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  • How can I get columns name from select query in php?

    - by Farshad Mehrvarzan
    I want to execute a SELECT query but I don't how many columns to select. Like: select name, family from persons; How can I know which columns to select? "I am currently designing a site for the execute query by users. So when the user executes this query, I won't know which columns selected. But when I want to show the results and draw a table for the user I should know which columns selected."

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  • mysql_query where statment help

    - by Anders Kitson
    I am retrieving values from the url with the GET method and then using a if statement to determine of they are there then query them against the database to only show those items that match them, i get an unknown error with your request. here is my code $province = $_GET['province']; $city = $_GET['city']; if(isset($province) && isset($city) ) { $results3 = mysql_query("SELECT * FROM generalinfo WHERE province = $province AND city = $city ") or die( "An unknown error occurred with your request"); } else { $results3 = mysql_query("SELECT * FROM generalinfo"); } /*if statement ends*/

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  • Having a problem inserting into database

    - by neo skosana
    I have a stored procedure: CREATE PROCEDURE busi_reg(IN instruc VARCHAR(10), IN tble VARCHAR(20), IN busName VARCHAR(50), IN busCateg VARCHAR(100), IN busType VARCHAR(50), IN phne VARCHAR(20), IN addrs VARCHAR(200), IN cty VARCHAR(50), IN prvnce VARCHAR(50), IN pstCde VARCHAR(10), IN nm VARCHAR(20), IN surname VARCHAR(20), IN eml VARCHAR(50), IN pswd VARCHAR(20), IN srce VARCHAR(50), IN refr VARCHAR(50), IN sess VARCHAR(50)) BEGIN INSERT INTO b_register SET business_name = busName, business_category = busCateg, business_type = busType, phone = phne, address = addrs, city = cty, province = prvnce, postal_code = pstCde, firstname = nm, lastname = surname, email = eml, password = pswd, source = srce, ref_no = refr; END; This is my php script: $busName = $_POST['bus_name']; $busCateg = $_POST['bus_cat']; $busType = $_POST['bus_type']; $phne = $_POST['phone']; $addrs = $_POST['address']; $cty = $_POST['city']; $prvnce = $_POST['province']; $pstCde = $_POST['postCode']; $nm = $_POST['name']; $surname = $_POST['lname']; $eml = $_POST['email']; $srce = $_POST['source']; $ref = $_POST['ref_no']; $result2 = $db->query("CALL busi_reg('$instruc', '$tble', '$busName', '$busCateg', '$busType', '$phne', '$addrs', '$cty', '$prvnce', '$pstCde', '$nm', '$surname', '$eml', '$pswd', '$srce', '$refr', '')"); if($result) { echo "Data has been saved"; } else { printf("Error: %s\n",$db->error); } Now the error that I get: Commands out of sync; you can't run this command now

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  • Understanding Nested If.. Else statements

    - by user1174762
    For some reason my PHP login script keeps returning "invalid email/password combination", yet i know I am entering the correct email and password. Does anyone see what I might be doing wrong? <?php $email= $_POST['email']; $password= $_POST['password']; if (!empty($email) && !empty($password)) { $connect= mysqli_connect("localhost", "root", "", "si") or die('error connecting with the database'); $query= "SELECT user_id, email, password FROM users WHERE email='$email' AND password='$password'"; $result= mysqli_query($connect, $query) or die('error with query'); if (mysqli_num_rows($result) == 1) { $row= mysqli_fetch_array($result); setcookie('user_id', $row['user_id']); echo "you are now logged in"; } else { echo "invalid username/password combination"; } } else { echo" you must fill out both username and password"; } ?>

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  • How can I perform this query between related tables without using UNION?

    - by jeremy
    Suppose I have two separate tables that I watch to query. Both of these tables has a relation with a third table. How can I query both tables with a single, non UNION based query? I want the result of the search to rank the results by comparing a field on each table. Here's a theoretical example. I have a User table. That User can have both CDs and books. I want to find all of that user's books and CDs with a single query matching a string ("awesome" in this example). A UNION based query might look like this: SELECT "book" AS model, name, ranking FROM book WHERE name LIKE 'Awesome%' UNION SELECT "cd" AS model, name, ranking FROM cd WHERE name LIKE 'Awesome%' ORDER BY ranking DESC How can I perform a query like this without the UNION? If I do a simple left join from User to Books and CDs, we end up with a total number of results equal to the number of matching cds timse the number of matching books. Is there a GROUP BY or some other way of writing the query to fix this?

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  • Duplicate Blob field with foreach

    - by JGSilva
    I have some fields (blob) where I have uploaded some images. The images display correctly and I can open it without problem in Photoshop for example. I created a button where user can duplicate the product and everything works fine, but when it comes to duplicate the image entry I got some errors, like 1064 and others ones that I can't remember cause I am working 3 days inside this. Because de original product have 3 or more images I select then and gave an foreach. What I notice when a print de blob is that in the end it eats the next array, like if don't have an end. In other words, the next item got inside that utf-8 character in the print. That gave me some clue. The next approach was to save it in somewhere, and reupload it. The problem is that only the first one works. When I download the image saved, it opens normally so, it is not a saving in disk problem. When I gave a print in the $result, the same happens, is like the image is hungry and ate the next one. Here is the code. Notice = I created the [$count] to see if was not an rewrite in array error. Even tried to , in beging of the foreach, kind of clean the vars… $count=0; foreach ($original_image as $key => $val) { $count++; //$arquivo = ''; //$image = ''; //$file = ''; //$this->image = ''; //$return = ''; $arquivo[$count] = $val['pi_id'].'.'.$val['pi_type']; $image[$count] = $caminho_url.$arquivo[$count]; if (file_exists($image[$count])) { $this->image = Image::factory($image[$count]); $this->image->save($image[$count]); $file[$count]=mysql_real_escape_string(addslashes(fread(fopen($image[$count], "r"), filesize($image[$count])))); $return[$count] = Product::add_image($id_prod, $file[$count], $val['pi_type'],$val['pi_main']); }else { die('no'); } }

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  • As3 & PHP URLEncoding problem!

    - by Jk_
    Hi everyone, I'm stuck with a stupid problem of encoding. My problem is that all my accentuated characters are displayed as weird iso characters. Example : é is displayed %E9 I send a string to my php file : XMLLoader.load(new URLRequest(online+"/query.php?Query=" + q)); XMLLoader.addEventListener(Event.COMPLETE,XMLLoaded); When I trace q, I get : "INSERT INTO hello_world (message) values('éàaà');" The GOOD query My php file look like this : <?php include("conection.php");//Conectiong to database $Q = $_GET['Query']; $query = $Q; $resultID = mysql_query($query) or die("Could not execute or probably SQL statement malformed (error): ". mysql_error()); $xml_output = "<?xml version=\"1.0\"?>\n"; // XML header $xml_output .= "<answers>\n"; $xml_output .= "<lastID id=".'"'.mysql_insert_id().'"'." />\n"; $xml_output .= "<query string=".'"'.$query.'"'." />\n"; $xml_output .= "</answers>"; echo $xml_output;//Output the XML ?> When I get back my XML into flash the $query looks like this : "INSERT INTO hello_world (message) values('%E9%E0a%E0');" And these values are then displayed into my DB which is annoying. Any help would be appreciated! Cheers. Jk_

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  • Stop invalid data in a attribute with foreign key constraint using triggers?

    - by Eternal Learner
    How to specify a trigger which checks if the data inserted into a tables foreign key attribute, actually exists in the references table. If it exist no action should be performed , else the trigger should delete the inserted tuple. Eg: Consider have 2 tables R(A int Primary Key) and S(B int Primary Key , A int Foreign Key References R(A) ) . I have written a trigger like this : Create Trigger DelS BEFORE INSERT ON S FOR EACH ROW BEGIN Delete FROM S where New.A <> ( Select * from R;) ); End; I am sure I am making a mistake while specifying the inner sub query within the Begin and end Blocks of the trigger. My question is how do I make such a trigger ?

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  • How do I workaround this error ? You can't specify target table my table for update in FROM clause

    - by Jules
    I'm struggling to convert my select query into a update query, it has aliases.. Update pads set RemoveMeDate = '1999-01-01 00:00:00' where padid in ( SELECT old_table.padid FROM `jules-fix-reasons`.`pads` AS old_table JOIN `jules`.`pads` AS new_table ON old_table.padid = new_table.`PadID` WHERE new_table.RemoveMeDate <> '2001-01-01 00:00:00' AND old_table.RemoveMeDate = '2001-01-01 00:00:00') I've tried removing the aliases, but that doesn't help :(

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  • Query filter design for string field

    - by Midhat
    A field in my table can have arbitrary strings. On the UI, there is a drop down having options like All, Value1, Value2 And the results were filtered by the selected option value. So far this is easy and adding new filters to the UI is not a problem. Needs no changes in my stored procedure. Now I want to have an "Others" option here as well, which will return rows not having the column value as Value1 or Value2. Apparently this will require a "not in" operator in my query, and will make maintenance difficult, as the list of values is likely to change Any suggestions, design tips?

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  • sql UPDATE, a calculation is used multiple times, can it just be calculated once?

    - by Zachery Delafosse
    UPDATE `play` SET `counter1` = `counter1` + LEAST(`maxchange`, FLOOR(`x` / `y`) ), `counter2` = `counter2` - LEAST(`maxchange`, FLOOR(`x` / `y`) ), `x` = MOD(`x`, `y`) WHERE `x` `y` AND `maxchange` 0 As you can see, " LEAST(`maxchange`, FLOOR(`x` / `y`) ) " is used multiple times, but it should always have the same value. Is there a way to optimize this, to only calculate once? I'm coding this in PHP, for the record.

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  • COUNT issue across multiple tables

    - by Kim
    I am trying to count across 2 tables and I dont see whats wrong with my query yet I get a wrong result. User 2 does not exist in table_two, so the zero is correct. SELECT t1.creator_user_id, COUNT(t1.creator_user_id), COUNT(t2.user_id) FROM table_one AS t1 LEFT JOIN table_two AS t2 ON t2.user_id = t1.creator_user_id GROUP BY t1.creator_user_id, t2.user_id Actual result 1 192 192 2 9 0 Expected result 1 16 12 2 9 0 The result indicate a missing group by condition, but I already got both fields used. Where am I wrong ? Also, can I sum up all users that doesnt exist in table_two for t1 ? Like user 3 exists 21 times in t1, then the results would be: 1 16 12 (users with > 0 in t2 will need their own row) 2 30 0 (user 2=9 + user 3=21 => 30) Its okay for the user Id to be wrong for sum of t1 for all users with 0 in t2. If not possible, then I'll just do two queries.

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  • Very simple shopping cart, remove button

    - by Kynian
    Im writing sales software that will be walking through a set of pages and on certain pages there are items listed to sell and when you click buy it basically just passes a hidden variable to the next page to be set as a session variable, and then when you get to the end it call gets reported to a database. However my employer wanted me to include a shopping cart, and this shopping cart should display the item name, sku, and price of whatever you're buying, as well as a remove button so the person doing the script doesnt need to go back through the entire thing to remove one item. At the moment I have the cart set to display everything, which was fairly simple. but I cant figure out how to get the remove button to work. Here is the code for the shopping cart: $total = 0; //TEST CODE: $_SESSION['itemname-addon'] = "Test addon"; $_SESSION ['price-addon'] = 10.00; $_SESSION ['sku-addon'] = "1234h"; $_SESSION['itemname-addon1'] = "Test addon1"; $_SESSION ['price-addon1'] = 99.90; $_SESSION ['sku-addon1'] = "1111"; $_SESSION['itemname-addon2'] = "Test addon2"; $_SESSION ['price-addon2'] = 19.10; $_SESSION ['sku-addon2'] = "123"; //end test code $items = Array ( "0"=> Array ( "name" => $_SESSION['itemname-mo'], "price" => $_SESSION ['price-mo'], "sku" => $_SESSION ['sku-mo'] ), "1" => Array ( "name" => $_SESSION['itemname-addon'], "price" => $_SESSION ['price-addon'], "sku" => $_SESSION ['sku-addon'] ), "2" => Array ( "name" => $_SESSION['itemname-addon1'], "price" => $_SESSION ['price-addon1'], "sku" => $_SESSION ['sku-addon1'] ), "3" => Array ( "name" => $_SESSION['itemname-addon2'], "price" => $_SESSION ['price-addon2'], "sku" => $_SESSION ['sku-addon2'] ) ); $a_length = count($items); for($x = 0; $x<$a_length; $x++){ $total +=$items[$x]['price']; } $formattedtotal = number_format($total,2,'.',''); for($i = 0; $i < $a_length; $i++){ $name = $items[$i]['name']; $price = $items[$i]['price']; $sku = $items[$i]['sku']; displaycart($name,$price,$sku); } echo "<br /> <b>Sub Total:</b> $$formattedtotal"; function displaycart($name,$price,$sku){ if($name != null || $price != null || $sku != null){ if ($name == "no sale" || $price == "no sale" || $sku == "no sale"){ echo ""; } else{ $formattedprice = number_format($price,2,'.',''); echo "$name: $$formattedprice ($sku)"; echo "<form action=\"\" method=\"post\">"; echo "<button type=\"submit\" />Remove</button><br />"; echo "</form>"; } } } So at this point Im not sure where to go from here for the remove button. Any suggestions would be appreciated.

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  • HOw Do I update from table-2 to table-1

    - by mathew
    HI what is the wrong in this code?? i have set it 24 hours to update the value in the table.but the problem is if $row is empty then it inserts value from table-2 but after 24 hours it wont update the value. what I want is it must delete the existing value and insert new one(random value) or it must update the same $row with new value what ever... if ($row == 0){ mysql_query("INSERT INTO table-1 (regtime,person,location,address,rank,ip,geocode) SELECT NOW(),person,location,address,rank,ip,geocode FROM table-2 ORDER BY RAND() LIMIT 1");}else{ mysql_query("UPDATE table-1 SELECT regtime=NOW(), person=person, location=location, address=address, rank=rank, ip=ip, geocode=geocode FROM table-2 ORDER BY RAND() LIMIT 1");}

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  • make db connection persistent throught zend framework

    - by kamikaze_pilot
    I'm using zend framework. currently everytime I need to use the db I go ahead and connect to the DB: function connect(){ $connParams = array("host" => $host, "port" => $port, "username" => $username, "password" => $password, "dbname" => $dbname); $db = new Zend_Db_Adapter_Pdo_Mysql($connParams); return $db } so I would just call the connect() function everytime I need to use the db My question is...suppose I want to reuse $db everywhere in my site and only connect once in the very initial stage of the site load and then close the connection right before the site gets sent to the user, what would be the best practice to accomplish this? Which file in Zend should I save $db in, what method should I use to save it (global variable?), and which file should I do the connection closing in?

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  • Select 2 Rows from Table when COUNT of another table

    - by Marcus
    Here is the code that I currently have: SELECT `A`.* FROM `A` LEFT JOIN `B` ON `A`.`A_id` = `B`.`value_1` WHERE `B`.`value_2` IS NULL AND `B`.`userid` IS NULL ORDER BY RAND() LIMIT 2 What it currently is supposed to do is select 2 rows from A when the 2 rows A_id being selected are not in value_1 or value_2 in B. And the rows in B are specific to individual users with userid. What I need to do is make it also so that also checks if there are already N rows in B matching a A_id (either in value_1, or value_2) and userid, and if there are more than N rows, it doesn't select the A row.

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  • Best datastructure for this relationship...

    - by Travis
    I have a question about database 'style'. I need a method of storing user accounts. Some users "own" other user accounts (sub-accounts). However not all user accounts are owned, just some. Is it best to represent this using a table structure like so... TABLE accounts ( ID ownerID -> ID name ) ...even though there will be some NULL values in the ownerID column for accounts that do not have an owner. Or would it be stylistically preferable to have two tables, like so. TABLE accounts ( ID name ) TABLE ownedAccounts ( accountID -> accounts(ID) ownerID -> accounts(ID) ) Thanks for the advice.

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