db->getQuery(); //Show me the Query! $rows = $db->loadObjectList(); //shuffle($rows); foreach($rows as $row) { echo "$row->id"; }

    Read the article

  • Processing data from an AJAX request

    - by Josh K
    I have a PHP API I'm working with that outputs everything as JSON. I need to call one of the API methods and parse it out using an AJAX request. I am using jQuery (though it shouldn't matter). When I make the request it errors out with a "parsererror" as the textStatus and a "Syntax Error: invalid label" when I make the request. Simplified code: $.ajax ({ type: "POST", url: "http://mydomain.com/api/get/userlist/"+mid, dataType: "json", dataFilter: function(data, type) { /* Here we assume and pray */ users = eval(data); alert(users[1].id); }, success: function(data, textStatus, XMLHttpRequest) { alert(data.length); // Should be an array, yet is undefined. }, error: function(XMLHttpRequest, textStatus, errorThrown) { alert(textStatus); alert(errorThrown); }, complete: function(XMLHttpRequest, textStatus) { alert("Done"); } }); If I leave off the eval(data) then everything works fine. Well, except for data still being undefined in success. Note that I'm taking an array of objects in PHP and then passing them out through json_encode. Would that make any difference? There has been no progress made on this. I'm willing to throw more code up if someone believes they can help. Here is the PHP side of things private function _get_user_colors($id) { $u = new User(); $u->get_where(array('id' => $id)); $bar = array(); $bar['user'] = $u->stored; foreach($user->colors as $color) { $bar['colors'][] = $color; } echo(json_encode($bar)); } I have had zero issues using this with other PHP based scripts. I don't know why Javascript would take issue with it.

    Read the article

  • How to remove the link if value is 0 using asp.net mvc

    - by kumar
    i have this code.. <table class="dashboard-table"> <thead> <tr> <th>&nbsp;</th> <th>Worked</th> </tr> </thead> <% foreach (var e in Model.ExceptionsByType) { %> <tr> <td> <%=Html.ActionLink(e.ExceptionTypeName, "VirtualScrollingDataRequested", Model.exceptionCategory.GetControllerName(), new { C_EXCPT_TYPE = e.ExceptionTypeID, GUI_SPEC_STAT_DSPL = 2, C_EXCPT_CATG = Model.exceptionCategory.Id, @ASSET_CLASS = string.Empty, @INST_MNEM = string.Empty, @_lock = "ALL" }, new { @title = e.BuildGridTitle(2, e.ExceptionTypeName) })%> </td> <td class="number"> <%=e.WorkedExceptions %> </td> </tr> <% } %> </table> e.WorkedExceptions is the count of exceptions.. I need to to the condition here if the e.workedexceptions == 0 I need to remove the link? please can any body hlep me out? thanks

    Read the article

  • image list, listview,picturebox

    - by user548694
    I wanted to show my pics in picturebox. but also wanted to show a preview of pics. When user select a pic, it is shown in picbox but i have problem in resoulution. Here is my code private void openToolStripMenuItem_Click(object sender, EventArgs e) { ofd = new OpenFileDialog(); ofd.Title = "Open an Image File"; ofd.FileName = ""; ofd.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp"; if (ofd.ShowDialog() == DialogResult.OK) { DirectoryInfo dir = new DirectoryInfo(@"c:\pic"); foreach (FileInfo file in dir.GetFiles()) { this.imageList1.Images.Add(Image.FromFile(file.FullName)); } this.listView1.View = View.LargeIcon; this.imageList1.ImageSize = new Size(40, 40); this.listView1.LargeImageList = this.imageList1; for (int j=0; j < this.imageList1.Images.Count; j++) { ListViewItem item = new ListViewItem(); item.ImageIndex = j; listView1.Items.Add(item); ListViewItem item2 = new ListViewItem(); item2.SubItems.Add(j.ToString()); } private void listView1_SelectedIndexChanged(object sender, EventArgs e) { int i = this.listView1.FocusedItem.Index; this.PicBox1.Image = this.imageList1.Images[i]; } On click i see only image of resolution of (40,40) becuse i have set it this.imageList1.ImageSize = new Size(40, 40); and not orignal size. How can I have it. 2- I want to write also image names and index(image no) under each images. Its it possible. reagrsd,

    Read the article

  • Creating a image viewer window controll.

    - by Scott Chamberlain
    I am learning GDI+ and I am trying to make a display window with scroll bars (so I can only see part of the image at a time and I can scroll around it). I have read through the basics of GDI+ from several books but I have not found any good tutorials online or in books available to me about doing more advanced things like this. Any recommendations on guides or example code on how do do this? Here is what I have so far protected override void OnPaint(PaintEventArgs e) { base.OnPaint(e); if (Label != null) { using (Bitmap drawnLabel = new Bitmap(Label.LabelHeight, Label.LableLength, System.Drawing.Imaging.PixelFormat.Format1bppIndexed)) using (Graphics drawBuffer = Graphics.FromImage(drawnLabel)) { drawBuffer.ScaleTransform(_ImageScaleFactor, _ImageScaleFactor); foreach (Epl2.IDrawableCommand cmd in Label.Collection) { cmd.Paint(drawBuffer); } drawBuffer.ResetTransform(); } } } I would like to paint this in to a PictureBox I have on the control and control what is shown by a VScrollBar and HScrollBar but I don't know how to do that step. P.S. Label is a custom class that I have in my namespace, it is a object that represents a label you would print from a label printer.

    Read the article

  • Why is it possible to enumerate a LinqToSql query after calling Dispose() on the DataContext?

    - by DanM
    I'm using the Repository Pattern with some LinqToSql objects. My repository objects all implement IDisposable, and the Dispose() method does only thing--calls Dispose() on the DataContext. Whenever I use a repository, I wrap it in a using person, like this: public IEnumerable<Person> SelectPersons() { using (var repository = _repositorySource.GetNew<Person>(dc => dc.Person)) { return repository.GetAll(); } } This method returns an IEnumerable<Person>, so if my understanding is correct, no querying of the database actually takes place until Enumerable<Person> is traversed (e.g., by converting it to a list or array or by using it in a foreach loop), as in this example: var persons = gateway.SelectPersons(); // Dispose() is fired here var personViewModels = ( from b in persons select new PersonViewModel { Id = b.Id, Name = b.Name, Age = b.Age, OrdersCount = b.Order.Count() }).ToList(); // executes queries In this example, Dispose() gets called immediately after setting persons, which is an IEnumerable<Person>, and that's the only time it gets called. So, a couple questions: How does this work? How can a disposed DataContext still query the database for results when I walk the IEnumerable<Person>? What does Dispose() actually do? I've heard that it is not necessary (e.g., see this question) to dispose of a DataContext, but my impression was that it's not a bad idea. Is there any reason not to dispose of it?

    Read the article

  • IEnumerator seems to be effecting all objects, and not one at a time

    - by PFranchise
    Hey, I am trying to alter an attribute of an object. I am setting it to the value of that same attribute stored on another table. There is a one to many relationship between the two. The product end is the one and the versions is the many. Right now, both these methods that I have tried have set all the products returned equal to the final version object. So, in this case they are all the same. I am not sure where the issue lies. Here are my two code snipets, both yield the same result. int x = 1 IEnumerator<Product> ie = productQuery.GetEnumerator(); while (ie.MoveNext()) { ie.Current.RSTATE = ie.Current.Versions.First(o => o.VersionNumber == x).RSTATE; x++; } and foreach (var product in productQuery) { product.RSTATE = product.Versions.Single(o => o.VersionNumber == x).RSTATE; x++; } The versions table holds information for previous products, each is distinguished by the version number. I know that it will start at 1 and go until it reaches the current version, based on my query returning the proper number of products. Thanks for any advice.

    Read the article

  • Why does p:panelGrid not work with ui:repeat?

    - by CycDemo
    If I use as below, I get no error, no output. Why does p:panelGrid not work with ui:repeat? Note : I don't want to use c:forEach because of the I already face a lot of JSF issue. <p:panelGrid> <ui:repeat value="#{MyBean.dataList}" var="data"> <p:row> <p:column> <h:outputText value="#{data.name}"/> </p:column> <p:column> <h:outputText value="#{data.description}"/> </p:column> </p:row> </ui:repeat> </p:panelGrid> MyBean.java public List<Data> getDataList(){ List<Data> result = new ArrayList<Data>(); result.add(new Data("Name 1", "Description 1")); result.add(new Data("Name 2", "Description 2")); result.add(new Data("Name 3", "Description 3")); result.add(new Data("Name 4", "Description 4")); return result; } Expected output with primefaces

    Read the article

  • How to store sorted records in csv file ?

    - by Harikrishna
    I sort the records of the datatable datewise with the column TradingDate which is type of datetime. TableWithOnlyFixedColumns.DefaultView.Sort = "TradingDate asc"; Now I want to display these sorted records into csv file but it does not display records sorted by date. TableWithOnlyFixedColumns.DefaultView.Sort = "TradingDate asc";TableWithOnlyFixedColumns.Columns["TradingDate"].ColumnName + "] asc"; DataTable newTable = TableWithOnlyFixedColumns.Clone(); newTable.DefaultView.Sort = TableWithOnlyFixedColumns.DefaultView.Sort; foreach (DataRow oldRow in TableWithOnlyFixedColumns.Rows) { newTable.ImportRow(oldRow); } // we'll use these to check for rows with nulls var columns = newTable.DefaultView.Table.Columns.Cast<DataColumn>(); using (var writer = new StreamWriter(@"C:\Documents and Settings\Administrator\Desktop\New Text Document (3).csv")) { for (int i = 0; i < newTable.DefaultView.Table.Rows.Count; i++) { DataRow row = newTable.DefaultView.Table.Rows[i]; // check for any null cells if (columns.Any(column => row.IsNull(column))) continue; string[] textCells = row.ItemArray .Select(cell => cell.ToString()) // may need to pick a text qualifier here .ToArray(); // check for non-null but EMPTY cells if (textCells.Any(text => string.IsNullOrEmpty(text))) continue; writer.WriteLine(string.Join(",", textCells)); } } So how to store sorted records in csv file ?

    Read the article

  • Display attribute from XML using PHP

    - by user560411
    Hello. I need to display the id attribute of CD from the following XML file. I display correctly everything except the id. Any help would be appreciate. display code <?php $doc = new DOMDocument(); $doc->load( 'insert.xml' ); $CATEGORIES = $doc->getElementsByTagName( "CD" ); foreach( $CATEGORIES as $CD ) { $TITLES = $CD->getElementsByTagName( "TITLE" ); $TITLE = $TITLES->item(0)->nodeValue; $BANDS= $CD->getElementsByTagName( "BAND" ); $BAND= $BANDS->item(0)->nodeValue; $YEARS = $CD->getElementsByTagName( "YEAR" ); $YEAR = $YEARS->item(0)->nodeValue; echo "<b>$TITLE - $BAND - $YEAR\n</b><br>"; } ?> XML <?xml version="1.0" encoding="utf-8"?> <MY_CD> <CATEGORIES> <CD id="3231"> <TITLE>NEVER MIND THE BOLLOCKS</TITLE> <BAND>SEX PISTOLS</BAND> <YEAR>1977</YEAR> </CD> <CD id="2453"> <TITLE>NEVERMIND</TITLE> <BAND>NIRVANA</BAND> <YEAR>1991</YEAR> </CD> </CATEGORIES> </MY_CD>

    Read the article

  • Conflict with @Html.LabelFor and W3C Validator?

    - by Tyler
    I have a model that I am using to present an index of a model from a database and have given a display name to some of the rows that may need spaces in them, (I.e. "weekstarting" in a db would be given a display name of "Week Starting"). So I set the display name for my model like this: [DisplayName("Week Starting")] public DateTime WeekStarting { get; set; } and then in the table headers for my table I use the following line of code to display the field name using its given display name: @Html.LabelFor(x => x.First().WeekStarting) The above all works fine. But I am using the W3C validator and it is giving me the following error for the example I have given: The for attribute of the label element must refer to a form control. Forgive me if it is obvious but what am I doing wrong here? I am not using a form I am simply displaying an index of items in a table. I have tried to look for an answer and saw someone suggest that the form controls being referred to need ids (even though I'm not using a form) but this would not be applicable in this instance because if I tried to set an id in the index it would be duplicated with each item in the index: foreach (var item in Model.Tbms) { <tr><td>@item.value</td><tr>.... would be repeated for each item, and also unsure where I would put the id in any case, the td? } Or is there a better way to label the field header, with my preferred display name in the first place? I guess I could just swap @Html.LabelFor... for Hard code field name but do I have to?

    Read the article

  • Binding Events rather than using onclick

    - by Abs
    Hello all, I have been told its better to bind events to elements rather than having onclicks with functions everywhere. I agree with this as it devolves more from the HTML which means cleaner and easier to debug code. But I am having trouble doing this! I loop through some data with PHP (see below) and I currently use onclick to call a function. How can I bind this onclick event to many elements using JQuery. <?php foreach($main_tags as $key=>$value){ ?> <li> <a id="<?php echo $key; ?>" href="#" onclick="tag_search('<?php echo $key; ?>'); return false;"> <?php echo $key; ?> <span class="num-active"> <?php echo $value; ?> </span> </a> </li> <?php } ?> Thanks all for any help

    Read the article

  • List of running minimum values

    - by scarle88
    Given a sorted list of: new []{1, 2, -1, 3, -2, 1, 1, 2, -1, -3} I want to be able to iterate over the list and at each element return the smallest value iterated so far. So given the list above the resultant list would look like: 1 1 -1 -1 -2 -2 -2 -2 -2 -3 My rough draft code looks like: var items = new []{1, 2, -1, 3, -2, 1, 1, 2, -1, -3}; var min = items.First(); var drawdown = items.Select(i => { if(i < min) { min = i; return i; } else { return min; } }); foreach(var i in drawdown) { Console.WriteLine(i); } But this is not very elegant. Is there an easier to read (linq?) way of doing this? I looked into Aggregate but it seemed to be the wrong tool. Ultimately the list of items will be very long, in the many thousands. So good performance will be an issue to.

    Read the article

  • Make a PHP GET request from a PHP script and exit

    - by Abs
    Hello all, Is there something simpler than the following. I am trying to make a GET request to a PHP script and then exit the current script. I think this is a job for CURL but is there something simpler as I don't want to really worry about enabling the CURL php extension? In addition, will the below start the PHP script and then just come back and not wait for it to finish? //set GET variables $url = 'http://domain.com/get-post.php'; $fields = array( 'lname'=>urlencode($last_name), 'fname'=>urlencode($first_name) ); //url-ify the data for the GET foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; } rtrim($fields_string,'&'); //open connection $ch = curl_init(); //set the url, number of POST vars, POST data curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch,CURLOPT_GET,count($fields)); curl_setopt($ch,CURLOPT_GETFIELDS,$fields_string); //execute GET $result = curl_exec($ch); //close connection curl_close($ch); I want to run the other script which contains functions when a condition is met so a simple include won't work as the if condition wraps around the functions, right? Please note, I am on windows machine and the code I am writing will only be used on a Windows OS. Thanks all for any help and advice

    Read the article

  • JavaScript two-dimensional Array to PHP

    - by vi
    Hi I have to send a two-dimensional JavaScript Array to a PHP page. Indeed, I'm working on a form-builder, in which the user can add or remove fields. These fields are added (or removed) using JavaScript (jQuery). When the user is done and hit a 'publish' button, I have to get all the fields concerned and send them to a PHP page which would build a real form with it. I found a way to do it but I'm pretty sure it's not very clean : addedFields = new Array(); $("#add-info .field").each(function() { addedFields.push(new Array($(this).find('.name').val(), $(this).find('.type').val(), $(this).find('.size').val())); }); Basically, the ".field" class objects are <tr> and the ".name", ".type" and ".size" objects are inputs. So I get an array of [name, type, size], then I convert it into a string using addedFields = addedFields.join(";"); Finally, I go to the PHP form that way ; document.location.href = "create.php?addedfields=" + addedFields; Concerning the PHP code, I create a PHP array using the explode() function: $addedFields = explode(";", $_GET['addedfields']); and then I use it again for each element in the array: foreach ($addedFields as $field) { $field = explode(",", $field); echo "<li>Field with name : '$field[0]', of '$field[1]' type and with a size of $field[2]"; }

    Read the article

  • CodeIgniter: help with this query

    - by iamjonesy
    Hi, I have just started my first CI app. I have a view that displays some posts. Each post can have multiple comments and I want to display the total number of comments next to each post. So far all my db call are in my controller (will be changing this). function index(){ $data['query'] = $this->db->get('posts'); $this->load->view('blog_view', $data); } In my view: <?php foreach($query->result() as $row): <div class="post-box"> <p><?php echo $row->body; ?><small>&nbsp;added by <?php echo $row->username; ?> on <?php echo date ('d/m/Y',strtotime($row->created)); ?>&nbsp;<a href="<?php echo base_url(); ?>blog/comments/<?php echo $row->id; ?>"><img src="<?php echo base_url(); ?>images/comments_icon.png" />&nbsp;0</a></small></p> </div> <?php endforeach; ?> I want to get the total number of comments where comment.post_id = the current record's id. and display it next to the comments icon. Any help with this most appreciated, Billy

    Read the article

  • Should I change $_REQUEST to $_POST

    - by Scarface
    Hey guys quick question, I have a checkbox system where a list of items can be checked and deleted on the click of a button. I currently use request and it does the job but I was wondering if $_REQUEST was some sort of security risk or improper. If anyone has any advice I would appreciate it. Should I change to $_POST? If so, what is the best way to go about it? foreach ($_REQUEST as $key=>$value) { if (substr($key,0,3)==="img") { $id = substr($key,3); if(isset($_REQUEST['Delete'])) { $sql = 'SELECT file_name,username FROM images WHERE id=?'; $stmt = $conn->prepare($sql); $result=$stmt->execute(array($id)); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { $image=$row['file_name']; $user=$row['username']; $myFile = "$user/images/$image"; unlink($myFile); } <input id=\"img".$id."\" name=\"img".$id."\" type=\"checkbox\">

    Read the article

< Previous Page | 361 362 363 364 365 366 367 368 369 370 371 372  | Next Page >